Answer:
D = (9,-4) E = (3,-4) F= (3, -10) G=(9,-10)
Step-by-step explanation:
Simply switch the signs (- or +)
Ex: rotate (9,1) 180 degrees
Your answer would be (-9,-1)
Tim and Kevin each sold candies and peanuts for a school fund-raiser. Tim sold 16 boxes of candies and 4 boxes of peanuts and earned $132. Kevin sold 6 boxes of peanuts and 20 boxes of candies and earned $190. Find the cost of each. Cost of a box of candy. Cost of a box of peanuts.
We have the following:
let x cost of a box of candy
let y cost of a box of peanuts
[tex]\begin{gathered} \text{ Tim} \\ 16x+4y=132 \\ \text{ Kevin} \\ 20x+6y=190 \end{gathered}[/tex]resolving the system of equations:
[tex]\begin{gathered} 20x+6y=190 \\ 16x+4y=132\Rightarrow4y=132-16x\Rightarrow y=\frac{132-16x}{4} \\ \text{replacing:} \\ 20x+6\cdot(\frac{132-16x}{4})=190 \\ 20x+198-24x=190 \\ -4x=190-198 \\ x=\frac{-8}{-4} \\ x=2 \end{gathered}[/tex]now, for y
[tex]\begin{gathered} y=\frac{132\cdot16\cdot2}{4} \\ y=25 \end{gathered}[/tex]Therefore the cost of the box of candy is $ 2 and the cost of the box of peanuts is $ 25
on the coordinate plane below
As we can see by the picture below, the school is on the point (5, -2).
y = -x +3
x+y = 17
Are these parallel?
Answer:
Yes
Step-by-step explanation:
The equations need to be in slope intercept form. The first equation is but the second one isn't. Solve the second equation for y to put it in slope intercept form.
x + y = 17
x - x + y = 17 - x
y = -x + 17
To determine if they are parallel the slopes need to be the same.
y = -1x + 3
y = -1x +17
The slope are both -1, so they are parallel
Answer:
Yes
Step-by-step explanation:
Find the equation of the line that is parallel to y= 3x -2 and contains the point (2,11) Y= ?x + ?
Solution:
Given:
[tex]\begin{gathered} y=3x-2 \\ \text{Through the point (2,11)} \end{gathered}[/tex]Two parallel lines have identical slopes.
[tex]m_1=m_2[/tex]Hence, the slope of line 1 is gotten by comparing the equation given to the equation of a line in the slope-intercept form.
[tex]\begin{gathered} y=mx+b \\ \text{where m is the slope} \\ b\text{ is the y-intercept} \end{gathered}[/tex]
Thus,
[tex]\begin{gathered} y=mx+b \\ y=3x-2 \\ \\ \text{Comparing both equations,} \\ m_1=3 \\ \text{The slope of line 1 is 3.} \end{gathered}[/tex]Since both lines are parallel, then the slopes are equal.
[tex]\begin{gathered} m_1=m_2=3 \\ m_2=3 \\ \text{The slope of line 2 is 3} \end{gathered}[/tex]To get the equation of line 2 through the point (2,11), the formula below is used;
[tex]\begin{gathered} \frac{y-y_1}{x-x_1}=m \\ \\ \text{where;} \\ x_1=2 \\ y_1=11 \\ m=3 \\ \text{Hence,} \\ \frac{y-11}{x-2}=3 \\ \text{Cross multiplying,} \\ y-11=3(x-2) \\ y-11=3x-6 \\ y=3x-6+11 \\ y=3x+5 \end{gathered}[/tex]
Therefore, the equation of the line that is parallel to y = 3x - 2 passing through the point (2,11) is;
[tex]y=3x+5[/tex]36. The widths of platinum samples manufactured at a factory are normally distributed, with a mean of 1.3 cm and a standard deviation of 0.3 cm. Find the z-scores that correspond to each of the following widths. Round your answers to the nearest hundredth, if necessary.(a) 1.7 cmz = (b) 0.9 cmz =
Part (a)
Using the formula for the z-scores and the information given, we have:
[tex]\begin{gathered} \text{ z-score=}\frac{\text{ data value }-\text{ mean}}{\text{ standard deviation }} \\ \text{ z-score=}\frac{1.7\text{ cm }-\text{ 1.3 cm}}{0.3\text{ cm}} \\ \text{ z-score=}\frac{0.4\text{ cm}}{0.3\text{ cm}}\text{ (Subtracting)} \\ \text{ z-score=1.33 (Dividing)} \\ \text{The z-score for 1.7 cm is 1.33 rounding to the nearest hundredth.} \end{gathered}[/tex]Part (b)
Using the formula for the z-scores and the information given, we have:
[tex]\begin{gathered} \text{ z-score=}\frac{\text{ data value }-\text{ mean}}{\text{ standard deviation }} \\ \text{z-score=}\frac{\text{ 0.9 cm }-1.3\text{ cm}}{\text{ 0.3 }}\text{ (Replacing the values)} \\ \text{z-score=}\frac{\text{ }-0.4}{\text{ 0.3 }}\text{ (Subtracting)} \\ \text{ z-score= }-1.33 \\ \text{The z-score for 0.9 cm is -1.33 rounding to the nearest hundredth.} \end{gathered}[/tex]Find an equation of the circle having the given center and radius.Center (-3, 3), radius 16
The equation of a circle is given by the next formula:
[tex](x-h)^2+(y-k)^2=r^2[/tex]Where the center is the point (h, k) and r means the radios. Therefore:
[tex]\begin{gathered} (x-(-3))^2+(y-3)^2=(\sqrt[]{6}_{})^2 \\ (x+3)^2+(y-3)^2=6^{} \end{gathered}[/tex]Answer is letter C
For the simple harmonic motion equation d=5sin (pi/4^+), what is the period?
the period is 8
Explanation
the function sin has the form
[tex]\begin{gathered} y=Asin(B(x+c))+D \\ where \\ Period=\frac{2\pi}{B} \end{gathered}[/tex]so
Step 1
a) identify B in the given function
given
[tex]d=5\text{ sin\lparen}\frac{\pi}{4}t)[/tex]hence
[tex]\begin{gathered} \frac{\pi}{4}t\Rightarrow B(t+c) \\ so \\ c=0 \\ \frac{\pi}{4}t=Bt \\ therefore \\ B=\frac{\pi}{4} \end{gathered}[/tex]b) now, replace in the formula to find teh period
[tex]\begin{gathered} Per\imaginaryI od=\frac{2\pi}{B} \\ Period=\frac{2\pi}{\frac{\pi}{4}}=\frac{2\pi *4}{1*\pi}=\frac{8\pi}{\pi}=8 \\ so \\ Period=8 \end{gathered}[/tex]therefore, the period is 8
I hope this helps you
Answer:
8
Step-by-step explanation:
A
P
E
X
a scale drawing of a school bus is 1 inch to 5 feet. if the length of the school bus is 5 inches on the scale drawing. what is the actual length of the bus?
Answer:
25 feet
Step-by-step explanation:
we can set up the proportional relationship of the drawing vs the actual size
so 1 inch to 5 feet would be 1:5
so then if we scale up 1 inch to 5 inch
then we have 1:5=5:Actual length of the bus
so then we have 5*5=25 feet
PRYZ is a rhombus. If RK=5, RY = 13, and YRZ = 67, find each measure.
The Solution:
The correct answer is 67 degrees.
Given the rhombus below:
We are required to find the measure of angle PRZ.
Considering trianglePRZ, we can apply the law of cosine to the angle of interest, which is, angle PRZ.
[tex]R=\cos ^{-1}(\frac{p^2+z^2-r^2}{2pz})[/tex]In this case,
[tex]\begin{gathered} p=(5+5)=10 \\ z=13 \\ r=13 \\ R=\text{?} \end{gathered}[/tex]Substituting these values in the formula, we get
[tex]R=\cos ^{-1}(\frac{10^2+13^2-13^2}{2(10)(13)})[/tex][tex]R=\cos ^{-1}(\frac{100^{}+169^{}-169^{}}{2(10)(13)})=\cos ^{-1}(\frac{100^{}}{260})=67.380\approx67^o[/tex][tex]m\angle\text{PRZ}\approx67^o[/tex]Therefore, the correct answer is 67 degrees.
1. The population of Whatville is given by the y=83,000(1.04) where x is the years since 2010.a) What was the population in 2010?b) What is the population in 2020?c) When will the population reach 100,000? Show your work.
ANSWER:
a) 83,000 people
b) 122,860 people
c) 4.75 years
STEP-BY-STEP EXPLANATION:
We have that the population given by the following equation:
[tex]y=83000\cdot\mleft(1.04\mright)^x[/tex]a) What was the population in 2010?
Since no year has passed, the value of x would be 0.
Replacing:
[tex]\begin{gathered} y=83000\cdot(1.04)^0 \\ y=83000 \end{gathered}[/tex]The population in 2010 is 83,000 people
b) What is the population in 2020?
From 2010 to 2020 10 years have passed, therefore the value of x is 10
[tex]\begin{gathered} y=83000\cdot(1.04)^{10} \\ y=122860 \end{gathered}[/tex]The population in 2020 is 122,860 people
c) When will the population reach 100,000?
Since the population is 100,000 people, it is the value of y, therefore we must solve and calculate the value of x
[tex]\begin{gathered} 100000=83000\cdot\mleft(1.04\mright)^x \\ 1.04^x=\frac{100000}{83000} \\ \ln 1.04^x=\ln \frac{100}{83} \\ x\cdot\ln 1.04=\ln \frac{100}{83} \\ x=\frac{\ln \frac{100}{83}}{\ln 1.04} \\ x=4.75 \end{gathered}[/tex]Which means that for the population to be 100,000 people, 4.75 years would have to pass
True or False: A power has two parts, a base and an exponent. True False
The said statement is true.
A power has two parts, a base and an exponent.
Example
[tex]2^3[/tex]The answer is TRUE
A)State the angle relationship B) Determine whether they are congruent or supplementary C) Find the value of the variable D) Find the measure of each angle
Answer:
a) Corresponding
b) Congruent, since they have the same measure.
c) p = 32
d) 90º
Step-by-step explanation:
Corresponding angles:
Two angles that are in matching corners when two lines are crossed by a line. They are congruent, that is, they have the same measure.
Item a:
Corresponding
Item b:
Congruent, since they have the same measure.
Item c:
They have the same measure, the angles. So
3p - 6 = 90
3p = 96
p = 96/3
p = 32
Item d:
The above is 90º, and the below is the same. So 90º
at Frank's auto plaza there are currently 11 new cars, 8 used cars, 12 new trucks and 10 used trucks. frank is going to choose one of these vehicles at random to be the deal of the month. what is the probability that the vehicle that frank chooses is used or is a car?
11 new cars
8 used cars
12 new trucks
10 used trucks
Total vehicles
11+8+12+10 = 41
It is the denominator of the fraction.
The subset "used" + "cars" has 11 (new cars) + 8 (used cars) + 10 (used trucks) = 29 elements.
It is the numerator of the fraction.
P(U or C) = 29/41
Use the given information to select the factors of f(x).
ƒ(4) = 0
f(-1) = 0
f(³/²) = 0
options are:
(2x-3)
(2x+3)
(x-4)
(3x-2)
(x-1)
(x+4)
(3x+2)
(x+1)
The factors of f(x) are (x-4), (x+1) and (2x-3) respectively.
How to select the factors of f(x)To select the factors of f(x), we are to pick the functions that satisfy the conditions of the given information.
For f(4) = 0:
The function that evaluates to 0 when x = 4 is (x - 4). That is:
f(x) = (x - 4)
f(4) = (4 - 4) = 0
For f(-1) = 0:
The function that evaluates to 0 when x = -1 is (x + 1). That is:
f(x) = (x + 1)
f(-1) = (-1 + 1) = 0
For f(3/2) = 0:
The function that evaluates to 0 when x = 3/2 is (2x-3). That is:
f(x) = (2x-3)
f(3/2) = (2 × 3/2 - 3) = 0
Therefore, (x-4), (x+1) and (2x-3) are the corresponding factors of f(x)
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can you please solve this practice problem for me I need assistance
The missing angle in the triangle of the left is:
51 + 74 + x = 180
x = 180 - 51 - 74
x = 55°
The missing angle in the triangle of the right is:
55 + 74 + x = 180
x = 180 - 55 - 74
x = 51°
Then, both triangles are similar. This means that their corresponding sides are in proportion. These sides are:
35 in
Please help me with this problem so my son can better understand I have attached an image of the problem
We have to solve for c:
[tex](c+9)^2=64[/tex]When we have quadratic expressions, we have to take into account that each number has two possible square roots: one positive and one negative.
We can see it in this example: the square root of 4 can be 2 or -2. This is beacuse both (-2)² and 2² are equal to 4.
Then, taking that into account, we can solve this expression as:
[tex]\begin{gathered} (c+9)^2=64 \\ c+9=\pm\sqrt[]{64} \\ c+9=\pm8 \end{gathered}[/tex]We then calculate the first solution for the negative value -8:
[tex]\begin{gathered} c+9=-8 \\ c=-8-9 \\ c=-17 \end{gathered}[/tex]And the second solution for the positive value 8:
[tex]\begin{gathered} c+9=8 \\ c=8-9 \\ c=-1 \end{gathered}[/tex]Then, the two solutions are c = -17 and c = -1.
We can check them replacing c with the corresponding values we have found:
[tex]\begin{gathered} (-17+9)^2=64 \\ (-8)^2=64 \\ 64=64 \end{gathered}[/tex][tex]\begin{gathered} (-1+9)^2=64 \\ (8)^2=64 \\ 64=64 \end{gathered}[/tex]Both solutions check the equality, so they are valid solutions.
Answer: -17 and -1.
Use the deck of 52 standard playing cards to answer the question.
Given:
A deck of 52 playing cards is given.
Required:
Probability of selecting a number card, a red card and an ace.
Answer:
There are 40 number cards.
Therefore, probability of selecting a number card=
[tex]\frac{1}{40}[/tex]There are 26 red cards.
Therefore, probability of selecting a red card=
[tex]\frac{1}{26}[/tex]The probability of selecting an ace =
[tex]\frac{1}{52}[/tex]Final Answer:
The Probabilities of selecting a number card, a red card and an ace are,
[tex]\frac{1}{40},\frac{1}{26},\frac{1}{52}[/tex]respectively.
How do I solve this I do understand how to
Solve for the unknown variable using a pythagoras theorem:
Hypotenuse = 32+x
Opposite = 56
Adjacent = x
[tex]\begin{gathered} \text{Hyp}^2=\text{opp}^2+\text{adj}^2 \\ (32+x)^2=56^2+x^2 \\ (32+x)(32+x)=3136+x^2 \\ 1024+64x+x^2=3136+x^2 \\ \text{collect like terms} \\ 64x+x^2-x^2=3136-1024 \\ 64x=2112 \end{gathered}[/tex]Collect like terms
[tex]\begin{gathered} \frac{64x}{64}=\frac{2112}{64} \\ x=33 \end{gathered}[/tex]Therefore the correct value of x = 33
how do I know which picture goes with the correct equation
If B is between A and C, but B is not midpoint, then the graph would be
The equation would be
[tex]AC=AB+BC[/tex]On the other hand, if B is between A and C, and B is a midpoint, the graph would be
The equation would be
[tex]AB=BC[/tex]Elisa purchased a concert ticket on a website. The original price of the ticket was $95. She used a coupon code to receive a 10% discount. The website applied a 10% service fee to the discounted price. Elisa's ticket was less than the original by what percent?
The price of the ticket after the cupon is:
[tex]95\cdot0.9=85.5[/tex]To this price we have to add 10%, then:
[tex]85.5\cdot1.1=94.05[/tex]Hence the final cost of the ticket is $94.05.
To find out how less is this from the orginal price we use the rule of three:
[tex]\begin{gathered} 95\rightarrow100 \\ 94.05\rightarrow x \end{gathered}[/tex]then this represents:
[tex]x=\frac{94.05\cdot100}{95}=99[/tex]Therefore, Elisas's ticket was 1% less than the orginal price.
Complete the equation of the line through (-7,-3) and (-2,4)
If one line passes through the points (x₁, y₁) and (x₂, y), the slope of the line can be calculated using the formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}...(1)[/tex]Additionally, the equation can be expressed in point-slope form as:
[tex]y-y_2=m(x-x_2)...(2)[/tex]From the problem, we identify:
[tex]\begin{gathered} (x_1,y_1)=(-7,-3) \\ \\ (x_2,y_2)=(-2,4) \end{gathered}[/tex]Then, we calculate the slope of the line using (1):
[tex]m=\frac{4-(-3)}{-2-(-7)}=\frac{4+3}{-2+7}=\frac{7}{5}[/tex]Finally, we find the equation of the line using (2):
[tex]\therefore y-4=\frac{7}{5}(x+2)[/tex]What is the image of the point (-7,-3) after a rotation of 90° counterclockwise about the origin?
The new point after rotation of point (-7, -3) counterclockwise by 90 degrees will be ( 3, -7).
What is meant by coordinates?A pair of numbers that employ the horizontal and vertical distinctions from the two reference axes to represent a point's placement on a coordinate plane. typically expressed by the x-value and y-value pairs (x, y).
Coordinates are always written in the form of small brackets the first term will be x and the second term will be y.
Given: the Point A be (-7, -3)
After rotation, this point moves to a unique coordinate (x, y) which exists as point B
Let's say the origin is O
Slope of line segment AO = (-3-0)/(-7-0) = 3/7
Slope of line segment BO = (y - 0)/(x - 0) = y/x
Since both lines exist perpendicular to each other so
Slope AO × Slope BO = -1
3/7 × y/x = -1
⇒ 3y = -7x
If we observe the result then it will be clear that if we put x = 3 then y = -7 will be the new coordinate.
Therefore, the new point after rotation of point (-7, -3) counterclockwise by 90 degrees will be ( 3, -7).
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Find any domain restrictions on the given rational equation:
X+2
-25
+1=
8x
2x-10
Select all that apply.
A. x = 5
127
B. x = -2
C. X = -5
D. x = 0
The domain restrictions on the rational equation
[tex]\frac{x +2}{x^{2} -25 }+1 =\frac{8x}{2x-10}[/tex] are Options A and C. x = 5 and x = - 5 .
What are domain restrictions?A domain restriction is a prescription or criterion that limits the range of possible values for a function. A domain in mathematics is the collection of all values for which a function produces a result. Domain constraints allow us to create functions defined over numbers that meet our needs.Functions defined in pieces are made up of various functions with distinct domain restrictions. Some functions are not allowed to accept values that would make them undefined.How to find the domain restrictions?
The numbers that makes the denominators zero and the entire expression infinite or undefined are the domain restrictions.
Consider the denominators,
[tex]x^{2}[/tex] - 25 ≠ 0 --(1)
[tex]x^{2}[/tex] ≠ 25
x ≠ 5 and x ≠ -5
2x - 10 ≠ 0 ---(2)
2x ≠ 10
x ≠ 10/2
x ≠ 5
The domain restrictions on the rational equation [tex]\frac{x +2}{x^{2} -25 }+1 =\frac{8x}{2x-10}[/tex] are
x ≠ 5 and x ≠ -5 .
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Rewrite the following equation in slope-intercept form.
10x − 10y = –1 ?
Write your answer using integers, proper fractions, and improper fractions in simplest form.
Answer:
y = x + 1/10
Step-by-step explanation:
Rewrite the following equation in slope-intercept form: 10x − 10y = –1 ?
slope intercept form: y = mx + b so you are solving for y:
10x − 10y = –1
subtract 10x from both sides:
10x − 10y – 10x = –1 – 10x
-10y = –1 – 10x
divide all terms by -10:
-10y/(-10) = –1/(-10) – 10x/(-10)
y = 1/10 + x
rearrange for slope intercept form: y = mx + b
y = x + 1/10
Answer:
[tex]y=x+\dfrac{1}{10}[/tex]
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}[/tex]
Given equation:
[tex]10x-10y=-1[/tex]
To write the given equation in slope-intercept form, perform algebraic operations to isolate y.
Add 10y to both sides of the equation:
[tex]\implies 10x-10y+10y=10y-1[/tex]
[tex]\implies 10x=10y-1[/tex]
Add 1 to both sides of the equation:
[tex]\implies 10x+1=10y-1+1[/tex]
[tex]\implies 10x+1=10y[/tex]
[tex]\implies 10y=10x+1[/tex]
Divide both sides of the equation by 10:
[tex]\implies \dfrac{10y}{10}=\dfrac{10x+1}{10}[/tex]
[tex]\implies \dfrac{10y}{10}=\dfrac{10x}{10}+\dfrac{1}{10}[/tex]
[tex]\implies y=x+\dfrac{1}{10}[/tex]
Therefore, the given equation in slope-intercept form is:
[tex]\boxed{y=x+\dfrac{1}{10}}[/tex]
HELP ASAP 15 POINTS Determine which integer will make the equation true.
4x + 7 = 23
S = {3, 4, 5, 6}
3
4
5
6
Answer:
S = 4
Step-by-step explanation:
23-7 = 16
16/4 = 4
4x4+7 = 23
Answer: S = 4
Step-by-step explanation:
23 - 7 = 16
16 / 4 = 4
4 x 4 + 7 = 23
A farmer is planning on picking 1,000 bell peppers on the first day of the harvest. After picking the first 600, he finds that 70 percent of them are green and 30 percent of them are red. How many of the remaining peppers must he pick must be red in order for exactly half of the total number of peppers picked to be red?
Answer:
320 red bell peppers
Step-by-step explanation:
First, let's calculate how many green and red bell peppers the farmer harvest in the first time:
Green peppers: 600*70/100 = 420
Red peppers: 600*30/100 = 180
If the farmer wants that half (50%) of the pepper harvest are red:
The total number of red peppers harvest have to be:
100*50/100 = 500
For this reason, the amount of remaining red peppers that have to be harvest are:
500 - 180 = 320
Answer: The farmer has to harvest more 320 red bell peppers
Graph the intersection or union, as appropriate, of the solutions of the pair of linear inequalities
See graph below
Expanation:The given inequalities:
[tex]\begin{gathered} x\text{ + y }\leq\text{ 4} \\ x\text{ }\ge2 \end{gathered}[/tex]To plot the graphs, we will assing values to x in order to get the corresponding values of y for each of the inequality:
let x = 0, 2, 4
x + y = 4
from the above: y = 4 - x
when x = 0
y = 4
when x = 2
y = 4 - 2 = 2
when x = 4
y = 4 -4 = 0
we only have x in the second inequality
we will have a vertical line for x = 2
But the shading will be towards the right because the inequality is greater than x
plotting the graph:
The solution of the inequalities is the point of intersection of both graphs (the darker shade)
Which of the following transformations could be used to refute Anthony's claim? Select all that apply.
A parallelogram has rotational symmetry of order 2. This means that rotation transformation maps a parallelogram onto itself 2 times during a rotation of 360 degrees about its center.
And that is at 180 degrees and 360 degrees.
Hence, the only correct option is a rotation of 180 degrees clockwise about the center.
Answer:
Option D
You roll a die. What is the probability that you’ll get a number less than 3?0.3330.50.6670.75
Recall that the numbers in a die are 1,2,3,4,5,6.
[tex]S=\mleft\lbrace1,2,3,4,5,6\mright\rbrace[/tex]Hence the number of possible outcomes is 6.
[tex]n(S)=6[/tex]We need a number less than 3. Let A be this event.
[tex]A=\mleft\lbrace1,2\mright\rbrace[/tex]The favorable outcome is 2.
[tex]n(A)=\mleft\lbrace1,2\mright\rbrace[/tex]Since there are 1,2 less than 3 in a die.
[tex]P(A)=\frac{Favourable\text{ outcomes}}{\text{Total outcomes}}=\frac{n(A)}{n(S)}[/tex]Substitute n(A)=2 and n(S)=6, we get
[tex]P(A)=\frac{2}{6}=\frac{1}{3}=0.333[/tex]Hence the required probability is 0.333.
Parallel and Perpendicular LinesDetermine whether the following lines are parallel, perpendicular, orneither. Write the corresponding letter on the line next to the question.A = parallel, B = perpendicular, or C = neither1. y = }x+6 and y =- *x + 4
One of the criteria for lines being perpendicular is the fact that the slope of the function in a perpendicular line is the inverse of the slope of the first times -1.
And as you can see m (being the slope of the first equation) is the inverse of the second equiation:
[tex]m=\frac{7}{3},m_1=-\frac{1}{m}[/tex][tex]-\frac{1}{m}=-\frac{1}{\frac{7}{3}}=-\frac{3}{7}[/tex]Therefore line 1 is perpendicular to line 2.
