determine the point and slope that were used to write each linear equation in point slope form
Answers
The slope-point form is:
[tex]y-y_0=m(x-x_0)[/tex]where (x0,y0) is a point in the line and m is the slope.
A) If the equation is written in slope-point form, we have:
[tex]y-0=2(x-5)[/tex]Then, the point is (5,0) and the slope is m=2.
Answer: Point = (5,0)
Slope = 2
B)
[tex]\begin{gathered} y+3=5x \\ y-(-3)=5(x-0) \end{gathered}[/tex]Answer: Point (0,-3)
Slope = 5
Related Questions
Four friends participated in a free contest for charity. Erin scored 4 less points than Taylor. Nya scored three times as many points as Erin. Aaron scored 10 more points than Nya. Together the four friends scored a total of 158 points. Find how many points each friend made :How many points Taylor scored :Erin scored : Nya scored :Aaron scored:
Answers
Taylor's scored 22 points
Erin scored 18 points
Nya scored 54 points
Aaron scored 64 points
Explanation:Let Taylor's point = x
Erin scored 4 less points than Taylor:
Erin's score = x - 4
Nya scored three times as many points as Erin:
Nya's score = 3(x - 4)
Aaron scored 10 more points than Nya:
Aaron's score = Nya's score + 10
= 3(x - 4) + 10
The total score of the four friend = 158 points
Taylor's score + Erin's score + Nya's score + Aaron's score = 158
x + (x - 4) + 3(x -4) + 3(x-4) + 10 = 158
Expand the parenthesis:
x + x -4 + 3x - 12 + 3x - 12 + 10 = 158
collect like terms:
x + x + 3x + 3x - 4 - 12 - 12 + 10 = 158
8x - 18 = 158
8x = 158 + 18
8x = 176
Divide both sides by 8:
8x/8 = 176/8
x = 22
Taylor's scored 22 points
Erin scored : x-4 = 22- 4 = 18 points
Nya scored : 3(x-4) = 3(22-4) = 3(18) = 54 points
Aaron scored: 3(x-4) + 10 = 54 + 10 = 64 points
Find the coordinates of point p that partition AB in the ratio 1: 4,
Answers
Given:
[tex]A(1,-1)\text{ ; B(}4,4)\text{ m:n =1:4}[/tex][tex](x,y)=(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})[/tex][tex](x,y)=(\frac{4+4}{1+4},\frac{4-4}{1+4})[/tex][tex](x,y)=(\frac{8}{5},0)[/tex]Therefore the point P be ( 1.6 ,0)
You have an investment account that has a balance of $50,000. If the account iscompounded daily and has an interest rate of 4%, how much did you originally depositinto the account 10 years ago?
Answers
Since we know the future alue of the account, using the formula for the compounded interest with n = 365 (since the account is compounded daily), t=10, r = 4% and A=50000 in the following equation:
[tex]A=P(1+\frac{r}{n})^{n\cdot t}[/tex]using these values and solving for P, we get:
[tex]\begin{gathered} 50000=P(1+\frac{0.04}{365})^{365\cdot10} \\ \Rightarrow P=\frac{50000}{(1+\frac{0.04}{365})^{3650}}=33516.74 \\ P=33,516.74 \end{gathered}[/tex]therefore, the original amount deposited 10 years ago is $33,516.74
the circle below has center E. Suppose that m
Answers
Notice that the triangle △GEF is an isosceles triangle, since GE=EF (both sides are radii of the circle).
Since △GEF is an isosceles triangle with GE=EF, then the measure of the angles opposed to those sides is the same:
[tex]m\angle GFE=m\angle EGF[/tex]Since the line FH is tangent to the circle, the angle ∠HFE is a right angle.
Since ∠HFG and ∠GFE are adjacent angles, then:
[tex]m\angle\text{HFG}+m\angle\text{GFE}=m\angle\text{HFE}[/tex]Substitute m∠HFG=62 and m∠HFE=90 to find m∠GFE:
[tex]\begin{gathered} 62+m\angle\text{GFE}=90 \\ \Rightarrow m\angle GFE=28 \end{gathered}[/tex]Since the sum of the internal angles of any triangle is 180 degrees, then:
[tex]m\angle\text{GFE}+m\angle\text{EGF}+m\angle\text{FEG}=180[/tex]Substitute the values of m∠GFE and m∠EGF:
[tex]\begin{gathered} 28+28+m\angle\text{FEG}=180 \\ \Rightarrow\angle FEG=124 \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} \text{m}\angle\text{FGE}=28 \\ m\angle FEG=124 \end{gathered}[/tex]If f(x)=x squared + 3x - 10 then over which of the following intervals is f(x)<0 ?
Answers
Given data:
The given function is f(x)= x^2 +3x-10.
The given inequality is,
[tex]\begin{gathered} f(x)<0 \\ x^2+3x-10<0 \\ x^2+5x-2x-10<0 \\ x(x+5)-2(x+5)<0 \\ (x+5)(x-2)<0 \\ -5Thus, the value of x is -5How to draw the graphs of the following non-linear functions?y=x^2 + 1y=3^x + 1
Answers
The first step is to substitute values of x into each equation.
For y = x^2 + 1,
if x = - 2, y = (- 2)^2 + 1 = 4 + 1 = 5
if x = - 1, y = (- 1)^2 + 1 = 1 + 1 = 2
if x = 0, y = (0)^2 + 1 = 0 + 1 = 1
if x = 1, y = (1)^2 + 1 = 1 + 1 = 2
if x = 2, y = (2)^2 + 1 = 4 + 1 = 5
We would plot the corresponding values of x and y on the graph as shown below
For y = 3^(x + 1),
if x = - 2, y = 3^(-2 + 1) = 3^-1 = 0.33
if x = - 1, y = 3^(-1 + 1) = 3^0 = 1
if x = 0, y = 3^(0 + 1) = 3^1 = 3
if x = 1, y = 3^(1 + 1) = 3^2 = 9
if x = 2, y = 3^(2 + 1) = 3^3 = 27
We would plot the corresponding values of x and y on the graph as shown below
True or False. The graph is linear, but not proportional.
Answers
Answer:
True.
The graph is linear, but not proportional.
Explanation:
Given the graph in the attached image;
The graph is linear because it is a straight line graph.
A linear graph is always straight.
A proportional relationship in which the two components have a constant ratio.
The proportional graph is a straight line graph that passes through the origin (0,0).
Since the given graph does not pass through the origin, it is not a proportional graph.
Therefore, The graph is linear, but not proportional.
Help me out please I don’t understand what I’m doing
Answers
Since we have the value for selling each shirt, the earnings that came from the hats sold and the total earnings we can complete equation using a linear equation in which the cost of each shirt will represent the slope and the y-intercept will be the earnings that came from the hats, like this:
[tex]5x+40=125[/tex]then clear the equation for x in order to find how many shirts were sold
[tex]\begin{gathered} 5x=125-40 \\ 5x=85 \\ x=17 \end{gathered}[/tex]The area of an equilateral triangle is decreasing at a rate of 3 cm2/min. Find the rate (in centimeters per minute) at which the length of a side is decreasing when the area of the triangle is 100 cm2.
Answers
The rate at which the length of a side is decreasing when the area of the triangle is 100 cm² is equal to -0.227 centimeters per minute.
What is rate of change?Rate of change is a type of function that describes the average rate at which a quantity either decreases or increases with respect to another quantity.
How to calculate the area of an equilateral triangle?Mathematically, the area of an equilateral triangle can be calculated by using this formula;
A = (√3/4)s²
Where:
A represents the area of an equilateral triangle.s represents the side length of an equilateral triangle.Next, we would determine the side length of a square by making s the subject of formula as follows:
s = (√4A)/√3
s = (√4 × 100)/√3
Side length, s = 15.20
Note: The rate of change (dA/dt) is negative because it is decreasing.
By applying chain rule of differentiation, the rate of change (dA/dt) in area of this equilateral triangle with respect to time is given by:
dA/dt = (√3/4)(2s)ds/dt
dA/dt = (√3/4) × (2 × 15.20) × -3
dA/dt = -0.227 centimeters per minute.
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12 = - 2/5 yI got -30 I want to see if I did the correct steps
Answers
Solution
[tex]12=-\frac{2}{5}y[/tex]Step 1: Simplify the expression
[tex]\begin{gathered} 12=-\frac{2}{5}y \\ \text{cross multiply} \\ 12(5)=-2y \\ 60=-2y \end{gathered}[/tex]Step 2: Divide the both side by -2
[tex]\begin{gathered} 60=-2y \\ \frac{60}{-2}=-\frac{2y}{-2} \\ y=-30 \end{gathered}[/tex]Therefore the correct value of y = - 30
Add these fractions using fraction bars after choosing a common denominator Use the fraction bar inactivate to find the difference
Answers
The fractions you have to add are 1/3 and -5/6
[tex]\frac{1}{3}+(-\frac{5}{6})[/tex]The denominators are "3" and "6"
The common denominator between both numbers is 6.
6*1=6
3*2=6
Multiply 1/3 by factor 2 so that both fractions will have the same denominator
[tex]\frac{1}{3}\cdot2=\frac{1\cdot2}{3\cdot2}=\frac{2}{6}[/tex]Now you can add both fractions
[tex]\frac{2}{6}+(-\frac{5}{6})=\frac{2}{6}-\frac{5}{6}=\frac{2-5}{6}=-\frac{3}{6}[/tex]The result is not in its most reduced form, to siplify the fraction divide both the numerator and denominator by 3
[tex]-\frac{3}{6}\div3=-\frac{1}{2}[/tex]The result is -1/2, in the number line:
The crew knows the amount of dirt the truck can hold each trip in cubic yards.
Answers
Given:
Measurements of hole are 48ft 39ft and and 9ft
Required:
Volume in cubic yd
total number of trip
total cost of trip
Explanation:
First we need to convert given measurements from ft to yd
[tex]\begin{gathered} 3ft=1yd \\ 48ft=16yd \\ 39ft=13yd \\ 9ft=3yd \end{gathered}[/tex]
A)
[tex]V=lhw=16*13*3=624yd^3[/tex]B)
11 cubic yd in 1 trip
then
624 cubic yd in x trip
[tex]x=\frac{624}{11}=56.7\approx57[/tex]C)
cost for 1 trip is $1175
then
cost for 57 trip is y
[tex]y=57*1175=66975[/tex]Final answer:
Volume in cubic yd is 624
total number of trips is 57
total cost of trip $66975
Find a degree 3 polynomial with real coefficients having zeros 3 and 1 - 32 and a lead coefficient of 1.
Write Pin expanded form. Be sure to write the full equation, including P(x)
Answers
The polynomial function of least degree with only real coefficients will be; y = x³ - 8 · x² + 22 · x - 20.
What is polynomial ?Algebraic expressions called polynomials include constants and indeterminates. Polynomials can be thought of as a type of mathematics.
The statement indicates that the polynomial has real coefficients having zeros 3 and 1 - 32 and a lead coefficient of 1.
By algebra of quadratic equations, equations with real coefficients with complex roots are α + i β and α - i β. Then we get;
y = 1 · (x - 3) · (x - 3 - i) · (x - 3 + i)
y = (x - 3) · [x² - 3 · x - i · x - 3 · x + i · x + (3 + i) · (3 - i)]
y = (x - 3) · (x² - 6 · x + 9 - i²)
y = (x - 3) · (x² - 6 · x + 10)
y = x³ - 6 · x² + 10 · x - 2 · x² + 12 · x - 20
y = x³ - 8 · x² + 22 · x - 20
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Answer:
[tex]p(x)=x^3-5x^2+16x-30[/tex]
Step-by-step explanation:
Given information:
Degree 3 polynomial with real coefficients.Zeros: 3 and (1 - 3i).Lead coefficient of 1.For any complex number [tex]z = a+bi[/tex] , the complex conjugate of the number is defined as [tex]z^*=a-bi[/tex].
If f(z) is a polynomial with real coefficients, and z₁ is a root of f(z)=0, then its complex conjugate z₁* is also a root of f(z)=0.
Therefore, if p(x) is a polynomial with real coefficients, and (1 - 3i) is a root of p(x)=0, then its complex conjugate (1 + 3i) is also a root of p(x)=0.
Therefore, the polynomial in factored form is:
[tex]p(x)=a(x-3)(x-(1-3i))(x-(1+3i))[/tex]
As the leading coefficient is 1, then a = 1:
[tex]p(x)=(x-3)(x-(1-3i))(x-(1+3i))[/tex]
Expand the polynomial:
[tex]\implies p(x)=(x-3)(x-(1-3i))(x-(1+3i))[/tex]
[tex]\implies p(x)=(x-3)(x-1+3i)(x-1-3i)[/tex]
[tex]\implies p(x)=(x-3)(x^2-x-3xi-x+1+3i+3ix-3i-9i^2)[/tex]
[tex]\implies p(x)=(x-3)(x^2-x-x-3xi+3ix+1+3i-3i-9i^2)[/tex]
[tex]\implies p(x)=(x-3)(x^2-2x+1-9(-1))[/tex]
[tex]\implies p(x)=(x-3)(x^2-2x+10)[/tex]
[tex]\implies p(x)=x^3-2x^2+10x-3x^2+6x-30[/tex]
[tex]\implies p(x)=x^3-2x^2-3x^2+10x+6x-30[/tex]
[tex]\implies p(x)=x^3-5x^2+16x-30[/tex]
distance of (-5,-3) and (-9,4)
Answers
Answer:11
Step-by-step explanation:
Consider the following functions round your answer to two decimal places if necessary
Answers
Solution
Step 1:
[tex]\begin{gathered} f(x)\text{ = }\sqrt{x\text{ + 2}} \\ \\ g(x)\text{ = }\frac{x-2}{2} \end{gathered}[/tex]Step 2
[tex]\begin{gathered} (\text{ f . g\rparen\lparen x\rparen = }\sqrt{\frac{x-2}{2}+2} \\ \\ (\text{ f . g\rparen\lparen x\rparen }=\text{ }\sqrt{\frac{x\text{ +2}}{2}} \end{gathered}[/tex]Step 3
Domain definition
[tex]\begin{gathered} The\:domain\:of\:a\:function\:is\:the\:set\:of\:input\:or\:argument\:values \\ \:for\:which\:the\:function\:is\:real\:and\:defined. \\ \mathrm{The\:function\:domain} \\ x\ge \:-2 \\ \\ \:\mathrm{Interval\:Notation:}\text{ \lbrack-2, }\infty) \end{gathered}[/tex]Final answer
Solve each word problem using a system of equations. Use substitution or elimination. 1. One number added to three times another number is 24. Five times the first number added to three times the other number is 36.
Answers
ANSWER
The first number is 3 and the second number is 7
EXPLANATION
Let the first number be x.
Let the second number be y.
The first line of the word problem is:
One number added to three times another number is 24.
This means that:
x + 3(y) = 24
=> x + 3y = 24 ______(1)
The second line of the word problem is:
Five times the first number added to three times the other number is 36.
5(x) + 3(y) = 36
5x + 3y = 36 ______(2)
Now, we have a system of equations:
x + 3y = 24 ____(1)
5x + 3y = 36 ___(2)
From the first equation, we have that:
x = 24 - 3y
Substitute that into the second equation:
5(24 - 3y) + 3y = 36
120 - 15y + 3y = 36
Collect like terms:
-15y + 3y = 36 - 120
-12y = -84
Divide through by -12:
y = -84 / -12
y = 7
Recall that:
x = 24 - 3y
=> x = 24 - 3(7) = 24 - 21
x = 3
Therefore, the first number is 3 and the second number is 7.
The table shows a proportional relationship.
x 12 8 24
y 3 2 6
Describe what the graph of the proportional relationship would look like.
A line passes through the point (0, 0) and continues through the point (3, 12).
A line passes through the point (0, 0) and continues through the point (2, 8).
A line passes through the point (0, 0) and continues through the point (6, 24).
A line passes through the point (0, 0) and continues through the point (12, 3).
Answers
The graph of the proportional relationship would look like A line passes through the point (0, 0) and continues through the point (12, 3).
What is Graph?Graph is a mathematical representation of a network and it describes the relationship between lines and points.
A proportional relationship graph between two variables is a relationship where the ratio between the two variables is always the same.
The given table is
x 12 8 24
y 3 2 6
The graph of the proportional relationship would look like.
A line passes through the point (0, 0) and continues through the point (12, 3).
In the ordered pair the first value represents the x axis value and second value represents the y value. The ordered pair (12, 3) is coordinated with the values of x and y in the table.
Hence the graph of the proportional relationship would look like A line passes through the point (0, 0) and continues through the point (12, 3).
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What is a stem and leaf plot? How is it used and how exactly do i solve one? (an example would be great)
Answers
A stem and leaf plot is a table where each of the data is divided into two parts. The stem, that is the first digit and the leaf is the last digits. Let's say that we have the following set of data.
[tex]10,\text{ 12, 25, 28, 29, 35, 38, 40, 44}[/tex]If we want to make a stem and leaf plot of that data, we first write a column where we place the first digit of each number without repetition, like this:
[tex]\begin{gathered} 1 \\ 2 \\ 3 \\ 4 \end{gathered}[/tex]These are the stems. Now the leaves are the last digit of each number put in order next to the corresponding first digit, like this:
[tex]\begin{gathered} 1\parallel\text{ 0 2} \\ 2\parallel\text{ 5 8 9} \\ 3\text{ }\parallel\text{5 8} \\ 4\text{ }\parallel\text{0 4} \end{gathered}[/tex]solve the system by addition method x + 4y = 34x + 5y = - 10
Answers
y = 2
so,
x + 4 * 2 = 3
x = 3 - 4 * 2 = 3 - 8 = -5
so,
x = -5 and y = 2
Suppose the population of a certain city is 5700 thousand. It is expected to decrease to 4823 thousand in 50 years. Find the percent decrease.Around to the nearest tenth
Answers
We can calculate a percent change by calculating the difference between the actual state and the previous state and then dividing this difference by the previuos state.
Finally, multypling by 100% gives the percentage change.
Here we have the last state as the future population (4823 thousand people). The actual state (in this case the state to which wew want to compare the variation ir change) is 5700 thousand people.
The difference is 4823 - 5700 = -877.
Then, we can divide it by the actual population and we will have:
[tex]\frac{4823-5700}{5700}=\frac{-877}{5700}\approx0.1538[/tex]This is equivalent to:
[tex]01538\cdot100\%=15.38\%[/tex]If we have to round to nearest tenth, the percent change is 15.4%.
Tank A contains a mixture of 10 gallons of water and 5 gallons of pure alcohol tank b has 12 gallons of what and 3 gallons of alcohol how many gallons should be taken from each tank and combiend in order to obtain 8 gallons of a solution countaning 25% alcohol
Answers
The volume from tanks A and B are taken as 3 and 5 gallons respectively.
Here,
Let the volume taken from tank A and tank B be x and y.
According to the question,
x + y = 8 - - - - - (1)
And
Composition of the alcohol in Tank A = 1/3
Composition of the alcohol in tank B = 1 /5
x / 3 + y / 5 = 8 / 4
5x + 3y = 30
From equation 1
5(y8 - y) + 3y = 30
-5y + 40 + 3y = 30
-2y = -10
y = 5
Now, put y in equation 1
x = 8 - 5
x = 3
Thus, the Volume from tanks A and B are taken as 3 and 5 gallons respectively.
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C) 1) if Z1 and 22 are complementary angles, and mZ1 = 74°; find m22.
Answers
Answer:
16
Explanation:
The angles ∠1 and ∠2 are complementary, meaning
[tex]\angle1+\angle2=90^o[/tex]Visually,
Now, ∠1 = 74; therefore,
[tex]74^o+\angle2=90^o[/tex]subtracting 74 from both sides gives
[tex]\angle2=90^o-74^o[/tex][tex]\angle2=16^o[/tex]which is our answer!
What is the solution to14h + 6 = 2(5 + 7h) - 4 ?
Answers
14h + 6 = 2(5 + 7h) - 4
First , apply distributive porperty to solve the parentheses:
14h+6 =2(5)+2(7h)-4
14h+6 = 10+14h-4
Move the "h " terms to the left:
14h-14h = 10-4-6
0 = 0
h has infinite solutions.
3.) Write the explicit formula for the arithmetic sequence. 50, 47, 44, 41,...
Answers
all the terms are 3 less than its preceding term, simple!
So, the formula would be:
[tex]a_n=a+(n-1)d[/tex]Where
a is the first term
d is the common difference (diff in 2 terms)
From the sequnce,
first term (a) is 50
common difference (d) = 47 - 50 = -3
So, we have:
[tex]\begin{gathered} a_n=a+(n-1)d \\ a_n=50+(n-1)(-3_{}) \\ a_n=50-3n+3 \\ a_n=53-3n \end{gathered}[/tex]Explicit Formula:
[tex]a_n=53-3n[/tex]If a car in 3 hours travels 156 miles, what is the speed of the car in miles per hour?
Answers
To calculate the speed a vehicle is traveling you have to use the following formula:
[tex]S=\frac{d}{t}[/tex]Where
S: speed
d: distance
t: time
The car traveled d=156miles in t=3hs
Its speed can be calculated as:
[tex]\begin{gathered} S=\frac{156}{3} \\ S=52 \end{gathered}[/tex]The car's speed was 52 miles per hour
Which points are included in the solution Set of the systems of equations graphed below?
Answers
Given:
Required:
We need to find the points are included in the solution
Explanation:
Recall that the solution of the system of inequalities is the intersection region of all the solutions in the system.
The points G and F lie inside the intersection.
The points in the solution are G and F.
Final answer:
Points F and G.
Need help asap !! Thank you
Answers
The coordinate of the x-intercept and y-intercept will be (-3, 0) and (0, -2), respectively.
What is a linear equation?A connection between a set of variables results in a linear system when presented on a graph. The variable will have a degree of only one.
The linear equation is given below
- 2x - 3y = 6
For the x-intercept, the value of the y will the zero. Then we have
- 2x - 3(0) = 6
-2x = 6
x = -3
The x-intercept is at (-3, 0).
For the y-intercept, the value of the x will the zero. Then we have
- 2(0) - 3y = 6
-3y = 6
x = -2
The y-intercept is at (0, -2).
Thus, the coordinate of the x-intercept and y-intercept will be (-3, 0) and (0, -2), respectively.
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Last month, Ebony had 110 dollars in achecking account. The current balance is146 dollars. What is the percent change inthe account balance from last month to thismonth? Round your answer to the nearest whole percent.
Answers
Problem
Last month, Ebony had 110 dollars in a
checking account. The current balance is
146 dollars. What is the percent change in
the account balance from last month to this
month? Round your answer to the nearest whole percent.
Solutiion
For this case we can use the following formula:
[tex]\text{Change}=\frac{\text{Actual}-\text{Before}}{\text{Before}}\cdot100[/tex]And replacing we got:
[tex]\text{Change}=\frac{146-110}{110}\cdot100=32.72[/tex]And then the answer wounded to the nearest percent would be:
33%
The Ruiz family took a summer trip.
In 4 days, they drove 1,600 miles. If they drove an equal
number of miles each day, how many miles did they drive
each day? Describe the basic fact you use to find your
answer and how many zeros you add from the dividend.
Answers
Answer:
400 miles each day
Step-by-step explanation:
You have 1600 miles divided into four days.
1600 / 4
We can use the basic fact that multiplying a number by ten simply means shifting everything to the left, for example 2 x 10 = 20, we just shifted 2 to the left and inserted a 0.
So for this problem, we can do the same. Divide 1600 by 100, or 10 x 10, then divide by 4.
1600/16 = 100
16/4 = 4.
Now, since we divided by ten twice before, we can get the right answer by multiplying by ten twice.
4 x 10 = 40
40 x 10 = 400
Show all five steps of the hypothesis test. You can either type them in here, or write them out on paper and send me a scan/picture of your work.The average movie ticket in 2010 cost $7.89. A random sample of 15 movie tickets from the suburbs of a large U.S. city indicated that the mean cost was $11.09 with a standard deviation of $4.86. At the 0.01 level of significance, can it be concluded that the mean in this area is higher than the national average?
Answers
Step 1
State the null and alternative hypothesis
[tex]\begin{gathered} H_o=7.89 \\ H_a>7.89 \end{gathered}[/tex]Step 2
State the p-value of the significance level.
[tex]\begin{gathered} \alpha=0.01 \\ p=\frac{\alpha}{2}=\frac{0.01}{2}=0.005 \end{gathered}[/tex]Step 3
Calculate the statistical test
[tex]\begin{gathered} n=15 \\ \mu(\operatorname{mean})=11.09 \\ \sigma(s\tan dard\text{ deviation)=4.86} \end{gathered}[/tex]The t-test formula is given as
[tex]t=\text{ }\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt[]{n}}}[/tex]Where
[tex]\begin{gathered} \bar{x}=\operatorname{mean} \\ \mu=theoretical\text{ }value \\ \end{gathered}[/tex][tex]\begin{gathered} t=\frac{7.89-11.09}{\frac{4.86}{\sqrt[]{15}}} \\ t=\frac{7.89-11.09}{1.254846604} \\ t=\frac{-3.2}{1.254846604} \\ t=-2.550112492 \end{gathered}[/tex]Step 4
Find the p-value from the t-test.
[tex]\text{The p-value from the t-test is 0.01}209[/tex]Step 5
Conclusion
The result is not significant at p<0.01. Therefore, the null hypothesis is rejected. It cannot be concluded that the mean in this area is higher than the national average because the p-value is greater than 0.01t
