Answer:
When an object experiences acceleration to the left, the net force acting on this object will also be to the left.If the mass of the object was doubled, it would experience an acceleration of half the magnitudeExplanation:
When an object experiences acceleration to the left, the net force acting on this object will also be to the left.
From Newton's second law of motion, the acceleration of the object is given as;
a = ∑F / m
a = -F / m
The negative value of "a" indicates acceleration to the left
where;
∑F is the net force on the object
m is the mass of the object
At a constant force, F = ma ⇒ m₁a₁ = m₂a₂
If the mass of the object was doubled, m₂ = 2m₁
a₂ = (m₁a₁) / (m₂)
a₂ = (m₁a₁) / (2m₁)
a₂ = ¹/₂(a₁)
Therefore, the following can be deduced from the acceleration of this object;
When an object experiences acceleration to the left, the net force acting on this object will also be to the left.If the mass of the object was doubled, it would experience an acceleration of half the magnitude
16. A kettle used at a building site is filled with 25 liters of water at 16 °C. The water is heated until it reaches 90 °C. Calculate the amount of heat required in kJ.
Answer:
The Heat is [tex]Q = 7736.7 \ KJ[/tex]
Explanation:
Generally from the question we are told that
The volume of the water is [tex]V = 25 L = \frac{25}{1000} = 0.025 \ m^3[/tex]
The initial temperature is [tex]T_i = 16^oC = 16 + 273 = 289 \ K[/tex]
The final temperature is [tex]T_f = 90^o C = 90 + 273 = 363 \ K[/tex]
Generally the heat required is mathematically represented as
[tex]Q = m * c_w * (T_f - T_i)[/tex]
Here [tex]c_w[/tex] is the specific heat capacity of water with value [tex]c_w = 4182 J/(K kg)[/tex]
m is the mass of the water which is mathematically represented as
[tex]m = \rho * V[/tex]
Here [tex]\rho[/tex] is the density of the water which has a value [tex]\rho = 1000 kg/m^3[/tex]
So
[tex]m = 0.025 * 1000 = 25 kg[/tex]
So
[tex]Q = 25 * 4182 * (363 - 289)[/tex]
=> [tex]Q = 7736700 \ J[/tex]
Converting to KJ
[tex]Q = \frac{ 7736700}{1000}[/tex]
=> [tex]Q = 7736.7 \ KJ[/tex]
Difference between gravity and weight
Answer:
there diferent duh. next time use 69 not 79
Explanation:
Answer:
Weight is a quantity that you measure for a particular object, while gravity is a measure of how curved is the spacetime where that object is living.
Weight is measured is gram while gravity is measured in
newtons per kilogram.
Hope it helps :)
Q3. What is the symbol for a :-
(a) millimeter
(b) micrometer
(c) centimeter
(d) kilometer
(e) metre
(f) nanometer
Explanation:
a. mm
b. μm
c. cm
d. km
e. m
f. nm
A projectile is launched at an angle into the air at velocity v and angle 0. Determine its vertical acceleration.
The answer choices are in the picture.
The acceleration due to gravity only points downward with magnitude g. The angle of the projectile doesn't matter.
A truck heading east has an initial velocity of 6/ms. It accelerates at 2/ms2 for 12 seconds. What distance does the truck travel in the given time
Answer:
216m
Explanation:
As we know S=ut+1/2at^2
S=6×12+1/2×2×12×12
=72+144
=216 m
Using a set of observations to test a hypothesis.
how much higher is 0.25 meters than 0.0254 meters (with real objects)
Answer:
0.2246 meters
Explanation:
.25-0.0254 meters = 0.2246 meters
One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this first snowball, you throw a second one at a low angle timed to arrive before or at the same time as the first one. Assume both snowballs are thrown with a speed of 34.8 m/s. The first one is thrown at an angle of 70◦ with respect to the horizontal.
At what angle should the second snowball be thrown to arrive at the same point as the first?
Answer in units of degrees
Answer:
20 degrees
Explanation:
Given that,
Speeds of both snowballs is 34.8 m/s
The first one is thrown at an angle of 70◦ with respect to the horizontal. We need to find the angle at which should the second snowball be thrown to arrive at the same point as the first.
We need to find the angle at which the second snowball be thrown to arrive at the same point as the first. We can find the distances of both balls and equate them.
It means, range of both projectiles are equal. So,
[tex]\dfrac{u^2\sin2\theta_1}{g}=\dfrac{u^2\sin2\theta_2}{g}[/tex]
We have, [tex]\theta_1=70^{\circ}[/tex]
So,
[tex]\theta_2=\dfrac{1}{2}(\sin^{-1}(\sin2\theta_1))\\\\\theta_2=\dfrac{1}{2}(\sin^{-1}(\sin(140))\\\\\theta_2=20^{\circ}[/tex]
Hence, the second snowball is thrown at an angle of 20 degrees.
Three runners are competing in a 120-m race. Each begins when the starting signal sounds and all three runners cross the finish line at the same time. The first runner moves at a constant speed of 6 m/s. The second runner sprints at a constant speed of 7.5 m/s, stops after 60 m to rest for 4 s, then runs the second half of the race at a constant speed of 7.5 m/s. The third runner dashes 60 m at a constant speed of 12 m/s but realizes they forgot their keys, so runs back to the starting line at a constant speed of 12 m/s, then turns around and runs straight to the finish line at a constant speed of 12 m/s. Which of the following statements about this situation is NOT true?
Assume all average velocities and average speeds are for the period from the starting signal to the moment the runners cross the finish line. You may select more than one option.
a. The average speed of the third runner is not equal to his average velocity
b. The average velocity of the third runner is zero.
c. The first runner's average velocity is equal to the second runner's average velocity
d. The second runner's average speed is less than 7.5 m/s.
e. All three runners have the same average velocity.
Answer:
The correct answer is B is false
Explanation:
This problem highlights the difference between vectors (speed) and scalars (speed)
average speed is defined by
v = Δx / Δt
bold indicates vectors
the average speed is
v= Δx / Δt
Let's calculate
first runner
Δt = Δx / v₁
Δt = 120/6
Δt = 20 s
Second runner
Δt₁ = dx1 / v2
Δt₁ = 60 / 7.5
Δt₁ = 8 s
v₂ = 0
Δt₂ = 4 s
Δt₃ = dx₃ / v₂
Δt₃ = 60 / 7.5
Δt₃ = 8 s
the displacement is Dx = 60 + 60 = 120 m
time is t_total = Δt₁ + Δt₂ + Δt₃
the average speed is
v = Dx / Dt
v = 120 / (8 + 4 + 8)
v = 6 m / s
speed has the same value
third runner
Δt₁ = 60/12
Δt₁ = 5 s
Get back to the finish line
Δt₂ = (-60) / (- 12)
Δt₂ = 5 s
Δt₃ = 120/12
Δt₃ = 10 s
The displacement (vector) is
dx = 60 -60 + 120
dx = 120
Time is t_total = Δt₁ + Δt₂ + Δt₃
veloicity is
v = dx / t_total
v = 120 / (5 + 5+ 10)
v = 6 m / s
the radidity is
the distance (scalar) traveled
dx = 60 +60 + 120
dx = 240 m
time t_total = dt1 + dt2 + dt3
the speed
v = 240 / (20)
v = 12 m / s
with these results we can review the final statements
a) True The speed is twice the speed
b) False The velocity is 6 m / s
c) True the speeds from the three runners are equal
d) True the speeds of all runners are equal
The correct answer is B is false
Give some hypothetical examples where destroying evidence might leave more that could identify you.
A car is coasting to a stop with a constant acceleration. The car was going 35 m/s when the driver started coasting. The car moves 50. m forward while slowing down.
Show this on a vt graph.
Determine the acceleration of the car.
Answer: Plot each graph on the same coordinate system.
35 ( m/ s)
50 m
a v t.
Answer:
I think the car is accelerating at 85 m/s because the car is moving at 35/m plus when it was coasting it went 50.
Explanation:
Sorry I dont have a graph but here is what I think about on the acceleration.
Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the red spectrum rom 675 to 700 nm. 1. What is the mean of the wavelength distribution for this radiation? 2. What is the variance of the wavelength distribution for this radiation? 3. If instead, the wavelengths are uniformly distributed at integer nanometers from 75 to 100 nanometers, how do the mean and variance of the wavelength distribution compare to the original distribution? Briefly explain.
Answer: See explanation
Explanation:
1. What is the mean of the wavelength distribution for this radiation?
Mean = (a+b)/2
= (675 + 700)/2
= 1375/2
= 687.5
2. What is the variance of the wavelength distribution for this radiation?
Variance= {(b-a+1)^2 - 1}/12
= {(700 - 675 + 1)-1}^2/12
= (26^2)-1/12
= 676-1/12
= 675/12
= 56.25
3. If instead, the wavelengths are uniformly distributed at integer nanometers from 75 to 100 nanometers, how do the mean and variance of the wavelength distribution compare to the original distribution?
New Mean = (a+b)/2
= (75 + 200)/2
= 175/2
= 87.5
New Variance= {(b-a+1)^2 - 1}/12
= {(100 - 75 + 1)-1}^2/12
= (26^2)-1/12
= 676-1/12
= 675/12
= 56.25
From the solutions, while the mean differs, the variance (56.25) is thesame due to the fact that variance depends on interval length and the first and second question has same interval length.
Two cars A and B are 100m apart moving towards each other with
velocity 40m and 60m's respectively calculate the time the meet
each other and the time they are 100m apart in their opposite destinations.
Let car A's starting position be the origin, so that its position at time t is
A: x = (40 m/s) t
and car B has position at time t of
B: x = 100 m - (60 m/s) t
They meet when their positions are equal:
(40 m/s) t = 100 m - (60 m/s) t
(100 m/s) t = 100 m
t = (100 m) / (100 m/s) = 1 s
so the cars meet 1 second after they start moving.
They are 100 m apart when the difference in their positions is equal to 100 m:
(40 m/s) t - (100 m - (60 m/s) t) = 100 m
(subtract car B's position from car A's position because we take car A's direction to be positive)
(100 m/s) t = 200 m
t = (200 m) / (100 m/s) = 2 s
so the cars are 100 m apart after 2 seconds.
Which of these is only a physical change?
A. Melting a solid
B. Burning
C. Rusting
D. Forming a precipitate
Mary pushed a box across the floor with 54N to the left and Doug helped her by exerting a force
of 75N to the left and another force of 20N was exerted on the box in the opposite direction,
what is the net force acting on the box? *
Help plzz
There are two containers of equal volumes, each filled with a different gas. Both containers have the same number of moles of gas and are at the same temperature. The molecules of gas in container 1 are four times more massive than the molecules of gas in container 2. The number of moles in container 2 is increased until it is a factor of 4 larger than the number of moles in container
1. The volume and temperature of container 2 remain unchanged. After increasing the number of moles in container
2: Which container, 1 or 2, has a higher pressure, or are they the same? Which container, 1 or 2, has a higher average (rms) speed of gas molecules, or are they the same? Which container, 1 or 2, has a higher average kinetic energy of gas molecules, or are they the same? Which container, 1 or 2, has a higher thermal energy, or are they the same?
Answer:
Molecules in container 2 has a higher pressure.
Molecules in container 2 has a greater rms speed.
Molecules in container 2 has a greater kinetic energy.
Molecules in container 2 has a greater thermal energy.
Explanation:
At constant volume and temperature, The number of moles of a gas is proportional to its pressure.
The lower the pressure, the lesser the rms speed of molecules, kinetic energy of the molecules and thermal energy of the molecules, hence the answer above.
Define physical laws
Answer:
physical law (plural physical laws) A universal statement about the operation of nature, based on empirical observations of physical behavior, tested using scientific method.
Explanation:
noise pollution may cause partial hearing impairment true or false
Answer: True
Explanation: When people pollute it breaks down the earth, that is why icebergs are melting and animals are going extinct. Before we know it, people are gonna start losing hearing, and there brain will shut down. That is also why people should stop polluting.
Which question cannot be answered through making measurements?
A. How much carbon dioxide is released into the atmosphere when a
square mile of tropical rain forest burns?
B. Should the government invest in technologies that can reduce the
rate of global warming?
C. Which human activities contribute to global warming?
D. What is the relationship between carbon dioxide emissions and
average global temperature?
Answer: it would be A
Explanation: how are we to measure the air of a square mile
Answer: Should the government invest in technologies that can reduce the
rate of global warming?
Explanation: Trust me
Solar panels work because photons from the sun give their energy to electrons in the panels (photoelectric effect). At noon on a typical day in San Diego, the power of the visible radiation from the sun is about 225 Watts per square meter. If you had solar panels on your roof covering an area of 2 meters by 6 meters, and the efficiency of the panel was 13% (meaning that 13 out of every 100 photons hitting the panel sent an electron down the wire), how many electrons per second would you get
Answer:
The number of electrons per second received by the panel is 2.19 x 10²¹ electrons/second
Explanation:
Given;
intensity of light, I = 225 W/m²
area of the solar panel, A = 2m x 6m = 12m²
Power of photons hitting the panel = 225 W/m² x 12m² = 2700 W
Power received by the electrons in the panel = 0.13 x 2700 W = 351 W
Energy of these electrons = 351 J/s
The number of electrons per second is given by;
[tex]= \frac{1 \ electron}{1.602*10^{-19} \ J} *\frac{351 \ J}{s} = 2.19*10^{21} \ electrons/second[/tex]
Therefore, the number of electrons per second received by the panel is 2.19 x 10²¹ electrons/second
impulse is the product of a force and the blank during which that force acts
What is the average speed of a dancer who moves 4 meters across the stage in 16 seconds?
Answer:
[tex]v=0.25 \frac{m}{s}[/tex]
Explanation:
Hello,
In this case, since the average velocity is computed as the change in the distance divided by the elapsed time:
[tex]v=\frac{\Delta x}{\Delta t}[/tex]
As 4 m were displaced in 16 seconds, the average speed turns out:
[tex]v=\frac{4m}{16s} \\\\v=0.25 \frac{m}{s}[/tex]
Best regards.
By which method is heat transferred in a microwave oven? A.Conduction B.Convection C.Evaporation D.Radiation if you get it right i will give you a brainliest
What comes to mind when you think of the
word energy?
Think of all of the ways that you have heard
people use that word.
Good energy, Bad energy, Energy used to run, Energy drinks,
PLZZ ANSWER THE QUESTION
Answer:
I think that bicycle B is C 6km/min
hope this helps <3
Let A be the last two digits, and let B be the last three digits, and the C be the sum of the last 4 digits of your 8-digit student ID. (Example: For 20245347, A = 47, B = 347, and C = 19) A train moves at an average speed of (23.0 + A) m/s for (250.0 + B) seconds and then at an average speed of (45.0 + C) m/s for (800.0 + B) seconds. Determine the average speed for the entire time in meters per second (m/s). Round your final answer to 3 significant figures.
Answer:
66.053m/s
Explanation:
A = 47
B = 347
C = 19
Train moves at
(23 + A)m/s
= 23 + 47 = 60m/s
At (250.0+B) seconds
250.0+347 =
547 seconds
Distance d,
= 70 x 597
= 41790
It also moves at
(45.0 + c)
= 45 + 19
= 64m/s
Time = 800 + B
= 800 + 347
= 1147
Distance,
= 64 x 1147
= 73408m
Total distance,
= 73408 + 41790
= 115,198
Total time,
= 597 + 1147
= 1744
Average speed,
= Total distance / total time
= 115198/1174
= 66.053m/s
If a person and wheelchair have a combined weight of 185 lb, how much ideal effort
force is required to travel up the ramp?
Answer:
Effort force[tex]=824.04 \sin\theta[/tex]
where [tex]\theta[/tex] is the angle of inclination of the ramp.
Explanation:
The given combined mass of a person and wheelchair is 185 lb.
In SI unit, 1 pound= 0.453592 kg
So, 185 lb=[tex]185\times0.453592[/tex] kg=84kg (approximately)
Assuming the whole mass as a point mass and denote it by M, so
M=84kg
Let the angle of inclination of the ram with the is [tex]\theta[/tex] with respect to the ground and assume that the friction offered by ram id negligible, so neglection the frictional force.
The applied effort force, F, will be minimum when applied in the direction parallel to the ramp surface as shown in the figure.
The gravitational force action on M is Mg in the downward direction.
For the mass M to be at an equilibrium condition on the ramp, the sum of the total force in any direction will be zero.
Equate the sum of all the forces in the direction parallel to the ramp to zero.
[tex]F-Mg\sin\theta=0[/tex]
[tex]\Rightarrow F=Mg \sin\theta[/tex]
[tex]\Rightarrow F=84\times 9.81\sin\theta[/tex]
[tex]\Rightarrow F=824.04\sin\theta N[/tex].
Forces of 11.9 N north, 19.1 N east, and 14.4 N south are simultaneously applied to a 3.77 kg mass as it rests on a frictionless air table. What is the magnitude of its acceleration?
Help please it’s due by 11:59p
Answer: 6 m/s squared
Explanation:
6m/s squared. Hope this helped
Plz give brainliest
You are at the park with your little brother, when you notice a small merry-go-round with a radius that looks to be about 1.5 m. Your brother climbs on, and you give him a spin. From rest, you speed up smoothly, completing one full lap in 3.0 seconds. You wonder what sort of acceleration (magnitude and direction) your brother experiences at the very start of the motion, and at the very end of the first lap. He is quite young and hasn't studied any physics, so he does not know how to answer your question. You decide to give him your smartphone (which has a built-in accelerometer), and repeat the experiment. What will the smartphone record
Answer:
Explanation:
angle covered in one rotation = 2π radian
θ = ωt + 1/2 αt²
θ is angle rotated in time t with initial angular velocity of ω and angular acceleration α .
Putting the values
2π = 0 + 1/2 x α x 3²
α = 1. 4 radian / s²
linear acceleration = α x r = 1.4 x 1.5 = 2.1 m / s².
Initial acceleration = 2.1 m /s²
final angular velocity = α t = 1.4 x 3 = 4.2 radian / s
linear velocity = 4.2 x 1.5 = 6.3 m /s
centripetal acceleration = v² / R = 6.3² / 1.5 = 26.46 m /s²
radian acceleration = 26.46 m /s
tangential acceleration = 2.1 m /s²
Total final acceleration = √ ( 26.46² + 2.1² )
= √ ( 700.13 + 4.41)
Final acceleration = 26.53 m / s²
The kid will undergo a circular motion and the smartphone which has a built-in accelerometer will record the acceleration [tex]26.54 \,m/s^2[/tex], which is the magnitude of the vector sum of both radial acceleration and tangential acceleration.
Circular MotionThe angle covered in one full rotation, i.e.; the angular displacement is,
[tex]\theta = 2\pi\,\, radian[/tex]
The kinematics equation in the case of rotational motion is given by;
[tex]\theta = \omega_i \,t + \frac{1}{2} \alpha t^2[/tex]
But the initial angular velocity, [tex]\omega_i = 0[/tex]
Time taken to complete one lap is, [tex]t = 3\,s[/tex]
Therefore, substituting the given values in the kinematics equation;
[tex]2\pi \;rad=0 + \frac{1}{2} \alpha\times (3)^2[/tex]
[tex]\implies \alpha = \frac{4 \pi\,\,rad}{9\,s^2} =1.395\,rad/s^2 \approx 1.4\,rad/s^2[/tex]
We know that linear acceleration (here tangential direction) is given by,
[tex]a_T=a = r \alpha = 1.5\,m \times 1.4\; rad/s^2=2.1\,m/s^2[/tex]
Also, the final angular velocity after 3 s is given by;
[tex]\omega_f = \alpha t=1.4\,rad/s^2 \times 3\,s = 4.2\,rad/s[/tex]
Therefore, the final linear velocity is;
[tex]v_f = r \omega = 1.5\,m \times 4.2\,rad/s = 6.3\,m/s[/tex]
We know that the centripetal or the radial acceleration is given by;
[tex]a_r = \frac{v^2}{r} = \frac{(6.3\,m/s)^2}{1.5m}=26.46\,m/s^2[/tex]
Therefore, the total acceleration is given by;
[tex]a_{total} = \sqrt{(a_T)^2 + (a_r)^2\,} =\sqrt{(2.1)^2 + (26.46)^2} =\sqrt{704.54} =26.54 \,m/s^2[/tex]
Learn more about circular motion here:
https://brainly.com/question/2562955
