Consider the Bell X-2 research aircraft, which was the first aircraft to achieve Mach 3 on September 27th , 1956. During this flight, the aircraft reached a velocity of 936 m/s at an altitude of 65,500 ft. Calculate the actual Mach number that the X-2 achieved during this flight. Now, consider two other conditions. Condition #1: Assuming the aircraft travels at the same velocity in Jupiter’s atmosphere at an altitude where the temperature is -145 °C. Also, assume that the atmosphere of Jupiter is made up of entirely hydrogen gas (H2) which has a molecular weight of 2.016 g/mol. Calculate the Mach number of the X-2 on Jupiter. Condition #2: Assuming the aircraft travels at the same velocity in Pluto’s atmosphere at an altitude where the temperature is -223 °C. Also, assume that the atmosphere of Pluto’s is made up of entirely nitrogen gas (N2) which has a molecular weight of 28.013 g/mol. Calculate the Mach number of the X-2 on Pluto.

Answer:

a. 50.9 mΩ b. 9.32 × 10¹⁸ electrons/s c. 4.55 × 10⁵ A/m² d. i. resistance and current density  ii. They would decrease.

Explanation:

a. The resistance of the copper wire is given by

R = ρl/A where ρ = resistivity of copper wire = 1.68 × 10⁻⁸ Ωm, l = length of copper wire = 10 m and A = cross-sectional area of coper wire = πd²/4 where d = diameter of copper wire = 2.05 mm = 2.05 × 10⁻³ m

A =  πd²/4  

= π(2.05 × 10⁻³ m)²/4

= 13.2025/4  × 10⁻⁶ m²

= 3.3 × 10⁻⁶ m².

So R = ρl/A

=  1.68 × 10⁻⁸ Ωm × 10 m/3.3 × 10⁻⁶ m²

= 0.0509 Ω

= 50.9 mΩ

b. Since a current of 1.5 A flows through the wire, it means that 1.5 C/s, that is 1.5 Coulombs of charge flows through it per second.

Since 1 electron = 1.609 × 10⁻¹⁹ C, the number of electrons in 1.5 A is 1.5 C/s ÷ 1.609 × 10⁻¹⁹ C per electron = 1.5/1.609 × 10⁻¹⁹ C = 9.32 × 10¹⁸ electrons/s

c. The current density J = I/A where I = current = 1.5 A and A = cross-sectional area of copper wire = 3.3 × 10⁻⁶ m²

J = 1.5 A/3.3 × 10⁻⁶ m²

= 4.55 × 10⁵ A/m²

d. i. If the diameter were twice the initial diameter, d' = 2d, then the resistance and current density would change since they are dependent of the cross-sectional area of the wire which is then dependent on the diameter of the wire.

ii. If the diameter were twice the initial diameter, d' = 2d, then since the cross-sectional area A' = πd'²/4 = π(2d)²/4 = 4πd²/4 = 4A. So, the cross-sectional area increases by a factor of four.

The new resistance R' =  ρl/4A = R/4

The new current density J' = I/4A = J/4.

So the resistance and current density would decrease.

Answer:

true

Explanation:

Answer:

this is my old profile,i just need my back

Answer:

79.29

Explanation:

Given that,

The y component of a vector, y = 36

The angle between the vector and the x-axis is 27.

We need to find the magnitude of a vector.

Let a and b are x and y component of a vector m. There resultant is R. So,

[tex]R=\sqrt{a^2+b^2}[/tex]

Where

[tex]a=c\cos\theta\ \text{and}\ b=c\sin\theta[/tex]

We have, b = 36 and θ = 27°

So,

[tex]36=R\sin\theta\\\\R=\dfrac{36}{\sin\theta}\\\\R=\dfrac{36}{\sin(27)}\\R=79.29[/tex]

So, the magnitude of the vector is 79.29

Answer:

Vf = 22.62 [m/s] in 2 seconds.

Explanation:

In order to solve this problem we must use the following kinematics equation

[tex]v_{f} = v_{i} + (g*t)[/tex]

where:

Vf = final velocity [m/s]

Vi = initial velocity = 3 [m/s]

g = gravity acceleration = 9.81 [m/s^2]

t = time = 2 [s]

Vf = 3 + (9.81*2)

Vf = 22.62 [m/s]

Solution:

1. millimeter, centimeter

 1 centimeter = 10 millimeter

 So, centimeter is the larger unit here.

2. kilogram, megagram

    1 megagram = 1000 kilogram

   So, megagram is the larger unit here.

3. microsecond, millisecond

    1 millisecond = 1000 microsecond

   So, millisecond is the larger unit here.

4.dL, mL

  1 dL = 100 mL

So, dL is the larger unit here.  

5.mg, kg

  1 mg = 0.000001 kg

 So, kg is the larger unit here.

6. Mm,mm

   1 mm = 1 mm

  Both are same

7. S, cs

   1 second = 100 centisecond

So, S is the larger unit.  

8. M, mm

   1 M  = 1000 mm

So, M is the larger unit here.  

9. U s, ks

   Us is larger.

Answer:

hago

Explanation:

hago mis quehaceresmeans means I do my homework

Answer: 490

Explanation:

Answer:

total distance travelled

Explanation:

Answer:

the  wavelength of the wave is 1.5 m

Explanation:

Given;

speed of the wave, v = 90 m/s

frequency of the wave, f = 60 Hz

The wavelength of the wave is given as;

v = fλ

λ = v / f

where;

λ is the wavelength of the wave

Substitute the given values of v and f, to determine the wavelength.

λ = v / f

λ = 90 / 60

λ = 1.5 m

Therefore, the  wavelength of the wave is 1.5 m

Answer:

The value is  [tex]KE = 9 J[/tex]

Explanation:

From the question we are told that

      The mass is  [tex]m = 0.5 \ kg[/tex]

     The velocity is  [tex]v = 6 \ m/s[/tex]

Generally the kinetic energy is mathematically represented as

        [tex]KE = \frac{ 1}{2} * m*v^2[/tex]

=>     [tex]KE = \frac{ 1}{2} * 0.5*6^2[/tex]

=>     [tex]KE = 9 J[/tex]

Answer:

The required  total area is 1.48 m²

Explanation:

Given that,

Latitude = 44+° N

New Mexico,

Latitude= 35+° N

Heat capacity = 4200 J/Kg°C

Temperature = 60°C

Let us assume the input temperature 22°C

Estimate volume of water 100 ltr for 4 person.

We need to calculate the heat

Using formula of heat

[tex]H=mc_{p}\Delta T[/tex]

[tex]H=mc_{p}(T_{f}-T_{i})[/tex]

Put the value into the formula

[tex]H=100\times4200\times(60-22)[/tex]

[tex]H=15960\ KJ[/tex]...(I)

Let solar radiation for 6 hours/day.

We need to calculate the total energy per unit area

Using formula of energy

[tex]E=1000\times6\times3600\ J/m^2[/tex]

[tex]E=21600\ KJ/m^2[/tex]

Let the efficiency of collector is 50 %

Then,  the total energy per unit area will be

[tex]E=21600\times\dfrac{50}{100}[/tex]

[tex]E=10800\ KJ/m^2[/tex]....(II)

We need to calculate the required total area

Using equation (I) and (II)

[tex]A=\dfrac{H}{E}[/tex]

Where, H = heat

E = total energy

Put the value into the formula

[tex]A=\dfrac{15960}{10800}[/tex]

[tex]A=1.48\ m^2[/tex]

Hence, The required  total area is 1.48 m²

Answer:

(472i + 80.3j) m

Explanation:

Given the following :

Distance of tee shot = 300m

Distance of second shot = 189.0 m

Displacement r1 of tee shot :

r1 = 300 mi

Displacement r2 of second shot :

r2 = 172.0 mi + 80.3 mj

The final displacement of the golf ball from the tee:

r_final = r1 + r2

r_final = (300i)m + (172.0i + 80.3j) m

r_final = (300 + 172)i m + 80.3j m

r_final = (472i + 80.3j) m

Newton’s laws explain why scientists could expect this to happen , The mass of the rocket decreases as fuel is burned, so the acceleration increases, therefore the correct answer is option B.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum. The mathematical expression for Newton's second law is as follows

As given in the problem Scientists launch a rocket, and they monitor its acceleration and the force exerted by its engines. As the rocket gets higher, the monitors show that the acceleration of the rocket is increasing but the force exerted stays the same.

Newton's laws clarify why scientists may anticipate this to occur. The right response is option B because as fuel is burnt, the rocket's mass reduces, and its acceleration rises.

Learn more about Newton's second law here,refer to the link given below ;

brainly.com/question/13447525

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Answer:

yes SI units are used for scientific works

Explanation:

because they are standard units and can be used by anyone easly

Answer:

Average speed (s) = total distance/total elapsed tiime

Explanation:

To calculate the average speed of an object, you must know the total distance an object travels and the total elapsed time of its whole journey.

Answer:

To find the average speed of an object, divide the total distance covered by the object by the total time it takes the object to cover such distance.

average speed= total distance covered/total time

Answer:

b) 31.4 m^2

Explanation:

Area of rectangle = lb

= 4.79 x 3.547

= 16.990

Approximately 17m²

A¹ = pi(d/2)²

= Pi(6.32m/2)²

= 31.37m

=Approximately 31.4

31.4 m² is the most precise estimate that you can obtain from your measurements for the area of your bedroom

The question is missing some parts. Here is the complete question.

An ideal gas is contained in a vessel at 300K. The temperature of the gas is then increased to 900K.

(i) By what factor does the average kinetic energy of the molecules change, (a) a factor of 9, (b) a factor of 3, (c) a factor of [tex]\sqrt{3}[/tex], (d) a factor of 1, or (e) a factor of [tex]\frac{1}{3}[/tex]?

Using the same choices in part (i), by what factor does each of the following change: (ii) the rms molecular speed of the molecules, (iii) the average momentum change that one molecule undergoes in a colision with one particular wall, (iv) the rate of collisions of molecules with walls, and (v) the pressure of the gas.

Answer: (i) (b) a factor of 3;

              (ii) (c) a factor of [tex]\sqrt{3}[/tex];

              (iii) (c) a factor of [tex]\sqrt{3}[/tex];

             (iv) (c) a factor of [tex]\sqrt{3}[/tex];

              (v) (e) a factor of 3;

Explanation: (i) Kinetic energy for ideal gas is calculated as:

[tex]KE=\frac{3}{2}nRT[/tex]

where

n is mols

R is constant of gas

T is temperature in Kelvin

As you can see, kinetic energy and temperature are directly proportional: when tem perature increases, so does energy.

So, as temperature of an ideal gas increased 3 times, kinetic energy will increase 3 times.

For temperature and energy, the factor of change is 3.

(ii) Rms is root mean square velocity and is defined as

[tex]V_{rms}=\sqrt{\frac{3k_{B}T}{m} }[/tex]

Calculating velocity for each temperature:

For 300K:

[tex]V_{rms1}=\sqrt{\frac{3k_{B}300}{m} }[/tex]

[tex]V_{rms1}=30\sqrt{\frac{k_{B}}{m} }[/tex]

For 900K:

[tex]V_{rms2}=\sqrt{\frac{3k_{B}900}{m} }[/tex]

[tex]V_{rms2}=30\sqrt{3}\sqrt{\frac{k_{B}}{m} }[/tex]

Comparing both veolcities:

[tex]\frac{V_{rms2}}{V_{rms1}}= (30\sqrt{3}\sqrt{\frac{k_{B}}{m} }) .\frac{1}{30} \sqrt{\frac{m}{k_{B}} }[/tex]

[tex]\frac{V_{rms2}}{V_{rms1}}=\sqrt{3}[/tex]

For rms, factor of change is [tex]\sqrt{3}[/tex]

(iii) Average momentum change of molecule depends upon velocity:

q = m.v

Since velocity has a factor of [tex]\sqrt{3}[/tex] and velocity and momentum are proportional, average momentum change increase by a factor of

(iv) Collisions increase with increase in velocity, which increases with increase of temperature. So, rate of collisions also increase by a factor of [tex]\sqrt{3}[/tex].

(v) According to the Pressure-Temperature Law, also known as Gay-Lussac's Law, when the volume of an ideal gas is kept constant, pressure and temperature are directly proportional. So, when temperature increases by a factor of 3, Pressure also increases by a factor of 3.

Answer:

She must throw it in the opposite direction away from herself and the ship at a velocity of -8.33 m/s.

Explanation:

She must throw it in the opposite direction away from herself and the ship. To find the velocity with which she throws it, we consider the law of conservation of momentum.

Since initial momentum = final momentum and the initial momentum of the astronaut and wrench = 0

0 = final momentum

0 = mv + MV where m = mass of wrench = 1.0 kg, v = velocity of wrench, M = mass of astronaut + suit = 100 kg and V = velocity of astronaut.

So. mv = -MV

v = -MV/m

Now, if the astronaut is supposed to cover a distance of 100 m from the space ship in 20 minutes, her velocity should be, V = distance/time = 100 m/ 20 min = 100 m/(20 × 60 s)  = 100 m/1200 = 0.0833 m/s

So v = -MV/m

= -100 kg × 0.0833 m/s ÷ 1.0 kg

= -8.33 m/s

She must throw the wrench in the opposite direction away from herself and the ship at a velocity of -8.33 m/s.

Answer:

h2o and o2

Explanation:

Answer:

Total energy =kinetic energy +potential energy.

Answer:

Kinetic Energy + Potential Energy = total energy

Explanation:

The conservation of mechanical energy can be written as “KE + PE = const”. Though energy cannot be created nor destroyed in an isolated system, it can be internally converted to any other form of energy.

Answer:

ask questions about the

Explanation:

Answer:

34

Explanation:

Answer:

Velocity=-0.033

Speed=0.17

Explanation:

Explanation:

the rate at which something occurs or is repeated over a particular period of time or in a given sample

Answer:

Frequency is the number of occurrences of a repeating event per unit of time. It is also referred to as temporal frequency, which emphasizes the contrast to spatial frequency and angular frequency. Frequency is measured in units of hertz (Hz) which is equal to one occurrence of a repeating event per second.

Hope this helps :D

Answer:

 Δt = 3.04 10³ s

Explanation:

a) This is a thermal conduction exercise that is described by the expression

         P = k A | dT/dx |     (1)

where P power, k thermal  conductivity, A the area, T the temperature and x the thickness

The power supplied to the wood is

          P = Q / Δt

where the heat is given by

         Q = m [tex]c_{e}[/tex] ΔT'

we substitute

         P = m c_{e} ΔT'/ Δt

We assume that the changes in temperature and time can be approximated by their differences,

we substitute in 1

          m c_{e} ΔT'/Δt = k A dT / dx

as the temperature changes are small, we can assume a linear variation, consequently the derivatives can be approximated to the variations

           m ce ΔT'/Δt = k A ΔT/Δx    (2)

let's write the temperature variations explicitly

        ΔT’= (T_f -T₀)

        ΔT’= 56 -0

        ΔT = [tex](T_{h} - T_{c} )[/tex]

        ΔT = 70 -0    

the thermal diffusivity is

           α = k /ρ c_{e}

            k = α c_{e}

the definition of density

            ρ = m / V

            ρ = m / A L

            k = α c_{e} m / A L

we substitute   in 2

          m c_{e} Δx = (α c_{e} m / A L) A ΔT /ΔT'   dt

          Δx = α /L   ΔT / ΔT’  Δt

          Δt = L Dx /α ΔT'/ΔT

let's calculate

          Δt = 2.54 1.27 10⁻⁴ / 8.5 10⁻⁸    (56- 0) / (70-0)

          Δt = 3.04 10³ s

Answer:

One source of carbon dioxide is us.

Explanation:

we inhale oxygen and exhale carbon dioxide.

One significant source of carbon dioxide emissions is the combustion of fossil fuels. When fossil fuels like coal, oil, and natural gas are burned for energy, they release carbon dioxide into the atmosphere.

The combustion process involves the reaction of fossil fuels with oxygen, resulting in the release of carbon dioxide as a byproduct.  

For example, when gasoline is burned in a car's engine, it undergoes combustion, producing carbon dioxide along with other combustion byproducts. Similarly, when coal is burned in a power plant to generate electricity, it emits carbon dioxide into the atmosphere.

These human activities, particularly the burning of fossil fuels, have significantly increased the concentration of carbon dioxide in the Earth's atmosphere.

However, human activities are the primary drivers of the increased levels of carbon dioxide in the atmosphere over the past century.

To know more about carbon dioxide:

https://brainly.com/question/13229518

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