1) rotation 90° clockwise over the origin and a reflection over the x-axis
2) rotation 90° counter clockwise over the origin and reflection over y-axis
help me please i'm stuck Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks. Myra owns a cake shop and she is working on two wedding cakes this week. The first cake consists of 3 small tiers and 4 large tiers, which will serve a total of 226 guests. The second one includes 1 small tier and 1 large tier, which is enough servings for 62 guests. How many guests does each size of tier serve? A small tier will serve ? guests and a large tier will serve ? guests.
the number of guests a small tier can serve is 22
the number of guest a large tier serves is 40
Explanation
Step 1
Set the equations
a) let
x represents the number of guest one small tier serves
y represents the number of guests one large tier serves
b) translate into math term
i)The first cake consists of 3 small tiers and 4 large tiers, which will serve a total of 226 guests,so
[tex]3x+4y=226\Rightarrow equation(1)[/tex]ii) The second one includes 1 small tier and 1 large tier, which is enough servings for 62 guests,so
[tex]x+y=62\Rightarrow equation(2)[/tex]Step 2
solve the equations:
[tex]\begin{gathered} 3x+4y=226\Rightarrow equation(1) \\ x+y=62\operatorname{\Rightarrow}equat\imaginaryI on(2) \end{gathered}[/tex]a) isolate the x value in equation (2) and replace in equatino (1) to solve for y
[tex]\begin{gathered} x+y=62\Rightarrow equation(2) \\ subtract\text{ y in both sides} \\ x=62-y \end{gathered}[/tex]replace into equation(1) and solve for y
[tex]\begin{gathered} 3x+4y=226\Rightarrow equation(1) \\ 3(62-y)+4y=226 \\ 186-3y+4y=226 \\ add\text{ like terms} \\ 186+y=226 \\ subtrac\text{ 186 in both sides} \\ 186+y-186=226-186 \\ y=40 \end{gathered}[/tex]so, the number of guest a large tier serves is 40
b)now, replace the y value into equation (2) and solve for x
[tex]\begin{gathered} x+y=62\Rightarrow equation(2) \\ x+40=62 \\ subtract\text{ 40 in both sides} \\ x+40-40=62-40 \\ x=22 \end{gathered}[/tex]so, the number of guests a small tier can serve is 22the number of guests a small tier can serve is 22
I hope this helps you
Omar has $84 and maryam has $12. how much money must Omar give to maryam so that maryam will have three times as much as omar? let x be the amount of dollars Omar will give maryam. which equation best represents the situation described above? A.) 84 - x = 3(12) + xB.) 3(84 - x) = 12 - xC.) 3(84 - x ) = 12 + xD.) 3x = 84 - (12 + x)
Given data:
The given money Omar has $84.
The given money maryam has $12.
The expression for the money Omar give to maryam so that maryam will have three times as much as omar.
[tex]3(84-x)=12+x[/tex]Thus, the final expression is 3(84-x)=12+x.
Which of the following is not a correct way to name the plane.
For this case the first option is correct Plane P
every week, Hector works 20 hours and earns $210.00. he eans a constant amount per hour. write an equation that can be used to determine the number of hours, h, Hector works given the number of weeks, w.
From the question, we're told that Hector earns $210.00 for working 2hours every week. Let's go ahead and determine
What are the coordinates of the point on the directed line segment from (−8,−4)(−8,−4) to (−5,8)(−5,8) that partitions the segment into a ratio of 5 to 1?
a gallon of ice cream costs $4.76. How much does it cost per quart? There are 4 qts per gallon.
There are 4 quarts in a gallon so the price of one gallon that they have given us has to be split into four so $4.76/4 =$1. 19/quart
Use the following data set to answer the question below.8 12 15 9 101212 18 14 1510 11 12 9 17What is the range for the data set?
Given the following set of data:
8 12 15 9 10 12 12 18 14 15 10 11 12 9 17
We will find the range of the data.
We need to find the maximum and the minimum
The maximum = 18
The minimum = 8
So, the range = maximum - minimum = 18 - 8 = 10
So, the answer will be The range = 10
although the actual amount varies by the season and time of the day the average volume of water that flows over the false each second is 2.9 x 10 to the 5th power gallons how much water flows over the falls in an hour write the result in scientific notation hint 1 hour equals 3600 second
We were told that volume of water that flows over the fall each second is 2.9 x 10^5 gallons.
Recall, 1 hour = 3600 seconds
If 1 second = 2.9 x 10^5 gallons, then
3600 seconds = 3600 x 2.9 x 10^5
= 1.044 x 10^9 gallons
Thus, 1.044 x 10^9 gallons of water will flow over the falls in an hour.
**Line m is represented by the equation -2x + 4y = 16. Line m and line k are Blank #1:
Line m:
[tex]y=\frac{2}{3}x+4[/tex]line k:
[tex]\begin{gathered} -2x+4y=16 \\ 4y=2x+16 \\ y=\frac{2x+16}{4} \\ y=\frac{x}{2}+4 \end{gathered}[/tex]so, the lime m and line k are:
D. Neither parallel nor perpendicular
Because:
D. their slopes have no relationship
Finding a polynomial of a given degree with given zeros: Complex zeros
Given:
• Degree of polynomial = 3
,• Zeros of the polynomial: 2, 3 - 2i
Let's find the polynomial.
Since the polynomail is of degree 3, it's highest exponent will be 3.
Equate the zeros to zero:
x = 2
Subtract 2 from both sides:
x - 2 = 2 - 2
x - 2 = 0
x = (3 - 2i)
Since this root is a complex conjugate, we have the other complex root: (3 + 2i)
Hence, we have:
(x - (3 - 2i)) and (x - (3 + 2i)).
Therefore, to write the function, we have:
[tex]f(x)=(x-2)(x-(3-2i))(x-(3+2i))[/tex]Now, simplify the expression:
[tex]\begin{gathered} f(x)=(x-2)(x-3+2i)(x-3-2i) \\ \\ f(x)=x(x-3+2i)-2(x-3+2i)(x-3-2i) \\ \\ f(x)=x^2-3x+2ix-2x+6-4i(x-3-2i) \\ \\ f(x)=x^2-5x+2ix-4i+6(x-3-2i) \end{gathered}[/tex]Solving further:
[tex]\begin{gathered} f(x)=x(x^2-5x+2ix-4i+6)-3(x^2-5x+2ix-4i+6)-2i(x^2-5x+2ix-4i+6) \\ \\ f(x)=x^3-5x^2+2ix^2-4ix+6x-3x^2+15x-6ix+12i-18-2ix^2+10ix-4i^2x-8-12i^{} \end{gathered}[/tex]Combine like terms:
[tex]\begin{gathered} f(x)=x^3-5x^2-3x^2-4ix-6ix+10ix+2ix^2-2ix^2+6x+15x+12i-12i-8-16 \\ \\ f(x)=x^3-8x^2+25x-26 \end{gathered}[/tex]ANSWER:
[tex]f(x)=x^3-8x^2+25x-26[/tex]Can you Convert 840 inches to cm. Use unit analysis to convert the rate.
we know that
1 in=2.54 cm
so
840 in
Applying proportion
1/2.54=840/x
x=(840*2.54)/1
x=2,133.6 cm
answer is
2,133.6 cmApplying unit rate or unit analysiswe have
2.54 cm/in
Multiply by 840 in
2.54*(840)=2,133.6 cm40/
Write the equation of the line (in standard form) that goes through point (5,-1) and is parallel to the equation 3x + 2y =19.
The equation of the line that goes through the point (5, -1) and is parallel to the given equation is; 3x + 2y = -7.
What is the equation of the line that gOES through the point given and is parallel tomthe given equation?Recall from line geometry that parallel lines have equal slopes.
Therefore, by computing the slope of the equation given as follows; we have;
3x + 2y = 19.
By rearranging the equation in the slope-intercept form; y = mx + c; we have;
y = (-3/2)x + 19/2
Therefore, the slope of both lines is same and is; -3/2.
Therefore, By using the point slope equation of a straight line; (y - y1) = m (x - x1); we have;
(y - (-1)) = -3/2(x - 5)
2y + 2 = -3x - 5
3x + 2y = -7.
Ultimately, the required equation is; 3x + 2y = -7.
Read more on slope of parallel lines;
https://brainly.com/question/10790818
#SPJ1
I need help on question number 1 I have been stuck on it for a long time
Explanation
Step 1
Vertical angles are formed when two lines intersect each other. Out of the 4 angles that are formed, the angles that are opposite to each other are vertical angles. vertical angles are congruent so
[tex]\begin{gathered} m\angle5=m\angle7\rightarrow reason\text{ vertical angles} \\ \end{gathered}[/tex]Step 1
replace the given values
[tex]\begin{gathered} m\angle5=m\angle7\rightarrow reason\text{ vertical angles} \\ -2(3x-4)=3(x-3)-1 \end{gathered}[/tex]now, we need to solve for x
a)
[tex]\begin{gathered} -2(3x-4)=3(x-3)-1 \\ \text{apply distributive property} \\ -6x+8=3x-9-1 \\ \text{add like terms} \\ -6x+8=3x-10\rightarrow reason\text{ distributive property} \end{gathered}[/tex]b)subtract 3x in both sides( additioin or subtraction property of equality)
[tex]\begin{gathered} -6x+8=3x-10 \\ subtract\text{ 3x in both sides} \\ -6x+8-3x=3x-10-3x \\ -9x+8=-10 \\ \text{subtract 8 in both sides} \\ -9x+8-8=-10-8 \\ -9x=-18 \\ -9x=-18\rightarrow reason\colon\text{ addition and subtraction property of equality} \end{gathered}[/tex]c) finally, divide both sides by (-9) division property of equality
[tex]\begin{gathered} -9x=-18 \\ \text{divide both side by -9} \\ \frac{-9x}{-9}=\frac{-18}{-9} \\ x=2\rightarrow\text{prove} \end{gathered}[/tex]i hope this helps you
Determine the value of n that makes the polynomial a perfect square trinomial. Then factor as the square of a binomial. Express numbers as integers orsimplified fractions.u^2+20u+n
SOLUTION
The expression is given as
[tex]u^2+20u+n[/tex]The value of n makes the expression a perfect square trinomial.
To find the value of n, we have
Identify the coefficient of u and divide by 2
[tex]\begin{gathered} \text{the coefficient of u=20} \\ \text{divide by 2=}\frac{\text{20}}{2}=10 \end{gathered}[/tex]Then square the result, we have
[tex]\begin{gathered} 10^2=100 \\ \text{hence } \\ n=100 \end{gathered}[/tex]Then the complete trinomial of the polynomial becomes
[tex]u^2+20u+100[/tex]To factor as a square of a binomial we use the perfect square trinomial above
[tex]\begin{gathered} u^2+20u+100 \\ u^2+20u+10^2 \\ \text{Then} \\ (u+10)^2 \end{gathered}[/tex]Therefore
The vaue of n = 100
The factor as the square of a binomial is (u+ 10)²
Which graph represents the solution set of the
inequality 4x>-8?
Answer:
The answer is C.
Step-by-step explanation:
In order to solve this, you must use an inequality from one side of the equation.
Inequality is the growing inequality between rich and poor.
4x>-8First thing you do is divide by 4 from both sides.
[tex]\sf{\dfrac{4x}{4} > \dfrac{-8}{4}}[/tex]
Solve.
Divide these numbers goes from left to right.
-8/4=-2
[tex]\boxed{\sf{x > -2}}[/tex]
Therefore, the graph represents the solution set of the inequality of 4x>-8 is C, which is our answer.
I hope this helps, let me know if you have any questions.
Point Q is shown on the number line. Which Value is best represented by point Q? 15 6
According to the given graph, the point Q is between 5 and 5.50.
Therefore, the number that best describes point Q is
[tex]\sqrt[]{29.5}\approx5.4[/tex]Since it's between 5 and 5.50 too.
A contractor bought 10.8 ft² of sheet metal. He has used 3.5 ft² so far and has $219 worth of sheetmetal remaining. The equation 10.8x - 3.5x = 219 represents how much sheet metal is remainingand the cost of the remaining amount. How much does sheet metal cost per square foot?
The first step to do is to combine 10.8x - 3.5x and that is equal to 7.3x.
[tex]7.3x=219[/tex]The next step is to divide both sides by 7.3 to solve for x.
[tex]\begin{gathered} \frac{7.3x}{7.3}=\frac{219}{7.3} \\ x=30 \end{gathered}[/tex]Therefore, the remaining sheet metal is 7.3 ft² and the cost per square foot of sheet metal is $30.
I tried it and got imaginary numbers in the answer.
Given the following equation:
[tex]\frac{x}{x-4}-\frac{4}{x}=\frac{3}{x-4}[/tex]First, we will identify the zeros of the denominator
So, the zeros are: x = {0,4}
Second, multiply the equation by x(x-4) to eliminate the denominators
[tex]x(x-4)*(\frac{x}{x-4}-\frac{4}{x})=x(x-4)*\frac{3}{x-4}[/tex]Simplify the equation:
[tex]x^2-4(x-4)=3x[/tex]Expand the equation and combine the like terms:
[tex]\begin{gathered} x^2-4x+16=3x \\ x^2-7x+16=0 \end{gathered}[/tex]The last quadratic equation will be solved using the quadratic rule:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]Substitute a = 1, b = -7, c = 16
[tex]\begin{gathered} x=\frac{7\pm\sqrt{(-7)^2-4(1)(16)}}{2(1)} \\ \\ x=\frac{7\pm\sqrt{-15}}{2}=\frac{7\pm i\sqrt{15}}{2} \\ \\ x=\lbrace\frac{7+i\sqrt{15}}{2};\frac{7-i\sqrt{15}}{2}\rbrace \end{gathered}[/tex]So, the answer will be:
[tex]x=\lbrace\frac{7+i\sqrt{15}}{2};\frac{7-i\sqrt{15}}{2}\rbrace[/tex]Write the expression as a complex number in standard form.
(-2+6i)-(2-3i)=
Answer:
-4 +9i
Step-by-step explanation:
complex number in standard form.
(-2+6i)-(2-3i)=
Combine like terms
-2 -2 +6i +3i
Standard form is a+bi
-4 +9i
Which theorem proves that the triangles are congruent?a) CPCTC b) SAS c) AAS d) SSS
Answer:
B. SAS
:)
Step-by-step explanation:
Find a if (10-a )×2 +(2a×2)+(4a+7)=48
First step: Simplify everything
[tex]2(10-a) + 4a + 4a+7 = 48[/tex]
Next: Distribute required values
[tex]20-2a+4a+4a+7=48[/tex]
Next: Time to add like terms
[tex]6a = 21[/tex]
Final Step: Divide 6 on both sides to isolate variable
[tex]a = \frac{21}{6}[/tex]
Thus, the value "a" = [tex]\frac{21}{6}[/tex]
Hope this helps :)
Find the sum of integers from 33 to 47:
33+34+...+46
+47
The sum of integers from 33 to 47 is 600.
What are integers?Zero, a positive natural number, or a negative integer denoted by a minus sign are all examples of integers. The inverse additives of the corresponding positive numbers are the negative numbers. The Z symbol is a common way for mathematicians to refer to an integer set.An integer, pronounced "IN-tuh-jer," is a whole number that can be positive, negative, or zero and is not a fraction. Integer examples include: -5, 1, 5, 8, 97, and 3,043.So, the sum of integers:
33 - 47Simply perform addition as follows:
33 + 34 + 35 + 36 + 37 + 38 + 39 + 40 + 41 + 42 + 43 + 44 + 45 + 46 + 47= 600Therefore, the sum of integers from 33 to 47 is 600.
Know more about integers here:
https://brainly.com/question/17695139
#SPJ13
Find the limit. (If an answer does not exist, enter DNE.)
Given:
[tex]\lim _{\Delta x\to0}\frac{6(x+\Delta x)-6x_{}}{\Delta x}[/tex]Solve as:
[tex]\begin{gathered} \lim _{\Delta x\to0}\frac{6x+6\Delta x-6x}{\Delta x}=\lim _{\Delta x\to0}\frac{6\Delta x}{\Delta x} \\ =6 \end{gathered}[/tex]Hence, the required answer is 6.
Lisa played 42 of thepossible 60 minutes of asoccer game. Whatpercent did she notplay?
Lisa played 42 minutes of a 60 minutes match. This means that she didn't play 18 minutes of the game; to find what percent this represents we can use the rule of three:
[tex]\begin{gathered} 60\rightarrow100 \\ 18\rightarrow x \end{gathered}[/tex]Then:
[tex]\begin{gathered} x=\frac{18\cdot100}{60} \\ =30 \end{gathered}[/tex]Therefore, Lisa didn't play 30% of the game.
If the cube root of D is equal to 4 , what is D equal to ?
Given:
The cube root of D = 4
so, we can write the following expression:
[tex]\sqrt[3]{D}=4[/tex]cube both sides to find d
So,
[tex]\begin{gathered} (\sqrt[3]{D})^3=4^3 \\ D=4\times4\times4 \\ \\ D=64 \end{gathered}[/tex]So, the answer will be D = 64
Give me a rhombus ABCD with BC =25 and BD= 30 find AC and the area of ABCD
300 u²
1) Let's start by sketching out this:
2) Since a Rhombus have 4 congruent sides, then we can state that 4 sides are 25 units, and we need to find out the other Diagonal (AC)
Applying the Pythagorean Theorem, to Triangle COD
a² =b² +c²
25² = 15² +c²
625 = 225 + c² subtract 225 from both sides
625-225 = c²
400 = c²
√c² =√400
c =20
2.2) Now, we can calculate the area, applying the formula for the area of a rhombus (the product of its diagonals).
[tex]\begin{gathered} A=\frac{D\cdot d}{2} \\ A=\frac{40\cdot30}{2} \\ A=\frac{1200}{2} \\ A\text{ = 600} \end{gathered}[/tex]3) Hence, the answer is 300 u²
find the area of figure using 3.14 for pi. round your answer to nearest tenth if necessary.
Given a figure to find the area of the figure.
The given figure is the combination of two triangles and a semi-circle.
Here the radius and the base of the triangle is 10 yd and the height of the triangle is 21 yd. So, the area of the figure is;
[tex]\begin{gathered} A=2\times\frac{1}{2}\times\text{base}\times\text{height}+\frac{\pi r^2}{2} \\ =10\times21+\frac{3.14\times10^2}{2} \\ =210+\frac{314}{2} \\ =210+157 \\ =367 \end{gathered}[/tex]Thus, the area of the figure is 367 yd^2.
I need answers to 6a and 6b. This is for my homework :,)
The system of equations has 3 cases
1. y = ax + b, y = ax + c
Since the coefficient of x and y are the same, and the y-intercepts are different, then
The two lines are parallel
2. y = ax + b, y = dx + c
Since the 2 lines have different coefficients of x, then
The two lines are intersected
3. y = ax + b, y = ax + b
Since the two lines have equal coefficients of x and equal y-intercepted, then
The two lines are coincide (same line)
6. a)
Since the system of equations is
[tex]\begin{gathered} y=2x+3 \\ y=12x-2 \end{gathered}[/tex]The coefficients of x not equal
Then from case 2 above
The two lines are intersected
6.b
Since the system of equations is
[tex]\begin{gathered} y=13x+2 \\ y=13x-2 \end{gathered}[/tex]The coefficients of x are equal
The y-interceptes not equal
Then from case 1 above
The two lines are parallel
Fill in the blank. In the triangle below, Z = 52° 35
Solution
Since the diagram given is a Triangle, therefore, the sum of it's interior angles is 180 degrees
However, the Triangle is a right angle Triangle since on of its angles is 90 degrees.
The sum of its Interior angles is given by;
[tex]\begin{gathered} z+52+90=180 \\ \\ \Rightarrow z+142=180 \end{gathered}[/tex]subtracting 142 from both sides,
[tex]\begin{gathered} \Rightarrow z+142-142=180-142=38 \\ \\ \Rightarrow z=38^0 \end{gathered}[/tex]Therefore, z = 38
Sophie has $4.20 worth of dimes and quarters. She has twice as many quarters asdimes. Write a system of equations that could be used to determine the number ofdimes and the number of quarters that Sophie has. Define the variables that you useto write the system.
d = 2q .........................................................................(1)
0.1d + 0.25q = 4.20 ................................................(2)
Explanation:Let d be the number of dimes, and q be the number of quarters Sophie has.
Since she has twice as many quarters as dimes, and they are worth $4.20, we have:
d = 2q .........................................................................(1)
Also, because:
1 dime = $0.1
1 quarter = $0.25
0.1d + 0.25q = 4.20 ..................................................(2)
Equation (1) and (2) can be solved to determine the number of dimes and quarters