Factor the expression using the GCF for 44-11

Option B x = -2 to x = 1 in this interval the function is increasing and linear

What does a function show as increasing and decreasing?

If the value of f(x) grows as the value of x increases, the function is said to be increasing; conversely, if the value of f(x) decreases as the value of x increases, the function is said to be declining.

To determine if a function is increasing or decreasing on an interval, we need to know the sign of its first derivative on that interval. To determine if a function is linear, we need to know if the function is of degree one.

A function that is linear is of degree one and the graph of a linear function is a straight line, where the slope of the line is the coefficient of x.

To determine if a function is linear and increasing or decreasing on an interval, we need to determine the sign of the first derivative of the function on that interval, if the first derivative is positive, the function is increasing, if it is negative, the function is decreasing.

Additionally, it is also important to consider the domain of the function, to ensure the function is defined on that interval.

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Answer:

a= [tex]\frac{57}{13}[/tex]

Step-by-step explanation:

Find the value of y by subbing in x

y = 5x-3

y = 5(13) - 3

y = 62

Sub x and y into the 2nd equation, Solve for a

62 = a (13) + 5

62 = 13a + 5

57 = 13a

a= [tex]\frac{57}{13}[/tex]

The unit price of the souvenirs for female teachers is RM5.50.

First, let's define some variables to represent the information given in the problem:

Let M be the number of male teachers

Let F be the number of female teachers

Let P_M be the unit price of the souvenirs for male teachers

Let P_F be the unit price of the souvenirs for female teachers

We are given that M = 16, F = 28, and P_M = RM5. The problem asks us to find P_F.

We can set up the following equation to represent the total cost of the souvenirs:

(M * P_M) + (F * P_F) = RM234

Substituting in the values we know, we get:

(16 * RM5) + (28 * P_F) = RM234

Solving for P_F, we find:

P_F = (RM234 - (16 * RM5)) / 28

P_F = (RM234 - RM80) / 28

P_F = RM154 / 28

P_F = RM5.50

Therefore, the unit price of the souvenirs for female teachers is RM5.50.

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The value of x is 13 / 2 which satisfies the equation "-3 (4x - 5 ) = 2( 1 - 5x)".

In order to determine the value of x that satisfies the equation, we need to solve the equation and find the value of x,

Now solving

the given equation,

-3 (4x - 5 ) = 2( 1 - 5x)

(- 12 x + 15 ) = ( 2  - 10 x)

Shifting the constant terms to one side of the equation and terms having the variable x are kept to another side of the equation.

So,

- 12 x + 10 x =  - 15 + 2

 - 2 x =  -  13

  x = - 13/ - 2

  x = 13 / 2

The value of x is 13 / 2 which satisfies the given equation.

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Answer:

C, D, E

Step-by-step explanation:

Additive inverses is pretty much the same number, but one is positive and one is negative.

In this case C, D, and E would be it.

C; both are 7, but ones negative and ones positive

D; both are 20, but ones negative and ones positive

and same with E... both are 335, but ones negative and ones positive

The number 9 x 10^7 is 30,000 times greater than the number 3 x 10³.

To obtain how many times a number a is greater than a number b, we have to obtain the ratio, which is the division of the number a by the number b.

The numbers in this problem are given as follows:

The division of these two numbers is given as follows:

(9 x 10^7)/(3 x 10³).

The division of the two coefficients is given as follows:

9/3 = 3.

For the powers of 10, we have the division of two terms with the same base and different exponents, hence we keep the base and subtracted the exponents, as follows:

10^7/10³ = 10^(7 - 3) = 10^4 = 10,000.

Hence the complete quotient is given as follows:

3 x 10,000 = 30,000.

Which is how many times the number 9 x 10^7 is greater than the number 3 x 10³.

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Answer:

Step-by-step explanation:

14 - (2% × 14) = 

14 - 2% × 14 = 

(1 - 2%) × 14 = 

(100% - 2%) × 14 = 

98% × 14 = 

98 ÷ 100 × 14 = 

98 × 14 ÷ 100 = 

1,372 ÷ 100 = 

Answer : 13.72

Answer:

Step-by-step explanation:

Find out the difference between the numbers,  Decrease = Old value - New value. Step 2: Divide this 'decrease' by the old value and multiply it by 100. This makes the percent decrease in the formula , Percent Decrease = (Old Value - New Value) / Old Value] × 100]

The pounds of green beans that CJ bought at the market will be 3.75 pounds.

In Mathematics, it is important to note that an expression is simply used to show the relationship between the variables that are provided or the data given regarding an information. In this case, it is vital to note that they have at least two terms which have to be related by through an operator. Some of the mathematical operations that are illustrated in this case include addition, subtraction, etc.

In this case, CJ went to the market and bought 1.5 pounds of potatoes for dinner. He bought 2.5 times as many pounds of green beans.

Therefore, the pounds of green beans that he bought at the market will be:

= 1.5 × 2.5

= 3.75 pounds.

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We draw y=3 on a graph is a straight line perpendicular to y-axis and parallel to x-axis passing through point (0,3)

An unending, one-dimensional figure with no width is a straight line. It consists of an infinite number of points connected on either side of a point. There is no curvature in a straight line. It might be angled, vertical, or horizontal. Any angle we draw between any two locations along a straight line will always be a 180-degree angle. By comprehending the equations of straight lines in various formats and learning how to solve questions based on straight lines, we will explore the universe of straight lines.

So that, we draw y=3 on a graph is a straight line perpendicular to y-axis and parallel to x-axis passing through point (0,3) as shown in attached diagram.

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u in the plane in set of real numbers rℝcubed3 spanned by the columns, then the one solution matrix is,   [tex]\left[\begin{array}{ccc}x_{1} &\\x_{2} &\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}2&\\6.66&\\\end{array}\right][/tex]

Given data,

Let u [-16 18 10] and A [2 -3 1 -4 5 1]

u in the plane in set of real numbers rℝcubed3 spanned by the columns of A,

So,

We can write,

u = [tex]\left[\begin{array}{ccc}-16&\\18&\\10&\end{array}\right][/tex] and A = [tex]\left[\begin{array}{ccc}2&-3\\1&-4\\5&1\end{array}\right][/tex]

Then,

AX = b

w = [tex]\left[\begin{array}{ccc}2&-3&-16\\1&-4&18\\5&1&10\end{array}\right][/tex]

A = [tex]\left[\begin{array}{ccc}2&-3\\1&-4\\5&1\end{array}\right][/tex]

null A = [tex]\left[\begin{array}{ccc}x_{1} &\\x_{2} &\\\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}2&-3\\1&-4\\5&1\end{array}\right][/tex]    [tex]\left[\begin{array}{ccc}x_{1} &\\x_{2} &\\\end{array}\right][/tex]= [tex]\left[\begin{array}{ccc}0&\\0&\\0&\end{array}\right][/tex]

2[tex]x_{1}[/tex] - 3[tex]x_{2}[/tex] = 0

[tex]x_{1}[/tex] - 4[tex]x_{2}[/tex] = 0

5[tex]x_{1}[/tex] + 1[tex]x_{2}[/tex] = 0

We can solve the equations,

2[tex]x_{1}[/tex] - 3[tex]x_{2}[/tex] = 0

[tex]x_{1}[/tex] - 4[tex]x_{2}[/tex] = 0

-----------------------

[tex]x_{1}[/tex] - 7[tex]x_{2}[/tex] = 0

[tex]x_{1}[/tex] = 7[tex]x_{2}[/tex]

We can substitute [tex]x_{1}[/tex] values,

2[tex]x_{1}[/tex] - 3[tex]x_{2}[/tex] = 0

2*7[tex]x_{2}[/tex] - 3[tex]x_{2}[/tex] = 0

[tex]14x_{2}[/tex] - 3[tex]x_{2}[/tex] = 0

11[tex]x_{2}[/tex] = 0

[tex]x_{2}[/tex] = 0

[tex]\left[\begin{array}{ccc}2&-3\\1&-4\\5&1\end{array}\right][/tex]    [tex]\left[\begin{array}{ccc}x_{1} &\\x_{2} &\\\end{array}\right][/tex]= = [tex]\left[\begin{array}{ccc}-16&\\18&\\10&\end{array}\right][/tex]

2[tex]x_{1}[/tex] - 3[tex]x_{2}[/tex] = -16

[tex]x_{1}[/tex] - 4[tex]x_{2}[/tex] = 18

5[tex]x_{1}[/tex] + 1[tex]x_{2}[/tex] = 10

We can solve the matrix equations,

2[tex]x_{1}[/tex] - 3[tex]x_{2}[/tex] = -16

[tex]x_{1}[/tex] - 4[tex]x_{2}[/tex] = 18

--------------------------

[tex]x_{1}[/tex] - 7[tex]x_{2}[/tex] = 2

[tex]x_{1}[/tex] = 2 + 7[tex]x_{2}[/tex]

[tex]x_{1}[/tex] = 2 + 7(0)

[tex]x_{1}[/tex] = 2

2[tex]x_{1}[/tex] - 3[tex]x_{2}[/tex] = -16

2*2 - 3[tex]x_{2}[/tex] = -16

4 - 3[tex]x_{2}[/tex] = -16

- 3[tex]x_{2}[/tex] = -16 - 4

- 3[tex]x_{2}[/tex] = -20

3[tex]x_{2}[/tex] = 20

[tex]x_{2}[/tex] = 20/3

[tex]x_{2}[/tex] = 6.66

Therefore,

u in the plane in set of real numbers rℝcubed3 spanned by the columns, then the one solution matrix is,   [tex]\left[\begin{array}{ccc}x_{1} &\\x_{2} &\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}2&\\6.66&\\\end{array}\right][/tex]

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Answer:

The estimate of ^50 to the nearest tenth is 7.1. The two perfect squares closest to 50, one greater than 50 and less than 50, are 49 and 64. The square roots of 49 and 64 are 7 and 8, respectively.

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

[tex]y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{3}}x+1\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

so we're really looking for the equation of a line whose slope is 1/3 and that it passes through (-6 , 8)

[tex](\stackrel{x_1}{-6}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{ \cfrac{1}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -8= \cfrac{1}{3} (x +6) \\\\\\ y-8=\cfrac{1}{3}x+2\implies {\Large \begin{array}{llll} y=\cfrac{1}{3}x+10 \end{array}}[/tex]

Answer:

b- exponential

Step-by-step explanation:

right

The distance from City Hall to 2nd Street along Cedar Road is 5.4 miles

The scale factor is the size by which the shape is enlarged or reduced. It is used to increase the size of shapes like circles, triangles, squares, rectangles, etc.

From City Hall to 1st St. form a triangle. Also, City Hall to 2nd St. form a triangle.

We can use the ratio of the distances along Aspen road (scale factor) of the triangles to find the required distance. That is:

scale factor =  (2.8 + 3.5)/2.8 = 6.3/2.8 = 2.25

Let the distance from City Hall to 1st St. be x. Thus:

scale factor = (x + 3.0)/x

2.25 = (x + 3.0)/x

2.25x = x + 3.0

2.25x -x = 3.0

1.25x = 3.0

x = 3.0/1.25

x = 2.4 miles

distance from City Hall to 2nd Street along Cedar Road = x + 3.0

distance from City Hall to 2nd Street along Cedar Road = 2.4 + 3.0 = 5.4 miles

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To find the area of the region enclosed by the graphs of f(x) = x - 2x^2 and g(x) = -5x, we need to find the points where the two graphs intersect and then use those points to find the area of the region between the two graphs.

An explanation graph is what?

A graph is a representation of the relationship between two variables that are normally measured along one of a pair of axes at right angles.

We can find the points of intersection by setting the two functions equal to each other and solving for x:

x - 2x^2 = -5x

2x^2 + 5x - x = 0

2x(x+5) -1(x+5) = 0

(2x-1)(x+5) = 0

x = 1/2 or x = -5

The solution x = -5 is extraneous as it does not give a valid value for the x-coordinate of the point of intersection.

So, x = 1/2 is the valid solution.

So the two graphs intersect at (1/2, 1/4)

Now, we can find the area of the region enclosed by the two graphs by finding the definite integral of the function f(x) - g(x) with respect to x, where the definite integral is taken between the points of intersection x= -5 and x=1/2

So, the definite integral of (x-2x^2)-(-5x) with respect to x, between x = -5 and x =1/2 is:

∫[(x-2x^2)-(-5x)]dx = ∫(x-2x^2+5x)dx = ∫(3x-2x^2)dx between -5 and 1/2

= [x^2-2/3x^3] between -5 and 1/2

= (1/2)^2 - 2/3(1/2)^3 - (-5)^2 + 2/3(-5)^3

= 1/4 - 2/24 - 25 + 2/3*125/27

= 1/4 - 1/12 + 5/3

= (12-3+40)/12 = 49/12

So the area of the region enclosed by the graphs is 49/12 square units.

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Answer:

(-2.25, -0.5)

or (-2 1/4, -1/2)

or (-9/4, -1/2)

Step-by-step explanation:

The difference in x coordinate between point a and point b is 9 and y coordinate is 2.

Point a is lower and point b is higher, which means we need to multiply the difference between the coordinate x and y by 1/4 plus the coordinate of point a because pointt p is on the 1/4 segment a to b.

9 * 1/4 = 9/4 = 2.25

2 * 1/4 = 2/4 = 0.5

point a has the coordinate of ( -5, -1 )

-5 + 2.25 = -2.25

-1 + 0.5 = -0.5

the new coordinate should be (-2.25, -0.5)

or (-2 1/4, -1/2)

or (-9/4, -1/2)

Answer:

Option C. - (negative eleven-fourths, negative one-half)

Step-by-step explanation: edg 2023

The Ksp of the lead II iodide is 6.4 * 10^-9.

We know that the solubility product has to do with the amount of the solute that we can be able to find that has dissolve in the saturated solution form the data that we have from the question that is given.

Now we know that;

Number of moles of the solute = mass/ molar mass

= 0.54 g/461 g/mol

= 1.17 * 10^-3 moles

Molarity = 1.17 * 10^-3 moles/ 1 L

= 1.17 * 10^-3 M

Then Ksp = [x] [2x]^2

Ksp = 4x^3

Ksp = 4( 1.17 * 10^-3 )^3

Ksp = 6.4 * 10^-9

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A highlight table is used to visualize the relative proportion of values in a table.

It is a way to present data in a graphical format that makes it easier to understand and compare the relative size of different categories.

It can be used to create a heatmap-like visualization that uses different colors or shades to indicate the relative frequency of values in a table. Highlight tables are useful for quickly identifying patterns and trends in large datasets, and for comparing the relative size of different categories of data.

They can also be used to compare data over time, or to compare data from different sources. Highlight tables can be created using various data visualization tools, such as spreadsheet software, data visualization libraries, or specialized data visualization software.

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The equation the line is, x+2y=2

A straight line is an endless one-dimensional figure that has no width. It is a combination of endless points joined both sides of a point and has no curve.

Here, we have to points (-6,4) and, (2,0)

So, by using the formula of equation of straight line of two-point form, we get,

(y-y_1)/(x-x_1 )=(y_2-y_1)/(x_2-x_1 )

=>(y-4)/(x+6)=(0-4)/(2+6)

=>-2y+8=x+6

=>x+2y=2

Hence, the required equation is,  x+2y=2

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Answer:2

Step-by-step explanation:

Answer: the answer is 4 i think

Step-by-step explanation:

Answer:

[tex] {20}^{2} - {16}^{2} = 144 \\ \sqrt{144} = 12[/tex]

If you have problems in mathematics you can take my number and send me your questions if you want

The value of y when x = 4, z = 6 is 24.

The equation for the relationship between y, x and z is y = xz.

Given that x = 2 and z = 3, we have y = 2 * 3 = 6.

Therefore, when x = 4 and z = 6, y = 4 * 6 = 24.

The relationship between y, x and z can be expressed as y = xz, which means that the value of y is proportional to the values of x and z. When the values of x and z are given, we can calculate the value of y based on this equation. For example, when x = 2 and z = 3, the value of y is 2 * 3 = 6. Similarly, when x = 4 and z = 6, the value of y is 4 * 6 = 24. In general, when the values of x and z are given, the value of y can be determined by multiplying the values of x and z. Therefore, when x = 4 and z = 6, the value of y is 24.

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The snapshot graph of the wave at t=0s is a graph of the displacement of the wave along the x-axis at time t=0s.

It is a graph of the wave's initial position, which is usually a sinusoidal graph with a maximum value at the center and decreasing values as x increases. This is because the wave is traveling from left to right and its amplitude decreases as it moves further from its source. To explain in more detail, a sinusoidal wave is a wave that oscillates up and down in a regular pattern.

The snapshot graph at t=0s will show the wave at its highest point, which is the amplitude of the wave. As the wave moves along the x-axis, its amplitude will decrease as it moves further from its source. The graph will also show the wave's wavelength, which is the distance between two successive crests or troughs.

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The sum or the compound interest were Rs. 10,089 & Rs. 2589, respectively, according to the supplied statement.

Per year, as used in contracts, is used to describe ongoing duties, or those that take place continuously during the course of an agreement. For instance, if a customer pays 3% interest on a loan annually, it indicates that you will have to pay 3% more of the loan's principle each year until the deal is through.

Given : Initial principle amount (P) = Rs. 7500

      Rate of interest (R) = 16% per annum

To find : Compound interest (C.I.) = ?

Solution :

It is given that Initial principle amount (P) = Rs. 7500

Rate of interest (R) = 16% per annum

      Time (t) = 1 year = 2 ( ∵ Half Yearly)

We know the formula for Compound Interest,

       Compound Interest (A) = [tex]P\left(1+\frac{R}{100}\right)^{n t}[/tex]

[tex]\begin{aligned}& =7500\left(1+\frac{16}{100}\right)^2 \\& =7500\left(\frac{100+16}{100}\right)^2 \\& =7500\left(\frac{116}{100}\right)^2\end{aligned}[/tex]

= 7500 * 1.345

= Rs. 10,089

Now, Compound interest = A - P

= 10,089 - 7500

= Rs. 2589

∴ Final amount = Rs. 10,089

Compound Interest = Rs. 2589

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The complete question is-

Calculate the amount and the compound interest on Rs. 7500 for 1 year at 16% p.a compounded half yearly​

well, since one is a horizontal line and the other is a vertical line, Check the picture below.

Answer: The correct options are:

1. Significantly different from

1. Inconsistent

Sales Data for Midwest:

Midwest region total stores Sales equal to 63.1%. The percentage for a current store is less than the total stores therefore data in the given table is not consistent. The data given is relatively for the first month's sales and is significantly different from the other stores.

Step-by-step explanation:

1. To get system B form A: C. Swap only the right-hand sides of both equations.

2. They are not equivalent systems.

The point of intersection of two equations of a system gives us the solution, which is the coordinate of that point.

If two systems are equivalent, then they will have the same solution or point of intersection.

1. To get system B from A, the values at the right hand side of both equations were swapped.

2. The graph of system A, -10x - 4y = 0 and -2y + 7y = 8 is given in figure 1. The solution is (-0.64, 1.6).

The graph of system B, -10x - 4y = 8 and -2y + 7y = 0 is given in figure 2. The solution is (-0.8, 0).

Therefore, the systems are not equivalent.

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Answer:

£42.30

Step-by-step explanation:

6% of £45 = 2.7

£45-£2.70=£42.30

When you say don't use the dollar sign do you mean I should convert from dollars to pounds?

The value of d is -9.We can find by both sides solving for d.

Subtraction means you are taking something away from a group or number of things. When you subtract what is left in the group becomes less. An example of a subtraction problem is the following: 5 - 3 = 2.

First we add and subtract same terms to get the variables on one side and the constants on the other.Then multiply or divide to isolate the variable.In the last solve for given variables.You must perform the same exact operation to each side of the equation.

Now we have

d+8=-d-10

d+d = -10-8

2d= -18

d= -9

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