Answer:
well at the rate he goes he would be at 2.5km
A small, 29 gram pith balls carrying 2 nC of charge is dangling from an insulating string. Another charged pith balls carrying an unknown amount of charge is brought close to the first ball, causing it to shift away. When everything is in equilibrium, the two balls are horizontally separated by distance of 5 cm, and the string is tilted about 11 degrees away from the vertical direction. How much charge is on the second ball
Answer:
[tex]q_2=7.67\times 10^{-6}\ C[/tex]
Explanation:
Given that,
Mass of a pitch ball, m = 29 g = 0.029 kg
Charge on one pitch ball, q₁ = 2 nC
Another charged pith balls carrying an unknown amount of charge is brought close to the first ball, causing it to shift away. When everything is in equilibrium, the two balls are horizontally separated by distance of 5 cm or 0.05 m, and the string is tilted about 11 degrees away from the vertical direction.
At equilibrium,
[tex]T\cos\theta=mg\ .....(1)\\\\\text{and}\\\\T\sin\theta=\dfrac{kq_1q_2}{d^2}\ ....(2)[/tex]
Where q₂ is the change on the second ball
Dividing equation (2) by (1) we get :
[tex]\tan\theta=\dfrac{kq_1q_2}{d^2mg}[/tex]
Solving for q₂, we get :
[tex]q_2=\dfrac{\tan\theta d^2 mg}{kq_1}\\\\q_2=\dfrac{\tan(11)\times 0.05^2\times 0.029\times 9.8}{9\times 10^9\times 2\times 10^{-9}}\\\\q_2=7.67\times 10^{-6}\ C[/tex]
So, the charge on the second ball is [tex]7.67\times 10^{-6}\ C[/tex].
Pots A and B both have plain soil, bean seeds, and the same amount of light. Pot B receives more water (see table). After 50 days the plants are measured. Based on the data, what is the correct conclusion?
The amount of water affects the mass and the height of the plants.
What is the correct conclusion from the data obtained?The correct conclusion is the conclusion which the data obtained supports.
Plants need both water and sunlight to grow.
The variation the amount of water or sunlight that a plant receives will affect the growth rate of the plant.
Based on the data obtained from the experiment where Pots A and B both have plain soil, bean seeds, and the same amount of light, while Pot B receives more water, the amount of water affects the mass and the height of the plants.
In conclusion, plants need both water and sunlight for growth.
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Use an ideal op amp to design a differentiation circuit for which the time constant is 10‐3s usinga 10 nF capacitor. What are the gains and phase shifts found for the circuit at one‐tenth and 10times the unity‐gain frequency? A series input resistor is added to limit the gain magnitude athigh frequencies to 100 V/V. What is the associated 3‐dB frequency? What gain and phase shiftresult at 10 times the unity‐gain frequency?
Answer:
Attached below is the detailed solution
Gains at one-tenth unity gain = 0.1 v/v
Gains at 10 times unity gain = 10 v/v
phase shift at 10 times unity gain =-95.71⁰
Explanation:
a)Gain at one-tenth unity gain
w/Wc = 100/1000 = 0.1 v/v
b)Gain at 10 times unity gain
w / Wc = 10 krad/sec / 1 krad/sec = 10 v/v
3-db frequency of new differentiator = 15.915 khz
attached below is the detailed solutions
Assuming all object are moving with the same velocity, witch statement describes the object with the largest intertia?
Answer:
Mass is the quantitative measure of inertia of any object.
Explanation:
The object that have largest mass will have largest inertia as well as largest momentum.
Help please due by 3:00
Answer:
zero
Explanation:
Acceleration is a measure of the rate of change of velocity. If the velocity is unchanging, its rate of change is zero.
The acceleration is zero.
A Tennis ball falls from a height 40m above the ground the ball rebounds
with 0.5 of the velocity with which it strikes the ground. If the ball rebound
with 1/2 of the velocity with which the balls strike the ground any time the
ball striked the ground. Calculate
[i] the position of the ball after 5s from the ground
[iiafter how many bounds will the ball remain on the ground
(iii) what is the time interval between the third and fourth bounds
(iii) predicts the velocity of the ball after 6s
If the ball is dropped with no initial velocity, then its velocity v at time t before it hits the ground is
v = -g t
where g = 9.80 m/s² is the magnitude of acceleration due to gravity.
Its height y is
y = 40 m - 1/2 g t²
The ball is dropped from a 40 m height, so that it takes
0 = 40 m - 1/2 g t²
==> t = √(80/g) s ≈ 2.86 s
for it to reach the ground, after which time it attains a velocity of
v = -g (√(80/g) s)
==> v = -√(80g) m/s ≈ -28.0 m/s
During the next bounce, the ball's speed is halved, so its height is given by
y = (14 m/s) t - 1/2 g t²
Solve y = 0 for t to see how long it's airborne during this bounce:
0 = (14 m/s) t - 1/2 g t²
0 = t (14 m/s - 1/2 g t)
==> t = 28/g s ≈ 2.86 s
So the ball completes 2 bounces within approximately 5.72 s, which means that after 5 s the ball has a height of
y = (14 m/s) (5 s - 2.86 s) - 1/2 g (5 s - 2.86 s)²
==> (i) y ≈ 7.5 m
(ii) The ball will technically keep bouncing forever, since the speed of the ball is only getting halved each time it bounces. But y will converge to 0 as t gets arbitrarily larger. We can't realistically answer this question without being given some threshold for deciding when the ball is perfectly still.
During the first bounce, the ball starts with velocity 14 m/s, so the second bounce begins with 7 m/s, and the third with 3.5 m/s. The ball's height during this bounce is
y = (3.5 m/s) t - 1/2 g t²
Solve y = 0 for t :
0 = (3.5 m/s) t - 1/2 g t²
0 = t (3.5 m/s - 1/2 g t)
==> (iii) t = 7/g m/s ≈ 0.714 s
As we showed earlier, the ball is in the air for 2.86 s before hitting the ground for the first time, then in the air for another 2.86 s (total 5.72 s) before bouncing a second time. At the point, the ball starts with an initial velocity of 7 m/s, so its velocity at time t after 5.72 s (but before reaching the ground again) would be
v = 7 m/s - g t
At 6 s, the ball has velocity
(iv) v = 7 m/s - g (6 s - 5.72 s) ≈ 4.26 m/s
Sandstone is a sedimentary rock. Which two processes cause sand particles to form sandstone?
1. cementation and cooling
2.compaction and cementation
3.cooling and erosion
4.erosion and heating
Answer:
Compaction and cementation
Explanation:
Cementation: As ions are deposited by fluids to form a compound that hardens loose sedimentary rocks.
Compaction: As the density of sedimentary rocks on edge of them are forced together through sediments.
Answer:
number 2 is correct
Explanation:
cementation as icons are deposited by fluids to form a compound that hardens looses sedimentary rocks .
compaction is the density of sedimentary rocks on edge of them, are forced together though sediments mark me brainest add and follow me
An object is accelerating uniformly from 8.0 m/s to 16.0 m/s in 10 seconds. How far does the object travel in 10 seconds?
Answer:
Explanation:
Using the equation of motion to get the distance
average Speed =distance/ time
Distance = average speed * time
Distance = (v-u)t
Distance = (16-8)* 10
Distance =8*10
Distance = 80m
Hence the distance covered by the object is 80m
Which of the following is NOT a benefit of cool down activities?
A.
reduced muscle soreness
B.
maximal lightheadedness
C.
injury prevention
D.
gradually reduced heart rate
Please select the best answer from the choices provided.
A
B
C
D
The option that is not a benefit of cool down activities from the question is
Maximal lightheadedness
Cooling down activities can be regarded as easy exercise which is carried out after an intense activity, so that the body can gradually transit to a state of resting or near-resting state. It can be carried out base on on the intensity of the exercise,Examples of this activities can involve a slow jog or walk. With lower intensities, stretching, Upper body stretch as well as light jogging.Benefits of Cooling down activities are listed as Injury prevention as well as Gradually reduced heart rate and reduced muscles soreReduced muscles sore: after intense work out, the muscle must have been so stretched so with cooling down activities muscles sore can be prevented
Maximal lightheadedness can be regarded as been dizzy and not a benefit to Cooling down activities
Therefore, Cooling down activities helps the body to move slowly to state of rest.
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A constant force is applied to a body that is already moving. The force is directed at an angle of 60 degrees to the direction of the body's velocity. What is most likely to happen is that: the body will stop moving. the body will move in the direction of the force. the body's velocity will increase in magnitude but not change direction. the body will gradually change direction more and more toward that of the force while speeding up. the body will first stop moving and then move in the direction of the force.
Answer:
the body will gradually change direction more and more toward that of the force while speeding up.
Explanation:
From the question we were told that constant force is applied to a body that is already moving
if the applied force is in opposite direction to the motion of the object, there would be deceleration.
Whenever a force is applied to moving body , acceleration will occur in the body if the force and the motion of the body act in the same direction.
However in case of the question since the force is directed at an angle of 60 degrees to the direction of the body's velocity then the body will gradually change direction more and more toward that of the force while speeding up.
.
If a car has a mass of 1,300 kg and is moving at a constant velocity of 20 m/s, what is the net force acting on the car?
Constant velocity means there is no acceleration in the direction of the car's movement and hence no force acting on the car in this direction.
The only forces acting on the car are due to gravity and the Earth pushing back up on the car. But the car doesn't move up or down, so the net force is 0.
A minerals that help in clotting of blood?
Answer:
Calcium helps in blood clotting. Thank You !
Answer: Calcium
Explanation:
Calcium is Important for healthy bones and teeth; helps muscles relax and contract; important in nerve functioning, blood clotting, blood pressure regulation, immune system health
In a particular area of the country, electrical energy costs $0.12 per kilowatt-hour. (Round your answers, in dollars, to at least two decimal places.) (a) How much does it cost to operate an old-style incandescent 100-W light bulb continuously for 24 hours? $ (b) A modern LED light bulb that emits as much visible light as a 100-W incandescent only draws 16.0 W of power. How much does it cost to operate this bulb for 24 hours? $ (c) A particular electric oven requires a potential difference of 220 V and draws 20.0 A of current when operating. How much does it cost to operate the oven for 5.30 hours? $
Answer:
a) cost = $ 0.29 , b) cost = $ 0.046 , c) cost = $ 2.80
Explanation:
a) Let's find the energy consumed by this bulb, which is the product of the power and time
energy = P t
energy = 100 24 = 2400 W h
as the cost of energy is given in kWh we reduce this value
Energy = 2400 Wh (1 kW / 1000W)
Energy = 2.40 kWh
Calculate the cost of energy
cost = 0.12 2.40
cost = $ 0.288
cost = $ 0.29
b) energy = 16.0 24 = 384 Wh
we reduce to kWh
energy = 0.384 kWh
cost = 0.12 0.384
cost = $ 0.0461
cost = $ 0.046
c) let's find the power consumed by the oven
P = I V
P = 20.0 220
P = 4400 W
we look for the energy consumed
energy = 4400 5.30
energy = 23320 Wh
we reduce to kWh
energy = 23.32 kWh
we calculate the cost of this energy
cost = 0.12 23.32
cost = $ 2,798
cost = $ 2.80
A radar station sends a signal to a ship which is located a distance 13.9 kilometers from the station at bearing 136° clockwise from the north. At the same moment, a helicopter is at a horizontal range of 19.6 kilometers, at bearing 152° clockwise from the north, with an elevation of 2.57 kilometers. Let east be the î direction, north be the ĵ direction, and up be the direction.
(A) What is the displacement vector (in km) from the helicopter to the ship? (Express your answer in vector form. Do not include units in your answer.)
(B) What is the distance (in km) between the helicopter and ship?
(C) The ship begins to sink at a rate of 5.40 m/s. Write the position vector (in km) of the ship relative to the helicopter as a function of time as the ship sinks. Assume that the helicopter remains hovering at its initial position and that the sinking rate remains the same even after the ship sinks under the surface. (Use the following as necessary: t. Do not include units in your answer.)
(D) Evaluate the position of the ship relative to the helicopter (in km) after 1.90 h. (Express your answer in vector form. Do not include units in your answer.)
Answer:
A) d = 7.9267 km, θ = 157.19
D) d = 35.17 km
Explanation:
For this exercise the easiest way is to decompose the vectors
Ship
X axis (North)
The angle measured from the positive side of the x axis (unit vector i^ ) counterclockwise
θ = 136- 136 = 224
cos θ = x₁ / 13.9
x₁ = 13.9 cosc 224
x₁ = - 9.9988 103 m
z axis
sin 224 = z₁ / 13.9
z₁ = 13.9 sin224
z₁ = -9.6558 m
Axis y
y₁ = 0
Helicopter
x-axis (North)
θ = 360 - 152
θ = 208
cos θ = x₂ / 19.6
x₂ = 19.6 cos 208
x₂ = -17.3058 km
z axis
sin 204 = z₂ / 19.6
z₂ = 19.6 sin 204
z₂ = -7.9720 km
Axis y
y₂ = 2.57 km
It's a bit strange the way the axes give, but having the decomposition of the vectors we can answer the questions
A) They ask the displacement vector, let's start looking for the distance
d = √ [(x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²]
we substitute
d =√[(17.3058 - 9.9988)² + (2.57 - 0)² + (7.9720 -9.6558)²]
d = √ [7.307² + 2.57² + 1.6838²]
d = 7.9267 km
the angle of this vector is with respect to North (x-axis)
cos θ = -7.307 / 7.9267
θ = cos⁻¹ (-0.9218)
θ = 157.19
Y-axis elevation angle
cos θ'= 2.57 / 7.9267
θ’= cos⁻¹ (0.3242)
θ’= 71.09
b) d = 7.9267 km
c) at this time the ship is sinking at constant speed, the sinking direction is the same vertical direction of the helicopter (y-axis)
the distance is
y₁ = v₁ t
let's reduce speed to km /h
v₁ = 5.4 m / s (1km/1000m ) (3600s/1h)= 19.44 km /h
y₁ = 19.44 t
the vector positions is
d = √ [(x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²]
d = √ [7.307² + (2.57 -19.44 t)² + 1.6838²]
in vertical angle is
cos θ'= (2.57 -19.44t) / d
At an angle to the x axis is
cos θ = -7.307 / d
d) let's evaluate the position for t = 1.90 h
distance
d = √ [7.307² + (2.57- 19.44 1.9)² + 1.6838²]
d = √ [7.307² + (-34.366)² + 1.6838²]
d = 35.17 km
Determine an example of a social influence.
a brother or sister
your best friend
a community leader
All are social influences.
Answer:
all are social influences
What is the difference between environmental science and environmentalism?
Explanation:
Environmental science is the pursuit of knowledge about the workings of the environment and our interactions with it. Environmentalism is a social movement dedicated to protecting the natural world. Nature makes resources at similar speeds
A certain lightning bolt moves 50.0 C of charge. How many units of fundamental charge is this?
The dipole moment of water is p = 6.17 x 10-30 C m. If the electric field in a microwave oven is on average 94.7 x 10-6 N/C, and water molecules start anti-parallel to the external field (180o), how much energy (in Joules) is deposited into a water sample in 2.39 seconds with 13.1 of water if the direction of this field switches every 3.42 x 108 times a second and each time the electric field flips the water molecules align themselves with the new direction?
Answer:
Explanation:
Given that:
p = 6.17 × 10⁻³⁰ Cm
Electric field E = 94.7 × 10⁻⁶ N/C
Then:
[tex]U= -p^{\to} *E^{\to}[/tex]
[tex]U_i = -pE \ cos180^0 =pE \\ \\ U_f = -pE \ cos 0^0 = -pE[/tex]
∴
[tex]\Delta U = U_i - U_f = 2pE \ \ per \ dilute/per \ switch[/tex]
This implies that one switch of dipole produces 2pE energy to be deposited in the water.
mass of water = 13.1 g
The number of water molecule = [tex]\dfrac{mass}{molar \ mass}\times N_A[/tex]
=[tex]\dfrac{13.1}{18.015}\times6.023 \times 10^{23}[/tex]
= 4.38 × 10²³ molecules of water.
∴ Number of dipoles = 4.38 × 10²³
The total number of switches in 2.39 sec = switch frequency × 2.73
Number of switches = 2.39 × 3.42 × 10⁸
Number of switches = 817380000
Number of switches = 8.174 × 10⁸
The total energy Q deposited = Energy deposited per dipole × Number of dipole × no of switches
Q = (2pE) × 4.38 × 10²³ × 8.174 × 10⁸
Q = (2 × 6.17 × 10⁻³⁰ × 94.7 × 10⁻⁶ × 4.38 × 10²³ × 8.174 × 10⁸ )
Q = 0.41838 J
How is electrolysis used in order to prevent materials from corrosion or rusting?
Answer:
We use electrolysis to prevent a material from rusting,
The metal forms a coating around the material and hence prevents any contact between the material and the environment
This process also gives us the physical strength of the material and the aesthetic properties of the coated metal
the metal commonly used to coat the object is Zinc and the process is called galvanisation
A boat Is headed due north on a river that's flowing directly east. What is the general direction of travel for this boat with respect to the land?
A. southeast
B. northeast
C. northwest
D.
east
Answer:
Its northeast. Just took the exam.
Explanation:
Answer:
See image
Explanation:
Plato
Real-world efficiencies are generally very high, in the 90 percent range. Please select the best answer from the choices provided. T F
Answer:
t
Explanation:
Answer: true
Explanation:
Consider the Bell X-2 research aircraft, which was the first aircraft to achieve Mach 3 on September 27th , 1956. During this flight, the aircraft reached a velocity of 936 m/s at an altitude of 65,500 ft. Calculate the actual Mach number that the X-2 achieved during this flight. Now, consider two other conditions. Condition #1: Assuming the aircraft travels at the same velocity in Jupiter’s atmosphere at an altitude where the temperature is -145 °C. Also, assume that the atmosphere of Jupiter is made up of entirely hydrogen gas (H2) which has a molecular weight of 2.016 g/mol. Calculate the Mach number of the X-2 on Jupiter. Condition #2: Assuming the aircraft travels at the same velocity in Pluto’s atmosphere at an altitude where the temperature is -223 °C. Also, assume that the atmosphere of Pluto’s is made up of entirely nitrogen gas (N2) which has a molecular weight of 28.013 g/mol. Calculate the Mach number of the X-2 on Pluto.
Answer:
Explanation:
mach number is ratio of speed with respect to speed of sound .
speed of aircraft = 936 m /s
speed of sound at 65500 ft = 295 m /s
mach number = 936 / 295 = 3.17
velocity of sound at - 145 degree and in hydrogen gas .
velocity of sound
[tex]V=\sqrt{\frac{RT}{M} }[/tex]
[tex]V=\sqrt{\frac{8.3\times(273-145)}{2\times10^{-3}} }[/tex]
= 729 m /s
mach number
= 936 / 729 = 1.28
velocity of sound at - 223 degree and in nitrogen gas .
velocity of sound
[tex]V=\sqrt{\frac{RT}{M} }[/tex]
[tex]V=\sqrt{\frac{8.3\times(273-223)}{28.013\times10^{-3}} }[/tex]
= 122 m /s
mach number
= 936 / 122 = 7.67
In a football game, running back is at the 10-yard line and running up the field towards the 50 yard
line, and runs for 3 seconds at 8 yd/s. What is his current position (in yards)?
Answer:
34 yards or 34 yard line
Explanation:
8 × 3 = 24
24 + 10 = 34
A wildebeest and a chicken participate in a race over a 2.10 km long course. The wildebeest travels at a speed of 19.0 m/s and the chicken can do 3.30 m/s. The wildebeest runs for 1.680 km and then stops to tease the slow-moving chicken, which eventually passes by. The wildebeest waits for a while after the chicken passes and then runs toward the finish line. Both animals cross the finish line at the exact same instant. Assume both animals, when moving, move steadily at their respective speeds.
(a) how far (in m) is the chicken from the Finish Line when the wildebeest resume the race?
(b) for how long in time (in s) was the wildebeest stationary?
Answer:
Explanation:
2.1 km = 2100 m
1.68 km = 1680 m
a ) Time taken by wild beast to travel 1680 m
= 1680 / 19 = 88.42 s
Time taken by wild beast to travel 2100 m
2100 / 19 = 110.52 s
distance travelled by chicken in 88.42 s
= 88.42 x 3.3 = 291.78 s
Its distance from the end point
= 2100 - 291.78 = 1808.22m
b ) Time taken by chicken to travel 2100 m
= 2100 / 3.3 = 636.36 s
Both reach simultaneously so , time of resting by wild beast
= 636.36 - 110.52 = 525.84 s .
A teenager received a ticket for driving 80 miles per hour. This information describes the teenager's
Answer:
Speed
Explanation:
Ii is given that, "A teenager received a ticket for driving 80 miles per hour.". It doesn't give any information about the direction of motion. It means it represents the speed of teenager. Speed is a scalar quantity. It doesn't have direction.
Hence, the given information describes the teenager's speed.
Answer:
Speed! :)
Explanation:
There is no reference to the direction, which cancels out velocity and direction. In addition, they don't mention the initial speed and the time, so acceleration is out, leaving your answer... SPEED:)
Hope this helps, have a marvelous day!
PLS I NEED HELP ASAP
A rollercoaster speeds up from rest to 100mph (45m/s) in 1.2s. (Acceleration=37.5)
The rollercoaster car then travels vertically upwards, and decelerates at 10m/s^2
How much time passes before it is stationary (for a moment)?
Answer:
5.7s
Explanation:
it is stationary when v = 0 so use the equations of motion to find t. Please see photo attached
The time passed before it is stationary (for a moment) will be 5.7s.
What is acceleration?Acceleration is defined as the rate change of velocity with time.
acceleration a = (Δv) / (Δt)
A rollercoaster speeds up from rest to 100mph (45m/s) in 1.2s. The rollercoaster car then travels vertically upwards, and decelerates at 10m/s^2
Time taken for the change in speed is t.
The acceleration is given by
-10= (45 -0)/ t
t = 4.5
Total time passed = 4.5 +1.2 = 5.7s
Thus, the time passed is 5.7s.
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a coin with a diameter of 2.1 cm with an initial angular speed of 19 rad/sec and rolls in a straight line. The rotation slows at an angular acceleration of magnitude 1.9 rad/s^2. What is the magnitude of the linear acceleration?
Answer:
the magnitude of the linear acceleration is [tex]=1.995 \,\,cm/s^2\\[/tex]
Explanation:
Recall that the linear acceleration (a) is associated with the angular acceleration vi the formula:
[tex]a=R\,\alpha[/tex]
where R stands for the radius of the rotational motion (in our case 2.1 cm/2 = 1.05 cm, and [tex]\alpha[/tex] stands for the angular acceleration in radians per units of time squared.
Then the linear acceleration in our case is:
[tex]a=R\,\alpha\\a=1.05 cm * (1.9\,\,\,rad/s^2)\\=1.995 \,\,cm/s^2[/tex]
Use the picture to answer the question.
A red striped bowling ball with 3 finger holes.
Name at least three physical properties of the bowling ball.
Answer:
The physical properties is hardness shape and color, I choose hardness because I have grabbed bowling balls before and they are very hard well there could be different types of bowling balls made of different things but I have never seen one or toughed a bowling ball that is not hard. Another physical property I chose for the bowling ball was shape, The reason I chose shape was because the bowling ball is circle, the actual name for a 3-D circle is sphere. The last physical property for a bowling ball is color because mostly all bowling balls have color for example the one in the picture it is red with a little bit of pink, there is many different bowling balls that have different color different hardness but NOT different shape. That is the physical properties of a bowling ball.
Explanation:
Answer: The bowling ball is round in shape and red in color. The bowling ball is smooth and hard.
Explanation:
did it on edge
what are the chemical symbols for carbon aluminium hydrogen oxygen and sodium
El unico que se es el del oxígeno: o2
Convert 26.4 mi to km
Answer:
42.48 [km]
Explanation:
To convert miles to kilometers we must know the conversion factor which is equal to:
[tex]1.609[\frac{km}{mi} ][/tex]
We make the product of the value required by the conversion factor:
[tex]26.4[mi]*1.609[\frac{km}{mi} ]\\\\[/tex]
26.4*1.609 = 42.48 [km]
