Brody spent $260 on 4 chairs. To find out how much he spent on each chair, he did the following work in long division. 65 4) 260 -24 20 -20 0 Did he do the problem correctly? Why or why not? O A. No, because there is a remainder of o. B. No, because the first digit in the quotient should be 4, not 6. O C. No, because the problem should be 260 14. O D. Yes, he worked the problem correctly.
Answers
He spend $260 on 4 chairs:
To know how much he spent on each chair he must:
Divide 260 into 4You first pick the firt digit of the dividend (260) and look if you can divide that digit into the divider (4) as in this case the firt digit 2 cannot be divided into 4 you take the first and secon digit (26) and divide it into 4 (how many times fix 4 in 26), this is equal to 6 times (this is the first digit of the quotient), then you multiply the 6 by 4 (6*4=24)and put the result under the 26 to substract it:
Now you lower the zero (of the 260) next to the result of the previous subtraction:
And divide 20 into 4 (how many times fix 4 in 20) this is equal to 5 times (this is the second digit of the quotient ) then you multiply the 5 by 4 (5/4 =20) and put the result under the 20 to substract it:
The remainder of 0 means the division has not decimal result, the result of 260 into 4 is an interger number (65)
The firt digit of the quotient is 6 because 26 into 4 is 6.
So the division he did is the correct form to find how much cost each chair ($65)
Related Questions
Simplify the problem and use the chart to find the answer.
Answers
When an exponent is a fraction, the number of the numerator is the exponent and the number of the denominator is the radical number:
Then, in this case:
Since
[tex]\sqrt[2]{x^3}=\sqrt[]{x^3}[/tex](when the number of the radical is 2 we can write it without the 2), then
[tex]\sqrt[2]{x^3}=\sqrt[]{x^3}[/tex]Then
Answer: III
A translation is a type of transformation in which a figure is flipped,TrueFalse
Answers
In a circle with radius 8, an angle measuring radians intercepts an arc. Find thelength of the arc in simplest form.
Answers
s = 28π/3
Explanation:The radius, r = 8
The angle, θ = 7π/6 radian
The length of the arc, s = rθ
s = 8 x 7π/6
s = 28π/3
Camden, a florist, is dividing 56 flowers equally into 8 bouquets. He uses division to find that he can put 7 flowers in each bouquet. Which subtraction equation could he use to check his answer?
Answers
The subtraction equation that Camden could use to check his answer is, x = 56 - 8 x 7.
What is a subtraction equation?A subtraction equation is an equation, which is a mathematical statement that two mathematical expressions share equality, which involves the use of the subtraction operation.
The result of a subtraction operation is known as the difference. The other parts of a subtraction operation are the minuend and the subtrahend.
The total number of flowers for the bouquets = 56
The number of bouquets = 8
The number of flowers for each bouquet = 7 (56/8)
Check:
x = 56 - 7 x 8
x = 56 - 56
x = 0
To check if the answer is correct, Camden should multiply 7 by 8 and then subtract the product from 56.
Thus, the difference in the subraction equation x = 56 - 8 x 7 that Camden used is zero, showing that his earlier division operation was correct.
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Which set of ordered pairs does not show y as a function of x? A. {(3,-2); (5,-3); (7,-4); (9,-5)} B. O {(3,-2); (6,-2); (9,-2); (12,-2)} c.{(4, -2); (5,-3); (6,-4); (7,-5)} D.O{(4, -2); (5,-3); (4,-8); (5,-9)}
Answers
Katherine bought à sandwich for 5 1/2 dollar and a adrink for $2.60.If she paid for her meal with a $ 10 bill how much money did she have left?
Answers
To find out how much Katherin have left we need to substrac the amount she spent:
[tex]10-5\frac{1}{2}-2.6=10-5.5-2.6=1.9[/tex]Therefore she has $1.9 left.
To do this same problem in fraction form we need to convert the 2.6 in fraction, to do this we multiply the number by 10 and divided by ten. Then:
[tex]2.6\cdot\frac{10}{10}=\frac{26}{10}=\frac{13}{5}[/tex]then we have:
[tex]\begin{gathered} 10-5\frac{1}{2}-\frac{13}{5}=10-\frac{11}{2}-\frac{13}{5} \\ =\frac{100-55-26}{10} \\ =\frac{19}{10} \end{gathered}[/tex]Therefore, the answer in decimal form is 19/10 dollars.
√64= A. 16 B. 8 C. 7 D. 9
Answers
Answer:
B. 8
Explanation:
[tex]64=8\times8[/tex]We can write this in index form as:
[tex]64=8^2[/tex]Therefore:
[tex]\sqrt[]{64}=\sqrt[]{8^2}[/tex]On the right-hand side, the square root sign cancels the square, so we have:
[tex]\sqrt[]{64}=8[/tex]The correct choice is B.
How do I solve this problem?Mary reduced the size of a painting to a width of 3.3 inches. What is the new height of it was originally 32.5 inches tall and 42.9 inches wide? Round your answer to the nearest tenth.
Answers
Given the follow equivalence
[tex]\frac{Oldwidth}{Oldheight}=\frac{Newwidth}{Newheight}[/tex]where
old width=42.9
Old height= 32.5
New width=3.3
then
[tex]\frac{42.9}{32.5}=\frac{3.3}{Newheight}[/tex][tex]Newheight=3.3*\frac{32.5}{42.9}[/tex][tex]Newheight=2.5[/tex]New height is 2.5 inches
I need help with this practice problem I’m having trouble solving it
Answers
A generic cosecant function is
[tex]f(x)=A\csc (kx+\theta)+C[/tex]We must find A, k, θ, and C using the information that we have.
Finding A:
To find A we can use the range of the function, we know there is a gap between -9 and 5, that's the crucial information, the value of A will be the mean of |-9| and |5| (in modulus!), therefore
[tex]A=\frac{|-9|+|5|}{2}=\frac{9+5}{2}=\frac{14}{2}=7[/tex]Therefore
[tex]f(x)=7\csc (kx+\theta)+C[/tex]Finding C:
We can use the fact that we know A and find C, let's suppose that
[tex]\csc (kx+\theta)=1[/tex]For an unknown value of x, it doesn't matter, using the range again we can use the fact that 5 is a local minimum of the function, therefore, when the csc(kx + θ) is equal to 1 we have that the function is equal to 5
[tex]\begin{gathered} 5=7\cdot1+C \\ \\ C=-2 \end{gathered}[/tex]And we find that C = -2. Tip: You can also suppose that it's -1 and use -9 = 7 + C, the result will be the same.
Finding k:
Now we will use the asymptotes, we have two consecutive asymptotes at x = 0 and x = 2π, it means that the sin(kx) is zero at x = 0 and the next zero is at x = 2π, we know that sin(x) is zero every time it's a multiple of π, which gives us
[tex]\begin{gathered} \sin (0)=0\Rightarrow\sin (k\cdot0)=0\text{ (first zero | first asymptote)} \\ \sin (\pi)=0\Rightarrow\sin (2k\pi)=0\Rightarrow k=\frac{1}{2}\text{ (second zero | second asymptote)} \end{gathered}[/tex]Therefore, k = 1/2
[tex]f(x)=7\csc (\frac{x}{2}+\theta)-2[/tex]Finding θ:
It's the easiest one, since we have a zero at x = 0 it implies that θ = 0
Therefore our function is
[tex]f(x)=7\csc (\frac{x}{2})-2[/tex]Final answer:
[tex]f(x)=7\csc \mleft(\frac{x}{2}\mright)-2[/tex]
Find the equations (in terms of x) of the line through the points (-2,-3) and (3,-5)
Answers
The general equation of a line passing through two points (xb₁,y₁)Pxb₂,y₂) is expressed as
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{where} \\ m\Rightarrow slope\text{ of the line, expr}essed\text{ as }m\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ (x_1,y_1)\Rightarrow coordinate_{}\text{ of point P} \\ (x_2,y_2)\Rightarrow coordinate_{}\text{ of point Q} \end{gathered}[/tex]Given that the coordinates of the two points are (-2, -3) and (3, -5), we have
[tex]\begin{gathered} (x_1,y_1)\Rightarrow(-2,\text{ -3)} \\ (x_2,y_2)\Rightarrow(3,\text{ -5)} \end{gathered}[/tex]Step 1:
Evaluate the slope o the line.
The slope is thus evaluated as
[tex]\begin{gathered} m\text{ = = }\frac{y_2-y_1}{x_2-x_1} \\ \text{ = }\frac{\text{-5-(-3)}}{3-(-2)} \\ =\frac{-5+3}{3+2} \\ \Rightarrow m\text{ = -}\frac{2}{5} \end{gathered}[/tex]Step 2:
Substitute the values of x₁,
Thus, we have
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ x_1=-2 \\ y_1=-3 \\ m\text{ =- }\frac{2}{5} \\ \text{thus,} \\ y-(-3)\text{ = -}\frac{2}{5}(x-(-2)) \\ y+3\text{ =- }\frac{2}{5}(x+2) \end{gathered}[/tex]Step 3:
Make .
[tex]\begin{gathered} y+3\text{ =- }\frac{2}{5}(x+2) \\ \text{Multiply both sides of the equation by 5 } \\ 5(y+3)\text{ = -2(x+2)} \\ \text{open brackets} \\ 5y\text{ + 15 =- 2x - 4} \\ \Rightarrow5y\text{ =- 2x - 4 -15} \\ 5y\text{ = -2x-1}9 \\ \text{divide both sides of the equation by the coefficient of y, which is 5.} \\ \text{thus,} \\ \frac{5y}{5}=\frac{-\text{2x-1}9}{5} \\ \Rightarrow y\text{ =- }\frac{2}{5}x\text{ - }\frac{19}{5} \end{gathered}[/tex]Hence, the equation of the line is
[tex]y\text{ = -}\frac{2}{5}x\text{ - }\frac{19}{5}[/tex]y₁ and m into the general equation of the line.
The 250 m between Sam's house and the tennis court corresponds to 5 cm on a town
map. What is the actual distance between Sam's school and the library if they are 8.4
cm apart on the same map?
Answers
Sam's school and the library are actually 420m apart.
What is the Scale Drawing?A scale drawing is a more compact representation of the original image, structure, or object.
The town is depicted at scale on the town map.
Original dimensions divided by the scale drawing's dimensions gives the drawing's scale.
The first step is to establish the map's scale in order to calculate the precise distance between Sam's school and the library.
Map scale: 250 m / 5 cm = 50
In this scale, 1 cm equals 50 m.
Scale of the drawing times the distance on the map equals the actual distance between Sam's school and the library.
50 x 8.4 = 420m
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Find the first three terms of this sequence Un=5n-2n3.
Answers
The first three terms of the sequence defined by the formula; Un=5n-2n³ as in the task content are; 3, -6 and -39 respectively.
What are the first three terms of the sequence given by the formula; Un=5n-2n³?It follows from the task content that the first three terms of the sequence defined by the formula be determined.
On this note, it follows that the first three terms are at; n = 1, n = 2 and n = 3 respectively.
Hence we have;
1st term; U(1) = 5(1) - 2(1)³ = 3.2nd term; U(2) = 5(2) - 2(2)³ = -6.3rd term; U(3) = 5(3) - 2(3)³ = -39.Hence, the first three terms are; 3, -6 and -39.
The first three terms of the sequence are as listed above.
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3: A Bunch of SystemsSolve each system of equations without graphing and show your reasoning. Then, check yoursolutions,
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Use the elimination method to solve the given system of equations.
To do so, multiply the first equation by -3 so that the coefficient of x in the first equation becomes the additive inverse of the coefficient of x in the second equation:
[tex]\begin{gathered} -3(2x+3y)=-3(16) \\ \Rightarrow-6x-9y=-48 \end{gathered}[/tex]Then, the system is equivalent to:
[tex]\begin{gathered} -6x-9y=-48 \\ 6x-5y=20 \end{gathered}[/tex]Add both equations to eliminate the variable x and to obtain an equation in terms of the variable y only:
[tex]\begin{gathered} (-6x-9y)+(6x-5y)=-48+20 \\ \Rightarrow-6x-9y+6x-5y=-28 \\ \Rightarrow-14y=-28 \\ \Rightarrow y=\frac{-28}{-14} \\ \therefore y=2 \end{gathered}[/tex]Replace y=2 into the first equation to find the value of x:
[tex]\begin{gathered} 2x+3y=16 \\ \Rightarrow2x+3(2)=16 \\ \Rightarrow2x+6=16 \\ \Rightarrow2x=16-6 \\ \Rightarrow2x=10 \\ \Rightarrow x=\frac{10}{2} \\ \therefore x=5 \end{gathered}[/tex]Replace y=2 and x=5 into the second equation to confirm the answer:
[tex]\begin{gathered} 6x-5y=20 \\ \Rightarrow6(5)-5(2)=20 \\ \Rightarrow30-10=20 \\ \Rightarrow20=20 \end{gathered}[/tex]Therefore, the solution to the system of equations is x=5, y=2.
what is the domain and range of {(1,0), (2,0), (3,0) (4,0), (5,0)}
Answers
We have the following:
The domain is the input values or the values of x and the range is the output values or the values of y
Therefore:
[tex]\begin{gathered} D=\mleft\lbrace{}1,2,3,4,5\mright\rbrace \\ R=\mleft\lbrace0\mright\rbrace \end{gathered}[/tex]Professor Ivy’s students have a Mean grade of 69.5 and a Standard Deviation of 6.5.3. If Johnny has an 82 in the class, what would the z-score for Johnny’s grade be? (round to the tenthsplace)4. What percentile does Johnny’s score put him in? (round to the nearest whole number)
Answers
Given:
Mean,ц = 69.5
Standard deviation, σ = 6.5
Let's solve for the following:
• 3. If Johnny has an 82 in the class, what would the z-score for Johnny’s grade be?
Apply the z-score formula:
[tex]z=\frac{x-\mu}{\sigma}[/tex]Where:
x = 82
ц = 69.5
σ = 6.5
Thus, we have:
[tex]\begin{gathered} z=\frac{82-69.5}{6.5} \\ \\ z=\frac{12.5}{6.5} \\ \\ x=1.9 \end{gathered}[/tex]Therefore, the z-score is 1.9
Question 4.
Here, we are to find P(Z<1.9).
Using the standard normal distribution table, we have:
NORMSDIST(1.9) = 0.9712
Now convert to percentage:
0.9712 x 100 = 97.12% = 97%
ANSWER:
3). 1.9
4.) 97%
Given the definitions of f(a) and g(x) below, find the value of (19)( 1),f (x) = x2 + 3x – 11g(x) = 3a + 6
Answers
The given functions are,
[tex]\begin{gathered} f(x)=x^2+3x-11_{} \\ g(x)=3x+6 \end{gathered}[/tex]Fog can be determined as,
[tex]\begin{gathered} \text{fog}=f(g(x)) \\ =f(3x+6) \\ =(3x+6)^2+3(3x+6)-11 \\ =9x^2+36+36x+9x+18-11 \\ =9x^2+45x+43 \end{gathered}[/tex]The value of fog(-1) can be determined as,
[tex]\begin{gathered} \text{fog}(-1)=9(-1)^2+45(-1)+43 \\ =9-45+43 \\ =7 \end{gathered}[/tex]Thus, the requried value is 7.
5. Helen, Riley, and Derrick are on a running team. Helen ran 15 1/4 kilometers last week. Riley ran 4 1/12 less kilometers than Helen, and Derrick ran 7 3/8 more kilometers than Riley. If their goal is to run 60 kilometers in total, how much further do they need to run to meet their goal? I
Answers
Given in the scenario:
a.) Helen ran 15 1/4 kilometers last week.
b.) Riley ran 4 1/12 less kilometers than Helen.
c.) Derrick ran 7 3/8 more kilometers than Riley.
d.) Their goal is to run 60 kilometers in total.
To be able to determine how much further do they need to run to get 60 kilometers in total, we must first determine how many kilometers did Riley and Derrick run.
We get,
A.)
[tex]\text{Riley: }4\frac{1}{12}\text{ less kilometers than Helen}[/tex][tex]\text{ = 15 }\frac{1}{4}\text{ - 4 }\frac{1}{12}[/tex]Recall: To be able to subtract mixed numbers, you must first convert them into an improper fraction with a common denominator. The LCM of the two denominators must be their denominator when converted.
The LCM of 4 and 12 is 12. We get,
[tex]\text{ 15 }\frac{1}{4}\text{ = }\frac{1\text{ + (4 x 15)}}{4}\text{ = }\frac{1\text{ + 60}}{4}\text{ = }\frac{61}{4}\text{ = }\frac{(61)(3)}{12}\text{ = }\frac{183}{12}[/tex][tex]4\text{ }\frac{1}{12}\text{ = }\frac{1\text{ + (4 x 12)}}{12}\text{ = }\frac{1\text{ + 48}}{12}\text{ = }\frac{49}{12}[/tex]Let's now proceed with the subtraction,
[tex]15\frac{1}{4}-4\frac{1}{12}=\frac{183}{12}\text{ - }\frac{49}{12}\text{ = }\frac{183\text{ - 49}}{12}\text{ = }\frac{134}{12}\text{ = }\frac{\frac{134}{2}}{\frac{12}{2}}\text{ = }\frac{67}{6}\text{ or 11}\frac{1}{6}[/tex]Conclusion: Riley ran 11 1/6 kilometers.
B.)
[tex]\text{Derrick: }7\frac{3}{8}\text{ more kilometers than Riley}[/tex][tex]\text{ = 11}\frac{1}{6}\text{ + 7}\frac{3}{8}[/tex]Recall: To be able to add mixed numbers, you must first convert them into an improper fraction with a common denominator. The LCM of the two denominators must be their denominator when converted.
The LCM of 6 and 8 is 24. We get,
[tex]11\frac{1}{6}\text{ = }\frac{1\text{ + (11 x 6)}}{6}\text{ = }\frac{1\text{ + 66}}{6}\text{ = }\frac{67}{6}\text{ = }\frac{(67)(4)}{24}\text{ = }\frac{268}{24}[/tex][tex]7\frac{3}{8}\text{ = }\frac{3\text{ + (7 x 8)}}{8}=\frac{3\text{ + 56}}{8}=\frac{59}{8}=\frac{(59)(3)}{24}=\frac{177}{24}[/tex]Let's now proceed with the addition,
[tex]11\frac{1}{6}\text{ + 7}\frac{3}{8}\text{ = }\frac{268}{24}\text{ + }\frac{177}{24}\text{ = }\frac{268\text{ + 177}}{24}\text{ = }\frac{445}{24}\text{ or 18}\frac{13}{24}[/tex]Conclusion: Derrick ran 18 13/24 kilometers.
C.) To be able to determine how much further do they need to run to get 60 kilometers in total, we subtract 60 by the sum of distance the three people ran.
We get,
[tex]\text{ 60 - (15 }\frac{1}{4}\text{ + 11}\frac{1}{6}\text{ + 18}\frac{13}{24})[/tex]The same process that we did, convert all numbers into similar fractions.
The LCM of 4, 6 and 24 is 24. We get,
[tex]15\frac{1}{4}\text{ = }\frac{1\text{ + }(15\text{ x 4)}}{4}\text{ = }\frac{1\text{ + 60}}{4}\text{ = }\frac{61}{4}\text{ = }\frac{(61)(6)}{24}\text{ = }\frac{366}{24}[/tex][tex]11\frac{1}{6}\text{ = }\frac{1\text{ + (11 x 6)}}{6}\text{ = }\frac{1\text{ + 66}}{6}\text{ = }\frac{67}{6}\text{ = }\frac{(67)(4)}{24}\text{ = }\frac{268}{24}[/tex][tex]\text{ 18}\frac{13}{24}=\text{ }\frac{13+(18\text{ x 24)}}{24}\text{ = }\frac{13\text{ + 432}}{24}\text{ = }\frac{445}{24}[/tex][tex]60\text{ = }\frac{60\text{ x 24 }}{24}\text{ = }\frac{1440}{24}[/tex]Let's proceed with the operation,
[tex]\text{ 60 - (15 }\frac{1}{4}\text{ + 11}\frac{1}{6}\text{ + 18}\frac{13}{24})\text{ = }\frac{1440}{24}-(\frac{366}{24}\text{ + }\frac{268}{24}\text{ + }\frac{445}{24})[/tex][tex]\text{ }\frac{1440\text{ - (366 + 268 + 445)}}{24}\text{ = }\frac{1440\text{ - 1079}}{24}[/tex][tex]\text{ = }\frac{361}{24}[/tex]Therefore, they need to run a total of 361/24 kilometers to be able to meet their goal.
A collection of dimes and quarters has a value of $1.35. List all possible combinations of dimes and quarters. Remember to write a let statement
Answers
3 combinations:
3 quarters and 6 dimes
5 quarters and 1 dime
1 quarter and 11 dimes
1) Remember that a dime corresponds to $0.10 and a quarter to $0.25. And the value we want to find is $1.35
2) As we can see the last digit on $1.35 is 5 then we can infer that we're going to need an odd number of quarters ($0.25). Also, notice that we need whole numbers for the quantities of each coin. In other words, multiples of 0.10 and 0.25 whose sum yields to $1.35. So let's do it step by step:
So, we can write out the following list of combinations:
q (quarter) 3 q = 3 x 0.25 = $ 0.75
d (dimes) 6 d = 6 x 0.10 = $ 0.60
0.60 + 0.75 = 1.35
2.2) Another possible combination:
q (quarter) 5 q = 5 x 0.25 = $ 1.25
d (dimes) 1 d = 1 x 0.10 = $ 0.10
0.10+1.25= 1.35
2.3)
q (quarter) 1 q = 1 x 0.25 = $ 0.25
d (dimes) 11 d = 11x 0.10 = $ 1.10
0.25+1.10 = 1.35
3) Hence, considering that we need to combine dimes and quarters and their sum must be lesser than $1.35 We have three combinations with whole numbers of dimes and quarters:
3 quarters and 6 dimes
5 quarters and 1 dime
1 quarter and 11 dimes
A) Write an expression for the given number trick B) Simplify the expression you came up with
Answers
a)
Since we need an Expression, we also need a variablel for the "number".
Let's use "n".
We will translate each of the lines:
Pick a number : n
Mutiply that number by 12, so it becomes: n x 12
Add 15 to that, so we put parenthesis around that expression and add "15" to it:
(n x 12) + 15
Divide by 3, then we simply divide whole thing by 3, so we have:
[tex]\frac{(n\times12)+15}{3}[/tex]b)
To simplify, let's re-write:
[tex]\begin{gathered} \frac{(n\times12)+15}{3} \\ =\frac{12n+15}{3} \\ =\frac{12n}{3}+\frac{15}{3} \\ =4n+5 \end{gathered}[/tex]This is the simplified form.
The pro shop at the Hidden Oaks Country Club ordered two brands of golf balls. Swinger balls cost$2.10 each and the Supra balls cost $1.00 each. The total cost of Swinger balls exceeded the total costof the Supra balls by $330.00. If an equal number of each brand was ordered, how many dozens ofeach brand were ordered?AnswerHow to enter your answer (opens in new window)KeypadKeyboard Shortcutdozen
Answers
The Solution:
Given that equal number of each brand of golf ball was ordered.
Let the number of each brand ordered be represented with n
Each swinger ball cost $2.10
So, the total cost of the swinger ball ordered is:
[tex]2.10n[/tex]Each Supra ball cost $1.00
So, the total cost of the supra ball ordered is:
[tex]\begin{gathered} 1.00\times n \\ \text{which becomes}\colon \\ n \end{gathered}[/tex]Given that the total cost of the Swinger balls exceeded the total cost of the Supra balls by $330.00. We have the linear equation below:
[tex]2.1n=n+330[/tex]We are required to find the number of dozens of each brand of golf balls that were ordered.
So, we shall solve for n and then divide the value by 12.
[tex]\begin{gathered} 2.1n=n+330 \\ \text{collecting the like terms, we get} \\ 2.1n-n=330 \\ 1.1n=330 \end{gathered}[/tex]Dividing both sides by 1.1, we get
[tex]\begin{gathered} \frac{1.1n}{1.1}=\frac{330}{1.1} \\ \\ n=300\text{ balls} \end{gathered}[/tex]Dividing 300 by 12 (since 1 dozen = 12 balls), we get
[tex]\frac{300}{12}=25\text{ dozens of each brand of golf balls were ordered.}[/tex]Therefore, the correct answer is 25 dozens.
Translate the following word phrases to an algebraic expression and simplify: “8 times the difference of 6 times a number and 3”
Answers
SOLUTION:
Step 1:
In this question, we are meant to:
Translate the following word phrases to an algebraic expression and simplify:
“8 times the difference of 6 times a number and 3”
Step 2:
Assuming the unknown number be y, we have that:
[tex]\begin{gathered} 8\text{ ( 6y - 3 )} \\ =\text{ 48 y - 24} \end{gathered}[/tex]CONCLUSION:
The final answer is:
[tex]48y\text{ - 24}[/tex]
Solve the triangle with the given measures. More than one triangle may be possibletriangle ABCM
Answers
then
[tex]undefined[/tex]The sum of three consecutive integers is -39. What are the three numbers? Enter your answer as three numbers separated by a comma.
Answers
Answer:
-12, -13, and -14
Explanation:
x, y, and z are the three consecutive numbers and they sum -39, so we can write the following equation
x + y + z = -39
Since these numbers are consecutives, we get
y = x + 1
z = x + 2
So, replacing these equation on the first one and solving for x, we get
x + y + z = -39
x + (x + 1) + (x + 2) = -39
x + x + 1 + x + 2 = -39
3x + 3 = -39
3x + 3 - 3 = -39 -3
3x = -42
3x/3 = -42/3
x = -14
Then, y and z are
y = -14 + 1 = -13
z = -14 + 2 = -12
Therefore, the consecutive numbers are
-12, -13, and -14
The equation for the line of best fit is shown below.What does the y-intercept represent? A. the cost to upload an unlimited amount of files B. the cost to enroll in the file sharing service C. the cost per file uploaded D. the cost per Mb uploaded
Answers
Answer:
B. the cost to enroll in the file-sharing service
Explanation:
The y-intercept is the cost when x = 0. It means that it is the cost of the service when the customer uploads 0 Mb, so it should represent the cost to enroll in the file-sharing service.
Find the exact solution to the exponential equation. (No decimal approximation)
Answers
Let's solve the equation:
[tex]\begin{gathered} 54e^{3x+3}=16 \\ e^{3x+3}=\frac{16}{54} \\ e^{3x+3}=\frac{8}{27} \\ \ln e^{3x+3}=\ln (\frac{8}{27}) \\ 3x+3=\ln (\frac{2^3}{3^3}) \\ 3x+3=\ln (\frac{2}{3})^3 \\ 3x+3=3\ln (\frac{2}{3}) \\ 3x=-3+3\ln (\frac{2}{3}) \\ x=-1+\ln (\frac{2}{3}) \\ x=-1+\ln 2-\ln 3 \end{gathered}[/tex]Therefore the solution of the equation is:
[tex]x=-1+\ln 2-\ln 3[/tex]add or subtract : x/4 + 3/4 =
Answers
Answer:
x + 3 / 4
Explanation:
A rectangular vegetable garden will have a width that is 3 feet less than the length, and an area of 54 square feet. If x
represents the length, then the length can be found by solving the equation:
x(x-3) = 54
What is the length, x, of the garden?
The length is
feet.
The solution is?
Answers
To determine the length of the rectangular flower garden, we need to derive equations from the given measurements and relations. The given measurements are the area, and the relation of the width and the length. From these, we generate the equation needed. We do as follows:
Area = Length x Width
where length = x ft
width = x - 3 ft
area = 54 ft^2
54 ft^2 = x ft (x -3) ft
54 ft^2 = x^2 - 3x ft^2
Solving for the value of x, we will have two values which are
x = -6 ft ( NOTE: this value can't be the answer since we cannot have a negative value for the length)
x = 9 ft = length
I ONLY need help with the last question help me with special Angles in a circle..GEOMETRY
Answers
We want to know the measure of the angle BCD. In this case, we see that it is an inscribed angle, and then its measure is half of the arc it intercepts (in this case BD).
With this in mind,
[tex]m\measuredangle BCD=\frac{1}{2}m\hat{BD}=\frac{1}{2}(130^{\circ})=65^{\circ}[/tex]And then, the angle BCD has 65°.
What is the value of the trig ratio sin A?
Answers
The sine relation is given by the length of the opposite leg to the angle over the length of the hypotenuse.
So, for the given triangle, we have:
[tex]\begin{gathered} \sin A=\frac{BC}{AC}\\ \\ \sin A=\frac{20}{29} \end{gathered}[/tex]Therefore the value of sin A is 20/29.
in the figure shown MN is parallel to segment YZ what is the length of segment YZ
Answers
We will solve this question using the similar angle theorem
The shape consist of two triangles which i am going to draw out,
One is a big triangle while the other is a small triangle
Let NZ = a
To find NZ We will equate the ratio of the big triangle to that of the small triangle
[tex]\frac{7.5\operatorname{cm}}{3\operatorname{cm}}=\frac{(a+5)cm}{5\operatorname{cm}}[/tex]We then cross multiply to get,
[tex]\begin{gathered} 3(a+5)=7.5\times5 \\ 3a+15=37.5 \\ by\text{ collecting like terms we will have that} \\ 3a=37.5-15 \\ 3a=22.5 \\ \frac{3a}{3}=\frac{22.5}{3} \\ a=7.5\operatorname{cm} \end{gathered}[/tex]Therefore XZ=XN+NZ
[tex]XZ=5+7.5=12.5\operatorname{cm}[/tex]To calculate YZ ,
We will use the pythagorean theorem,
[tex]\begin{gathered} XZ^2=YZ^2+XY^2 \\ 12.5^2=YZ^2+7.5^2 \\ 156.25=YZ^2+56.25 \\ YZ^2=156.25-56.25 \\ YZ^2=100 \\ YZ=\sqrt[]{100} \\ \vec{YZ}=10.0cm \end{gathered}[/tex]Therefore ,
The value of YZ is
[tex]\vec{YZ}=10.0\operatorname{cm}[/tex]Hence ,
The correct answer is OPTION B
