Here,point can be written as:
[tex]\begin{gathered} x1=11, \\ y1=-5 \\ x2=0 \\ y2=1 \end{gathered}[/tex]The formula for the distance between the points as follows;
[tex]\begin{gathered} d=\sqrt{(x1-x2)^2+(y1-y2)^2} \\ d=\sqrt{(11-0)^2+(-5-1)^2} \\ d=\sqrt{121+36} \\ d=\sqrt{157} \\ d=12.53 \end{gathered}[/tex]Thus, the distance between the point is 12.53.
I am studying for the big test tomorrow and just need someone to go through this sheet I made with me.Sorry
SOLUTION
Let us solve the simultaneous equation
[tex]\begin{gathered} -2x-y=0 \\ x-y=3 \end{gathered}[/tex]using elimination
To eliminate, we must decide which of the variables, x or y is easier to eliminate. The variable you must eliminate must be the same and have different sign. Looking above, it is easier to eliminate y because we have 1y above and 1y below. But to eliminate the y's, one must be +y and the other -y. So that +y -y becomes zero.
So to make the y's different, I will multiply the second equation by a -1. This becomes
[tex]\begin{gathered} -2x-y=0 \\ (-1)x-y=3 \\ -2x-y=0 \\ -x+y=-3 \end{gathered}[/tex]So, now we can eliminate y, doing this we have
[tex]\begin{gathered} -2x-x=-3x \\ -y+y=0 \\ 0-3=-3 \\ \text{This becomes } \\ -3x=-3 \\ x=\frac{-3}{-3} \\ x=1 \end{gathered}[/tex]Now, to get y, we put x = 1 into any of the equations, Using equation 1, we have
[tex]\begin{gathered} -2x-y=0 \\ -2(1)-y=0 \\ -2-y=0 \\ \text{moving -y to the other side } \\ y=-2 \end{gathered}[/tex]So, x = 1 and y = -2
Using substitution, we make y or x the subject in any of the equations. Looking at this, It is easier to do this using equation 2. From equation 2,
[tex]\begin{gathered} x-y=3 \\ \text{making y the subject we have } \\ y=x-3 \end{gathered}[/tex]Now, we will put y = x - 3 into the other equation, which is equation 1, we have
[tex]\begin{gathered} -2x-y=0 \\ -2x-(x-3)=0 \\ -2x-x+3=0 \\ -2x-1x+3=0 \\ -3x+3=0 \\ -3x=-3 \\ x=\frac{-3}{-3} \\ x=1 \end{gathered}[/tex]So, substituting x for 1 into equation 1, we have
[tex]\begin{gathered} -2x-y=0 \\ -2(1)-y=0 \\ -2\times1-y=0 \\ -2-y=0 \\ y=-2 \end{gathered}[/tex]Substituting x for 1 into equation 2, we have
[tex]\begin{gathered} x-y=3 \\ 1-y=3 \\ y=1-3 \\ y=-2 \end{gathered}[/tex]Now, for graphing,
JUIVE Suppose that the amount in grams of a radioactive substance present at time t (in years) is given by A(t) = 800e 0.86t. Find the rate of change of the quantity present at the time when t = 5. 9.3 grams per year 0 -72.7 grams per year -9.3 grams per year 0 72.7 grams per year
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
A(t) = 800e^(-0.86t)
Step 02:
Rate of change
t1 = 0
A(t) = 800e^(-0.86t)
A(t) = 800e^(-0.86*0)
A(0) = 800
t2 = 5
A(t) = 800e^(-0.86t)
A(t) = 800e^(-0.86*5)
A (t) = 800e^(-4.3)
A(5) = 10.85
Step 03:
[tex]\frac{\Delta y}{\Delta x}=\frac{A(5)\text{ - A(0)}}{5-0}[/tex][tex]\frac{\Delta y}{\Delta x}=\frac{10.85-800}{5-0}=\frac{-789.15}{5}=-157.83[/tex]100 points!!!!
PLS WRITE IN SLOPE INTERCEPT FORM
–18y + 8 = 12x
SOLVE FOR Y
Answer: y = (-2/3)x + (4/9)
Step-by-step explanation:
y = mx + b is the form expected
-18y + 8 = 12x
subtract 8 from both sides
-18y = 12x - 8
divide both sides by -18
y = (12x/-18) - (8/-18)
Simplify the negatives and pull x out of the parenthesis (this only works if x is in the numerator).
y = (-12/18)x + 8/18
Simplify the fractions
y = (-2/3)x + 4/9
Answer:
The required value of y is,
y = -(2/3)x + (4/9)Step-by-step explanation:
Given equation,
→ -18y + 8 = 12x
The slope-intercept form is,
→ y = mx + b
Let's rewrite the equation,
→ y = mx + b
→ -18y + 8 = 12x
→ -18y = 12x - 8
→ -y = (12x - 8)/18
→ -y = (2/3)x - (4/9)
→ y = -(2/3)x + (4/9)
Hence, this is the answer.
The answer is 57.3 provided by my teacher, I need help with the work
Apply the angles sum property in the triangle ABC,
[tex]62+90+\angle ACB=180\Rightarrow\angle ACB=180-152=28^{}[/tex]Similarly, apply the angles sum property in triangle BCD,
[tex]20+90+\angle BCD=180\Rightarrow\angle BCD=180-110=70[/tex]From triangle ABC,
[tex]BC=AC\sin 62=30\sin 62\approx26.5[/tex]From triangle BDC,
[tex]BD=BC\cos 20=26.5\cos 20\approx24.9[/tex]Now, consider that,
[tex]\angle BDE+\angle BDC=180\Rightarrow\angle BDE+90=180\Rightarrow\angle BDE=90[/tex]So the triangle BDE is also a right triangle, and the trigonometric ratios are applicable.
Solve for 'x' as,
[tex]x=\tan ^{-1}(\frac{BD}{DE})=\tan ^{-1}(\frac{24.9}{16})=57.2764\approx57.3[/tex]Thus, the value of the angle 'x' is 57.3 degrees approximately.ang
The number line below shows the values of x that make the inequality x > 1 true. Select all the values of x from this list that make the inequality x> 1 true. a. 3 b. -3c. 1 d. 700 e. 1.052. Name two more values of x that are solutions to the inequality.
Answer:
(a)3, 1, 700 and 1.05
(b)6 and 9
Explanation:
(a)The values of x from the list that make the inequality x> 1 true are:
3, 1, 700 and 1.05
(b)Two more values of x that are solutions to the inequality x>1 are:
6 and 9.
The table shows the linear relationship between the average height in feet of trees on a tree farm andthe number of years since the trees were planted,Average Tree HeightNumber of Years Sincethe Trees were planted1361115Average Height (ft)10244580108m
Rate of change = change in y / change in x
From the table, number of years since the tree are planted are the x
They are; 1, 3, 6, 11 , 15
Average height are y, and they are;
10, 24, 45, 80, 105
Now, to calculate the rate of change, we will find the difference between two values of y then divide it by the difference between 2 values of x
If we are going to pick the first and second value of y, we must also pick the first and second value of x
If we are to pick the second and 3rd value of y, we must then pick the 2nd and 3rd value of x
That is;
rate of change = 24 -10 / 3-2
= 14/2
= 7 ft/yr
URGENT!! ILL GIVE
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Answer:
-45 is an integer
√100 = 10 is a whole number
√89 is an irrational number-root
4.919191... is a rational decimal
-2/5 is a rational number-ratio
.12112111211112... is an irrational decimal
Finnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn
See if anybody can answer this. A concession stand sells lemonade for $2 each and sports drinks for $3 each. The concession stand sells 54 cups of lemonade and sport drinks. The total money collected for these items is $204. How much money was collected on sports drinks?
Jacob is constructing a pentagonal tent for his school carnival. The tent has a side length of 5.13 meters. What is the area of the tent? What is the perimeter of the tent? What is the sum of three of the interior angles in the tent once Jacob obtains the value of its area and perimeter?
The tent is pentagonal , this means it has 5 sides. The tent have a side length of 5.13 meters.
The area of the pentagon can be calculated below
[tex]\begin{gathered} \text{area of the tent=}\frac{perimeter\times apothem}{2} \\ \tan \text{ 36=}\frac{2.565}{a} \\ a=\frac{2.565}{\tan \text{ 36}} \\ a=\frac{2.565}{0.726542528} \\ a=3.53041962601 \\ \text{perimeter}=\text{ 5.13}\times5=25.65\text{ meters} \\ \text{area =}\frac{25.65\times3.53041962601}{2} \\ \text{area}=\frac{90.5445}{2} \\ \text{area}=45.27225 \\ \text{area}\approx45.27meter^2 \end{gathered}[/tex]Each interior angle of a pentagon is
[tex]\begin{gathered} \text{ interior angle=}\frac{180\times3}{5}=\frac{540}{5}=108^{\circ} \\ \text{ Sum of thr}ee\text{ interior angles = 108}\times3=\text{ }324\text{ degre}e \end{gathered}[/tex]Henry had a batting average of 0.341 last season (out of 1000 at-bats, he had 341 hits). Given that thisbatting average will stay the same this year, answer the following questions. What is the probability that his first hit will not occur until his 5th at-bat? Answers. 0.64. 0.083. 0.129. 0.166
The probability of success (a hit) is given by:
p = 0.341
The complement (a failure) of this probability is:
q = 1 - 0.341 = 0.659
Then, we can construct a probability distribution for the first hit until his nth at-bat:
[tex]P(x=n)=p\cdot q^{n-1}[/tex]For his 5th at-bat, we have n = 5, then:
[tex]\begin{gathered} P(x=5)=0.341\cdot(0.659)^{5-1}=0.341\cdot0.659^4 \\ \\ \therefore P(x=5)=0.064 \end{gathered}[/tex]a sample size 115 will be drawn from a population with mean 48 and standard deviation 12. find the probability that x will be greater than 45. round the final answer to at least four decimal places
B) find the 90th percentile of x. round to at least two decimal places.
The probability that x will be greater than 45 is 0.1974.
The 90th percentile of x is 63.3786
Given,
The sample size drawn from a population = 115
The mean of the sample size = 48
Standard deviation of the sample size = 12
a) We have to find the probability that x will be greater than 45.
Here,
Subtract 1 from p value of the z score when x = 45
Then,
z = (x - μ) / σ
z = (45 - 48) / 12 = -3/12 = -0.25
The p value of z score -0.25 is 0.8026
1 - 0.8026 = 0.1974
That is,
The probability that x will be greater than 45 is 0.1974.
b) We have to find the 90th percentile of x.
Here,
p value is 0.90
Then, z score will be equal to 1.28155
Now find x.
z = (x - μ) / σ
1.28155 = (x - 48) / 12
15.3786 = x - 48
x = 15.3786 + 48
x = 63.3786
That is,
The 90th percentile of x is 63.3786
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Compare A and B in three ways, where A = 51527 is the number of deaths due to a deadly disease in the United States in 2005 and B = 17241 is the number of deaths due to the same disease in the United States in 2009. a. Find the ratio of A to B. b. Find the ratio of B to A. c. Complete the sentence: A is ____ percent of B.
ANSWER
Ratio of A to B = 2.99 (to 2 decimal places)
Ratio of B to A = 0.33 (to 2 decimal places)
A is 299% of B (to nearest integer)
STEP BY STEP EXPLANATION
for ratio of A to B:
[tex]\begin{gathered} \frac{A}{B}\text{ = }\frac{51527}{17241}\text{ = }2.98863 \\ \text{ = 2.99 (to 2 decimal places)} \end{gathered}[/tex]for ratio of B to A:
[tex]\begin{gathered} \frac{B}{A}\text{ = }\frac{17241}{51527}\text{ = 0.33460 } \\ \text{ = 0.33 (to 2 decimal places)} \end{gathered}[/tex]A is x % of B:
[tex]\begin{gathered} A\text{ = }\frac{x}{100}\times B \\ x\text{ = }\frac{100\text{ }\times A}{B} \\ x\text{ = }\frac{100\text{ }\times\text{ 51527}}{17241}\text{ = 298.86} \\ x\text{ = 299\% (to nearest integer)} \end{gathered}[/tex]Hence, the ratio of A to B = 2.99 (to 2 decimal places), B to A = 0.33 (to 2 decimal places) and A is 299% of B (to nearest integer).
There is a raffle with 250 tickets. One ticket will win a $320 prize, one ticket will win a $240 prize, one ticket will win a $180 prize, one ticket will win a $100 prize, and the remaining tickets will win nothing. If you have a ticket, what is the expected payoff
Given that: There is a raffle with 250 tickets. One ticket will win a $320 prize, one ticket will win a $240 prize, one ticket will win a $180 prize, one ticket will win a $100 prize, and the remaining tickets will win nothing.
The expected payoff will be:
[tex]\begin{gathered} EV=\frac{1}{250}(320)+\frac{1}{250}(240)+\frac{1}{250}(180)+\frac{1}{250}(100)+\frac{246}{250}(0) \\ EV=\frac{320+240+180+100}{250} \\ EV=\frac{840}{250} \\ EV=3.36 \end{gathered}[/tex]So the expected payoff will be $3.36.
Rewrite the fallowing as an exponential expression in simplest form.
SOLUTION
[tex]\begin{gathered} 5x\sqrt[]{x} \\ 5x\times\sqrt[]{x} \\ 5x^1\times x^{\frac{1}{2}} \\ 5x^{1+\frac{1}{2}} \\ 5x^{\frac{3}{2}} \\ \end{gathered}[/tex]12.Work backwards to write a quadratic equation that will have solutions of x = -1/2 and x = 4. (Your equation must only have integer coefficients, meaning no fractions or decimals.)
In general, a quadratic equation can be written in terms of its solutions:
[tex]y=(x-a)(x-b).[/tex]Now, notice that:
[tex]x+\frac{1}{2}=0\text{ }[/tex]when x= -1/2, and it is equivalent to:
[tex]2x+1=0.[/tex]Therefore, you can write the quadratic equation as:
[tex]y=(2x+1)(x-4).[/tex]Computing the above multiplication, you get:
[tex]y=2x^2-8x+x-4.[/tex]Simplifying the above equation you get:
[tex]y=2x^2-7x-4.[/tex]Answer: [tex]y=2x^{2}-7x-4[/tex]A popcorn stand offers buttered or unbuttered popcorn in three sizes: small, medium, and large. What is the P(buttered)
The popcorn we can order is either buttered or unbuttered.
Therefore, the probability of choosing buttered popcorn is 1/2
A storage box has a volume of 56 cubic inches. The base of the box is 4 inches by 4 inches. Lin’s teacher uses the box to store her set of cubes with an edge length of 1/2 inch.If the box is completely full how many cubes are in the set?
To answer this question, we have to find the volume of one of the cubes from Lin's set. To do it use the formula to find the volume of a cube, which is the edgelength raised to 3:
[tex]\begin{gathered} V=ed^{3^{}} \\ V=(\frac{1}{2})^3 \\ V=\frac{1}{8} \end{gathered}[/tex]In this case, each cube has a volume of 1/8 cubic inches. To find the number of cubes in the set, perform the division of the volume of the box by the volume of one cube:
[tex]n=\frac{V_{box}}{V_{cube}}=\frac{56}{\frac{1}{8}}=8\cdot56=448[/tex]The set has 448 cubes.
d1 = 16 m; d2 = 14 m what's the rhombus?
Step 1 : To determine the area of the rhombus
[tex]\begin{gathered} d_1=16m,d_2\text{ = 14m } \\ Area\text{ = }\frac{1}{2}\text{ }\times d_1\text{ }\times d_2 \\ Area\text{ = }\frac{1}{2}\text{ }\times\text{ 16 }\times\text{ 14} \\ Area\text{ = }\frac{224}{2} \\ Area=112m^2 \end{gathered}[/tex]Therefore the area of the rhombus = 112m²
URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100 POINTS!!!
Find the surface area of the cone. Use 3.14 for pi.The surface area is about __in.2.(I need just the answer, I don't need explanation)
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
s = 50in
d = 20in
surface area of a cone = ?
Step 02:
surface area of a cone
SA = πr² + πrs
r = d/2 = 20in / 2 = 10in
SA = 3.14*(10in)² + 3.14*50in*10in
SA = 314in² + 1570in²
SA = 1884in²
The answer is:
SA = 1884in²
what is 9.77 with 8% tax
it will be 9.77+0.08(9.77)=10.5516
Question 1 of 10 - What is the value of the expression below when d= 5 and m = -2? d? + | dm|
Note the absolute value of any negative value is positive.
A pianist plans to play 4 pieces at a recital from her repertoire of 25 pieces, and is carefully consideringwhich song to play first, second, etc. to create a good flow. How many different recital programs arepossible?
Given 25 pieces of repertoire, if a pianist plans to play 4 pieces at a recital and is considering playing which song to play first, second, etc, the possible ways is,
[tex]^{25}P_4=\frac{25!}{(25-4)!}=\frac{25!}{21!}=303600\text{ possible recital programs}[/tex]Hence, the different recital programs possible is 303600
Faith borrowed $2250 for home repairs. She paid back 24 payments of$132 each. How much did she pay in interest on the loan?a. $87.71b. $2,520c. $918d. $4.38
• We are given that Faith paid $132 for 24 months.
So; 132 * 24 = $3168
• Since we know that Faith initially borrowed $2250
Interest paid = $3168 - $2250
= $918
• Option C is the correct choice.
The following distribution represents the number of credit cards that customers of a bank have. Find the mean number of credit cards.Number of cards X01234Probability P(X)0.140.40.210.160.09
To solve this problem we have a formula at hand: the mean (m) number of credits cards is
[tex]m=\sum ^{}_XX\cdot P(X)[/tex]Then,
[tex]m=0\cdot0.14+1\cdot0.4+2\cdot0.21+3\cdot0.16+4\cdot0.09=1.66[/tex]a) rewrite each equation using function notation f(x) b) find f(3)
Hello there. To solve this question, we'll simply have to isolate y and plug in the value for x.
Given the equation:
4x - 3y = 8
To rewrite it using the notation y = f(x), subtract 4x on both sides and divide the equation by -3
-3y = 8 - 4x
y = - 8/3 + 4x/3
Now, plug in x = 3 in order to find f(3)
f(3) = -8/3 + 4 * 3/3 = -8/3 + 12/3 = 4/3
(A) A shipment of 10 cameras will likely have 6 defectives. If a person buys 2 cameras, what is the probability of getting 2 defectives?(B) What are the odds in favor of getting a defective camera?
To solve the exercise, you can use the formula of the binomial distribution:
[tex]\begin{gathered} P(x)=\binom{n}{x}p^x(1-p)^{n-x} \\ \text{ Where } \\ n\text{ is the number of trials (or the number being sampled)} \\ x\text{ is the number of successes desired} \\ p\text{ is the number of getting a success in one trial} \end{gathered}[/tex]So, in this case, we have:
[tex]\begin{gathered} n=10 \\ p=\frac{6}{10}=0.6 \end{gathered}[/tex]Because "success" is that there are defective cameras, 6 defective cameras out of 10 in total.
For part A, we have:
[tex]\begin{gathered} x=2 \\ P(x)=\binom{n}{x}p^x(1-p)^{n-x} \\ P(2)=\binom{10}{2}\cdot0.6^2\cdot(1-0.6)^{10-2} \\ P(2)=\binom{10}{2}\cdot0.6^2\cdot(0.4)^8 \\ P(2)=45\cdot0.36\cdot0.00065536 \\ P(2)=0.0106 \end{gathered}[/tex]Therefore, the probability of getting 2 defective cameras is 0.0106.
For part B, we have:
[tex]\begin{gathered} x=1 \\ P(x)=\binom{n}{x}p^x(1-p)^{n-x} \\ P(1)=\binom{10}{1}\cdot0.6^1\cdot(1-0.6)^{10-1} \\ P(1)=\binom{10}{1}\cdot0.6^1\cdot(0.4)^9 \\ P(1)=10\cdot0.6\cdot0.000262144 \\ P(1)=0.0016 \end{gathered}[/tex]Therefore, the probability of getting one defective camera is 0.0016.
The diameter of circle is 20 inches. find the circumference in terms of pi
The below formula is used to find the circumference of a circle;
[tex]C=2\pi r[/tex]But we know that the diameter of a circle is expressed as;
[tex]d=2r[/tex]Let's replace 2r with d in the 1st equation, we'll then have;
[tex]C=\pi d[/tex]We've been told that the diameter of the circle is 20inches, if we substitute this value into our equation, we'll have;
[tex]C=20\pi[/tex]The highly temperature one day was -3 the low temperature was -7 what was the difference
Question
Refer to section 1.3.2, Credit scores, beginning on page 22 of the report.
Arrange the five tiers of credit scores in order, starting with the lowest tier of credit scores.
The five credit score tiers are listed in ascending order, starting with the lowest tier:
Deep Subprime < Subprime < near prime < prime < super prime
A consumer's credit score may have a big impact on their ability to receive credit. These interactive infographics show how lending practices have changed for borrowers with various credit score profiles.
We focus on the five credit score levels that are commercially available.
The range of subprime credit scores is 580 to 619.
The range of Prime's credit score is from 660 to 719.
Deep subprime credit scores fall below 580.
Near prime credit scores range from 620 to 659.
Super prime credit is defined as having a score of 720 or higher.
The following are the five credit scores, listed from lowest to highest:
Deep Subprime < Subprime < near prime < prime < super prime
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