Answer:
0.232m
Explanation:
We are given that
Acceleration,[tex]a=290m/s^2[/tex]
[tex]t_1=20ms=20\times 10^{-3}s=0.02s[/tex]
[tex]1ms=10^{-3}s[/tex]
[tex]t_2=30ms=30\times 10^{-3}s=0.03s[/tex]
We have to find the distance reached by tongue.
We know that
[tex]s=ut+\frac{1}{2}at^2[/tex]
Initial speed, u=0
Using the formula
[tex]x_1=0+\frac{1}{2}(290)(0.02)^2[/tex]
[tex]x_1=0.058m[/tex]
[tex]v=u+at[/tex]
Using the formula
Speed after 0.02s
[tex]v=0+(290)(0.02)[/tex]
[tex]v=5.8m/s[/tex]
Distance=vt
By using the formula
Distance traveled in 0.03 s
[tex]x_2=5.8(0.03)=0.174m[/tex]
Total distance traveled in 50 ms
[tex]\Delta x=x_1+x_2=0.058+0.174[/tex]
=0.232m
Of the charge Q initially on a tiny sphere, a portion q is to be transferred to a second, nearby sphere. Both spheres can be treated as particles and are fixed with a certain separation. (a) For what value of q/Q will the electrostatic force between the two spheres be maximized? What are the (b) smaller and (c) larger values of q/Q that give a force magnitude that is 75% of that maximum?
Answer:
2. Smaller value of q = 1/4Q
3. Larger value of q = 3/4Q
Explanation:
1. Please check the attachment for the solution of part 1. Due to time factor I couldn't type out the solution properly.
2. The smaller value is
F = 75% = 75/100
= 3/4 * Q²/16piEod² ---3
When we equate 1 and 3
We get 3Q²/16 = Qq - q² from here we cross multiply to get
3Q² = 16(Qq-q²)
3Q² = 16Qq-16q²
16q² - 16Qq + 3Q² = 0
When solve this out using the quadratic equation formula, we have:
Q/2 +- 2Q/8
We can get the smaller value of q as
Q/2-2Q/8
Solve using LCM we get
2Q/8 = 1/4Q = Q/4
C. The larger value of q
Q/2+2Q/8
= 6Q/8
= 3Q/4
Please use the attachment it will guide you to understand this better.
It has been suggested that rotating cylinders about 10 mi long and 5.9 mi in diameter be placed in space and used as colonies. The acceleration of gravity is 9.8 m/s 2 . What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on
Answer:
ω = 0.05 rad/s
Explanation:
We consider the centripetal force acting as the weight force on the surface of the cylinder. Therefore,
[tex]Centripetal Force = Weight\\\frac{mv^{2}}{r} = mg\\\\here,\\v = linear\ speed = r\omega \\therefore,\\\frac{(r\omega)^{2}}{r} = g\\\\\omega^{2} = \frac{g}{r}\\\\\omega = \sqrt{\frac{g}{r}}\\[/tex]
where,
ω = angular velocity of cylinder = ?
g = required acceleration = 9.8 m/s²
r = radius of cylinder = diameter/2 = 5.9 mi/2 = 2.95 mi = 4023.36 m
Therefore,
[tex]\omega = \sqrt{\frac{9.8\ m/s^{2}}{4023.36\ m}}\\\\[/tex]
ω = 0.05 rad/s
What is the loudness, in decibels, of a sound 1 trillion times as loud as the softest audible sound?
The loudness of this sound in decibels is _________ dB. (Type an integer or a decimal.)
Answer:
What is the loudness, in decibels, of a sound 100 trillion times as loud as the softest audible sound? The loudness of this sound in decibels is dB. (Type an integer or a decimal.)
How can pressure impact the alignment of minerals within the rock
Which of the following is an example of exothermic reaction?
Explanation:
Exothermic reaction are those in which heat releases during a reaction
what is physical quantity
Answer:
a physical quantity is any physical property that can be quantified, that is, be measured using numbers.
Answer: A physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as the combination of a numerical value and a unit. For example, the physical quantity mass can be quantified as n kg, where n is the numerical value and kg is the unit.
16.An astronaut, visiting a newly discovered planet, finds the acceleration due to gravity by dropping an objectfrom a height of 1.0 meter and measuring how long it takes the object to hit the ground. If it takes the object0.8 seconds to hit the ground, what is the acceleration due to gravity on th
Answer:
g = 3.125 m/s²
Explanation:
To find the acceleration due to gravity we will use the second equation of motion:
[tex]h = V_{i}t + \frac{1}{2}gt^{2}\\[/tex]
where,
h = height = 1 m
Vi = initial speed object = 0 m/s (object is initially at rest)
t = time taken = 0.8 s
g = acceleration due to gravity = ?
Therefore,
[tex]1\ m = (0\ m/s)(0.8\ s)+\frac{1}{2}g(0.8\ s)^{2}\\\\\frac{2\ m}{0.64\ s^{2}} = g\\\\[/tex]
g = 3.125 m/s²
In the parts that follow select whether the number presented in statement A is greater than, less than, or equal to the number presented in statement B.
1. Statement A: 2.567 km, to two significant figures.
Statement B: 2.567 km, to three significant figures.
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
2. Statement A: (2.567 km+ 3.146 km), to two significant figures.
Statement B: (2.567 km, to two significant figures) + (3.146 km, to two significant figures).
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
3. Statement A: Area of a rectangle with measured length = 2.536 m and width = 1.4 m.
Statement B: Area of a rectangle with measured length = 2.536 m and width = 1.41 m.
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
Answer:
1) A> B, 2) A = B, 3) A> B
Explanation:
When a figure is given the number of significant figures to determine the precision or uncertainty the number
1) the uncertainty in the number with three significant figures is less than the number with two significant figures
statement A 2.6
statement B 2.57
A> B
2) decalration A
2,567 + 3,146 = 5,713
with two figures it remains
5.7
statement B
2.6 + 3.1 = 5.7
A = B
3) for the product the result is with the number that has the least significant figures
statement A
rectangles area
2.536 * 1.4 = 3.6
statement B
2.536 * 1.41 = 3.58
A> B
Use one of the following formulas to solve distance:
speed=d/t
*Hint: You will have to manipulate the formula
At dinner you got mad and threw your burrito at a speed of 4 m/s. It flies for 18 seconds through the air. How much distance did the burrito
cover?
Answer:
72m
Explanation:
Given parameters:
Speed of the Burrito = 4m/s
Time = 18s
Unknown:
Distance covered by the flying Burrito = ?
Solution:
Speed is the rate of distance covered per unit of time.
Speed = [tex]\frac{distance}{time}[/tex]
Distance = Speed x time
So;
Distance = 18 x 4 = 72m
Roots spreading far and wide
Answer:
₮₣ ₮₣ ₮₣ ₮₣ ₮₣ ₮₣ ₣5₣ đ₮ɽ ₮₣ ₮ɽ
A 0.18 kg baseball moving at +21.80 m/s is slowed to a stop by a catcher who exerts a constant force of -360 N.
How long does it take this force to stop the ball?
___s
How far does the ball travel before stopping?
___m
Answer:
hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.
It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.
What is force?To find the time it takes for the catcher to stop the ball, you can use the equation:
time = distance / velocity
In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:
time = 0 / 21.80
time = 0 s
So, it takes 0 seconds for the catcher to stop the ball.
To find the distance the ball travels before stopping, you can use the equation:
distance = 1/2 * acceleration * time^2
In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:
distance = 1/2 * (-2000 m/s^2) * (0 s)^2
distance = 0 m
So, the ball travels 0 meters before stopping.
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Two equal in magnitude, positive charges Q are fixed at distance 2d from each other. The third charge, of magnitude q and unknown sign is positioned very carefully into the midpoint on the line connecting the first two charges. Pick the statement which is correct:
a. The third charge will accelerate towards one of the charges.
b. The third charge will be in equilibrium and this equilibrium is stable.
c. The third charge will be in equilibrium and this equilibrium is unstable.
d. The third charge will be in equilibrium. This equilibrium is stable if charge is positive and unstable if charge is negative.
e. All these statements are wrong.
Answer:
the correct one is d
Explanation:
To answer which statement is correct, let's look for the force on the third charge
F = F₁₃ + F₂₃
force is electric force
F = [tex]k \frac{q_1 q_2}{r^2}[/tex]
In the exercise we are told that the distance between the two charges is 2d, therefore the distance of each charge to the third is x = d and the two falls have a car Q
F₁₃ = k q Q / d²
F₂₃ = k q Q / d²
suppose that charge 3 is positive for which the forces are repulsive
F = k q Q / d₂ - k q Q / d₂
F = 0
suppose that the charge 3 is negative for which the forces are of attraction
F = -k q Q / d₂ + k q Q / d₂
F = 0
We can see that regardless of the sign of charge 3 the forces on it are zero, so it has no acceleration, it is in equilibrium.
Let's analyze the type of equilibrium, for this we move the charge 3 towards one of the sides
charge 3 positive
the force towards the approaching side increases and the other decreases, therefore the load has a net force towards the center, in that case the equilibrium is stable
negative charge 3
The force towards the approaching side is stronger and more attractive and the other decreases, therefore it has an attractive net force that carries it towards the charge, it is closer, in this case the balance is unstable
To review the different answers, the correct one is d
Two blocks, M = 14.2 kg and m = 4.73 kg, are connected via a massless rope. They are being pushed up a frictionless hill, with a slope of 15.80, with a constant force in the direction of the incline, such that there is a total acceleration of 2.53 m/s2 for the system
Slope is rise over run, meaning the ratio of the change in height to the change in horizontal distance. So a slope of 15.80 corresponds to an angle of ascension θ of
tan(θ) = 15.80 → θ ≈ 86.38°
The order of the blocks (i.e. whether the large one is pulling the smaller one up or vice versa) does not matter, since friction is not a concern. So if we take the connected blocks as a single mass, by Newton's law we have a net force acting parallel to the incline of
∑ F = P - (M + m) g sin(θ) = (M + m) a
(see the attached free body diagram)
where
P = magnitude of the push
g = 9.80 m/s²
a = 2.53 m/s²
and M and m are the given masses.
Then the system requires a push of
P = (M + m) (a + g sin(θ))
P = (14.2 kg + 4.73 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))
P ≈ 233 N
If you have to find the tension in the rope, consider the free body diagram for one of the blocks. By Newton's second law, the net parallel force acting on, say, the larger block (if it's being pulled by the rope) is
∑ F = T - M g sin(θ) = M a
where
T = tension in the rope
Then
T = M (a + g sin(θ))
T = (14.2 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))
T ≈ 175 N
Why do the snakes only get one unit of energy?
Answer: Snakes are reptiles
Explanation: All reptiles are ectothermic (they obtain body heat from their environment).
As snake belongs to secondary consumer, it get less amount of energy in food cycle. If producer (grass) get 100 unit of energy, according to food chain snakes only gets one unit of energy.
What is food chain?The sequence of events in an ecosystem known as a "food chain" occurs when one live organism eats another organism, which is then eaten by a larger organism. A food chain is created by the transfer of nutrients and energy from one creature to another at various trophic levels.
The feeding habits or connections between living things are also explained by the food chain. Trophic level is the term used to describe the orderly phases in a food chain, from producers at the bottom through primary, secondary, and tertiary consumers. A trophic level is any position along a food chain.
A food chain demonstrates the interdependence of all living things on one another. The direction of energy flow within an ecosystem is described by the food chain.
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A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the person is 68.0 kg, the mass of the skateboard is 4.10 kg, and the mass of the brick is 2.50 kg. If the person throws the brick forward (in the direction they are facing) with a speed of 21.0 m/s relative to the skateboard and we ignore friction, determine the recoil speed of the person and the skateboard, relative to the ground.
Answer:
0.74 m/s
Explanation:
From the question,
We apply the law of conservation of momentum,
Total momentum before collision = Total momentum after collision.
Since the skateboard, the person and the brick where stationary, therefore, the total momentum before collision is 0
0 = Total momentum after collision
(m+M)V + m'v = 0
Where m = mass of the skateboard, M = mass of the person, m' = mass of the brick, V = recoil velocity of the person and the skateboard, v = velocity of the brick
make V the subject of the equation above
V = -m'v/(m+M)................... Equation 1
Given: m = 4.10 kg, M = 68.0 kg, m' = 2.50 kg, v = 21.0 m/s.
Substitute these values into equation 1
V = -(2.5×21)/(68+2.5)
V = 52.50/70.5
V = 0.74 m/s
how is space Technology different from space exploration
Answer:
Space technology is technology developed by space science for use in astronautics, for purposes such as spaceflight or space exploration. Space technology includes spacecraft, satellites, space stations, and support infrastructure equipment, and procedures and space warfare.
What are the applications of diodes and rectifiers?
Answer:
The most common and important application of a diode is the rectification of AC power to DC power. Using the diodes, we can construct different types of rectifier circuits. The basic types of these rectifier circuits are half wave, full wave center tapped and full bridge rectifiers.
Explanation:
Here ya go <3
If you are givin force and time, you can determine power if you can know.
A. Watts
B. Energy
C. Joules
D. Distance
Answer:
D. Distance
Explanation:
Power is work divided by time. Work is force times distance, therefore you need distance in order to find power.
what happens to the orbit time as the distance increases.
What type of metals are known as ferromagnetic metals
Answer:
those who are attracted to magnets. ex: iron, cobalt and nickel
4) The components of Vector A are given as follows Ax = -2.4 Ay = + 3.8 What is the magnitude of the A, and what is the angle that A makes with the x axis
Answer:
A = 4.49
α = 57.72°
Explanation:
Knowing the magnitude of x & y of a vector we can determine the total magnitude of a vector.
[tex]A=\sqrt{A_{x}^{2} +A_{y}^{2} } \\A=\sqrt{(2.4)^{2} +(3.8)^{2} }\\A=4.49[/tex]
The angle tangent can be used to determine the angle.
[tex]tan(\alpha )=\frac{3.8}{2.4}\\tan(\alpha ) =1.5833\\\alpha =tan^{-1}(1.5833) \\\alpha = 57.72 (deg)[/tex]
An object initially at rest experiences an acceleration
of 1.4 m/s for 5.0 s and then travels at that
constant velocity for another 6.0 s.
Part A
What is the object's average velocity over the 11 s interval?
Answer:
1.4m/s
Explanation:
Average velocity is the total distance covered divided by the total time taken.
Average velocity = [tex]\frac{total distance }{time }[/tex]
Total time taken = 5s + 6s = 11s
The first distance covered = velocity x time = 1.4 x 5 = 7m
second distance covered = velocity x time = 1.4 x 6 = 8.4m
So;
Average velocity = [tex]\frac{7 + 8.4}{11}[/tex] = 1.4m/s
Please help I will mark brainlest .
Answer:
lithium atom
Explanation:
If you search up lithium atom the same atom will come out.
Sorry if it's wrong.
A uniform soda can of mass 0.140 kg is 12.0 cm tall and filled with 0.354 kg of soda (Fig. 9-41). Then small holes are drilled in the top and bottom (with negligi- ble loss of metal) to drain the soda. What is the height h of the com of the can and contents
a. initially
b. after the can loses all the soda?
c. What happens to h as the soda drains out?
d. If x is the height of the remaining soda at any given instant, find x when the com reaches its lowest point .
Answer:
Explanation:
a ) The centre of mass of a can filled completely with any liquid of any mass lies at the center of the can or at height h /2 where h is height of the can . So centre of mass of can of mass .140 kg of height 12 cm will lie at height 6 cm . Similarly center of mass of its content will also lie at height 6 cm that is center point of the content .
Hence overall center of mass of can along with its content will lie at height 6 cm initially .
b )
After the can loses all the soda , can becomes empty . Hence its center of mass will lie at its center again .
c ) Its center of mass remains unchanged as the soda drains out completely .
d ) When soda starts draining out of the can , its lower part becomes heavier than the upper part . Hence its center of mass moves downwards . Its height is lowered . As height of soda is lowered in the can , center of mass also is lowered . It reaches its lowest point when soda in the can reaches half the height or when the can is half filled .
After that center of mass again starts rising upwards until the can is completely empty .
kinda easy but too lazy
Answer:
We don't promote laziness here, my dear child. :)
An object accelerates uniformly from rest. If the final velocity of the object after 6.0 s is
18 m/s east, how far did the object travel?
Answer:
54m
Explanation:
Given parameters:
Initial velocity = 0m/s
Time taken = 6s
Final velocity = 18m/s east
Unknow:
How far did the object travel = ?
Solution:
To solve this problem, we use one of the kinematics equation:
We first find the acceleration which is the change in velocity
So;
S = [tex](\frac{v - u}{2} ) t[/tex]
S is the distance
v is the final velocity
u is the initial velocity
t is the time taken
Therefore;
S = [tex]\frac{18 - 0}{2}[/tex] x 6 = 54m
energy flow diagram of petrol driven lawnmower
I forgot the answer but I read it early
Which of the following statements is true?
1)Efficiency is calculated by multiplying work input and work output.
2)a few machines are 100 percent efficient.
3) Some machines are frictionless.
4)The ratio of work output to work input is always less than one.
Answer:
4)
Explanation:
Efficiency is calculated by dividing the energy out by energy in, not multiplying
No machines are 100% Efficient
No machines are frictionless
4) is true
how can students earn a GED
Answer:
How Can You Earn Your GED?
You must be at least 16 years old to take the GED Test, and you must not be enrolled in high school. ...You must pass all four subject tests in the GED battery of tests, which means scoring at least a 145 on each test (New Jersey requires a score of at least 150 to pass).>Rules
You must be at least 16 years old to take the GED Test, and you must not be enrolled in high school. You should also meet state eligibility requirements for the amount of time you've been out of high school. In some states, you have to be out of high school for at least 60 consecutive days before you're allowed to take the test. Contact the program administrator in your state for more details.
You must pass all four subject tests in the GED battery of tests, which means scoring at least a 145 on each test (New Jersey requires a score of at least 150 to pass). Scores range from 100 to 200 on the 2014 version). A score of 165 on each test is the benchmark for college and career readiness, and you will receive an Honors distinction if you reach this score. The four tests take seven and a half hours total and are administered by computer. You don't have to take them all on the same day, but some states enforce specific time frames for completing the tests. Most questions are multiple choice, although there is also a mix of fill-in-the-blank, drag and drop, and select-an-area questions, as well as an essay question on the Reasoning Through Language Arts section.
If you don't pass a test the first time around, you can retake it, although different states have different requirements for people who need to retake GED tests (such as additional fees or proof of attending a preparation class). Testing accommodations are available for those with disabilities; you can sign up for them through your online account after you register. You usually have to pay to sign up for the tests, but the cost varies from state to state. After you take each test, you will receive your scores within 24 hours. Here are some more details about the score report.
Explanation:
I hope I helped and I hope u get what your looking for!!
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The latent heat of vaporization for water at room temperature is 2430 J/g.
1. How much kinetic energy does each water molecule that evaporates possess before it evaporates?
2. Find the pre-evaporation rms speed of a water molecule that is evaporating.
3. What is the effective temperature of these molecules (modeled as if they were already in a thin gas)?
4. Why do these molecules not burn you
a. These molecules got to be slow-moving in collisions that made other molecules fast-moving; the average molecular energy decreases.
b. These molecules got to be slow-moving in collisions that made other molecules fast-moving; the average molecular energy is unaffected.
c. These molecules got to be fast-moving in collisions that made other molecules slow-moving; the average molecular energy is unaffected.
d. These molecules got to be fast-moving in collisions that made other molecules slow-moving; the average molecular energy increases.
Answer:
1) [tex]kinectic energy=7.26*10^-^2^0J[/tex]
2) [tex]V= 2.0m/s[/tex]
3) [tex]T=3.5*10^3K[/tex]
4) The Molecules do not burn because of the presences of hydrogen bond in place
Explanation:
From the question we are told that
latent heat of vaporization for water at room temperature is 2430 J/g.
1)Generally in determining the molar mass of water evaporated we have that
-One mole (6.02 x 10. 23 molecules)
-Molar mass of water is 18.02 g/mol
Mathematically the mass of water is give as
[tex]M=\frac{18.02}{6.02*10^-^2^6}[/tex]
[tex]M=3*10^-^2^3g[/tex]
Therefore
[tex]kinectic energy=2430J/g*3*10^-^2^3g[/tex]
[tex]kinectic energy=7.26*10^-^2^0J[/tex]
b)Generally the evaporation speed V is given as[tex]V= \sqrt{\frac{K.E*2}{m} }[/tex]
Mathematically derived from the equation
[tex]\frac{1}{2} mv^2 =K.E[/tex]
To Give
[tex]V= \sqrt{\frac{K.E*2}{m} }[/tex]
[tex]V= \sqrt{\frac{7.26*10^-^2^0J*2}{3*10^-^2^3g} }[/tex]
[tex]V= 2.0m/s[/tex]
c)Generally the equation for velocity [tex]Vrms=\sqrt{\frac{3RT}{M} }[/tex]
Therefore
Effective temperature T is given by
[tex]T=\frac{\sqrt{v}*m}{R}[/tex]
where
[tex]T=\frac{\sqrt{2.0m/s}*6.02*10^-^2^6}{0.082057 L atm mol-1K-1}[/tex]
[tex]T=3.5*10^3K[/tex]
4) The Molecules do not burn because of the presences of hydrogen bond in place