Construct a scatterplot and identify the mathematical model that best fits the data. Assume that the model is to be used only for the scope of the given data and consider only linear, quadratic, logarithmic, exponential, and power models. Use a calculator or computer to obtain the regression equation of the model that best fits the data. You may need to fit several models and compare the values of R2.Average sunset times are taken for six months across the summer. Giving the months April through September values 1 through 6, find the regression equation of the best model.y = –0.357x2 + 2.17x + 17.87y = 21.24 e0.983xy = 21.20 – 0.343xy = 20.62x–0.029
Answers
We will have the following:
From the options given we graph each possible solution with the data, that is:
In order:
From this, we can see that the function that best fits the data is:
[tex]y=-0.357x^2+2.17x+17.87[/tex]
Related Questions
I inserted a picture of the question Check all that apply
Answers
Recall that the line equation is of the form
[tex]y=mx+c\ldots\ldots\text{.}(1)[/tex]The points lie in the line are (2,5) and (-2,-5).
Setting x=2 and y=5 in the equa
A genetic experiment with
peas resulted in one sample of offspring that consisted of 447 green peas and 169 yellow peas.
a. Construct a 90% confidence interval to estimate of the percentage of yellow peas.
b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow?
a. Construct a 90% confidence interval. Express the percentages in decimal form.
L s p< (Round to three decimal places as needed.)
b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow?
O
No, the confidence interval includes 0.25, so the true percentage could easily equal 25%
L
O Yes, the confidence interval does not include 0.25, SO the true percentage could not equal 25%
Answers
Using the z-distribution, it is found that:
a. The 90% confidence interval to estimate of the percentage of yellow peas is: (34.04%, 41.58%).
b. The correct option is: Yes, the confidence interval does not include 0.25, so the true percentage could not equal 25%.
What is a confidence interval of proportions?The bounds of a confidence interval of proportions is given according to the equation presented as follows:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which the parameters are described as follows:
[tex]\pi[/tex] is the sample proportion.z is the critical value of the distribution.n is the sample size, from which the estimate was builtThe confidence level is of 90%, hence the critical value is z = 1.645, using a z-distribution calculator.
The values of the sample size and of the estimate are given as follows:
[tex]n = 447, \pi = \frac{169}{447} = 0.3781[/tex]
Hence the lower bound of the interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3781 - 1.645\sqrt{\frac{0.3781(0.6219)}{447}} = 0.3404[/tex]
The upper bound is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3781 + 1.645\sqrt{\frac{0.3781(0.6219)}{447}} = 0.4158[/tex]
As a percentage, the interval is given as follows: (34.04%, 41.58%).
The confidence interval does not contain 0.25, hence the true percentage would not be equal to 25%, contradicting the expectation.
A similar problem, also involving the z-distribution, is given at https://brainly.com/question/25890103
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Please help me with my calc hw, I'd be more than happy to chip in albeit with my limited knowledge.
Answers
Given:
[tex]F(x)=\int_0^x\sqrt{36-t^2}dt[/tex]Required:
To find the range of the given function.
Explanation:
The graph of the function
[tex]y=\sqrt{36-t^2}[/tex]is upper semicircle with center (0,0) and radius 6, with
[tex]-6\leq t\leq6[/tex]So,
[tex]\int_0^x\sqrt{36-t^2}dt[/tex]is the area of the portion of the right half of the semicircle that lies between
t=0 and t=x.
When x=0, the value of the integral is also 0.
When x=6, the value of the integral is the area of the quarter circle, which is
[tex]\frac{36\pi}{4}=9\pi[/tex]Therefore, the range is
[tex][0,9\pi][/tex]Final Answer:
The range of the function is,
[tex][0,9\pi][/tex]Carlos is saving money to buy a new Nintendo Switch game. He has $25. After he receives his allowance (n), he will have $45. Which of the following equations models this situation?
Answers
ANSWER
25 + n = 45
EXPLANATION
We have that Carlos already has $25.
His allowance is n. After receiving it, he now has $45.
This means that if we add the amount he had and his allowance, we will have $45.
Therefore:
25 + n = 45
This equation models the situation accurately.
question 5 only. determine the missing side length QP. the triangles are not drawn to scale.
Answers
This is a simple question.
First, we can see both triangles are proportional, it means it has the same relation between its sides even if one is in a large scale and the other on a a small scale.
Now we can identify which side corresponds to which side. Once side AC is the longest one for triangle ABC it means its equivalent for triangle PQR is the side RP, so the equivalent for side AB is side QP. Once we know that we can write the following relation and calculate:
Graph the line y = -4 on the graph below.
Answers
we have the equation
y=-4
This is a horizontal line (parallel to the x-axis) that passes through the point (0,-4)
see the graph below to better understand the problem
using first principles to find derivatives grade 12 calculus help image attached much appreciated
Answers
Given: The function below
[tex]y=\frac{x^2}{x-1}[/tex]To Determine: If the function as a aximum or a minimum using the first principle
Solution
Let us determine the first derivative of the given function using the first principle
[tex]\begin{gathered} let \\ y=f(x) \end{gathered}[/tex]So,
[tex]f(x)=\frac{x^2}{x-1}[/tex][tex]\lim_{h\to0}f^{\prime}(x)=\frac{f(x+h)-f(x)}{h}[/tex][tex]\begin{gathered} f(x+h)=\frac{(x+h)^2}{x+h-1} \\ f(x+h)=\frac{x^2+2xh+h^2}{x+h-1} \end{gathered}[/tex][tex]\begin{gathered} f(x+h)-f(x)=\frac{x^2+2xh+h^2}{x+h-1}-\frac{x^2}{x-1} \\ Lcm=(x+h-1)(x-1) \\ f(x+h)-f(x)=\frac{(x-1)(x^2+2xh+h^2)-x^2(x+h-1)}{(x+h-1)(x-1)} \end{gathered}[/tex][tex]\begin{gathered} f(x+h)-f(x)=\frac{x^3+2x^2h+xh^2-x^2-2xh-h^2-x^3-x^2h+x^2}{(x+h-1)(x-1)} \\ f(x+h)-f(x)=\frac{x^3-x^3+2x^2h-x^2h-x^2+x^2+xh^2-2xh-h^2}{(x+h-1)(x-1)} \\ f(x+h)-f(x)=\frac{x^2h+xh^2-2xh+h^2}{(x+h-1)(x-1)} \end{gathered}[/tex][tex]\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{x^{2}h+xh^{2}-2xh+h^{2}}{(x+h-1)(x-1)}\div h \\ \frac{f(x+h)-f(x)}{h}=\frac{x^2h+xh^2-2xh+h^2}{(x+h-1)(x-1)}\times\frac{1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{h(x^2+xh^-2x+h^)}{(x+h-1)(x-1)}\times\frac{1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{x^2+xh-2x+h}{(x+h-1)(x-1)} \end{gathered}[/tex]So
[tex]\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=\frac{x^2-2x}{(x-1)(x-1)}=\frac{x(x-2)}{(x-1)^2}[/tex]Therefore,
[tex]f^{\prime}(x)=\frac{x(x-2)}{(x-1)^2}[/tex]Please note that at critical point the first derivative is equal to zero
Therefore
[tex]\begin{gathered} f^{\prime}(x)=0 \\ \frac{x(x-2)}{(x-1)^2}=0 \\ x(x-2)=0 \\ x=0 \\ OR \\ x-2=0 \\ x=2 \end{gathered}[/tex]At critical point the range of value of x is 0 and 2
Let us test the points around critical points
[tex]\begin{gathered} f^{\prime}(x)=\frac{x(x-2)}{(x-1)^2} \\ f^{\prime}(0)=\frac{0(0-2)}{(0-1)^2} \\ f^{\prime}(0)=\frac{0(-2)}{(-1)^2}=\frac{0}{1}=0 \\ f^{\prime}(2)=\frac{2(2-2)}{(2-1)^2}=\frac{2(0)}{1^2}=\frac{0}{1}=0 \end{gathered}[/tex][tex]\begin{gathered} f(0)=\frac{x^2}{x-1}=\frac{0^2}{0-1}=\frac{0}{-1}=0 \\ f(2)=\frac{2^2}{2-1}=\frac{4}{1}=4 \end{gathered}[/tex]The function given has both maximum and minimum point
Hence, the maximum point is (0,0)
And the minimum point is (2, 4)
Use a system of equations to solve the following problem.The sum of three integers is380. The sum of the first and second integers exceeds the third by74. The third integer is62 less than the first. Find the three integers.
Answers
the three integers are 215, 12 and 153
Explanation:
Let the three integers = x, y, and z
x + y + z = 380 ....equation 1
The sum of the first and second integers exceeds the third by 74:
x + y - 74 = z
x + y - z = 74 ....equation 2
The third integer is 62 less than the first:
x - 62 = z ...equation 3
subtract equation 2 from 1:
x -x + y - y + z - (-z) = 380 - 74
0 + 0 + z+ z = 306
2z = 306
z = 306/2
z = 153
Insert the value of z in equation 3:
x - 62 = 153
x = 153 + 62
x = 215
Insert the value of x and z in equation 1:
215 + y + 153 = 380
368 + y = 380
y = 380 - 368
y = 12
Hence, the three integers are 215, 12 and 153
I need help with this question please help me asap?
Answers
Answer
Explanation
• Range (R): the amount between the upper and lower limit.
[tex]f(x) = \sqrt{ {x }^{2} - 121} [/tex]what's the inverse of this equation
Answers
EXPLANATION:
The first thing to do in the equation is to interchange the variables in order to do the inverse function and thus solve the equation correctly.
So the equation is as follows:
[tex]\begin{gathered} x=\sqrt[]{x^2-121} \\ Now\text{ we exchange }the\text{ variables x and y;} \\ x=\sqrt[]{y^2-121} \\ y=\sqrt[]{x^2+121};\text{ y}=-\sqrt[]{x^2+121} \\ \sqrt[]{x^2+121\text{ ; }-\sqrt[]{x^2+121}} \\ \text{the answer is : }\sqrt[]{x^2+121\text{ },\text{ }}\text{ }-\sqrt[]{x^2+121^{}} \end{gathered}[/tex]What is the slope of a line perpendicular to the line whose equation is15x + 12y = -108. Fully reduce your answer.Answer:Submit Answer
Answers
GIven:
The equation of a line is 15x+12y=-108.
The objective is to find the slope of the perpencidular line.
It is known that the equation of straight line is,
[tex]y=mx+c[/tex]Here, m represents the slope of the equation and c represents the y intercept of the equation.
Let's find the slope of the given equation by rearranging the eqation.
[tex]\begin{gathered} 15x+12y=-108 \\ 12y=-108-15x \\ y=-\frac{15x}{12}-\frac{108}{12} \\ y=-\frac{5}{4}x-9 \end{gathered}[/tex]By comparing the obtained equation with equation of striaght line, the value of slope is,
[tex]m_1=-\frac{5}{4}[/tex]THe relationship between slopes of a perpendicular lines is,
[tex]\begin{gathered} m_1\cdot m_2=-1 \\ -\frac{5}{4}\cdot m_2=-1 \\ m_2=-1\cdot(-\frac{4}{5}) \\ m_2=\frac{4}{5}^{} \end{gathered}[/tex]Hence, the value of slope of perpendicular line to the given line is 4/5.
1 litre=1000cm³. About how many test tubes, each holding 24cm³ of water, can be filled from a
1 litre flask?
Answers
Answer: 125/3 or about 41.667
Note that you can't have 2/3 of a test tube, so the expected answer may be 42 test tubes.
Step-by-step explanation:
Write a simple algebra equation using the word problem
24x = 1000
x represents the number of test-tubes, each of which hold 24cm^3 of water.
divide both sides by 24
x = 125/3 or about 41.667
1/4×3/2×8/9 whats the answer?
Answers
Multiply the given fractions to find the answer, use the given example:
Now, solve the given multiplication:
[tex]\frac{1}{4}\cdot\frac{3}{2}\cdot\frac{8}{9}=\frac{1\cdot3\cdot8}{4\cdot2\cdot9}=\frac{24}{72}=\frac{1}{3}[/tex]The answer is 1/3.
The width of a rectangle is [tex] \frac{3}{4} [/tex] its length. The perimeter of the rectangle is 420 ft. What is the length, in feet, of the rectangle?
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The width of a rectangle is 3/4 its length.
[tex]w=\frac{3}{4}l[/tex]The perimeter of the rectangle is 420 ft.
Recall that the perimeter of a rectangle is given by
[tex]P=2(w+l)[/tex]Let us substitute the value of the given perimeter and the width
[tex]\begin{gathered} P=2(w+l) \\ 420=2(\frac{3}{4}l+l) \end{gathered}[/tex]Now simplify and solve for length
[tex]\begin{gathered} 420=2(\frac{3}{4}l+l) \\ 420=\frac{3}{2}l+2l \\ 420=3.5l \\ l=\frac{420}{3.5} \\ l=120\: ft \end{gathered}[/tex]Therefore, the length of the rectangle is 120 feet.
Slope =
y-intercept = (0,
Answers
Answer:
y intercept= (0,-3)
slope= 2/1 or simplified 2
Step-by-step explanation:
the stock market lost 231 points on Tuesday then walks 128 more points on Wednesday find a change of points over the two days
Answers
the change of the points is:
[tex]-231-128=-359[/tex]so in the 2 days the stock market lost 359 points
5. Kara earns a 3.5% commission on all sales made by recommendations to the hair salon. If the total amount of sales from referrals by Karo was $3,670, how much did Kara make?
Answers
Let's begin by listing out the information given to us:
Commission (C) = 3.5% = 0.035
Total amount of sales (T) = $3,670
To determine how much Kara made, we will find the product of the commission & total amount of sales:
[tex]\begin{gathered} Kara(K)=Commission(C)\cdot TotalAmountOfSales(T) \\ K=C\cdot T=0.035\cdot3670=128.45 \\ K=128.45 \end{gathered}[/tex]We therefore, see that Kara made $128.45 from referrals
What does slope mean?
Answers
Slope is a measure of its steepness
Mathematically,
Slope = Rise / Run
Rise = y2 - y1
Run = x2 - x1
Slope = y2 - y1 / x2 - x1
Answer:
Suppose a linear equation describes something (say, population growth). The slope is the rate (say, of growth) and the y-intercept gives the starting value.
Step-by-step explanation:
If the expression 1/ square root of x was placed in form x^a, then which of the following would be the value of a?
Answers
4) -1/2
1) Rewriting the expression:
[tex]\frac{1}{\sqrt[]{x}}[/tex]2) As a power we can write this way, considering that we can rewrite any radical as a power and that when we have a radical on the denominator we can rewrite it as a negative rational exponent. So we can write it out:
[tex]\frac{1}{\sqrt[]{x}}=\frac{1}{x^{\frac{1}{2}}}=x^{-\frac{1}{2}}[/tex]3) Hence, the answer is 4) -1/2
Find the area of this trapezoid. Be sure to include the correct un4 cm6 cm4 cm15 cm
Answers
So,
Here we have the following trapezoid:
Remember that the area of a trapezoid can be found if we apply the following formula:
[tex]A=\frac{1}{2}(\text{base}1+\text{base}2)\cdot\text{height}[/tex]Where bases 1 and 2 are the greater and smaller bases respectively.
So, if we replace:
[tex]\begin{gathered} A=\frac{1}{2}(15+4)\cdot4 \\ A=\frac{1}{2}(19)\cdot4 \\ A=9.5\cdot4 \\ A=38 \end{gathered}[/tex]So the area is 38cm^2.
Solve the system using the elimination method:2x - y + z = -26x + 3y - 4z = 8-3x + 2y + 3z = -6
Answers
multiply 2x - y + z = - 2 for 3
[tex]6x-3y+3z=-6[/tex]then sunstract the equation 1 and 2
[tex]\begin{gathered} 6x+3y-4z=8 \\ 6x-3y+3z=-6 \\ 6y-7z=14 \end{gathered}[/tex]multiply -3x+2y+3z=-6 for 2
[tex]-6x+4y+6z=-12[/tex]adding
[tex]\begin{gathered} -6x+4y+6z=-12 \\ \underline{6x-3y+3z=-6} \\ y+9z=-18 \end{gathered}[/tex]multiply y+9z=-18 for 6
[tex]6y+54z=-108[/tex]Subtracting
[tex]\begin{gathered} 6y+54z=-108 \\ \underline{6y-7z=14} \\ 61z=-122 \end{gathered}[/tex]then solve
[tex]\begin{gathered} 61z=-122 \\ \frac{61z}{61}=\frac{-122}{61} \\ z=-2 \end{gathered}[/tex][tex]\begin{gathered} 6y-7\mleft(-2\mright)=14 \\ 6y+14=14 \\ 6y+14-14=14-14 \\ 6y=0 \\ y=0 \end{gathered}[/tex][tex]\begin{gathered} 6x-3\cdot\: 0+3\mleft(-2\mright)=-6 \\ 6x-6=-6 \\ 6x-6+6=-6+6 \\ 6x=0 \\ x=0 \end{gathered}[/tex]answer is: x = 0, y = 0 and z = - 2
The answer to
√19
lies between two consecutive integers.
Use your knowledge of square numbers to state which
two integers it lies between.
√19 is between
and
Answers
The most appropriate choice for square root will be[tex]\sqrt{19}[/tex] lies between 4 and 5
What is square root of a number?
A number's square root is a value that, when multiplied by itself, yields the original number. The opposite way to square a number is to find its square root. Squares and square roots are therefore related ideas. Assuming that x is the square root of y, the equation would be written as x=y or as x2 = y. The radical symbol for the number's root is "" in this instance. When multiplied by itself, the positive number represents the square of the original number. The original number is obtained by taking the square root of a square of a real integer. For instance, the square of 3 is 9, the square root of 9 is 9, and 9 squared equals 3. Finding the square root of 9 is simple because it is a perfect square.
[tex]\sqrt{p} = p^{\frac{1}{2}}[/tex]
[tex]\sqrt{19} = 4.36\\[/tex]
4.36 lies between 4 and 5
[tex]\sqrt{19}[/tex] lies between 4 and 5
To learn more about square root of a number, refer to the link-
https://brainly.com/question/3617398
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Iq scores were gathered for group of college students at a local university. What is the level of measurement of dataNominal, ordinal, interval, ratio
Answers
Nominal data refers to non numerical data, for example categories, colors, etc...
Ordinal data refers to numerical data with a natural order, it comprehends real numbers.
Intervals comprehends data with equal distance between the values and no meaningful zero
Ratios comprehends data with equal distance between the values and a meaningul zero value.
With this in mind, the IQ scores of the college students represent numerical data, with a natural order, and the distance between the values is not equal, so you can classify the data as "ordinal"
Help in writing an equation. I believe that it is supposed to be a linear equation
Answers
Since the information required us that the equation has to start in zero we can think of functions like the root of x but also we have to add a value of 1/3. In other words one equation with those characteristics is
[tex]y=\sqrt{x}+\frac{1}{3}[/tex]the bearing from S to R is 160° what is the bearing of S from R
Answers
.
The bearing of S from R is given as;
[tex]90+90+90+70=340\degree[/tex]According to Debt.org the average household has $7,281 in credit card debt. Estimate how much interest the average household accumulates over the course of 1 year. We are going to assume the APR is 16.99%.
Answers
In order to estimate the interest the average househould accumulates in 1 year, you use the following formula:
A = Prt
where P is the initial credit card debt ($7,281), r is the interest rate per period (16.99%) and t is the number of time periods. In this case the value of r is given by the APR, then, there is one period of 1 year.
To use the formula it is necessary to express 16.99% as 0.1699. Thus, you have:
I = 7,281 x 0.1699 x 1
I = 1,237.04
Hence, the interest accumulated is of $1,234.04
2. The area A of a rectangle is represented by the formula A = Lw, where Lis the length and wis the width. The length of the rectangle is 5. Write anequation that makes it easy to find the width of the rectangle if we knowthe area and the length.
Answers
1) Considering that the Area of a rectangle is given as:
[tex]A=lw[/tex]2) We can then write the following equation plugging into that the length= 5.
Say the area is "A", then we can find the width this way:
[tex]\begin{gathered} A=5ww \\ 5w=A \\ \frac{5w}{5}=\frac{A}{5} \\ w=\frac{A}{5} \end{gathered}[/tex]Note that we rewrote that to solve it for w (width).
All we need is to plug into the A the quantity of the area of this rectangle
Thus, the answer is w=A/5
HelppppppFunction f is a(n)functionThe graph is a reflection in thewith a verticaland atranslationunits:The domain of f isThe domain of the parent function is;The range of f isThe range of the parent function is
Answers
Answer:
In order of appearance of boxes
quadraticx-axisstretch3 (units)upall real numbersall real numbersy ≤ 3y ≥ 0Step-by-step explanation:
The given function f(x) = -2x² + 3 belongs to the quadratic family of equations. A quadratic equation has a degree of 2. The degree is the highest power of the x variable in the function f(x)
The parent f(x) = x²
Going step by step:
2x² ==> graph x² is vertically stretched by 2. For any value of x in x², the new y value is twice that the old value. For example, in the original parent function x², for x = 2, y = 4. In the transformed function 2x², for x = 2, y = 2 x 4 = 8 so it has been stretched vertically. It becomes skinnier compared to the original
-2x² => graph is reflected over the x-axis. It is the mirror image of the original graph when viewed from the x-axis perspective
-2x² + 3 ==> graph is shifted vertically up by 3 units
Domain is the set of all x-input values for which the function is defined. For both x² and -2x² + 3 there are no restrictions on the values of x. So the domain for both is the set of all real numbers usually indicated by
-∞ < x < ∞
The range is the set of all possible y values for a function y = f(x) for x values in domain.
The range of f(x) = x² is x≥ 0 since x² can never be negative
Range of -2x² + 3 is x ≤ 3 : Range of -2x² is y ≤ 0 since y cannot be negative and therefore range of -2x² + 3 is y ≤ 3
3450 turns to degrees and 3450 turns to radians.
Answers
We will have the following:
*First: We know that 1 turn will be equal to 360°. So:
[tex]3450\cdot360=1242000[/tex]So, 3450 turns equal to 1 242 000 degrees.
*Second: We have that the expression to convert degrees to radians is:
[tex]d\cdot\frac{\pi}{180}=r[/tex]Here d represents degrees and r radians. So, we replace the number of degrees and solve for radians:
[tex](1242000)\cdot\frac{\pi}{180}=6900\pi[/tex]So, 3450 turns are 6900pi radians.
Which of the following could be the points that Jamur plots?
Answers
To solve this problem, we need to calculate the midpoint for the two points in each option and check if it corresponds to the given midpoint (-3,4).
Calculating the midpoint for the two points of option A.
We have the points:
[tex](-1,7)and(2,3)[/tex]We label the coordinates as follows:
[tex]\begin{gathered} x_1=-1 \\ y_1=7 \\ x_2=2 \\ y_2=3 \end{gathered}[/tex]And use the midpoint formula:
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]Substituting our values:
[tex](\frac{-1_{}+2_{}}{2},\frac{7_{}+3_{}}{2})[/tex]Solving the operations:
[tex](\frac{1_{}}{2},\frac{10_{}}{2})=(\frac{1_{}}{2},5)[/tex]Since the midpoint is not the one given by the problem, this option is not correct.
Calculating the midpoint for the two points of option B.
We have the points:
[tex](-2,6)and(-4,2)[/tex]We follow the same procedure, label the coordinates:
[tex]\begin{gathered} x_1=-2 \\ y_1=6 \\ x_2=-4 \\ y_2=2 \end{gathered}[/tex]And use the midpoint formula:
[tex]\begin{gathered} (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ \text{Substituting our values} \\ (\frac{-2-4_{}}{2},\frac{6+2_{}}{2}) \\ \text{Solving the operations:} \\ (\frac{-6}{2},\frac{8}{2}) \\ (-3,4) \end{gathered}[/tex]The midpoint for the two points in option B is (-3,4) which is the midpoint given by the problem.
Answer: B (-2,6) and (-4,2)
