Dunoga cycled 15.26 kilometres and then ran 740 metres. What was the total distance he covered in kilometres?​

Answers

Answer 1

Answer:16 Kilometers

Step-by-step explanation:15.26km+.74km

Answer 2

Dunoga covered a distance of 16 km in total.

What is unit conversion?

A unit conversion expresses the same property as a different unit of measurement.

For instance, time can be expressed in minutes instead of hours, while distance can be converted from miles to kilometers, or feet, or any other measure of length.

Given that, Dunoga cycled 15.26 kilometers and then ran 740 meters. We need to find the distance he covered in kilometers,

To find the total distance, we will add the distance he covered by cycle and by running,

But the units of both the distances are not same and to add we need to convert the units,

Since, the answer required in kilometers, so we will convert meter into kilometers,

1 km = 1000 m

Therefore,

740 m = 740 / 1000 = 0.74 km

Therefore, the distance he covered in kilometers = 0.74+15.26

= 16 km

Hence, Dunoga covered a distance of 16 km in total.

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Related Questions

6. The graph shows how much money Priya has in her savings account weeksafter she started saving on a regular basis.

Answers

Given:

Graph is given.

6a.

[tex]\text{Money in the account after 10 weeks= \$320}[/tex]

6b.

[tex]\text{Number of weeks take to save \$200= 5 weeks}[/tex]

6c.

[tex]\text{Priya have \$80 in her account when she started the savings regularly}[/tex]

Use the quadratic function fly)=-22 +53411 to answer the following questions,a) Use the vertex formula to determine the vertes.The verteris(Type an ordered pair Simplify your answer.)

Answers

The vertex of a quadratic function can be found by using the following expression:

[tex]x=\frac{-b}{2a}[/tex]

Where "a" is the number multiplying x² and b is the number multiplying x. For this function a = -2 and b = 5. Applying these on the problem we have:

[tex]x=\frac{-5}{2\cdot(-2)}=\frac{-5}{-4}=\frac{5}{4}=1.25[/tex]

To find the y coordinate of the vertex we need to use the value for x that we found above. We have:

[tex]\begin{gathered} f(x)=-2x^2+5x+11 \\ f(\frac{5}{4})=-2\cdot(\frac{5}{4})^2+5\cdot(\frac{5}{4})+11 \\ f(\frac{5}{4})=-2\frac{25}{16}+\frac{25}{4}+11 \\ f(\frac{5}{4})=\frac{-50}{16}+\frac{25}{4}+11 \\ f(\frac{5}{4})=-3.125+6.25+11=14.125 \end{gathered}[/tex]

The ordered pair for this function's vertex is (1.25, 14.125)

cuántos cifras tiene el cociente de 900÷25

Answers

Given the expression

the sign shown below is posted in front of a roller coaster ride at the Wadsworth country fairgrounds.if h represents the height of a rider in inches,what is the correct translation of the statement on this sign?h<48h>58h≤48h≥48

Answers

Answer:

h≥48​

Explanation:

If all riders must be at least 48 inches tall, it can mean the following.

0. The height of the riders can be ,exactly 48 inches, tall (h=48)

,

1. The height of the riders can be, greater than 48 inches,, (h>48).

Combining the two, we have:

h≥48​

Rewrite y + 1 = -2x – 3 in standard form

Answers

The algebraic expressions can be written as

[tex]a+b+c=0[/tex]

The given expression is,

[tex]\begin{gathered} y+1=-2x-3 \\ -2x-y=1+3 \\ -2x-y=4 \\ -2x-y-4=0 \\ 2x+y+4=0 \end{gathered}[/tex]

Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this section to solve the following exercise.The number of ducks and pigs in a field totals 37. The total number of legs among them is 98. Assuming each duck has exactly two legs and each plg has exactly fourlegs, determine how many ducks and how many pigs are in the field.ducks?pigs?

Answers

Lets call x to the number of ducks

and y the number of pigs.

Then:

[tex]2x+4y=98[/tex]

Because there are 2 legs per duck and 4 legs per pig.

If the total of animals is 37, then:

[tex]x+y=37[/tex]

Then:

[tex]x=37-y[/tex]

And replacing on the first equation we get:

[tex]2(37-y)+4y=98[/tex][tex]74-2y+4y=98[/tex][tex]2y=98-74[/tex][tex]2y=24[/tex][tex]y=\frac{24}{2}[/tex][tex]y=12[/tex]

There are 12 pigs and therefore 25 ducks.

In Mr. Peter's class, 75% of the students have a pet. There are 15 students with pets in the class. How many total students are in the class?

Answers

Answer:

20 Students

Explanation:

Let the total number of students in the class = x

Number of students that have pets = 15

Percentage of students that have pets = 75%

Therefore:

[tex]75\%\text{ of x=15}[/tex]

We then solve for x.

[tex]\begin{gathered} \frac{75}{100}\times x=15 \\ 0.75x=15 \\ x=\frac{15}{0.75} \\ x=20 \end{gathered}[/tex]

We have 20 students in total in the class.

A basic cellular package costs $20/month for 60 minutes of calling with an additional charge of $0.20/minute beyond that time. The cost function C(x) for using x minutes would beIf you used 60 minutes or less, i.e. if if x≤60, then C(x)=20 (the base charge). If you used more than 60 minutes, i.e. (x−60) minutes more than the plan came with, you would pay an additional $0.20 for each of those (x−60) minutes. Your total bill would be C(x)=20+0.20(x−60). If you want to keep your bill at $50 or lower for the month, what is the maximum number of calling minutes you can use?

Answers

The maximum number of calling minutes you can use for $50 is 210 minutes.

To solve this, we have the function cost C(x) that depends on the amount of acalling munutes (x)

We want this cost to be $50 or lower. This means:

[tex]\begin{gathered} CostFunction\colon C(x)=20+0.2(x-60) \\ Maximum\text{ value of 50:}C(x)\le50 \end{gathered}[/tex]

Then we can create an inequality:

[tex]50\ge20+0.2(x-60)[/tex]

And now we can solve for x:

[tex]\begin{gathered} 50\ge20+0.2(x-60) \\ \frac{50-20}{0.2}\ge x-60 \\ 150+60\ge x \\ x\le210\text{ minutes} \end{gathered}[/tex]

Thus, with $50 we can talk up to 210 minutes.

To be sure of the result, let's plug x = 210 in the function and it should give us a cost of C(210) = 50:

[tex]\begin{gathered} x=210\Rightarrow C(210)=20+0.2(210-60) \\ C(210)=20+0.2\cdot150 \\ C(210)=20+30=50 \end{gathered}[/tex]

This confirms the result.

Solve the system of equations.y= x2 - 3x + 6y = 2x + 6

Answers

We have the following:

[tex]\begin{gathered} y=x^2-3x+6 \\ y=2x+6 \end{gathered}[/tex]

We subtract the equations:

[tex]\begin{gathered} y-y=x^2-3x+6-2x-6 \\ 0=x^2-5x \\ 0=x(x-5) \\ x=0;x=5 \end{gathered}[/tex]

for y:

[tex]\begin{gathered} y=2\cdot0+6 \\ y=6 \\ y=2\cdot5+6 \\ y=16 \end{gathered}[/tex]

therefore, the answer is:

(0,6) and (5,16), the option D.

Write the equation of the line through the given point. Use slope-intercept form. (-5,2); perpendicular to y = - 2/3x +5

Answers

[tex]y=\frac{3}{2}x+\frac{19}{2}[/tex]

Explanation

Step 1

we have a perpendicular line, its slope is

[tex]\begin{gathered} y=\frac{-2}{3}x+5 \\ \text{slope}=\frac{-2}{3} \end{gathered}[/tex]

two lines are perpendicular if

[tex]\begin{gathered} \text{slope}1\cdot\text{ slope2 =-1} \\ \text{then} \\ \text{slope}1=\frac{-1}{\text{slope 2}} \end{gathered}[/tex]

replace

[tex]\text{slope1}=\frac{\frac{-1}{1}}{\frac{-2}{3}}=\frac{-3}{-2}=\frac{3}{2}[/tex]

so, our slope is 3/2

Step 2

using slope=3/2 and P(-5,2) find the equation of the line

[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-2=\frac{3}{2}(x-(-5)) \\ y-2=\frac{3}{2}(x+5) \\ y-2=\frac{3}{2}x+\frac{15}{2} \\ y=\frac{3}{2}x+\frac{15}{2}+2 \\ y=\frac{3}{2}x+\frac{19}{2} \end{gathered}[/tex]

The function h (t) = -4.9t² + 19t + 1.5 describes the height in meters of a basketball t secondsafter it has been thrown vertically into the air. What is the maximum height of the basketball?Round your answer to the nearest tenth.1.9 metersO 19.9 meters16.9 metersO 1.5 meters

Answers

Since the function describing the height is a quadratic function with negative leading coefficient this means that this is a parabola that opens down. This also means that the maximum height will be given as the y component of the vertex of the parabola, then if we want to find the maximum height, we need to write the function in vertex form so let's do that:

[tex]\begin{gathered} h(t)=-4.9t^2+19t+1.5 \\ =-4.9(t^2+\frac{19}{4.9}t)+1.5 \\ =-4.9(t^2+\frac{19}{4.9}t+(\frac{19}{9.8})^2)+1.5+4.9(\frac{19}{9.8})^2 \\ =-4.9(t+\frac{19}{9.8})^2+19.9 \end{gathered}[/tex]

Hence the function can be written as:

[tex]h(t)=-4.9(t+1.9)^2+19.9[/tex]

and its vertex is at (1.9,19.9) which means that the maximum height of the ball is 19.9 m

In 2005 there were 744 radio stations, by 2015 that number had increased by 13.8%. How many radio stations in 2015?

Answers

Answer: We have to find the radio stations in 2015, which is 13.8% more than the radio stations in 2005 which were 744:

[tex]\begin{gathered} x=\text{ Radio stations in 2015} \\ \\ x=(1.138)\times(744) \\ \\ x=846.672 \\ \\ x\approx847 \end{gathered}[/tex]

Solve the system using the elimination method. State your final answer as an ordered pair. DO NOT include any spaces in your answers.

Answers

Given:-

let

5x-4y=1 be the equation 1

-5x-10y=-15 be the equation 2

step 1-

add equation 1 and 2

we get=

-14y=-14

y=1

this is required value of y

we are going to put this value of y in equation 1

we get

5x-4(1)=1

5x-4=1

5x=1+4

5x=5

x=1

this is required value of x

hence value of x and y are(1,1)

helpppppp!!!!!!!!!!!!!!!!!!!!

Answers

Answer

D. Observations of constellations show that stars have moved over time.

Explanation:

A scientific claim is basically an observation in science.

Constellation changes there position over time because of earth's rotation around sun. So, observation of constellations shows that stars have moved over time is a scietific claim. If stars would not move then constellation will not form.

CorrectBob's Golf Palace had a set of 10 golf clubs that were marked on sale for $840. This was a discount of 10% off the original selling price.Step 3 of 4: What was the store's percent of profit based on cost ($390)? Follow the problem-solving process and round your answer tothe nearest hundredth of a percent, if necessary.

Answers

The percent change is given by:

[tex]Percent_{\text{ }}change=\frac{New_{\text{ }}value-old_{\text{ }}value}{old_{\text{ }}value}\times100[/tex]

The old value is $390

What is the name of the decimal number?7.1seventy-one seven and one hundredthsseven and one tenth seventeen

Answers

Answer:

seven and one-tenth.

Explanation:

To name decimal number, we first name the values before the decimal point, in this case, seven

Then, we add an and that corresponds to the decimal point

Finally, we say the number after the decimal point and the place of this number, in this case, one-tenth.

Therefore, the name of the decimal number 7.1 is:

seven and one-tenth.

I need help, I don’t know which one would have factors of 5x-8

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

data:

factor:

5x - 8

Step 02:

difference of squares:

(5x - 8)(5x + 8) = 25x² - 64

The answer is:

25x² - 64

Find the area of each figure. Round to the nearest 10th if necessary.

Answers

1.

First, divide the figure into 3 different figures.

Find the area of each figure, and then add them:

A1 is a rectangle:

Area of a rectangle: Lenght x width

A1 = 8 x 5.3 = 42.4 in2

A2 is also a rectangle:

Lenght = 4

width = 8 - 5.3 = 2.7

A2 = 4 x 2.7 = 10.8 in2

A3 is a triangle:

Area of a triangle = (base x height) / 2

base = 2.7

Height = 8-4 = 4

A3= ( 2.7 x 4 ) / 2 = 5.4 in2

Total area = A1 + A2 + A3 = 42.4 + 10.8 + 5.4 = 58.6 in2

Answer = 58.6 in2

Which statement is true for all real values of θ? sin2θ − cos2θ = 1 cos2θ − sin2θ = 1 cos2θ = sin2θ − 1 cos2θ = 1 − sin2θ

Answers

The statement holds true for all true values of is cos²θ = 1 − sin²θ

What is meant by trigonometric identities?Trigonometric Identities are equalities that involve trigonometry functions and hold true for all variables in the equation. There are numerous trigonometric identities involving the side length and angle of a triangle. Trigonometry identities are trigonometry equations that are always true, and they are frequently used to solve trigonometry and geometry problems as well as understand various mathematical properties. Knowing key trig identities aids in the retention and comprehension of important mathematical principles as well as the solution of numerous math problems. Convert everything to sine and cosine terms. When possible, use the identities. Begin by simplifying the left side of the equation, then move on to the right side if you get stuck.

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Solve the system of inequalities by graphing.y\ge-3

Answers

[tex]\begin{gathered} y\le2x-3 \\ y\ge-3 \end{gathered}[/tex]

Solve each system of the equation by elimination method. x+3y=-204x+5y=-38

Answers

Given the equation system:

[tex]\begin{gathered} x+3y=-20 \\ 4x+5y=-38 \end{gathered}[/tex]

To solve this system using the elimination method, the first step is to multiply the first equation by 4 so that the leading coefficient is the same, i.e., both equations start with "4x"

[tex]\begin{gathered} 4(x+3y=-20) \\ 4\cdot x+4\cdot3y=4\cdot(-20) \\ 4x+12y=-80 \end{gathered}[/tex]

Then subtract the second equation from the first one

From the resulting expression, you can calculate the value of y

[tex]\begin{gathered} 7y=-42 \\ \frac{7y}{7}=-\frac{42}{7} \\ y=-6 \end{gathered}[/tex]

Next, you have to substitute the value of y in either the first or second equation to find the value of x:

[tex]\begin{gathered} x+3y=-20 \\ x+3\cdot(-6)=-20 \\ x-18=-20 \\ x=-20+18 \\ x=-2 \end{gathered}[/tex]

The solution of the system is (-2,-6)

In the triangle below, suppose that mZW=(x+4)º, mZX=(5x-4)°, and mLY= (4x)".Find the degree measure of each angle in the triangle.

Answers

[tex]\begin{gathered} W+X+Y=180 \\ x+4+5x-4+4x=180 \\ 10x=180 \\ x=18 \end{gathered}[/tex][tex]\begin{gathered} \text{The angle W is,} \\ W=x+4 \\ W=18+4=22 \\ \text{The angle X is,} \\ X=5x-4 \\ X=5\times18-4=86 \\ \text{The angle Y is,} \\ Y=4x \\ Y=4\times18=72 \end{gathered}[/tex]

x equals 6 y equals 1 y = x + ?

Answers

The given information is

A 35-foot wire is secured from the top of a flagpole to a stake in the ground. If the stake is 1 feet from the base of the flagpole, how tall is the flagpole?

Answers

The figure for the height of flagpole, wire and ground is,

Determine height of the pole by using the pythagoras theorem in triangle.

[tex]\begin{gathered} l^2=b^2+h^2 \\ (35)^2=(14)^2+h^2 \\ 1225-196=h^2 \\ h=\sqrt[]{1029} \\ =32.078 \\ \approx32.08 \end{gathered}[/tex]

Thus, height of the flagpole is 32.08 feet.

help meeeee pleaseeeee!!!





thank you

Answers

Step-by-step explanation:

what is the problem ?

first you need to put "1" in place of the x and calculate, and then you need to put "2" in place of the x and calculate.

just simple calculation !

(a)

R(1) = 1000×1² / (1² + 4) = 1000 / 5 = 200

$200 million

(b)

R(2) = 1000×2² / (2² + 4) = 4000 / 8 = 500

$500 million

there ! that's all that was needed.

I’m not firmiliar with the sun or difference of cubes (HW assignment)

Answers

Given:

[tex]125r^3-216[/tex]

Find-: Factor using the formula of the sum or difference of cube.

Sol:

Factoring sum and differences of cubs is:

[tex]\begin{gathered} x^3-y^3=(x-y)(x^2+y^2+xy) \\ \\ x^3+y^3=(x+y)(x^2+y^2-xy) \end{gathered}[/tex]

Apply for the given information.

[tex]\begin{gathered} =125r^3-216 \\ \\ =(5r)^3-(6)^3 \end{gathered}[/tex][tex]\begin{gathered} x^3-y^3=(x-y)(x^2+y^2+xy) \\ \\ (5r)^3-(6)^3=(5r-6)((5r)^2+(6)^2+(5r)(6)) \\ \\ =(5r-6)(25r^2+36+30r) \end{gathered}[/tex]

you pull with 45nm on a torque wrench of 1m what's the tourqe at the end

Answers

The torque at the end is equal to 45 Nm.

What is torque?

Torque can be defined as a measure of the amount of force which causes a physical object to rotate about an axis. This ultimately implies that, torque is a force which tends to cause the rotation of a physical object about an axis.

Mathematically, torque can be calculated by using this formula:

τ = Fd

Where:

τ represents the torque.F represents the force.d represents the perpendicular distance.

In this scenario, we can reasonably infer and logically deduce that the torque at the end would be equal to 45 Newton meter (Nm) because the force was not applied over a perpendicular distance.

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reduce the square root of -360

Answers

reduce the square root of

[tex]\begin{gathered} \sqrt[]{-360} \\ 360=36\cdot10=6^2\cdot10 \\ \end{gathered}[/tex]

There is no square root for the negative number

so, this is represent a complex number

So,

[tex]\begin{gathered} \sqrt[]{-360}=\sqrt[]{-1}\cdot\sqrt[]{360} \\ =i\cdot\sqrt[]{6^2\cdot10} \\ =i\cdot6\sqrt[]{10} \\ =6\sqrt[]{10}\cdot i \end{gathered}[/tex]

can someone please help me find the answer to the following?

Answers

We are given a tangent and a chord of a circle. The angle ABC form by the intersection of the tangent and the chord is half the arc they both intersect, therefore, we must find the major arc of the circle, we can do that with the fact that the total arc of the circle is 360, therefore:

[tex]\begin{gathered} \text{arcAB}=360-50 \\ \text{arcAB}=310 \end{gathered}[/tex]

Therefore, the angle is:

[tex]\begin{gathered} \angle ABC=\frac{1}{2}\times310 \\ \angle ABC=155 \end{gathered}[/tex]

Angle ABC is 155 degrees.

I don't get any of this help me please

Answers

Using scientific notation, we have that:

a) As an ordinary number, the number is written as 0.51.

b) The value of the product is of 1445.

What is scientific notation?

An ordinary number written in scientific notation is given as follows:

[tex]a \times 10^b[/tex]

With the base being [tex]a \in [1, 10)[/tex], meaning that it can assume values from 1 to 10, with an open interval at 10 meaning that for 10 the number is written as 10 = 1 x 10¹, meaning that the base is 1.

For item a, to add one to the exponent, making it zero, we need to divide the base by 10, hence the ordinary number is given as follows:

5.1 x 10^(-1) = 5.1/10 = 0.51.

For item b, to multiply two numbers, we multiply the bases and add the exponents, hence:

(1.7 x 10^4) x (8.5 x 10^-2) = 1.7 x 8.5 x 10^(4 - 2) = 14.45 x 10².

To subtract two from the exponent, making it zero, we need to multiply the base by 2, hence the base number is given as follows:

14.45 x 100 = 1445.

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