Consider the following data. The expected value is -2.1.Find the variance, standard deviation, P(X ≥ -1), and P(X ≤ -3).

Consider The Following Data. The Expected Value Is -2.1.Find The Variance, Standard Deviation, P(X -1),

Answers

Answer 1

Given

The data,

To find:

The variance, standard deviation, P(X ≥ -1), and P(X ≤ -3).

Explanation:

It is given that,

Then,

The variance is,

[tex]\begin{gathered} Var[x]=(-4-(-2.1))^2\times0.2+(-3-(-2.1))^2\times0.3+(-2-(-2.1))^2 \\ \times0.1+(-1-(-2.1))^2\times0.2+(0-(-2.1))^2\times0.2 \\ =(-4+2.1)^2\times0.2+(-3+2.1)^2\times0.3+(-2+2.1)^2\times0.1+(-1+2.1)^2 \\ \times0.2+(2.1)^2\times0.2 \\ =3.61\times0.2+0.81\times0.3+0.01\times0.1+1.21\times0.2+4.41\times0.2 \\ =0.722+0.243+0.001+0.242+0.882 \\ =2.09 \end{gathered}[/tex]

And the standard deviation is,

[tex]\begin{gathered} SD=\sqrt{Var[x]} \\ =\sqrt{2.09} \\ =1.45 \end{gathered}[/tex]

Also,

[tex]\begin{gathered} P\left(X≥-1\right)=P(X=-1)+P(X=0) \\ =0.2+0.2 \\ =0.4 \\ P\left(X≤-3\right)=P(-4)+P(-3) \\ =0.2+0.3 \\ =0.5 \end{gathered}[/tex]

Hence, the answers are,

Variance is 2.09

Standard deviation is 1.45

P(X ≥ -1) is 0.4

P(X ≤ -3) is 0.5.

Consider The Following Data. The Expected Value Is -2.1.Find The Variance, Standard Deviation, P(X -1),
Consider The Following Data. The Expected Value Is -2.1.Find The Variance, Standard Deviation, P(X -1),

Related Questions

Consider the equation below. 4(x - 4) + 6x = 14 Part A: Enter the value for x that makes the equation true. X = Part B: Explain the algebraic steps you took to get the solution. thea Part C: Explain how you know your solution in Part A is correct.

Answers

Part A) To find out the value for x that makes it an identity, (true), we need to solve it.

4(x-4) +6x=14 Distiribute

4x -16 +6x = 14 Combine like terms

2x -16 = 14 Add 16 to both sides

2x = 30 Divide both sides by 2

x =15

Part B) Above explained.

Part C) We can know it by plugging it into the original equation:

4(15 -4) +6(15) = 14

4(11) +90 = 14

44

Find the midpoint of the line segment IJ where I (3,-9) and J (-10,-5)

Answers

Answer:

M (-7/2, -7)

Explanation:

Given the coordinates as I(3, - 9) and J(-10, -5), we can go ahead and determine the midpoint of the line segment IJ using the midpoint formula stated below;

[tex]M(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

So we have that x1 = 3, x2 = -10, y1 = -9, and y2 = -5.

Let's go ahead and substitute the above values into our formula and simplify;

[tex]\begin{gathered} M\lbrack\frac{3+(-10)}{2},\frac{-9+(-5)}{2}\rbrack \\ =M(\frac{3-10}{2},\frac{-9-5}{2}) \\ =M(-\frac{7}{2},\frac{-14}{2}) \\ =M(-\frac{7}{2},-7) \end{gathered}[/tex]

INT. ALGEBRA: Write an equation that passes through (-10,-30) and is perpendicular to 12y-4x=8

Thank you for your help, and please do show work! I will be looking to give the Brainliest answer to someone!

Answers

The equation of the perpendicular line is y = -3x - 60

How to determine the line equation?

The equation is given as

12y - 4x = 8

Make y the subject

12y= 4x + 8

y = 1/3x + 2/3

The point is also given as

Point = (-10, -30)

The equation of a line can be represented as

y = mx + c

Where

Slope = m

By comparing the equations, we have the following

m = 1/3

This means that the slope of 12y - 4x = 8 is 1/3

So, we have

m = 1/3

The slopes of perpendicular lines are opposite reciprocals

This means that the slope of the other line is -3

The equation of the perpendicular lines is then calculated as

y = m(x - x₁) +y₁

Where

m = -3

(x₁, y₁) = (-10, -30)

So, we have

y = -3(x + 10) - 30

Evaluate

y = -3x - 30 - 30

y = -3x - 60

Hence, the perpendicular line has an equation of y = -3x - 60

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Can someone please help me with this problem? I’ve been struggling with it

Answers

Consider the following table for interval notation:

First row:

x<0 is the same as:

[tex]-\inftyThen, the graph of that interval looks like:

And the interval notation for that inequality is:

[tex](-\infty,0)[/tex]

Second row:

-2

The graph of this inequality is:

The interval notation is:

[tex](-2,1\rbrack[/tex]

Third row

The inequality that is represented by that interval is:

[tex]-3\le x[/tex]

Its graph is:

Fourth row

The interval represented in that graph is:

[tex]\lbrack0,6)[/tex]

The inequality represented by that interval is:

[tex]0\le x<6[/tex]

The drama club was selling ticketsto the school play. Adult ticketscost $8.00 each, and studenttickets cost $5.00 each. The littletheater holds 142 people and wassold out for both Friday andSaturday. The total sales for thetwo days was $1,948.00.1. How many adult tickets weresold out over the two days?2. How many student tickets weresold out over the two days?

Answers

We are given a problem that can be solved using a system of linear equations. Let A, be the number of adults, and S the number of students. Since there are in total 142 people and there were two days, this means that the sum of the number of adults and the number of students must be 284, which can be written mathematically as follows:

[tex]A+S=284,(1)[/tex]

This is our first equation. The second equation is found using the total sales of $1948. Since the ticket per adult is $8 and per student is $5, we have the following equations:

[tex]8A+5S=1948,(2)[/tex]

To solve this equation we will solve for A in equation (1), by subtracting S to both sides;

[tex]\begin{gathered} A+S-S=284-S \\ A=284-S \end{gathered}[/tex]

Now we will replace this value in equation (2):

[tex]8(284-S)+5S=1948[/tex]

Now we will apply the distributive property:

[tex]2272-8S+5S=1948[/tex]

Addins like terms:

[tex]2272-3S=1948[/tex]

Subtracting 2272 to both sides;

[tex]\begin{gathered} 2272-2272-3S=1948-2272 \\ -3S=-324 \end{gathered}[/tex]

Dividing both sides by -3:

[tex]S=-\frac{324}{-3}=108[/tex]

Now we replace this value in equation (1), where we have already solved for A:

[tex]\begin{gathered} A=248-108 \\ A=140 \end{gathered}[/tex]

Therefore, there were sold 108 student tickets and 140 adult tickets.

Sofia got a raise from her annual salary of $43,000 to $44,505. whay percent was her raise?

Answers

[tex]\begin{gathered} \text{ The raise is given by} \\ R=1-\frac{\text{ Final salary}}{\text{ Initial salary}} \\ \\ R=1-\frac{44505}{43000} \\ \\ R=1-1.035 \\ R=0.035 \\ \text{ thus the increment is }3.5\text{ \%} \end{gathered}[/tex]

How do I solve for x? Would my answer be 27?

Answers

SOLUTION

Exterior property of a triangle

An exterior angle of a triangle is equal to the sum of its two opposite non-adjacent interior angles.

Hence,

[tex](5x+13)^0=(4x+2)^0+(2x-9)^0[/tex]

Simplify and evaluate for x

[tex]\begin{gathered} 5x+13^0=4x+2^0+2x-9^0 \\ 5x+13^0=4x+2x+2^0-9^0 \\ 5x+13^0=6x-7^0 \\ \text{Collect like terms} \\ 13^0+7^0=6x-5x \\ 20^0=x \\ \therefore x=20^0 \end{gathered}[/tex]

Therefore,

[tex]x=20^0[/tex]

the variable y is directly proportional to x. if y equals -0.6 when x equals 0.24, find x when y equals -31.5.

Answers

You have that y is proportional to x. Futhermore, you have y = -0.6 when x = 0.24.

Due to y is proportional to x, you have the following equation:

[tex]y=kx[/tex]

where k is the constant of proportionality. In order to find the value of x when y = -31.5, you first calculate k.

k is calculated by using the information about y=-0.6 and x=0.24. You proceed as follow:

y = kx solve for k

k = y/x replace by known x and y values

k = -0.6/0.24

k = -2.5

Hence, the constant of proportionality is -2.5.

Next, you use the same formula for the relation between y and x to find the value of x when y = -31.5. You proceed as follow:

y = kx solve for x

x = y/

Find the formula for an exponential function that passes through the 2 points given

Answers

The form of the exponential function is

[tex]f(x)=a(b)^x[/tex]

a is the initial value (value f(x) at x = 0)

b is the growth/decay factor

Since the function has points (0, 6) and (3, 48), then

Substitute x by 0 and f(x) by 6 to find the value of a

[tex]\begin{gathered} x=0,f(x)=6 \\ 6=a(b)^0 \\ (b)^0=1 \\ 6=a(1) \\ 6=a \end{gathered}[/tex]

Substitute the value of a in the equation above

[tex]f(x)=6(b)^x[/tex]

Now, we will use the 2nd point

Substitute x by 3 and f(x) by 48

[tex]\begin{gathered} x=3,f(x)=48 \\ 48=6(b)^3 \end{gathered}[/tex]

Divide both sides by 6

[tex]\begin{gathered} \frac{48}{6}=\frac{6(b)^3}{6} \\ 8=b^3 \end{gathered}[/tex]

Since 8 = 2 x 2 x 2, then

[tex]8=2^3[/tex]

Change 8 to 2^3

[tex]2^3=b^3[/tex]

Since the powers are equal then the bases must be equal

[tex]2=b[/tex]

Substitute the value of b in the function

[tex]f(x)=6(2)^x[/tex]

The answer is:

The formula of the exponential function is

[tex]f(x)=6(2)^x[/tex]

The formula for the perimeter of a
rectangle is P = 2l + 2w. Solve the formula for
w.

Answers

P = 2l + 2w

P = 2( l + w )

P/2 = 2( l + w ) /2

P/2 = l + w

answer: w = P/2 - 1

Please give me the answers asap the time is running down

Answers

Explanation

Given the question

[tex]|x|<13[/tex]

To get the values of x, we will consider two possibilities which are:

[tex]\begin{gathered} x\text{ being positive},\text{ so that} \\ x<13 \end{gathered}[/tex]

And

[tex]\begin{gathered} x\text{ being negative} \\ -x<13 \\ x>-13 \end{gathered}[/tex]

Therefore, the value of x is

[tex]\begin{bmatrix}\mathrm{Solution\colon}\: & \: -13

So the correct option is

[tex]\begin{bmatrix}\mathrm{Solution\colon}\mleft\lbrace x|\: \mright? & \: -13Option A is correct

The first option is correct

I need help on a problem

Answers

Those are similar triangles, which means, they are related by a ratio

For example in this case,

7: 10

to find x

10 / 7 = x/3

x= 10*3 /7

x= 30/ 7

x= 4.29

____________

what is the area of a circle with the radius of 10, then rounding the answer to the nearest tenth?

Answers

Given a circle with a radius = r = 10 in

The area of the circle is given by the following formula:

[tex]A=\pi\cdot r^2[/tex]

Substitute with r= 10

so, the area will be:

[tex]A=\pi\cdot10^2=\frac{22}{7}\cdot10^2=\frac{22}{7}\cdot100=314.2857[/tex]

Rounding the answer to the nearest tenth:

So, the answer will be area = 314.3 square inches

In the figure, m < 1= (x-6)º and m2 2= (5x).

Answers

We have the measure of angles 1 and angle 2, as we can see from the diagram in the image, angles 1 and 2 added form the right angle (90°) in the figure.

Thus, the sum of x-6 and 5x, must be equal to 90°.

(a) Write an equation:

[tex]x-6+5x=90[/tex]

(b) To find the degree measure of each angle, first we need to solve for the value of x in the equation.

Combining like terms:

[tex]6x-6=90[/tex]

Adding 6 from both sides:

[tex]\begin{gathered} 6x-6+6=90+6 \\ 6x=96 \\ \end{gathered}[/tex]

Divide both sides by 6:

[tex]\begin{gathered} \frac{6x}{6}=\frac{96}{6} \\ x=16 \end{gathered}[/tex]

Now that we have x, we find angle 1:

[tex]m\angle1=x-6=16-6=10[/tex]

And the measure of angle 2:

[tex]m\angle2=5x=5(16)=80[/tex]

A birthday cake has a diameter of 9 inches. A wedding cake has a diameter of 14 inches. What is thedifference in area between the top surfaces of the two cakes?

Answers

90.32 square inches

Explanation

Step 1

the area of the circle is given by:

[tex]\text{Area}=\frac{\pi}{4}\cdot diameter^2[/tex]

Step 2

find the areas

birthday cake

[tex]\begin{gathered} \text{Area}_b=\frac{\pi}{4}\cdot9^2 \\ \text{Area}_b=\frac{81\pi}{4} \\ \text{Area}_b=\frac{254.46}{4} \\ \text{Area}_b=63.61\text{ square inches} \end{gathered}[/tex]

Now, the wedding cake

[tex]\begin{gathered} \text{Area}_w=\frac{\pi}{4}\cdot14^2 \\ \text{Area}_w=\frac{\pi}{4}\cdot196\text{ square inches} \\ \text{Area}_w=49\cdot\pi\text{ square inches} \\ \text{Area}_w=153.93\text{ square inches} \end{gathered}[/tex]

Step 3

finally, find the difference

[tex]\begin{gathered} \text{difference}=153.93\text{ square inches-63.61 inches} \\ \text{difference}=90.32 \end{gathered}[/tex]

so, the answer is 90.32 square inches

the line AB is drawn on the grid.(i) Write down the coordinates of A

Answers

Answer:

The coordinate of point A = (0, 1)

Explanation:

Given:

the line AB is drawn on the grid

To find:

the coordinates of A

The coordinates of a point is in the form: (x, y)

To determine the coordinates of A, we will trace the y axis and x-axis.

At point A, x = 0, y = 1

The coordinate of point A = (0, 1)

Help please.

We have the equation negative 9 minus this whole expression, 9x minus 6—this whole thing is being subtracted from negative 9—is equal to 3 times this whole expression, 4x plus 6.
Solve the Equation

Answers

The value of x in the equation given is x = -4/7.

What is an equation?

A mathematical equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario.

The information given will be illustrated as:

9 - (9x - 6) - 9 = 3(4x + 6)

9 - 9x + 6 - 9 = 12x + 18

Collect like terms

-9x + 6 = 12x + 18

-9x - 12x = 18 - 6

-21x = 12

Divide

x = 12/-21

x = -4/7

This illustrates the concept of equations.

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hi! im mia, and i need help with math!question: Write a statement that correctly describes the relationship between these two sequences: 6, 7, 8, 9, 10, and 18, 21, 24, 27, 30.

Answers

The Solution:

Given the pair of sequences below:

[tex]\begin{gathered} \text{ First sequence: 6,7,8,9,10} \\ \\ \text{ Second sequence: 18,21,24,27,30} \end{gathered}[/tex]

We are asked to write a statement that correctly describes the relationship between the two sequences.

The two sequences are both linear sequences. Their common differences are:

[tex]\begin{gathered} \text{ First sequence: d=T}_3-T_2=\text{T}_2-T_1 \\ =8-7=7-6=1 \\ \text{ So, the co}mmon\text{ difference is 1} \end{gathered}[/tex]

The general formula for the first sequence is

[tex]T_n=a+(n-1_{})d=6+(n_{}-1)1=6+n-1=5+n[/tex]

Similarly,

[tex]\begin{gathered} \text{ Second sequence}\colon\text{ } \\ d=\text{T}_3-T_2=\text{T}_2-T_1 \\ d=24-21=21-18=3 \\ \text{ So, the co}mmon\text{ difference is 3} \end{gathered}[/tex]

The general formula for the second sequence is

[tex]S_n=18+(n-1_{})3=18+3n_{}-3=15+3n=3(5+n)[/tex]

Thus, the relationship between the two sequences is:

[tex]S_n=3T_n[/tex]

Where

[tex]\begin{gathered} S_n=\text{ the second sequence} \\ T_n=\text{ the first sequence} \end{gathered}[/tex]

Therefore, the correct answer is:

[tex]S_n=3T_n[/tex]

A school choir needs to make t-shirts for its 75 members. A printing company charges $2 per shirt, plus a $50 fee for each color to be printed on the shirts. Write an equation that represents the relationship between the number of t- shirts ordered, the number of colors on the shirts and the total cost of the order. If you use a variable (letter) specify what it represents.

Answers

Let:

C(n,m) = Total cost

n = number of t- shirts ordered

m = fee for each color to be printed on the shirts

Therefore, the total cost of the order would be given by the following equation:

C(n,m) = $2n + $50m

Where:

n = 75

C(n,m) = $2(75) + $50m

C(n,m) = $150 + $50m

is it a function? X (-2, -1, 0, 1, 2 ) Y (-7, -2, 1, -2, -7 )

Answers

To be a function, it is nesessary that the values of x correspond to a unique value of y (a value of x cannot correspond to 2 different values of y). The same value of y can correspond to two or more values of x

As in the given data each value of x has just one value of y. Then, it is a function.



A shop, had a sale.
(a) In the sale, normal prices were reduced by 15%.

The normal price of a chair was reduced in the sale by $24.
Work out the normal price of the chair.

Answers

Answer:

$160

Step-by-step explanation:

A shop, had a sale. In the sale, normal prices were reduced by 15%. The normal price of a chair was reduced in the sale by $24. Work out the normal price of the chair.

if 15% of normal price equals $24 then:

24/15% or 24/0.15 = $160 normal price

CHECK:

$160 * 0.15 = $24

Answer:

$160

Step-by-step explanation:

We want to know the price of the chair

So:

24 / 0.15 = 160$

or

24 / 15% = 160

a mother duck lines her 8 ducklings up behind her. in how many ways can the ducklings line up?

Answers

In position one, we can have any of the 8 ducks

In position two, we can have 7 ducks, since one has to occupy position one

and so on

then, we have:

[tex]8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1=8![/tex]

the factorial of 8 is 40320

How many possible values for y are there where y = Cos-lo? O A. O Ο. O B. Infinite O C. 1 O D. 2

Answers

Answer:

B. Infinite

Explanation:

Given that:

[tex]y=\cos ^{-1}(0)[/tex]

This implies that:

[tex]\cos (y)=0[/tex]

From the graph of f(x)=cos(x), we observe that:

[tex]\cos (x)=0\text{ for }x=\frac{\pi}{2}+k\pi\text{ for any }k\in\Z,\text{ }\Z\text{ being the set of integers}[/tex]

Therefore, there are infinitely possible values of y.

What is the answer to this question?

Answers

The reflection of a point P over a line as in the P' if the line m is the "perpendicular bisector" of line PP'. Point P' is called the "image" of point P.

What is termed as the reflection of the point?A reflection point represents when a figure is built around a single point recognized as point of reflection or the figure's center. On the other side, per each point in the graph, some other point is observed directly opposite it.

For the given question.

Line m is the line along which reflection of point P is taken.

Then, line m is called the "perpendicular bisector" of line PP'.

P is the object and P' will be the image of the point P.

Thus, the complete definition of the reflection is given as-

The reflection of a point P over a line as in the P' if the line m is the "perpendicular bisector" of line PP'. Point P' is called the "image" of point P.

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? Question
Rachel and Jeffery are both opening savings accounts. Rachel deposits $1,500 in a savings account that earns 1.5% interest,
compounded annually. Jeffery deposits $1,200 in a savings account that earns 1% interest per year, compounded
continuously.
If y represents the account balance after t years, which two equations form the system that best models this situation?

Answers

For the conditions stated, y=1500+2250t and y=1200+1200t, respectively, will be necessary equations because both Rachel and Jeffery are opening savings accounts. Rachel places $1,500 in a savings account that accrues annual compound interest of 1.5%. Jeffery places $1,200 in a savings account that accrues continuously compounded interest of 1% per year.

What is equation?

A mathematical statement known as an equation is made up of two expressions joined together by the equal sign. A formula would be 3x - 5 = 16, for instance. When this equation is solved, we discover that the value of the variable x is 7.

Here,

according to given condition,

y=1500+1500*1.5t

y=1500+2250t

y=1200+1200*1t

y=1200+1200t

So the required equation will be y=1500+2250t and y=1200+1200t for the conditions given as Rachel and Jeffery are both opening savings accounts. Rachel deposits $1,500 in a savings account that earns 1.5% interest, compounded annually. Jeffery deposits $1,200 in a savings account that earns 1% interest per year, compounded continuously.

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4x- 1/2+ 2/3x combine like terms

Answers

Okay, here we heve this:

We need to combine like terms in the following equation:

[tex]\begin{gathered} 4x-\frac{1}{2}+\frac{2}{3}x \\ =(4x+\frac{2}{3}x)-\frac{1}{2} \\ =\frac{14}{3}x-\frac{1}{2} \end{gathered}[/tex]

The table gives a set of outcomes and their probabilities. Let A be the event the outcome is divisible by 3". Find P(A). 12 Outcome Probability Tim elaps 1 0.14 PAUS 2 0.02 3 0.19 Smart out of 4 0.01 5 0.04 7 6 0.17 7 0.15 8 0.28

Answers

Here, we want to get the probability that a selected outcome is divisible by 3

What we have to do here is ti select numbers that are multiples of 3 and add their probabilities

From the given table, the outcomes that are multiples of 3 are;

3 and 6 only

So, we proceed to add the probabilities of these outcomes

Mathematically, we have this as;

[tex]P(A)\text{ = 0.19 + 0.17 = 0.36}[/tex]

Dan's dog walking job pays $15 per hour his job as a car wash attendant pays $400 each week Dan wants to know how many hours he needs to spend walking dogs to earn more than $520 in a week. Which three equalities can model this situation? select all the correct answers.

Answers

Answer:

520<400+15x

15x>120

15x+400>520

Explanation:

Pay of Dan's car wash attendant job =$400 per week

The amount he earns per hour walking dogs = $15

Let the number of hours spent walking dogs in a week = x

Therefore, total earning for walking dogs =$15x

Since he wants to earn more than $520, we have that:

[tex]15x+400>520\text{ (Option F)}[/tex]

We can rewrite this as:

[tex]520<400+15x\text{ (Option B)}[/tex]

If we collect like terms, we have:

[tex]\begin{gathered} 520-400<15x \\ 120<15x \\ \implies15x>120\text{ (Option C)} \end{gathered}[/tex]

So the inequalities are:

0. 520<400+15x

,

1. 15x>120

,

2. 15x+400>520

I need help on this

Answers

To answer this question, we need to evaluate each function in x=66, this way:

[tex]\begin{gathered} y=7(66) \\ y=462 \\ y=(66)^2-12(66)+84 \\ y=3648 \\ y=1.1317^{66} \\ y=3517.76 \end{gathered}[/tex]

In this case, the function that has a greater value at x=66 is the one in the second option:

[tex]y=x^2-12x+84[/tex]

Four times a number decreased by three is between -15 and 41?

Answers

Answer:

The number will lie between -3 and 11

Step-by-step explanation:

Let the number be 'x'

According to the question,

-15 < 4x - 3 < 41

-12 < 4x < 44 (Adding 3)

-3 < x < 11 (Dividing by 4)

Other Questions
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