describe the center and spread of the data using the more appropriate status either the mean median range interquartile range or standard division

Answers

Answer 1

[tex]\begin{gathered} \mleft\lbrace1,12,2,9,2,3,7,3,3,6\mright\rbrace \\ \operatorname{mean}=\frac{1+12+2+9+2+3+7+3+3+6}{10}=\frac{48}{10}=4.8 \end{gathered}[/tex][tex]\sigma=\sqrt[]{\frac{\sum ^N_{i\mathop=1}(x-\operatorname{mean})^2}{N}}=3.4[/tex]


Related Questions

Find the probability of at least 2 girls in 6 births. Assume that male and female births are equally likely and that the births are independent events.0.6560.1090.2340.891

Answers

We need to use Binomial Probability.

Of 6 births, we want to find the probability of at least 2 of them being girls.

To solve this, we need to find:

Probability of exactly 2 girls

Probability of exactly 3 girls

Probability of exactly 4 girls

Probability of exactly 5 girls

Probability of exactly 6 girls

If we add all these probabilities, we get the probability of at least 2 girls.

To find the probabilities, we can use the formula:

[tex]_nC_r\cdot p^r(1-p)^{n-r}[/tex]

Where:

n is the number of trials (in this case, the number of total births)

r is the number of girls we want to find the probability

p is the probability of the event occurring

[tex]_nC_r\text{ }is\text{ }the\text{ }combinatoric\text{ }"n\text{ }choose\text{ }r"[/tex]

The formula for "n choose r" is:

[tex]_nC_r=\frac{n!}{r!(n-r)!}[/tex]

Then, let's find the probability of exactly 2 girls:

The probability of the event occurring is:

[tex]P(girl)=\frac{1}{2}[/tex]

Because there is a 50% probability of being a girl or a boy.

let's find "6 choose 2":

[tex]_6C_2=\frac{6!}{2!(6-2)!}=\frac{720}{2\cdot24}=15[/tex]

Now we can find the probability of exactly 2 girls:

[tex]Exactly\text{ }2\text{ }girls=15\cdot(\frac{1}{2})^2(1-\frac{1}{2})^{6-2}=15\cdot\frac{1}{4}\cdot(\frac{1}{2})^4=\frac{15}{4}\cdot\frac{1}{16}=\frac{15}{64}[/tex]

We need to repeat these calculations for exactly 3, 4, 5, and 6 girls:

Exactly 3 girls:

let's find "6 choose 3":

[tex]_6C_3=\frac{6!}{3!(6-3)!}=\frac{720}{6\cdot6}=20[/tex]

Thus:

[tex]Exactly\text{ }3\text{ }girls=20\cdot(\frac{1}{2})^3(1-\frac{1}{2})^{6-3}=20\cdot\frac{1}{8}\cdot\frac{1}{8}=\frac{5}{16}[/tex]

Exactly 4 girls:

"6 choose 4":

[tex]_6C_4=\frac{6!}{4!(6-4)!}=\frac{720}{24\cdot2}=15[/tex]

Thus:

[tex]Exactly\text{ }4\text{ }girls=15\cdot(\frac{1}{2})^4(1-\frac{1}{2})^{6-4}=15\cdot\frac{1}{16}\cdot\frac{1}{4}=\frac{15}{64}[/tex]

Exactly 5 girls:

"6 choose 5"

[tex]_6C_5=\frac{6!}{5!(6-5)!}=\frac{720}{120}=6[/tex]

Thus:

[tex]Exactly\text{ }5\text{ }girls=6\cdot(\frac{1}{2})^5(1-\frac{1}{2})^{6-5}=6\cdot\frac{1}{32}\cdot\frac{1}{2}=\frac{3}{32}[/tex]

Exactly 6 girls:

"6 choose 6"

[tex]_6C_6=\frac{6!}{6!(6-6)!}=\frac{720}{720\cdot0!}=\frac{720}{720}=1[/tex]

Thus:

[tex]Exactly\text{ }6\text{ }girls=1\cdot(\frac{1}{2})^6(1-\frac{1}{2})^{6-6}=\frac{1}{64}\cdot(\frac{1}{2})^0=\frac{1}{64}[/tex]

now, to find the answer we need to add these 5 values:

[tex]\frac{15}{64}+\frac{5}{16}+\frac{15}{64}+\frac{3}{32}+\frac{1}{64}=\frac{57}{64}=0.890625[/tex]

To the nearest tenth, the probability of at least 3 girls is 0.891, thus, the last option is the correct one.

can you please solve this for me I'll make sure to give the best review

Answers

-9 is an integer

the location of -9 is with 41

6.3 is a repeating decimal

the location is with 5.86666...

-4/5 is a fraction

the location is with 11/12

What value n makes the eauqation n x 3/4 = 3/16

Answers

Answer:

N = 1/4

Step-by-step explanation:

Okay, so 1/4 is equal to N.

3/4 x1/4=3/16

What happens to F(x) when x is negative but approaches zero for the functionF(x) = 1/x, whose graph is shown below?

Answers

Given: The graph of the function below

[tex]F(x)=\frac{1}{x}[/tex]

To Determine: What happens to F(x) when x is negative but approaches zero

Solution:

It can be observed from the given graph that when x is negative but approaches zero, F(x) approaches negative infinity

This is as shown below

From the options provided, the best answer is F(x) is a negative number, OPTION C

Tank B, which initially contained 80 liters of water, is being drained at a rate of 2.5 liters per minute. How many liters of water remain in the tank after 7 minutes?

Answers

Tank B originally had 80 liters of water.

Water is being drained off the tank at a rate of 2.5 liters per minute.

After 7 minutes have passed, the tank has lost 7*2.5 = 17.5 liters of water.

This means the tank still has 80 - 17.5 = 62.5 liters of water.

After 7 minutes 62.5 liters of water remain in the tank

Chen is opening a new account with a $1,200 deposit. She will be keeping money in the account, compounded monthly for no more than 3 years. the formula gives the value, V, of the account as a function of time, t. Which is a reasonable domain of this function?V(t)= 1,200(1 + 0.02)^t/12A) 0< or equal to t < or equal to 36B) 0C) 0 < or equal to t < or equal to 1,273.45D) 1,200 < or equal to t < or equal to 1,273.45

Answers

The Solution:

Given the function:

[tex]V(t)=1200(1+0.02)^{\frac{t}{12}}[/tex]

We are required to find a reasonable domain for the given function.

The domain of the function V(t) is the range of values for t.

The question says Chen is will continue to keep money in the account for not more than 3 years, but the interest will be compound monthly.

Recall:

1 year = 12 months

So,

3 years will be

[tex]12\times3=36\text{ months}[/tex]

This means that the range of values for t is:

[tex]0\leq t\leq36[/tex]

Therefore, the correct answer is [option A]

The area of Bryce is 71.5 sq units.what is the area of abcd?

Answers

Solution

Step 1:

Area of BXYC = 71.5 square units

Step 2:

The area of ABCD is twice the area of BXYC

Step 3:

[tex]\begin{gathered} \text{Area of ABCD = 2 }\times\text{ Area of BXYC} \\ Area\text{ of ABCD = 2 }\times\text{ 71.5} \\ Area\text{ of ABCD = 143 square units} \end{gathered}[/tex]

5. The domain of f(x) = -2x + 1 is {-4, -1, 0, 2}. Find the range.

Answers

Answer: Range = { 9, 3, 1, -3}

Explanation:

The function is f(x) = -2x + 1

Domain = {-4, -1, 0, 2}

Note that the domain is a set of of all the values of x ( i.e. the independent variable)

The range is a set of the corresponding value of f(x) for each value of x in the domain.

For x = -4

f(-4) = -2(-4) + 1 = 8 + 1

f(-4) = 9

f(-1) = -2(-1) + 1 = 2 + 1

f(-1) = 3

f(0) = -2(0) + 1 = 0 + 1

f(0) = 1

f(2) = -2(2) + 1 = -4 + 1

f(2) = -3

Therefore the set of all the values above which is the range will be given as:

Range = { 9, 3, 1, -3}

find the reference angle for -0.8pi

Answers

Answer:

What is Meant by the Reference Angle? In mathematics, the reference angle is defined as the acute angle and it is measuring less than 90 degrees. It is always the smallest angle, and it makes the terminal side of an angle with the x-axis.

A tee box is 48 feet above its fairway. When a golf ball is hit from the tee box with an initial vertical velocity of 32 ft/s, the quadratic equation 0 = -16t^2+ 32t +48 givesthe time t in seconds when a golf ball is at height 0 feet on the fairway.What is the height of the ball at 1 second and is the ball at its maximum height at 1 second (explain)?

Answers

Answer:

Step by step explanation:

write an algebraic model for the statement then solve the model the sum of a number and -9 is -21

Answers

Answer:

[tex]x + ( - 9) = - 21[/tex]

[tex]x - 9 = - 21[/tex]

[tex]x = - 12[/tex]

Find the slope of line segment AB where the coordinates of A are
(3,-3) and B are (1,2).

A: -2/5
B: -5/2
C: 2/5
D: 5/2

Answers

The answer is C because you use the slope formula to find the coordinates.
The slope formula is y2-y1 over x2-x1 from there you should get your answer. Hope this helps.

Graph the solution to the following system of inequalities.y>3x+7y≤−3x-8

Answers

Step 1. Graphing the first inequality.

The first inequality is:

[tex]y>3x+7[/tex]

to graph this, we need to graph the line 3x+7, which compared with the slope-intercept equation

[tex]y=mx+b[/tex]

where m is the slope and b is the y-intercept, the line

[tex]y=3x+7[/tex]

is a line with a slope of 3 and a y-intercept at 7:

SInce the inequality is:

[tex]y>3x+7[/tex]

The solution just for this inequality are the values greater than the red line, but not including the red line so we represent is a dotted line and a shaded part above:

Step 2. Graph the second inequality.

The second inequality is:

[tex]y\le-3x-8[/tex]

As we did with the first inequality, we graph the line -3x-8 first.

comparing -3x-8 with the slope-intercept equation:

[tex]y=mx+b[/tex][tex]y=-3x-8[/tex]

we can see that the slope m is -3 and the y-intercept b is -8. This line is shown in blue in the following diagram along with our results for the previous inequality:

Since the inequality form is:

[tex]y\le-3x-8[/tex]

We shade the values below this blue line:

The final solution will be the intersection between the red part and the blue part:

Takashi is driving to his grandmother's house. he is driving at a constant speed and will not make any stops along the way. Takashi’s distance in miles from his grandmother’s house h hours after leaving can be described by equationA. Identify and interpret the independent variable? B. Identify and interpret the coefficient? C. Identify and interpret the constant term ?D. Identify and interpret the dependent variable?

Answers

Let's begin by listing out the information given to us:

To calculate Takashi's distance from his grandmother's house is given by the formula:

[tex]\begin{gathered} distance=speed\cdot time \\ h=v\cdot t \end{gathered}[/tex]

Independent variable refers to the variable that stands by itself and whose value is not affected by the other

Dependent variable refers to the variable whose value is affected by the value of another variable

A. The distance (h) does not change irrespective of Takashi's speed, hence it is the independent variable

B. The coefficient is the speed (v)

C. The constant is time (t)

D. The speed (v) changes with variation in time, hence it is the dependent variable

David’s watch broke. He decides to get it fixed instead of replacing it. Since David is a loyal customer, he received a coupon in the mail for a discount. The total cost to repair the watch can be represented by 0.07r + (r – 20), where r represents the original cost of the repair. Explain what each part of the expression represents in the context of the problem.

Answers

→ r represents the original cost of the repair.

→ 0.07r represents the tax.

→ (r – 20) represents the discount

Given,

The total cost to repair the watch can be represented by 0.07r + (r – 20), where r represents the original cost of the repair.

Explain what each part of the expression represents in the context of the problem.

Now, According to the question:

Given the following algebraic expression:

0.07r + (r – 20)

In the context of fixing David’s broken watch, the variable r represents the original cost of the repair while 0.07r most likely represents the amount of money charged as tax. Lastly the expression (r – 20) represents the discount on fixing David’s broken watch.

What each part of the expression represents in the context of the problem include the following:

→ r represents the original cost of the repair.

→ 0.07r represents the tax.

→ (r – 20) represents the discount

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In Square ABCD, AE = 3x + 5 and BD = 10x + 2.What is the length of AC?

Answers

Let's begin by identifying key information given to us:

We have square ABCD

[tex]\begin{gathered} AE=3x+5 \\ BD=10x+2 \\ BD=2\cdot AE \\ 10x+2=2(3x+5) \\ 10x+2=6x+10 \\ \text{Put like terms together, we have:} \\ 10x-6x=10-2 \\ 4x=8 \\ \text{Divide both sides by ''4'', we have:} \\ \frac{4x}{4}=\frac{8}{4} \\ x=2 \\ \\ \end{gathered}[/tex]

For a square, the diagonals are equal, AC = BD

[tex]\begin{gathered} AC=BD \\ AC=10x+2 \\ x=2 \\ AC=10(2)+2=20+2 \\ AC=22 \end{gathered}[/tex]

WILL GIVE BRIANLYEST 100 POINTS ACULLY 200 BC IM GIVING EXTRA POINTS

Answers

Answer:

the mean would increase to a value to about 24.6

Q2: median is 7.

Step-by-step explanation:

Answer:

Q1) the mean would increase in value to about 24.6

Q2) 7

There are 39 chocolates In a box call identically sheet dear 16 off filled with nuts 13 with caramel and 10 are solid chocolate you randomly select one piece eat it and then select a second piece find the probability of selecting to solid in a row

Answers

The probability of selecting two solid chocolates in a row is 0.0607 .

In the question ,

it is given that

there are total 39 chocolates in the box .

number of chocolates filled with nuts = 16

number of chocolates filled with caramel = 13

number of chocolates filled with solid = 10

Probability of selecting first chocolate as a solid is  10/39.

Now , there are 38 chocolates , with 9 solid chocolates ,

hence the probability of selecting second chocolate as a nut is = 9/38

So, the probability of selecting two solid chocolates in a row = 10/39×9/38

= 90/1482

= 0.0607

Therefore , the probability of selecting two solid chocolates in a row is 0.0607 .

The given question is incomplete , the complete question is

There are 39 chocolates in a box, all identically shaped. There 16 are filled with nuts, 13 with caramel, and 10 are solid chocolate. You randomly select one piece, eat it, and then select a second piece. Find the probability of selecting 2 solid chocolates in a row.

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tristan asked his coworkers about how much time they spent commuting each morning Find the median

Answers

SOLUTION

In a box and whisker plot, the firt dot on the box is Q1

The second dot on the box is Q2

The third dot on the box is Q3

Q2 is the median

From what we see,

[tex]Q2=25[/tex]

Hence the answer is 25, option D

Ana has $75 and saves an additional $13 per week. Which equation can be used to findhow many weeks it will take until she has $452?75 + w = 4520 75 + 13w = 45213w = 75 = 452452 + 13w = 75

Answers

[tex]\begin{gathered} \text{The equation is;} \\ 75\text{ + 13w = 452} \end{gathered}[/tex]

Here, we want to get an equation

Firstly, since we do not have the number of weeks, we can represent it with a variable (a letter)

In this case, we shall be representing it with w

Since she saves $13 in a week, in w weeks, the amount saved will be;

13 * w = $13w

Now, recall that she has $75 before she started saving. What this mean is that at the end of the w weeks, the amount she will have will be ;

[tex]13w\text{ + 75}[/tex]

We now proceed to equate this to the total she wants to save and we finally have the complete equation below;

[tex]13w\text{ + 75 = 452}[/tex]

Write an equation of the line that passes through (4, 3) and is parallel to the line defined by 5x-2y-3. Write the answer in slope-intercept form (if possible)
and in standard form (Ax+By-C) with smallest integer coefficients. Use the "Cannot be written" button, if applicable.

Answers

The final answer to the question is highlighted in the box

How many angles and sides are there in a Heptagon?ANGLES:SIDES:

Answers

The heptagon is a polygon of 7 sides and 7 angles

The heptagon is a closed figure formed from 7 sides

Since every 2 sides connected to form an angle, then

It contains also 7 angles

Then the answer is :

Angles: 7

Sides: 7

HELP ASAPwrite an expression to represent:"the sum of a number b and 24"

Answers

The sum of a number 'b' and 24 can be written like this:

[tex]b+24[/tex]

What is the sign of mlio Choose 1 answer: Positive Negative Neither positive nor negative the sum is zero.

Answers

[tex]\frac{3}{5}+\frac{3}{5}=\frac{6}{5}[/tex]

The sign will be positive.

can u pls help me with this question and this is homework

Answers

the probability is:

[tex]\frac{15+5}{50}=\frac{20}{50}=\frac{2}{5}[/tex]

so the answer is 2/5

I need to find the equation of a circle I will include picture

Answers

Given,

The center of the circle is (6, -3).

The coordinates of the point, circle is passing through (6,6).

The general equation of the circle is,

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Here, x, y are the coordinates of the point.

h and k are the center of the circle.

r is the radius of the circle.

Substituting the value of h, k , x and y in the equation of circle then,

[tex]\begin{gathered} (6-6)^2+(6-(-3))^2=r^2 \\ 0+9^2=r^2 \\ r=9 \end{gathered}[/tex]

So, the radius of the circle is 9.

Substituting the value of h, k and r in the general equation of circle.

[tex]\begin{gathered} (x-6)^2+(y-(-3))^2=9^2 \\ x^2+36-12x+y^2+9+6y=81 \\ x^2+y^2-12x+6y-36=0 \end{gathered}[/tex]

Hence, the equation of circle is x^2+y^2-12x+6y-36=0

using the converse of the same-side interior angles postulate what equation shows that g∥h

Answers

Answer: [tex]\angle 2+\angle 4=180^{\circ}[/tex] or [tex]\angle 1+\angle 3=180^{\circ}[/tex]

Decompose the fraction 11 /12 towingtwo ways

Answers

Given:-

[tex]\frac{11}{12}[/tex]

To find:-

Decompose the fraction in two ways.

Way one,

[tex]\frac{11}{12}=\frac{5}{12}+\frac{6}{12}[/tex]

Way two,

[tex]\frac{11}{12}=\frac{10}{24}+\frac{12}{24}[/tex]

On a particular day, the amount of untreated water coming into the plant can be modeled by f(t) = 100 + 30cos(t/6) where t is in hours since midnight and f(t) represents thousands of gallons of water. The amount of treated water at any given time, t, can be modeled by g(t) = 30e^cos(t/2)a) Define a new function, a′(t), that would represent the amount of untreated water inside the plant, at any given time, t.b) Find a′ (t).c) Determine the critical values of this function over the interval [0, 24).

Answers

a)The amount of untreated water inside the plant will be the difference between the difference f(t) - g(t), then, a(t) can be defined as follows:

[tex]a(t)=100+30cos(\frac{t}{6})-30e^{cos(\frac{t}{2})}[/tex]

b) the derivative of a(t) is the following:

[tex]a^{\prime}(t)=-5sin(\frac{t}{6})+15sin(\frac{t}{2})e^{cos(\frac{t}{2})}[/tex]

c) the critical values of a(t) over the interval [0, 24) are:

[tex]\begin{gathered} t=0 \\ t=6\pi \end{gathered}[/tex]

15. x=m<1=I'll upload a picture of my HW

Answers

Opposite angles are the same

Then:

[tex]\begin{gathered} 6x+4=8x\text{ - }18 \\ 18+4=8x\text{ -}6x \\ 22=\text{ 2x} \\ x=\text{ 22/2} \\ x=11 \end{gathered}[/tex]

So: (Remember the line has a 180º degrees

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