Answers
We start by counting the number of atoms of each element on each side of the reaction.
Now we balance the reaction by trial and error, starting with chlorine. We have 2 chlorine atoms in the reactants and 3 clear atoms in the products, so to balance we cross the coefficients placing 3 on the reactant side and two on the product side in the respective molecules:
[tex]3Mg_{}Cl_2+Cr_2O_3\rightarrow MgO+2CrCl_3[/tex]Now we continue with the oxygens, we have 3 oxygens on the reactant side and 1 on the products, so we put the coefficient 3 on the products side in front of the respective molecule:
[tex]3Mg_{}Cl_2+Cr_2O_3\rightarrow3MgO+2CrCl_3[/tex]We now have the balanced equation. We have 3 Mg atoms, 6 Cl atoms, 2 Cr atoms, and 3 O atoms on each side of the reaction.
Related Questions
a) A solution of sodium thiosulfate, Na2S2O3, is 0.1047 M. 18.59 mL of this solution reacts with 38.62 mL of I2 solution. What is the molarity of the I2 solution?
2(Na2S2O3) + I2↔Na2S4O6 + 2(NaI)
b) 26.64 mL of the I2 solution from above is required to titrate a sample containing As2O3. Calculate the mass of As2O3 (197.8 g/mol) in the sample.
As2O3 + 5(H2O) + 2I2 → 2(H3AsO4) + 4HI
Answers
From the calculations, the molarity of the iodine solution is 0.025 M and the mass of the arsenic oxide solution is 0.066 g.
What is the molarity?Let us recall that the molarity is defined as the ratio of the number of moles to the volume of the solution. It is a measure of the amount of substance present. Ley us now try to use what we know to obtain the molarity of the solution in each of the cases of the questions.
a) Using;
CAVA/CBVB = NA/NB
CA = Amount of thiosuphate
CB = Amount of iodine
VA = volume of thiosuphate
VB = volume of iodine
NA = number of moles of thisulphate
NB = Number of moles of iodine
Hence;
0.1047 M * 18.59 mL/CB * 38.62 mL = 2/1
0.1047 M * 18.59 mL * 1 = CB * 38.62 mL * 2
CB = 0.1047 M * 18.59 mL * 1 /38.62 mL * 2
CB = 1.946/77.2
CB = 0.025 M
b) Using the formula;
Number of moles = concentration * volume
Number of moles = 0.025 M * 26.64 /1000 L
= 6.66 * 10^-4 moles
Again;
1 mole of the arsenic oxide reacts with 2 moles of iodine solution
x moles of the arsenic oxide reacts with 6.66 * 10^-4 moles of iodine
x = 1 mole * 6.66 * 10^-4 moles/ 2 moles
x = 3.33 * 10^-4 moles
Mass of the arsenic oxide = 3.33 * 10^-4 moles * 197.8 g/mol
= 0.066 g
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A 150 g piece of iron (Cp = 25.09 J/(mol-°C)) was heated to a temperature of
47°C and then placed in contact with a 275 g piece of copper at 20°C (Cp = 25.46
J/(mol-°C)). What is the final temperature of the two pieces of metal?
Answers
Final temperature of the two pieces of metal is 32.25°C
Temprature is the degree of hotness or coldness of the object
Here given data is
Mass of iron = 150 g
Mass of copper = 275 g
Specific heat of iron = 25.09 J/mol°C
Specific heat of copper = 25.46J/mol°C
Temprature in iron = 47°C = initial temprature = T₁
Temprature in copper = 20°C = initial temprature = T₁'
So here we have to find final temprature of two pieces of metal =?
So, the formula is Q =mcΔT
Q = (150 g - 275 g) × (25.09 J/mol°C - 25.46J/mol°C) × ( 47°C-20°C )
Q = 125×0.37×27
Q = 243 J
243 J/125×0.37 = 5.25°C = change in temprature
Initial temprature = 27°C
Final temprature = ?
ΔT = T₂ - T₁
27°C = T₂ - 5.25°C
T₂ = 27°C + 5.25°C
T₂ = 32.25°C
Final temperature of the two pieces of metal is 32.25°C
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What is the Organic compound shown? A) PropyneB) 1-ButeneC) 1-ButyneD) Acetylene
Answers
ANSWER
1-Butyne
STEP-BY-STEP EXPLANATION:
To name the below structure, we need to consider the following
0. The number of carbon atoms present in the structure
,1. The type of bond and the location
According to the structure given, we have four carbon atoms
These four carbon atoms mean Butane according to the alkane family
We have a tripple bond in between the first and second carbon atom
Since we have a tripple bond, the -ane in butane will be changed to -yne
Hence, the name of the structure is 1-Butyne
Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will form, enter its empirical formula in the last column.
Answers
1) A precipitate called [tex]Fe(OH)_{2}[/tex]
2) A precipitate is formed called [tex]Mg(CH_{3} COO)_{2}[/tex]
What is a precipitate?The term precipitate is used to describe the product that is formed when there is a reaction between two aqueous phase reactants that leads to the formation of a solid product from the reaction as we can see from the image that is attached.
we now have to look at the reactions as we can see them in the mage that is attached. We must note that we can only say that a precipitate has been formed if the product is solid after we have mixed the aqueous phase reactants.
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I get 11 pls help and see if I’m right
Answers
Answer
None of these
Explanation
The option for 2-bromo-5propylbenzaldehyde does not seem to be provided
A cheeseburger from a fast food restaurant contains 19 g of fat, 20 g of carbohydrates and 28 g of protein. How many kcal of energy does the cheeseburger contain? (Food caloric values are 9.0 kcal/g for fats, 4.0 kcal/g for carbohydrates and 4.0kcal/g for protein). Round the answer for each type of food to the nearest tens place. A. 70. kcal B. 360 calories C. 17 calories D. 630 calories
Answers
Answer:
Example:
Here, we want to get the kcal of energy contained in the cheeseburger
To do this, we multiply the caloric values of each food type by their masses and then sum
Mathematically, we have that as:
[tex]19(9)\text{ + 20\lparen4\rparen + 28\lparen4\rparen = 363 kcal}[/tex]To the nearest tens, we have that as 360 kcal
I need help to this problem
Answers
The energy efficiency of this rotating space heater is equal to: C. 64%.
What is energy efficiency?Energy efficiency can bed defined as a process that involves the use of less energy to provide goods and services or perform the same task. This ultimately implies that, energy efficiency helps to reduce air pollution and degradation of the environment.
How to determine the efficiency of this space heater?Mathematically, energy efficiency can be calculated by using this formula:
Energy efficiency = WO/WI × 100
Where:
WO represents the output energy.WI represents the input energy.Note: the amount of energy that was used to produced thermal energy represents the output energy used for heating the room.
Substituting the given parameters into the formula, we have;
Energy efficiency = 896/1,400 × 100
Energy efficiency = 0.64 × 100
Energy efficiency = 64%.
In this context, we can reasonably infer and logically deduce that the space heater's efficiency is equal to 64 percent.
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Complete Question:
A rotating space heater used 1,400 joules of energy while heating a room. Of that total, 896 joules produced thermal energy, 181 joules produced kinetic energy, 203 joules produced light energy, and 120 joules produced sound energy. What is the space heater's efficiency?
O 156.25%
O 36%
O 64%
O 56.25%
Which of the following statements about temperature scales are correct? Select all that apply.
Zero on the Kelvin scale corresponds to absolute zero.
The Kelvin and Fahrenheit scales are commonly used in chemistry.
The units the Celsius and Fahrenheit scales are both called degrees.
Water boils at 273 K on the Kelvin scale.
Answers
Zero on the Kelvin scale corresponds to absolute zero this statements about temperature scales is correct
What is Temperature scales ?Using a beginning point (0 or zero) and a unit of measurement, a temperature scale can be used to indicate or measure temperature. This is typically accomplished by designating certain physical events as occurring at 0 and 100 degrees Fahrenheit, respectively, at specific temperatures, such as the freezing and boiling points of water.
The Fahrenheit and Celsius (Centigrade) systems are the two most often used temperature scales. Due to the fact that all molecular activity stops at the zero points of the Rankin and Kelvin scales, two other scales, they are known as the absolute scales. This location is referred to as absolute zero.Learn more about Temperature scales here:
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A 5.325-gram sample of methyl benzoate, a compound used in the manufacture of perfumes, is found to contain 3.758 g carbon, .316 g hydrogen, and 1.251 grams of oxygen. What is the empirical formula for this substance?
Answers
Answer
The empirical formula for the compound is C₄H₄O₁Explanation
Given:
Mass composition: 3.758 g carbon, 0.316 g hydrogen, and 1.251 grams oxygen.
What to find:
The empirical formula for the substance.
Step-by-step solution:
The first step is to convert the number of grams of each element into moles as shown below using the molar masses of H = 1.00784 g/mol and C = 12.011 g/mol and O = 15.999 g/mol
Note: Mole = Mass/Molar mass
Moles C = 3.758g/12.011 g/mol = 0.31 mol
Moles H = 0.316g/1.00784 g/mol = 0.31 mol
Moles O = 1.251g/15.999 g/mol = 0.078 mol
Now, let's divide the number of moles of each element by the smallest number obtained:
C = 0.31/0.078 = 4
H = 0.31/0.078 = 4
O = 0.078/0.078 = 1
The empirical formula for the compound is C₄H₄O₁
I need help on balancing the equations and on what type of reaction it is.
Answers
Given the balanced chemical reaction expressed as:
[tex]2Au_2O_3\rightarrow4Au+3O_2[/tex]A Redox reaction is a reaction that involves the transfer of electrons and changes in the oxidation state between the elements.
The given chemical equation is therefore an oxidation-reduction reaction since it involves a change in the oxidation state of the elements.
Determine the moles of Au₂O₃
[tex]\begin{gathered} \text{Mole = }\frac{Mass}{Molar\text{ mass}} \\ \text{Mole of Au}_2O_3=\frac{10g}{441.93g\text{/mol}} \\ \text{Mole of Au}_2O_3=0.02263\text{moles} \end{gathered}[/tex]According to stochiometry, you can see that 2 moles of Gold(III)oxide produce 4 moles of Gold. Hence the moles of Gold produced will be:
[tex]\begin{gathered} \text{moles of Gold=}\frac{0.02263\times4}{2} \\ \text{moles of Gold=}0.02263\times2 \\ \text{moles of Gold=}0.0453\text{moles} \end{gathered}[/tex]Determine the mass of Gold.
[tex]\begin{gathered} \text{Mass of Gold=moles}\times molar\text{ mass} \\ \text{Mass of Gold=}0.0453\times196.97 \\ \text{Mass of Gold}=8.91\text{grams} \end{gathered}[/tex]Next is determining the mole of Oxygen
According to stochiometry, you can see that 2 moles of Gold(III)oxide produce 3 moles of Oxygen. Hence the moles of Oxygen produced will be:
[tex]\begin{gathered} \text{moles of Oxygen=}\frac{0.02263\times3}{2} \\ \text{moles of Oxygen}=0.033945\text{moles} \end{gathered}[/tex]Determine the mass of oxygen produced
[tex]\begin{gathered} \text{Mass of O}_2=moles\times\text{Molar mass} \\ \text{Mass of O}_2=0.033945\times16 \\ \text{Mass of O}_2=0.543\text{grams} \end{gathered}[/tex]Hence the mass of oxygen produced is 0.543 grams
If you start with 29.0 grams of Ca(OH)2 and 12.5 grams of HCI how many moles of water can be formed?
Answers
Answer
The moles of water that will be produced = 0.343 mol
Explanation
Given:
Mass of Ca(OH)2 = 29.0 g
Mass of HCl = 12.5 g
We know the reaction : Ca(OH)2 + 2HCI —> CaCI2 + 2H2O
Molar mass of Ca(OH)2 = 74.093 g/mol
Molar mass of HCl = 36.458 g/mol
Molar mass of H2O = 18.015 g/mol
Required: Moles of water that will be formed
Solution:
Use the stoichiometry to find the moles of water using both the reactants.
For Ca(OH)2:
[tex]\begin{gathered} 29.0\text{ g Ca\lparen OH\rparen}_2\text{ x }\frac{1\text{ mole Ca\lparen OH\rparen}_2}{74.093\text{ g Ca\lparen OH\rparen}_2}\text{ x }\frac{2\text{ mol H}_2O}{1\text{ mol Ca\lparen OH\rparen}_2} \\ \\ =\text{ 0.783 mol H}_2O \end{gathered}[/tex]For HCl
[tex]\begin{gathered} 12.5\text{ g HCl x }\frac{1\text{ mol HCl}}{36.458\text{ g}}\text{ x }\frac{2\text{ mol H}_2O}{2\text{ mol HCl}} \\ \\ =\text{ 0.343 mol H}_2O \end{gathered}[/tex]HCl will produce less moles of H2O, thus HCl is the limiting reactant/reagent and the moles of water that will be produced = 0.343 mol
Which of the following statements does not describe the structure of an atom?
The electron cloud is a small and compacted space around the nucleus.
Inside the nucleus of an atom are protons and neutrons.
Protons are positively charged sub-atomic particles.
Electrons are negatively charged sub-atomic particles.
Answers
Answer:
A. The electron cloud is a small and compacted space around the nucleus.
Explanation:
Hope this helps! :))
What is the largest possible electronegativity difference for a bond to be covalent?A.0.5B.1.7C.0.0D.1.0
Answers
Answer
B. 1.7
Explanation
As a rule, an electronegativity difference of 2 or more on the Pauling scale between atoms leads to the formation of an ionic bond. A difference of less than 2 between atoms leads to covalent bond formation.
Therefore, the largest possible electronegativity difference for a bond to be covalent is 1.7
Calculate the number of molecules in 2.37 g of c3H8 (molar mass 44.11 g/mol)
Answers
Step 1
Avogadro's number states that:
1 mole of C3H8 = 44.11 g of C3H8 = 6.02x10^23 formula units (molecules in this case)
---------
Step 2
Information provided:
2.37 g C3H8
The molar mass = 44.11 g/mol
---------
Step 3
Procedure:
44.11 g C3H8 ---------- 6.02x10^23 molecules of C3H8
2.37 g C3H8 ---------- X
X = 2.37 g C3H8 x 6.02x10^23 molecules of C3H8/44.11 g C3H8
X = 3.23x10^22 molecules of C3H8
Answer: Please, revise your options because I cannot find any mistake in my procedure. (Ask your teacher, please)
I found 3.23x10^22 molecules of C3H8 but there is no option alike.
Use the chemical equation to answer the questionCo(H0+4Cr+heat CoCl₂ + 6H₂OCobalt ions form complex ions with water and chloride. The Co(H₂O) ions are pink, and the CoCions are blue. A scientist creates a solution that is purple at equilibrium. How can thescientist make the solution more pink?(2 point)O by adding hydrochloric acid (HCI)Oby adding Co(H₂O) ionsO by adding water (H₂O)
Answers
Answer
By adding water (H2O)
Explanation
In this reaction, water is a product, adding the product will favour the reverse reaction, which is the formation of more Co(H2O)6^2+.
HELP ASAP PLEASE. A legend is a traditional story that explains something in real life. Sometimes they are accepted as true, but sometimes they are fantastical and just plain fun. There are many legends that surround the North Star explaining its creation as well as why it is stationary.
Take some time to research some of the legends of the North Star. After you have had a chance to read several of them, create your own fantastical story of the North Star. It can be how it came to be or explain why it is stationary.
Answers
A legend of the North star goes as follows:
Once upon a time, when God was creating the universe, the curious star Tam once he learned that God was humans on earth, he began visiting humans. He became fond of one human. But each time he had to return to the sky, the human could not see him again. Therefore, he decided to remain stationary so that the human can always locate him.What is the North Star?The North star is a star that sits directly above the North pole of the earth. It is also known as Polaris.
The North star is especially significant in that the North star is an ever-present star in the skies. It neither rises nor sets unlike other stars in the skies.
Because of this special feature of the North star, it serves as a guiding beacon in the skies for travelers. Also, several legends have been told about the North star.
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Calculate the volume of 0.875 mol/dm3 NaOH solution needed to make up a 100.0 ml of a diluted solution with a concentration of 0.235 mol/dm3 NaOH.
Answers
The volume of 0.875 mol/dm³ NaOH solution needed to make up a 100.0 ml of a diluted solution with a concentration of 0.235 mol/dm³ NaOH is 73.15 mL.
Given that :
molarity M1 = 0.875 mol/ dm³
M2 = 0.235 mol/ dm³
volume V2 = 100mL
using the formula , we get
M1 V1 = M2 V2
substituting the values in the formula we get :
0.875 × V1 = 0.235 × 100 mL
V1 = 26.857 mL
the volume added = V2 - V1 = 100 mL - 26.85 = 73.15
Thus, The volume of 0.875 mol/dm³ NaOH solution needed to make up a 100.0 ml of a diluted solution with a concentration of 0.235 mol/dm³ NaOH is 73.15 mL.
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What do I do to fill out the table, what belongs where ?
Answers
1) Write the proper formula for Mg2+ and Br-
Balance the charges.
Mg2+: Multiply by 1. This gives a total of two positive charges.
Br-: Multiply by 2. This gives a total of two negative charges.
Use multipliers as subscripts
[tex]\text{MgBr}_2[/tex]2) Write the proper formula for Al3+ and O2-
Al3+: Multiply by 2. This gives a total of six positive charges.
O2-: Multiply by 3. This gives a total of six negative charges.
Use multipliers as subscripts
[tex]Al_2O_3[/tex]Write a balanced chemical reaction for each of the following double replacement reactions:
a. Hydrochloric acid reacts with sodium hydroxide.
b. Hydrochloric acid reacts with barium hydroxide.
c. Hydrochloric acid reacts with ammonium hydroxide
Answers
Balanced chemical reaction for each of the following double replacement reactions:
a) HCl + NaOH -----> NaCl + H₂O
b) 2HCl + Ba(OH)₂ ----> BaCl₂ + 2H₂O
c) 3HCl + Al(OH)₃ ----> AlCl₃ + 3H₂O
Balanced chemical reaction is when the number of atoms in the reactant sides are equal to the no. of atoms in product side.
a) Hydrochloric acid reacts with sodium hydroxide.
HCl + NaOH -----> NaCl + H₂O
b) Hydrochloric acid reacts with barium hydroxide.
2HCl + Ba(OH)₂ ----> BaCl₂ + 2H₂O
c) Hydrochloric acid reacts with ammonium hydroxide
3HCl + Al(OH)₃ ----> AlCl₃ + 3H₂O
Thus, Balanced chemical reaction for each of the following double replacement reactions:
a) HCl + NaOH -----> NaCl + H₂O
b) 2HCl + Ba(OH)₂ ----> BaCl₂ + 2H₂O
c) 3HCl + Al(OH)₃ ----> AlCl₃ + 3H₂O
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I keep getting 37.5 KPA but apparently that isn't the answer can anyone help?
Answers
ANSWER
The pressure of the gas is 281.25 mmHg
EXPLANATION
Given that;
The initial pressure of the gas is 75 mmHg
The intial temperature of the gas is 80K
The final temperature of the gas is 27 degrees Celcius
Follow the steps below to find the final pressure of the gas
Step 1; Convert the final temperature to degrees kelvin
[tex]\text{ T K = t}\degree C\text{ + 273.15}[/tex][tex]\begin{gathered} \text{ T K = 27 + 273.15} \\ \text{ T K = 300.15K} \end{gathered}[/tex]Step 2; Apply the Gay Lussac's law
[tex]\text{ }\frac{\text{ P1}}{\text{ T1}}\text{ = }\frac{\text{ P2}}{\text{ T2}}[/tex][tex]\begin{gathered} \text{ }\frac{\text{ 75}}{\text{ 80}}\text{ = }\frac{\text{ P2}}{\text{ 300.15}} \\ \text{ cross multiply} \\ \text{ 75 }\times\text{ 300.15 = P2 }\times\text{ 80} \\ 22511.25\text{ = 80 P2} \\ \text{ Divide both sides by 80} \\ \text{ P2 = }\frac{\text{ 22511.25}}{\text{ 80}} \\ \text{ P2 = 281.25mmHg} \end{gathered}[/tex]Classify CH3CH2NH2 as astrong base or a weak base.Strong BaseWeak Base
Answers
Answer:
CH3CH2NH2 is a weak base.
Explanation:
CH3CH2NH2 is a weak base since its Kb is small, and thus it partially dissociates.
Find the percentage by mass of I in CaI2 if it is 13.6% Ca by mass. (Round your answer to one decimal place.) %
Answers
First, we have to remember what a mass percentage means (in this particular case):
It is the amount of each element in a compound, and it is calculated as follows:
[tex]\%\text{ m/m = }\frac{mass\text{ of the element}}{mass\text{ of the compound}}*100\text{ }[/tex]The addition of the different mass percentages is equal to 100%.
In this case, we have the percentage of one of the elements of the compound, we can make the respective subtraction:
[tex]\%I\text{ = 100 - 13.6 = 86.4 \%}[/tex]Then, the answer is that the iodine mass percentage is 86.4%
what is the volume (in L) in a cylinder filled with 23.0 g of N2 gas at a temperature of 65 C and a pressure of 2.37 atm?
Answers
The volume of the cylinder filled with 23.0 g of N₂ gas at a temperature of 65 °C and a pressure of 2.37 atm is 9.6 L
Given that,
Mass of the nitrogen gas in the cylinder (m) = 23 g
Temperature (T) = 65 ℃ = 65 + 273 = 338 K
Pressure (P) = 2.37 atm
R (gas constant) = 0.082057338 L.atm.K⁻¹.mol⁻¹
In Ideal gas law or general gas equation,
PV = nRT
Number of moles in nitrogen (n) = Given mass (m) of nitrogen/ Molar mass of nitrogen
Given mass (m) = 23 g
Molar mass of Nitrogen = 28 g/mol
Number of moles of nitrogen (n) = 23 / 28 = 0.82 moles of nitrogen
PV = nRT
2.37 * V = 0.82 * 0.0821 * 338
2.37 * V = 22.75
V = 22.75 / 2.37
V = 9.6 L
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A 1.6700 g sample of pure compound was analyzed and found to contain 0.1870 ghydrogen, 0.8899 g carbon with the remainder being oxygen. What is the molecularformula of the unknown compound if its molar mass is 90.14 g/mol.?
Answers
Answer: C4H10O2
Explanation:
At first find the percentage composition, in 1.67 g compound what percentage of Carbon, Hydrogen and Oxygen are there. Then from those percentages through unitary method find out how much Carbon, Hydrogen and Oxygen would be there in 90.1 g of compound. From those amounts finds their mole number, as in divide the obtained amount by their gram equivalent mass. The numbers you obtain are the corresponding number of Carbon Hydrogen and Oxygen in one molecule of the compound. Hope this helps
Which is a common use for a type of electromagnetic radiation?
A tanning bed uses microwaves.
Water purification uses radio waves.
Thermal imaging uses infrared waves.
Weather radar uses ultraviolet waves.
Answers
Common use for a type of electromagnetic radiation is Thermal imaging uses infrared waves.
When magnetic field comes in contact with electric field than electromagnetic radiations are formed. The magnetic field and the electric field are perpendicular to each other. types of electromagnetic waves are : Radio waves, Microwaves, Infrared waves, Visible light , Ultraviolet waves, X- rays , gamma rays.
A tanning bed uses the ultraviolet waves
water purification uses the UV waves
Thermal imaging uses the infrared waves
weather radar use the Radio waves
Thus, Common use for a type of electromagnetic radiation is the Thermal imaging uses infrared waves.
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I need help regarding the theoretical yield. Why are we doing 6 / 3 in the second step? (20 POINTS)
Answers
In calculating the theoretical yield of ammonia, the 6/3 done in the second step is to convert moles of hydrogen to moles of ammonia since the mole ratio of hydrogen to ammonia is 3 : 2.
What is the theoretical yield of a reaction?The theoretical yield of a reaction is the maximum amount of product that can be obtained from a given reaction based on the equation of the reaction.
The theoretical yield of a reaction is obtained from the mole ratio of the limiting reagent and the product of the reaction.
Considering the given reaction whose reaction equation is given below:
N₂ (g) + 3 H₂ (g) ---> 2 NH₃ (g)
Hydrogen is given as the limiting reagent:
The amount of hydrogen present 12 g
Moles of hydrogen = 12 g/ 2 g/mol = 6 moles
Mole ratio of ammonia to hydrogen = 3 : 2
Moles of ammonia produced = moles of hydrogen * mole ratio of ammoia to hydrogen
Moles of ammonia = 6 moles * 2/3 moles = 4 moles
Mass of ammonia produced = 4 moles * 17 g/mol
Mass of ammonia produced = 68 g
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At 302 K , to what pressure can the carbon dioxide in the cartridge inflate a 3.05 L mountain bike tire? (Note that the gauge pressure is the difference between the total pressure and atmospheric pressure. In this case, assume that atmospheric pressure is 14.7 psi .)
Answers
Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore the carbon dioxide in the cartridge inflate a 3.05 L mountain bike tire to 104.3psi pressure.
What is ideal gas equation?Ideal gas equation is the mathematical expression that relates pressure volume and temperature.
Mathematically,
PV=nRT
where,
P = pressure
V= volume=3.05 L
n =number of moles=1mole(assumed as it is not given in question)
T =temperature = 302 K
R = Gas constant = 0.0821 L.atm/K.mol
P × 3.05 L =1 mole× 0.0821 L.atm/K.mol × 302 K
P =8.12atm
1 atm = 14.7 psi
Hence Pressure in psi = 8.12atm×14.7 psi = 119.49 psi
Pressure by the gas= Total pressure - Atmospheric pressure = 119.49 - 14.7 psi = 104.3psi
Therefore the carbon dioxide in the cartridge inflate a 3.79 L mountain bike tire to 104.3psi pressure.
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How many molecules of ethane gas, C2H6 are in 15 grams of the compound?
Answers
3.01×10²³molecules.
Explanations:
The formula for the number of molecules of a compound given the number of moles is expressed as:
[tex]nu\text{mber of molecules=moles}\times6.02\times10^{23}[/tex]Get the moles of ethane gas using the formula:
[tex]\begin{gathered} \text{moles of ethane=}\frac{Mass\text{ of ethane}}{Molar\text{ mass of ethane}} \\ \text{Moles of ethane=}\frac{15}{2(12)+1(6)} \\ \text{Moles of ethane}=\frac{15}{30}\text{moles} \\ \text{Moles of ethane}=0.5\text{moles} \end{gathered}[/tex]Determine the required number of molecules of ethane
[tex]\begin{gathered} nu\text{mber of mol}ecules=0.5\times6.02\times10^{23} \\ nu\text{mber of mol}ecules=3.01\times10^{23} \end{gathered}[/tex]Hence the molecule of ethane gas that is in 15 grams of the compound is 3.01×10²³molecules.
Andrew wants to become a certified forensic pathologist. What is MOST likely to be true about his path to achieve this goal?
A.
It is fairly easy and doesn’t take a long time.
B.
There is no required residency or clinical fellowship.
C.
It requires a medical degree like a regular doctor.
D.
There are no schools that are currently offering this training.
Answers
Answer:
A
Explanation:
it is easy and doesn't take a long time
Starting with a gas of N2 in a balloon of temperature 148.5°C and volume 241.8mL, what is its final volume if you cool it to -96.4°C?
Answers
Answer
101.3 mL
Explanation
Given:
The initial temperature, T₁ = 148.5 °C = (148.5°C + 273) = 421.5 K
The initial volume, V₁ = 241.8 mL
Final temperature, T₂ = -96.4 °C = (-96.4°C + 273) = 176.6 K
What to find:
The final volume of the gas.
Step-by-step solution:
The final volume, V₂ of the gas can be calculated using Charle's law formula.
[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \\ \Rightarrow V_2=\frac{V_1\times T_2}{T_1}=\frac{241.8mL\times176.6K}{421.5K}=\frac{42701.88\text{ }mL}{421.5} \\ \\ V_2=101.3\text{ }mL \end{gathered}[/tex]The final volume of the gas is 101.3 mL
