Answer:
spherical shape
Explanation:
The Earth is massive enough that the pull of gravity maintains its roughly spherical shape. Most of its deviation from spherical stems from the centrifugal force caused by rotation around its north-south axis. This force deforms the sphere into an oblate ellipsoid.
If you drop a rock from 700 meters high, how long will it take the hit the ground? (Remember to make height negative when solving because it is falling)
Answer:
it would be 11.95 seconds
Explanation:
sorry for saying i did not know
Convert 1 x 10-3 nm to m. given: 1 m = 1,000,000,000 nm
Answer:
l m = 1000000000 nm
? = 0.001
= 0
Water waves are waves because the wave moves up and down. transverse longitudinal
Answer:
it is transverse because longitudinal run lengthwise rather than across
hoped this helped lmk if it did
20
A force of 1 N accelerates a mass of 1 kg at the rate of 1 m/s/s. The
acceleration of a mass of 2 kg acted upon by a net force of 2 N is
O half as much
twice as much.
the same.
O none of these
Answer:
Doing it right now i’ll pm once done give me 5 minutes:)
Explanation:
What is the acceleration of gravity on Earth?
Answer:
9.807 m/s²
Explanation:
PLS make me brainliest
Answer:
[tex]\huge\boxed{\sf 9.8 \ m/s^2}[/tex]
Explanation:
The acceleration due to gravity is g the value of which is 9.8 m/s².
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807summarize your observations about the relationships between molecular mass (heavy vs light), kinetic energy, particle speed, and temperature
Answer:
See explanation
Explanation:
Given that the kinetic energy of particles is obtained from; Ek = 1/2 mu^2. The speed of particles is given by c = [3RT/M]^1/2.
From what we can see in the graphs with heavy particles, they only have higher peaks while the lighter particles have lower peaks of kinetic energy and particle speed.
From the graphs and the temperatures used, it is evident that the shape of the graphs were almost the same. Temperature appears not to have any outstanding effect on it.
If a baseball is held in the air at shoulder level then dropped to the ground, does it have more energy when it is held in the air at shoulder level or just before it hits the ground?
Answer:
it should not be dropping it goes up in the air then it goes down
Which equation shows the correct relationship between mechanical energy, kinetic energy, and potential energy?
ME = KE + PE
O ME + KE = PE
O ME = KE - PE
O ME + PE = KE
Answer:
ME= KE+PE
Explanation:
just took quiz
The correct relationship between mechanical energy, kinetic energy, and potential energy is ME= KE + PE, the correct option is A.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
The expression for total mechanical energy is as follows
[tex]ME = KE + PE[/tex]
As total mechanical energy is the sum of all the kinetic as well potential energy stored in the system.
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Gravitational potential energy depends on the ____________ of the object.
Answer:
Height And Mass!
Explanation:
Got It from Google! I ain't smart XDD
Centripetal forces are always directed toward the (center, outside) of a circle.
Answer:
Centripetal forces are directed toward the center of a circle.
Hope this helps.
Explanation:
The force needed to move a body in a curved way is understood as centripetal force. Centripetal forces are always directed toward the center of a circle.
What is centripetal force?The force needed to move a body in a curved way is understood as centripetal force. This is a force that can be sensed from both the fixed frame and the spinning body's frame of concern.
The direction of centripetal force is always in the path of the center of the course.
Hence center is the right option. Centripetal forces are always directed toward the center of a circle.
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A cyclist is coasting at 13 m/s when she starts down a 460 m long slope that is 30 m high. The cyclist and her bicycle have a combined mass of 70 kg. A steady 15 N drag force due to air resistance acts on her as she coasts all the way to the bottom. What is her speed at the bottom of the slope?
Answer:
The value is [tex]v = 23.6 \ m/s[/tex]
Explanation:
From the question we are told that
The velocity is [tex]u = 13 \ m/s[/tex]
The length of the slope is [tex]l = 460 \ m[/tex]
The height of the slope is [tex]h = 30 \ m[/tex]
The mass of the cyclist and her bicycle is [tex]m = 70 \ kg[/tex]
The drag force is [tex]F = 15 \ N[/tex]
Generally from the law of energy conservation we have that
[tex]PE + KE_t = W * KE_b[/tex]
Here [tex]PE[/tex] is the potential energy at the top of the slope which is mathematically represented as
[tex]PE = m* g * h[/tex]
=> [tex]PE = 70 * 9.8 * 30[/tex]
=> [tex]PE = 20580 \ J[/tex]
and [tex]KE_t[/tex] is the kinetic energy at the top of the slope which is mathematically represented as
[tex]KE_t = \frac{1}{2} * m * u^2[/tex]
=> [tex]KE_t = \frac{1}{2} * 70 * 13^2[/tex]
=> [tex]KE_t = 5915 \ J[/tex]
And W is the work done by the bicycle which is mathematically represented as
[tex]W = F * l[/tex]
=> [tex]W = 15 * 460[/tex]
=> [tex]W = 6900 \ J[/tex]
and [tex]KE_b[/tex] is the kinetic energy at the bottom of the slope which is mathematically represented as
[tex]KE_b = \frac{1}{2} * m * v^2[/tex]
=> [tex]KE_b = \frac{1}{2} * 70 * v^2[/tex]
=> [tex]KE_b = 35 v^2[/tex]
So
[tex]20580 + 5915 = 6900 + 35 v^2[/tex]
=> [tex]v = 23.6 \ m/s[/tex]
Suppose a large housefly 3.0 m away from you makes sound with an intensity level of 40.0 dB. What would be the sound intensity level if there 1000 identical flies at that same distance?
Answer:
Explanation:
Let the intensity of the noise be represented by I
Given that
40dB = 10 log 10 ( I /I•) ........ 1
I• is the lowest or threshold intensity of sound made.
I represents the intensity of the sound/ noise
The intensity of noise of 1000flies will be
β = 10 log 10 (1000I/I•)
Open up the bracket
β = 10 log 10(1000)+ 10 log 10(I/I•)
10 log 10(10^3)+10 log 10(I/I•)
3×10(10 log 10) +10 log 10(I/I•)
Recall, 10 log 10 = 1
30×1 + 10 log 10(I/I•).........2
Put equation 1 into 2
β =30+40
= 70db
The sound intensity produced by the large housefly at a distance of 3.0 m is 10,000 times greater than the reference intensity. If there are 1000 identical flies at the same distance, the sound intensity level would be 70.0 dB.
The sound intensity level (L) in decibels (dB) follows a logarithmic scale and can be calculated using the formula:
L = 10 × log₁₀(I/I0)
40.0 dB = 10 × log₁₀(I1/I0)
4.0 = log₁₀(I1/I0)
I1/I0 = 10⁴
I1/I0 = 10,000
This means that the sound intensity produced by the large housefly at a distance of 3.0 m is 10,000 times greater than the reference intensity.
For the sound intensity level when there are 1000 flies, we need to multiply the original sound intensity by 1000:
I_total = 1000 × I₁
I_total/I0 = 1000 × 10,000
I_total/I0 = 10,000,000
L_total = 10 × log₁₀(I_total/I0)
L_total = 10 × log₁₀(10,000,000)
L_total = 10 × 7
L_total = 70 dB
Therefore, if there are 1000 identical flies at the same distance, the sound intensity level would be 70.0 dB.
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Acceleration and force are proportional
Answer:
whats the question tho
it was a dark and stormy night.Buffy hameard thunder exactly 6 secounds after she saw lightning , the temperature of air is 15°C . the speed light is 3×10^8 m/s
caculate the speed of sound
Answer:
υ = 345.82 m/s
Explanation:
The formula used to find the speed of sound in air, at different temperatures is given as follows:
[tex]v = v_{0}\sqrt{\frac{T}{273} }[/tex]
where,
υ = speed of sound at given temperature = ?
υ₀ = speed of sound at 0°C = 331 m/s
T = temperature in K = 15°C + 273 = 298 k
Therefore, using these values in the equation, we get:
[tex]v = (331 m/s)\sqrt{\frac{298 k}{273 k}}\\[/tex]
υ = 345.82 m/s
Hydropower is alternative source of energy
Answer:
Hydropower is an alternate source!Its expensive and takes up large spaces and many natural resources Takes homes of natural species.Answer:
because Hydropower is fueled by water, so it's a clean fuel source, meaning it won't pollute the air like power plants that burn fossil fuels, such as coal or natural gas. Hydroelectric power is a domestic source of energy, allowing each state to produce their own energy without being reliant on international fuel sources.
Explanation:
please mark as brainlest
An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pipe diameter is 8.8 cm is 2.4 m/s. Calculate the flow speed at a location where the diameter has narrowed to 5.80 cm
Answer:
The value is [tex]v_2 = 5.53 \ m /s[/tex]
Explanation:
From the question we are told
The pipe diameter at location 1 is [tex]d = 8.8 \ cm = \frac{8.8 }{10} = 0.88 \ m[/tex]
The velocity at location 1 is [tex]v_1 = 2.4 \ m /s[/tex]
The diameter at location 2 is [tex]d_2 = 5.80 \ cm = 0.58 \ m[/tex]
Generally the area at location 1 is
[tex]A_1 = \pi * \frac{d^2}{ 2}[/tex]
=> [tex]A_1 = \pi * \frac{0.88^2}{ 2}[/tex]
=> [tex]A_1 = 3.142 * \frac{0.88^2}{ 2}[/tex]
=> [tex]A_1 = 1.2166 \ m^2[/tex]
Generally the area at location 1 is
[tex]A_2 = \pi * \frac{d_1^2}{ 2}[/tex]
=> [tex]A_2 = \pi * \frac{0.58^2}{ 2}[/tex]
=> [tex]A_2 = 0.528 \ m^2[/tex]
Generally from continuity equation we have that
[tex]A_1 * v_1 = A_2 * v_2[/tex]
=> [tex]1.2166 * 2.4 = 0.528 * v_2[/tex]
=> [tex]1.2166 * 2.4 = 0.528 * v_2[/tex]
=> [tex]v_2 = 5.53 \ m /s[/tex]
Moist air initially at 1258C, 4 bar, and 50% relative humidity is contained in a 2.5-m3 closed, rigid tank. The tank contents are cooled. Determine the heat transfer, in kJ
Here is the missing part of the question
To Determine the heat transfer, in kJ if the final temperature in the tank is 110 deg C
Answer:
Explanation:
The image attached below shows the process on T - v diagram
At State 1:
The first step is to find the vapor pressure
[tex]P_{v1} = \rho_1 P_g_1[/tex]
[tex]= \phi_1 P_{x \ at \ 125^0C}[/tex]
= 0.5 × 232 kPa
= 116 kPa
The initial specific volume of the vapor is:
[tex]P_{v_1} v_{v_1} = \dfrac{\overline R}{M_v}T_1[/tex]
[tex]116 \times 10^3 \times v_{v_1} = \dfrac{8314}{18} \times (125 + 273)[/tex]
[tex]116 \times 10^3 \times v_{v_1} = 183831.7778[/tex]
[tex]v_{v_1} = 1.584 \ m^3/kg[/tex]
At State 1:
The next step is to determine the mass of water vapor pressure.
[tex]m_{v1} = \dfrac{V}{v_{v1}}[/tex]
[tex]= \dfrac{2.5}{1.584}[/tex]
= 1.578 kg
Using the ideal gas equation to estimate the mass of the dry air [tex]m_a[/tex][tex]P_{a1} V = m_a \dfrac{\overline R}{M_a}T_1[/tex]
[tex](P_1-P_{v1}) V = m_a \dfrac{\overline R}{M_a}T_1[/tex]
[tex](4-1.16) \times 10^5 \times 2.5 = m_a \dfrac{8314}{28.97}\times ( 125 + 273)[/tex]
[tex]710000= m_a \times 114220.642[/tex]
[tex]m_a = \dfrac{710000}{114220.642}[/tex]
[tex]m_a = 6.216 \ kg[/tex]
For the specific volume [tex]v_{v_1} = 1.584 \ m^3/kg[/tex] , we get the identical value of saturation temperature
[tex]T_{sat} = 100 + (110 -100) \bigg(\dfrac{1.584-1.673}{1.210 - 1.673}\bigg)[/tex]
[tex]T_{sat} =101.92 ^0\ C[/tex]
Thus, at [tex]T_{sat} =101.92 ^0\ C[/tex], condensation needs to begin.
However, since the exit temperature tends to be higher than the saturation temperature, then there will be an absence of condensation during the process.
Heat can now be determined by using the formula
Q = ΔU + W
Recall that: For a rigid tank, W = 0
Q = ΔU + 0
Q = ΔU
Q = U₂ - U₁
Also, the mass will remain constant given that there will not be any condensation during the process from state 1 and state 2.
At State 1;
The internal energy is calculated as:
[tex]U_1 = (m_a u_a \ _{ at \ 125^0 C})+ ( m_{v1} u_v \ _{ at \ 125^0 C} )[/tex]
At [tex]T_1[/tex] = 125° C, we obtain the specific internal energy of air
SO;
[tex]U_{a \ at \ 125 ^0C } = 278.93 + ( 286.16 -278.93) (\dfrac{398-390}{400-390} )[/tex]
[tex]=278.93 + ( 7.23) (\dfrac{8}{10} )[/tex]
[tex]= 284.714 \ kJ/kg\\[/tex]
At [tex]T_1[/tex] = 125° C, we obtain the specific internal energy of water vapor
[tex]U_{v1 \ at \ 125^0C} = u_g = 2534.5 \ kJ/kg[/tex]
[tex]U_1 = (m_a u_a \ at \ _{ 125 ^0C }) + ( m_{v1} u_v \ at \ _{125^0C} )[/tex]
= 6.216 × 284.714 + 1.578 × 2534.5
= 5768.716 kJ
At State 2:
The internal energy is calculated as:
[tex]U_2 = (m_a u_a \ _{ at \ 110^0 C})+ ( m_{v1} u_v \ _{ at \ 110^0 C} )[/tex]
At temperature 110° C, we obtain the specific internal energy of air
SO;
[tex]U_{a \ at \ 110^0C } = 271.69+ ( 278.93-271.69) (\dfrac{383-380}{390-380} )[/tex]
[tex]271.69+ (7.24) (0.3)[/tex]
[tex]= 273.862 \ kJ/kg\\[/tex]
At temperature 110° C, we obtain the specific internal energy of water vapor
[tex]U_{v1 \ at \ 110^0C}= 2517.9 \ kJ/kg[/tex]
[tex]U_2 = (m_a u_a \ at \ _{ 110 ^0C }) + ( m_{v1} u_v \ at \ _{110^0C} )[/tex]
= 6.216 × 273.862 + 1.578 × 2517.9
= 5675.57 kJ
Finally, the heat transfer during the process is
Q = U₂ - U₁
Q = (5675.57 - 5768.716 ) kJ
Q = -93.146 kJ
with the negative sign, this indicates that heat is lost from the system.
Solid state physics uses the. Theory to understand how the large-scale properties of solids result from their atomic scale structure
Answer:
Quantum theory
Explanation:
The scientific foundation in quantum mechanics is quantum theory, which describes the existence and behavior of mass and antimatter at the subatomic particles levels. Quantum theory and quantum theory are often related to as the existence and behavior of matter in the universe at that stage.
A transverse, sinusoidal wave travels in a string and can be described by the function: y(x,t)=0.87 sin(21x−4.9t). What is the speed of this wave?
Answer:
2.61m/s
Explanation:
Given the wave function;
y(x,t)=0.87 sin(21x−4.9t).
The general wave equation is expressed as;
[tex]y = Asin(2\pi ft + 2\pi x /\lambda)[/tex]
f is the frequency of the wave
t is the time
[tex]\lambda\\[/tex] is the wavelength
On comparing;
2πft = 4.9t
2πf= 4.9
f = 4.9/2π
f = 4.9/2(3.14)
f = 4.9/6.28
f = 0.78Hz
Get the wavelength;
2πx/[tex]\lambda[/tex] = 21x
2π/[tex]\lambda[/tex] = 21
2π = 21[tex]\lambda[/tex]
[tex]\lambda[/tex] = 21/2π
[tex]\lambda[/tex] = 21/2(3.14)
[tex]\lambda[/tex] = 21/6.28
[tex]\lambda[/tex] = 3.34m
Speed = frequency * wavelength
Speed of the wave = 0.78 * 3.34
Speed of the wave = 2.61m/s
Hence the speed of the wave is 2.61m/s
A ball is thrown in the air at an angle of 60.0° to the ground, with an initial speed of 30m/s. How far from its original position does it land?
Answer:
A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?
Explanation:bkdbjkfej jf jfekjwniorigoexhndvgkj...............aplokdiuhyfgbv ..............................................
Three charges are enclosed inside a spherical closed surface. The net flux through the surface is −216 N · m2/C. If two of the charges inside the closed surface are 1.74 nC and 1.16 nC, determine the value (magnitude and sign) of the third charge.
Answer:
q₃ = -4.81 nC
Explanation:
We can use the Gauss Law here:
∅ = q/∈₀
where,
∅ = Net Flux = - 216 N.m²/C
q = total charge enclosed inside sphere = ?
∈₀ = permittivity of free space = 8.85 x 10⁻¹² C/N.m²
Therefore,
- 216 N.m²/C = q / 8.85 x 10⁻¹² C²/N.m²
q = (-216 N.m²/C)(8.85 x 10⁻¹² C²/N.m²)
q = - 1.91 nC
So, the total charge will be sum of all three charges:
q = q₁ + q₂ + q₃
- 1.91 nC = 1.74 nC + 1.16 nC + q₃
q₃ = - 1.91 nC - 1.74 nC - 1.16 nC
q₃ = -4.81 nC
A light board, 10 m long, is supported by two sawhorses, one at one edge of the board and a second at the midpoint. A small 40-N weight is placed between the two sawhorses, 3.0 m from the edge and 2.0 m from the center. What forces are exerted by the sawhorses on the board
Answer:
8N and 32N
Explanation:
Given that a light board, 10 m long, is supported by two sawhorses, one at one edge of the board and a second at the midpoint. A small 40-N weight is placed between the two sawhorses, 3.0 m from the edge and 2.0 m from the center.
To calculate the forces that are exerted by the sawhorses on the board, we must consider the equilibrium of forces acting on the board.
Let the two upward forces produce by the saw horses be P1 and P2
Assuming that the weight is negligible
Sum of the upward forces = sum of the downward forces.
P1 + P2 = 40 ....... (1)
Also, the sum of the clockwise moment = sum of the anticlockwise moments.
Let's assume that the board is uniform. The weight will act at the centre.
Taking moment at the centre:
P1 × 5 + 40 × 2 = 0
P1 = 40 / 5
P1 = 8N
Substitute P1 into equation 1
8 + P2 = 40
P2 = 40 - 8
P2 = 32N
Answer:
56
Explanation:
If an object has more mass then it will have...
A: less intertia
B: more inertia
C: more volume
D: less volume
True or False: The motion of the plates over the surface of the Earth occurs at a noticeable and fairly rapid rate.
Which climate condition is typically found in the tropics due to the interaction of the atmosphere and hydrosphere? (3 points)
a
Dry with low humidity
b
Dry with high humidity
c
Wet with high humidity
d
Stormy with low humidity
Answer:
wet with high humidity
Explanation:
i took the test
Plants in the rainforest
that was a little random
(question 1) A person with a mass of 50 kilograms pushes a 2000-kilogram car to the right with a force of 500 Newtons. What is the force that the car applies to the person?
(question 2) An ice skater with a mass of 50 kilograms pushes another skater (with a mass of 40 kilograms) with a force of 25 newtons. How much acceleration does the 50-kg skater have?
(question 3) Two people are moving a heavy desk. One person pulls to the right with a force of 25 newtons, while the other pushes to the right with a force of 50 newtons. There is also 29 newtons of friction pointing to the left. what is the net force on the desk?
(question 4) Two people are trying to pull 5-kilogram block in opposite directions. The first person pulls to the right with a force of 25 newtons, and the second person pulls to the left with a force of 15 newtons. What is the acceleration of the block?
IK its a lot but I need help please
Answer:
q1: 0.5m/s2
Explanation:
HELPPPP QUESTION IS ABOVE
Answer:
discount rate
Explanation:
i could be wrong but i believe thats what it is
jujuju on da beati dont knowww
Answer:
The answer is Juju knows. Pplease mark as solved and thanks
Explanation:
Answer
Explanation:
Answer
Explanation:Answer
Explanation:Answer
Explanation:Answer
Explanation:Answer
Explanation:
Which of the following is a correct description of an atom?
A. A very small particle that holds a positive or negative charge depending upon the element
B. A mixture of protons and electrons surrounded by neutrons in very tight orbits
C.A very small particle that's the same for every element
D. The smallest particle of an element that still keeps the properties of that element
Answer:
A it makes sense
Explanation:
The best description of an atom is that it is A very small particle that holds a positive or negative charge, depending upon the element. Hence, option A is correct.
What is an Atom?The smallest unit of matter that can be divided with releasing charged particles is the atom. It is also the smallest bit of matter with chemical substance properties. As a result, the atom is the basic building block of chemistry.
Examine the many-electron-electron arrangements in the electron shells around the atom's nucleus.
A large portion of a molecule is empty space. The remainder of the structure, which is composed of neutrons and protons, is surrounded by a cloud of negatively charged electrons, while the nucleus itself has a positive charge.
Therefore, for an atom, the best description is that it is a very small particle that hold charge depending on the element.
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