Can someone help me pls, i also have 3 more questions like this :D

A heavy vehicle of mass 200 tones has a maximum speed of 20m/s up a hill inclined at 1.15 degree to horizontal when the engine is working at 800 kilowatts.  The resistance to motion of the truck will be 800 N

We can define power as the rate of doing work, it is the work done in unit time. The SI unit of power is Watt (W) which is joules per second (J/s).

since , Power = Force * velocity

Force = power / velocity

          = 800 * [tex]10^{3}[/tex]/ 20 = 4 * [tex]10^{4}[/tex] N

F net = 0

F - friction force - mg(sin (theta)) = 0

4 * [tex]10^{4}[/tex]  - fr - 2 * [tex]10^{5}[/tex] * 9.8 * sin(1.15) =0

fr = resistive force = 4 * [tex]10^{4}[/tex] - 2 * [tex]10^{5}[/tex] * 9.8 * sin(1.15)

fr = 800 N

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When something, like a spring, is stretched, the added length is referred to as its extension.According to Hooke's law, as long as the limit of proportionality is not crossed, a spring's extension is directly proportionate to the force exerted.

Solve the problem ?

The spring's compression at the specified weight is 0.80cm.

"Your inquiry is incomplete because it appears to be lacking the information below,"

The taptap's spring has a k value of 2.4 104 N/m.

the settings provided;

Each of the 27 people weighs 69 kg.

Each of the three goats weighs 15 kg.

Each of the five hens weighs 3 kg.

The weight of the bananas is 25 kg

The taptap's total mass, which includes every passenger, is computed as;

the people's combined mass is 27 x 70 or 1960 kg.

The goats' combined mass is 3 x 15 =45 kg.

The birds' combined mass is equal to 5 x 3 = 15 kg.

The bananas weigh a total of 25 kilograms

The extension of the spring

=   1960×9.8/2.4×104

= 19208/24000

=  0.80 cm

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Given data

*The given mass of the car is m = 1475 kg

*The maximum tension is T = 2551 N

The formula for the maximum possible acceleration of the truck is given by Newton's second law as

Substitute the known values in the above expression as

Hence, the maximum possible acceleration of the truck is a_max = 1.72 m/s^2

Mechanical advantage is a measure of the ratio of the output force produced to the input force applied in a system, mainly in the case of simple machines, such as levers and pulleys. It is a dimensionless quantity.

From the definition, the mechanical advantage of a simple machine is inversely proportional to the input force applied on the system. So, an increase in this force decreases the mechanical advantage of a simple machine.

For example, the mechanical advantage of a lever can be decreased by increasing the force on load arm or by reducing the force on the effort arm.

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If the truck exerts a force f on the sedan then Force f will exert on the truck.

According to newtons third law ,"every action have an equal and opposite

reaction".

If truck exerts a Force [tex]F_{ts}[/tex] on sedan then sedan will exert a force [tex]F_{st}[/tex] on truck and [tex]F_{ts}[/tex] = - [tex]F_{st}[/tex]

so, we can say that vehicle experiences a force of same magnitude.

given the truck exerts force on the sedan, so the sedan also exerts Force F on the truck.

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Given data

*The given mass of the car is m = 1610 kg

*The given effective force constant is k = 5.75 × 10^4 N/m

(a)

The formula for the period of oscillation of a 1610 kg car is given as

Substitute the known values in the above expression as

Hence, the time period of oscillation of a 1610 kg car is T = 1.05 s

(b)

As from the given data, the amplitude of the oscillation of the car decreases by a factor of 5.00. Then, the expression for the amplitude of the oscillation, and the damping constant (b) is calculated as

Substitute the known values in the above expression as

Hence, the damping constant is b = 9871.2 kg/s

The freight train has a momentum of mv = (4.5 × 105 kg)(1.4 m/s) = 6.3 ×105 kg-m/s.

An automobile with a mass of 1800 kg would need to go at a speed of 6.3  × 105 kg-m/s ÷ 1800 kg = 350 m/s in order to have a momentum of the same magnitude. (Roughly 800 mph)

A moving body's amount of motion is referred to as momentum. It has units of kg m/s and is theoretically represented as p = m * v.

The momentum equation connects the total force exerted on a fluid element to its acceleration or rate of change of momentum and is a formulation of Newton's Second Law. You're certainly familiar with the formula F = ma, which links applied force and acceleration in solid mechanics analysis.

Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.

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r - Radius

h - Height

1. Area of a circle = π×r²

2. Circumference of a circle = 2×π×r

3. Volume of a cylinder = π×r²×h

A region's size on a plane or curved surface is expressed by the term "area," which is a mathematical concept. As opposed to surface area, which refers to the area of an open surface or the boundary of a three-dimensional object, plane region or plane area refers to the area of a form or planar lamina.

The circumference of a circle or ellipse in geometry is its perimeter. That is, if the circle were opened up and straightened out to a line segment, the circumference would be the length of the arc. The curve length around any closed figure is more often referred to as the perimeter.

A cylinder is one of the most basic curvilinear geometric shapes and has traditionally been a solid in three dimensions. It is regarded as a prism with a circle as its base in basic geometry. In several contemporary fields of geometry and topology, a cylinder can alternatively be characterized as an infinitely curved surface.

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Answer:

Explanation:

 Given:

L  = 881.0  m

F = 28.0 N

___________

A - ?

The work :

A = L*F = 881.0 * 28.0 ≈ 24 670  J

Answer:

490.5

Explanation:

Force = Mass × Acceleration

Since, Weight is a force and 'g' is the acceleration due to the earth's gravity,

Weight = Mass × g

Weight = 50 kg × 9.81 m/s² = 490.5 kg-m/s² or 490.5 N

Answer:

Starting speed  Vo = 6.7 m/s

Explanation:

Given:

t = 9.0 s

S = 30 m

___________

V₀ - ?

The path is numerically equal to the area of  the figure lying under the velocity graph:

S = V₀* t / 2

Starting speed:

V₀ = 2*S / t = 2*30 / 9 ≈ 6.7 m/s

Limiting factors are those factors which limits the growth in the ecosystem. Examples of limiting factors include temperature, sunlight, soil configuration, precipitation and nutrients. It is important to know what the limiting factor is for the limiting factors greatly affects the growth of the plants. Not considering these limiting factors would result in the failure of growing the plants in a greenhouse.

What is Limiting factors ?

Any element (variable) in the environment that has the potential to restrict a process, such as the expansion, abundance, or distribution of a population of species in an ecosystem, is referred to as a limiting factor. Both density-dependent and density-independent limiting variables are possible. Those that depend on population density have a tendency to restrict population increase, abundance, or dispersal. On the other hand, a limiting factor that is independent of population density can restrict population expansion, abundance, or dispersal.

Limiting factors are those factors which limits the growth in the ecosystem. Examples of limiting factors include temperature, sunlight, soil configuration, precipitation and nutrients. It is important to know what the limiting factor is for the limiting factors greatly affects the growth of the plants. Not considering these limiting factors would result in the failure of growing the plants in a greenhouse.

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The magnitude of the induced emf in the loop is 1mV.

The formula to be used is:

E = B (dA/dt)

B = magnetic of magnetic field parallel to the axis of loop = 0.5 T

dA/dt = rate of change of area of the loop = 20 cm²/s = 20 x 10⁻⁴ m²

θ = Angle of the magnetic field with the area vector = 0

E = emf induced in the loop

Now, plugging in the values we get:

E = B (dA/dt)

E = (0.5) (20 x 10⁻⁴ )

E = 10 x [tex]10^{-4}[/tex] volts

E = 1 mV

Therefore,  the magnitude of the induced emf in the loop is 1mV.

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It is distinguished from the other planets by the presence of liquid water on its surface, the presence of life, and active plate movement. It rotates on its axis once every 24 hours (a day) and orbits the Sun once every 365 days (a year). The Earth has a single moon.

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Answer:

Resultant force of the given forces: approximately [tex]11.2\; {\rm N}[/tex] at approximately [tex]53^{\circ}[/tex] west of south.

Explanation:

The resultant force of these forces will be:

Refer to the diagram attached. The resultant [tex]5\; {\rm N}[/tex] force to the south and the [tex]10\; {\rm N}[/tex] force to the west are perpendicular to each other, forming the two legs of a right triangle. The hypotenuse of this right triangle will be the net effect of these two forces.

Apply Pythagorean's Theorem on this triangle to find the magnitude of this net effect:

[tex]\begin{aligned}(\text{length of hypotenuse}) &= \sqrt{10^{2} + 5^{2}} \approx 11.2\end{aligned}[/tex].

Hence, the magnitude of this net effect will be approximately [tex]11.2\; {\rm N}[/tex].

Let [tex]\theta[/tex] denote the angle between this resultant force and west. In this right triangle:

[tex]\begin{aligned} \tan(\theta) &= \frac{(\text{opposite})}{(\text{adjacent})} \\ &= \frac{5\; {\rm N}}{10\; {\rm N}} \\ &= \frac{1}{2}\end{aligned}[/tex].

[tex]\begin{aligned} \theta &= \arctan\left(\frac{1}{2}\right) \approx 27^{\circ}\end{aligned}[/tex].

Hence, the angle between this resultant force and south will be approximately [tex](90^{\circ} - 27^{\circ}) = 63^{\circ}[/tex]. This resultant force will be at approximately [tex]63^{\circ}[/tex] west of south.

Mechanical energy  type of energy is the sum of kinetic and potential energy in an object that is used to do work.

Potential energy plus kinetic energy are combined to form mechanical energy. It refers to the power underlying an object's location and motion. A compressed spring, for instance, has mechanical energy in the form of potential energy, while a moving vehicle has mechanical energy in the form of kinetic energy.

A sequence of blades installed on a rotor shaft in a turbine generator are pushed by a flowing fluid, including such air, water, steam, combustion gases, or water. A generator's rotor shaft rotates or spins due to the fluid's force on the blades. In turn, the generator converts the rotor's physical (kinetic) energy into electricity.

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If the second player moved horizontally, the speed he must maintain to catch the ball is 27.67 m/s.

The range of the projectile is the maximum horizontal distance travelled by the ball.

R = (u²sin(2θ)) / (g)

where;

R = (32² x sin(2 x 30) ) / (9.8)

R = 90.49 m

The time of motion of the ball is calculated as follows;

R = uₓt

where;

R = ucosθ(t)

t = R/ucosθ

t = (90.49) / (32 cos30)

t = 3.27 seconds

If the second player moved horizontally, the speed he must maintain to catch the ball is calculated as;

R = Ut

U = R/t

U = (90.49) / (3.27)

U = 27.67 m/s

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At initial speed must the quarter back through the ball for it to reach the reciver.

What is initial speed

The initial speed is the velocity at which motion start.

Sol-

The horizontal velocity is Vi*cos38.6and the vertical velocity is Vi*sin38.6

horizontal

28.4=Vi*cos38.6 time find time in terms of Vi.

Vertical

hf=hi+Vi*sin38.6*t -1/2 g t^2

now hf=hi=0

so

0=Vi*sin 38.6-1/2 g t and put the expression you got for t, then solve for Vi. You will encounter the need for one trig identity.

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The acceleration of the object will be 13.33 m/s^2.

According to Newton's second law of motion,

The magnitude of Force is equal to the product of the mass of the body and the acceleration it is given ( or achieves ).

The units of force, mass and acceleration are Newton, kg and m/s^2 respectively.

In numerical terms,

Force = mass × acceleration

i.e. F = m × a

Given,

mass of the body = 15 kg

Force applied to the body = 200 N.

Putting these values in the equation,

200 = 15 × a

=> a = 200/15

=> a = 13.33 m/s^2.

Therefore, the acceleration of the given body will be 13.33 m/s^2.

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It is to be noted that electronegativity will assist the analyst in the determination of the nature of the interactions between the elements discovered by the Curiosity Rover.

The electronegativity values of two bound atoms indicate whether a bond is nonpolar or polar covalent, as determined by the bonding atoms' properties.

Electronegativity is a measurement of an atom's proclivity to attract electrons (or electron density) toward itself.

Electrons in a polar covalent bond are moved toward the more electronegative atom; consequently, the atom with the partial negative charge is the more electronegative atom. The bigger the electronegativity difference, the more polarized the electron arrangement and the larger the atoms' partial charges.

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In a crash rear-seat passengers in a vehicle can fly ahead with first-rate force injuring or killing passengers in the front seat. Option A.

There is a common misconception that people are safer in the back seat, but the reality is that rear-seat passengers who are not buckled up are more likely to die in a crash. Upon impact, they're often thrown forward into the back of front seats with significant force. Sit upright and you will have the least chance of getting an auto injury.

It will keep you secure and will lower your risk for serious injury. Headrests also protect you in the event of an accident. consistent with a recent study by the Insurance Institute for Highway Safety IIHS the back seat is no longer the safest place. In fact, sitting in the front seat increases your chances of surviving a car accident.

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The period of a satellite orbiting mercury 265,000 m above its surface is 100 minutes if the radius of the planet mercury is 2.43*10^6m and its mass is 3.2*10^23 kg.

v = √ G M / r

r = R + d

v = Orbital velocity

G = Gravitational constant

M = Mass of planet

r = Radius of the orbit

R = Radius of planet ( mercury )

d = Distance from surface to satellite

m = 3.2 * [tex]10^{23}[/tex] kg

R = 2.43 * [tex]10^{6}[/tex] m

d = 265000 m

G = 6.67 * [tex]10^{-11}[/tex] N m² / kg²

r = R + d

r = 2.43 * [tex]10^{6}[/tex] + 265000

r = 2.695 * [tex]10^{6}[/tex] m

v = √ ( 6.67 * [tex]10^{-11}[/tex] * 3.2 * [tex]10^{23}[/tex] ) / 2.695 * [tex]10^{6}[/tex]

v = √ 7.92 * [tex]10^{6}[/tex]

v = 2.81 * 10³ m / s

v = 2.81 km / s

v = 2 π r / T

T = Time period

T = 2 * 3.14 * 2.695 * [tex]10^{6}[/tex] / 2.81 * 10³

T = 6.02 * 10³ s

T = 100 minutes

Therefore, the period of a satellite orbiting mercury is 100 minutes

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Based on this knowledge,he is  most justified in concluding that the   originates between the Sun and the asteroid belt.

Comets are frozen leftovers from the formation of the solar system composed of dust, rock, and ices. They variety from a few miles to tens of miles wide, however as they orbit in the direction of the sun, they warmth up and spew gases and dirt right into a sparkling head that can be large than a planet. This cloth bureaucracy a tail that stretches thousands and thousands of miles.

Asteroids lack the magnetic area and atmosphere that shield us on earth from harm. Living internal an asteroid is one way to defend your self from harmful radiation, it is expected that by tunneling 100 meters deep beneath an asteroid, people would be sufficiently shielded from radiation.

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The net force on an object if a  force of 30 N to the right is applied to an object. An opposite force of 20 N to the left is applied to the same object is 10 N to the right. And the right option is D.

The net force is the vector sum of all the forces that act upon an object.

To calculate the net force applied to the object, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the right option is D. 10 N to the right.

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It tells us that a toy has a mass of 3.0 kg, with a speed of 4.0 m/s.

We apply the following formula:

Ec = m * v²/2

We replace data and solve:

Ec = 3.0 kg* (4.0 m/s)²

Ec = 3.0 kg* 16 m²/s²/2

Ec = 48 kg * m²/s²/2

Ec = 24 kg * m²/s²

Ec = 24 N * m ========> Joules units

Ec = 24 J

Considering the definition isotopes and atomic mass of an element, the average atomic mass of element x is 12.1

The same chemical element can have the same atomic numbers, but the number of neutrons is different. These atoms are called isotopes of the element.

The atomic masses of chemical elements are calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.

In this case, you know:

The average mass of the element x can be calculated as:

average mass of element x=12 amu×0.95 + 14 amu×0.05

average mass of element x= 12.1 amu

Finally, the atomic mass of the element x is 12.1.

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A car is driving with a constant velocity around a circular track. The track’s radius is 156.1 m, and the car returns to its starting position in

49.3 s the car’s centripetal acceleration is 0.327 m/sec².

Rate of change of velocity with respect to time is called acceleration.

when the magnitude of velocity is constant and direction is changing

than the acceleration is centripetal acceleration.  

Given that is question radius of track  is 156.1 m and  car returns to its starting position in 49.3 s.

Velocity of car = Circumference of Circle / total time

                        = 352.308/ 49.30

                 v     = 7.14 m/sec

Centripetal acceleration = v²/r

                                         = 51.06/156.1

                                         = 0.327 m/sec²

The car’s centripetal acceleration is  0.327 m/sec².

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The non-conservative work done on the boy is 1.337 kJ

Given that,

Mass of boy, m = 68.1 kg

Initial speed of boy, u = 1,60 m/s

The boy then drops through a height of 1.56 m

Final speed of boy, v = 8.51 m/s

Now, we have to find the non-conservative work was  done on the boy.

The Work done by the non-conservative forces is equal to the sum of total change in kinetic energy and total change in potential energy.

[tex]W=\frac{1}{2}m (v^{2}-u^{2})+(0-mgh)[/tex]

[tex]W=\frac{1}{2}m (v^{2}-u^{2})-mgh[/tex]

[tex]W=\frac{1}{2}(68.1) ((8.51)^{2}-(1.60)^{2})-68.1*9.8*1.56[/tex]

W = 1337.62 Joules

or

W = 1.337 kJ

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a. The speed of the satellite is  244 m/s

b. The period of the satellite is 1.72 × 10⁷ s

c. The radial acceleration of the satellite is 8913 rad/s

The speed of the satellite is given by v = √(GM/R) where

So, substituting the values of the variables into the equation, we have that

v = √(GM/R)

v = √(6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg /6380 km + 300 km)

v = √(6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg /6680 km)

v = √(39.83324 × 10¹³ Nm²/kg ÷ 6.680 × 10⁶ m)

v = √(5.963 × 10⁻³ × 10⁷ Nm²/kg)

v = √(5.963 × 10⁴ Nm/kg)

v = 2.44 × 10² m/s

V = 244 m/s

So, the speed of the satellite is  244 m/s

The period of the orbit is given by T = 2πR/v where

So, substituting the values of the variables into the equation, we have

T = 2πR/v

T = 2π × 6680 km/244 m/s

T = 2π × 6680 × 10³ m/244 × 10⁵ m/s

T = 13660π × 10³ m/244 × 10⁵ m/s

T = 41971.68 × 10³ m/244 × 10⁵ m/s

T = 17201.5 × 10³ s

T = 1.72015 × 10⁷ s

T ≅  1.72 × 10⁷ s

So, the period of the satellite is 1.72 × 10⁷ s

The radial acceleration of the satellite is given by a = v²/R where

Substituting the values of the variables into the equation, we have

a = v²/R

a = (244 m/s)²/6680 km

a = 59536 m²/s²/6680 × 10³ m

a = 8.913 × 10³ rad/s

a = 8913 rad/s

So, the radial acceleration of the satellite is 8913 rad/s

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The problem describes a situation where a bullet is launched at a certain angle respect to the horizontal to hit in the target, given the launching conditions and the distance to the target. The formulas to compute the magnitudes involved in the projectile motion are

x=[tex]v0[/tex] cos0 t

Y=[tex]V0[/tex] sin0 t

xm=[tex]v0[/tex]² sin 20/g

[tex]Xm[/tex] is the maximum horizontal distance the object can reach when it returns to the ground (or launching height).

let's check if X is computed correctly .

The set of data is correct. We can now proceed to the required distance. We know the bullet is shot directly to the target, so the angle is 0, keeping the same speed. The new maximum distance is 150 m, so we can compute the time needed to complete the flight

since

Let's find the time from the formula

X=[tex]V0[/tex] cos0 t

t=[tex]Xm[/tex]/[tex]V0[/tex] cos0

t=150/100=1.5

Y=(9.8)(0.66)²÷2

Y=-2.134

The bullet will hit 2.134 meters below the target

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