Answer:
Using the equation for orbital speed
orbital speed= square root of GM/r
Where
G= Gravitational Constant = 6.674x10^-11m^3/kg.s^2
M= mass of The Earth=5.972x10^24 kg
r= the combined radius of The Earth and the height of the satellite above The Earth=6378km+ 3600km= 9978km converting to meters gives (1000m=1km) 9978km*1000m/1km= 9,978,000m or 9.978x10^6m
orbital speed = square root of (6.674x10^-11*5.972x10^24/9.978x10^6= 63198m/s
an airplane maintains a heading (W20N)at an airspeed of 900 km/h. It is flying through a hurricane with winds of 300 km/h, from the northeast.
a) In which direction is the plane moving relative to the ground?
(B) -what is the ground speed
(C)how long would it take the plane to fly from one city to another 500 km away along the path in (b)
Show working!!
Answer:
tan x = 60/700
x = 4.9 degree east north
v = √(60^2 + 700^2)
v = 702.6 kph
hope this helps
Answer and explanation please, much appreciated!!
Answer:
Done
Explanation:
I already answered this problem when you had previously asked for it. Kindly refer that solution.
As a bullet shot vertically upward rises, the kinetic energy of the bullet
The kenitc energy of the bullet lowers as it keeps going up.
Because gravity is pushing the bullet down as the bullet goes up.
I'm pretty sure that the way to put this answer.
The input force of 29.3 N acting on the effort arm of a lever moves 1.7 m, which lifts a 1 N weight resting on the load arm a distance of 11.1 m. What is the efficiency of the machine (in %, rounded to the nearest 0.1)?
Hey this is for high school or middle school
You push horizontally on a 120-N box that is initially resting on a horizontal table. The coefficient of static friction between the box and the table is 0.75, and the coefficient of kinetic friction is 0.40. Find the friction force on the box if the push is equal to(a) 84 N; (b) 94 N.
(a) When the applied force is 84 N, the friction force on the box is 36.02 N.
(b) When the applied force is 94 N, the friction force on the box is 46.02 N.
Frictional force on the boxThe frictional force on the box when it is pushed with a certain force is calculated as follows;
Ff = μFₙ
F - Ff = ma
Mass of the box is calculated as follows;
W = mg
m = W/g
m = 120/9.8
m = 12.24 kg
Acceleration of the box is calculated as follows;
a = μg
a = 0.4(9.8)
a = 3.92 m/s²
When the applied force is 84 N,
F - Ff = ma
F - ma = Ff
84 - 12.24(3.92) = Ff
36.02 N = Ff
When the applied force is 94 N,
F - Ff = ma
F - ma = Ff
94 - 12.24(3.92) = Ff
46.02 N = Ff
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1. In a certain wire, 10 C of charge passes through it in 100 seconds. What is
the current in the wire?
Answer:
the correct answer is 10 wires
Explanation:
So you divide 10x the seconds then you know that 10x10 is 100 and then the answer becomes 10.
How far does a car go in 30 seconds at a speed of 29 m/s? (The equation for
distance is d = st.)
d = speed x time
distance = 29 x 30
distance = 870m
please mark as BRAINLIEST
A weight lifter pulls on a 225 kg bar with 1600 N of force, but the bar does not move. How much work
is performed? (show your work)
A. 0 J
B. 7.1 J
C. 1375 J
D. 1825 J
Answer:
A
Explanation:
its A bro trust me ik it is
Two balls at the ends of two strings are moving at the same
speed in horizontal circular paths. One string is three times
as long as the other. Compare the magnitudes of the two
centripetal accelerations.
Answer:
Fc = M v^2 / R centripetal acceleration
Fc2 / Fc1 = R1 / R2 since M and v are the same for both
If R2 = 3 R1 then the centripetal acceleration for particle 2 will be 1/3 of that of innermost (R1) particle
please help
Newton second law of motion is F =ma
Answer: ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
Explanation: Newton's second law of motion is F = ma, or force is equal to mass times acceleration.
Hi there!
Using Newton's Second Law:
[tex]F = ma[/tex]
F = Net Force (60 N)
m = mass (30 kg)
a = acceleration (m/s²)
Solve for acceleration given the other values.
[tex]60 = 30a\\\\a = \frac{60}{30} = \boxed{2 \frac{m}{s^2}}[/tex]
If the net force increases (while the mass is held constant), the acceleration will INCREASE.
If the mass of the object increases (while the net force is held constant), then the acceleration will DECREASE.
A system in which only one particle can move has the potential energy shown in (figure 1). Suppose u1 = 60 j. What is the y-component of the force on the particle at y = 0. 5 m ?.
The y-component of the force on the particle at the given position is 120 N.
Electric force on the particle
The electric force on the particle is determined by applying Coulomb's law and work-energy theorem as shown below;
Fd = W
Where;
F is the applied forced is the distanceW is potentialF = W/d
F = 60/0.5
F = 120 N
Thus, the y-component of the force on the particle at the given position is 120 N.
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A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much was done?
Answer:
[tex]45 J[/tex]
Explanation:
The equation for work is:
[tex]Work=Force*Distance[/tex]
We can substitute the given values into the equation:
[tex]Work=15N*3m\\Work=45Nm\\Work=45J[/tex]
Answer:
45 J
Explanation:
w =fd
w = 15(3)
A record spins at 33 rpm (revolutions per minute), which is an angular velocity of about 3.46 radians per second. What is the approximate linear velocity of a fly that sits on the record, 12 cm from the center
Hi there!
We can use the following equation to relate angular velocity to linear velocity.
[tex]v = \omega r[/tex]
v = linear velocity (m/s)
ω = angular velocity (3.46 rad/sec)
r = distance from axis of rotation (.12 m)
Plug in the given values.
[tex]v = (3.46)(.12) = \boxed{.415 \frac{m}{s}}[/tex]
Help me please!!!!!!!
Answer:
A) Plasticine
Explanation:
Palestine doesn't take much strain to harden and its strain rate isn't sensitive, therefore making it perfectly plastic.
FIND A RELATION BETWEEN DIRECTION OF ACCELERATION AND THE APPARENT WEIGHT
In some years there are more hurricanes than usual. This is probably because In some years there are more hurricanes than usual. This is probably because there are more windy days than usual. the ocean is warmer than usual. the gravitational pull of the Moon is stronger. the ozone layer is very thin.
Answer:
the ocean is warmer than usual
Explanation:
When the ocean is warmer than usual, more water precipitates upwards into the formation of rain-heavy clouds. When these clouds cross over land and release this large amount of water, hurricanes can be caused.
hope this helps!
1. How fast is each cyclist going in units of meters per second*?
2. Which cyclist is going faster? How much faster is this cyclist going compared to the other one?
Answer:
1. a = 1m/s
b = 3m/s
2. b is faster by 2m/s
Explanation:
v (speed) = d/t
va (speed for cyclist a) = 5/5
1m/s
vb = 9/3
3m/s
comparison = 3 - 1 = 2
difference = 2m/s
cyclist b is going faster because they cover more distance in a second
What is the wavelength of this wave?
Frequency: 2 Hz
Speed: 5 cm/s
2.5 Hz
2.5 cm
Answer:
2.5 cm
Explanation:
velocity = frequency × wave length
5 = 2 × wave length
wave length = 5÷2 = 2.5 cm not Hz because wave length is distance and measured by cm or m
Which changes would cause an increase in the resistance of a wire? Check all that apply.
Answer:
The answer is increasing its temperature to longer and thinner.
Consider a system to be one train car moving toward another train car at rest. When the train cars collide, the two cars stick together. What is the total momentum of the system after the collision? 800 kg • m/s 1,600 kg • m/s 2,400 kg • m/s 4,000 kg • m/s.
The momentum of the body is given by the product of the mass and velocity of the body. The total momentum of the system after the collision is 2400 kgm/sec.
What is the law of conservation of momentum?According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
The momentum of the body is given by the product of the mass and velocity of the body.
According to the law of conservation of momentum
Momentum before collision =Momentum after collision
The given data in the problem is;
mass of train m₁ = 600
mass of car m₂= 400
the velocity of train = 4 m/sec
velocity of car =0 m/sec (rest)
Momentum after collision;
[tex]\rm M_f=m_1v_1+m_2v_2 \\\\\ \rm M_f=600 \times 4 +400 \times 0 \\\\ \rm M_f=2400\;kgm/sec[/tex]
Hence the total momentum of the system after the collision is 2400 kgm/sec.
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Answer:
2,400 kg • m/s
Explanation:
If a person does 20 J of work on a book in 10 seconds, how powerful was the person while doing the work?
Answer:
2 W
Explanation:
P = W/t
= 20 J / 10 s
= 2 W
A 750 kg roller coaster car drops from rest at a height of 90 m along a frictionless track. What is velocity of the roller coaster at the top of a second hill that is 60 m high? Show work
The velocity of the roller coaster at the top of the second hill is 24.25 m/s.
What is velocity?
Velocity is the rate of change of displacement. The s.i unit is m/s
To calculate the velocity of the coaster car, we use the formula below.
Formula:
mg(H-h) = mv²/2............... Equation 1Where:
m = mass of the coaster carH = Height of droph = Height of the second hillv = velocity of the roller coaster.From the question,
Given:
m = 750 kgH = 90 mh = 60 mg = constant = 9.8 m/s²Substitute these values into equation 1
750(9.8)(90-60) = 750(v²)/2Solve for v
375v² = 220500v² = 220500/375v² = 588v = √588v = 24.25 m/sHence, The velocity of the roller coaster at the top of the second hill is 24.25 m/s.
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The amplitude of the electric field component of an electromagnetic wave is increased from e to 3e. What is the corresponding change in the intensity of the wave?.
When the amplitude electric field increase from e to 3e, the intensity of the wave will increase by a factor of 9.
Intensity and amplitude electric field
The relationship between intensity and amplitude of an electric field given as;
I ∝ E₀²
[tex]\frac{I_1}{E_1_0^2} = \frac{I_2}{E_2_0^2}\\\\I_2 = \frac{I_1E_2_0^2}{E_1_0^2}[/tex]
where;
I is the intensity of the waveE is the amplitude electric fieldWhen the amplitude electric field increase from e to 3e[tex]I_2 = \frac{I_1 \times (3e)^2}{(e)^2} \\\\I_2 = 9I_1[/tex]
Thus, when the amplitude electric field increase from e to 3e, the intensity of the wave will increase by a factor of 9.
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Inelastic collisions do not conserve kinetic energy. Does
this violate the Law of Conservation of Energy?
Answer:
No. Because undefined amounts of energy are also released in deformation of the objects, heat released, etc.
a
17. When a 50 cm long wooden log has a radius of 7 cm and a mass of 770g, what is
the density of the wood?
Answer:
The density is 1.1gcm3
A 200 kg man is stuck, motionless, in the middle of a frictionless ice pond. Because it's cold, he's wearing a coat. He wants to get off the pond. Since he has studied physics and knows about conservation of momentum, he decides to throw his 4 kg coat. If he throws the coat at 50 m/s, what will his speed be
The speed of the man when he throws the coat is 1 m/s.
Conversion of linear momentumThe speed of the man can be determined by applying the principle of conservation of linear momentum as follows;
m₁v₁ = m₂v₂
v₁ = (m₂v₂)/m₁
v₁ = (50 x 4)/200
v₁ = 1 m/s
Thus, the speed of the man when he throws the coat is 1 m/s.
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please help me with this work
A 2 µC charge q1 and a 2 µC charge q2 are 0. 3 m from the x-axis. A 4 µC charge q3 is 0. 4 m from the y-axis. The distances d13 and d23 are 0. 5 m. Find the magnitude and direction of the resulting vector R. Round your answer to the nearest tenth.
The net force on q₃ is 0.46 N vertically upwards along the +Y axis. The product of the two charges is directly proportional to the force.
What is Coulomb's law?The electrostatic force is directly proportional to the product of the two charges and inversly proportional to the product of the two charges.
The given data in the problem is;
F is the electric force =?
Q₁ is the charged particle 1 = 2 C
Q₂ is the charged particle 2 = 2 C
d₁₂ is the distance between particles = 0.5 m
The electric force is given by;
[tex]\rm F=\frac{ Kq_1q_2}{r^2} \\\\[/tex]
[tex]\rm F=\frac{ 9\times 10^9 (2\times 10^{-6} \times 4\times10^{-6}}{(0.5)^2} \\\\\rm F=0.288\ N[/tex]
This force is applied on both charges
So the result of the net force is given by;
[tex]\rm F_{net}= 2Fcos \theta \\\\ \rm F_{net}==2 \times 0.288 cos 37^0 \\\\ \rm F_{net}=0.46 \ N[/tex]
Hence the net force on q₃ is 0.46 N vertically upwards along the +Y axis.
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Answer:
Explanation:
E2020
convection is the transfer of energy by the motion of heated particles in a fluid. according to this information,which statement best describes an example of convection
A a shirt heated by an iron
B a puddle heated by the sunlight
C a dark colored car heated by sunlight
D warm air rising
Answer:D warm air rising
how can the change that the molecular scale affect the Lakes Macro scale appearance
The molecules of water determines the macro scale appearance of the lake .
What is a lake?The term lake is used to describe any large body of water that is surrounded by land. We know that water is composed of molecules and the orientation of molecules affect the macro scale appearance of the water.
Hence, as the molecules of water change their orientation, the macro scale appearance of the lake changes likewise.
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