The group of organic substances known as organic carbonic acids includes zinc carbonate. Compounds with the carbonic acid functional group are known as organic carbonic acids. Zinc carbonate is a substance with a very low acidity
Explain about the Zinc carbonate?An odourless, white, sand-like substance known as zinc carbonate. Cosmetics, lotions, ceramics, pottery, rubber, feed additives, and medications all use it.
Zinc (Zn), carbon (C), and oxygen make up the inorganic compound known as zinc carbonate (O). ZnCO3 is its chemical composition. Oxygen is -2, carbon is +4, and zinc has an oxidation state of +2.
With the chemical formula ZnCO3, zinc carbonate is a white, insoluble zinc salt. By reacting with the proper amounts of sulphate, it can be used to create the majority of straightforward zinc salts. Smithsonite, also known as zinc spar, is a mineral that contains zinc carbonate.
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How many significant figures (SF) are in each of the following measured quantities? Drag the appropriate measurement to the respectable bins
Chemistry => Measurements => Significant Figures
Significant figures correspond to the number of digits in a number. We have to take into account the following:
• Zeros at the beginning of a number or at the end are not counted as digits, but zeros in between the number should be counted.
,• When we write a number in scientific notation, the 10 that accompanies the number should not be counted.
Following these indications, let's count the significant figures of each given number:
In summary, we have the answer will be:
1SFs
3.00 m
4.0x10^3 mL
3SFs
50 100 00g
80.10 mL
60.4 °C
6SFs
9018.17 kg
A 45 mL sample of calcium chloride stock solution produces a 0.182 M diluted solution by adding 50. mL of water. What is the molarity of the stock solution?
A solution of Calcium Chloride was made, we are asked to find the concentration of the initial solution.
We will apply the following equation to find it:
[tex]C_1V_1=C_2V_2[/tex]Where,
C1 is the initial concentration we have to find
V1 is the initial volume, 45mL
C2 is the final concentration, 0.182M
V2 is the final volume, 50. mL
We clear C1 and replace the known data;
[tex]C_1=\frac{C_2V_2}{V_1}[/tex][tex]\begin{gathered} C_1=\frac{0.182M\times50.mL}{45mL} \\ C_1=0.202M \end{gathered}[/tex]The molarity of the stock solution is 0.202M
Answer: 0.202M
How many liters of a 0.75 M solution can be made with 75 grams of lead (ll) oxide?
Step 1
Molarity is defined as:
Molarity (M or mol/L) = Moles of lead (II) oxide/Volume of solution (L)
Molarity = mass of lead (II) oxide/molar mass of lead (II) oxide x volume (L) (1)
-------------------------
Step 2
The molar mass of PbO = 223 g/mol
PbO = lead (ll) oxide
------------------------
Step 3
Data provided:
Molarity = 0.75 M
Mass of PbO = 75 g
------------------------
Step 4
Procedure:
The volume of the solution is cleared from (1):
Volume (L) = mass PbO/(molar mass PbO x Molarity)
Volume (L) = 75 g/(223 g/mol x 0.75 mol/L) = 0.45 L approx.
Answer: Volume = 0.45 L
What makes water a polar molecule? options:A) The equal forces between oxygen and hydrogenB) The liquid nature of waterC) The uneven bend in the bond between oxygen and hydrogenD) The ionic bond between oxygen and hydrogen
The polarity of a molecule is given by the difference in charges, hydrogen has a slightly positive charge and oxygen has a negative charge. Its electronegativity difference between hydrogen and oxygen is less than 1.7 making the bond a covalent bond.
That said, we can rule out options A and D. Now, the state of matter does not affect the polarity of the molecule, so option B will also be incorrect.
The correct option will be C, since there is a difference in charges that makes water polar.
Answer: C) The uneven bend in the bond between oxygen and hydrogen
A 3.00 L sample of paint that has a density of 4.65 g/mL is found to contain 33.1 g lead (II) nitride. what is mass percentage of lead in the paint and what is the ppm?
Density relates the mass of a compound to its volume. We will first find the mass of the solution using the density and volume given. We have the following equation:
[tex]\rho=\text{ density = }\frac{Mass}{Volume}[/tex]We clear the mass,
[tex]\begin{gathered} Mass\text{ = }\rho\times Volume \\ Mass\text{ =}4.65\frac{g}{mL}\times3000mL \\ Mass\text{ =}13950\text{ g} \end{gathered}[/tex]So, the mass of paint is 13950 g. Now the mass percentage of the lead in the paint will be calculated as follows:
[tex]\begin{gathered} \%mass=\frac{\text{ Mass of lead (II) nitride}}{Mass\text{ of paint}}\times100 \\ \%mass=\frac{33.1\text{ g}}{13950\text{ g}}\times100 \\ \%mass=0.24\% \end{gathered}[/tex]The mass percentage of lead in the paint is 0.24%.
ppm concentration means the quantity of solute in milligrams (mg) is in a liter (L) of a solution. So, to calculate ppm concentration we will divide the milligrams of lead (II) nitride between the liters of paint:
[tex]\begin{gathered} \text{ppm = }\frac{\text{33.1g of lead}\times\frac{1000mg}{1g}}{3L} \\ \text{ppm =11033ppm of lead} \end{gathered}[/tex]The ppm of lead in the paint is 11033ppm.
4) Mixtures of He and oxygen are used in scuba diving to help prevent “TheBends". For a particular dive the total pressure in the tank is 15 atm. If thepartial pressure of oxygen is 6.0 atm, what is the partial pressure of He ?A
By following Daltons laws of partial pressure .
" the pressure that eachgaswould have exerted ,Add up to the total pressure" .
• Therefore :
,• Total Pressure = P.Pressure (oxygen) + P.Pressure of (He)
15 atm = 6atm + Pressure of He
P.Pressure ofHe = 15atm-6atm
= 9 atm
This means that the partial pressure of He = 9atm +
During the chlorination of silicon, chlorine gas is reacted with solid silicon to form silicon tetrachloride.Si(s) + 2Cl2(g) + heat - SiC|4(g)Which will not cause the reaction to shift towards the products?A) adding a catalystB) increasing the pressureC increasing the temperatureD) increasing the concentration of CL2(g)
Let's analyze each option to find what best fit as an answer:
A - the function of a catalyst is to lower the energy of activation in a reaction, causing it to occur in a faster way. Since this question is not much about energy or kinetics, this would be the best fit, adding a catalyst or not adding it would not be too influential in the shift of the reaction.
B - Increasing the pressure in a reaction containing gases will mostly favor the side with a lower value of moles, smaller amount of moles = less pressure, so if we add more pressure, the reaction will shift towards the side of the products
C - If we treat heat as a reactant, if we add more temperature, it will shift towards the products, to counteract this increase of temperature
D - Adding reactants will favor the reaction to shift towards the products
Therefore the answer is letter A
3. 135 g of ice is placed in a beaker of water. The water temperature in the beaker is 67 °C. After all the icemelts, the final water temperature in the beaker is 19.7 °C. 4 ptsHeat of fusion for water = 334 J/g. Specific heat of water = 4.184 J/g °C. T2-T1 = 47.3 °C.Note there are a couple different ways to solve this problems to sove this por(a) Determine the initial volume of water in the beaker (before the ice was added).(b) Determine the final volume of water in the beaker (after all the ice has melted).
Answer:
Explanation:
Answer to the 1st one. I have my doubts for the second one so didn't post :)
Use the balanced equation to solve the problem.Na₂CO3 +CaCl2 → 2NaCl + CaCO3115g of CaCl₂ react.How many moles of NaCl are made?mol
2.0724moles
Explanations:Given the balanced chemical reaction between Na2CO3 and CaCl2 expressed as:
[tex]Na_2CO_3+CaCl_2\rightarrow2NaCl+CaCO_3[/tex]Given the following parameters
Mass of CaCl₂ = 115g
Determine the moles of CaCl₂
[tex]\begin{gathered} moles\text{ of CaCl}_2=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CaCl}_2=\frac{115}{110.98} \\ moles\text{ of CaCl}_2=1.0362moles \end{gathered}[/tex]According to stochiometry, 1 mole of CaCl2 prodcues 2 moles of NaCl. The moles of NaCl requred is given as:
[tex]\begin{gathered} moles\text{ of NaCl}=2\times1.0362 \\ moles\text{ of NaCl}=2.0724moles \end{gathered}[/tex]Therefore moles of NaCl made is 2.0724moles
7. The average human can hold 4.0 L of oxygen (O₂) in their lungs. At body temperature (37 °C) and 110 kPa, how manymoles of gas is that?
Answer
number of moles = 0.171 mol
Explanation
Given
Volume of oxygen = 4.0 L
Temperature = 37 °C = 310 K
Pressure = 110 kPa = 1.08562 atm
we know R = 0.082 L.atm.k/mol
Required: number of moles
Solution
To solve this problem, use the ideal gas law
PV = nRT
n = PV/RT
n = (1.08562 x 4.0 L)/(0.082 L.atm.k/mol x 310 K)
n = 0.171 mol
Read each question carefully and choose the letter of the best answer.
This element is nonmetal and appears in the periodic table.
The number that represents the position of the elements is called, the atomic number, it also represents the number of protons = numbers of electrons an atom has.
Answer: D. the atomic number
number of litres of gas in 4.51 mol Xe
First, we assume STP conditions and Ideal gas conditions.
In STP conditions, we say that:
1 mol of any gas = 22.4 L (liters)
Procedure:
1 mol Xe ------ 22.4 L (STP)
4.51 moles Xe ------- X
X = 101 L
Answer: 101 L
How many grams of solute would you use to prepare the following solutions?241.0 mL of 1.11 M NaOHExpress your answer with the appropriate units.
10.7 grams
Explanations:The formula for calculating the molarity of a solution is given as:
[tex]\begin{gathered} molarity=\frac{moles}{volume} \\ moles=molarity\times volume \end{gathered}[/tex]Given the following parameters
molarity of NaOH = 1.11M
volume of solution = 241.0mL = 0.241L
Find the moles of NaOH
[tex]\begin{gathered} moles\text{ of Na}OH=\frac{1.11mol}{L}\times0.241L \\ moles\text{ of Na}OH=0.2675moles \end{gathered}[/tex]Determine the mass of solute (NaOH)
[tex]\begin{gathered} Mass\text{ of NaOH}=mole\times molar\text{ mass} \\ Mass\text{ of NaOH}=0.2675\times40 \\ Mass\text{ of NaOH}=10.7grams \end{gathered}[/tex]Hence the grams of solute that would be used to prepare the solution is 10.7grams
Which of the following describes a physical property?Corrosiveness of sodiumToxcity of cadmiumWater when heated forms steamFlammability of hydrogen
Physical properties are the ones that describe the behavior of the substances when exposed to different physical changes.
In this case, the one that describes a physical change is water when heated forms steams. In this case water changes its state of matter but it is still the same substance, there is not chemical change, just physical.
The correct answer is Water when heated forms steams.
39.When the polyatomic ion (SO4)-2 combines with the iron (III) ion, Fe+3, the formula for the compound is...Select one:a. FeSO4b. Fe2SO4c. Fe2(SO4)3d. Fe3(SO4)2
Answer
c. Fe2(SO4)3
Explanation
The polyatomic ion (SO₄)⁻² has a net charge of -2 and iron (III) ion, Fe⁺³ has an oxidation number of +3. For a compound to be formed between them, two of Fe⁺³ will need three of the polyatomic ion, (SO₄)⁻² and the formula of the compound will be Fe2(SO4)3.
Isopropyl alcohol is mixed with water to produce 32.0% (v/v) alcohol solution.How many milliliters of each component are present in 655 mL of this solution? Assume the volumes are additive.Alcohol: _____________ mL Water: __________ mL
Isopropyl alcohol + water = Solution
Solute = Isopropyl alcohol
Solvent = water
% V/V = mL of solute / 100 ml of solution
Now we have 655 mL of solution.
32.0 % V/V means 32 mL of Isopropyl alcohol dissolved in 100 mL of solution.
So,
32 mL Isopropyl alcohol ------------------- 100 mL Solution
x ------------------- 655 mL Solution
x represents the volume of Isopropyl alcohol in 655 mL of solution
[tex]x\text{ = }\frac{655\text{ mL solution x 32 mL }Isopropylalcohol\text{ }}{100\text{ mL solution}}=\text{ 209.6 mL of }Isopropylalcohol[/tex]Now
Alcohol: 209.6 mL
Water: 655 mL (solution = Alcohol + Water) - 209.6 mL (alcohol) = 445.4 mL of water
Find the element that is oxidized and the one that is reduced Si + 2 F2 --> SiF4
Answer
The element that is oxidized is Si and the one that is reduced is F₂.
Explanation
Si + 2F₂ → SiF₄
The given reaction is an oxidation-reduction (redox) reaction:
Oxidation: Si → Si⁴⁺ + 4e⁻
Reduction: 2F₂ + 4e⁻ → 4F⁻
Si is a reducing agent, and F₂ is an oxidizing agent.
An oxidizing agent gains electrons and is reduced in a chemical reaction.
A reducing agent loses electrons and is oxidized in a chemical reaction.
Therefore, the element that is oxidized is Si and the one that is reduced is F₂.
When copper is heated with an excess of sulfur, copper(I) sulfide is formed.
In a given experiment, 1.53 g of copper was heated with excess sulfur to yield 1.76 g of copper(I) sulfide.
What is the percent yield?
If 1.53 g of copper is heated with excess sulfur to yield 1.76 g of copper (I) sulfide, the percent yield would be 75.43%.
Percent yieldThe percent yield of a reaction is the actual yield relative to the theoretical yield of the same reaction.
The percent yield of a reaction is mathematically expressed as:
Percent yield = actual yield/theoretical yield x 100%.
Let us now consider the reaction in question. The equation of the reaction is given as:
[tex]Cu + S --- > CuS[/tex]
The mole ratio of the copper that reacts to the copper sulfide that is formed is 1:1.
Recall that: mole = mass/molar mass
The molar weight of copper is 63.55 g/mol
Mole of 1.53 g copper = 1.53/63.55
= 0.024 moles
The equivalent mole of copper sulfide produced will also be 0.024 moles.
The molar mass of CuS is 95.61 g/mol
Mass of 0.024 moles CuS = 0.024 x 96.61
= 2.32 g
2.32 g is the theoretical yield of the reaction. But 1.76 g of copper sulfide is the actual yield.
Percent yield = 1.75/2.32 x 100%
= 75.43%
Thus, the percent yield of the reaction, if 1.53 g of copper is heated with excess sulfur to produce 1.76 g of copper (I) sulfide, is 75.43%.
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General nucleus and electron attraction explained
General nucleus and electron attraction explained
We can say this:
The net positive charge from the nucleus (remember that protons are in the nucleus) that an electron can feel attraction from, is the effective nuclear charge. The core electrons (electrons are on shells around the nucleus) are said to shield the valence electrons from the full attractive forces of the pro
calculate the theoretical and % yield of copper when 0.500 g of Cu was used and 0.350 g were recovered at the end of the experiment. complete solution
The theoretical percentage yield of copper is 70%
This is further explained below.
What is a yield?Generally, the equation for yield is mathematically given as
[tex]yield =\frac{\text { mote no. of product }}{\text { mote no. of reactant }} \times 100$[/tex]
Here, Based on Theoretical Yield
[tex]\begin{aligned} \text { mole rio. of reactant } &=-\frac{0.5}{63.546} \text { mole } \\ \end{aligned}$[/tex]
Based on the Actual yield
mole rio. of Product=0.35/63.546 mole
(Here atomic man of Cu=63.546g/mol )
Therefore, we apply the initially stated equation for %yield
So, %yield =[tex]\frac{\frac{0.35}{63.546}}{\frac{0.5}{(63.546}} \times 100 \%$[/tex]
=[tex]\frac{0.35}{0.5} \times 100 \%\\[/tex]
=0.7 *100%
=70%
In conclusion, the percentage yield is 70%
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1. 60.0 mL of 0.322 M lithium chloride, LICI (aq) are combined with 20.0 mL of 0.530 M Tin (II) nitrate,
Sn(NO₂)2 (aq), 0.632 g of precipitate are recovered.
a. Write a balanced chemical equation for the reaction.
b. Write a balanced net-ionic equation for the reaction.
c. Calculate the moles of precipitate that are actually produced in the reaction.
d. Calculate the moles of precipitate that should be produced if the reaction went to completion.
e. Calculate the percent yield of the reaction.
Answer:
60.0 mL of 0.322 M potassium iodide are combined with 20.0 mL of 0.530 M lead (II) nitrate.
How many grams of lead (II) iodide will precipitate? (you must write your own reaction)
Explanation:
In a lab experiment, 7.97 g of phosphorus reacts with bromine to form 69.65 g of phosphorus tribromide. How much phosphorus tribromide would be formed if 12.05 g of phosphorus reacted with 61.68 g of bromine? answer:______gi put what i got in the image and it is wrong sorry
1) List the known and unknown quantities.
First experiment:
Reactants
Phosphorus: 7.97 g.
Bromine: excess.
Product
Phosphorus tribromide: 69.65 g.
Second experiment
Reactants
Phosphorus: 12.05 g.
Bromine: 61.68 g.
Product
Phosphorus tribromide: unknown.
2) Write and balance the chemical equation.
[tex]2P+3Br_2\rightarrow2PBr_3[/tex]3) Convert the masses.
3.1-Convert the mass of P to moles of P.
The molar mass of P is 30.97 g/mol.
[tex]mol\text{ }P=12.05\text{ }g\text{ }P*\frac{1\text{ }mol\text{ }P}{30.97\text{ }g\text{ }P}=0.38909\text{ }mol\text{ }P[/tex]3.2-Convert the mass of Br to moles of Br.
The molar mass of Br2 is 159.8080 g/mol.
[tex]mol\text{ }Br_2=61.68\text{ }g\text{ }Br_2*\frac{1\text{ }mol\text{ }Br_2}{159.8080\text{ }g\text{ }Br_2}=0.38596\text{ }mol\text{ }Br_2[/tex]4) Which is the limiting reactant?
4.1-How many moles of Br2 do we need to use all of the P?
The molar ratio between Br2 and P is 3 mol Br2: 2 mol P.
[tex]mol\text{ }Br_2=0.38909\text{ }mol\text{ }P*\frac{3\text{ }mol\text{ }Br_2}{2\text{ }mol\text{ }P}=0.583635\text{ }mol\text{ }Br_2[/tex]We need 0.583635 mol Br2 and we have 0.38596 mol Br2. We do not have enough Br2. This is the limiting reactant.
4.2-How many moles of P do we need to use all of the Br2?
The molar ratio between Br2 and P is 3 mol Br2: 2 mol P.
[tex]mol\text{ }P=0.38596\text{ }mol\text{ }Br_2*\frac{2\text{ }mol\text{ }P}{3\text{ }mol\text{ }Br_2}=0.25731\text{ }mol\text{ }P[/tex]We need 0.25731 mol P and we have 0.38909 mol P. We have enough P. This is the excess reactant.
5) Moles of phosphorus tribromide produced from the limiting reactant.
Limiting reactant: 0.38596 mol Br2.
The molar ratio between Br2 and PBr3 is 3 mol Br2: 2 mol PBr2.
[tex]mol\text{ }PBr_2=0.38596\text{ }mol\text{ }Br_2*\frac{2\text{ }mol\text{ }PBr_3}{3\text{ }mol\text{ }Br_2}=0.25731\text{ }mol\text{ }PBr_3[/tex]6) Conver the moles of Pbr3 to mass of PBr3.
The molar mass of PBr3 is 270.6858 g/mol.
[tex]g\text{ }PBr_3=0.25731\text{ }PBr_3*\frac{270.6858\text{ }g\text{ }PBr_3}{1\text{ }mol\text{ }PBr_3}=69.6502\text{ }g\text{ }PBr_3[/tex]The mass of PBr3 produced in the reaction is 69.65 g PBr3.
.
predict the product of this combination reaction. Include thephysical state of the product and balance the reaction. Hint: You have aluminumand sulfide ions in your product. What are the charges of those ions? How wouldyou write the formula so that the charges cancel?
We are asked to predict a reaction having two solids as reactants. The reaction occurs in the solid phase. Initially the elements are in their natural state, so they will have an oxidation state equal to 0.
This is a combination reaction, so the product will be a combination of aluminum and sulfur.
When combined, aluminum has an oxidation state of +3, this means that it gives up its electrons. Sulfur has an oxidation state of -2. The resulting product will be aluminum sulfide (Al2O3). so, the reaction will be:
[tex]Al_{(s)}+S_{8(s)}\rightarrow Al_2^{+3}S_3^{-2}[/tex]We must balance the equation.
Let's start with sulfur. We multiply each sulfur-containing molecule by its opposite. In other words, we multiply the S8 molecule by 3 and we multiply the S3 molecule by 8.
And to balance the aluminum we must multiply the aluminum molecule by 16. So, the balanced equation will be:
[tex]16Al_{(s)}+3S_{8(s)}\rightarrow8Al_2^{+3}S_{3(s)}^2[/tex]So, the answer, in summary, will be:
We obtain a product with the formula Al2O3. Al is an ion with a charge of +3, and S is an ion with a charge of -2.
Calculate the boiling point of a 0.33 m solution of a solute in benzene.
(Kb = 2.53°C /m).
The boiling point of the solution is 80.93°C.
What is the boiling point?We know that the boiling point has to do with the temperature at which the pressure inside the system is the same as the atmospheric pressure. Now we know that the boiling point of the pure benzene is 80.1 °C.
Also;
ΔT = K m i
ΔT = boiling point elevation
K = boiling point constant
m = molality
i = Van Hoff factor
ΔT = 2.53°C /m * 0.33 m * 1
ΔT = 0.83°C
Boiling point of the solution = 0.83°C + 80.1 °C
= 80.93°C
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Predict the products for each of the following reactions. Write the molecular equation, the complete ionic equation, and the net ionic equation. Classify the reactions in as many ways as you can.
Aqueous sodium carbonate is added to aqueous hydrochloric acid.
The equation that is the net description of the ions involved is;[tex]CO_{3} ^{2-} (aq) + 2H^{+} (aq)----- > H_{2} O(l) + CO_{2} (g)[/tex]
What is the net ionic equation?The term net ionic equation has to do with the final ionic equation which does not include the spectator ions. What I mean by the spectator ions are those ions that do not undergo a change in a chemical reaction. The first step when we want to write the net ionic equation is first to write down the molecular equation and balance the equation accordingly.
We shall now show the balanced overall reaction equation of the process
Thus, the balanced molecular equation of this reaction is; [tex]Na_{2} CO_{3} (aq) +2 HCl(aq) ----- > NaCl(aq) +H_{2} O(l) + CO_{2} (g)[/tex]
The net ionic equation is;
[tex]CO_{3} ^{2-} (aq) + 2H^{+} (aq)----- > H_{2} O(l) + CO_{2} (g)[/tex]
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Find the molecular formula for a compound that contains 4.90 % N and 11.2 % O. The molecular mass of the compound is 92.0 g/mol.
The molecular formula for the compound that contains 4.90 g N and 11.2 g O is N₂O₄
How to determine molecular formulaWe'll begin by obtaining the empirical formula for the compound. This is illustrated below:
Nitrogen (N) = 4.90 gOxygen (O) = 11.2 gEmpirical formula =?Divide by their molar mass
N = 4.9 / 14 = 0.35
O = 11.2 / 16 = 0.7
Divide by the smallest
N = 0.35 / 0.35 = 1
O = 0.7 / 0.35 = 2
Thus, the empirical formula of the compound is NO₂
Finally, we shall determine the molecula formula. Details below
Molar mass of compound = 92 g/molEmpirical formula = NO₂Molecular formula =?Molecular formula = empirical × n = molar mass
[NO₂]ₙ = 92
[14 + (16×2)]ₙ = 92
46n = 92
Divide both side by 46
n = 92 / 46
n = 2
Molecular formula = [NO₂]ₙ
Molecular formula = [NO₂]₂
Molecular formula = N₂O₄
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Complete question:
Find the molecular formula for a compound that contains 4.90 g N and 11.2 g O. The molar mass of the compound is 92.0 g/mol.
5
Select the correct answer from each drop-down menu.
Complete the following statements to describe solids, liquids, and gases. Select the correct answer from each drop-down
A solid
A liquid
Agas
a definite volume and
a definite volume and
V a definite volume and
a definite shape.
a definite shape.
a definite shape.
Reset
Next
A solid has an identifiable shape and volume. A liquid has a fixed volume and an ill-defined shape. A gas has an undefined shape and a fixed volume.
Which statement regarding solids, liquids, and gases is accurate?A solid is something that has a specific shape and volume. The definition of a liquid is something that has a fixed volume but no fixed shape. A gas is described as something that has neither a fixed shape nor a fixed volume.
What are the solid, liquid, and gas elements' four characteristics?A solid has a distinct volume and shape, a liquid has a distinct volume but no distinct shape, and a gas lacks both.
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Which process is not reversible?Dissolving sugar in water Burning butane in a candle lighterMelting waxExtracting iron metal from iron (III) oxide
Answer
The process that is NOT reversible is Burning butane in a candle lighter
Explanation
All other processes can be reversed
Assuming that each double-displacement reaction occurs, predict the products and write each balanced chemical equation.
a.
Sn(OH)2 + FeBry -*?
b. CsNO3 + KCI -* ?
The products of the double displacement reactions are given in the equations of the reaction below:
a. 3 Sn(OH)₂ (aq) + 2 FeBr₃ (aq) ---> 3 SnBr₂ (aq) + 2 Fe(OH)₃ (s)
Iron (iii) hydroxide is obtained as a precipitate
b. CsNO₃ (aq) + KCI (aq) ---> CsCl (aq) + KNO₃ (aq)
No double displacement reaction occurs as both products are soluble.
What are double displacement reactions?Double displacement reactions are reactions in which there is an exchange of radicals by two compounds when solutions of the compounds are added together.
In a double displacement reaction, an insoluble precipitate is obtained since one of the products of the double displacement reaction is insoluble in aqueous solutions.
The products of the double displacement reactions are given in the equations of the reaction below:
a. Reaction between Sn(OH)₂ and FeBr₃
3 Sn(OH)₂ (aq) + 2 FeBr₃ (aq) ---> 3 SnBr₂ (aq) + 2 Fe(OH)₃ (s)
Iron (iii) hydroxide is obtained as a precipitate
b. Reaction between CsNO₃ and KCI
CsNO₃ (aq) + KCI (aq) ---> CsCl (aq) + KNO₃ (aq)
No double displacement reaction occurs as both products are soluble.
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17. Which of the following represents a formula for a chemical compound?A. CB. KOHC. O
KOH. Option B is correct
Explanations:A chemical compound are made up of more than one element combined together. According to the question, we need to determine the formula that represents a compound.
The compound there is KOH since it contains three elements (Potassium, Oxygen and Hydrogen)
