An archery bow is drawn a distance d = 0.39 m and loaded with an arrow of mass m = 0.088 kg. The bow acts as a spring with a spring constant of k = 195 N/m, and the arrow flies with negligible air resistance. To simplify your work, let the gravitational potential energy be zero at the initial height of the arrow. If the arrow is shot at an angle of θ = 45° above the horizontal, how high, in meters above the initial height, will the arrow be when it reaches its peak?

Answers

Answer 1

The maximum height reached by the arrows is determined as 8.6 m.

What is the initial speed of the arrow?

The initial velocity of the arrow is calculated by applying the principle of conservation of energy as shown below;

K.E = U

where;

K.E is the kinetic energy of the arrowU is the elastic potential energy of the bow

¹/₂mv² = ¹/₂kx²

mv² = kx²

v² = kx²/m

v = √(kx²/m)

where;

k is spring constant of the bowm is the mass of the arrowx is the extension of the bow

v = √(195 x 0.39²/0.088)

v = 18.36 m/s

The maximum height reached by the arrow is calculated as follows;

H = (v² sin²θ) / (2g)

where;

θ is angle of projection of the arrowg is acceleration due to gravity

H = (18.36² (sin45)²) / (2 x 9.8)

H = 8.6 m

Thus, the height of the arrow above the ground when it reaches its peak is 8.6 m.

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Related Questions

read through the different scenarios below and choose what kind of energy transfer is happening for each one. note: each answer will be used 1 time.

Answers

1. A ceiling fan plugged into the wall socket.

The input is the electrical energy and the output is the mechanical energy from the rotation of the fan blades.

So, the energy transfer must be electrical to mechanical.

2. A stove heating a pot of water for pasta

The input is the light energy from the stove and the output is the thermal energy to heat the water.

So, the energy transfer must be light to thermal.

3. A wind turbine generating power

The input is the mechanical energy from the rotation of the turbine blades and the output is the electrical energy that is being generated.

So, the energy transfer must be mechanical to electrical.

4. A person eats a snack when they are hungry and has the energy to take a walk.

The input is the chemical energy that the person gets from eating food and the output is the mechanical energy (doing physical work).

So, the energy transfer must be chemical to mechanical.

5. A solar panel is used to create power

The input is the light energy from the Sun and it is being converted into electrical energy to generate power.

So, the energy transfer must be light to electrical.

6. A microwave is used to heat up a burrito.

The input to the microwave is the electrical energy and the output is the thermal energy to heat up the burrito.

So, the energy transfer must be electrical to thermal.

7. A lamp is plugged into the wall and shines down on a room

The input to the lamp is electrical energy which is being converted into light energy.

So, the energy transfer must be electrical to light.

8. A plant grows by absorbing the sun's rays

The input to the plant is the nuclear energy from the sun and the output is the chemical energy.

So, the energy transfer must be nuclear to chemical.

9. A game controller uses batteries to power it.

The batteries provide chemical energy as input and the output is the electrical energy to power the controller.

So, the energy transfer must be chemical to electrical.

10. The sun heats up a person sunbathing at the beach.

The input is the nuclear energy from the sun and output is the thermal energy by absorbing the heat.

So, the energy transfer must be nuclear to thermal.

The density of copper is 8.94 g/cm^3. What is the mass of a rectangular sheet of copper: 10 cm wide, 45 cm long, and 0.2 cm thick? I have no idea how to solve for mass or where to start. :(

Answers

Answer:

Mass = 804.6 g

Explanation:

The dimension of the rectangular copper = 10 cm wide, 45 cm long, and 0.2 cm thick

The volume of the rectangular copper = 0.1m x 0.45m x 0.002m

The volume of the rectangular copper = 0.00009 m³

The density of copper = 8.94 g/cm³ = 8.94 x 1000 kg/m³

The density of copper = 8940 kg/m³

Mass = Density x Volume

Mass = 8940 x 0.00009

Mass = 0.8046 kg

Mass = 804.6 g

You exert a force of 5.3 N on a book to slide it across a table. If you do 2.5 J of work in the process, how far did the book move?

Answers

We will have the following:

[tex]2.5J=5.3N\cdot x\Rightarrow x=\frac{2.5J}{5.3N}[/tex][tex]\Rightarrow x=\frac{25}{53}m\Rightarrow x\approx0.47m[/tex]

So, the book moved 25/53 meters, that is approximately 0.47 meters.

Fill in the blank: 66 in. = yd

Answers

Answer: 1.833

Explanation:

Multiply the value in inches by 0.027777777777727 (the conversion factor)

So 66 inches*.027777777777727=1.833 yards

Answer:

66inches = 1.833 yards

Explanation:

Can all rocks be dated with radiometer methods? Explain

Answers

Answer: No.

Explanation:

Radiometer dating is used on igneous rocks.

Unlike the other two rock types, sedimentary annd metamorphisis, all igneous rocks possess one specific age/ time of origin.

25. A student cycles along a level road at a speed of 5.0 m / s. The total mass of the student and bicycle is 120 kg. The student applies the brakes and stops. The braking distance is 10 m. What is the average braking force?

Answers

If a student bikes at a pace of 5.0 m/s down a straight route. The student's bicycle weighs 120 kg in total. The pupil puts on the brakes and comes to a stop. The average braking force of the automobile would be 150 newtons if the stopping distance were 10 meters.

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

Work done by the braking force of the cycle   = change in kinetic energy of the student

Force  × distance  = 1/2 × mass × velocity²

F = 0.5 x 120 x 5² / 10

F = 150 Newtons

Thus, the average braking force of the cycle would be  150 Newtons.

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A worker pushes horizontally on a large crate with a force of 245 N, and the crate is moved 3.5 m. How much work was done? answer in : ___J

Answers

The amount of work done by a force can be written as the following:

[tex]W=F.\Delta x[/tex]

For our case, we can replace our values and we'll get:

[tex]W=245*3.5=857.5J[/tex]

Thus, the amount of work done is 857.5J

What is absolute zero?0k0c273-100

Answers

The absolute zero is measured in Kelvin scale

Thus absolute zero is 0K.

Calculate the kinetic energy of a roller coaster that has a mass of 1,778.6 kg and is traveling with a velocity to 24.5 m/s at the bottom of the first hill.

Answers

Given:

The mass of the roller coaster is m = 1778.6 kg

The velocity of the roller coaster is v = 24.5 m/s

To find the kinetic energy of the roller coaster.

Explanation:

The formula to calculate the kinetic energy is

[tex]K\mathrm{}E\text{. =}\frac{1}{2}mv^2[/tex]

Substituting the values, the kinetic energy will be

[tex]\begin{gathered} K\mathrm{}E\text{. =}\frac{1}{2}\times1778.6\times(24.5)^2 \\ =533802.325\text{ J} \end{gathered}[/tex]

Final Answer: The kinetic energy of the roller coaster is 533802.325 J.

What are the answers for a, b and c in MJ?

Answers

Given:

The orbital height of the satellite, h=94 km=94000 m

The mass of the satellite, m=1045 kg

The new altitude of the satellite, d=207 km=207000 m

To find:

a) The energy needed.

b) The change in the kinetic energy.

c) The change in the potential energy.

Explanation:

The radius of the earth, R=6.37×10⁶ m

The mass of the earth, M=6×10²⁴ kg

a) The orbital velocity is given by,

[tex]v=\sqrt{\frac{GM}{r}}[/tex]

Where G is the gravitational constant and r is the radius of the satellite from the center of the earth.

Thus the initial orbital velocity of the earth,

[tex]\begin{gathered} v_1=\sqrt{\frac{6.67\times10^{-11}\times6\times10^{24}}{(6.37×10^6+94000)}} \\ =7868.43\text{ m/s} \end{gathered}[/tex]

The orbital velocity after changing the altitude is,

[tex]\begin{gathered} v_2=\sqrt{\frac{6.67\times10^{-11}\times6\times10^{24}}{(6.37\times10^6+207000)}} \\ =7800.5\text{ m/s} \end{gathered}[/tex]

Thus the total energy needed is given by,

[tex]E=(\frac{1}{2}mv_2^2-\frac{GMm}{(R+d)})-(\frac{1}{2}mv_1^2-\frac{GMm}{(R+h)})[/tex]

On substituting the known values,

[tex]\begin{gathered} E=1045[(\frac{1}{2}\times7868.43^2-\frac{6.67\times10^{-11}\times6\times10^{24}}{(6.37\times10^6+207000)})-(\frac{1}{2}\times7800.5^2-\frac{6.67\times10^{-11}\times6\times10^{24}}{(6.37×10^6+94000)})] \\ =623\text{ MJ} \end{gathered}[/tex]

b)

The change in the kinetic energy is given by,

[tex]\begin{gathered} KE=\frac{1}{2}mv_2^2-\frac{1}{2}mv_1^2 \\ =\frac{1}{2}m(v_2^2-v_1^2) \end{gathered}[/tex]

On substituting the known values,

Two points ___________ create a line.A. sometimesB. neverC. alwaysD. not enough information

Answers

According to the Euclidean Postulates, a straight line segment can be drawn joining any two points.

Therefore, the answer is:

[tex]C)\text{ Always}[/tex]

Marc is sitting at his desk with good posture. What MOST likely is Marc doing?

Answers

It is most likely that Marc is studying while assuming a good sitting posture.

What is posture?

Posture is defined as the the various ways an individual carry their body in order to assume a particular position which may be while sitting of standing up.

There different types of postures which are classified under good or bad posture. They include the following:

Healthy Posture.Kyphosis Posture.Flat Back Posture.Swayback Posture.Forward Head Posture.

To sit correctly at a dest with a good posture is an example of a healthy posture which was assumed by Marc.

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find an equation of the line with y intercept (0,7) and the slope of 1/2

Answers

Consider that a general way of writing a line equation is:

y = mx + b

where m is the slope of the line and b is the y coordinate of the y-intercept of the line.

Then, by using the given information:

m = 1/2

b = 7

You have the following equation of line:

y = 1/2*x + 7

The acceleration of gravity depends on (click all that apply)

Answers

The expression for the acceleration due to gravity can be given as,

[tex]g=\frac{GM}{R^2}[/tex]

Here, g is the acceleration due to gravity, G is the gravitational constant, M is the mass of planet and R is the distance from the center of planet.

Therefore, the acceleration due to gravity depends upon the distance from center of planet and the mass of planet.

Hello please could you help me with the physics ?

Answers

In order to calculate the amount of energy needed, we can use the formula below:

[tex]Q=m\cdot c\cdot\Delta T[/tex]

Where Q is the amount of energy in Joules, m is the mass in kg, c is the specific heat coefficient and DeltaT is the change in temperature.

So, for m = 0.8, c = 4.2*10^3 and DeltaT = 85 (from 15°C to 100°C), we have:

[tex]\begin{gathered} Q=0.8\cdot4.2\cdot10^3\cdot85 \\ Q=285600\text{ J} \end{gathered}[/tex]

Then, for the energy needed to evaporate the water, we have a similar formula:

[tex]Q=m\cdot L[/tex]

Where L is the latent heat. So, for L = 2.3 * 10^6, we have:

[tex]\begin{gathered} Q=0.8\cdot2.3\cdot10^6 \\ Q=1840000\text{ J} \end{gathered}[/tex]

The idea that our solar system formed from an interstellar cloud of dust, hydrogen,helium and other ionized gases is known as what theory?A. Big Bang TheoryB. Geocentric TheoryC. Nebular Hypothesis Theory

Answers

Given:

The solar system formed from an interstellar cloud of dust, hydrogen,

helium and other ionized gases.

To find:

The name of the theory tells us the fact

Explanation:

The Sun and all the planets of our Solar System began as a giant cloud of molecular gas and dust. The nebular hypothesis tells us about this theory.

Hence, the correct answer is 'The nebular hypothesis theory'.

What total energy (in J) is stored in the capacitors in the figure below (C1 = 0.900 µF, C2 = 16.0 µF) if 1.80 10-4 J is stored in the 2.50 µF capacitor?

Answers

The total energy  stored in the capacitors is determined as  2.41 x 10⁻⁴ J.

What is the potential difference of the circuit?

The potential difference of the circuit is calculated as follows;

U = ¹/₂CV²

where;

C is capacitance of the capacitorV is the potential difference

For a parallel circuit the voltage in the circuit is always the same.

The energy stored in 2.5 μf capacitor is known, hence the potential difference of the circuit is calculated as follows;

U = ¹/₂CV²

2U = CV²

V = √2U/C

V = √(2 x 1.8 x 10⁻⁴ / 2.5 x 10⁻⁶)

V = 12 V

The equivalent capacitance of C1 and C2 is calculated as follows;

1/C = 1/C₁ + 1/C₂

1/C = (1)/(0.9 x 10⁻⁶)  +  (1)/(16 x 10⁻⁶)

1/C = 1,173,611.11

C = 1/1,173,611.11

C = 8.52 x 10⁻⁷ C

The total capacitance of the circuit is calculated as follows;

Ct = 8.52 x 10⁻⁷ C   +   2.5 x 10⁻⁶ C

Ct = 3.35 x 10⁻⁶ C

The total energy of the circuit is calculated as follows;

U =  ¹/₂CtV²

U =  ¹/₂(3.35 x 10⁻⁶ )(12)²

U = 2.41 x 10⁻⁴ J

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An air compressor has a volume of 100.L What volume of gas is pumped into the tank if the pressure goes from 750 torr to a pressure of 145 psi?Remember to convert pressure to atm. Refer to picture for conversions if needed.

Answers

ANSWER:

1000 L

STEP-BY-STEP EXPLANATION:

The first thing is to convert the unit of both pressures to atm, with the help of the conversion equivalences shown, just like this:

[tex]\begin{gathered} P_1=750\text{ torr }\cdot\frac{1\text{ atm}}{760\text{ torr}}=0.987\text{ atm} \\ P_2=145\text{ psi }\cdot\frac{1\text{ atm}}{14.7\text{ psi}}=9.87\text{ atm} \end{gathered}[/tex]

Now, applying Boyle's Law, we calculate the value of the volume, like this:

[tex]\begin{gathered} P_1\cdot V_1=P_2\cdot V_2 \\ V_1=\frac{P_2\cdot V_2}{P_1} \\ \text{ replacing} \\ V_1=\frac{9.87\cdot100}{0.987}_{} \\ V_1=1000\text{ L} \end{gathered}[/tex]

The volume of gas is 1000 L

2. During which Epoch did humans first appear?Holocene3. How many million years ago did humans first appear?2.8 million years ago4. What are the three periods of the Mesozoic Era?Cretaceous, Jurassic, Triassic5. When did dinosaurs first appear?Triassic period6. In what period did birds first appear?Jurassic7. During what period did the dome-like uplift of the Adirondack region begin?

Answers

(1)

The three eras within the Phanerozoic eon are

1) The Paleozoic era (541 million to 252 million years ago)

2) The Mesozoic era (252 million to 66 million years ago)

3) The Cenozoic era (66 million years ago to the present)

Can you tell me the types of thermal processes and there meanings

Answers

Isothermal process: Temperature remains constant

Adiabatic process: No heat is exchanged to or from the system.

Isochoric process : Change in volume is zero.

ISobaric process : Pressure remains constant .

An Alaskan rescue plane traveling 37 m/s
drops a package of emergency rations from
a height of 153 m to a stranded party of
explorers.
The acceleration of gravity is 9.8 m/s².
Where does the package strike the ground
relative to the point directly below where it
was released?

Answers

Throught the given statement, the package strike the ground at the vilocity = -57.04 m/s

What is the meaning of velocity?

The direction of the movement of the body or the object is defined by its velocity. Most of the time, speed is a scalar quantity. In its purest form, velocity is a vector quantity. It measures how quickly a distance changes. It is the rate at which displacement is changing.

we get,

y = 0m

y0 = 166m

v0y = 0 m/s

g = 9.8 m/s^2

t = ?

Now, solving for t,

y = y0 + v0y×t - (0.5)gt²

0 = 166 - (0.5)(9.8)t²

t = 5.82 s

Now that we have time, we can use the equation to solve for the range.

x = vx(t)

x = (40)(5.82)

x = 232.8 m

v = v0y - gt

v = 0 - (9.8)(5.82)

v = -57.04 m/s

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Sodium has a density of 1.95 g/cm3. What is the volume of 56.2 g of sodium?

Answers

Answer: couldn't type in that little 3 haha

Explanation:

A person pushes a 500 kg crate with a force of 1200 N and the crate accelerates at .5 m/s^2. What is the force of friction acting on the crate?

Answers

The force of friction acting on the crate is 950 N.

What is force of friction?

Force of friction is defined as the force that opposes the motion of an object when two surfaces are in contact.

The frictional force on the object is determined by applying Newton's second law of motion as shown below.

F - Ff = ma

where;

F is the applied force = 1200 NFf is the frictional forcem is the mass of the crate = 500 kga is the acceleration of the crate = 0.5 m/s²

1200   -  Ff = 500(0.5)

1200 - Ff = 250

Ff = 1200 - 250

Ff = 950 N

Thus, the force of friction acting on the crate preventing the motion of the crate is determined by applying Newton's second law of motion.

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Which of the following is an appropriate measure of electric power on a toaster label?220 W55 Ω110 V2.0 A

Answers

A Watt is the unit of electrical power

When an object falls through air, there is a drag force that depends on the product
of the surface area of the object, and the square of its velocity, i.e. F=CAv2
, where C
is a constant, determine the dimension of C and its SI unit

Answers

The dimensions and unit of C from the expression above is [ML^-3] and kgm^-3

What is dimension and units ?

Despite the fact that the solution to any engineering problem must incorporate units, dimensions and units are frequently misunderstood. While units are arbitrary names that are correlated to certain dimensions to make it relative, dimensions are tangible quantities that can be measured (e.g., a dimension is length, whereas a metre is a relative unit that describes length). Through a conversion factor, all units for the same dimension are related to one another.

given in question drag force depends upon the product of the cross sectional area of the object and the square of its velocity

and drag force can be given by

F = CAv^2     ----------- (1)

It is given that

Dimension of mass = [M]

Dimension of length = [L]

Dimension of time = [T]

So, by using above dimension we can write

the dimension of force,

F = [ MLT^-2]

dimension of cross-section area,

A = [L^2]

and dimension of velocity

v = [LT^-1]

now, by putting these values in equation (1), we will get

F = CAv^2

[ MLT^-2] = C[L^2][LT^-1]^2

C = [ML^-3T^0]

C = [ML^-3]

The dimensions and unit of C from the expression above is [ML^-3] and kgm^-3

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Hence, the dimension of constant C will be,

Look at Figure 13-17 to answer the question.Will the acceleration of the piano be greater in A or in B? Use Newton's second law ofmotion to explain your answer.

Answers

Answer:

Explanation:

Newton's second law states that the applied force is directly proportional to the rate of change of momentum

momentum = mass x velocity

Rate of change in momentum = (final momentum - initial momentum)/time

Rate of change in momentum = m(v - u)/t

where

v is final velocity

u is initial velocity

t is times

Recall,

Acceleration = (v - u)/t

Thus, the equation becomes

Force = ma

This means that as the force increases, the acceleration increases.

Considering the given scenarios,

First piano is pushed by force from the man

For second piano, there is additional force from the woman and the mass of the piano remains the same. Since there is more force, there is more acceleration. Thus,

Acceleration is greater in B

. Chloe performed an experiment on the amount of a certain gas that can be dissolved in water at different temperatures. Her data from the experiment is shown on the graph below. What type of function would best fit this set of data?

Answers

The values on the curve corresponding to the y axis are the y values

The values on the curve corresponding to the x axis are the x values

We would pick corresponding x and y values on the graph and compare them

On the graph, each small square represents 1 unit on both axes.

If x = 1, y = 1

If x = 4, y = 2

if x = 9, y = 3

We know that the square root of 1 is 1, the square root of 4 is 2 and the square root 9 is 3. This means that

y is the square root of x

The function is

[tex]y\text{ = }\sqrt[]{x}[/tex]

Thus, it is a square root function

The first option is correct

A 60.0 kg skier with an initial speed of 14 m/s coasts up a 2.50 m high rise

Find her final speed right at the top, in meters per second, given that the coefficient of friction between her skis and the snow is 0.38?

Answers

The final speed (in meters per second), given that the coefficient of friction between her skis and the snow is 0.38 is 14.65 m/s

How do I determine the final velocity?

First, we shall obtain the force. This can be obatined as follow:

Mass (m) = 60 KgAcceleration due to gravity (g) = 9.8 m/s²Normal reaction (N) = mg = 60 × 9.8 = 588 NCoefficient of kinetic friction (μK) = 0.38Force (F) = ?

F = μKN

F = 0.38 × 588

F = 223.44 N

Next, we shall obtain the acceleration of the skier. This can be obtained as follow:

Mass (m) = 60Force (F) = 223.44 NAcceleration (a) = ?

a = F / m

a = 223.44 / 61

a = 3.724 m/s²

Finally, we shall determine the final velocity. This can be obtained as follow:

Initial speed (u) = 14 m/sDistance (s) = 2.5 mDeceleration (a) = 3.724 m/s²Final speed (v) =?

v² = u² + 2as

v² = 14² + (2 × 3.724 × 50)

v² = 196 + 18.62

v² = 214.62

Take the square root of both sides

v = √214.62

v = 14.65 m/s

Thus, the the final speed is 14.65 m/s

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The final speed right at the top will be 14.65 m/s and the coefficient of friction between her skis and the snow is 0.38.

What is velocity?

The ratio between displacement to time is referred to as the velocity of the object. It is a vector quantity with SI unit meter per second (m/s).

According to the question, the given information is :

Skier's mass, m = 60 kg

The acceleration due to gravity, g = 9.8 m/s²

Initial Speed, u = 14 m/s

Distance, s = 2.5 m

Deceleration is given as, a = 3.724 m/s².

Normal reaction force (N) will be equal to mg.

N = 60 × 9.8

N = 588 N

The coefficient of kinetic friction is given as, μ = 0.38

By using the formula,

F = μKN

F = 0.38 × 588

F = 223.44 N

Now, let's calculate the acceleration of the skier :

f = ma

a = f/m

a = 223.44/60

a =  3.724 m/s².

Now, calculate the velocity,

v² = u² + 2as

v² = 14² + 2 (3.724) (50)

v² = 196 + 18.62

v² = 214.62

v = 14.65 m/s.

Hence, the final speed right at the top will be 14.65 m/s.

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You and some friends are duck pin bowling. You’re up and you roll your bowling ball (m = 1.6kg) down the lane. It collided with one pin (0.68kg) on the end in a perfectly elastic one dimensional collision. If the ball was moving at a velocity of 6 m/s just before it hits the pin, what is the velocity of the bowling pin after the collision?

Answers

Given:

The mass of the bowling ball is m1 = 1.6 kg

The mass of the pin is m2 = 0.68 kg

The initial velocity of the ball is

[tex]v_i=\text{ 6 m/s}[/tex]

Required: Velocity of the bowling pin after the collision.

Explanation:

According to the conservation of momentum, the velocity after the collision will be

[tex]\begin{gathered} m1v_i+m2\times0\text{ =\lparen m1+m2\rparen v}_f \\ v_f=\frac{m1v_i}{m1+m2} \\ =\frac{1.6\times6}{1.6+0.68} \\ =4.21\text{ m/s} \end{gathered}[/tex]

Final Answer: The velocity of the bowling pin after the collision is 4.21 m/s

Sean and Greg are on a job site standing on two beams 11.0 ft apart. they need to lift their crate of tools midway between them with ropes up 33.5 ft to where they are working. (a) What is the angle between the ropes when the crate is on the ground? (b) How much force do Sean and Greg need to exert on the ropes when lifting the 115-lb crate off the ground? (c) How much force do both Sean and Greg need to exert when the crate is 5.75 ft below them? (d) Explain why the force to lift the crate changes as it moves closer to them crate is 5.75 ft below them? (d) Explain why the force to lift the
crate changes as it moves closer to them.

Answers

a ) The angle between the ropes when the crate is on the ground = 18.4°

b ) Force exerted by Sean and Greg = 260.8 N

c ) Force exerted when the crate is 5.75 ft below them = 354.9 N

a ) The angle between the ropes,

Distance between crate and a person = 33.5 ft

Distance between Sean and Greg = 11 ft

Consider only one person side of the rope and the midway point between Sean and Greg. This forms a right angled triangle.

sin θ = 5.5 / 33.5

θ = [tex]sin^{-1}[/tex] ( 0.16 )

θ = 9.2°

Angle between the ropes = 2 θ

Angle between the ropes = 2 * 9.2

Angle between the ropes = 18.4°

b ) Force exerted,

Since both ropes pull the same amount of weight for the same amount of distance, their tensions will be equal,

T = T1 = T2

Resolving the tension into its horizontal and vertical component.

[tex]T_{y}[/tex] = T cos θ

[tex]T_{x}[/tex] = T sin θ

Since there is not time component mentioned assuming the crate is pulled at a constant velocity. Therefore acceleration will be zero and hence net force in vertical direction will be zero.

m = 115 lb = 52.16 kg

∑ [tex]F_{y}[/tex] = 0

T cos θ + T cos θ - m g = 0

2 T cos 9.2° = 52.16 * 9.8

T = 511.17 / 1.96

T = 260.8 N

c ) When the crate is 5.75 ft below them,

tan θ = 5.5 / 5.75

θ = [tex]tan^{-1}[/tex] ( 0.96 )

θ = 43.8°

∑ [tex]F_{y}[/tex] = 0

T cos θ + T cos θ - m g = 0

2 T cos 43.8° = 52.16 * 9.8

T = 511.17 / 1.44

T = 354.9 N

d ) The force to lift the crate changes as it moves closer to them is because in a shorter cable the horizontal force increases and the vertical force decreases. So it becomes harder to pull as it gets closer to the destination.

Therefore,

a ) The angle between the ropes when the crate is on the ground = 18.4°

b ) Force exerted by Sean and Greg on the ropes when lifting the 115-lb crate off the ground = 260.8 N

c ) Force exerted by Sean and Greg when the crate is 5.75 ft below them = 354.9 N

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