Answer:
Hi there!
Your answer is:
B. x> -2
Step-by-step explanation:
Divide both sides -1 to solve for A. When dividing by a negative, switch the signs!
Hope this helps
what would x equal to if x equaled 4 in this: 4x
Answer:
x = 4 and the expression when evaluated at x = 4, is 16.
Step-by-step explanation:
For this problem, we will simply look at the wording of the question and the given expression. The question ask, "What would x be equal to if x equaled 4 in this: 4x?"
In the problem, we are already given that x = 4 in the following expression, so the answer to the question is x = 4. If we were to evaluate the expression when x = 4, we would say the following:
If x = 4, then:
4x
= 4(4)
= 16
Hence, the expression would be 16 if evaluated when x = 4.
Cheers.
(-2,6)
(-2,0)
(7,-5)
Calculate the area of the triangle
Answer:
the answer to this is
27
Question 2 of 5 Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. Complete the table of inputs and outputs for the given function. g(x) = -4x-1
Answer:
-2 | 7
0 | -1
3 | -13
-1 | 3
Step-by-step explanation:
i just did this question
A store charges 7% sales tax. Which expression can be used to find the total cost of an item with a price of p? O 0.07p O 0.93p O 1.07p O 7.00p
please help!!
Answer:
The answer is C
Step-by-step explanation:
Answer:
I think that the answer is C I hope that this helpful
Step-by-step explanation:
C
Any can help ? And explain please and thank you
Answer:
d
Step-by-step explanation:
Which rate describes a unit price?
0 $0.01 for 12 seconds
0 $0.25 for 5 minutes
0 $1.00 for 4 hours
0 $5.00 for 1 day
Answer:
the third one
Step-by-step explanation:
Which expression is the completely factored from x^3+8y^6? (x+2y^2)^3
Answer:
Step-by-step explanationSince both terms are perfect cubes, factor using the sum of cubes formula, Since both terms are perfect cubes, factor using the sum of cubes formula,
a
3
+
b
3
=
(
a
+
b
)
(
a
2
−
a
b
+
b
2
)
where
a
=
x
and
b
=
2
y
2
.
(
x
+
2
y
2
)
(
x
2
−
2
x
y
2
+
4
y
4
)
Sorry its a glitch
Solve for h.
15.3 + 1 h =1.3- 1 h
Answer:
-7 = h
Step-by-step explanation:
15.3 + 1h = 1.3 - 1h
+1h +1h
15.3 + 2h = 1.3
Remember what you do to one side you MUST do to the other.
15.3 + 2h = 1.3
-15.3 -15.3
2h = -14
Now to isolate the variable you divide both sides by 2 to get, h = -7
Hope that helps and have a great day!
Hey there!☺
[tex]Answer:\boxed{h=-7}[/tex]
[tex]Explanation:[/tex]
[tex]15.3+1h=1.3-1h[/tex]
In our first step, we will simplify both sides in the equation:
[tex]15.3+h=1.3+-h\\h+15.3=-h+1.3[/tex]
Now add h to both sides:
[tex]h+15.3+h=-h+1.3+h\\2h+15.3=1.3[/tex]
In step 3, divide both sides by 2:
[tex]\frac{2h}{2}=\frac{-14}{2}[/tex]
Simplify -14/2:
[tex]\frac{-14}{2}=-7\\ h=-7[/tex]
h=-7 is your answer.
Hope this helps!☺
The sum of two consecutive integers is 15
Answer:
i am pretty sure it is 7 and 8
Step-by-step explanation:
7 and 8 are before and after each other, so they are consecutive. 7 + 8 is 15
Which representation does not show y as a function of x?
Answer:D i think
Step-by-step explanation:
Help me pls I need this
Answer:
[tex]\frac{1}{729} c^{27}[/tex]
Step-by-step explanation:
[tex]\left(9c^{-9}\right)^{-3}=\frac{1}{\left(9c^{-9}\right)^3}[/tex]
[tex]\frac{1}{9^3\left(c^{-9}\right)^3}[/tex]
[tex]\frac{1}{729c^{-9\times 3}}[/tex]
[tex]\frac{1}{729c^{-27}}[/tex]
[tex]\frac{c^{27}}{729}=\frac{1}{729} c^{27}[/tex]
4 Divided by 61,630
Answer:
15409.75
Step-by-step explanation
61630/ 4
=
30815/ 2
(Decimal: 15407.5)
How to simplify The expression 5(x+1)-5x
Answer:
55 times x , 5 times 1 (keep the -5x after that)it will then be 5x+5-5xchange the x to be together 5x-5x+5The result will be 5Answer: 5
Step-by-step explanation:
5(x+1)-5x
distribute
=(5)(x)+(5)(1)+ -5x
=5x+5+ -5x
Combine like terms
5x+5+ -5x
= (5x+ -5x) + 5
= 0 + 5
= 5
13 apples for 2 pies
Oa. 6.5 apples per pie
Ob. 6.5 pies per apple
Oc. 7 apples per pie
Od. 7 pies per apple
What is the answer it’s unit rates btw
13 apples for 2 pies.
To Find:The unit rates.
Solution:13 apples = 2 pies
or, 1 pie = 13/2 = 6.5 apples
Answer:Option a. 6.5 apples per pie.
Help please ty! (Middle School)
Answer:
it will be C
its 0.7 less than one
solve for the equation of value of x(show your solution)
"EXPONENTIAL FUNCTIONS"
[tex]1.) {9}^{2x} - 5 = 27[/tex]
[tex]2.) {25}^{2x} - 1 = {125}^{3x} + 4[/tex]
[tex]3.) {7}^{3x} + 4 < {49}^{2x} + 1[/tex]
[tex]4.) {16}^{2x} - 5 \geqslant {64}^{2x} - 3[/tex]
deadline: friday october 8pm
i hope you can help me:(
Answer:
2. ) {25}^{2x} - 1 = {125}^{3x} + 4
=> {25}^{2x} = {125}^{3x} + 4 +1
=> {(5)^(2)}^{2x} = {(5)^(3)}^{3x} + {5}^{1}
=> {5}^{4x} = {5}^{9x} + {5}^{1}
=> 4x = 9x + 1
=> 4x - 9x = 1
=> - 5x = 1
=> x = 1/-5
thanks for ur smart brains i gave all my points to u have fun
Answer:
the answer is B.
Step-by-step explanation:
30/5 is 6
Answer:
B)6
Step-by-step explanation:
the result after dividing
A lion runs at a speed of 50 mph and a cheetah runs 78 mph. If they both run at a steady rate, how far will a cheetah run in the time it takes a lion to run 13.75 miles?
Answer:
21.45 mi
Step-by-step explanation:
Distance = speed × time
The time it takes the lion is:
13.75 mi = 50 mi/hr × t
t = 0.275 hr
The distance ran by the cheetah in that time is:
d = 78 mi/hr × 0.275 hr
d = 21.45 mi
Answer:
21.45 miles
Step-by-step explanation:
First, let's find the main ratio:
50:78
Now, let's bring a variable into the equation.
13.75:x
We can find the number to multiply by dividing 13.75 by 50 using long division.
13.75÷50=0.275
We need to find how many miles the cheetah ran, so we will multiply 78 and 0.275.
78·0.275=21.45
So, the cheetah ran 21.45 miles in the time it took the lion to run 13.75 miles.
A company manufactures wheels for in-line skates. The diameters of the wheels have a mean of 3 inches and a standard deviation of 0.1 inches. Because so many of their customers use the metric system, the company decided to report their production statistics in millimeters They report that the standard deviation is now 2.54 mm. A corporate executive is worried about this increase in variation. Should he be concerned
Answer: He should not be concerned
Step-by-step explanation:
The variation is still the same and has not changed because the only thing that changed are the units. A unit change does not mean that the diameter has changed, only the method of measuring it has changed.
Absolutely speaking, the diameter is still the same. A standard deviation of 0.1 inches is the same as a standard deviation of 2.54mm so the executive should not be worried.
Find the flaw with the following "proof" that every postage of 3 cents or more can be formed using just 3-cent and 4-cent stamps.Basis Step: We can form postage of 3 cents with a single 3-cent stamp, and we can form postage of 4 cents using a single 4-cent stamp.Inductive Step: Assume that we can form postage of j cents for all nonnegative integers j with j ≤ k using just 3-cent and 4-cent stamps. We can then form postage of k + 1 cents by replacing one 3-cent stamp with a 4-cent stamp or by replacing two 4-cent stamps by three 3-cent stamps.Which of these statements describes a flaw in the proof?
Answer:
The main flaw of this proof is that it did not take into consideration the fact a 4 cent postage must be made with a 4 cent stamp and a 3 cent postage must be made with a 3 cent stamp but only looked at allocating the stamps based on the total amount of postage
Step-by-step explanation:
From the question we are told that
The proof is
Every postage stamp of three cents or more can be formed using just 3 cent and 4 cent stamps.
Basic Step : We can form postage of 3 cents with a single 3 cent stamp and we can form postage of 4 cents using a single four cents tamp
Inductive Step: Assume that we can form postage of j cents for all non negative integers j with j <= k using just 3 cent and 4-cent stamps. We can then form postage of k+1 cents by replacing one 3 cent stamp with a 4-cent or two 4-cent stamps with three 3-cent stamps
FLAW IDENTIFICATION
Looking the inductive step, the statement ''by replacing one 3 cent stamp with a 4-cent or two 4-cent stamps with three 3-cent stamps '' means that it is possible to use a 3-cent stamp for postage that requires a 4 -cent stamp and this is not correct according the statement in the basic step
Generally the main flaw of this proof is that it did not take into consideration the fact a 4 cent postage must be made with a 4 cent stamp and a 3 cent postage must be made with a 3 cent stamp but only looked at allocating the stamps based on the total amount of postage
1,000 grams
To convert kilograms to grams, you can use the ratio
1 kilogram
true or false
Answer:
True
Step-by-step explanation:
A Kilogram (kilo) is a unit of measuring metric mass. To perform this conversion you need to note that
1 Kilogram (kg) = 1000 grams
Which means that converting Kilogram to Grams would involve multiplying kilogram by 1000.
For example, 100 kg to grams = 100 * 1000 = 100,000 Grams
The pumpkin patch had two corn mazes, as shown by the shaded and non-shaded sections in the model below. A model with 4 rows of 7 squares, representing 28 acres, and 2 rows of 7 squares, representing 14 acres. Which expression is shown by the model? 28 + 14 = 7 (4 + 14) 28 + 14 = 4 (7 + 2) 28 + 14 = 4 (14 + 28) 28 + 14 = 7 (4 + 2) ;p winner get brainliest no joke
Answer: 28+14 = 7 (4+2)
Step-by-step explanation:
The first option is incorrect because after you distribute 7 into (4 + 14), you get 28 + 14 = 28 + 98.The second option is incorrect because after you distribute 4 into (7 + 2), you get 28 + 14 = 28 + 8.The third option is incorrect because after you distribute 4 into (14 + 28), you get 28 + 14 = 56 + 112.The fourth option is correct because after you distribute 7 into ( 4 + 2), you get 28 + 14 = 28 + 14.Answer:
It's D.
yuhhhhhhhhhhhhhhhhhhhhhh.
What’s 2×100 +18-1+20
Answer:
it is 237
Step-by-step explanation:
Answer: 237
Step-by-step explanation:
You do not to do order of operations for this problem
2 x 100 = 200
200 + 18 = 218
218 - 1 = 217
217 + 20 = 237
Hope it helps!
Answer this question please?
Answer:
it would be y = 9/2x
this is because you are trying to find the baking soda so you put that on the bottom, the sugar is just the multiplier for the baking soda
Step-by-step explanation:
In the number 921.430865. What is the place value of the digits
indicated?
O Tens
O Ten Thousandths
O Tenths
O Ones
decimal number 68 81239 in its expanded form
Answer:
(a) Tens=2
(b) Ten thousandths=8
(c) Tenths=4
(d) Ones=1
Step-by-step explanation:
The given number is 921.430865.
The place value names before the decimal point in the number are
[tex]\cdots-\text{Thousands}-\text{Hundreds}-\text{Tens}-\text{Ones}-[ . decimal][/tex]
The place value names before the decimal point in the number are
[tex][decimal.]\text{Tenths}-\text{Hundredths}-\text{Thousandths}-\text{Ten thousandths}-\cdots[/tex]
So, in the given number, the place value of
(a) Tens=2
(b) Ten thousandths=8
(c) Tenths=4
(d) Ones=1
The Empirical Rule The following data represent the length of eruption for a random sample of eruptions at the Old Faithful geyser in Calistoga, California.108 108 99 105 103 103 94102 99 106 90 104 110 110103 109 109 111 101 101
110 102 105 110 106 104
104 100 103 102 120 90
113 116 95 105 103 101
100 101 107 110 92 108(a) Determine the sample standard deviation length of eruption.Express your answer rounded to the nearest whole number.(b) On the basis of the histogram drawn in Section 3.1, Problem 28, comment on the appropriateness of using the Empirical Rule to make any general statements about the length of eruptions.(c) Use the Empirical Rule to determine the percentage of eruptions that last between 92 and 116 seconds.(d) Determine the actual percentage of eruptions that last between 92 and 116 seconds, inclusive.(e) Use the Empirical Rule to determine the percentage of eruptions that last less than 98 seconds.(f) Determine the actual percentage of eruptions that last less than 98 seconds.
Answer:
(a) Sample Standard Deviation approximately to the nearest whole number = 6
(b) The use of Empirical Rule to make any general statements about the length of eruptions is empirical rules tell us about how normal a distribution and gives us an idea of what the final outcome about the length of eruptions is.
(c) The percentage of eruptions that last between 92 and 116 seconds using the empirical rule is 95%
(d) The actual percentage of eruptions that last between 92 and 116 seconds, inclusive is 95.45%
(e) The percentage of eruptions that last less than 98 seconds using the empirical rule is 16%
(f) The actual percentage of eruptions that last less than 98 seconds is 15.866%
Step-by-step explanation:
(a) Determine the sample standard deviation length of eruption.
Express your answer rounded to the nearest whole number.
Step 1
We find the Mean.
Mean = Sum of Terms/Number of Terms
= 90+ 90+ 92+94+ 95+99+99+100+100, 101+ 101+ 101+101+ 102+102+ 102+103+103+ 103+103+103+ 104+ 104+104+105+105+105+ 106+106+107+108+108+108 + 109+ 109+ 110+ 110+110+110+ 110+ 111+ 113+ 116+120/44
= 4582/44
= 104.1363636
Step 2
Sample Standard deviation = √(x - Mean)²/n - 1
=√( 90 - 104.1363636)²+ (90-104.1363636)² + (92 -104.1363636)² ..........)/44 - 1
= √(199.836777 + 199.836777 + 147.2913224+ 102.7458678+ 83.47314049+ 26.3822314+ 26.3822314+ 17.10950413+17.10950413+ 9.836776857+ 9.836776857, 9.836776857+9.836776857+ 4.564049585+ 4.564049585+ 4.564049585+ 1.291322313+ 1.291322313+ 1.291322313+ 1.291322313+ 1.291322313+ 0.01859504133+ 0.01859504133+ 0.01859504133+ 0.7458677685+ 0.7458677685+ 0.7458677685+ 3.473140497+ 3.473140497+ 8.200413225+ 14.92768595+ 14.92768595+ 14.92768595+ 23.65495868+ 23.65495868+ 34.38223141+ 34.38223141+34.38223141+ 34.38223141+ 34.38223141+47.10950414+ 78.56404959+ 140.7458677+ 251.6549586) /43
= √1679.181818/43
= √39.05073996
= 6.249059126
Approximately to the nearest whole number:
Mean = 104
Standard deviation = 6
(b) On the basis of the histogram drawn in Section 3.1, Problem 28, comment on the appropriateness of using the Empirical Rule to make any general statements about the length of eruptions.
The use of Empirical Rule to make any general statements about the length of eruptions is empirical rules tell us about how normal a distribution and gives us an idea of what the final outcome about the length of eruptions is .
(c) Use the Empirical Rule to determine the percentage of eruptions that last between 92 and 116 seconds.
The empirical rule formula states that:
1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .
2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .
3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ
Mean = 104, Standard deviation = 6
For 68% μ - σ = 104 - 6 = 98, μ + σ = 104 + 6 = 110
For 95% μ – 2σ = 104 -2(6) = 104 - 12 = 92
μ + 2σ = 104 +2(6) = 104 + 12 = 116
Therefore, the percentage of eruptions that last between 92 and 116 seconds is 95%
(d) Determine the actual percentage of eruptions that last between 92 and 116 seconds, inclusive.
We solve for this using z score formula
The formula for calculating a z-score is is z = (x-μ)/σ
where x is the raw score, μ is the population mean, and σ is the population standard deviation.
Mean = 104, Standard deviation = 6
For x = 92
z = 92 - 104/6
= -2
Probability value from Z-Table:
P(x = 92) = P(z = -2) = 0.02275
For x = 116
z = 92 - 116/6
= 2
Probability value from Z-Table:
P(x = 116) = P(z = 2) = 0.97725
The actual percentage of eruptions that last between 92 and 116 seconds
= P(x = 116) - P(x = 92)
= 0.97725 - 0.02275
= 0.9545
Converting to percentage = 0.9545 × 100
= 95.45%
Therefore, the actual percentage of eruptions that last between 92 and 116 seconds, inclusive is 95.45%
(e) Use the Empirical Rule to determine the percentage of eruptions that last less than 98 seconds
The empirical rule formula:
1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .
2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .
3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ
For 68% μ - σ = 104 - 6 = 98,
Therefore, 68% of eruptions that last for 98 seconds.
For less than 98 seconds which is the Left hand side of the distribution, it is calculated as
= 100 - 68/2
= 32/2
= 16%
Therefore, the percentage of eruptions that last less than 98 seconds is 16%
(f) Determine the actual percentage of eruptions that last less than 98 seconds.
The formula for calculating a z-score is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
For x = 98
Z score = x - μ/σ
= 98 - 104/6
= -1
Probability value from Z-Table:
P(x ≤ 98) = P(x < 98) = 0.15866
Converting to percentage =
0.15866 × 100
= 15.866%
Therefore, the actual percentage of eruptions that last less than 98 seconds is 15.866%
If f(x) = 1/x + 2/x ,
then f
(1/3) =
Answer:
f(1/3) = 9
Step-by-step explanation:
f(x) = 1/x + 2/x
f(1/3) = 1/(1/3) + 2/(1/3)
f(1/3) = 1(3) + 2(3)
f(1/3) = 3 + 6
f(1/3) = 9
Which expression represents the average of three test scores?
Answer:
Step-by-step explanation:
(test 1+ test 2+ test 3)/3Solve the following equation for w :
P= 2h+w+ π w
Simplity (6 1/4) ^ 4
Answer: 81/16
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