Answer:
Metal is copper.
Explanation:
Mass of a metal, m = 54 g
Heat energy required, Q = 773 J
The temperature changes from 63.0 °C to 100.0 °C.
We need to identify the metal. Heat required to raise the temperature is given by :
[tex]Q=mc\Delta T[/tex]
c is specific heat of the metal
We can identify the metal by finding its specific heat.
[tex]c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{773}{54\times (100-63)}\\\\=0.386\ J/g^{\circ} C[/tex]
The metal is copper. Its specific heat is [tex]0.386\ J/g^{\circ} C[/tex].
What is the total number of valence electrons in an atom with the electron configuration 2-8-1 ?
A) 1
B) 2
C) 8
D) 11
Answer:
1 because the last one is 1 and the previous shell was complete.
Answer: A)1
Explanation:
Valence electrons are always in Thebes last shell and last number of the configuration.
15 POINTS PLS ANSWER CORRECTLY AND FAST
Drag the tiles to the boxes to form correct pairs.
Read the excerpts from Mark Twain's Adventures of Huckleberry Finn.
Match each of these examples of external conflict with the type of conflich
It reflects.
1. character versus character
2. character versus nature
3. character versus society
a. Huck travels down the dangerous and
long Mississippi River.
b. Huck helps Jim, a runaway slave,
even though he knows his community
would not approve.
c. Huck stops con men named the duke and
Dauphin from cheating the townspeople.
The order it would go in is character versus nature character versus society and finally character versus character
hope this helps
The first example is that of conflict between character versus nature followed by character versus character and character versus society.
What is a conflict?
Conflict is defined as an activity which occurs between two persons who are though conscious but not rational.It is usually defined in terms of wants of a person , needs or obligations.
There are four types of conflict , 1) self conflict which is the conflict with self 2) conflict with others based on differences on opinions 3)conflict with environment in order to adjust withe the environmental problems and 4) conflict with supernatural in opposition to the belief in super natural powers.
Conflict can also be emotional,intellectual as well as theoretical,intellectual conflict is also a sub class of cultural conflict.
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Please, help me
The following reagents are required for laboratory practice.
Answer:
A
Explanation:
Answer:
A is the answer for this question
Write the balanced nuclear equation for the alpha decay of each isotope.
200/84Po
nuclear equation:
thorium-229
nuclear equation:
244/96Cm
nuclear equation:
bismuth-210
nuclear equation:
Explanation:
First, a quick revision of radioactive decay:
During alpha decay, an alpha particle is emitted from the nucleus —- it is the equivalent of a helium atom (i.e. it has a mass of 4 and an atomic number of 2). So, let's take the following question:
Polonium-210 is a radioisotope that decays by alpha-emission. Write a balanced nuclear equation for the alpha decay of polonium-210.
In symbols, the equation becomes
210/84Po--->?+4/2HE
The sums of the superscripts and of the subscripts must be the same on each side of the equation.
Take 4 away from the mass number (210-4 = 206)
Take 2 away from the atomic number (84-2 = 82). Lead is element number 82.
So, the equation is
210/84 Po--->206/82Pb+4/2He
Now let's try one for beta decay — remember that, in beta decay, a neutron turns into a proton and emits an electron from the nucleus (we call this a beta particle)
Write a balanced nuclear equation for the beta decay of cerium-144)
In nuclear equations, we write an electron as 0^-1e.
144/58Ce-->144/59Pr+^0-1e
Here's a fission reaction.
A nucleus of uranium-235 absorbs a neutron and splits in a chain reaction to form lanthanum-145, another product, and three neutrons. What is the other product?
We write a neutron as 1/0n, so the equation is
235/92U +1/0n--->145/57La+X+3 1/0n
Sum of superscripts on left = 236. Sum of superscripts on right = 148. So X
must have mass number = 236 – 148 = 88.
Sum of subscripts on left = 92. Sum of subscripts on right = 57. So X
must have atomic number = 92 – 57 = 35. Element 35 is bromine.
The nuclear equation is
235/92U+1/0n--->145/57La+88/35Br+31/0N
A nuclear decay leads to the formation of a product that has a different isotope from that of the parent.
What is a nuclear equation?A nuclear equation has to do with an equation in which one isotope is transformed into a different isotope.
For 200/84Po;
200/84Po ----> 4/2 He + 196/82Pb
For 244/96Cm
244/96Cm -----> 4/2 He + 240/94Pu
For bismuth-210
210/83Bi -----> 4/2 He + 206/81Tl
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What is the molar mass of 81.50 g of gas
exerting a pressure of 1.75 atm on the
walls of a 4.92 L container at 307 K?
The molar mass of gas = 238.29 g/mol
Further explanationGiven
mass = 81.5 g
P=1.75 atm
V=4.92 L
T=307 K
Required
molar mass
Solution
The gas equation can be written
[tex]\large{\boxed{\bold{PV=nRT}}[/tex]
[tex]\tt n=\dfrac{mass}{molar~mass}[/tex]
So the equation becomes :
[tex]\tt Molar~mass=\dfrac{mRT}{PV}[/tex]
Input the value :
[tex]\tt M=\dfrac{81.5\times 0.082\times 307}{1.75\times 4.92}\\\\M=238.29~g/mol[/tex]
Answer:
239
Explanation:
A student is performing a titration on a solution of HNO3 with an unknown concentration. They used a solution of KOH that they determined the concentration to be 8.2 x 10-2 M beforehand. They use an aliquot of 15.0 mL of HNO3 to titrate.
a. If the equivalence point is reached after the addition of 18.5 mL of titrant, what was the original pH of the analyte? [1.00]
b. What would the pH of the analyte be at the equivalence point? [You should be able to figure this out yourself!]
c. If the student over-titrates the analyte and adds 19.2 mL of titrant, what would the pH of the analyte be? [11.22]
d. If the student under-titrates and only adds 10.0 mL of titrant, what is the pH of the analyte? [1.56]
e. Draw a titration curve for this question.
What happens to sugar in a cup of tea?
How do other factors shape earths surface
Answer:
Other factors shape earths surface are:
Factors that Shape Earth's Surface.
Unit Notes.
Plate Tectonics. Continental Drift. ...
Results of plate movement. ...
Weathering. ...
Erosion and Deposition.
4. A 40.0L tank of ammonia has a pressure of 12.7 kPa. Calculate the volume of the
ammonia if its pressure is changed to 8.4 kPa while its temperature remains constant.
Answer:
V₂ = 60.47L
Explanation:
Given data:
Initial volume = 40.0 L
Initial pressure = 12.7 KPa
Final volume = ?
Final pressure = 8.4 KPa
Solution:
The given problem will be solved through the Boyls law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
12.7 KPa× 40.0 L = 8.4 KPa × V₂
V₂ = 12.7 KPa× 40.0 L/ 8.4 KPa
V₂ = 508 KPa. L / 8.4 KPa
V₂ = 60.47L
The volume of the ammonia gas if it's pressure is changed to 8.4 KPa is 60.5 L
From the question given above, The following data were obtained:
Initial pressure (P₁) = 12.7 KPa
Initial volume (V₁) = 40 L
Final pressure (P₂) = 8.4 KPa
Temperature = constant
Final volume (V₂) = ?Using the Boyle's law equation, the final volume of the ammonia can be obtained as illustrated below:
P₁V₁ = P₂V₂
12.7 × 40 = 8.4 × V₂
508 = 8.4 × V₂
Divide both side by 8.4
V₂ = 508 / 8.4
V₂ = 60.5 LTherefore, the final volume of the ammonia gas is 60.5 L
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Convert 1.5x10^25 atoms of hydrogen into moles of Hydrogen
Why are regions that receive more solar energy more likely to develop hurricanes
Explanation:
Plants are more likely to thrive in those regions. Those regions have more water evaporation. Regions that receive more solar energy are typically drier.
A sample of an unknown metal has a mass of 22.4g. A graduated cylinder contains 3.2 ml of water. After the metal sample is added to the graduated cylinder, the water level reads 4.7 ml. Calculate the density of the metal
Answer:
d = 14.9 g/mL
Explanation:
Given data:
Mass of metal = 22.4 g
Volume of eater = 3.2 mL
Volume of water + metal = 4.7 mL
Density of metal = ?
Solution:
Volume of metal:
Volume of metal = volume of water+ metal - volume of water
Volume of metal = 4.7 mL - 3.2 mL
Volume of metal = 1.5 mL
Density of metal:
d = m/v
d = density
m = mass
v = volume
d = 22.4 g/ 1.5 mL
d = 14.9 g/mL
fully explain, why each characteristic would or would not favor the formation of an amorphous solid
Answer:
Crystalline solids have regular ordered arrays of components held together by uniform intermolecular forces, whereas the components of amorphous solids are not arranged in regular arrays. The learning objective of this module is to know the characteristic properties of crystalline and amorphous solids. When cleaved or broken, they produce fragments with irregular, often curved surfaces; and they have poorly defined patterns when exposed to x-rays because their components are not arranged in a regular array. An amorphous, translucent solid is called a glass.
Which is best represented by the equation?
2Mg + 02 → 2MgO
O A. Law of Conservation of Energy
O B. Law of Conservation of Mass
O C. Law of Superposition
What's the percentage of C in CO2
Answer:
27.29%
Explanation:
What is Entropy of reaction?
Answer:
The entropy change in a chemical reaction is given by the sum of the entropies of the products minus the sum of the entropies of the reactants.
Explanation:
Hope it helps
FOLLOW MY ACCOUNT PLS PLS
Methane CH4 gas and oxygen O2 gas react to form carbon dioxide CO2 gas and water H2O vapor. Suppose you have 11.0 mol of CH4 and 7.0 mol of O2 in a reactor. Suppose as much as possible of the CH4 reacts. How much will be left? Round your answer to the nearest 0.1 mol
Answer:
The number of moles of CH₄ that will remain is 7.5 moles
Explanation:
Complete combustion reaction of oxygen and methane is given as;
CH₄ + 2O₂ → CO₂ + 2H₂O
comparing the number of moles of methane and oxygen in the reaction above, the amount of methane used in the reaction is calculated as follows;
2 moles of O₂ -----------> 1 mole of CH₄
7 moles of O₂ ------------> x moles of CH₄
x = 7 / 2
x = 3.5 moles of CH₄
Total moles of CH₄ in the reactor = 11.0 moles
The number of moles that will remain = 11.0 moles - 3.5 moles
The number of moles that will remain = 7.5 moles
Therefore, the number of moles of CH₄ that will remain is 7.5 moles
which climate zone gets the smallest amount of solar energy throughout the year brainly
giving brainliest
Answer: A.
Explanation: The poles get the least amount of sunlight throughout the year.
Place the following compounds in order from lowest to greatest vapor pressure. CH3CH2CH2CH3 CH3CH2OH CH3CH2CH3 NaF A B C D (Enter the letter corresponding to each compound.)
Answer:
C
Explanation:
There are 3 factors that affect the vapor pressure of a liquid, they are;
surface area
intermolecular forces and
temperature.
If we consider the options, we will notice that NaF is held together by strong ionic bonds in its crystal lattice. Also, CH3CH2OH is held together both by dispersion forces and strong hydrogen bonds.
However, CH3CH2CH2CH3 and CH3CH2CH3 are only held together by weak dispersion forces. Which of them is expected to have the weakest magnitude of intermolecular forces? We must know that larger and heavier molecules exhibit stronger dispersion forces than smaller and lighter ones.
This implies that the magnitude of intermolecular forces in CH3CH2CH2CH3 is much greater than that in CH3CH2CH3. Hence at the same temperature, CH3CH2CH3 has the greatest vapour pressure among the four substances listed in the question.
why are elements in the column with helium so stable ?
Answer:
Explanation:
because they have complete valence shell thats why they are not reactive towards chemical reaction and are quite stable
List 2 differences between an ionic and covalent chemical bond
According to the ,cell theory where do cells come from?
Answer:
cells come from pre existing cells
Write an equation that shows the formation of a cesium ion from a neutral cesium atom.
Answer:
Cesium is an Element in the Periodic table with atomic number 55, symbol Cs and belongs to the first group of the metals which is Alkali metals.
Ionization energy (IE) is defined as the amount of energy consumed by a ground state gaseous atom to discharge an electron which will results in a formation of a Cation
It forms ions be releasing the electron
[tex]Cs(g) + IE[/tex] → [tex]Cs^+ + e^-[/tex] IE= 38.939 KJ
Why do leavening gases expand faster at higher altitudes
Answer:
Cakes, breads and other foods that contain leavening agents rise more quickly at higher altitudes, because gases produced by the agents expand faster than at sea level. The loaves may collapse if the gases dissipate before the proper temperature is reached. Most baking recipes can be adjusted for high altitudes.
Explanation:
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Fe2O3(s) 2Al(s)Al2O3(s) 2Fe(s) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.73 moles of Fe2O3(s) react at standard conditions.
Answer:
[tex]\Delta S=54.3\frac{J}{K}[/tex]
Explanation:
Hello!
In this case, for the given reaction, we can write the equation to compute the entropy change as shown below:
[tex]\Delta s=2\Delta S_{Fe}+\Delta S_{Al_2O_3}-2\Delta S_{Al}-\Delta S_{Fe_2O_3}[/tex]
Letting:
[tex]\Delta s_{Fe}=27.3\frac{J}{mol*K}\\\\ \Delta s_{Fe_2O_3}=84.4\frac{J}{mol*K}\\\\\Delta s_{Al}=28.3\frac{J}{mol*K}\\\\\Delta s_{Al_2O_3}=51.00\frac{J}{mol*K}[/tex]
We obtain the entropy change per mole of Fe2O3(s):[tex]\Delta s=2*27.3\frac{J}{mol*K}+84.4\frac{J}{mol*K}-2*28.3\frac{J}{mol*K}-51.0\frac{J}{mol*K} \\\\\Delta s=31.4\frac{J}{mol*K}[/tex]
Finally, the total entropy change when 1.73 moles of Fe2O3(s) react turns out:
[tex]\Delta s=31.4\frac{J}{mol*K}*1.73mol\\\\\Delta S=54.3\frac{J}{K}[/tex]
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Why it important not to mix the test solution in one well with the solution in another week on your spot plate
Depending on the factors, combining two chemicals that aren't designed to interact might result in an explosion, an unintended chemical reaction, or a misleading result.
What is explosion ?An explosion is a sudden increase in volume accompanied by a tremendous energy release that typically results in the production of high temperatures and the discharge of high-pressure gases. High explosive detonations produce supersonic explosions that move through shock waves.
Explosions often fall into one of three categories: chemical, mechanical, or nuclear. Every kind of explosion has the potential to be devastating and serious, wreaking unimaginable damage on the local populace, environment, and infrastructure.
What causes gamma ray bursts is one of the largest unsolved questions of all. These bursts, which happen around once every day, are the most powerful explosions known to science.
Thus, depending on the factors, combining two chemicals that aren't designed to interact might result in an explosion, an unintended chemical reaction.
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Use the ideal gas law formula (PV = nRT R = 0.0821 L atm/mol K) to determine the volume of 1.00
mole of a gas under the following conditions:
T= 273 K P = 2.00 atm
V=_
IL
T = 546 K, P = 1.00 atm
V =
L L
T = 409.5 K P = 1.50 atm
V=L
Answer:
11.2 , 44.8 , 22.4
Explanation:
on edge
The volume with the help of the ideal gas equation for the first condition is 11.2L, the second condition is 44.8L, and for the third condition is 22.4L.
Ideal gas equation[tex]PV=nRT[/tex]
where P =pressure, V = volume, n = moles of gas, R = rydberg constant, and T = temperature.
Rearrange the above equation for the calculation of Volume as follows,
[tex]V=\frac{nRT}{P}[/tex]
We can calculate the volume for the first condition as follows,
Substitute 0.0821 Latm/Kmol for R, 273 K for T, 2atm for P, 1 for n in the above equation,
[tex]V=\frac{1 mol\times0.0821Latm\ Kmol\times273K}{2 atm} \\=11.20 L[/tex]
For the second condition,
[tex]V=\frac{1mol\times0.0821 L atm/mol K\times546K}{1 atm} =44.8L[/tex]
For third condition,
[tex]V=\frac{1mol\times0.0821 L atm/mol K\times409.5K}{1.50 atm} =22.4L[/tex]
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When bonding to other elements, it is easier for a sodium atom to gain seven electrons than to lose one electron.
Answer:
it's easier to lose one electron because it's less work for the atom to do and easier to lose one than gain a whole 7, because the atom wants to gain a full outer shell as soon as possible
Rhodium crystallizes in a face-centered cubic unit cell. The radius of a rhodium atom is 135 pm. Determine the density of rhodium in g/cm3
Answer:
Density of unit cell ( rhodium) = 12.279 g/cm³
Explanation:
Given that:
The radius (r) of a rhodium atom = 135 pm
The atomic mass of rhodium = 102.90 amu
For a face-centered cubic unit cell,
[tex]r = \dfrac{a}{2\sqrt{2}}[/tex]
where;
a = edge length.
Making "a" the subject of the formula:
[tex]a = 2 \sqrt{2} \times r[/tex]
[tex]a = 2 \times 1.414 \times 135 \ pm[/tex]
a = 381.8 pm
to cm, we get:
a = 381.8 × 10⁻¹⁰ cm
However, recall that:
[tex]density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}[/tex]
where;
mass of unit cell = mass of atom × numbers of atoms per unit cell
Also;
[tex]mass\ of\ atom =\dfrac{ atomic \ mass}{Avogadro \ number}[/tex]
[tex]mass\ of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}[/tex]
Recall also that number of atoms in a unit cell for a face-centered cubic = 4
So;
[tex]mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4[/tex]
mass of unit cell = 6.83380375 × 10⁻²² g
[tex]Density \ of \ unit \ cell = \dfrac{6.83380375 \times 10^{-22}}{(381.8\times 10^{-10})^3}[/tex]
Density of unit cell ( rhodium) = 12.279 g/cm³
The density of rhodium is equal to 12.4g/cm^3
Data;
radius = 135pmatomic mass = 102.90 amuThe radius of a FCC is calculated as
[tex]r = \frac{a}{2\sqrt{2} }\\a = 2\sqrt{2} * r\\a = 2 * 1.414 * 135 = 381.8pm = 381.8 * 10^-^1^0cm\\[/tex]
The Density of RhodiumThe formula of density is given as
[tex]\rho = \frac{mass}{volume}\\[/tex]
The mass of a unit cell = mass of atom * number of atoms per unit cell.
[tex]mass of atom = \frac{atomic mass}{avogadro's number} = \frac{102.90}{6.023*10^2^3}\\[/tex]
For BCC number of atom in unit cell = 4
mass of unit cell = [tex]\frac{102.90}{6.02*10^2^3} * 4[/tex]
This makes the density of the atom equal to
[tex]\rho = \frac{\frac{102.90}{6.02*10^2^3} }{(381*10^-^1^0)^3}* 4\\ \rho = 12.4 g/cm^3[/tex]
The density of Rhodium is 12.4 g/cm^3
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Please I need help!!!!
Answer:
the answer is b I am sure
