Some atoms are neutral and others have positive or negative charges.
The charged atoms are called "ions".
- If the ion has positive charge, it is called cation.
- If the ion has negative charge, it is called anion.
Ions can be identified by their charge, for example:
- Cations: Na^+1, K^+1, Mg^+2
- Anions: Cl^-1, Br^-1
Write the correct formula for the following compound:
magnesium hydroxide
The formula of magnesium hydroxide is Mg(OH)2.
How magnesium hydroxide?Magnesium hydroxide is an inorganic compound having the chemical formula of Mg(OH)2. It is present in nature as mineral brucite. It is a white solid substance with low solubility in water. Magnesium hydroxide is a component of antacids such as milk of magnesia. Extended use or overuse of this medication for constipation results in dependence on laxatives and constipation. Overuse of Magnesium hydroxide also causes diarrhea that does not go away, dehydration, and mineral imbalances. Severe nausea, vomiting, or diarrhea are the symptoms of using a high dose of magnesium hydroxide. After using a medicine such as a laxative, nausea, vomiting or diarrhea can be cured.
So we can conclude that Mg(OH)2 is the correct formula for magnesium hydroxide.
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find the natural logarithm of7.56
Sulfur burns in oxygen to form sulfur dioxide. Write a skeleton equation for this chemical reaction.
A skeletal chemical equation is a representation of a chemical reaction using chemical formulae of reactants and products.
Sulfur = S
Oxygen = O
Sulfur dioxide = SO2
The skeleton equation is:
[tex]S+O_2\text{ }\Rightarrow SO_2[/tex]Here the skeleton equation = balanced equation.
I need help with something please
Since both metals are in the same group in the periodic table and both non-metals are also in the same group in the periodic table, they have the same charge (metals = 1+; non-metals = 1-). So this makes the reaction easier for us:
NaCl + LiBr = LiCl + NaBr
Why is reproducibility so important to scientistis
Answer: They serve as proof that an established and documented work can be verified, repeated, and reproduced.
Explanation: Reproducibility and research integrity are essential tenets of every scientific study and discovery. They serve as proof that an established and documented work can be verified, repeated, and reproduced. New knowledge in biomedical science is built on the shoulders of established and proven principles.
Answer:
Evidence of accuracy
Explanation:
it creates new opportunities for insights and facilitates innovation in terms of scientific knowledge.
A student finds two green powders that look the same. He wants to figure out if the two powders are the same or different substances. Which of the following is
the best method to use?
I temperature of each powder
Mix the two green powders together and then test the properties.
A student finds two green powders that look the same he wants to figure out if the two powders are the same or different substances then mix the two green powders together and then test the properties
A powder is a dry bulk solid composed of many very fine particles that may flow freely when shaken or tilted and to figure out unknown two mixture powder are same or different then student want to mix the two green powders together and then test the properties because of properties student the two unknown powder are to be determined
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In the following equation, how many grams of CO2 are produced if 2 moles of O2 react completely with methane (CH4)? CH4 + 2O2 -> CO2 + 2H2OHELPFUL INFO: molar mass of CO2=44g/mol, molar mass of O2=32g/mol, molar mass of CH4=16g/mol, and molar mass of water = 18g/mol
Step 1 - "Reading" the equation
The given chemical equation is:
[tex]CH_{4(g)}+2O_{2(g)}\to CO_{2(g)}+2H_2O_{(l)}[/tex]The bigger numbers, those that come before the formulas of the substances, indicate the quantity in moles of each substance required in this rection.
We can "read" this reaction thus as :
one mole of CH4 reacts with 2 moles of O2 thus producing one mole of CO2 and two moles of H2O
As the exercise is specifically asking about the proportion between O2 and CO2, we can further simplify this statement to:
two moles of O2 produce one mole of CO2
Step 2 - Obtaining the "recipe" for the reaction
In order to obtain a relation in grams, we need to multiply the number of moles of each substance by its respective molar mass. Let's remember that:
two moles of O2 produce one mole of CO2
Therefore, converting to grams (molar masses: 32 g/mol for O2; 44 g/mol for CO2)
[tex]\begin{gathered} O_2\to2\text{ moles }\times32\text{ g/mole = 64g} \\ CO2\to1\text{ mole }\times44\text{ g/mole = 44g} \end{gathered}[/tex]We have now obtained the "recipe" for this reaction:
64g of O2 produce 44g of CO2
Pretty much as we would with a cake recipe, we can use this to predict how much CO2 is formed.
Since the reaction of two moles of O2 is exactly what we have already calculated, 44g of CO2 would be formed in this reaction.
The solubility in hexane of organic compound O is measured and found to be 0.520-that would contain 120. mg of O at this temperature.Be sure your answer has the correct unit symbol and 3 significant digits.00.0olo88at 25. °C. Calculate the volume of a saturated solution of O in hexanemLE
According to the explanation given in the previous session, now we have hexane in an organic compound with the solubility of 0.520 g/mL at 25°C. We need to find the value of volume at 120.0 mg
1 gram = 1000 mg
120.0 mg = 0.12 grams
Now we can calculate the volume:
0.520g = 1 mL
0.12g = x mL
0.520x = 0.12
x = 0.12/0.520
x = 0.231 mL is the volume for this compound
Complete the balanced dissociation equation for the compound below. If
the compound does not dissociate, write NR after the reaction arrow.
LiOH(s) →
LiOH ⇌ Li + + OH - NR
When there are too many OH ions, water dissociates fully to the left, possibly leaving only Li + and OH ions and H 2 O molecules.
IN CHEMISTRY, WHAT IS AN ION?An atom or collection of atoms that is classified as an ion as a different number of electrons than proton atoms. The particle is a positive ion, also known as a cation, if the number of electrons is smaller than the number of protons.
How do ions form?Ions are created when there are more protons in an atom than electrons, which is the case in all atoms. An atom that has gained or lost one or more electrons, and as a result has a negative or positive charge, is what is referred to as an ion. Exchanging electrons between atoms or molecules is the process of ionization.
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I’m not sure and I’m kind of confused can anyone help?
We will reconstruct the model in the following manner :
From the above diagram we can see that :
• number of Carbon atom = 3
• number of hydrogen atom = 8
• rewrite this in an alphabetical order, you get :
[tex]\begin{gathered} C_3H_8\text{ } \\ \Rightarrow Propane\text{ } \end{gathered}[/tex]the molecule has a chemical formula = C3H8Classify the following compounds as alkane, alkene, alkyne based on the given structure
We have the next compounds
And we must classify them as alkane, alkene, alkyne.
We need to know that
- Alkane: They are the simplest hydrocarbons, containing only carbon and hydrogen held together by single bonds.
- Alkene: Alkenes are hydrocarbons that contain a double bond.
- Alkyne: Alkynes are hydrocarbons that contain a triple bond.
1. We can see that the structure has a double bond. So, it is an Alkene.
2. We can see that the structure has a triple bond. So, it is an Alkyne.
3. We can see that the structure has a double bond. So, it is an Alkene.
4. We can see that the structure has a triple bond. So, it is an Alkyne.
ANSWER:
1. Alkene
2. Alkyne
3. Alkene
4. Alkyne
0.650 moles of O₂(g) are added to 1.00 L flask and the internal pressure is measured at 20.00 atm. What is the temperature of the gas under these conditions (in *C)?___ °C ?
Answer:
T = 101.96 degrees
Explanation:
We are given the following
Number of moles = 0.650 mol
Volume = 1.00 L
Pressure = 20.00 atm
We are going to use the ideal gas low which is given by:
pV = nRT
Therefore:
[tex]T\text{ = }\frac{pV}{nR}[/tex]We know R = 0.08206 L.atm/Kmol
[tex]\begin{gathered} T\text{ = }\frac{20\ast1}{0.65\ast0.08206} \\ T\text{ = 374.960 K} \end{gathered}[/tex]T(in degrees) = 374.96 - 273
= 101.96 degrees
The 946 mL of Gatorade bottle contains FD&C Blue I at concentration of 0.100mg/L. Molar mass of Blue I is 792.84 g/mol.
a) Calculate the molarity of Blue I in Gatorade.
b) How many molecules of Blue I would you consume by drinking the entire bottle of Gatorade.
The molarity of Blue I in Gatorade is 0.00010 mol L⁻ molecules of Blue I would you consume by drinking the entire bottle of Gatorade is 4.77 mol
Molarity is the amount of substance in certain volume of solution and also moles of solute per liter of solution
Here given data is
Volume = 946 mL
Molar mass = 792.84 g/mol
Concentration = 0.100mg/L
We have to find molarity and molecules of Blue I would you consume by drinking the entire bottle of Gatorade = ?
Molarity = number of moles of solute/volume of solution
Molarity = 0.100mg/L/946 mL
Molarity =0.00010 mol L⁻
Now we have to find molecules of Blue I = ?
Molecules of Blue I = 792.84 g/mol × avagadro number
Avagadro number = 6.022×10²³
Molecules of Blue I = 792.84 g/mol×6.022×10²³
Molecules of Blue I = 4.77 mol
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What is the percent mass of 42.5 g KCl dissolved in 122.5 g water?
Answer
% mass of KCl = 25.76%
Explanation
Given:
mass of KCl = 42.5 g
mass of water = 122.5 g
Required: The % mass of KCl
Solution:
Step 1: Calculate the total mass
42.5 g + 122.5 g = 165 g
Step 2: Calculate the % of KCl
%KCl = (42.5/165)*100
%KCl = 25.76%
A balloon filled to 2.0 L here in Michigan (at 20°C and 752 mmHg) is taken to the top of Mt. Everest. The pressure at the top of Mt. Everest is 253 mmHg, and the balloon grows to a size of 5.1 L. What is the temperature (in °C) at the top of Mt. Everest?
tellsTo answer this question we can use the Combined Gas Law, which tell us that the pressure, volume, and temperature of one situation is equal to the second situation, now let's see how is this formula and how can we apply it to our question:
P1 * V1/T1 = P2 * V2/T2
Now in your question:
1 * 2/20 = 0.33 * 5.1/T2 (I did the transformation mmHg - atm, that makes the question easier, so 752 mmHg = roughly 1 atm and 253 mmHg = 0.33 atm)
2/20 = 1.683/T2
0.1 = 1.683/T2
T2 = 16.8°C
10. When a metal atom combines with a nonmetal
atom, the nonmetal atom will
A. lose electrons and decrease in size
B. lose electrons and increase in size
C. gain electrons and decrease in size
D. gain electrons and increase in size
When a metal atom combines with a nonmetal atom, the nonmetal atom will gain electrons and decrease in size
What happen when metal react with non metal ?In a reaction between metals and non-metals, electrons are moved from the metal atoms to the non-metal atoms, resulting in the formation of ions. An ionic compound is the name given to the resulting substance.
Ions are created when metals and non-metals interact because the metal atoms' electrons are transferred to the non-metal atoms.The end result of this procedure is an ionic compound. Metal atoms provide their electrons to non-metal atoms. Metal atoms change into positive ions, whereas non-metal atoms change into negative ions.Learn more about Metals and non metal here:
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Given the equation below, how many moles of nitrogen gas (N2) areneeded to react with 7.5 moles of hydrogen gas (H2)?N2+ 3H2 —>2 NH3
Answer
2.5 moles of N₂ are needed to react with 7.5 moles of hydrogen gas
Explanation
Given:
Equation: N₂ + 3H₂ → 2NH₃
Moles of H₂ = 7.5 moles
What to find:
The moles of nitrogen gas (N₂) needed to react with 7.5 moles of hydrogen gas
Step-by-step solution:
Let the mole of N₂ needed be x.
From the given balanced chemical equation:
3 moles of H₂ react with 1 mole of N₂
Therefore, 7. 5 moles of H₂ will react with x moles of N₂
Cross multiply
[tex]\begin{gathered} x\text{ moles }N_2\times3\text{ moles H}_2=7.5\text{ moles H}_2\times1\text{ mole N}_2 \\ \text{Divide both sides by 3 moles H}_2 \\ \frac{x\text{ moles }N_2\times3\text{ moles H}_2}{3\text{ moles H}_2}=\frac{7.5\text{ moles H}_2\times1\text{ mole N}_{2}}{3\text{ moles H}_2} \\ x\text{ moles }N_2=2.5\text{ moles} \end{gathered}[/tex]4 Al(s) + 302(g)->2Al2O3(s)When 42.39 g of Al and 85.16 g of O2 were reacted, 6.67 grams of aluminum oxidewere obtained. What is the percent yield? (Hint: You need to determine which one isthe limiting reactant and then the theoretical yield).
The reaction presented to us is balanced since we have 4 aluminum atoms and 6 oxygen atoms on both sides of the reaction.
Now, we have a given mass of aluminum and oxygen, we must first determine the moles of each using their molar mass.
Moles of Al
[tex]\begin{gathered} \text{Mol of Al}=GivengAl\times\frac{1molAl}{MolarMass,gAl} \\ \text{Mol of Al}=42.39gAl\times\frac{1molAl}{26.98gAl}=1.57molAl \end{gathered}[/tex]Moles of O2
[tex]\begin{gathered} MolO_2=GivengO_2\times\frac{1molO_2}{MolarMass,gO_2} \\ MolO_2=85.16gO_2\times\frac{1molO_2}{31.998gO_2}=2.66molO_2 \end{gathered}[/tex]Now that we have the number of moles, we will calculate what the limiting reagent is, that is, the reagent that limits the reaction by its number of moles.
To find the limiting reactant we must compare the amount of product obtained with the given amount of reactant separately. The reactant that produces the least amount of product is the limiting reactant.
Using Al as limiting reactant
[tex]\begin{gathered} \text{MolAl}_2O_3=MolAl\times\frac{2molAl_2O_3}{4molAl} \\ \text{MolAl}_2O_3=1.57molAl\times\frac{2molAl_2O_3}{4molAl}=0.785molAl_2O_3 \end{gathered}[/tex]Using O2 as a limiting reactant
[tex]\begin{gathered} \text{MolAl}_2O_3=MolO_2\times\frac{2molAl_2O_3}{3molO_2} \\ \text{MolAl}_2O_3=2.66molO_2\times\frac{2molAl_2O_3}{3molO_2}=1.77molAl_2O_3 \end{gathered}[/tex]Aluminum is the reagent that produces the least amount of aluminum oxide, so the limiting reagent will be Al. And it will produce 0.785 moles of Al2O3. In grams this will be:
[tex]\text{gAl}_2O_3=0.75molAl_2O_3\times\frac{101.95gAl_2O_3}{1molAl_2O_3}=80.03gAl_2O_3[/tex]The percent yield will be:
[tex]\begin{gathered} \text{Percent yield=}\frac{\text{Actual yield}}{Theoretical\text{ yield}}\times100\% \\ \text{Percent yield=}\frac{\text{6}.67gA_{}l_2O_3}{80.03ggA_{}l_2O_3}\times100\%=8.33\% \end{gathered}[/tex]The percent yield will be 8.33%
Calculate the imperial formula of the compound. Express your answer as a chemical formula.
The empirical formula corresponds to the simplest form of expressing a compound, it indicates the proportion of atoms in the molecule.
We have two elements S and F and they give us the mass resulting from the decomposition of the molecule. We can find the moles of each element using the atomic weight of each element as follows:
[tex]\begin{gathered} \text{Moles S= Given g of S}\times\frac{1\text{ mol S}}{AtomicWeight,\text{ g S}} \\ \text{Moles S= 0.905 g of S}\times\frac{1\text{ mol S}}{32.065\text{ g S}}=0.028\text{mol S} \end{gathered}[/tex][tex]\begin{gathered} \text{Moles F= Given g of F}\times\frac{1\text{ mol F}}{AtomicWeight,\text{ g F}} \\ \text{Moles F=3.221 g of F}\times\frac{1\text{ mol F}}{18.998\text{g F}}=0.170\text{mol F} \end{gathered}[/tex]To find the ratio between the elements we divide the moles of each element by the smallest number of moles found, that is by 0.028 moles.
[tex]\begin{gathered} S\rightarrow\frac{0.028}{0.028}=1 \\ F\rightarrow\frac{0.170}{0.028}=6 \end{gathered}[/tex]Therefore the empirical formula of the compound will be:
[tex]SF_6[/tex]Please help with Chemistry I'm confused at the elements reactivity:
Question:
Which of the following combination of elements is the most reactive?
Answer options:
A: Potassium and Iodine
B: Caesium and Iodine
C: Sodium and Bromine
D: Caesium and Bromine
The combination of elements that is the most reactive would be caesium and bromine.
Reactivity of metals and non-metalsThe reactivity series of elements is a table that shows how reactive elements are, usually in descending order.
Elements are classified as metals, non-metals, and metalloids. Metals or non-metals that are at the top of the reactivity series are highly reactive and cannot be displaced in solution by metals below them.
Highly reactive non-metals are also usually at the top of the reactivity series of non-metals. They are able to form compounds with a wide variety of elements.
A typical reactivity series of metals include caesium, rubidium, potassium, sodium, lithium, etc. A reactivity series of non-metals include fluorine, chlorine, oxygen, bromine, iodine, etc.
Thus, bromine is more reactive than iodine and caesium is more reactive than potassium and sodium.
The combination of elements that are the most reactive among the options is, therefore, Caesium and Bromine.
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2A + C + D + EDetermine the enthalpy(AH)in kJ of the above reaction using the reactions below:1B → C AH = 415.3 kJA + 1B →D AH = -95.7 kJ6A ->6E AH = 207.9 kJ
Explanations:
• We will follow Hess's Law of Constant Heat Summation:
(that states that if a reaction occurs in more than one route, then the the total enthalpy change for the reaction is the sum of all changes.)
For reaction :
[tex]\begin{gathered} B\Rightarrow C\text{ }\Delta H\text{ = 415.3 kJ }\ldots\text{.}\mathrm{}(\text{ reaction 1)} \\ A+B\text{ }\Rightarrow\text{ D }\Delta H\text{ = -95.7kJ}\ldots.(\text{ reaction 2 ) } \\ 6A\text{ }\Rightarrow6E\text{ }\Delta H\text{ = 207.9kJ }\ldots\ldots(\text{reaction 3 ) } \end{gathered}[/tex]∆H total =( reaction 3 )/6 +reaction 2 - reaction 1this can be expressed as :
[tex]\begin{gathered} \Delta H_{total\text{ }}=\text{ }\frac{207.9}{6\text{ }}+(-95.7\text{ ) - 415}.3\text{ } \\ \text{ = 34.65 -95.7 -415.3} \\ \text{ =-476.35kJ} \end{gathered}[/tex]This means that ∆H total= -476.35kJ.
A 51.72 g sample of a substance is initially at 23.5 °C. After absorbing 2547 J of heat, the temperature of the substance is 123.4 °C. What is the specific heat ( ) of the substance?
The heat absorbed or released by a substance is given by the following formula:
[tex]Q=m\cdot Cp\cdot(T2-T1)[/tex]Where Q is the heat absorbed or released, m is the mass of the substance, Cp is the specific heat, T2 is the final temperature and T1 is the initial one.
We know the values of Q, m, T2 and T1 because they are given by the question statement, and we have to find the value of Cp.
Solve the equation for Cp and use the given values to find its value:
[tex]\begin{gathered} Cp=\frac{Q}{m\cdot(T2-T1)} \\ Cp=\frac{2547J}{51.72g(123.4\degree C-23.5\degree C)} \\ Cp=\frac{0.49J}{g\degree C} \end{gathered}[/tex]The specific heat of the substance is 0.49J/g°C.
Classify each of the following chemical reactions as a synthesis decomposition and single displacement or double displacement reaction
1. Synthesis reaction : there is only 1 product formed from 2 or more reactant
E.g:
[tex]H_2(g)+N_2(g)\text{ }\Rightarrow2NH_3(g)\text{ }[/tex]2. Decomposition : reaction that occurs in presence of UV light and only 1 reactant that decomposes into 2 or more products.
E.g:
[tex]CH_3Br(g)+UV_{light}\Rightarrow CH_3(g)\text{ + Br (g)}[/tex]3. Single displacement : reaction that occurs when 1 reactant displaces other reactant from its compound:
E.g:
[tex]Zn(s)+CoCl_2(aq)\text{ }\Rightarrow ZnCl_2(aq)\text{ + Co(s)}[/tex]4. Double displacement : reaction that occurs when both reactant displaces each other.
E.g :
[tex]K_2S(aq)+Co(NO_3)_2\Rightarrow2KNO_3(aq)\text{ + }CoS(s)\text{ }[/tex]What is the concentration of A pill weighing 325mg containing 22mg Mg
Step 1 - Understanding percentual concentration
To express the concentration of a substance as a percentual concentration, we just need to divide its mass by the total mass:
[tex]concentration\text{ in \% = }\frac{m_{substance}}{m_{total}}\times100[/tex]Step 2 - Calculating the concentration in the pill
We want to calculate the concentration of Mg in the pill. Therefore, we'll divide its mass by the total mass of the pill:
[tex]concentration\text{ of Mg =}\frac{22mg}{325mg}\times100=6.8\text{ \%}[/tex]Answer: the concentration of Mg in the pill is 6.8%
A bike rides at an average speed of 25 km/h. How many minutes will it take for this rider to ride a distance of 20 km?
Answer:
48 minutes
Explanation:
60 divided by 25 equals 2.4 then you times 2.4 by 20
What is the density of hydrogen sulfide (H2S) at 0.2 atm and 311 K?Answer in units of g/L
Answer
Density = 0.267 g/L
Explanation
Given:
Pressure of H2S = 0.2 atm
Temperature = 311 K
We know:
The molar mass of H2S = 34,1 g/mol
R constant = 0.08206 L.atm/K.mol
Solution:
From the ideal gas law:
PV = nRT
We know that:
density = m/V
n = m/M
Therefore we can use the following equation to solve for density of H2S
[tex]\begin{gathered} density\text{ = }\frac{PM}{RT} \\ density\text{ = }\frac{(0.2\text{ atm x 34,1 g/mol\rparen}}{(0.08206\text{ }L.atm/K.mol\text{ x 311 K\rparen}} \\ \\ density\text{ = 0.267 g/L} \end{gathered}[/tex]In the reaction 2H2 + O2 →2H2O if 14grams of H2 react, how many grams of water could be produced?
Answer:
Explanation:2H2 + O2 —-> 2H2O
The mole ratio of H2 to H2O is 2 : 2 = 1:1
4 moles of H2 = 4 moles of H2O
Moles of H20 = 4mol
Molar mass of H2O = 18g/mol
Mass = moles X Molar mass
= 4mol x 18g/mol
= 72g
Calculate the mass (in g) of 5.86x10^20 SO3 molecules.
Answer
0.0779 g SO₃
Procedure
To solve this question, you will need to use the Avogadro's number equivalent to 6.02214 x 10^23 molecules/ mol, and then the molecular weight in grams per mole for the SO₃.
[tex]5.86\times10^{20}\text{ molecules SO}_3\frac{1\text{ mol SO}_3}{6.02214\text{ x 10}^{23}\text{molecules SO}_3}\frac{80.06\text{ g SO}_3}{1\text{ mol SO}_3}=0.0779\text{ g SO}_3[/tex]Why does an atom want to form an octet or duet?And yes I know these rules and I know that it “wants” a stable electronic configuration and a filled shell.
Answer
An atom wants to form an octet or duet because an atom always wants to be in the most stable form. For any atom, stability is achieved by following the octet rule or duet rule, which is to say all atoms (with a few exceptions) want 8 electrons (octet) or 2 electrons (duet) in their outermost electron shell just like noble gases.
Can you help show me the conversion works for this problem in my online homework please?
There are 2.04*10^-4 moles of hydrogen.
To start the calculation it is necessary to use the molar mass of glycine:
- Glycine molar mass: 75.08 g/mol.
From the formula of glycine, we know that in 75.08g of glycine, there are 5 moles of hydrogen. So, in 3.06*10^-3g of glycine will be another amount of hydrogen, and we can calculate it with a mthematical Rule of Three:
[tex]\begin{gathered} 75.08\text{gGlycine}-5\text{molHydrogen} \\ 3.06\cdot10^{-3}\text{gGlycine}-x=\frac{3.06\cdot10^{-3}\text{gGlycine}\cdot5\text{molHydrogen}}{75.08\text{gGlycine}} \\ x=2.04\cdot10^{-4}\text{molHydrogen} \end{gathered}[/tex]So, there are 2.04*10^-4 moles of hydrogen in 3.06*10^-3g of glycine.
