Answer:
The total mass of the atmosphere is 4.508 x 10⁹ kg
Explanation:
Given;
thickness of gas layer, h = 6.8 km
density of Earth's atmosphere, ρ = 1.3 kg/m³
the surface area of Earth is given as 5.10 x 10⁸ km²
Volume of the atmosphere is calculated as;
V = Ah
where;
A is the surface area of Earth
h is the thickness of gas layer
V = (5.10 x 10⁸ km²)(6.8 km)
V = 3.468 x 10⁹ km³
The total mass of the atmosphere is calculated as;
mass = density x volume
m = ρV
m = (1.3 kg/m³)(3.468 x 10⁹ km³)
m = 4.508 x 10⁹ kg
Therefore, the total mass of the atmosphere is 4.508 x 10⁹ kg.
A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate
the following ATTENTION：using the energy/work formulae only: 3.The kinetic energy of the Rock half way down ？ 4.the speed of the Rock half way down？
5.The speed of the Rock as it hits the ground？
Answer:
See the answers below.
Explanation:
In order to solve this problem we must use the principle of energy conservation. Which tells us that the energy of a body will always be the same regardless of where it is located. For this case we have two points, point A and point B. Point A is located at the top at 120 [m] and point B is in the middle of the cliff at 60 [m].
[tex]E_{A}=E_{B}[/tex]
The important thing about this problem is to identify the types of energy at each point. Let's take the reference level of potential energy at a height of zero meters. That is, at this point the potential energy is zero.
So at point A we have potential energy and since a velocity of 18 [m/s] is printed, we additionally have kinetic energy.
[tex]E_{A}=E_{pot}+E_{kin}\\E_{A}=m*g*h+\frac{1}{2}*m*v^{2}[/tex]
At Point B the rock is still moving downward, therefore we have kinetic energy and since it is 60 [m] with respect to the reference level we have potential energy.
[tex]E_{B}=m*g*h+\frac{1}{2}*m*v^{2}[/tex]
Therefore we will have the following equation:
[tex](6.5*9.81*120)+(0.5*6.5*18^{2} )=(6.5*9.81*60)+(0.5*6.5*v_{B}^{2} )\\3.25*v_{B}^{2} =4878.9\\v_{B}=\sqrt{1501.2}\\v_{B}=38.75[m/s][/tex]
The kinetic energy can be easily calculated by means of the kinetic energy equation.
[tex]KE_{B}=\frac{1}{2} *m*v_{B}^{2}\\KE_{B}=0.5*6.5*(38.75)^{2}\\KE_{B}=4878.9[J][/tex]
In order to calculate the velocity at the bottom of the cliff where the reference level of potential energy (potential energy equal to zero) is located, we must pose the same equation, with the exception that at the new point there is only kinetic energy.
[tex]E_{A}=E_{C}\\6.5*9.81*120+(0.5*9.81*18^{2} )=0.5*6.5*v_{C}^{2} \\v_{c}^{2} =\sqrt{2843.39}\\v_{c}=53.32[m/s][/tex]
What do C-microwaves reveal to scientists?
Answer:
Different wavelengths of microwaves (grouped into "sub-bands") provide different information to scientists. Medium-length (C-band) microwaves penetrate through clouds, dust, smoke, snow, and rain to reveal the Earth's surface.
A man weighs himself twice in an elevator. When the elevator is at rest, he weighs 824 N; when the elevator starts moving upward, he weighs 932 N. Most nearly how fast is the elevator accelerating, assuming constant acceleration?
a. 0.64 m/s
b. 1.1 m/s^2
c. 1.3 m/s
d. 9.8 m/s^2
Answer: c. 1.3 m/s^2
Explanation:
When he is at rest, is weight can be calculated as:
W = g*m
where:
m = mass of the man
g = gravitational acceleration = 9.8m/s^2
We know that at rest his weight is W = 824N, then we have:
824N = m*9.8m/s^2
824N/(9.8m/s^2) = m = 84.1 kg
Now, when the elevators moves up with an acceleration a, the acceleration that the man inside fells down is g + a.
Then the new weight is calculated as:
W = m*(g + a)
and we know that in this case:
W = 932N
g = 9.8m/s^2
m = 84.1 kg
Then we can find the value of a if we solve:
932N = 84.1kg*(9.8m/s^2 + a)
932N/84.1kg = 11.1 m/s^2 = 9.8m/s^2 + a
11.1 m/s^2 - 9.8m/s^2 = a = 1.3 m/s^2
The correct option is C
is this right? plzz anwser soon
Answer:
yes
Explanation:
Answer:
y e p
Explanation:
HELP ASAP!
Everything on screenshot!
what is happening in terms of matter and energy, while wood burns?
Answer:
The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. For example, when wood burns, the mass of the soot, ashes, and gases, equals the original mass of the charcoal and the oxygen when it first reacted. So the mass of the product equals the mass of the reactant
What average net force is required to accelerate a 3950 kg bus to a speed of 25m/s in 10.5 s?
Answer:
Explanation:
ACCELERATION = CHANGE IN VELOCITY
TIME TAKEN
∴ a = 25 - 0
10.5
∴ a = 50
21
by using f = ma,
we get , f = 3950 × 50
21
∴ A FORCE OF 9404.8 N IS NEEDED TO ACCELERATE A BUS OF 3950 KG.
the combined focal length of two thin lens is 24 cm and the focal length of one converging lens is 8
cm what is the focal length of the other
Answer: f = -12 cm
Explanation: Combined lenses is an array of simple lenses with a common axis. The combination is useful for correction of optical aberrations which cannot be corrected by simple lenses.
When two lenses are in contact and are thin, focal lengths are related as:
[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}[/tex]
If there is a distance between the lenses, the focal length will be:
[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}} -\frac{d}{f_{1}f_{2}}[/tex]
Since the lenses in the question above are thin and in contact, the focal length of one of them will be:
[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}[/tex]
[tex]\frac{1}{f_{2}} =\frac{1}{f_{1}} -\frac{1}{F}[/tex]
[tex]\frac{1}{f_{2}} =\frac{1}{8} -\frac{1}{24}[/tex]
[tex]\frac{1}{f_{2}} =\frac{-2}{24}[/tex]
[tex]f_{2}=[/tex] -12
The focal length of the other lens is -12 cm, with the negative sign meaning it's a converging lens.
If the angle between the net force and the displacement of an
object is greater than 90 degrees, then which option holds
true?
aThe object stops
b Kinetic energy decreases
C Kinetic energy increases
d Kinetic energy remains the same
Answer: kinetic energy decreases
Explanation:
When the angle between the net force and the displacement of an
object is greater than 90 degree, the Kinetic energy decreases.
The work done by a net force in moving an object over a given distance is given as;
[tex]W = F \times d \ cos(\theta)[/tex]
where;
θ is the angle between the net force and the displacementThe value of cos(θ) decreases from 0 to 180, consequently, the value of work-done will decrease as well.
Based on work-energy theorem, the work done on the object is equal to kinetic energy of the object.
[tex]W = K.E[/tex]
Thus, we can conclude that when the angle increases, the Kinetic energy decreases.
Learn more about kinetic energy here:https://brainly.com/question/10063455
Waves transport
over distances.
A. solids
B.
liquids
C.
gases
D.
energy
Answer:
d)energy
Explanation:
Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.
Which of the following is NOT a possible type of law that a government could pass to help fight climate change?
1. Making greenhouses gas production illegal
2. Regulating the amount of greenhouse gases businesses can produce
3. Funding research on technologies that are better for the environment than those we currently use
4. Providing tax incentives for businesses and people to take action
Answer:
4
Explanation:
because people could lie about it
A crate is pulled 7 m across a smooth surface. The tension in the rope pulling the crate is 40 N. If the work on the crate is 247 J, what is the angle the rope makes with the horizontal
Answer:
61.9°
Explanation:
The formula for calculating the workdone is expressed as
Workdone = Fdsin theta
F is the force applied on the crate
d is the distance covered
theta is the angle that the rope makes with the horizontal
Given
F = 40N
d = 7m
Workdone = 247J
Substituting into the formula:
247 = 40(7)sin theta
247 = 280sin theta
sin theta = 247/280
sin theta = 0.88214
theta = arcsin(0.88214)
theta = 61.9°
Hence the angle that the rope makes with the horizontal is 61.9°
A concave lens can be used to produce an enlarged and erect image. True or False?
Answer:
False
Explanation:
A single concave lens has the opposite effect of a magnifying glass.
If the angle between two forces increases, the magnitude of their resultant-
A Decreases
C. Remain unchanged
D. Decrease than decreases
A 3.6kg cat is laying on a tree branch, 3 meters above the ground. What is the cat’s potential energy?
Answer:
E = 105.84 J
Explanation:
Given that,
Mass of cat, m = 3.6 kg
It is laying 3 meters above the ground.
We need to find the cat's potential energy. The formula for the potential energy of an object is given by :
E = mgh
Substituting all the values,
E = 3.6 kg × 9.8 m/s²×3 m
E = 105.84 J
So, the cat's potential energy is 105.84 J.
Hannah, who has a mass of 65 kg, is riding at 25 m/s in her sports car when she must suddenly swerve off the road to avoid
hitting a dog and slams into the guard rail. Her seatbelt brings her to a stop in 0.4 seconds. What amount of force was
exerted on Hannah?
4000 N
4063 N
650 N
O N
Hannah comes to a rest in t = 0.4 s, so her acceleration is
a = (0 - 25 m/s) / (0.4 s) = -62.5 m/s²
(that is, the acceleration points in the direction opposing her movement forward as she brakes)
Then the force exerted on her by the seatbelt has magnitude
F = (65 kg) (62.5 m/s²) = 4062.5 N ≈ 4063 N
A certain planet has a radius of 4990 km. If, on the surface of that planet, a 95.0 kg object has a weight of 591 N, then what is the mass of the planet?

Answer:
3743.489 kg
Explanation:
F_g = 591 N
G = 6.674x10^-11 constant of gravity
m_1 = 95 kg
m_2 = unknown
r = 4990*1000 =
F_g = G[(m_1*m_2)/r^2]
591 N = 6.674x10^-11[(95*m_2)/4990^2]
8.855 = [(95*m_2)/4990^2]
355631.472 = 95*m_2
m_2 = 3743.489 kg
The mass of the planet, which has a radius of 4990 km, is 1.81×10²³kg.
What is Newton's law of universal gravitation ?Newton's law of universal gravitation states that
The force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.
Given parameters:
Mass of the object: m = 95 kg
Radius of the planet: r = 4990 km = 4990 × 1000 m.
Weight f the object: F= 591 N
We know that: universal gravitational constant: G = 6.674x10^-11 SI unit.
We have to find: mass of the planet: M = ?
Now, F= GMm/r^2
591 N = 6.674x10^-11[(95×M)/(4990×1000)^2]
⇒ M =1.81×10²³kg
Hence, mass of the planet is 1.81×10²³kg.
Learn more about gravitational force here:
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A 420 g soccer ball is kicked into the air with an initial velocity of 30 m/s. How much kinetic energy does the soccer ball have?
Answer:189000J
Explanation:KE=1/2mv^2
1/2(420g)(30m/s)^2
=189000J
An object of mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons. Calcuate the acceleration of the object
Answer:
this answer you question
A 4 kg bowling bowl is sitting on a table 1 meter off the ground. How much potential energy does it have?
Answer:
[tex]\huge\boxed{\sf P.E. = 39.2\ Joules}[/tex]
Explanation:
Given Data:
Mass = m = 4 kg
Acceleration due to gravity = g = 9.8 m/s²
Height = h = 1 m
Required:
Potential Energy = P.E. = ?
Formula:
P.E. = mgh
Solution:
P.E. = (4)(9.8)(1)
P.E. = 39.2 Joules
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807fill in the blank:
the more people (greater mass) you load into a car, the ___ (more or less) it will accelerate with the same force applied by the engine.
the more people (greater mass) you load into a car, the more it will accelerate with the same force applied by the engine.
Super fine 40-gauge copper wire has a diameter of only and weighs only . Suppose a spool of 40-gauge wire weighs less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used
This question is incomplete, the complete question is;
Super fine 40-gauge copper wire has a diameter of only 0.080 mm and weighs only 44.5 g/km. Suppose a spool of 40-gauge wire weighs 205 g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used ?
Answer: length of wire to be used is 4.6067 km
Explanation:
Circular diameter = d mm
Linear mass density of wire = μ g/km
let m be the mass of wire un-winded from spool to wind a magnet.
If M is mass of wire initially
then
Δm = M - m { which represents decrease of mass }
Also if L rep the length of wire pulled off,
then
Δm = μ × L grams
⇒ L = Δm/μ km
now given that weight Δm = 205 g and length per unit weight μ = 44.5 g/km
we substitute
L = 205 g / 44.5 g/km
L = 4.6067 km
Therefore length of wire to be used is 4.6067 km
PLEASE ANSWER QUESTION 7!!!! PLEASE
Answer:
Explanation:
The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects
so a option is correct
PLEASE HELP ASAP
ILL GIVE BRAINLIEST
2. What are three crucial pieces of evidence that supports the claim for the Big Bang theory. Include a piece of evidence that relates each of the following:
a. Light spectra
b. Motion of distant galaxies
c. Composition of matter in the universe
3. Explain how or why each piece of evidence supports the claim made in Big Bang theory.
Answer:
The evidence that the universe is expanding comes with something called the red-shift of light. Light travels to Earth from other galaxies. As the light from that galaxy gets closer to Earth, the distance between Earth and the galaxy increases, which causes the wavelength of that light to get longer. Distant galaxies are getting further away hinting at a point of origin. The composition of all observed matter in this universe points at a common origin point for all matter in the universe.
The three crucial evidences that supported the Big Bang theory are the CMB or cosmic microwave background, the expanding universe, the abundance of elements in the universe.
What is Big Bang theory ?Big Bang theory is one of the important theory scientists used in earliest to describe the origin of universe and the phenomenon of evolution.
Here,
2. The Big Bang theory described the origin of universe as an expansion from an atmosphere of high density and extreme temperature which lead to a huge explosion of matter known as the 'Big Bang' and thus creation of the universe.
The three crucial evidences that supported the Big Bang theory are:
The CMB or cosmic microwave background, the expanding universe, the abundance of elements in the universe.
3.(a) Light spectra was an important factor that supported the Big Bang theory mainly by the phenomenon called Doppler shift. Doppler shift occurs when stars move away, they get shifted to longer wavelength. This phenomenon is called red-shift or Doppler's Red shift. This was applicable in the case of Big Bang theory such that the theory claimed that, as a result of explosion which is the Big Bang, the material particles move away. This was similar to the red shift.
(b) The motion of distant galaxies was an evidence of the expansion of universe and soo the Big Bang theory. It was explained in such a way that, as the galaxies move away from us, it shows the more expansion of universe and the time duration since the origin of universe.
(c) The composition of matter in the universe was an important evidence that supported the Big Bang theory. The composition of universe that there is high abundance of hydrogen and helium in the atmosphere was claimed by the Big Bang theory.
Hence,
The three crucial evidences that supported the Big Bang theory are the CMB or cosmic microwave background, the expanding universe, the abundance of elements in the universe.
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what must be photographed with an impression before it is moved or cast ?
WILL GIVE BRAINLIEST TO THE CORRECT ANSWER
Estimate the net force needed to accelerate a 1000-kg car from rest.
AND
Estimate the weight of a 1000-kg car that is accelerating at 3m/s/s.
Answer:
See the answers below.
Explanation:
We can solve both problems using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F =m*a
where:
F = force [N] (units of newtons)
m = mass = 1000 [kg]
a = acceleration = 3 [m/s²]
[tex]F = 1000*3\\F=3000[N][/tex]
And the weight of any body can be calculated by means of the mass product by gravitational acceleration.
[tex]W=m*g\\W=1000*9.81\\W=9810 [N][/tex]
Ben runs from a position 3 m west of Main Street to a new position 45 m
west of Main Street in 6 seconds. What is Ben's velocity?
O
A. 7 m/s east
B. 7 m/s west
C. 8 m/s west
O
O
D. 8 m/s east
SUBMIT
Answer:
Option B. 7 m/s West.
Explanation:
From the question given above, the following data were obtained:
Position 1 (P₁) = 3 m West
Position 2 (P₂) = 45 m West
Time (t) = 6 s
Velocity (v) =?
Next, we shall determine the displacement of Ben. This can be obtained as follow:
Position 1 (P₁) = 3 m West
Position 2 (P₂) = 45 m West
Displacement =?
Displacement = P₂ – P₁
Displacement = 45 – 3
Displacement = 42 m West
Finally, we shall determine the velocity of Ben. This can be obtained as follow:
Time (t) = 6 s
Displacement (d) = 42 m West
Velocity (v) =?
v = d/t
v = 42 m West / 6 s
v = 7 m/s West
Thus the velocity of Ben is 7 m/s West
You push your friend, whose mass is 54kg, down a hill so she can go sledding. Her acceleration is 3m/s2. Calculate the amount of force you applied to your friend.
Answer:
18 newtons
Explanation:
Divide weight by speed
use particle motion to explain what happens when molten steel becomes a steel beam to be used in construction.
Explanation:
A molten steel is in a liquid phase of matter. It has no defined volume of shape at this state. The particles inside this materials in this form is randomized by they are still attached to each other.
On cooling, when the molten steel solidifies and sets into a solid steel beam, the particles take up a fixed position and forms a definite shape and this confers a definite volume on them. The randomized particles stops and forms fixed crystals about their lattice. This way, the beam can carry and support a fixed amount of load.Two displacement vectors have magnitudes of 5.0 m and 7.0 m, respectively. If these two vectors are added together, the magnitude of the sum
Answer:
8.6m
Explanation:
Step one:
given data
we are given two displacement vectors of magnitudes 5 and 7m
Let us assume they are in the same direction and they are acting perpendicular to each other.
Step two:
The magnitude of the vector sum is the resultant vector
which is found by
R^2=5^2+7^2
R^2= 25+49
R^2=74
R=√74
R=8.6m
