a) y = 3/5x + 11/5
b) y = -5/3x + 9
Explanation:[tex]\begin{gathered} a)\text{ }y\text{ = }\frac{3}{5}x\text{ - 3} \\ \text{compare with equation of line:} \\ y\text{ = mx + b} \\ m\text{ =slope, b = y-intercept} \\ m\text{ =slope = 3/5} \\ b\text{ = -3} \end{gathered}[/tex]For a line to be parallel to another line. the slope of the 1st line will be equalt to the slope of the 2nd line:
slope of 1st line = 3/5
So, the slope of the 2nd line = 3/5
Given point: (3, 4) = (x, y)
To get the y-intercept of the second line, we would insert the slope and the point into the equation of line
[tex]\begin{gathered} y\text{ = mx + b} \\ 4\text{ = }\frac{3}{5}(3)\text{ + b} \\ 4\text{ = 9/5 + b} \\ 4\text{ - }\frac{\text{9}}{5}\text{ = b} \\ \frac{20-9}{5}\text{ = b} \\ b\text{ = 11/5} \end{gathered}[/tex]The equation of line parallel to y = 3/5x - 3:
[tex]\begin{gathered} y\text{ = mx + b} \\ y\text{ = }\frac{3}{5}x\text{ + }\frac{11}{5} \end{gathered}[/tex][tex]b)\text{ line perpendicular to y = 3/5x - 3}[/tex]For a line to be perpendicular to another line, the slope of one will be the negative reciprocal of the second line
Slope of the 1st line = 3/5
reciprocal of 3/5 = 5/3
negative reciprocal = -5/3
slope of the 2nd line (perpendicular) = -5/3
We need to get the y-intercept of the perpendicular line:
[tex]\begin{gathered} \text{given point: (3,4) = (x, y)} \\ y\text{ = mx + b} \\ m\text{ of the perpendicular = -5/3} \\ 4\text{ = }\frac{-5}{3}(3)\text{ + b} \\ 4\text{ = -5 + b} \\ 4\text{ + 5 = b} \\ b\text{ = 9} \end{gathered}[/tex]The equation of line perpendicular to y = 3/5x - 3:
[tex]\begin{gathered} y\text{ = mx + b} \\ y\text{ = }\frac{-5}{3}x\text{ + 9} \end{gathered}[/tex]factor completely5r^3-10r^2+3r-6
You have the following polynomial:
5r³ - 10r² + 3r - 6
In order to factorize the given polynomial, use synthetic division:
5 -10 3 -6 | 2
10 0 6
5 0 3 0
The remainder is zero in the previous division, then, r - 2 is a factor of the given polynomial, the other factor is formed with the coefficients of the division, just as follow:
5r³ - 10r² + 3r - 6 = (r - 2)(5r² + 3)
Hence, the factor are (r - 2)(5r² + 3)
Answer:(r-2) x (5r^2+3)
Step-by-step explanation:
Find the percent markdown. Cost of a pants $36.95, selling price $24.02
Answer:
35%
Explanation:
Given cost of a pant = $36.95 and selling price = $24.02.
Let the markdown percent be y.
To determine the markdown percent, we'll use the below formula;
Sale Price = Original Price x (1 - Markdown% in decimal)
So let's go ahead and substitute the given values into the equation;
[tex]\begin{gathered} 24.02=36.95\ast(1-y) \\ 24.02=36.95-36.95y \\ -12.93=-36.95y \\ y=\frac{-12.93}{-36.95} \\ y=0.35 \\ \therefore y=35percent \end{gathered}[/tex]So the markdown percent is 35%
. Identify the difference. -2-(-6)
In this case,
This difference is made this way:
-2 - (-6) =
-2 +6 = 4
So there we have this identity. The minus before the parentheses turns the minus into plus sign.
The height of a tree is x feet. If it grows ½ times the original height, choose the correct expression that denotes the situation.
ANSWER
1.5(x)
EXPLANATION
The tree is originally x feet tall. If it grows 1/2 this height it means that now it is 1/2x taller, or we can express this as a decimal, 0.5x. If we add these two heights we'll have the new height of the tree:
[tex]x+0.5x=(1+0.5)x=1.5x[/tex]I need to order the numbers least to greatest for the numbers: sq root of 144 234/3 and 68.12
So, the order would be 8.25, 8.832 and 12
You go to the pet store with $25. You decide to buy 2 fish for $3.69 each and fish foos for $4.19. Rounded tanks are $11.48 square-shaped tanks are $14.89. Estimate your total cost to find which tank you can can buy. About how much money will you have left?
Answer: you will only have enough money for the rounded tank, after buying everything you will have 9 cents left
Step-by-step explanation: two $3.69 fish, $4.19 fish food. 2x3.69=7.38+4.19=11.57
25-11.57=13.43
13.43+11.48=24.91
25-24.91=0.09
3x - 4y = 65x + 8y = -1
CS 18 and 105 calories in each juice box The rules for two horseback riding packages are shown below. Go Galloping Horseback Rides $6 equipment fee plus S10 per hous hours horseback riding and let yepresent the total cost of the package. Write a system of equations to represent this situation let x represent the number of Lucky Horseshoe Stables $12 equipment fee plus hour 259 Calories What is the solution to the system of equations? What does the solution represent?
8A) Let x represent the number of hours of horseback riding.
Let y represent the total cost of the package
If Lucky horseshoe stables is used for x hours, the equation for the total cost would be
y = 7x + 12
If Go galloping horseshoe rides is used for x hours, the equation for the total cost would be
y = 10x + 6
Thus, the equations are
y = 7x + 12
y = 10x + 6
B) To solve the system of equations, we would substitute the first equation into the second equation. It becomes
7x + 12 = 10x + 6
10x - 7x = 12 - 6
3x = 6
x = 6/3
x = 2
y = 7x + 12 = 7 * 2 + 12
y = 14 + 12
y = 26
The solution of the system of equations is (2, 26)
All lines that cross the x-axis are vertical lines.A. TrueB. False
Given:
All lines that cross the x-axis are vertical line.
Required:
To find whether the given statement is true or false.
Explanation:
A vertical line is one the goes straight up and down, parallel to the y-axis of the coordinate plane.
The x-intercept is the point at which the graph crosses the x-axis.
Here all lines are not vertical lines.
Therefore the given statement is false.
Final answer:
False.
the length of a rectangle is 2 inches more than the width. The area is 24 square inches. Find the dimensions
Given:
length(l) = width(w) + 2
[tex]\text{Area}=24[/tex][tex]l\times w=24[/tex][tex](w+2)w=24[/tex][tex]w^2+2w-24=0[/tex][tex](w+6)(w-4)=0[/tex][tex]w=4\text{ or -6}[/tex]Negative not possible.
[tex]\text{width(w)}=4\text{ inches}[/tex][tex]\text{length(l)}=w+2[/tex][tex]\text{length of the rectangle=4+2}[/tex][tex]\text{length of the rectangle=}6\operatorname{cm}[/tex]Given that angle A lies in Quadrant IV and cos(A)= 7/10, evaluate sin(A).
The value of the trigonometric function is; sin(A) =√51/10.
What are trigonometric identities?Trigonometric identities are the functions that include trigonometric functions such as sine, cosine, tangents, secant, and, cot.
We have been given that angle A lies in Quadrant IV and cos(A)= 7/10 then;
cos(A)= 7/10
Hence, base = 7
hypotenuse = 10
Therefore, perpendicular
h² = b² + p²
10² = 7² + p²
100 = 49 + p²
p = √51
Then sin(A = perpedicular/ hypotenuse
sin(A) = √51/10
Hence, the value of the trigonometric function is; sin(A) =√51/10.
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what is the length of the dominant line in the time graph below? l leave your answer in simplest radical form.
Let's first calculate the lenght of the side of the rectangle.
[tex]l=\sqrt[]{8^2+5^2}=\sqrt[]{64+25}=\sqrt[]{89}[/tex]so we get that the dotted line is:
[tex]d=\sqrt[]{2^2+89}=\sqrt[]{93}[/tex]so the answer is square root of 93
4) Math Club members want to advertise their fundraiser each week in the school paper. They knowthat a front-page ad is more effective than an ad inside the paper. They have a $30 advertisingbudget. It cost $2 for each front-page ad and $1 for each inside page ad. The club wants to advertiseat least 20 times. a) Write and graph a system of inequalities to model the number of advertisements the club canpurchase to stay under budget. Be sure to label all parts of your graph.b) State one solution that would work. How much money will remain in the club's budget?
Problem:
Math Club members want to advertise their fundraiser each week in the school paper. They know that a front-page ad is more effective than an ad inside the paper. They have a $30 advertising budget. It cost $2 for each front-page ad and $1 for each inside page ad. The club wants to advertise at least 20 times.
a) Write and graph a system of inequalities to model the number of advertisements the club can purchase to stay under budget. Be sure to label all parts of your graph.
Solution:
Let us denote the number of front-page ads by x, and the number of inside ads by y:
x = number front-page ads
y= number of inside ads
Now, because they have a $30 advertising budget and It cost $2 for each front-page ad and $1 for each inside page ad, the first inequality that we have is:
[tex]2x+\text{ y }\leq30[/tex]If we represent the graph of the equality (line) 2x+y = 30, we have:
On the other hand, because the club wants to advertise at least 20 times, the second inequality that we have is:
[tex]x+y\ge20[/tex]If we represent the graph of the equality (line) x+y = 20, we have:
Now, the intersection point of the above lines, that is 2x+y = 30 and x+y = 20 is found as follows:
we have
y = 30 - 2x
and
y = 20-x
then
30-2x = 20-x
and
30-20 = 2x-x
that is
10 = x
when x = 10 then y = 20-x = 20-10 = 10
Select three equations that could represent a step in solving this system using the substitution method. 4x+y = 6 x = 8 0.00 0:52 9 1x 2 4(8)+y=6 o y = 18
the first step is replacing x=8 on the first equation, so
[tex]4(8)+y=6[/tex]the second step is do the multiplication
[tex]\begin{gathered} 32+y=6 \\ y+32=6 \end{gathered}[/tex]and the last step is place the 32 on the other side substracting
[tex]\begin{gathered} y=6-32 \\ y=-26 \end{gathered}[/tex]express the fuction graphed on the axes below as a piecewise function
Concept
Find the equation of line for the second line.
x1 = -2 y1 = 1
x2 = -4 y2 = 2
Next, apply equation of a line formula
[tex]\begin{gathered} \frac{y-y_1}{x-x_1\text{ }}\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ \frac{y\text{ - 1}}{x\text{ + 2}}\text{ = }\frac{2\text{ - 1}}{-4\text{ + 2}} \\ \frac{y\text{ - 1}}{x\text{ + 2}}\text{ = }\frac{1}{-2} \\ -2(y\text{ - 1) = 1(x + 2)} \\ -2y\text{ + 2 = x + 2} \\ -2y\text{ = x} \\ y\text{ = }\frac{-1}{2}x \end{gathered}[/tex]Final answer
The graphed as a piecewise function is given below
I need help with this practice problem Having a tough time solving properly
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
r = 7 sin (2θ)
Step 02:
polar equation:
r = 7 sin (2θ):
r = a sin nθ
n odd ==> n petals
n even ===> 2n petals
n = 2 ===> 2*2 petals = 4 petals
graph:
length of the petals:
r = 7 sin (2θ)
θ = 45°
r = 7 sin (2*45°) = 4.95
The answer is:
4.95
A game fair requires that you draw a queen from a deck of 52 ards to win. The cards are put back into the deck after each draw, and the deck is shuffled. That is the probability that it takes you less than four turns to win?
The probability (P) is winning in less than four turns can be decomposed as the following sum:
The probability of winning in one turn is
[tex]P(\text{Winning in turn 1})=\frac{\#Queens}{\#Cards}=\frac{4}{52}.[/tex]The probability of winning in the second turn is
[tex]\begin{gathered} P(\text{ Winning in the second turn})=P(\text{ Lossing (in turn 1)})\cdot P(\text{ Winning (in turn 2)}), \\ \\ P(\text{ Winning in the second turn})=\frac{\#NoQueens}{\#Cards}\cdot\frac{\#Queens}{\#Cards}, \\ \\ P(\text{ Winning in the second turn})=\frac{48}{52}\cdot\frac{4}{52}\text{.} \end{gathered}[/tex]The probability of winning in the third turn is
[tex]\begin{gathered} P(\text{ Winning in the third turn})=P(\text{ Lossing (in turn 1)})\cdot P(\text{ Lossing (in turn 2)})\cdot P(\text{ winning (in turn 3)}), \\ \\ P(\text{ Winning in the third turn})=\frac{\#NoQueens}{\#Cards}\cdot\frac{\#NoQueens}{\#Cards}\cdot\frac{\#Queens}{\#Cards}, \\ \\ P(\text{ Winning in the third turn})=\frac{48}{52}\cdot\frac{48}{52}\cdot\frac{4}{52}\text{.} \end{gathered}[/tex]Adding all together, we get
[tex]\begin{gathered} P(\text{ Winning in less than four turns})=\frac{4}{52}+\frac{48}{52}\cdot\frac{4}{52}+\frac{48}{52}\cdot\frac{48}{52}\cdot\frac{4}{52}, \\ \\ P(\text{ Winning in less than four turns})=\frac{469}{2197}, \\ \\ P(\text{ Winning in less than four turns})\approx0.2135, \\ \\ P(\text{ Winning in less than four turns})\approx21.35\% \end{gathered}[/tex]AnswerThe probability of winning in less than four turns is (approximately) 21.35%.
Which function rule would help you find the values in the table?J K2 -124 -246 -368 -48A k=-12jB k=-6jC k=j - 12D k=j - 6
Solution
As seen from the table
For each values of the table
We define the variation from K to J
[tex]\begin{gathered} K\propto J \\ K=cJ\text{ (where c is constant of proportionality)} \end{gathered}[/tex]When J = 2, K = -12
[tex]\begin{gathered} K=cJ \\ -12=c(2) \\ 2c=-12 \\ c=-\frac{12}{2} \\ c=-6 \end{gathered}[/tex]Therefore, the formula connecting them will be
[tex]k=-6j[/tex]Option B
the perimeter of a rectangle is a rational number. the length of a rectangle is 6 units. the width of a rectangle must be a/an rational/irrational (circle one) number.
A rational number
Explanations:The perimeter of a rectangle is given by the formula:
Perimeter = 2(Length + Width)
The Length = 6 units
Perimeter = 2 (6 + Width)
Perimeter = 12 - 2 Width
2 Width = 12 - Perimeter
Width = (12 - Perimeter)/2
Note that a rational number is a number that can be written as a fraction of two integers.
Since the perimeter is said to be a rational number, any rational number substituted into the formula equation for the width above will give a rational number.
The width of the rectangle is therefore a rational number
without dividing, how can you tell which quotient is smaller, 30:5 or 30:6 ? eXPLAIN
Without dividing, we can tell that 30:6 has smaller quotient between 30:5 and 30:6.
According to the question,
We have the following two expressions:
30:5 and 30:6
Now, we can easily find which expression has a smaller quotient when the dividend is the same. We need to look at the divisor. If the dividend is the same then the quotient will be smaller for the one with the greater divisor.
In this case, 30:6 has a greater divisor than 30:5 (6 is larger than 5). So, it will have smaller quotient.
Now, we can prove this by dividing both the expressions.
30/6 = 5
(So, it has smaller quotient.)
30/5 = 6
Hence, 30:6 has smaller quotient than 30:5.
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I need help on thisChange the equation into a equivalent equation written in the Slope-intercept form. x -7y + 5 =0
The slope-intercept form is an equation as follows:
[tex]y=mx+b[/tex]Then, we need to change the original equation in this equivalent:
[tex]-7y=-5-x\Rightarrow-7y=-x-5\Rightarrow7y=x+5[/tex]Dividing the total equation by 7, we have:
[tex]\frac{7}{7}y=\frac{x}{7}+\frac{5}{7}\Rightarrow y=\frac{1}{7}x+\frac{5}{7}[/tex]Therefore, the slope-intercept form is:
[tex]y=\frac{1}{7}x+\frac{5}{7}[/tex]Describe and justify the methods you used to solve the quadratic equations in parts A and B.
We know that give any pair of real numbers A and B, the following statement will be true:
[tex]A\cdot B=0[/tex]if, and only if
[tex]\begin{gathered} A=0 \\ or \\ B=0 \end{gathered}[/tex]Now, if we factor a quadratic equation into two factors A and B, and use the fact we've just mentioned, we can then equal each factor to zero, solve for x and get the solutions to said quadratic equation.
Sydney is making bracelets, 3 bracelets require 21 beads. The number of braclets varies directly with the number of beads.
Write an equation in the form of y = ax then find the amount o
beads needed for 32 bracelets.
Step-by-step explanation:
"varies DIRECTLY with" means there is an y = ax relationship.
y = number of bracelets
x = number of beads
3 = a×21
a = 3/21 = 1/7
now, when we have 32 bracelets
32 = 1/7 × x
32×7 = x = 224
224 beads are needed for 32 bracelets.
Solve the following system of linear equations using elimination.
x – y - 3z = 4
2x + 3y – 3z = -2
x + 3y – 2z = -4
By applying the elimination method, the solutions to this system of three linear equations include the following:
x = 2.y = -2.z = 0.How to solve these system of linear equations?In order to determine the solutions to a system of three linear equations, we would have to evaluate and eliminate each of the variables one after the other, especially by selecting a pair of linear equations at each step and then applying the elimination method.
Given the following system of linear equations:
x – y - 3z = 4 .........equation 1.
2x + 3y – 3z = -2 .........equation 2.
x + 3y – 2z = -4 .........equation 3.
From equation 1 and equation 3, we would eliminate x as follows:
x – y - 3z = 4
x + 3y – 2z = -4
-4y - z = 8 .........equation 4.
Next, we would pick a different pair of linear equations to eliminate x:
(x – y - 3z = 4) × 2 ⇒ 2x - 2y - 6z = 8
2x - 2y - 6z = 8
2x + 3y - 3z = -2
-5y - 3z = 10 ........equation 5.
From equation 4 and equation 5, we would eliminate z to get the value of y:
(-4y - z = 8) × 3 ⇒ -12y - 3z = 24
-12y - 3z = 24
-5y - 3z = 10
-7y = 14
y = 14/7
y = -2.
For the value of z, we have:
-4y - z = 8
z = -4y - 8
z = -4(-2) - 8
z = 8 - 8
z = 0
For the value of x, we have:
x – y - 3z = 4
x = 4 + y + 3z
x = 4 - 2 + 3(0)
x = 2
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A baker need 2/3 cup of sugar,but he can only find a 1/2 cup measure,so he decides to estimate, Which of the following would result in the correct amount of sugar?A)One Full scoop plus 1/3 of a scoopB)One Full scoop plus 1/2 of a scoop C) Two ScoopsD)3/4 of a scoop
He needs 2/3 cup of sugar . But he can only find 1/2 cup measures.
Can someone explain how I would know the difference between a 2:7 ratio and 7:2 ratio when a point partitions the line? Thank you!
Solution
For this case we can do the following:
We can understand 7/2 as the reciprocal of 2/7 and we can create the following diagram
Write an expression for the sequence of operations described below.1)) multiply 7 by 8, then divide f by the resultDo not simplify any part of the expression.Submit
We need to write an expression for the operations:
[tex]\begin{gathered} \text{ multiply 7 by 8} \\ \\ \text{dived f by the result} \end{gathered}[/tex]The first operation (multiplication) can be represented as:
[tex]7\cdot8[/tex]The second operation (the division of f by the previous result) can be represented as:
[tex]f\div(7\cdot8)[/tex]Notice that we need the parenthesis to indicate that the product is the first operation to be done.
Answer:
[tex]f\div(7\cdot8)[/tex]For what values of b will F(x) = logb x be a decreasing function?A.0 < b < 1B.0 > b > -1C.b > 0D.b < 0
Given:
There is a function given as below
[tex]F(x)=\log_bx[/tex]Required:
For what value of b the given function in decreasing
Explanation:
The given function is logarithm function
also written as
[tex]F(x)=\frac{log\text{ x}}{log\text{ b}}[/tex]The base b is determines that if the function is increasing or decreasing
here
for
[tex]0the given function is decreasingfor
[tex]b>1[/tex]the given function is increasing
Final answer:
[tex]0
What was the initial population at time t=0?Find the size of the bacterial population after 4 hours.
Answer;
[tex]\begin{gathered} a)\text{ 195 bacteria} \\ b)\text{ 3,291,055,916 bacteria} \end{gathered}[/tex]Explanation;
a) We want to get the initial population of the bacteria
We start by writing a formula that links the initial bacteria population to a later bacteria population after time t
[tex]A(t)=I(1+r)^t[/tex]where A(t) is the bacteria population at time t
I is the initial bacteria population
r is the rate of increase in population
t is time
Now, let us find r
At t = 10; we know that A(t) = 2I
Thus, we have it that;
[tex]\begin{gathered} 2I=I(1+r)^{10} \\ (1+r)^{10}\text{ = 2} \\ 1+r\text{ = 1.0718} \\ r\text{ = 1.0718-1} \\ r\text{ = 0.0718} \end{gathered}[/tex]Now, let us find I, since we have r. But we have to make use of t= 80 and A(t) = 50,000
Thus, we have;
[tex]\begin{gathered} 50,000=I(1+0.0718)^{80} \\ I\text{ = }\frac{50,000}{(1+0.0718)^{80}} \\ I\text{ = 195} \end{gathered}[/tex]The initial population is 195 bacteria
b) For after 4 hours, we have to convert to minutes
We know that there are 60 minutes in an hour
So, in 4 hours, we have 4 * 60 = 240 minutes
Now, we proceed to use the formula above with I = 195 and t = 240
We have that as;
[tex]\begin{gathered} A(240)=195(1+0.0718)^{240} \\ A(240)\text{ = 3,291,055,916 bacteria} \end{gathered}[/tex]Can you help me with #7? X^3-2x^2+3x-6 = 0Please follow prompt b
Given:
The polynomial is given as,
[tex]x^3-2x^2+3x-6=0[/tex]The objective is to factor the polynomial completely.
Explanation:
Consider x = 2 in the given equation.
[tex]\begin{gathered} f(2)=2^3-2(2)^2+3(2)-6 \\ =8-8+6-6 \\ =0 \end{gathered}[/tex]Thus, (x -2) is a factor of the polynomial.
Now, using synthetic division,
Thus, the polynomial equation will be,
[tex]x^2+3=0\text{ . . . . .(1)}[/tex]On factorizing the equation (1),
[tex]\begin{gathered} x^2=-3 \\ x=\pm\sqrt[]{-3} \\ x=\pm i\sqrt[]{3} \\ x=i\sqrt[]{3},-i\sqrt[]{3} \end{gathered}[/tex]Hence, the factors of the polynomial are (x-2), (x+i√3), (x-i√3).
