CanvasX &Question 16Consider the reaction: 4Na(s) + O2(8) → 2Na2O(s)

CanvasX &Question 16Consider The Reaction: 4Na(s) + O2(8) 2Na2O(s)

Answers

Answer 1

ANSWER

The mass of Na2O in grams is 123.49 grams

EXPLANATION:

Given information

The mass of sodium is 91 grams

The mass of oxygen is 34.0 grams

To find the amount of Na2O produced, follow the steps below

Step 1: Write the balanced equation of the reaction

[tex]\text{ 4Na}_{(s)}\text{ + O}_{2(g)}\rightarrow\text{ 2Na}_2O_{(S)}[/tex]

Step 2: Find the number of moles of sodium and oxygen using the formula below

[tex]\text{ Mole = }\frac{\text{ mass}}{molar\text{ mass}}[/tex]

Recall, that the molar mass of Na is 22.989 g/mol, and the molar mass of oxygen atom is 32 g/mol

For Na

[tex]\begin{gathered} \text{ Mole = }\frac{mass}{molar\text{ mass}} \\ \text{ Mole = }\frac{91.6}{22.989} \\ \text{ Mole = 3.985 moles} \end{gathered}[/tex]

For O2

[tex]\begin{gathered} \text{ Mole = }\frac{mass}{molar\text{ mass}} \\ \text{ } \\ \text{ Mole = }\frac{34}{32} \\ \text{ Mole = 1.0625 moles} \end{gathered}[/tex]

Step 3: Find the limiting reactant of the reaction

The limiting reactant is the reactant that has the least number of moles after dividing it by the coefficient of the reactant

From the reaction above, you will see that 4 moles of sodium react with one mole of oxygen to give 2 moles of sodium oxide.

For Na

[tex]\begin{gathered} \text{ Na = }\frac{\text{ number of moles}}{\text{ coefficient}} \\ \text{ Na = }\frac{3.985}{4} \\ \text{ Na = 0.99625 mole/wt} \\ \\ \text{ For O}_2 \\ \text{ O}_2\text{ = }\frac{1.0625}{1} \\ \text{ O}_2\text{ = 1.0625 moles/wt} \end{gathered}[/tex]

From the above calculations, you will see that Na has the least number of moles, hence, Na is the limiting reactant

Step 4: Find the number of moles of Na2O

The Na2O can be determined using a stoichiometric ratio

Let x represents the number of moles

[tex]\begin{gathered} \text{ 4 moles of Na }\rightarrow\text{ 2 moles of Na}_2O \\ 3.985\text{ moles of Na }\rightarrow\text{ x moles of Na}_2O \\ \text{ cross multiply} \\ \text{ 4 moles of Na }\times\text{ x moles of Na}_2O\text{ = 2 moles of Na}_2O\times3.985\text{ moles of Na} \\ \text{ x moles of Na}_2O\text{ = }\frac{2\cancel{moles\text{ of Na}_2}O\times3.985\cancel{moles\text{ of Na}}}{4\cancel{moles\text{ of Na}}} \\ \text{ x moles of Na}_2O\text{ = }\frac{2\times\text{ 3.985}}{4} \\ \text{ X moles of Na}_2O\text{ = 1.9925 moles} \end{gathered}[/tex]

Hence, the number of moles of Na2O is 1.9925 moles

Step 5: Find the mass of Na2O

[tex]\begin{gathered} \text{ Mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \end{gathered}[/tex]

Recall, that the molar mass of Na2O is 61.9789 g/mol

[tex]\begin{gathered} \text{ 1.9925 = }\frac{\text{ mass}}{61.978} \\ \text{ Cross multiply} \\ \text{ Mass = 1.9925}\times61.978 \\ \text{ Mass = 123.49 grams} \end{gathered}[/tex]

Hence, the mass of Na2O in grams is 123.49 grams


Related Questions

8) Identify which is the proton acceptor (base) in this following reaction:
HCI + H20 -> CH + H30+
O HCI
O H20
O H30+
O cl

Answers

The proton acceptor (base) in this following reaction is  H₃0⁺

Here given reaction is

HCI + H₂O  → CH + H₃O⁺

A proton is a subatomic particle found in the nucleus of every atom so in that reaction H₃0⁺ is the  proton acceptor because protonic acid is the proton donor H⁺ so H₃0⁺ must be bronsted acid and OH⁻ because it accept the proton is a therefore a bronsted base and a lewis acid is by definition an electron pair acceptor and a lewis base is an electron pair donor

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For each pair of bonds, indicate the more polar bond, and use an arrow to show the direction of polarity in each bond.a. C-O and C-Nb. P-Br and P-Clc. B-O and B-Sd. B-F and B-I

Answers

To calculate how polar a bond is we can look at the difference in electronegativity. An electronegativity greater than 1.7 represents an ionic bond, a bond less than 1.7 will be a covalent bond.

Let's see wich is the wich is the electronegativity of each element:

C=2.55

O=3.44

N=3.04

The difference of electronegativity of each pair of bonds will be:

Polar bonds are covalent bonds that have a difference in electronegativities. The greater the difference in electronegativity, the greater the polarity.

So, in this case, C-O bond will be more polar that C-N bond, the polarity.

The direction of the polarity will go towards the more electronegative element. So, we will have:

Answer: The most polar bond will be the C-O bond and the direction of polarity will be toward oxygen for the C-O bond and toward nitrogen for the C-N bond.

Calculate the frequency of light that has a wavelength of 6.2 * 10^-7 m.

Answers

Answer:

4.839 × 10^14 Hz or s^-1

Explanation:

speed of light = wavelength times frequency

frequency = speed of light ÷ wavelength

3.00 x 10^8 = speed of light

3.00 x 10^8 m/s ÷ 6.2 x 10^-7 m = 4.839 × 10^14 Hz or s^-1

socraticorg

can someone please help me with question 27 B please!

Answers

Answer:

Sodium carbonate + Nitric acid → sodium nitrate + water + carbon dioxide. - To write the balanced chemical reaction between sodium carbonate and nitric acid we should know the chemical formula of them. - The chemical formula of sodium carbonate is Na2CO3 and the chemical formula of nitric acid is HNO3

Explanation:

hope it help

How many copper atoms are in a pure copper statue with a mass of 187 kg?

Answers

Avogadro's number states that:

1 mol of Cu = 63.54 g of Cu = 6.02x10^23 atoms of Cu

Now, we proceed like this:

1 kg = 1000 g ===> 187 kg = 187,000 g

63.54 g Cu -------- 6.02x10^23 atoms of Cu

187,000 g Cu -------- X

X = 1.77x10^27 atoms Cu

Answer: 1.77x10^27 atoms Cu

explain the process of photosynthesis with these

Words:
Photosynthesis,
light,
water,
energy,
Carbon Dioxide,
Oxygen,
xylem,
stomata,
Sugar(Glucose),
phloem,
chloroplasts,
leaves,
roots

Be legible and neat please and thank you

Answers

The process of photosynthesis used by plant in which they produce sugar ( glucose ).

Photosynthesis is the process in which plants produced sugar by using sun - light , water and carbon dioxide. In the process of photosynthesis plants use carbon dioxide ( CO₂ ) and water H₂O from the air and the soil  then this carbon dioxide and water transforms to oxygen and sugar (glucose). the oxygen produced by plant back into the air and the sugar produces stores by the plant as the form of energy.

                                                sunlight

carbon dioxide  +   water       -------------->     glucose   +   oxygen

In the leaf cell a part called chloroplast in it energy in sunlight used to break oxygen and hydrogen. T he water required in the process of photosynthesis taken by the roots from soil and then it transport with the help of xylem cell to the different parts of plant. phloem takes sugar from leaves to different parts of plant. The stomata is for the transpiration exchange that means it takes carbon dioxide and the release oxygen back to air after the photosynthesis end.

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help me please if you can a. ammonia b. battery acid c.pure waterd. sea water

Answers

Answer:

ammonia

Explanation:

Dr. Lamar is performing an autopsy on a murder victim. What is he MOST likely to do during this procedure?

A.
Apply a Hematix strip to the fingertips to collect prints.

B.
Use the Kastle-Meyer test to examine blood samples.

C.
Collect hair samples from multiple places on the body.

D.
Scrape away any dried blood present on the body.

Answers

Collecting hair samples from multiple places on the body is most likely to be done during an autopsy.

What is Autopsy?

This is referred to as a post-mortem examination which is done on a corpse so as to determine the cause of the sickness and for appropriate actions to be taken.

Hair is easily dispersed as a result of light weight and structure and its ability to easily attach to other substances. The hair will be most likely taken during this procedure, it helps to identify the race and sex of the suspect. It can also be used to identify the suspect through DNA analysis which is therefore the reason why option C was chosen as the correct choice.

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Answer: C

Explanation:

What is the number of molecules in
500m cube of Oxygen at room temperature

Answers

4.95 is the number of molecules in 500m cube of Oxygen at room temperature and pressure

we have got data

pressure=1atm

temperature=298 k

volume=500 m^3

gas constant, R=8.31

now, by applying ideal gas equation

PV=nRT

1×500=n×8.31×298

n=2476.38/500

n=4.95

It is the lowest part of the material and has chemical elemental properties. Atoms do not independently exist; rather, they combine to form ions and molecules, which then combine to form the material that we can see, feel, and touch.

Molecules are made up of one or more atoms connected by covalent (chemical) connections. Atoms can be visualized as circles with a nucleus in the center (made up of protons and neutrons) and one or more concentric circles around it that indicate the "shells" or "levels" in which the electrons surrounding the atom's nucleus are located, as well as markings that identify the electron. each level

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What is the concentration in molarity of a solution which is 2.91 %m/v benzene (C₆H₆, MM =78.11 g/mol ) in CCl₄ (MM = 153.81 g/mol)?

Answers

According to molar concentration,concentration in molarity  of the solution is 3.77×10[tex]^-7[/tex] M.

What is molar concentration?

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.

In the given problem,mass of benzene =2.91 g  and molar mass of benzene=78.11 g/mole and volume=100-2.91=97.09 ml or 97.09×10[tex]^-3[/tex] L.

Substituting in the formula,molarity=2.91/78.11×1/97.09×10[tex]^-3[/tex]=3.77×10[tex]^-7[/tex] M.

Hence, the molarity of solution is 3.77×10[tex]^-7[/tex] M.

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JWhat did Rutherford’s model of the atom include that Thomson’s model did not have?

a nucleus
energy levels
electron clouds
smaller particles

Answers

Answer:

Rutherford's model of the atom included the nucleus, something lacking in Thomson's model. Rutherford's inclusion of the nucleus came about after his discovery of the nucleus of the atom in 1911. He was testing J.J. Thomson's Plum Pudding model by directing a beam of alpha particles toward a thin sheet of gold foil.

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3. If you need to produce 85 g of CO2, how many grams of: (these are 3 problems starting with thea. C3H8, do you need?same amount:b. O2, do you need?c. H2O will also be made?

Answers

1) First let's write the equation. It is a combustion reaction, so:

C₃H₈ + O₂ ---> CO₂ + H₂O

and balance the equation (same number of atoms of each element on both sides of the equation):

C₃H₈ + 5 O₂ ---> 3 CO₂ + 4 H₂O

Reactant side:

C - 3

H - 8

O - 10

Product side:

C - 3

O - 10

H - 8

2) Now let's transform 85 grams of CO₂ into mole. For this, we use the following equation:

mole = mass/molar mass

Molar mass of CO₂ is: (1×12) + (2×16) = 44 g/mol

mole = 85/44

mole = 1.9 mol of CO₂

3) Now we use the proportion of the balanced equation:

1 mol of C₃H₈ ---- 3 mol of CO₂

x mol of C₃H₈ ----- 1.9 mol of CO₂

x = 0.6 mol of C₃H₈

4) Now we transform mole of C₃H₈ into grams using its molar mass.

molar mass of C₃H₈ is: (3×12) + (8×1) = 44 g/mol

mass = mole × molar mass

mass = 0.6 × 44

mass of C₃H₈ = 28 g

Answer: a) mass of C₃H₈ = 28 g

For alternative b we follow the same process starting from step 3:

3)Now we use the proportion of the balanced equation:

5 mol of O₂ ---- 3 mol of CO₂

x mol of O₂ ----- 1.9 mol of CO₂

x = 3.16 mol of O₂

4) Now we transform mole of O₂ into grams using its molar mass.

molar mass of O₂ is: (2×16) = 32 g/mol

mass = mole × molar mass

mass = 3.16 × 32

mass of O₂ = 101 g

Answer: b) mass of O₂ = 101 g

For alternative c we follow the same process starting from step 3:

3) Now we use the proportion of the balanced equation:

4 mol of H₂O ---- 3 mol of CO₂

x mol of H₂O ----- 1.9 mol of CO₂

x = 0.84 mol of H₂O

4) Now we transform mole of H₂O into grams using its molar mass.

molar mass of H₂O is: (2×1) + (1×16) = 18 g/mol

mass = mole × molar mass

mass = 0.84 × 18

mass of H₂O = 15 g

Answer: c) mass of H₂O = 15 g

Substance Density (grams/cm3)Chloroform - 1.5Ebony wood - 1.2Mahogany wood - 0.85Oil - 0.9Water - 1.025.Since volume = mass/density, a 1,700 gram beam of mahogany wood has a volume of...Volume = Mass / DensitySelect one:a. 500 cm3b. 1,445 cm3c. 1,785 cm3d. 2,000 cm3

Answers

As the question gave us the formula in which we have to use to calculate the volume of this type of wood:

V = m/d

We have:

m = 1700 grams

d = 0.85

Now we add these values into the formula:

V = 1700/0.85

V = 2000 cm3, letter D

Which subatomic particle is positively charged?ProtonNeutronElectronNone

Answers

Explanation:

A proton is a positively charged subatomic particle.

A neutron is a neutrally charged subatomic particle.

An electron is a negatively charged subatomic particle.

Answer:

The first option is correct.

How many gram of iron is how many moles in 5237 & how many in 4180

Answers

To get the number of moles, you need to use this equation:

n = m/M

where n is the number of moles, m is the mass and M is the molar mass of Iron.

Given:

m = 5227 g

M = 55.8 g/mol (from the periodic table)

Therefore

n = 5227 g/55.8 g/mol

n = 93.7

The first option is closer to 93.7 so the answer is the first option.

Which of the following is used to find the mass of 3.2 moles of calcium carbonate?

Answers

1) Converting grams to moles or moles to grams

In order to do this kind of conversion, we need the molar mass (in grams) of the compound to use it as a conversion factor as follows:

[tex]\frac{molarmassofthecompound_{}}{1molofthecompound_{}}[/tex]

-

A gas occupying 0.6 L at 1.70 atm expands to 0.9 L. What is the new pressure assuming temperature remains constant?

Answers

Answer:

1.13 atm

Explanation:

The new pressure can be found by using the formula

P1V1 = P2V2

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the new pressure P2 we make P2 the subject

We have

[tex]p_2 = \frac{p1v1}{v2} \\ [/tex]

P1 = 1.7 atm

V1 = 0.6 L

V2 = 0.9 L

We have

[tex]p_2 = \frac{1.7 \times 0.6}{0.9} = 1.13333...\\ [/tex]

We have the final answer as

1.13 atm

Hope this helps you

ectQuestion 13What is being reduced in the following reaction ?C2H4(g) + 302(g) → 2CO2(g) + 2H2O(g)C2H4H20No reduction or oxidation is occurringCO2

Answers

Step 1

The reaction is written and balanced as:

C2H4(g) + 302(g) → 2CO2(g) + 2H2O(g)

Step 2

Oxidation states are analyzed

For O2)

On the left, its oxidation state is 0 (O2)

On the right, it is -2 (H2O)

Step 3

The half-reaction is written as:

6 O + 12 e- => 6 O2-

Therefore, O2 is being reduced

Answer: O2

2. 5.4 grams of carbon dioxide gas is confined to a 20.0 L container at atemperature of 32.5°C. What pressure does the gas exert? (15 kPa)

Answers

To calculate this, we will need to assume the gas behaves as an ideal gas.

So, we can use the Ideal Gas Law:

[tex]PV=nRT[/tex]

Where P is the pressure, V is the volume, n is the number of moles, is the absolut temperature and R is the gas law constant.

Since we have carbon dioxide, CO₂, we need to calculate its molar mass to convert the mass to number of moles:

[tex]\begin{gathered} M_{CO_2}=(1\cdot M_C+2\cdot M_O) \\ M_{CO_2}=(1\cdot12.0107+2\cdot15.9994)g\/mol \\ M_{CO_2}=44.0095g\/mol \end{gathered}[/tex]

So, the number of moles is:

[tex]\begin{gathered} M_{CO_2}=\frac{m}{n} \\ n=\frac{m}{M_{CO_{2}}}=\frac{5.4g}{44.0095g\/mol}=0.1227\ldots mol\approx0.12mol \end{gathered}[/tex]

Also, we need to convert the temperature to absolute temperature, so we can convert it to K by adding 273.15 to the degree celcius temperature:

[tex]T=32.5\degree C=(32.5+273.15)K=305.65K[/tex]

Now, we need to use the constant R that has the unit we want. We have K for temperature, mol for number of moles and L for volume. Is we want the pressure in kPa, we need to use the R constant with units L*kPa/(K*mol), which have the value:

[tex]R\approx8.31446\frac{L\cdot kPa}{K\cdot mol}[/tex]

So, solving the equation for P and substituting the values, we have:

[tex]\begin{gathered} PV=nRT \\ P=\frac{nRT}{V} \\ P=\frac{0.12mol\cdot8.31446L\cdot kPa\cdot K^{-1}mol^{-1}\cdot305.65K}{20.0L} \\ P=\frac{0.12\cdot8.31446\cdot305.65}{20.0}kPa \\ P=15.247\ldots kPa\approx15kPa \end{gathered}[/tex]

So, the pressure is approximately 15 kPa.

What type of evidence does this image BEST represent?

An imprint of a shoe sole on soil.



A.
trace evidence

B.
biological evidence

C.
ammunitions evidence

D.
impression evidence

Answers

Answer:

the answer is A since the foot is printed

Answer:

It represents a trace evidence,since it leads to a suspect

In one demonstration of this reaction, 39.00 mL of H2 are collected over water at 25°C. Atmospheric pressure is 749.0 mmHg. How many grams of H2 are collected?

Answers

Taking into account the ideal gas law, a mass of 0.00314 grams of H₂ is collected.

Definition of ideal gas law

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

P is the gas pressure.V is the volume that the gas occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. The numerical value of R will depend on the units in which the other properties are worked.n is the number of moles of the gas.

Mass of H₂

In this case, you know:

P= 749 mmHg= 0.985526 atm (being 760 mmHg= 1 atm)V= 39 mL= 0.039 L (being 1000 mL= 1 L)n= ?R= 0.082 (atm×L)÷(mol×K)T= 25 C= 298 K (being 0 C= 273 K)

Replacing in the ideal gas law:

0.985526 atm× 0.039 L = n× 0.082 (atm×L)÷(mol×K)× 298 K

Solving:

[0.985526 atm× 0.039 L]÷ [0.082 (atm×L)÷(mol×K)× 298 K]= n

0.00157 moles= n

Considering that the molar mass of H₂ is 2 g/mole, the mass can be calculated as:

mass= number of moles× molar mass

mass= 0.00157 moles× 2 g/mole

mass= 0.00314 grams

Finally, you collected a mass of 0.00314 grams.

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There are 4 moles of methane burned to produce how many moles of water? CH4+2O2=CO2+2H2O

Answers

ANSWER

8 moles of water

EXPLANATION

The major products formed when an organic compound undergo combustion reaction are water and carbon dioxide

Below is the combustion formula

[tex]\text{ C}_xH_y\text{ + x + }\frac{y}{4}O_2\text{ }\rightarrow\text{ xCO}_2\text{ + }\frac{y}{2}H_2O[/tex]

In the question above, 4 moles of methane reacts with oxygen

[tex]\begin{gathered} \text{ 4CH}_4\text{ + 4+}\frac{16}{4}O_2\text{ }\rightarrow\text{ 4CO}_2\text{ + }\frac{16}{2}H_2O \\ \\ \text{ 4CH}_{4(g)}\text{ + 8O}_{2(g)}\text{ }\rightarrow\text{ 4CO}_{2(g)}\text{ + 8H}_2O(l) \end{gathered}[/tex]

Therefore, 4 moles of methane will give 8 moles of water

What is TRUE about the precipitin test?

A.
It determines if blood is type A, B, or O.

B.
It uses hydrogen peroxide to make a chemical reaction.

C.
It requires a very small amount of blood.

D.
It can only be used on blood that is still wet.

Answers

Precipitin test is used to determine antigens and human blood from other sources. It is widely used in forensic laboratories. Thus we can determine the blood groups such as A, B,O etc.

What is precipitin?

Precipitin is an antibody which precipitates when other antigens binds with it. Thus, antigens from other source can be easily determined using precipitin reaction.

Precipitin reaction involves a specific serological precipitation of an antigen . Varying amounts of the antigen is added to the serum source where each antigen molecule extensively bound to the antibody excess zone.

A small antibody - antigen complex is formed there with  crosslinking reaction. The advantages of this test is that very small amount of test sample is needed and about fifty specimens can be easily tested within few minutes.

Therefore, the precipitin test can used to determine the antigen type of blood A, B or O. Hence, option A is correct.

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Answer: A

Explanation:

Q. According to Lewis dot theory, what types of electron pairs would you find surrounding the central atom of the sulfate ion?A. three bonding and one lone pairs of electrons.B. six bonding and no lone pairs of electrons.C. two bonding and two lone pair of electrons.D. one bonding and three lone pairs of electrons.

Answers

We must first check the valence number of the sulfur in the sulfate ion. In this ion, the valence number is +6 and we have 4 bonded oxygens.

[tex]\begin{gathered} S^{+6}\lbrack O^{-2}_4\rbrack^{-8} \\ SO^{-2}_4 \end{gathered}[/tex]

The Lewis structure of the sulfate ion is as follows:

We have six bonding in the molecule. So the answer will be B. six bonding and no lone pairs of electrons.

What is 4.8829g + 121.3 g + 9.384 g . ensure your answer confiding to rules regarding significant figures

Answers

Answer:

[tex]135.6g[/tex]

Explanation:

Here, we want to sum the given values, then give an answer to the correct significant figures

The correct significant figure for addition operation is the significant figure of the number that has the lowest count of values after the decimal places

Looking at the values, the number with the lowest significant figure after the decimal value is 121.3

Thus, our answer will have a value with 1 significant figure after the decimal place

We have it that:

[tex]\begin{gathered} \text{ 4.8829 + 121.3 + 9.384 = 135.5669g} \\ which\text{ finally is:} \\ 135.6g \end{gathered}[/tex]

Calculate the enthalpy of combustion (kJ/mol) of methyl linoleate (C₁₉H₃₄O₂), an important component of many biodiesel fuels made from corn oil and methanol, given the following standard enthalpies of formation: CO₂(g) = -393.5 kJ/mol H₂O(l) = -285.8 kJ/mol C₁₉H₃₄O₂(l) = -645.7 kJ/mol

Answers

Answer:

Explanation: 2 C19H34O2(l) + 53 O2(g) ==> 38 CO2(g) + 34 H2O(l) ... balanced equation

∆Hcombustion

∆H = ∑∆Hf products - ∑∆Hf reactants

∆H = [(38 x -393.5) + (34 x -285.8)] - (2 x -645.7) = (-14,953 + -9717) - (-1291)

∆H = -24,670 + 1291

∆H = 25,961 kJ

(be sure to check the math)

2- The vapor pressure of water at 80°C is 355 torr, Calculate the vapor
pressure of an aqueous solution made by dissolving 50 gm of ethylene
glycol (C₂H5O₂) in 50 gm of water. What is the vapor pressure lowering of
water in this solution?

Answers

The vapor pressure lowering of water in this solution is 1165 torr.


What is vapor pressure?
The pressure that a vapour exerts on its condensed phases in a closed system at a specific temperature is known as the vapour pressure or equilibrium vapour pressure. An indicator of a liquid's evaporation rate is the equilibrium vapour pressure. It has to do with how easily liquid-borne particles tend to elude detection (or solid). Volatile is a term used to describe a chemical that, at room temperature, has a high vapour pressure. Vapor pressure is the force that a vapour cloud exerts over a liquid surface. The kinetic energy of a liquid's molecules increases along with the temperature. The number of molecules vaporising also rises as a function of the molecules' rising kinetic energy, which raises the vapour pressure.

the vapor pressure of water and the mixture is 355 torr and 760 torrs. Therefore, the value of vapor pressure of oxygen would be,

Ptotal=PO2+PH2O

760=PO2+355

760−355=PO2

405=PO2

So, at the temperature, the vapor pressure of  Ethylene is 405 torr.

When volume reduces to 50ml, the pressure of the oxygen would be,

P1V1=P2V2

where P1 and P2 are the pressure and V1 and V2 are the volumes.

P1V1=P2V2

P1V1/V2=P2

405×100 / 50=P2

810=P2

So, when the volume is 50ml the vapor pressure of the oxygen is 810 torr.

Now the total pressure of water-saturated oxygen at 50 ml volume is,

Ptotal=PO2+PH2O

Ptotal=810+355

Ptotal=1165


So, the total vapor pressure is 1165 torr.
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Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
[] → CH3,CH3,(g) +O2,(g) → CO2,(g) + H2O(g)

Answers

[tex]$$\mathrm{CH}_3 \mathrm{CH}_3(y)+\mathrm{O}_2(q) \rightarrow \mathrm{CO}_2(q)+\mathrm{H}_2 \mathrm{O}(\text { I })$$[/tex]

[tex]\begin{tabular}{l|l}$C=2$ & $C=1$ \\$H=6$ & $H=2$ \\$O=2$ & $0=3$\end{tabular}[/tex]

First balance carbon then balms oxygen and followed by hydrogen through adding odd number Infront  of the reactant and product.

[tex]$$2\mathrm{CH}_3 \mathrm{CH}_3(y)+7\mathrm{O}_2(q) \rightarrow 4\mathrm{CO}_2(q)+6\mathrm{H}_2 \mathrm{O}(\text { I })$$[/tex]

[tex]\begin{tabular}{l|l}$C=4$ & $C=4$ \\$H=12$ & $H=12$ \\$O=14$ & $0=14$\end{tabular}[/tex]

What is  stoichiometric coefficients?

Stoichiometry as the calculation of products and reactants in a chemical response. It is fundamentally concerned with numbers. Stoichiometry is an critical concept in chemistry that makes a difference us utilize adjusted chemical conditions to calculate sums of reactants and products. Here, we make utilize of proportions from the adjusted condition. In common, all the responses that take put are subordinate on one primary figure, how much substance is present. Stoichiometry makes a difference us determine how much substance is required or is present.

Stoichiometry helps us determine

Reactants Products mass Molecular weight Chemical equations Formula.

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What is the total pressure in kPa exerted by a mixture containing two gases if the partial pressure of one gas is 64 kPa and the partial pressure of the other gas is 50.8 kPa?

Answers

Dalton's Law or Law of Partial Pressures says that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas that composes it. The partial pressure of a gas on the other hand is defined as the pressure it would exert if it were alone in the container.

So we need to sum all the values:

64 + 50.8 = 114.8 kPa

Answer: 114.8 kPa

what is the pH solution containing 0.3 M HCOOH and 0.52 M HCOOK?

Answers

First, we need the reaction to start the exercise.

HCOOH(aq) + H2O(l) = H3O+(aq) + HCOO-(aq)

HCOOK => HCOO- + H+

------------------------------------------------------------------------

pH)

We have here an ionic equilibrium, HCOOH is a weak acid.

pKa = 3.77 (from tables)

The concentration of HCOOH 0.3 M

The concentration of HCOO- = 0.52 M HCOOK.

If we propose Ka for HCOOH(aq)

[tex]Ka\text{ = }\frac{\lbrack H_3O^+\rbrack x\lbrack HCOO-\rbrack^{_{}}}{\lbrack HCOOH\rbrack}[/tex]

We clear (H3O+) and we apply -log and we get this:

[tex]pH\text{ = }pKa+log(\frac{[HCOO^-]}{[HCOOH]})[/tex][tex]pH=3.77+log(\frac{[0.52]}{[0.30]})\text{ }[/tex]

Answer: pH = 4.01

--------------------------------------------------------------------------------------------------

pOH)

pH + pOH = 14

(This formula appears from the ionic equilibrium of water)

pOH = 14 - 4.01 = 9.99

Answer: pOH= 9.99

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