Calculate the AHrxn from the AH of formation for the following reaction. C2H4(g) + 302(g) 2C02(g) + 2H20(1). Formation AH values for C2H4(g) = 52.30 kJ/mol, for 02(g) = 0 kJ/mol, for CO2(g) = -393.5 kJ/mol and for H20(1) =-285.8kJ/mol.A. -1305kJB. 1350kJC. 1411kJD. -1411kJ

Answers

Answer 1

Answer

A. -1305 kJ

Explanation

Given:

Equation: C2H4(g) + 302(g) ---- > 2C02(g) + 2H20(l).

Formation ΔH values:

​​for C2H4(g) = 52.30 kJ/mol,

for 02(g) = 0 kJ/mol,

for CO2(g) = -393.5 kJ/mol, and

for H20(1) = -285.8kJ/mol.

What to find:

The ΔHrxn from the ΔH of formation for the given reaction.

Step-by-step solution:

ΔHrxn = (Sum of ΔH formation for the product) - (Sum of ΔH formation for the reactants).

ΔHrxn = (ΔH for 2CO2(g) + ΔH for 2H2O(l)) + (ΔH for C2H4(g) + ΔH for 3O2(g))

ΔHrxn = [(2 x -393.5) + (2 x -285.8)] + [52.30 + (3 x 0)]

ΔHrxn =(-787.0 - 571.6) + (52.30 + 0)

ΔHrxn = -1358.6 + 52.30

ΔHrxn = -1306.3 kJ

so the closest answer is A. -1305 kJ


Related Questions

1. Find the elements sodium, oxygen, and phosphorus on the periodic table. Describe the monoatomic ions each would form. Then, given what you know about chemical bonding, describe and give the formulas for the types of ionic compounds they would produce with each other. Use the periodic table in the Chemistry: Problems and Solutions book to help with your answers.2. Given the chemical formulas of the following compounds, name each compound and state the rules you used to determine each name.KIFe2O3(NH4)3PO4

Answers

Answer for 2:

- KI: potassium iodide

- Fe2O3: diiron trioxide

- (NH4)3PO4: ammonium phosphate

Explanation for 2:

• KI,:

The compound KI is called potassium iodide, because it is a hydracid salt that has potassium in the positive parte (that's why it keeps the name of the metal). While the negative parte of the salt comes from the non-metal iodine.

• Fe2O3,:

The compound Fe2O3 is called

, because the molecule of this oxide has 3 oxygen atoms and 2 iron atoms.

• (NH4)3PO4:

The (NH4)3PO4 is a salt called ammonium phosphate, because it is formed from phosphoric acid (that gives the negative part of the salt), and ammonia (that gives the positive part of the salt). The negative part of salt ends in "...ate" because it comes from the acid that ends with the suffix "...ic".

Calculate the amount of zinc present in zinc carbonate.
Ca + ZnCO2(aq) --> CaCO3(aq) + Zn​

Answers

The group of organic substances known as organic carbonic acids includes zinc carbonate. Compounds with the carbonic acid functional group are known as organic carbonic acids. Zinc carbonate is a substance with a very low acidity

Explain about the Zinc carbonate?

An odourless, white, sand-like substance known as zinc carbonate. Cosmetics, lotions, ceramics, pottery, rubber, feed additives, and medications all use it.

Zinc (Zn), carbon (C), and oxygen make up the inorganic compound known as zinc carbonate (O). ZnCO3 is its chemical composition. Oxygen is -2, carbon is +4, and zinc has an oxidation state of +2.

With the chemical formula ZnCO3, zinc carbonate is a white, insoluble zinc salt. By reacting with the proper amounts of sulphate, it can be used to create the majority of straightforward zinc salts. Smithsonite, also known as zinc spar, is a mineral that contains zinc carbonate.

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Using 0.082 as your R value, what mass of NaN3 is required to produce 10L of N2 gas, at 273K and 1.5atm. Show all your work completely.Use the following formula to guide your work: 2NaN3 -> 2Na + 3 N2

Answers

To solve this question, we need to use the Clapeyron formula.

Clapeyron's formula is a mathematical expression that relates quantities such as pressure (P), volume (V), temperature (T) and the number of particles (n) that make up an ideal gas.

The formula is: PV = nRT

First, let's discover the number in moles of N2. We have:

P = 1.5 atm

V = 10 L

n = ???

R = 0.082 atm.L/mol.k

T = 273 K

1.5 x 10 = n x 0.082 x 273

15 = n x 22.386

n = 15/22.386

n = 0.67 moles

As we can see in the chemical reaction equation, the ratio between NaN3 and N2 is 2:3.

So:

2 mol of NaN3 --- 3 mol of N2

x mol of NaN2 --- 0.67 moles

3x = 2 x 0.67

x = 0.45 moles of NaN3

Now we transform this value into grams, using NaN3 formula mass, which is 65 g/mol:

65 g ---- 1 mol

x g ---- 0.45 mol

x = 29 g

Answer: 29 g of NaN3

A given sample of gas is held in a container with the volume of 6.02 L with a temperature of 59.5℃ at a pressure of 1.20 atm. What is the final pressure

Answers

The final pressure of a sample of gas held in a container with a volume of 6.02 L and a temperature of 59.5℃ is 0.26atm.

How to calculate pressure?

The pressure of a given gas can be calculated using Boyle's law equation as follows:

P₁V₁ = P₂V₂

Where;

P₁ = initial pressureV₁ = initial volumeP₂ = final pressureV₂ = final volumeT₁ = initial temperatureT₂ = final temperature

According to this question, a given sample of gas is held in a container with the volume of 6.02 L with a temperature of 59.5℃ at a pressure of 1.20 atm. The final pressure can be calculated as follows;

At STP;

V = 22.4LT = 273K

1.2 × 6.02/332.5 = P × 22.4/273

0.0217 = 0.082P

P = 0.26atm

Therefore, 0.26atm is the final pressure of the gas.

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In a different titration, a solid sample containing some Fe2+ ion weighs 1.705g. It requires 36.44 mL, 0.0244 M KMnO4 to titrate the Fe2+ in the dissolved sample to a pink end point.

a. How many moles MnO4 ion are required?
b. How many moles Fe2+ are there in the sample
c. How many grams of Fe are there in the sample?
d. What is the percent Fe in the sample?

Answers

The accurate responses are;

a) Number of moles of permanganate ion = 8.89 * 10^-4 moles

b) Number of moles of iron = 4.4 * 10^-3 moles

c) Mass of iron in the sample = 0.25 g

d) Percentage of iron in the sample = 14.7 %

What is titration?

The term titration refers to the kind of reaction in which the amount of substance can be obtained by the accurate determination of the volumes of the substances that have reacted in the process.

a) The number of moles of the permanganate ion that are involved is obtained from;

36.44 /1000 L * 0.0244 M = 8.89 * 10^-4 moles

b) Given that the reaction is 1:5 in the mole ratio of the permanganate ion and the iron III ion

1 mole of permanganate reacts with 5 moles of iron II

8.89 * 10^-4 moles reacts with 8.89 * 10^-4 moles* 5 moles/ 1 mole

= 4.4 * 10^-3 moles

c) Mass of the iron II ion in the sample = 4.4 * 10^-3 moles * 56 g/mol = 0.25 g

d) Percent of the iron in the sample = 0.25 g/1.705g * 100/1

= 14.7 %

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Ascorbic acid (vitamin C) is important in many metabolic reactions in the body, including the synthesis of collagen and prevention of scurvy. Given that themass percent composition of ascorbic acid is 40.9% C, 4.58% H, and 54.5% O, determine the empirical formula of ascorbic acid. Show all your work

Answers

Empirical formula:

Step 1

Information already provided

The mass percent composition:

40.9 % C

4.58 % H

54.5 % O

Information needed: from the periodic table

For C) 1 mol = 12.01 g

For H) 1 mol = 1.008 g

For O) 1 mol = 15.99 g

---------------------------

Step 2

A sample of 100 g is assumed, so:

40.9 % C => 40.9 g C

4.58 % H => 4.58 g H

54.5 % O => 54.5 g O

--------------------------

Step 3

Convert mass into moles:

40.9 g C x (1 mol/12.01 g) = 3.40 moles C

4.58 g H x (1 mol/1.008 g) = 4.54 moles H

54.5 g O x (1 mol/15.99 g) = 3.40 moles O

------------------------

Step 4

All moles calculated in step 3 need to be divided by the smallest one.

3.40 moles C/3.40 moles = 1

4.54 moles H/3.40 moles = 1.33

3.40 moles O/3.40 moles = 1

-----------------------

Step 5

Integer numbers are needed, so let's multiply by 3 all of them in step 4

Therefore,

For C) 3

For H) 3.99 = 4 approx.

For O) 3

All these numbers calculated will be the subindexes in ascorbic acid

Answer:

Empirical formula: C3H4O3

Which of the following will not affect the rate of a reaction?nature of the reactantscolor of reactanttemperatureconcentration of a reactant

Answers

Answer:

Color of reactant. Option B is correct

Explanations:What is a rate of reactions?

This is defined as the speed at which a reaction takes place. It can be expressed in terms of the concentration of reactants or products formed per unit time.

The following are the factors that affects reaction rate.

- concentration of a reactant

- Temperature

- Nature of the reactant

- Surface Area

- Catalysts.

Based on the explanations above, we can conclude that the color of reactant will not affect the rate of a reaction

0.650 moles of O₂(g) are added to 1.00 L flask and the internal pressure ismeasured at 20.00 atm. What is the temperature of the gas under theseconditions (in *C)? ________ °C?

Answers

1) List the known and unknown quantities.

Sample: O2

Amount of substance: 0.650 mol O2.

Volume: 1.00 L.

Pressure: 20.00 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)

Temperature: unknown.

2) Set the equation.

Ideal gas law.

[tex]PV=nRT[/tex]

3) Plug in the known quantities and solve for T.

[tex](20.00\text{ }atm)(1.00\text{ }L)=(0.650\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(T)[/tex][tex]T=\frac{(20.00atm)(1.00L)}{(0.650\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})}[/tex][tex]T=374.97\text{ }K[/tex]

4) Convert K to ºC.

[tex]ºC=K-273.15[/tex][tex]ºC=374.94-273.15[/tex][tex]ºC=101.81\text{ }ºC[/tex]

The temperature of the gas under these conditions is 101.81ºC.

.

A reaction take place between an acid and 0.5 grams of powdered magnesium. Which statement is true?A. The powdered magnesium reacts faster because the activation energy has been lowered.B. The magnesium tracts reacts faster because It has a higher concentration of magnesium.C. The powdered magnesium react faster because it has a greater surface area.D. The magnesium react faster it will create a higher temperature once the reaction starts

Answers

Explanation:

The rate of a reaction is defined as the rate of disappearance of reactants in a reaction or the rate of conversion of appearance of products during a reaction.

The rate of a reaction depends on the concentration of the reactants, the temperature of the reaction, the nature of reactants, and the presence or absence of catalysts during the reaction.

The surface of reactants comes into play. Reactants with high surface areas react faster than reactants with fewer surface areas. Hence, powdery reactants react faster than solid reactants.

Answer: C. The powdered magnesium react faster because it has a greater surface area.

Sugar forms when carbon, oxygen, and hydrogen combine in a specific ratio. From what you know about elements and the periodic table, what is true about the bonding in sugar?

Answers

Answer

B. The bonds in the compound are covalent

Explanation

The carbon, oxygen, and hydrogen that combine in a specific ratio to form the sugar are nonmetals. From what was learned about elements and the periodic table, nonmetals form covalent bonds among themselves to form compounds.

So what is true about the bonding in sugar is:

B. The bonds in the compound are covalent.

Name the attatched alkene

Answers

Answer:

limonene molecule.

Explanation:

During a titration, an endpoint was reached after adding 20 mL of sodium hydroxide solution, NaOH(aq), to 20 mL of sulfuric acid, H2SO4. The sodium hydroxide solution had a concentration of 1.50 mol/L. What was the initial concentration of the sulfuric acid? Select one: a. 1.50 mol/L b. 2.25 mol/L c. 3 mol/L d. 0.75 mol/L

Answers

Write the balanced chemical equation for the reaction as follows:

[tex]2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O[/tex]

Given:

Concentration of sodium hydroxide =1.50 mol/L

Volume of sodium hydroxide = 20 mL

Concentration of sulfuric acid = x

Volume of sulfuric acid = 20 mL

Firstly, we will determine the moles that is in 20 mL of 1.5 M NaOH:

[tex]\begin{gathered} 1.5\text{ }mole=1000mL \\ x\text{ }mol=20mL \\ \\ x=\frac{1.5mol\times20mL}{1000mL} \\ \\ x=0.03mol\text{ }NaOH \end{gathered}[/tex]

Based on the balanced chemical equation and the moles of NaOH we can use stoichiometry (ratios) to determine the moles of 20 mL sulfuric acid:

[tex]0.03mol\text{ }NaOH\times\frac{1mol\text{ }H_2SO_4}{2mol\text{ }NaOH}=0.015\text{ }mol[/tex]

Now that we know how many moles are in 20 mL of H2SO4, we can determine the moles in 1000mL (initial concentration):

[tex]\begin{gathered} 0.015\text{ }mol=20\text{ }mL \\ x\text{ }mol=1000\text{ }mL \\ x=\frac{0.015mol\times1000mL}{20mL} \\ \\ x=0.75mol•L^{-1} \end{gathered}[/tex]

Answer: D) 0.75 mol/L,

You randomly fina a brick labeled platinum! You get really excited because you look it up and find that platinum is worth $31.86 per gram.then density of platinum is 21.45 g/mL. You measure the volume and it’s 150 cm3 or 150.0mL. How much should the brick weigh if it’s is really platinum? And how much money would the brick be work

Answers

Step 1

Density is defined as:

D = mass of the platinum brick/volume of the platinum brick

D = m/V

------------------

Step 2

Information provided:

D = 21.45 g/mL

V = 150.0 mL

m = unknown

Price per grams of Pt = 31.86 $/g of Pt

Symbol for platinum = Pt (please, look at the periodic table)

-----------------

Step 3

How much should the brick weigh if it’s is really platinum?

From D = m/V

=> D x V = m

=> 21.45 g/mL x 150.0 mL = 3218 g approx.

------

And how much money?

3218 g of Pt x 31.86 $/g of Pt = $99,660 approx.

Answer:

3218 g

$99,660

when a bunsen burner is properly adjusted, what should the flame look like?

Answers

when a bunsen burner is properly adjusted, the flame looks Blue with no gap between the burner and the flame.

A Bunsen burner is a particular kind of gas burner that is frequently utilized as a heat source in lab investigations. The barrel or chimney of the burner is made up of a straight tube that extends vertically from a flat base. At the bottom of the chimney, liquid petroleum gas, such as propane or butane, or natural gas, primarily methane, is delivered.

The base of the chimney on Bunsen burners typically has a hose barb installed so that rubber tubing may supply the gas from a gas nozzle on the lab bench.

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3) Water is a polar solvent; gasoline is a non-polar solvent. Which compounds are
more likely to dissolve in water? Check all that apply.

CCI4
NaCI
CH4
Oil

Answers

According to given statement NaCI compounds are more likely to dissolve in water.

What is polar solvent with example?

Polar solvents, which do have "positive" and "negative" charges at different points throughout their structures, can dissolve other polar compounds. Acetone, methanol, dimethylformamide (DMF), dimethylsulfoxide (DMSO), isopropanol, and ethanol are some other polar solvents. A few of these solvents is water.

Why water is a polar solvent?

Due to the uneven distribution of its electron density, water is a polar molecule. This demonstrates that water is indeed a polar molecule because hydrogen and oxygen have different electronegativities. The fact that water can dissolve more chemicals compared to any other liquid makes it known as the "universal solvent."

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what is the volume (in liters) of a 4.2 gram sample of O2 at STP

Answers

to solve this we need to use the ideal gas law:

[tex]PV=nRT[/tex]

we need to calculate the number of mols of O2

[tex]n=\frac{m}{Mm}=\frac{4.2g}{32\text{ g/mol}}=0.131mol[/tex]

Now we just have to solve for volume and use the number of mols just calculated and the standard pressure (1 atm) and temperature 273.15K:

[tex]V=\frac{nRT}{P}=\frac{0.131mol\cdot0.082\text{ }\frac{atm\cdot l}{K\cdot mol}273.15K}{1atm}=2.94l[/tex]

why show you heat the sample to constant mass

Answers

Heating to constant mass is done to retain the constant mass of the sample so that its weight remains the same and does not affect the reading throughout the experiment.

Heating to constant mass is a process in which a sample usually a powder or crystal is heated until the mass of the sample remains constant or the same.This is done to remove the excess moisture or other impurities that may affect the accuracy of the readings during the experiment.In this process, the sample is heated, cooled down weighed, and again the sample is heated, cooled down, and weighed. This process is done repeatedly until the mass of the sample remains constant in two or three consecutive measurements. Thus, heating to constant mass gives a minimized error during the experiment.

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Question 16 of 25According to the Gibbs free energy equation, AG = AH-TAS, when is areaction always spontaneous?A. When AH and AS are both positiveB. When AH is negative and AS is positiveC. When AH is positive and AS is negativeD. When AH and AS are both negativeSUBMIT

Answers

Answer

B. When ΔH is negative and ΔS is positive

Explanation

The spontaneity of a reaction can be determined by the sign of the Gibbs free energy change. For a spontaneous reaction, the change in Gibbs free energy should be negative, that is:

[tex]\Delta G=\Delta H-T\Delta S[/tex]

The spontaneity of a process can depend on the temperature. Since the temperature value here corresponds to the absolute temperature, this implies that T > 0 for any T. Therefore, to have a negative difference for any temperature value, the change in enthalpy (ΔH), should be negative and the change in entropy (ΔS) should be positive so that we always subtract a positive number from a negative number. This corresponds to a negative value in ΔG.

Hence, the

The half-life of phosphorus−33 is 25.0 days. How much of a 2.7−oz sample of phosphorus−33 will remain after 150 days?

Answers

If phosphorus-33 have an half-life of 25 days the amount of phosphorus-33 that will remain after 150 days is 0.042 oz.

What is half-life?

Half-life is the time taken for half the sample of a radioactive substance to decay.

To calculate the amount of phosphorus-33 that will remain after 150 days, we use the formula below.

Formula:

R' = R/[tex]2^{T/t}[/tex]........ Equation 1

Where:

R = Original amount of phosphorus-33R' = Amount of phosphorus-33 that will remain after 150  daysT = Total timet = half-life

From the question,

Given:

R = 2.7 ozT = 150 dayst = 25 days

Substitute these values into equation 1

R' = 2.7/([tex]2^{150/25[/tex])R' = 2.7/[tex]2^{6}[/tex]R' = 2.7/64R' = 0.042 oz

Hence the amount of phosphorus-33 that will remain after 150 days is 0.042 oz.

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Which statement describes how a macroscopic property of gases provides information about microscopic gas particles?A. Gases fill their container, showing that gas particles are not tied together and can move far apart.B. Gases fill their container, showing that gas particles are strongly attracted through electrostatic forces.C. Gases have a fixed volume, showing that gas particles are strongly attracted through electrostatic forces.D. Gases have a fixed volume, showing that gas particles are not tied together and can move far apart.

Answers

It's important to know that gases don't have a defined volume as solids do because they don't have a definite shape.

Also, gas partcles are not tied together because their intermolecular forces are weak, this enables them to travel away one from another.

Therefore, the answer is A.

PLS HELP, IT’S DUE TODAY
In a nuclear fusion reaction, two small, light ___ (hydrogen atoms) combine under extreme __ and pressure to form one larger, heavier nucleus (helium).

Answers

Answer:

In a nuclear fusion reaction, two small, light 'nuclei' (hydrogen atoms) combine under extreme 'temperature' and pressure to form one larger, heavier nucleus (helium).

How many Chiral centers are in coibacin B

Answers

It is to be noted that Coibacin B has three Chiral Centers. A chiral center is a molecule atom that is bound to four separate chemical species, permitting optical isomerism.

What is Coibacin B?

Coibacin B is a natural substance with a substantial anti-inflammatory effect and possible utility in the treatment of leishmaniasis, a parasitic illness.

It should be noted that Leishmaniasis is a parasite infection that may be found in the tropics, subtropics, and southern Europe. It is considered a neglected tropical illness (NTD).

Infection with Leishmania parasites, which are disseminated by the bite of phlebotomine sand flies, causes leishmaniasis.

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Calculate the energy and frequency of red light having a wavelength of 650 nm (Note => 650 nm = 6.50 * 10^7 m)

Answers

The energy and frequency of the red light would be  2.88 × 10⁻¹⁹ Joules and 4.615 × 10¹⁴ Hz respectively if the red light has a wavelength of 650

nm.

What is Wavelength?

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

C = λν

As given in the problem we have to calculate the energy of the light if the wavelength of light is 6.5 × 10⁻⁷ meters.

The frequency of the red  light = 3 × 10⁸ / 6.5 × 10⁻⁷

                                                    = 4.615 × 10¹⁴ Hz

The energy of the red light = h ν

                                             = 6.26 × 10⁻³⁴ × 4.615 × 10¹⁴

                                             = 2.88 × 10⁻¹⁹ Joules

Thus, the energy and frequency of the red light would be  2.88 × 10⁻¹⁹ Joules and 4.615 × 10¹⁴ Hz respectively.

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Which is the least electronegative element?Group of answer choicescarbonnitrogenoxygenaluminum

Answers

In order to solve this question, we can use the electronegativity table (or also just a regular periodic table), which will give us the values of electronegativity for each element.

As we can see in this table, the least electronegative element will be Al, with only 1.61 of value. If you were with a regular periodic table, you could find this answer by thinking about the periodic table trend, or we can also call it a rule, that in most elements the electronegativity will grow in value from left to right and from the bottom to the top, then you would also get Al as your answer

Answer = Al, letter D

At 571.6 mmHg and 25 °C, a gas sample has a volume of 2,275 ml Determine the final pressure (in mmHg) at a volume of 1,255 mL and a temperature of 175°C? Show all your work

Answers

Here, there are 2 conditions of the gas here.

The next equation is used: (1)

[tex]\frac{P1xV1}{T1}=\frac{P2xV2}{T2}[/tex]

Data: conditions 1

P1 = pressure, in mmHg = 571.6 mmHg

T1 = temperature, in K = 25 °C + 273 = 298 K

V1 = 2,275 mL

-------------

Data: conditions 2

P2 = needs to be calculated

T2 = 175 °C + 273 = 448 K

V2 = 1,255 mL

--------------

From (1), P2 is cleared:

(P1 x V1/T1) x T2/V2 = P2

(571.6 mmHg x 2,275 mL/298 K) x (448 K/1,255 mL) = P2

1558 mmHg = P2

Answer: P2 = 1558 mmHg

give the n and l values and the number of orbitals for sublevel 5g.

Answers

The n and l values and the number of orbitals for sublevel 5g is :

5g shell , n= 5 subshell g , l = 4, Number of orbitals for sublevel = 9.

There are total four quantum numbers:

1) Principal quantum number , n

2) Angular quantum number , l

3) Magnetic quantum number , ml

4) spin quantum number , ms

For 5g shell, n = 5

subshell g , l = 4     ....0 - s , 1 - p , 2 - d, 3 - f, 4 -g

number of orbitals in subshell = (2l + 1)  ( 2×4 + 1) = 9

Thus,  The n and l values and the number of orbitals for sublevel 5g is :

5g shell , n= 5 subshell g , l = 4, Number of orbitals for sublevel = 9.

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What is the specific heat capacity of methanol (C) if it takes 7,490 joules of energy to heat 50.0 grams from 10.0 0C to 80.0 0C?

Answers

Answer:[tex]c=2.14J\text{/g}^0C[/tex]

Explanations

The formula for calculating the amount of heat energy absorbed is given as:

[tex]Q=mc\triangle t[/tex]

Given the following

• mass m = 50.0g

,

• Heat energy Q = 7490 Joules

,

• change in temperature = 80 -10= 70 degrees celsius

Substitute

[tex]\begin{gathered} 7490=50\times c\times70 \\ c=\frac{7490}{3500} \\ c=2.14J\text{/}g^oC \end{gathered}[/tex]

Hence the specific heat capacity of methanol is 2.14J/gC

While performing the extraction experiment, you were confused between the organic layer and the aqueous one, what is the easiest way to tell which layer is which?

Answers

The easiest way to tell which layer is wich, while performing the extraction experiment is to run a little test.

The test will consist on mixing a sample of both layers in different recipients with water.

After mixing them, the recipient with a homogeneous phase will have the aqueous layer, and the other one will be the organic layer.

Answer: The layer on top.

Explanation:

Assuming you were completing an extraction experiment and had a setup similar to the one below then the organic layer will float on top of the aqueous since most non-halogenated organic solvents have a density of less than 1.

35.A substance that affects the speed of a chemical reaction without itself being chemically changed is called a...Select one:a. catalyst.b. product.c. reactant.d. yield.

Answers

Answer

A. catalyst

Explanation

Catalyst, in chemistry, any substance that increases the rate of a reaction without itself being consumed.


A silver ring is composed of 1.81×1023 atoms. Calculate the mass of the ring in grams.

Answers

Solving with Moles

Mole equation: [tex]n=\dfrac{m}{MM}[/tex]

n = number of moles (mol)m = mass (g)MM = molar mass (g/mol)

To find mass given number of atoms:

Divide number of atoms by the number of atoms in the chemical formula ⇒ find number of moleculesDivide number of molecules by Avogadro's number ([tex]6.02*10^{23}[/tex]) ⇒ find number of moles (n)Solve for m using moles equation

Solving the Question

We're given:

Ag (silver)Atoms = [tex]1.81*10^{23}[/tex] atomsm = ?

In the chemical formula, which is Ag, there is only 1 atom.

Divide [tex]1.81*10^{23}[/tex] atoms by 1 atom to get the number of molecules in the silver ring:

[tex]1.81*10^{23}\div 1\\=1.81*10^{23}[/tex]

Therefore, there are [tex]1.81*10^{23}[/tex] molecules in the silver ring.

Now, divide [tex]1.81*10^{23}[/tex] molecules by Avogadro's number to find n:

[tex]\dfrac{1.81*10^{23}}{6.02*10^{23}}\\\\=\dfrac{1.81}{6.02}\\\\=\dfrac{1.81}{6.02}\\\\= 0.30066[/tex]

Therefore, the sample has 0.30066 mol.

Finally, solve for the mass using the moles equation:

[tex]n=\dfrac{m}{MM}[/tex]

⇒ Rearrange the equation:

[tex]m=n*MM[/tex]

⇒ MM of Ag = 107.87 g/mol

⇒ Plug in given information:

[tex]m=0.30066* 107.87\\m=32.4[/tex]

Therefore, the mass of the ring is 32.4 g.

Answer

32.4 g

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