Elias is adding and. He finds the lcd to be 10t2 and uses multiplication to find equivalent expressions. Which is the sum of ?.

Answers

Answer 1

The LCD (Least Common Denominator) of 10t2 is 10t2. To determine the equivalent expression is the sum of the fractions is 8t2.

A/B = C/D

Where A and B are the two fractions, and C and D are the equivalent fractions.

We will use this formula to determine the equivalent expression of the given fractions:

3t/20 = C/10t2

We can solve for C by multiplying both sides by 10t2, yielding:

30t2/20 = C/10t2

We can solve for C by multiplying both sides by 10t2, yielding:

30t2/20 = C/10t2

We can then simplify by cancelling out the 10t2 on the denominator, yielding:

C = 30t2/20

The equivalent expression for the given fractions is therefore 30t2/20.

To find the sum of the fractions, we first need to convert all fractions to equivalent fractions with a common denominator. In this case, the LCD is 10t2.

The equivalent expressions for the fractions are therefore:

3t/20 + 5/10t2 = 30t2/20 + 50/10t2

The sum of the fractions is then the sum of the numerators divided by the denominator, or:

30t2/20 + 50/10t2 = 80t2/10t2

We can simplify this expression by cancelling out the 10t2 on the denominator, yielding:

80t2/10t2 = 8t2

Therefore, the sum of the fractions is 8t2.

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Answer 2

The sum of 14t/10t^2 +  (5t^2 + 40t)/10t^2 is (5t^2 + 54t)/10t^2

In this question we have been given that Elias is adding 7t/5t^2 and (t + 8)/2t

He finds the least common divisor (LCD) of 7t/5t^2 and (t + 8)/2t which 10t^2

He uses multiplication to find an equivalent expression.

7t/5t^2 = 7t/5t^2 * 2/2

            = 14t/10t^2

and (t + 8)/2t = ((t + 8) * 5t)/(2t * 5t)

                     = (5t^2 + 40t)/10t^2

We need to find the sum 14t/10t^2 +  (5t^2 + 40t)/10t^2

We know that if the base of two rational expressions a/b and c/b then the denominator of the result is same and we just add numerators i.e., a/b + c/b = (a + c)/b

So, 14t/10t^2 +  (5t^2 + 40t)/10t^2

= [14t + (5t^2 + 40t)]/10t^2

= (5t^2 + 54t)/10t^2

Hence, 14t/10t^2 +  (5t^2 + 40t)/10t^2 = (5t^2 + 54t)/10t^2

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Elias Is Adding And. He Finds The Lcd To Be 10t2 And Uses Multiplication To Find Equivalent Expressions.

Related Questions

A point is chosen at random in the circle.
What percent of the time will the point be in
the square?
Round to the nearest tenth of a percent.
1 in.
[ ? ]%
Enter

Answers

63.64% is the percentage of the area of the square.

What is square?

The square is a 4 sided figure, each side of the square is equal and make a right angle.

The area of square having sided a unit can be given by a² square unit.

Given that,

The radius of the circle r =  1 in.

The area of the circle = π r² = π (1)² = π = 22/7 inch.

Also the area of square = 1/2 x (diameter)²

The diameter of the square = 2r = 2

Area = 1/2(2)² = 2 square in.

The required percentage = (2 / (22/7)) x 100 = (7 / 11) x 100 = 700 / 11 = 63.6363.

The percentage of the area of the square is 63.64%.

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Does the graph represent a non-proportional function? How do you know?

Answers

The graph attached represents a non proportional function

When does linear graphs give a proportional relationship?

Like the name goes, a Linear graph is a straight line graph that represents a linear relationship with the equation of the form

y = mx + c

A relationship is proportionate if its graph is a line or ray that passes through the origin. in this case c = 0

It is not proportional if the line or graph does not go through the origin.

Additionally, if anything is not linear, it is not proportional.

The attached graph passed through point (0, 1) which is not the origin (0, 0) hence the graph is not a proportional relationship

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24.
Select all polynomials that have a zero located at
(4, 0).
A. fa
B. f(x) = (2x - 8) (x + 5)
C. f(x) = 4x(x - 3)(x - 1)
D. f(x) = (x − 4)(x − 3)(x + 1)
E. f(x) = 2x(4- x)(x + 5)(3x - 4)

Answers

Answer:

B

D

E

The first choice A appears to be a typo, so I can't comment on that

Step-by-step explanation:

Substitute x = 4 in each of the polynomials and see which ones end up with a value of 0. Since each of the polynomials is a multiplicative of expressions if any one of the individual expressions is 0 then the whole expression becomes 0

A. Unknown

B. 2x - 8 = 2 · 4 - 8 = 8 - 8 = 0. So this has a zero at (4,0)

C None of the individual expressions will result in  0. So not a correct choice

D x - 4 = 4 - 4 = 0 So this is a correct choice

E. In this case we have a 4-x term which is 4- 4 = 0; so correct choice

19. MP Identify Structure Write a fraction that is equivalent to a
terminating decimal between 0.5 and 0.75.
D. MP Persevere with Problems Fractions in simplest form that have
denominators of 2, 4, 8, 16, and 32 produce terminating decimals. Fractions
with denominators of 6, 12, 18, and 24 produce repeating decimals. What
causes the difference? Explain.

Answers

0.625 is the terminating decimal between 0.5 and 0.75.

What is Fraction?

A fraction represents a part of a whole.

Terminating decimal between 0.5 and 0.75

we can find the mean of these two numbers and if the mean is terminating decimal then this will be the required answer.

0.5+0.75/2=0.625

Fractions having a denominator which can be factored in terms of 2 or 5 (or both) will terminate completely or will have terminating decimals.  

But the fractions whose denominator can not be factored only in terms of 2, 5 or both, will repeat or will have repeating decimals..

As 2=2¹  , 4= 2², 8=2³ , 16=2⁴

Here, 2,4,8,16, and 32 are all powers of 2 and fractions with these denominators will have terminating decimal expansion.  

As, 6=2×3, 12=3×4, 18=6×3, 24=6×4

But 6,12, 18, and 24 can'not be factored only in terms of 2 or 5 or both. Therefore, fractions with these denominators will have repeating decimals.

Hence, Fractions in simplest form that have denominators of 2, 4, 8, 16, and 32 produce terminating decimals. Fractions with denominators of 6, 12, 18, and 24 produce repeating decimals

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Geometry find length of third side

Answers

Answer:

[tex]\sqrt{34}[/tex]

Step-by-step explanation:

Using the Pythagorean theorem, the length of the third side is [tex]\sqrt{5^2+3^2}=\sqrt{34}[/tex].

Answer:

[tex]\sqrt{34} = c[/tex]

Step-by-step explanation:

Using the Pythagorean Theorem

[tex]a^{2} + b^{2} = c^{2} \\3^{2} + 5^{2} = c^{2} \\34 = c^{2} \\\sqrt{34} = c[/tex]

Hence , the length of the third side is [tex]\sqrt{34}[/tex]

A family used a professional decorator to help furnish their new home. The decorator selected $1,580 worth of furnishings. The family paid for the furnishings, plus 4.5% tax on the purchases. The decorator’s fee was 12% of the purchases, not including the tax.

Part A

Write an equation in the form of y=kx, using x to represent the decorator’s fee. Then use the equation to calculate the amount of that fee.

y=____x
$__

Write an equation in the form of y=kx to represent the tax. Then use the equation to calculate the amount of tax.
Part B

y=k___x
$___

Part C
What is the total cost that the family paid?
$___

Answers

Part A (decorator’s fee)

y = 0.12 x 1580

$189.6

Part B(tax)

y = 0.045 x 1580

$71.1

Part C(Total amount spent)

$1,580 + $189.6 + $71.1

$1840.7

What is a Linear Equation?

A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form Ax + B = 0. Here, x is a variable, A is a coefficient and B is constant. The standard form of a linear equation in two variables is of the form Ax + By = C. Here, x and y are variables, A and B are coefficients and C is a constant.

Part A (the decorator’s fee)

12% of purchases = 0.12

y = 0.12 x 1580

Decorator's fee = $189.6

Part B (the tax)

4.5% Tax = 0.045

y = 0.045 x 1580

Tax = $71.1

Part C (Total amount spent)

Purchasing fee + Decorators fee + Tax

= $1,580 + $189.6 + $71.1

$1840.7

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standard form (-7,3) and (1,2)

Answers

Answer:

(-14/6) and (2/4) are standard form

Order the set of numbers (2.2, 2, 1/5, 2.25, v5) from greatest to least.

Answers

Answer:

2.25, v5, 2.2, 2 1/5, 2

Step-by-step explanation:

v5 = 2.24

This morning, Lashonda's car had 13.01 gallons of fuel. Now, 2.6 gallons are left. How much fuel did Lashonda use?​

Answers

Answer:

10.41

Step-by-step explanation:

Given ,

Lashonda's car had 13.01 gallons of fuel.2.6 gallons are left now.

To Find : Number of Fuel used

Let us take the Number of fuel used as 'x'

13.01 = x + 2.60

x = 13.01 - 2.60

x = 10.41

Hence, the fuel used by Lashonda is 10.41

Lily has 15% more books than Jessica. If Lily has 150 more books than Jessica, how many books do they have together?


(pls help quickly....also pls include the steps cuz I have no idea how this works...)

Answers

Answer: 2150 books

Step-by-step explanation: Let the number of books Jessica has be the variable x. Percentage works the same way as multiplying fractions, for example 19% of "something" is 19/100 times that "something". If Jessica has x books, and Lily has 15% more books (that is, 115% Jessica's books), at the same time Lily has 150 more books, it's safe to assume that 15% of x is 150, and so, 15x/100 = 150, if so, 15x = 15000, and x = 1000. Now that Jessica has 1000 books, and Lily has Jessica's books and 150 more (or 1000 + 150), the problem sums up to (1000 + 150 + 1000) = 2150.

What is the end behavior of:
1. [tex]\sqrt{6x}[/tex]
2. [tex]\sqrt{x-5}-6[/tex]
3. [tex]-3\sqrt{x+3}+7[/tex]

Answers

The end behavior of each function is defined as follows:

1. [tex]\sqrt{6x}[/tex]: as x -> ∞, f(x) -> ∞.

2. [tex]\sqrt{x - 5} - 6[/tex]: as x -> ∞, f(x) -> ∞.

3. [tex]-3\sqrt{x + 3} + 7[/tex]: as x -> ∞, f(x) -> -∞.

How to obtain the end behavior of the functions?

The end behavior of a function is given by the limit of the function is the input x goes to either negative infinity or positive infinity.

The functions in this problem are all variations of the square root function, which is defined only for non-negative numbers, and thus only the limit when x goes to infinity has to be considered.

As x goes to infinity, the square root goes to infinity, which already define the end behavior for items 1 and 2.

For item 3, the negative leading coefficient means that the function is reflected over the x-axis, assuming a negative value, and thus the end behavior is that the function goes to negative infinity.

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if xy + 9ey = 9e, find the value of y'' at the point where x = 0.

Answers

The value of y'' at the point where x=0 is[tex]9 e y^{\prime \prime}=\frac{1}{9 e}$[/tex] ([tex]e^{2}[/tex])

Differentiation is one of the two important concepts apart from integration. Differentiation is a method of finding the derivative of a function. Differentiation is a process, in maths, where we find the instantaneous rate of change in function based on one of its variables. The most common example is the rate change of displacement with respect to time, called velocity. The opposite of finding a derivative is anti-differentiation.

If x is a variable and y is another variable, then the rate of change of x with respect to y is given by dy/dx. This is the general expression of derivative of a function and is represented as f'(x) = dy/dx, where y = f(x) is any function.

[tex]$x y+9 e^y=9 e$[/tex]

at [tex]x =0[/tex]

[tex]$9 e^y=9 e$[/tex]

[tex]$y=1$[/tex]

[tex]$w \cdot r . t x$[/tex]

[tex]$\left(y+x y^{\prime}\right)+9 e^y y^{\prime}=0[/tex]

at [tex]x=0[/tex]

[tex]$1+9 e y^{\prime}=0$[/tex]

[tex]$y^{\prime}=-\frac{1}{9 e}$[/tex]

[tex]$--------$[/tex]

[tex]$\left(y+x y^{\prime}\right)+9 e^y y^{\prime}=0$[/tex]

[tex]y^{\prime}+x y^{\prime \prime}+y^{\prime}+9 e^y y^{\prime \prime}+9 e^y\left(y^{\prime}\right)^2=0[/tex]

at [tex]x=0[/tex]

[tex]2\left(-\frac{1}{9 e}\right)+9 e y^{\prime \prime}+9 e\left(-\frac{1}{9 e}\right)^2=0[/tex]

[tex]-\frac{2}{9 e}+9 e y^{\prime \prime}+\frac{1}{9 e}=0[/tex]

[tex]9 e y^{\prime \prime}=\frac{1}{9 e}$[/tex][tex]\left(e^2)\right[/tex]

Therefore, the value of y'' at point where x=0 is [tex]9 e y^{\prime \prime}=\frac{1}{9 e}$[/tex]  ([tex]e^{2}[/tex])

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The function, "f" is defined by the following rule. f(x)=3x-1

Answers

Answer:

i don't know

Step-by-step explanation:

The amount of time it takes a student from school A to do a math activity follows the Normal distribution with a mean of 25 minutes and a standard deviation of 5 minutes. Students at school B complete a math activity with a mean time of 20 minutes and have a standard deviation of 8 minutes.

a.) If we take a random student from School A and a random student from School B. What is the expected difference in their minutes?

b.) What is the standard deviation of the difference of their minutes?

Answers

a.) The expected difference in their minutes is 25 - 20 = 5 minutes.

b.) To find the standard deviation of the difference, we can use the formula for the standard deviation of the difference between two normally distributed random variables:

sqrt(sd_1^2 + sd_2^2) = sqrt(5^2 + 8^2) = sqrt(25 + 64) = sqrt(89) = 9.43 minutes.

x/6 = 11/12 need to solve the equation for x helppppp

Answers

Answer: x= [tex]5\frac{1}{2}[/tex]

Step-by-step explanation:

[tex]\frac{x}{6} = \frac{11}{12} \\x(12)=11(6)\\12x=66\\\frac{12x}{12} =\frac{66}{12} \\x=\frac{11}{2} \\x=5\frac{1}{2}[/tex]

(you should cross-multiply the numbers)

(if the numerator is greater than the denominator then you  

                      should leave the answer as a mixed fraction)

Answer:

x= 11/2 or 5.5

Step-by-step explanation:

x/6 = 11/12

LCM = 12

=12 × x/6 = 12 × 11/12

=2(x) = 11 Note. 6 goes into 12 "2" and 12 goes into 12 "1"

=2x = 11

=2x/2 11/2

x = 11/2 or 5.5.

if f and g are differentiable and f(x) ≥ g(x) for a < x < b, then f '(x) ≥ g'(x) for a < x < b.

Answers

This statement is not always true. It's only true if f(x) and g(x) are both non-decreasing functions.

If f(x) and g(x) are non-decreasing functions, the inequality f(x) ≥ g(x) for a < x < b holds, meaning that the values of f(x) are always greater than or equal to the values of g(x) for x within the interval [a,b]. Since the derivative of a non-decreasing function is non-negative, it follows that f'(x) ≥ 0 and g'(x) ≥ 0 for all x in the interval [a,b], which implies f '(x) ≥ g'(x) for a < x < b.

However, if f(x) and g(x) are not non-decreasing functions, this statement is not true. The inequality f(x) ≥ g(x) for a < x < b does not necessarily imply that the derivatives f '(x) and g'(x) will also be greater than or equal for all x in the interval [a,b].

Therefore, This statement is not always true. It's only true if f(x) and g(x) are both non-decreasing functions.

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A number is increased by 2/5 to 49. What was the number?

Answers

Answer: 35

Step-by-step explanation:

35*140%=49

Explain the error in the work and how you might prevent it.

Answers

The error is [tex]12x^2 - 14x = - 26x^2[/tex] because 12x² and 14x are unlike terms, so we can not add them

To prevent it the dividend must be written as [tex]6x^3 + 0x^2 - 14x + 1[/tex]

Now, According to the question:

In the division, you must arrange the dividend according to the greatest power of the variable, and put 0 as a coefficient of the missing term to avoid adding, unlike terms.

Example:

If the dividend is [tex]3x^3 - 2x + 5[/tex], then you must write it as [tex]3x^3 + 0x^2 - 2x + 5[/tex]

Let us solve our question

∵ The dividend is [tex]6x^3[/tex] + 1 - 14x

→ You must arrange it from the greatest power of x

∴ The dividend is [tex]6x^3[/tex] - 14x + 1

∵ The term of x² is missing

→ Write it in the dividend with a coefficient of 0

∴ The dividend is  [tex]6x^3 + 0x^2 - 14x + 1[/tex]

The error is the adding of unlike terms

∵  [tex]6x^3[/tex]- 14x + 1 ÷ 3x + 6 = 2x² and [ [tex]6x^3[/tex] - 14x + 1 - [tex]6x^3[/tex] - ( [tex]6x^3[/tex] + [tex]12x^2[/tex])]

∵[tex][6x^3 - 14x + 1 - 6x^3 - (6x^3 + 12x^2)] = 6x^3 - 14x + 1 - 6x^3 - 12x^2[/tex]

∵ [tex]6x^3 - 14x + 1 - 6x^3 - 12x^2 = 0 - 12x^2 - 14x + 1[/tex]

∵[tex]0 - 12x^2 - 14x + 1 = -26x^2 + 1[/tex] ⇒ error

∴ The error is  -12x² - 14x = - 26x² because 12x² and 14x are unlike terms,

  so we can not add them

→ To prevent it, write 0 as a coefficient of the missing term

∵ The missing term is the term of x²

∴ Add to the dividend the term 0x²

∴ The dividend must be written as [tex]6x^3 + 0x^2 - 14x + 1[/tex]

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Solve for x. The answer to each problem will match a letter that will allow you to figure out the joke. 1. 5x – 7 = 4x + 3
2. 6 + 2x = 7x – 9
3. 8x + 1 = -8 – x
4. -5 + 12x = 18x + 7
5. -4x + 3 = 5x – 13 - x

Answers

The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3 That gives you the letters "joke"1.  5x – 7 = 4x + 3.

To solve for x, we can add 7 to both sides of the equation and subtract 4x from both sides:

5x - 7 + 7 = 4x + 3 + 7

5x = 4x + 10

x = 10

2.  6 + 2x = 7x - 9

To solve for x, we can add 9 to both sides of the equation, subtract 6 from both sides and divide both sides by -1:

6 + 2x + 9 = 7x - 9 + 9

2x = -3

x = -3/2

3. 8x + 1 = -8 - x

To solve for x, we can add x to both sides of the equation and add 8 to both sides:

8x + 1 + x = -8 - x + x + 8

9x + 1 = 0

x = -1/9

4. -5 + 12x = 18x + 7

To solve for x, we can subtract 12x from both sides of the equation and add 5 to both sides:

-5 + 12x - 12x = 18x + 7 - 12x

-5 = 6x + 7

x = -6

5.  -4x + 3 = 5x - 13 - x

To solve for x, we can add x to both sides of the equation, subtract 3 from both sides and divide both sides by -1:

-4x + 3 + x = 5x - 13 - x + x + 3

-3x = -10

x = 10/3

The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3

That gives you the letters "joke"

Therefore, The letters corresponding to the solutions are: x = 10, x = -3/2, x = -1/9, x = -6, x = 10/3 That gives you the letters "joke"1.  5x – 7 = 4x + 3.

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which angle corresponds to ∠8 ?

Answers

The angle which corresponds the ∠8 is ∠4 as ∠8 and ∠4 are parallel to each other.

What are parallel lines ?

parallel lines can be defined as the lines which are equi distant from each other and these lines never interest to each other.

Given ,

from the figure

the parallel lines are l and m.

the angles ∠1,∠2,∠3,∠4,∠5,∠6,∠7,∠8.

∠1,∠2,∠3,∠4. are in one plane

and ∠5,∠6,∠7,∠8. are in another plane.

so the angle which corresponds the ∠8 is ∠4 as ∠8 and ∠4 are parallel to each other.

Hence ,  the angle which corresponds the ∠8 is ∠4 as ∠8 and ∠4 are parallel to each other.

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A construction crew was made up of 12 men and the rest women. If 40% of the crew were men, how many women were in the crew

Answers

Answer:

Step-by-step explanation:

12 is 40% of what number?

30.

what is 60% of 30?

18

boom

Find the slope of a line perpendicular to the line whose equation is x - 6y =24. fully simplfy your answer

Answers

Answer:

Step-by-step explanation:

The slope of a line perpendicular to a given line is the negative reciprocal of the slope of the given line. To find the slope of the line x - 6y = 24, we can rearrange the equation to the form y = (1/6)x + 4. So the slope of the line is 1/6.

The slope of a line perpendicular to this line would be the negative reciprocal of 1/6 which is -6

determine the average rate of change in concentration of b from t=0 s to t=282 s.

Answers

The average rate of change in concentration of B from t=0 s to t=282 s is equals to the 0.00440 M/s.

Average rate of change in concentration is defined as the change in concentration divided by change in time , i.e , ∆c/∆t. Since we have provide the concentrations of reactant (A), we can determine the average change in A first. In first observation, Change in [A] = 0.410 - 0.720 M = - 0.310 M

Change in time = 141 s - 0 s = 141 s

rate of Change in concentration

= -0.310/141 = - 0.00220 M/s

In second observation, rate of change in concentration A =(0.100 - 0.410)/(282 - 141)

= - 0.310/141 = - 0.00220 M/s

Average Rate = - 0.310 M / 141s

= - 0.00220 M/s

here, negative sign indicating the [A] is decreasing over time.

To determine the average rate of change of B, we use the stoichiometry of the equation, A⟶2B

For every A that is used, 2 B's are produced (product). So, average rate of change of B = 2 x 0.00220

= +0.00440 M/s

(positive sign means B is being formed).

So, required average rate of change is 0.00440 M/s.

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Complete question:

determine the average rate of change in concentration of b from t=0 s to t=282 s. A⟶2B

Time (s). Concentration of A (M)

0. 0.720

141. 0.410

282. 0.100

Help pleaseeee thanks

Answers

Answer:

I'd say A, Adjacent

Step-by-step explanation:

I think its A because adjacent means together/along with, and these angles are next to each other.

Please help I can't figure it out

Answers

Answer:

quadrilateral, rhombus i think

Step-by-step explanation:

I need it done by today.

Answers

By algebra properties, the integer 975 is equivalent to rational expression 650 / (2 / 3).

How to simplify a rational expression to a unit rate

Rational numbers are real numbers of the form m / n, where m and n are integers and n is a non-zero integer. In this problem we find a rational expression of the form (a / b) / (c / d), where a, b, c, d are also integers and b and d are non-zero integers.

This expression must be simplified into a rational number of the form m / n, this can be done by the following algebra property:

(a / b) / (c / d) = (a · d) / (b · c)

If we know that a = 6, b = 1, c = 2 and d = 3, then the resulting expression is:

650 / (2 / 3) = (650 / 1) / (2 / 3) = (650 ÷ 1) / (2 ÷ 3) = (650 × 3) / (1 × 2) = 1950 / 2 = 975 / 1 = 975

The rational expression 650 / (2 / 3) is equivalent to integer 975.

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Amy is having her birthday party at a roller skating rink. The rink charges a fee of $100 plus $16 per person. A birthday person is not charged. If Amy wants to spend at most $350 for the party, how many people can she invite to her party

Answers

Amy can invite 15 people to her party since $100 is the fee plus $16 per person, meaning $340 would be spent on the guests and the total cost would be $340.

To calculate the number of people that can be invited, we need to set up an equation. Let x represent the number of people attending the party. We know that the cost is $100 plus $16 per person, so we can set up the equation: (100 + 16x) ≤ 350.

We then subtract 100 from both sides to get 16x = 250. Finally, we divide both sides by 16 to get x = 15.5. Since we can't have a fraction of a person, we round down to 16, and then add the birthday person, giving us a total of 16 people.

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A recipe calls for 4 boxes of rice to serve 13 people. If you want to serve 39 people, what should you do?.

Answers

A recipe calls for 4 boxes of rice to serve 13 people. If you want to serve 39 people, you need to call 12 boxes of rice.

As A recipe calls for 4 boxes of rice to serve 13 people.

It means that 4 boxes are sufficient to serve 13 people.

So, from above,

We can conclude that,

In 2 boxes, we can serve 6(1/2) people,

When we double the number of boxes we can serve the double person.

So, we can come to the conclusion,

In 8 boxes we can serve (13*2 = 26) people.

As we need to serve 39 people,

So, we order 8 + 4 = 12 boxes.

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You should use 12 number of boxes of rice to serve 39 people.

1. The recipe calls for 4 boxes of rice to serve 13 people

2. To serve 39 people, you need to multiply the amount of boxes of rice by 3

3. 4 boxes of rice * 3 = 12 boxes of rice

4. Therefore, you should use 12 boxes of rice to serve 39 people.

A recipe calls for 4 boxes of rice to serve 13 people, but if you want to serve 39 people, you need to multiply the amount of boxes of rice by 3. This means that 4 boxes of rice * 3 = 12 boxes of rice. Therefore, you should use 12 boxes of rice to serve 39 people, which is three times the amount that the recipe calls for. To serve even more people, you can simply keep multiplying the amount of boxes of rice by the number of people you want to serve. For example, to serve 100 people, you would need to use 40 number of boxes of rice (4 boxes of rice * 10 = 40 boxes of rice). Knowing this, you can easily adjust the amount of boxes of rice needed to serve any number of people.

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Value of x when 48= 3x

Answers

Answer:

Step-by-step explanation:

x = 16

Answer:

x = 16

Step-by-step explanation:

If 3 · 16 = 48 Then x = 16

A local charity is selling seats to a baseball game. Seats cost $32 each, and snacks cost an additional $8
each. The charity needs to raise $640 to consider this event a success.
Use the graph to approximate how many snacks the charity must sell if 10 seats are sold.
32 s +8y=640

Answers

By using the graph, the amount of snacks that the charity must sell if 10 seats are sold is equal to 40 snacks.

How to write and solve the equation graphically?

In order to graphically solve the equation, we would write an equation that models the situation by assigning variables to the cost of seats and cost of snacks, and then translate the word problem into algebraic equation as follows:

Let the variable s represent the cost of seats.Let the variable y represent the cost of snacks.

Since the seats cost $32 each and snacks cost an additional $8 each while the charity needs to raise $640, an equation that models the situation is given by;

32s + 8y = 640

By critically observing the graph, the charity must sell 40 snacks if 10 seats are sold.

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