Answer:
4.06 x 10⁴kg
Explanation:
Given parameters:
Gravitational force = 85N
Distance or separation = 36mm = 0.036m
Unknown:
Their masses = ?
Solution:
Both of the spherical objects have the same mass as indicated by the object.
From the newton's law of universal gravitation:
F = [tex]\frac{G m1 m2}{r^{2} }[/tex]
F is the gravitational force
G is the universal gravitation constant = 6.67 x 10⁻¹¹
m1 is the mass of object 1
m2 is the mass of object 2
r is the distance between them
Since m1 = m2 = m
So;
85 = [tex]\frac{6.67 x 10^{-11} x m^{2} }{0.036^{2} }[/tex]
Therefore;
m = 4.06 x 10⁴kg
All object in the universe attract each other on the basis of the masses and distance between them. The mass of the given particle is [tex]\bold {4.06 x 10^4kg}[/tex].
Universal law of gravitation:
It states that the all object in the universe attract each other on the basis of the masses and distance between them.
[tex]\bold{F=G{\frac{m_1m_2}{r^2}}}[/tex]
Where,
F = force = 85 N
G = gravitational constant = [tex]\bold{6.67 x 10\\^-^1^1}[/tex]
m1 = mass of object 1 = ?
m2 = mass of object 2 = ?
r = distance between centers of the masses = 36 mm
As stated in the question,
m1 = m2 = m
Now, put the values in the formula,
[tex]\bold { 85 = \dfrac {6.67\times 10^-^1^1 \times m^2}{0.036^2}}\\\\\bold { m = 4.06 x 10^4kg}[/tex]
Therefore, the mass of the given particle is [tex]\bold {4.06 x 10^4kg}[/tex].
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a) Two workers are trying to move a heavy crate. One pushes onthe crate with a force A, which has amagnitude of 445 newtons and is directed due west. The other pusheswith a force B, which has a magnitude of 325newtons and is directed due north. What are the magnitude anddirection of the resultant force A + Bapplied to the crate?
b) Suppose the second worker applies a force of-B instead of B. What then arethe magnitude and direction of the resultant force A -B applied to the crate? In both cases express thedirection relative to due west.
Answer:
Divide then multiply or multiply then divide
Explanation:
to get the answer of a and b
Which property of water causes the cracks in the pavement in cold climates ?
“As temperatures drop, the pavement contracts, building up tensile stresses that lead to cracking,” states MnDOT's Research Services Section. “Fractures occur every 20 to 30 feet across the lane, allowing water to penetrate the structure, which further weakens the pavement layer and the base beneath
If the speed of an object is doubled, what happens to its kinetic energy?
Answer:
Kinetic energy is energy of motion. Doubling the speed will quadruple the kinetic energy. The relationship between speed and kinetic energy is: This means that the factor by which kinetic energy increases is the square of the factor by which speed or velocity increases for a given object.
Explanation:
Is cordyceps fungi a predator? If not, what is it?
Answer:
It is a predator.
Explanation:
They eat other insects so therefore I think they're a predator.
calculated the pressure exerted when a force of 100N is applied on a area of 25m2
Answer:
P = 4[Pa]
Explanation:
Pressure is defined as the relationship between Force over area. So we can use the following equation.
[tex]P=F/A[/tex]
where:
P = pressure [Pa] (units of Pascals)
F = force = 100 [N]
A = area = 25 [m²]
Now replacing:
[tex]P=100/25\\P=4[Pa][/tex]
[tex]\\ \rm\longmapsto P=\dfrac{F}{A}[/tex]
[tex]\\ \rm\longmapsto P=\dfrac{100}{25}[/tex]
[tex]\\ \rm\longmapsto P=4Pa[/tex]
Grapevine Co. paid a dividend of $3 on its common stock yesterday. The company's dividends are expected to grow at a constant rate of 9% indefinitely. If the required rate of return on this stock is 13%, compute the current value per share of Grapevine Co. stock.
A. $81.75
B. $47.90
C. $75
D. $56.25
Answer:
the current value per share of Grapevine Co. stock is $ 81.75
Option A) $ 81.75 is the correct answer
Explanation:
Given that;
paid dividend D₀ = $ 3
company's dividends are expected to grow at a constant rate of g = 9% = 0.09
return of stocks r = 13% = 0.13
current value per share of Grapevine Co. stock = ?
Now, to calculate the current value per share of Grapevine Co. stock; we use the expression;
D₀( 1 + g) / ( r - g)
we substitute
current value per share of Grapevine Co. stock = 3( 1 + 0.09) / ( 0.13 - 0.09)
= 3(1.09) / 0.04
= 3.27 / 0.04
= 81.75
Therefore, the current value per share of Grapevine Co. stock is $ 81.75
Option A) $ 81.75 is the correct answer
An easy way to draw a circle is to hold a string fixed at one end (for instance, with a pin) and attach a pen to the other end. Holding the string taut and drawing wherever the taut string allows gives a circle. This is the same technique you follow when using a compass. With a compass, the string is simply replaced by a metal or plastic structure, which usually has some markings to let you pick the radius of your circle. The radius of a circle is the only measure that you need to determine any other measure, such as the circumference or area. For instance, the circumference C of a circle (the length measured around the outside of the circle, i.e., the perimeter) is C=2πr. Suppose that you have a piece of string 7 cm long. If one end is held fixed and you draw with a pen at the other end, keeping the string tight, then you will draw a circle.
Required:
a. What is the circumference of this circle?
b. Suppose that you needed to make a pen for some small animals. You have 12 m of fencing. You decide to make a circular pen, because if you wish to enclose an area using a given length of fencing, then a circular fence encloses a larger area than a fence of any other shape. What is the radius r of the pen?
Answer:
The answer is "44 cm and 1.910 m".
Explanation:
In point a:
Formula for Circumference [tex](C)=2 \pi r[/tex]
[tex]= 2 \times 3.14 \times 7 \ (cm)\\\\= 14 \times 3.14 \ (cm)\\\\=43.96 \ cm\\\\=44 \ cm\\[/tex]
In point b:
The formula for the radius of the pen:
[tex]\to r= \frac{C}{2\pi}[/tex] [tex]\therefore C= 12\\[/tex]
[tex]= \frac{12\ m}{2(3.14)}\\\\= \frac{12\ m}{6.28}\\\\= 1.910 \ m \\\\[/tex]
what is the twisted ladder shape of the DNA called?
Answer:
Double helix
Explanation:
The Double helix is a DNA molecule. The two strands around the Double Helix is called the twisted ladder.
Answer:
double helix
Explanation:
Two spherical objects are separated by a distance that is 1.94 x 10-3 m. The objects are initially electrically neutral and are very small compared to the distance between them. Each object acquires the same negative charge due to the addition of electrons. As a result, each object experiences an electrostatic force that has a magnitude of 7.61 x 10-21 N. How many electrons did it take to produce the charge on one of the objects
Answer:
n = 1 10¹⁰ electron
Explanation:
For this exercise we will use Coulomb's law
F = k q₁ q₂ / r²
where it indicates that the value of the force is 7.61 10⁻²¹ N, the distance between the objects is r = 1.94 10⁻³ m and the charge on the objects has the same charge q₁ = q₂ = q,
F = k q² / r²
q = [tex]\sqrt{ \frac{ k \ q^2}{k} }[/tex]
let's calculate
q = [tex]\sqrt{ \frac{ 7.61 \ 10^{-21} \ (1.93 \ 10^{-3})^2 }{9 \ 10^{9} } }[/tex]
q = √(3.182 10⁻¹⁸)
q = 1.783 10⁻⁹ C
the charge of an electron is q₀ = 1.6 10⁻¹⁹ C, therefore
q = n q₀
n = q / q₀
n = 1,78 10⁻⁹ / 1.6 10⁻¹⁰
n = 1.06 10¹⁰ electron
the number of electrons must be integer
n = 1 10¹⁰ electron
Coulomb's Law is a fundamental principle in physics that describes the electrostatic interaction between charged particles. It took approximately 3.62 electrons to produce the charge on one of the objects.
According to Coulomb's Law, the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
To solve this problem, we can use Coulomb's law, which relates the electrostatic force between two charged objects to the charges and the distance between them. Coulomb's law is given by:
[tex]F = k * (|q1 * q2|) / r^2[/tex]
Where:
F is the electrostatic force,
k is the electrostatic constant [tex](k = 8.99 x 10^9 Nm^2/C^2),[/tex]
q1 and q2 are the charges on the objects, and
r is the distance between the objects.
Given that the force F is [tex]7.61 x 10^{-21} N[/tex], and the distance r is [tex]7.61 x 10^{-21} N[/tex]m, and assuming the charges on both objects are equal (let's call it q), we can rewrite Coulomb's law as:
[tex]F = k * (q^2) / r^2[/tex]
Rearranging the equation, we get:
[tex]q^2 = (F * r^2) / k[/tex]
Substituting the given values:
[tex]q^2 = (7.61 x 10^{-21} N) * (1.94 x 10^{-3} m)^2 / (8.99 x 10^9 Nm^2/C^2)[/tex]
Calculating this expression:
[tex]q^2 = 3.352 x 10^{-37} C^2[/tex]
Taking the square root of both sides:
[tex]q = \sqrt {3.352 x 10^{-37} C^2}\\q = 5.79 x 10^{(-19)}C[/tex]
Now, we know that the elementary charge of an electron is approximately[tex]1.6 x 10^{(-19)} C[/tex]. Since each electron carries a charge of[tex]-1.6 x 10^{-19} C[/tex], we can calculate the number of electrons:
Number of electrons = q / (elementary charge)
Number of electrons =[tex](5.79 x 10^{-19} C) / (1.6 x 10^{-19} C)[/tex]
Number of electrons = 3.62
Therefore, it took approximately 3.62 electrons to produce the charge on one of the objects.
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A mass of 6 kg with initial velocity 16 m/s travels through a wind tunnel that exerts a constant force 8 N for a distance 1.6 m. It climbs a frictional incline of height 2.9 m inclined at an angle 16°, then moves along a second frictional surface of coefficient 0.1 before coming to rest.
The acceleration of gravity is 9.8 m/s^2. If the first frictional surface has a coefficient of 0.21 for a distance 1 m, how far does it slide along the second frictional region before coming to rest?
Answer:
[tex]D=99.4665307m \approx 99.5m[/tex]
Explanation:
From the question we are told that
Mass [tex]m=6kg[/tex]
Velocity of mass [tex]V_m=16[/tex]
Force of Tunnel [tex]F_t=8N[/tex]
Length of Tunnel [tex]L_t=1.6[/tex]
Height of frictional incline [tex]H_i=2.9[/tex]
Angle of inclination [tex]\angle =16 \textdegree[/tex]
Acceleration due to gravity [tex]g=9.8m/s^2[/tex]
First Frictional surface has a coefficient [tex]\alpha_1 =0.21\ for\ d_c=1[/tex]
Second Frictional surface has a coefficient [tex]\alpha _2=0.1[/tex]
Generally the initial Kinetic energy is mathematically given by
[tex]K.E=\frac{1}{2}mv^2[/tex]
[tex]K.E=\frac{1}{2}(6)(16)^2[/tex]
[tex]K.E=768[/tex]
Generally the work done by the Tunnel is mathematically given as
[tex]w_t=F_t*d_t[/tex]
[tex]w_t=8*1.6[/tex]
[tex]w_t=12.8J[/tex]
Therefore
[tex]Total energy\ E_t=Initial\ kinetic energy\ K.E*Work done\ by\ tunnel\ W_t[/tex]
[tex]E_t=K.E+E_t\\E_t=768J+12.8J[/tex]
[tex]E_t=780.8J[/tex]
Generally the energy lost while climbing is mathematically given as
[tex]E_c=mgh[/tex]
[tex]E_c=(6)(9.8)(2.9)[/tex]
[tex]E_c=170.52J[/tex]
Generally the energy lost to friction is mathematically given as
[tex]E_f=\alpha *m*g*cos\textdegree*d_c[/tex]
[tex]E_f=0.21*6*9.8*cos16*1[/tex]
[tex]E_f=11.86965942 \approx 12J[/tex]
Generally the energy left in the form of mass [tex]Em[/tex] is mathematically given as
[tex]E_m=E_t+E_c+E_f[/tex]
[tex]E_m=(768J)-(170.52)-(12)[/tex]
[tex]E_m=585.48J[/tex]
Since
[tex]E_m=\alpha_2*g*m*d[/tex]
Therefore
It slide along the second frictional region
[tex]D=\frac{585.46}{0.1*9.81*6}[/tex]
[tex]D=99.4665307m \approx 99.5m[/tex]
These two waves travel along the same string: y1 = (4.17 mm) sin(2.24?x - 300?t), y2 = (5.96 mm) sin(2.24?x - 300?t + 0.727?rad). What are (a) the amplitude and (b) the phase angle (relative to wave 1) of the resultant wave? (c) If a third wave of amplitude 5.20 mm is also to be sent along the string in the same direction as the first two waves, what should be its phase angle in order to maximize the amplitude of the new resultant wave?
Answer:
a) Amplitude is 9.49 mm
b) ∅ = 0.43056 rad = 24.7°
c) phase angle = 2.24x - 300t + 0.43056 rad
Explanation:
Given that;
A1 = y1 = (4.17 mm) sin(2.24x - 300t)
A2 = y2 = (5.96 mm) sin(2.24x - 300t + 0.727rad)
now phase difference between y1 and y2 is;
Δ∅ = (2.24x - 300t + 0.727rad) - (2.24x - 300t) = 0.727 rad = 41.65°
a) the amplitude
Amplitude A = √( A1² + A2² + 2A1A2cosΔ∅)
we substitute
A = √( (4.17)² + (5.96)² + (2 × 4.17 × 5.96 × cos(41.65) )
A = √( 17.3889 + 35.5216 + ( 49.7064 × 0.7472 )
A = √(52.9105 + 37.1406 )
A = √90.0511
A = 9.49 mm
Therefore, Amplitude is 9.49 mm
b) the phase angle (relative to wave 1) of the resultant wave;
tan∅ = A2sinΔ∅ / ( A1 + A2cosΔ∅)
we substitute
tan∅ = 5.96sin41.65 / ( 4.17 + 5.96cos41.65)
tan∅ = 3.96088 / ( 4.17 + 4.4534)
tan∅ = 3.96088 / 8.6234
tan∅ = 0.4593
∅ = tan⁻¹ ( 0.4593 )
∅ = 0.43056 rad = 24.7°
c)
For the third wave, maximum amplitude. it should be in the direction of resultant of A1 and A2
so, phase angle in order to maximize the amplitude of the new resultant wave will be;
phase angle = 2.24x - 300t + 0.43056 rad
Armand is monitoring a large sealed tank by way of a sensor that records the liquid level over time on a graph. He looks at the graph and claims that the sensor indicates there are waves in the liquid in the tank.
In the space provided, answer each of the following.
Part A: Explain how Armand knows that there is a wave in the tank.
Part B: Find the amplitude, in centimeters (cm), and frequency, in number of waves every second/cycle per second (Hz), of the wave.
Answer:
A.) armand probably looked at the graph that the liquid sensor sends information too
Explanation:
Calculate the magnitude of the gravitational force exerted by Venus on a 60 kg human standing on the surface of Venus. (The mass of Venus is 4.9multiply1024 kg and its radius is 6.1multiply106 m.)
Answer:
The gravitational force exerted by Venus on the human is 527 N.
Explanation:
Given;
mass of the human, m₁ = 60 kg
mass of Venus, m₂ = 4.9 x 10²⁴ kg
gravitational constant, G = 6.67 x 10⁻¹¹ Nm²/kg²
radius of the Venus, r = 6.1 x 10⁶ m
The gravitational force exerted by Venus on the human is calculated as;
[tex]F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67\times 10^{-11})(60)(4.9\times 10^{24})}{(6.1\times 10^6)^2} \\\\F = 527 \ N[/tex]
Therefore, the gravitational force exerted by Venus on the human is 527 N.
5. Did objects have to touch to interact? What causes this?
Answer:
★ For example, a useful analogy for explaining the Earth's gravity force is that the Earth can pull on objects without touching them just like a magnet can affect other objects without touching them. In Addition, the main notion to convey here is that forces can act at a distance with no perceivable substance in between.
Explanation:
Hope you have a great day :)
No, objects have no need to touch for interaction.
Forces that interact with objects without touchingWe know that there are some forces which interact with the objects from far distance without touching such as gravity of the earth. The Earth's gravitational force is that the Earth can pull on objects without touching them so we can conclude that objects have no need to touch for interaction with one another.
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List two things affected by friction PLEASE RESPOND I NEED HELP
metal and hair I think hope this helps
Answer:
cars and trains
Explanation:
i hope that good
can you guys help me to solve first question????
Torque question
A uniform spherical shell of mass M = 11.0 kg and radius R = 0.480 m can rotate about a vertical axis on frictionless bearings (see the figure). A massless cord passes around the equator of the shell, over a pulley of rotational inertia I = 0.160 kg m2 and radius r = 0.110 m, and is attached to a small object of mass m = 1.60 kg. There is no friction on the pulley's axle; the cord does not slip on the pulley. What is the speed of the object when it has fallen a distance 0.700 m after being released from rest? Use energy considerations.
A man walks 8 m east in 12 seconds . What is the man's velocity ?
Answer:
0.67m/s due east
Explanation:
Given parameters:
Displacement of the man = 8m east
Time taken = 12s
Unknown:
Velocity of the man = ?
Solution:
The velocity of a body is the rate of displacement per time;
Velocity = [tex]\frac{Displacement}{time}[/tex]
Velocity = [tex]\frac{8}{12}[/tex] = 0.67m/s due east
What is Nature? How does it explain the human condition?
Which characterictic of motion could change without changing the velocity of an object
Answer:
The direction could change
Solve ez points. I cant rlly get but i guess most of u do, so its ez
Answer:
A: nucleus
D: neutron
hope this helps :D
Answer:
A: nucleus
D: neutron
Explanation: hope this helps! <3
Bruce pulls a spring with a spring constant k=100 Nmk=100\, \dfrac{\text N}{\text m}k=100mNk, equals, 100, start fraction, start text, N, end text, divided by, start text, m, end text, end fraction, stretching it from its rest length of 0.20 m0.20\,\text m0.20m0, point, 20, start text, m, end text to 0.40 m0.40\,\text m0.40m0, point, 40, start text, m, end text.What is the elastic potential energy stored in the spring?
Answer:
K_{e} = 2.0 J
Explanation:
In this exercise you are asked to calculate the elastic potential energy of a spring
[tex]K_{e}[/tex] = ½ k x²
where k is the spring constant and x is the displacement from equilibrium position
In this exercise, indicate that the spring constant is k = 100 N/m, the length at rest is x₀ = 20 cm = 0.20 m, up to the position x₁ = 40 cm = 0.40 m, therefore the elongation
Δx = x₁ - x₀
Δx = 0.40 - 0.20
Δx = 0.20 m
let's calculate the elastic potential energy
K_{e} = ½ 100 0.20²
K_{e} = 2.0 J
Suppose you have two metal spheres that are exactly the same size, separated by a very large distance. Sphere A carries an excess of eight negative charges while sphere B carries an excess of two positive charges. Sphere A is momentarily connected to Sphere B using a metal wire and then the wire is removed. Draw charge diagrams of the two spheres for the two cases below before and after the connecting wire is used.
1. Before the spheres are connected using the wire .
2. After the wire has been removed .
Answer:
a) phere A has 8 negative charges and sphere B has 2 positive charges
b) each one has then 3 negative charges
Explanation:
In this case, it is asked to determine the charge of the spheres in two conditions
a) Before connecting the cable, sphere A has 8 negative charges and sphere B has 2 positive charges
b) After connecting the cable, as the spheres are metallic, the load is distributed, we have
q = 8 -2 = 6 negative charges
these charges are distributed between the two spheres, each one has then 3 negative charges
The velocity of the transverse waves produced by an earthquake is 5.09 km/s, while that of the longitudinal waves is 8.5512 km/s. A seismograph records the arrival of the transverse waves 64.9 s after that of the longitudinal waves. How far away was the earthquake
Answer:
Explanation:
Velocity of transverse wave Vt = 5.09 km/s
Velocity of longitudinal wave Vl = 8.5512 km/s
Let earthquake occurred d km away .
Time taken by transverse wave to travel d distance
= d / 5.09 s
Time taken by longitudinal wave to travel d distance
= d / 8.5512 s
According to question
[tex]\frac{d}{5.09} -\frac{d}{8.5512} = 64.9[/tex]
.19646 d - .11694 d = 64.9
.07952 d = 64.9
d = 816.15 km .
The pendulum on a grandfather clock is 0.993 m long and swings to a maximum 4.57° angle. If the bob of the pendulum has mass = 0.415 kg, how much PE does it have at the top of its swing?
Answer:
0.0128
Explanation:
Which is not a product of coal?
A. Monoxide
B. Carbon Dioxide
C. Methane
D. Calcium
Answer:
D
Explanation:
Hope this helps
The car A has a weight of 4000 lb and is traveling to the right at 3 ft/s. Meanwhile a 2000-lb car B is traveling at 6 ft/s to the left. If the cars crash head-on, and at a time instant during the crash the impact force on A is 900 lb to the left, what is magnitude and direction of the impact force exerted on B at the instant
Answer:
900 lb to the right
Explanation:
Newton's third law of motion states that for every action there is equal and opposite reaction.
Hence if the two cars (i.e. car A and car B) crash head on and there is an impact on car A of 900 lb to the left, car B would have to generate a force of equal magnitude and in an opposite direction. Since car A had a force of 900 lb to the left, the impact force exerted on car B would be 900 lb to the right.
The answer is 900 lb to the right
A 50kg person climbs a 2-meter ladder in 5 second. What is their power output in Watts as they do so?
Answer:
The answer is 196
Explanation:
Because the on the test I got it right
Their power output in watts as they do so will be "200 W". To understand the calculation, check below.
Power and Work done:According to the question,
Person's mass, m = 50 kg
Distance, d = 2 m
Time, t = 5 seconds
As we know,
Force = Mass × Acceleration
= 50 × 10
= 500 N
Now,
Work done = Force × Distance
= 500 × 2
= 1000 J
hence,
The Power will be:
= [tex]\frac{Work \ done }{Time}[/tex]
By substituting the values,
= [tex]\frac{1000}{5}[/tex]
= 200 W
Thus the above answer is correct.
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Which of the following is NOT a type of acceleration?
O A.
Positive acceleration
B.
Constant velocity
O c.
Change in direction
D.
Negative acceleration
NEED ASAP!! A box of mass 10 kg requires 20 N to slide it across a surface. What is the weight of the box? What is the coefficient of friction between the box and surface ?
Answer: 7
Explanation: 7 is the superior number
Please helpp this is due in 10 minutes?!!!!
Describe the potential energy and kinetic energy at each position of the
roller coaster car. Use these questions to help you.
1.Where is potential energy at its maximum?
2.Where is kinetic energy at its maximum?
3.Where is potential energy increasing and decreasing?
.4Where is kinetic energy increasing and decreasing?
Answer:
1. at the top of the coaster.
2. at the bottom of the coaster.
3. when the car is moving
4. when the car is moving
Explanation:
there is the most amount if potential energy at the top, and the keast at the bottom.
