What is the speed of an object at rest?
0 m/s
O 1 m/s
O 10 m/s
Answer:
1 m/s so number 2 is the right one
Explanation:
so when it is at rest it still has some of the left over energy so it would be at 1 m/s
prove velocity square = U square+2as
bad handwriting tho........... hope u understand
2. At the start of an experiment, a lab cart is moving with a velocity of 0.5 m/s to the right. The lab cart's
trip (motion) lasted 5 seconds. How far did the cart travel?
Answer:
2.5m
Explanation:
Speed/velocity = 0.5m/s
Time = 5s
speed = Distance/Time
Distance = Speed x Time
Distance = 0.5 x 5
Distance = 2.5m
Levi decides to examine the effect of fertilizer on the growth of tomato plants. He chooses four plants for his experiment and applies varying amounts of fertilizer to the three of them. He does not apply fertilizer to one plant.
Over a 15-day period, the plants receive fertilizer on Days 1, 4, 7, 10, and 13. Levi measures the height of all of his plants with a meter stick on Days 3, 6, 9, 12, and 15. He also makes sure to hold all experimental factors constant except for the fertilizer.
Which statement describes what Levi did to prepare the control group in his experiment?
Levi applied different amounts of fertilizer to three of his plants.
Levi did not apply any fertilizer to one of his plants..
Levi held all experimental factors constant except for fertilizer., ,
Levi measured his plants on five separate days.
Answer:
Levi did not apply any fertilizer to one of his plants..
Explanation:
In an experiment, there are two major groups namely: control group and experimental group. Control group is the group in an experiment that does not receive the experimental treatment i.e. the group which the independent variable is not applied to.
In this case, Levi is trying to examine the effect of fertilizer on the growth of tomato plants where he used varying amounts of fertilizer on three of the four plants he used for the experiment. The fourth plant did not receive any amount of fertilizer, which is the independent variable (variable being manipulated or changed). This means that Levi prepared the control group in his experiment by NOT APPLYING ANY FERTILIZER TO ONE OF HIS PLANTS.
Give me a good explanation for brainliest
Answer:to past school duhh
Explanation:
Select the correct answer.
These waves are traveling at the same speed. Which wave has the highest frequency?
A
B
C
D
Answer:
a is the correct choice
Explanation:
The wave has the highest frequency in option A.
What is frequency?The frequency of a wave is the number of cycles completed by the wave in a given period of time. Frequency is measured in Hertz (Hz).
How to calculate frequencyThe frequency of a wave is calculated as follows;
[tex]v = f \lambda\\\\f = \frac{v}{\lambda}[/tex]
where;
f is the frequencyv is the speed of the waveλ is the wavelengthFrom the given chart, in option A the wave completed more cycles in the given period of time.
Thus, the wave has the highest frequency in option A.
Learn more about frequency of waves here: https://brainly.com/question/19638389
Two 100 ohm resistors are connected in series and they are connected to seven 1.5V DC. What is the total current flowing in the circuit?
I = V/Rt = 1.5/(100+100) = 1.5/200 = 0.0075 A ....or 0.0075*1000 = 7.50 mA
I = V/Rt
= 1.5/(100+100) = 1.5/200
= 0.0075 A ....or 0.0075*1000 = 7.50 mA
What is Current?In a full electrical circuit, current is the rate at which electrons move past a certain point. Current = flow, at its most fundamental level.
The international unit for measuring current is an ampere (AM-pir), sometimes known as an amp. It describes how many electrons (sometimes referred to as "electrical charge") travel past a certain point in a circuit over a specified period of time.
In a circuit, a current of 1 ampere corresponds to the movement of 1 coulomb of electrons, or 6.24 billion (6.24 x 1018) electrons, through a single location in a second.
Therefore, I = 0.0075 A ....or 0.0075*1000 = 7.50 mA
To learn more about current, refer to the link:
https://brainly.com/question/2264542
#SPJ2
Students set up a controlled experiment (please help I am so tired and unable to function lol)
Cuál es la diferencia entre fricción beneficiosa y perjudicial? Pon 5 ejemplos de cada uno.
Answer:
Difference is given below.
Explanation:
The main difference between beneficial and harmful friction is that beneficial friction is necessary for performing different activities while on the other hand, harmful effect of friction is destroy different parts of products and machines. examples of beneficial friction are walking, holding things, rubbing hands to produce heat, running etc whereas examples of harmful friction are destruction of sole, slipping, tearing of machine's part, Wet roads and Mudslides etc.
Where on a roller coaster are there equal amounts of potential energy and kinetic energy?
Answer:
Picture?
Explanation:
The roller coaster will have equal kinetic and potential energy at any point starting from rest and reaching the minimum height.
The given problem is based on the concepts and fundamentals of kinetic energy and potential energy. The energy of an object by virtue of its position is known as kinetic energy. And the energy of object by virtue of its position is called potential energy.
In the given problem, the roller coaster will have highest potential energy at maximum height, but will have least kinetic energy there.Similarly, it will have maximum kinetic energy at the bottom of slide, but will have least potential energy there.So, at any point between starting from rest and reaching minimum height it will have both potential and kinetic energy in equal magnitude.Thus, we can conclude that the roller coaster will have equal kinetic and potential energy at any point starting from rest and reaching the minimum height.
Learn more about the kinetic and potential energy here:
https://brainly.com/question/17858145
calculate the speed of a person who travels 600km in 8 hrs express in m/s
please urgent will surely mark u the brainliast!!!!!!
Answer:
20.83 m/sExplanation:
The speed of an object can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question
600 km = 600,000 m
8hrs = 28,800 s
We have
[tex]v = \frac{600000}{28800} = \frac{6000}{288} = \frac{125}{6} \\ = 20.83333...[/tex]
We have the final answer as
20.83 m/sHope this helps you
Answer:
20.833333... m/s or 20 & 5/6 m/s
Explanation:
You want to convert km to meters, and hours to seconds. You do "dimensional analysis," which is just multiplying fractions so that units cancel.[tex]\frac{600 km}{8hr} * \frac{1hr}{60mins} * \frac{1min}{60sec} = \frac{600km}{28,800sec} = \frac{6km}{288sec}[/tex]
so now we have km/sec, but we need m/s, so...
[tex]\frac{6km}{288sec} * \frac{1000m}{1km} = \frac{6000m}{288sec} = \frac{125m}{6sec} = 20\frac{5}{6} m/s = 20.83333... m/s[/tex]
What is the measure of the average kinetic energy of the particles in a material known as?
A. heat transfer B. radiation
C. temperature
D. thermal expansion
Answer:
The answer is temperature
this is an opinion question but
explain why you think it is important to know the three different types of rocks.
If a 0.8kg ball is thrown with a velocity of 5 m/s,what is its KE?(KE=1/2 x m x v2)
During which phase of the moon does a lunar eclipse occur
Answer:
Full moon
Explanation:
Compare an Earth year to a cosmic year
Show that on a hypothetical planet having half the diameter of the Earth but twice its density, the acceleration of free fall is the same as on Earth.
Answer:
Steps include:
Find the ratio between the mass of this hypothetical planet and the mass of planet earth.Calculate the ratio between the acceleration of free fall (gravitational field strength) near the surface of that hypothetical planet and near the surface of the earth.Assumption: both planet earth and this hypothetical planet are spheres of uniform density.
Explanation:
Mass of that hypothetical planetLet [tex]M_0[/tex], [tex]r_0[/tex], and [tex]\rho_0[/tex] denote the mass, radius, and density of planet earth.
The radius and density of this hypothetical planet would be [tex](1/2)\, r_0[/tex] and [tex]2\, \rho_0[/tex], respectively.
The volume of a sphere is [tex]\displaystyle V = \frac{4}{3}\, \pi\, r^3[/tex].
Therefore:
The volume of planet earth would be [tex]\displaystyle V_0 = \frac{4}{3}\, \pi\, {r_0}^{3}[/tex].The volume of this hypothetical planet would be: [tex]\displaystyle V = \frac{4}{3}\, \pi\, \left(\frac{r_0}{2}\right)^3 = \frac{1}{6}\, \pi\, {r_0}^3[/tex].The mass of an object is the product of its volume and density. Hence, the mass of the earth could also be represented as:
[tex]\displaystyle M_0 = \rho_0\, V_0 = \frac{4}{3}\, \pi\, {r_0}^{3}\, \rho_0[/tex].
In comparison, the mass of this hypothetical planet would be:
[tex]\begin{aligned}M &= \rho\, V\\ &= (2\, \rho_0) \cdot \left(\frac{1}{6}\, \pi\, {r_0}^3\right) \\ &= \frac{1}{3}\, \pi\, {r_0}^{3}\, \rho_0 \end{aligned}[/tex].
Compare these two expressions. Notice that [tex]\displaystyle M = \frac{1}{4}\, M_0[/tex]. In other words, the mass of the hypothetical planet is one-fourth the mass of planet earth.
Gravitational field strength near the surface of that hypothetical planetThe acceleration of free fall near the surface of a planet is equal to the gravitational field strength at that very position.
Consider a sphere of uniform density. Let the mass and radius of that sphere be [tex]M[/tex] and [tex]r[/tex], respectively. Let [tex]G[/tex] denote the constant of universal gravitation. Right next to the surface of that sphere, the strength of the gravitational field of that sphere would be:
[tex]\displaystyle g = \frac{G \cdot M}{r^2}[/tex].
(That's the same as if all the mass of that sphere were concentrated at a point at the center of that sphere.)
Assume that both planet earth and this hypothetical planet are spheres of uniform density.
Using this equation, the gravitational field strength near the surface the earth would be:
[tex]\displaystyle g_0 &= \frac{G \cdot M_0}{{r_0}^2}[/tex].
.
On the other hand, the gravitational field strength near the surface of that hypothetical planet would be:
[tex]\begin{aligned}g &= \frac{G \cdot (M_0/4)}{{(r_0/2)}^2} = \frac{G \cdot M_0}{{r_0}^2}\end{aligned}[/tex].
Notice that these two expressions are equal. Therefore, the gravitational field strength (and hence the acceleration of free fall) would be the same near the surface of the earth and near the surface of that hypothetical planet.
As a side note, both [tex]g[/tex] and [tex]g_0[/tex] could be expressed in terms of [tex]\rho_0[/tex] and [tex]r_0[/tex] alongside the constants [tex]\pi[/tex] and [tex]G[/tex]:
[tex]\begin{aligned}g &= \frac{G \cdot M}{r^2}\\ &= \frac{G \cdot (1/3)\, \pi\, {r_0}^3 \, \rho_0}{(r_0/2)^2} = \frac{4}{3}\,\pi\, G\, r_0\, \rho_0\end{aligned}[/tex].
[tex]\begin{aligned}g_0 &= \frac{G \cdot M_0}{{r_0}^2}\\ &= \frac{G \cdot (4/3)\, \pi\, {r_0}^3 \, \rho_0}{{r_0}^2} = \frac{4}{3}\,\pi\, G\, r_0\, \rho_0\end{aligned}[/tex].
by how many times will the kinetic energy of a body increaseif its speed is tripled? show by calculation.
Answer:
9 times
Explanation:
Mass of a body remains constant.
Let the mass of a body be 'm'
Let the speed of the body be 'v'
Initial Kinetic Energy (K.E.) = [tex] \frac{1}{2} m {v}^{2} [/tex]
When speed is tripled , new speed = 3v
Mass of body = m (Mass is always constant)
Final Kinetic Energy (K.E.") =
[tex] \frac{1}{2} \times m \times {(3v)}^{2} [/tex]
[tex] = > \frac{1}{2} \times m \times 9v[/tex]
[tex] = > 9( \frac{1}{2} m {v}^{2} )[/tex]
But we already know that [tex]k.e. = \frac{1}{2} m {v}^{2} [/tex]
Hence
[tex] = > final \: k.e. = 9(initial \: k.e.)[/tex]
1 point
1. A bowler uses 10.5 N of force to roll a bowling ball, and the ball
accelerated at 2.5 m/s2 to reach a speed of 50.0 m/s. What is the mass of
the bowling ball to the nearest tenth of a kilogram? Answer in kg.*
According to Newton's third law of motion, if you push against a wall, the wall will __________.
Answer:
push up agaisnt you with equal force.
Answer:
c
Explanation:
A plant growing toward a light source is an example of an organism... *
A plant growing towards a light source is an example of an organism of Phototropism
A 13561 N car traveling at 51.1 km/h rounds
a curve of radius 2.95 × 102 m.
The acceleration of gravity is 9.81 m/s
a) Find the centripetal acceleration of the
car. Answer in units of m/s
Find the force that maintains circular motion.
Answer in units of N.
c) Find the minimum coefficient of static friction between the tires and the road that will
allow the car to round the curve safely.
Answer:
a) The centripetal acceleration of the car is 0.68 m/s²
b) The force that maintains circular motion is 940.03 N.
c) The minimum coefficient of static friction between the tires and the road is 0.069.
Explanation:
a) The centripetal acceleration of the car can be found using the following equation:
[tex] a_{c} = \frac{v^{2}}{r} [/tex]
Where:
v: is the velocity of the car = 51.1 km/h
r: is the radius = 2.95x10² m
[tex] a_{c} = \frac{(51.1 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2.95 \cdot 10^{2} m} = 0.68 m/s^{2} [/tex]
Hence, the centripetal acceleration of the car is 0.68 m/s².
b) The force that maintains circular motion is the centripetal force:
[tex] F_{c} = ma_{c} [/tex]
Where:
m: is the mass of the car
The mass is given by:
[tex] P = m*g [/tex]
Where P is the weight of the car = 13561 N
[tex] m = \frac{P}{g} = \frac{13561 N}{9.81 m/s^{2}} = 1382.4 kg [/tex]
Now, the centripetal force is:
[tex] F_{c} = ma_{c} = 1382.4 kg*0.68 m/s^{2} = 940.03 N [/tex]
Then, the force that maintains circular motion is 940.03 N.
c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:
[tex] F_{c} = F_{\mu} [/tex]
[tex] F_{c} = \mu N = \mu P [/tex]
[tex] \mu = \frac{F_{c}}{P} = \frac{940.03 N}{13561 N} = 0.069 [/tex]
Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.
I hope it helps you!
If a student has a mass of 75 kg, what is her weight on Earth?
7.65 N
075N
76.5 N
735 N
Answer:
735
Explanation:
w=mg
w=75*9.8=735N
WHo is Rick...from adult swim
Answer:
rick, also known by his fans as they benevolently call him as "Uncle Rick"
Explanation:
he is the one and only author of his trademark mythology
known best for his PJO, HBO and TOA series, uncle rick is one of the best things to ever happen to this planet
PLEASE HELP!!!!!
When current flows through this wire, what forms around the wire?
A. Electromagnetism
B. An electric field
C. An attraction between charged particles
D. A magnetic field
ONLY REPLY IF YOU KNOW THE ANSWER TO IT
Answer:The answer is A
Explanation:
Answer:
A. Electromagnetism
Explanation:
Whenever current travels through a conductor (the wire) a magnetic field is generated. Due to being a wire, the current formed is electric, so this making it an electromagnetic field.
Help my cat is constipated what do I do
Answer:
Increase Water Consumption
Try a New Diet
Help Your Cat Maintain a Healthy Weight
Increase Exercise and Enrichment
Minimize Stress and Anxiety
Add More Litter Boxes
Try Fiber or Probiotics
Ask Your Vet About Over-the-Counter Laxatives
Explanation:
Hope this helps ;)
An airplane's speed increased from 100m/s to 160m/s, at the average rate of 15m/s^2. How long did it take for the plane to complete this increase in speed?
Answer:
4s
Explanation:
Using the formula of motion as follows:
V = u + at
Where;
V = final velocity (m/s)
U = initial velocity (m/s)
a = acceleration (m/s)
t = time (s)
Based on the provided information, v = 160m/s, u = 100m/s, a = 15m/s², t = ?
V = u + at
160 = 100 + 15t
160 - 100 = 15t
60 = 15t
t = 60/15
t = 4seconds.
Therefore, the time it takes for the plane to complete this increase in speed is 4s.
The pupil of your eye
increases and -decreases in síze -Allows light to enter the eye
-both are true
Answer:
What is the question?
Explanation:
If you tell me the question I can help.
Two pebbles are dropped into a pool of water as shown. If a new wave with a
greater amplitude results, which kind of wave interaction has occurred?
Answer:
Constructive interference
Explanation:
Answer:
C. Constructive interference
Explanation:
What’s the answer????
