The question requires us to calculate the mass of reactant (O2) necessary to obtain 15 L of the product (NO2) under the conditions given.
The following information was provided by the question:
- Balanced chemical reaction: 2 NO(g) + O2(g) → 2 NO2(g)
- Final volume of NO2: 15 L
- Pressure: P = 752 mmHg
- Temperature: 344 K
- Gas constant: R = 0.08206 L⋅atm/mol⋅K
To solve this question, we'll need to go through the following steps:
1) calculate the number of moles that corresponds to 15 L of NO2, considering the temperature and pressure given;
2) use the stoichiometric relation to calculate the necessary amount of O2 to produce the previously calculated number of moles of NO2
3) use the molar mass of O2 and the value calculated on step 2 to obtain the necessary mass of O2
Next, we'll solve the problem following these steps:
1) To calculate the number of moles of NO2, we'll use the following equation:
[tex]P\times V=n\times R\times T[/tex]where P is the pressure, V is the volume of gas, n is the number of moles, R is the constant of gases and T is the temperature.
If we rearrange the equation to calculate the number of moles, we'll have:
[tex]n=\frac{P\times V}{R\times T}[/tex]Note that the problem provided all necessary information for this calculation, but the pressure given (752 mmHg) needs to be converted into atm to match the constant provided.
To do that, we'll use the following:
1 atm = 760 mmHg
Thus, we need to divide the value provided by 760:
[tex]P=752\text{ mmHg}\times\frac{1\text{ atm}}{760\text{ mmHg}}=0.989\text{ atm}[/tex]Now, we can apply the values of pressure, volume and temperature, as well as the constant provided, to the equation written above:
[tex]n=\frac{(0.989\text{ atm)}\times(15\text{ L)}}{(0.08206\text{ L.atm/mol.K)}\times(344\text{ K)}}=0.525\text{ mol}[/tex]So far, we have that the volume of NO2 to be produced (15 L) corresponds to 0.525 mol under the conditions of pressure and temperature provided.
2) Next, we use the chemical reaction to calculate the number of moles of O2 required to produce 0.525 mol of NO2.
From the reaction, we have that 1 mol of O2 leads to 2 mol of NO2. Then, we use this to calculate how many moles of O2 would produce 0.525 moles of NO2:
1 mol O2 --------------- 2 mol NO2
x -------------------------- 0.525 mol NO2
Solving for x, we have:
[tex]x=\frac{(1\text{ mol O2)}\times(0.525\text{ mol NO2)}}{(2\text{ mol NO2)}}=0.263\text{ mol O2}[/tex]Now, we know that 0.263 moles of O2 are necessary to produce 15 L of NO2
3) The last step is calculate the mass of O2 that corresponds to 0.263 moles of this compound.
To do this, we need the molar mass of O2. Since the atomic mass of oxygen is 15.99 u, the molar mass of O2 is:
molar mass O2 = (2 * 15.99) = 31.98 g/mol
With this information, we can calculate the mass of 0.263 moles of O2:
1 mol O2 -------------------- 31.98 g O2
0.263 mol O2 ------------ y
Solving for y, we have:
[tex]y=\frac{(0.263\text{ mol O2)}\times(31.98\text{ g O2)}}{(1\text{ mol O2)}}=8.41\text{ g O2}[/tex]Therefore, the mass of O2 necessary to produce 15 L of NO2 under the conditions given is 8.41 g.
In one demonstration of this reaction, 39.00 mL of H2 are collected over water at 25°C. Atmospheric pressure is 749.0 mmHg. How many grams of H2 are collected?
Taking into account the ideal gas law, a mass of 0.00314 grams of H₂ is collected.
Definition of ideal gas lawAn ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
P is the gas pressure.V is the volume that the gas occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. The numerical value of R will depend on the units in which the other properties are worked.n is the number of moles of the gas. Mass of H₂In this case, you know:
P= 749 mmHg= 0.985526 atm (being 760 mmHg= 1 atm)V= 39 mL= 0.039 L (being 1000 mL= 1 L)n= ?R= 0.082 (atm×L)÷(mol×K)T= 25 C= 298 K (being 0 C= 273 K)Replacing in the ideal gas law:
0.985526 atm× 0.039 L = n× 0.082 (atm×L)÷(mol×K)× 298 K
Solving:
[0.985526 atm× 0.039 L]÷ [0.082 (atm×L)÷(mol×K)× 298 K]= n
0.00157 moles= n
Considering that the molar mass of H₂ is 2 g/mole, the mass can be calculated as:
mass= number of moles× molar mass
mass= 0.00157 moles× 2 g/mole
mass= 0.00314 grams
Finally, you collected a mass of 0.00314 grams.
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A patient turns in a sample of urine for specific gravity test. The lab results record a value of1.024. What is the density of this patient's urine?
Specific gravity is the same concept for relative density. This measure indicates the density with respect to the density of water at standard temperature. The formula is:
[tex]\text{Specific gravity = }\frac{density\text{ of substance}}{density\text{ of water}},[/tex]If we are comparing pure water, the density of this would be 1.00 g/mL, so clearing the formula and replacing, we're going to have:
[tex]\begin{gathered} \text{density of substance (urine) = specific gravity }\cdot\text{ density of water,} \\ \text{density of urine = 1.024 }\cdot\text{ 1.00}\frac{g}{mL}, \\ \text{density of urine = 1.024 }\frac{g}{mL}. \end{gathered}[/tex]The density of the patient's urine is 1.024 g/mL if the specific gravity is 1.024.
For each pair of bonds, indicate the more polar bond, and use an arrow to show the direction of polarity in each bond.a. C-O and C-Nb. P-Br and P-Clc. B-O and B-Sd. B-F and B-I
To calculate how polar a bond is we can look at the difference in electronegativity. An electronegativity greater than 1.7 represents an ionic bond, a bond less than 1.7 will be a covalent bond.
Let's see wich is the wich is the electronegativity of each element:
C=2.55
O=3.44
N=3.04
The difference of electronegativity of each pair of bonds will be:
Polar bonds are covalent bonds that have a difference in electronegativities. The greater the difference in electronegativity, the greater the polarity.
So, in this case, C-O bond will be more polar that C-N bond, the polarity.
The direction of the polarity will go towards the more electronegative element. So, we will have:
Answer: The most polar bond will be the C-O bond and the direction of polarity will be toward oxygen for the C-O bond and toward nitrogen for the C-N bond.
Please select the correct answer for each question!
Answer:1=X
2=Y
3=X
Explanation:
8) Identify which is the proton acceptor (base) in this following reaction:
HCI + H20 -> CH + H30+
O HCI
O H20
O H30+
O cl
The proton acceptor (base) in this following reaction is H₃0⁺
Here given reaction is
HCI + H₂O → CH + H₃O⁺
A proton is a subatomic particle found in the nucleus of every atom so in that reaction H₃0⁺ is the proton acceptor because protonic acid is the proton donor H⁺ so H₃0⁺ must be bronsted acid and OH⁻ because it accept the proton is a therefore a bronsted base and a lewis acid is by definition an electron pair acceptor and a lewis base is an electron pair donor
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PLEASE HELP!!
For this car, the airbag must have a volume of 58 liters when fully inflated. To provide an adequate cushion for the driver’s head, the air pressure inside the airbag should be 4.4 psi. This pressure value is in addition to the normal atmospheric pressure of 14.7 psi, giving a total absolute pressure of 19.1 psi, which equals 1.30 atmospheres.
One of the main components of an airbag is the gas that fills it. As part of the design process, you need to determine the exact amount of nitrogen that should be produced. Calculate the number of moles of nitrogen required to fill the airbag. Show your work. Assume that the nitrogen produced by the chemical reaction is at a temperature of 495°C and that nitrogen gas behaves like an ideal gas.
Part C
Recall the balanced chemical equation from part B of task 1:
2NaN3 → 2Na + 3N2.
Calculate the mass of sodium azide required to decompose and produce the number of moles of nitrogen you calculated in part B of this task. Refer to the periodic table to get the atomic weights.
Part D
What would happen if the amount of sodium azide used was far greater or far less than what you calculated in part C? Describe both cases.
The number of moles of nitrogen required to fill the airbag is 1.197 moles.
The mass of sodium azide required to decompose and produce 1.197 moles of nitrogen is 51.87 g.
If the mass used was greater, the airbag could burst, but if the mass used was smaller, the airbag would not inflate properly.
What amount in moles of nitrogen is required to fill the bag?The number of moles of nitrogen required to fill the airbag is calculated from the equation of reaction as follows:
Using the ideal gas equation; PV = nRT
where;
P = pressureV = volumen = number of molesR = molar gas constantT = temperatureFrom the data provided:
P = 1.30 atm
V = 58 Liters
n = ?
R = 0.082 atm.L.mol⁻¹K⁻¹
T = 495 °C or ( 273.15 + 495) K = 768.15 K
solving for n;
n = PV/RT
n = (1.3 * 58) / (0.082 * 768.15)
n = 1.197 moles
Equation of reaction: 2 NaN₃ → 2 Na + 3 N₂
moles ratio = 2 moles of sodium azide produce 3 moles of N₂
Moles of azide required = 1.197 * 2/3 = 0.798 moles
molar mass of sodium azide = 65 g/mol
mass of sodium azide = 0.798 * 65
mass of sodium azide required = 51.87 g
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explain the process of photosynthesis with these
Words:
Photosynthesis,
light,
water,
energy,
Carbon Dioxide,
Oxygen,
xylem,
stomata,
Sugar(Glucose),
phloem,
chloroplasts,
leaves,
roots
Be legible and neat please and thank you
The process of photosynthesis used by plant in which they produce sugar ( glucose ).
Photosynthesis is the process in which plants produced sugar by using sun - light , water and carbon dioxide. In the process of photosynthesis plants use carbon dioxide ( CO₂ ) and water H₂O from the air and the soil then this carbon dioxide and water transforms to oxygen and sugar (glucose). the oxygen produced by plant back into the air and the sugar produces stores by the plant as the form of energy.
sunlight
carbon dioxide + water --------------> glucose + oxygen
In the leaf cell a part called chloroplast in it energy in sunlight used to break oxygen and hydrogen. T he water required in the process of photosynthesis taken by the roots from soil and then it transport with the help of xylem cell to the different parts of plant. phloem takes sugar from leaves to different parts of plant. The stomata is for the transpiration exchange that means it takes carbon dioxide and the release oxygen back to air after the photosynthesis end.
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what is the pH solution containing 0.3 M HCOOH and 0.52 M HCOOK?
First, we need the reaction to start the exercise.
HCOOH(aq) + H2O(l) = H3O+(aq) + HCOO-(aq)
HCOOK => HCOO- + H+
------------------------------------------------------------------------
pH)
We have here an ionic equilibrium, HCOOH is a weak acid.
pKa = 3.77 (from tables)
The concentration of HCOOH 0.3 M
The concentration of HCOO- = 0.52 M HCOOK.
If we propose Ka for HCOOH(aq)
[tex]Ka\text{ = }\frac{\lbrack H_3O^+\rbrack x\lbrack HCOO-\rbrack^{_{}}}{\lbrack HCOOH\rbrack}[/tex]We clear (H3O+) and we apply -log and we get this:
[tex]pH\text{ = }pKa+log(\frac{[HCOO^-]}{[HCOOH]})[/tex][tex]pH=3.77+log(\frac{[0.52]}{[0.30]})\text{ }[/tex]Answer: pH = 4.01
--------------------------------------------------------------------------------------------------
pOH)
pH + pOH = 14
(This formula appears from the ionic equilibrium of water)
pOH = 14 - 4.01 = 9.99
Answer: pOH= 9.99
--------------------------------------------------------------------------------------------------
What is 4.8829g + 121.3 g + 9.384 g . ensure your answer confiding to rules regarding significant figures
Answer:
[tex]135.6g[/tex]Explanation:
Here, we want to sum the given values, then give an answer to the correct significant figures
The correct significant figure for addition operation is the significant figure of the number that has the lowest count of values after the decimal places
Looking at the values, the number with the lowest significant figure after the decimal value is 121.3
Thus, our answer will have a value with 1 significant figure after the decimal place
We have it that:
[tex]\begin{gathered} \text{ 4.8829 + 121.3 + 9.384 = 135.5669g} \\ which\text{ finally is:} \\ 135.6g \end{gathered}[/tex]
can someone please help me with question 27 B please!
Answer:
Sodium carbonate + Nitric acid → sodium nitrate + water + carbon dioxide. - To write the balanced chemical reaction between sodium carbonate and nitric acid we should know the chemical formula of them. - The chemical formula of sodium carbonate is Na2CO3 and the chemical formula of nitric acid is HNO3
Explanation:
hope it help
How many gram of iron is how many moles in 5237 & how many in 4180
To get the number of moles, you need to use this equation:
n = m/M
where n is the number of moles, m is the mass and M is the molar mass of Iron.
Given:
m = 5227 g
M = 55.8 g/mol (from the periodic table)
Therefore
n = 5227 g/55.8 g/mol
n = 93.7
The first option is closer to 93.7 so the answer is the first option.
help me please if you can a. ammonia b. battery acid c.pure waterd. sea water
Answer:
ammonia
Explanation:
JWhat did Rutherford’s model of the atom include that Thomson’s model did not have?
a nucleus
energy levels
electron clouds
smaller particles
Answer:
Rutherford's model of the atom included the nucleus, something lacking in Thomson's model. Rutherford's inclusion of the nucleus came about after his discovery of the nucleus of the atom in 1911. He was testing J.J. Thomson's Plum Pudding model by directing a beam of alpha particles toward a thin sheet of gold foil.
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Consider this reaction:3Ca(s)+2H3PO4(aq)=Ca3(PO4)2(s)+3H2(g)How many grams of calcium are required to produce 50.500 g of calcium phosphate (MW = 310.19g/mol) assuming an excess of Phosphoric acid?
Answer
19.6 grams
Explanation
Given:
Mass of calcium phosphate produced = 50.500 g
Equation: 3Ca(s) + 2H3PO4(aq) ---> Ca3(PO4)2(s) + 3H2(g)
What to find:
The grams of calcium required to produce 50.500 g of calcium phosphate.
Step-by-step solution:
From the equation, 3 mol Ca produce 1 mol Ca3(PO4)2
1 mole Ca3(PO4)2 = 310.19 grams
1 mole Ca = 40.078 grams
This means, (3 x 40.078 g) = 120.234 g Ca produce 310.19 g Ca3(PO4)2
So x grams Ca will be required to produce 50.500 grams Ca3(PO4)2
x grams Ca will be equal
[tex]\frac{50.500\text{ }g}{310.19\text{ }g}\times120.234g\text{ }Ca=19.6\text{ }grams\text{ }Ca[/tex]The grams of calcium required to produce 50.500 g of calcium phosphate = 19.6 grams
identify an element that has similar chemical properties as those of the element krypton (K).
Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
[] → CH3,CH3,(g) +O2,(g) → CO2,(g) + H2O(g)
[tex]$$\mathrm{CH}_3 \mathrm{CH}_3(y)+\mathrm{O}_2(q) \rightarrow \mathrm{CO}_2(q)+\mathrm{H}_2 \mathrm{O}(\text { I })$$[/tex]
[tex]\begin{tabular}{l|l}$C=2$ & $C=1$ \\$H=6$ & $H=2$ \\$O=2$ & $0=3$\end{tabular}[/tex]
First balance carbon then balms oxygen and followed by hydrogen through adding odd number Infront of the reactant and product.
[tex]$$2\mathrm{CH}_3 \mathrm{CH}_3(y)+7\mathrm{O}_2(q) \rightarrow 4\mathrm{CO}_2(q)+6\mathrm{H}_2 \mathrm{O}(\text { I })$$[/tex]
[tex]\begin{tabular}{l|l}$C=4$ & $C=4$ \\$H=12$ & $H=12$ \\$O=14$ & $0=14$\end{tabular}[/tex]
What is stoichiometric coefficients?Stoichiometry as the calculation of products and reactants in a chemical response. It is fundamentally concerned with numbers. Stoichiometry is an critical concept in chemistry that makes a difference us utilize adjusted chemical conditions to calculate sums of reactants and products. Here, we make utilize of proportions from the adjusted condition. In common, all the responses that take put are subordinate on one primary figure, how much substance is present. Stoichiometry makes a difference us determine how much substance is required or is present.
Stoichiometry helps us determine
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2. 5.4 grams of carbon dioxide gas is confined to a 20.0 L container at atemperature of 32.5°C. What pressure does the gas exert? (15 kPa)
To calculate this, we will need to assume the gas behaves as an ideal gas.
So, we can use the Ideal Gas Law:
[tex]PV=nRT[/tex]Where P is the pressure, V is the volume, n is the number of moles, is the absolut temperature and R is the gas law constant.
Since we have carbon dioxide, CO₂, we need to calculate its molar mass to convert the mass to number of moles:
[tex]\begin{gathered} M_{CO_2}=(1\cdot M_C+2\cdot M_O) \\ M_{CO_2}=(1\cdot12.0107+2\cdot15.9994)g\/mol \\ M_{CO_2}=44.0095g\/mol \end{gathered}[/tex]So, the number of moles is:
[tex]\begin{gathered} M_{CO_2}=\frac{m}{n} \\ n=\frac{m}{M_{CO_{2}}}=\frac{5.4g}{44.0095g\/mol}=0.1227\ldots mol\approx0.12mol \end{gathered}[/tex]Also, we need to convert the temperature to absolute temperature, so we can convert it to K by adding 273.15 to the degree celcius temperature:
[tex]T=32.5\degree C=(32.5+273.15)K=305.65K[/tex]Now, we need to use the constant R that has the unit we want. We have K for temperature, mol for number of moles and L for volume. Is we want the pressure in kPa, we need to use the R constant with units L*kPa/(K*mol), which have the value:
[tex]R\approx8.31446\frac{L\cdot kPa}{K\cdot mol}[/tex]So, solving the equation for P and substituting the values, we have:
[tex]\begin{gathered} PV=nRT \\ P=\frac{nRT}{V} \\ P=\frac{0.12mol\cdot8.31446L\cdot kPa\cdot K^{-1}mol^{-1}\cdot305.65K}{20.0L} \\ P=\frac{0.12\cdot8.31446\cdot305.65}{20.0}kPa \\ P=15.247\ldots kPa\approx15kPa \end{gathered}[/tex]So, the pressure is approximately 15 kPa.
Which of the following is used to find the mass of 3.2 moles of calcium carbonate?
1) Converting grams to moles or moles to grams
In order to do this kind of conversion, we need the molar mass (in grams) of the compound to use it as a conversion factor as follows:
[tex]\frac{molarmassofthecompound_{}}{1molofthecompound_{}}[/tex]-
Calculate the enthalpy of combustion (kJ/mol) of methyl linoleate (C₁₉H₃₄O₂), an important component of many biodiesel fuels made from corn oil and methanol, given the following standard enthalpies of formation: CO₂(g) = -393.5 kJ/mol H₂O(l) = -285.8 kJ/mol C₁₉H₃₄O₂(l) = -645.7 kJ/mol
Answer:
Explanation: 2 C19H34O2(l) + 53 O2(g) ==> 38 CO2(g) + 34 H2O(l) ... balanced equation
∆Hcombustion
∆H = ∑∆Hf products - ∑∆Hf reactants
∆H = [(38 x -393.5) + (34 x -285.8)] - (2 x -645.7) = (-14,953 + -9717) - (-1291)
∆H = -24,670 + 1291
∆H = 25,961 kJ
(be sure to check the math)
-8- A student conducted a number of tests on a solid mixture, X. The inferences made are recorded in Table 2. Complete Table 2 by filling in the observations based on the inferences made. TABLE 2: TESTS ON MIXTURE X Test Observation Inferences (a) Distilled water was added to a portion of X and the resulting mixture stirred and filtered. (The residue was set aside for use later.) The filtrate was divided into 3 equal portions and tests (b) to (d) done on separate portions. Clions are present. (b) Dilute nitric acid followed by a few drops of silver nitrate solution was added. Ammonium hydroxide solution was added to the resulting mixture. An oxidizing agent is present. (c) A few drops of potassium iodide solution were added. Iron(III) ions are present. Aqueous sodium hydroxide was added until in excess. Carbonate ions are present. (e) Dilute nitric acid was added to the residue from test (a) and the gas produced passed through lime water. Total 1 •Pet (3 marks) (2 marks) (2 marks) (3 marks)
Answer:
There would be a change in the color of the potassium iodide from yellowish-brown to colorless
Explanation:
Here, we want to test for the presence of oxidizing agent by the use of potassium iodide
Since we already have the inference, we need to state what would be observed
Potassium iodide itself is a reducing agent
Thus, it becomes oxidized
In the process of being oxidized, there would be a color change
The color change observed will be from yellowish-brown to colorless
Which subatomic particle is positively charged?ProtonNeutronElectronNone
Explanation:
A proton is a positively charged subatomic particle.
A neutron is a neutrally charged subatomic particle.
An electron is a negatively charged subatomic particle.
Answer:
The first option is correct.
A gas occupying 0.6 L at 1.70 atm expands to 0.9 L. What is the new pressure assuming temperature remains constant?
Answer:
1.13 atmExplanation:
The new pressure can be found by using the formula
P1V1 = P2V2
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we're finding the new pressure P2 we make P2 the subject
We have
[tex]p_2 = \frac{p1v1}{v2} \\ [/tex]
P1 = 1.7 atm
V1 = 0.6 L
V2 = 0.9 L
We have
[tex]p_2 = \frac{1.7 \times 0.6}{0.9} = 1.13333...\\ [/tex]
We have the final answer as
1.13 atmHope this helps you
Calculate the frequency of light that has a wavelength of 6.2 * 10^-7 m.
Answer:
4.839 × 10^14 Hz or s^-1
Explanation:
speed of light = wavelength times frequency
frequency = speed of light ÷ wavelength
3.00 x 10^8 = speed of light
3.00 x 10^8 m/s ÷ 6.2 x 10^-7 m = 4.839 × 10^14 Hz or s^-1
socraticorg
What is TRUE about the precipitin test?
A.
It determines if blood is type A, B, or O.
B.
It uses hydrogen peroxide to make a chemical reaction.
C.
It requires a very small amount of blood.
D.
It can only be used on blood that is still wet.
Precipitin test is used to determine antigens and human blood from other sources. It is widely used in forensic laboratories. Thus we can determine the blood groups such as A, B,O etc.
What is precipitin?Precipitin is an antibody which precipitates when other antigens binds with it. Thus, antigens from other source can be easily determined using precipitin reaction.
Precipitin reaction involves a specific serological precipitation of an antigen . Varying amounts of the antigen is added to the serum source where each antigen molecule extensively bound to the antibody excess zone.
A small antibody - antigen complex is formed there with crosslinking reaction. The advantages of this test is that very small amount of test sample is needed and about fifty specimens can be easily tested within few minutes.
Therefore, the precipitin test can used to determine the antigen type of blood A, B or O. Hence, option A is correct.
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Answer: A
Explanation:
Dr. Lamar is performing an autopsy on a murder victim. What is he MOST likely to do during this procedure?
A.
Apply a Hematix strip to the fingertips to collect prints.
B.
Use the Kastle-Meyer test to examine blood samples.
C.
Collect hair samples from multiple places on the body.
D.
Scrape away any dried blood present on the body.
Collecting hair samples from multiple places on the body is most likely to be done during an autopsy.
What is Autopsy?This is referred to as a post-mortem examination which is done on a corpse so as to determine the cause of the sickness and for appropriate actions to be taken.
Hair is easily dispersed as a result of light weight and structure and its ability to easily attach to other substances. The hair will be most likely taken during this procedure, it helps to identify the race and sex of the suspect. It can also be used to identify the suspect through DNA analysis which is therefore the reason why option C was chosen as the correct choice.
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Answer: C
Explanation:
How many grams of H2 are required to completely convert 80g of Fe2O3?
Answer
3.0 grams H₂ is required.Explanation
Given:
Mass of Fe2O3 = 80 g
Equation:
What to find:
The grams of H2 required to completely convert 80g of Fe2O3.
Step-by-step solution:
From the equation of reaction;
3 moles of H2 completely react with 1 mole of Fe2O3
Note: Molar mass of H2 is 2.016 grams per mole and Molar mass of Fe2O3 is 159.69 g/mol
This implies; (3 x 2.016 g) = 6.048 grams H2 completely react with 159.69 grams Fe2O3.
Therefore, x grams H2 will completely convert 80 grams Fe2O3.
Cross multiply and divide both sides by 159.69 grams Fe2O3.
x grams H2 is now equal to
[tex]x=\frac{80\text{ }g\text{ }Fe_2O_3}{159.69\text{ }g\text{ }Fe_2O_3}\times6.048\text{ }g\text{ }H_2=3.0298\approx3.0\text{ }grams\text{ }H_2[/tex]Therefore the grams of H2 required to completely convert 80g of Fe2O3 is 3.0 grams
What is the concentration in molarity of a solution which is 2.91 %m/v benzene (C₆H₆, MM =78.11 g/mol ) in CCl₄ (MM = 153.81 g/mol)?
According to molar concentration,concentration in molarity of the solution is 3.77×10[tex]^-7[/tex] M.
What is molar concentration?Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.
In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.
In the given problem,mass of benzene =2.91 g and molar mass of benzene=78.11 g/mole and volume=100-2.91=97.09 ml or 97.09×10[tex]^-3[/tex] L.
Substituting in the formula,molarity=2.91/78.11×1/97.09×10[tex]^-3[/tex]=3.77×10[tex]^-7[/tex] M.
Hence, the molarity of solution is 3.77×10[tex]^-7[/tex] M.
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What is the total pressure in kPa exerted by a mixture containing two gases if the partial pressure of one gas is 64 kPa and the partial pressure of the other gas is 50.8 kPa?
Dalton's Law or Law of Partial Pressures says that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas that composes it. The partial pressure of a gas on the other hand is defined as the pressure it would exert if it were alone in the container.
So we need to sum all the values:
64 + 50.8 = 114.8 kPa
Answer: 114.8 kPa
In the reaction below, if a total of 10.0 g of zinc and hydrochloric acid react completely, what is the total mass of zinc chloride and hydrogen produced?Zn(s) + 2HCl(aq) to ZnCl2(aq) + H2(g)Exactly 10.0 gLess than 10.0 gNot enough information to tellGreater than 10.0 g
Answer:
Not enough information to tell.
Explanation:
What is given?
Mass of Zn = 10.0 g,
Mass of HCl = 10.0 g,
Molar mass of Zn = 65.4 g/mol,
Molar mass of HCl = 36.4 g/mol,
Molar mass of ZnCl2 = 136.2 g/mol,
Molar mass of H2 = 2 g/mol.
Step-by-step solution:
First, let's convert 10.0 g of each reactant to moles using their respective molar mass:
[tex]\begin{gathered} 10.0\text{ g Zn}\cdot\frac{1\text{ mol Zn}}{65.4\text{ g Zn}}=0.153\text{ moles Zn,} \\ \\ 10.0\text{ g HCl}\cdot\frac{1\text{ mol HCl}}{36.4\text{ g HCl}}=0.275\text{ moles HCl.} \end{gathered}[/tex]Now, let's identify what is the limiting reactant. Let's see how many moles of ZnCl2 can be produced by 0.153 moles of Zn if 1 mol of Zn reacted produces 1 mol of ZnCl2, and how many moles of ZnCl2 can be produced by 0.275 moles of HCl if 2 moles of HCl reacted produces 1 mol of ZnCl2:
[tex]\begin{gathered} 0.153\text{ moles Zn}\cdot\frac{1\text{ mol ZnCl}_2}{1\text{ mol Zn}}=0.153\text{ moles ZnCl}_2, \\ \\ 0.275\text{ moles HCl}\cdot\frac{1\text{ mol ZnCl}_2}{2\text{ moles HCl}}=0.138\text{ moles ZnCl}_2. \end{gathered}[/tex]You can realize that the limiting reactant, in this case, is HCl because is the first reactant consumed first and this reactant 'impose' the limit to produce the products.
So now, let's find how many moles of H2 are being produced by 0.275 moles of HCl if 2 moles of HCl reacted produces 1 mol of H2:
[tex]0.275\text{ moles HCl}\cdot\frac{1\text{ mol H}_2}{2\text{ moles HCl}}=0.138\text{ moles H}_2.[/tex]The final step is to convert each number of moles of each product to grams using their respective molar mass, as follows:
[tex]\begin{gathered} 0.138\text{ moles ZnCl}_2\cdot\frac{136.2\text{ g ZnCl}_2}{1\text{ mol ZnCl}_2}=18.8\text{ g ZnCl}_2, \\ \\ 0.138\text{ moles H}_2\cdot\frac{2\text{ g H}_2}{1\text{ mol H}_2}=0.276\text{ g H}_2. \end{gathered}[/tex]We're producing 18.8 g of zinc chloride (ZnCl2), and 0.276 g of hydrogen (H2), so based on this logic the answer would be not enough information to tell.
If you have 4 cups of flour, 2 sticks of butter, 8 eggs, 4 cups of sugar, 2 cups of milk, and 4 tsp of baking powder, how many cakes can you make?
Based on the mole ratio of the reactants, 2 cakes can be made.
What are limiting reactants?Limiting reactants are the reactants in a chemical reaction that are used up in a reaction.
Limiting reactants are the reactants upon which the reaction depends. Once the limiting reactant is used up, the reaction will stop.
Hence, the amount of product that can be formed from a reaction depends on the limiting reactant.
The limiting reactant of a reaction is obtained from the mole ratio of the reactants in the reaction.
Considering the equation of the reaction of the baking of cake:
2 cups flour + 1 stick butter + 4 eggs + 2 cups sugar + 1 cup milk + 2 tsp. baking powder = 1 cake
The amount of reactants present:
4 cups of flour,2 sticks of butter,8 eggs,4 cups of sugar,2 cups of milk, and4 tsp of baking powderThe amount of the reactants available is twice their mole ratio, hence two cakes can be made.
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