Using ratios, the sentences regarding a percentage of 8% are given as follows:
a. 8 for every 100.
b. 4 for every 50.
c. 1 for every 12.5.
d. 0.5 for every 6.25.
Ratio between two amountsThe ratio between two amounts a and b is given by the division of a by b, as follows:
r = a/b.
One example of ratio is a percentage, as a percentage of x% is equivalent to the ratio of x to 100, that is:
r = x/100.
Hence a percentage of 8% is equivalent to the following ratio:
r = 8/100.
That is, 8 for every 8.
Ratios are fractions, and they can be simplified, dividing both the numerator and the denominator by the same amount, as is the case in this problem:
r = 4/50 (simplifying by 2, four for every 50).r = 1/12.5 (simplifying by 4, one for every 12.5).r = 0.5/6.25 (simplifying by 2, 0.5 for every 6.25).More can be learned about ratios at https://brainly.com/question/2328454
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Put the following equation of a line into slope-intercept form, simplifying allfractions.2x + 8y = 24
Determine whether the lines are parallel, intersect, or coincideY = 4x - 53x + 4y = 7
Answer:
Explanation:
Given:
y=4x-5
3x+4y=7
We can check if the lines are parallel, intersect, or coincide by graphing. To graph, we plug in any values for x to determine the y values.
The graph of the lines is shown below:
So based on the graph, the lines intersect at a point.
Therefore, the lines intersect.
Nancy plans to take her cousins to an amusement park. She has a total of $100 to pay for 2 different charges. • $5 admission per person • $3 per ticket for rides Which inequality could Nancy use to determine y, the number of tickets for rides she can buy if she pays the admission for herself and x cousins? A. 5y + 3(x + 1) >= 100 B. 5(x + 1) + 3y > 100 C. 5(x + 1) + 3y =< 100 D. 5y + 3(x + 1) < 100
ANSWER
[tex]C.5(x\text{ + 1) + 3y }\leq100[/tex]EXPLANATION
Nancy has $100.
The charges are:
=> $5 admission per person. She has x cousins and herself to pay for, this means that she pays $5 for (x + 1) persons.
The admission charge is therefore:
$5 * (x + 1) = $5(x + 1)
=> $3 per ticket for rides. The number of rides she can pay for is y. So the charge for rides is:
$3 * y = $3y
Since she only has $100, everything she pays for can only be less than $100 or equal to $100.
This means that, if we add all the charges, they must be either less than or equal to $100.
That is:
[tex]5(x\text{ + 1) + 3y }\leq100[/tex]That is Option C.
Find the value or measure. assume all lines that appear to be tangent are tangent.JK=
In this problem we have that
mso
the formula to calculate the interior angle is equal to
msubstitute the given values
m
therefore
the answer is mUse the Distibutive Property: Expand -3(x + 3)
The distributive property of multiplication states the following:
[tex]a(b+c)=a\cdot b+a\cdot c[/tex]So, for the given expression, we have:
[tex]-3(x+3)=(-3)\cdot x+(-3)\cdot3=-3x-9[/tex]Use the given conditions to write an equation for the line.Passing through (−7,6) and parallel to the line whose equation is 2x-5y-8=0
For a line to be parallel to another line, the slope will be the same
1st equation:
[tex]\begin{gathered} 2x\text{ - 5y - 8 = 0} \\ \text{making y the subject of formula:} \\ 2x\text{ - 8 = 5y} \\ y\text{ = }\frac{2x\text{ - 8}}{5} \\ y\text{ = }\frac{2x}{5}\text{ - }\frac{8}{5} \end{gathered}[/tex][tex]\begin{gathered} \text{equation of line:} \\ y\text{ = mx + b} \\ m\text{ = slope, b = y-intercept} \end{gathered}[/tex][tex]\begin{gathered} \text{comparing the given equation and equation of line:} \\ y\text{ = y} \\ m\text{ = 2/5} \\ b\text{ = -8/5} \end{gathered}[/tex]Since the slope of the first line = 2/5, the slope of the second line will also be 2/5
We would insert the slope and the given point into equation of line to get y-intercept of the second line:
[tex]\begin{gathered} \text{given point: (-7, 6) = (x, y)} \\ y\text{ = mx + b} \\ 6\text{ = }\frac{2}{5}(-7)\text{ + b} \\ 6\text{ = }\frac{-14}{5}\text{ + b} \\ 6\text{ + }\frac{14}{5}\text{ = b} \\ \frac{6(5)\text{ + 14}}{5}\text{ = b} \\ b\text{ = }\frac{44}{5} \end{gathered}[/tex]The equation for the line that passes through (-7, 6) and parallel to line 2x - 5y - 8 = 0:
[tex]\begin{gathered} y\text{ = mx + b} \\ y\text{ = }\frac{2}{5}x\text{ + }\frac{44}{5} \end{gathered}[/tex]Identify the postulate illustrated by the statement: Line ST connects pointS and point T
We have two points known to be ( S ) and ( T ). A line connects two points.
The minimum number of points that are required to form a straight line in a cartesian coordinate system are ( two ).
The minimum number of points that are required to form a plane in a cartesian coordinate system are ( three ) which will form two vectors i.e it requires two lines formed with a common point.
Two planes always intersect at exactly one point with direction normal to the two plane normal vectors.
Hence, the only possible postulate that relates two points is the formation of a line between two points; hence, the correct postulate for the given statement is:
[tex]\text{\textcolor{#FF7968}{Through any two points there is exactly one line}}[/tex]
What is the image of (-5,1) after a dilation by a scale factor of 5 centered at the origin?
Explanation
Step 1
when you have a coordinate (x,y) and you want to get the image after a dilationi, make
[tex]\text{new image=(coordinate)}\cdot factor[/tex]then
let
coordinate=(-5,1)
dilation scale=5
now, replace
[tex]\begin{gathered} \text{new image=(coordinate)}\cdot factor \\ \text{new image=(-5,1)}\cdot5 \\ \text{new image=(}-25,5) \end{gathered}[/tex]I hope this helps you
Find the measure of each angle in the triangle. F R 6x 15x 15x O 02
Answer:
R = 75
O = 75
F = 30
Step-by-step explanation:
15x + 15x + 6x = 180
add like terms
36x = 180
divide
x = 5
The measure of angle P is 30°, angle R is 75° and angle O is 75° in triangle POR.
What is angle sum property of a triangle?Angle sum property of triangle states that the sum of interior angles of a triangle is 180°.
From the given triangle POR, ∠R=15x, ∠O=15x and ∠P=6x.
By using angle sum property, we get
∠P+∠O+∠R=180°
6x+15x+15x=180
36x=180
x=180/36
x=5
So, ∠R=15x=75°, ∠O=15x=75° and ∠P=6x=30°
Therefore, the measure of angle P is 30°, angle R is 75° and angle O is 75° in triangle POR.
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Suppose you know students at school are, on average, 68 inches tall with a standard deviation of 4 inches. If you sample 36 students, what is the probability their average height is more than 70 inches?
Answer:
0.135% or 0.00135
Explanation:
• The population mean height = 68 inches
,• The population standard deviation = 4 inches
,• Sample Size, n = 36
First, find the sample standard deviation:
[tex]\sigma_x=\frac{\sigma}{\sqrt{n}}=\frac{4}{\sqrt{36}}=\frac{4}{6}=\frac{2}{3}[/tex]Next, for X=70, find the z-score:
[tex]\begin{gathered} z-score=\frac{X-\mu}{\sigma_x} \\ z=\frac{70-68}{2\/3}=\frac{2}{2\/3}=3 \end{gathered}[/tex]Since we are looking for the probability that their average height is more than 70 inches, we need to find:
• P(X>70)=P(z>3)
Using the z-score table:
[tex]P(z>3)=0.0013499[/tex]The probability that their average height is more than 70 inches is 0.135%.
Find the vertex of the following equation: y = -5x² - 270x - 520
In order to find the vertex of this quadratic equation, first let's find the coefficients a, b and c from the standard form of the quadratic equation:
[tex]y=ax^2+bx+c[/tex]Comparing with the given equation, we have a = -5, b = -270 and c = -520.
Now, let's calculate the x-coordinate of the vertex using the formula below:
[tex]\begin{gathered} x_v=\frac{-b}{2a} \\ x_v=\frac{-(-270)}{2\cdot(-5)} \\ x_v=\frac{270}{-10} \\ x_v=-27 \end{gathered}[/tex]Using this value of x in the equation, we can find the y-coordinate of the vertex:
[tex]\begin{gathered} y_v=-5x^2_v-270x_v-520 \\ y_v=-5\cdot(-27)^2-270\cdot(-27)-520 \\ y_v=-5\cdot729+7290-520 \\ y_v=-3645+7290-520 \\ y_v=3125 \end{gathered}[/tex]Therefore the vertex is located at (-27, 3125).
Cost of a pen is two and half times the cost of a pencil. Express this situation as a
linear equation in two variables.
The equation to illustrate the cost of a pen is two and half times the cost of a pencil is C = 2.5p.
What is an equation?A mathematical equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario.
In this case, the cost of a pen is two and half times the cost of a pencil.
Let the pencil be represented as p.
Let the cost be represented as c.
The cost will be:
C = 2.5 × p
C = 2.5p
This illustrates the equation.
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Solve the system of two linear inequalities graphically,4x + 6y < 24(x22Step 1 of 3 : Graph the solution set of the first linear inequality.AnswerKeypadKeyboard ShortcutsThe line will be drawn once all required data is provided and will update whenever a value is updated. The regions will be added once the line is drawn.Enable Zoom/PanChoose the type of boundary line:Solid (-) Dashed (--)Enter two points on the boundary line:10-5Select the region you wish to be shaded:
Answer:
To solve the system of two linear inequalities graphically,
[tex]\begin{gathered} 4x+6y<24 \\ x\ge2 \end{gathered}[/tex]For step 1,
Draw a line 4x+6y=24
Since the given equation has less than sign, the required region will not include the line, Hence we draw the dashed line for the line 4x+6y=24.
Since we required redion is 4x+6y<24, the points bellows the line satisfies the condition hence the required region is below the line,
Similarly for the inequality,
[tex]x\ge2[/tex]It covers the region right side of the line x=2,
we get the siolution region as the intersecting region of both inequality which defined in the graph as,
Dark blue shaded region is the required solution set for the given inequalities.
STRUCTURE Quadrilateral DEFG has vertices D(-1, 2), E(-2, 0), F(-1,-1) and G(1, 3). A translation maps quadrilateral DEFG to
quadrilateral D'EFG. The image of D is D'(-2,-2). What are the coordinates of E, F, and G'?
E (
FD
G' (
The coordinates are;
E' = (-3, -4)F' = (-2, -5)G' = (0, -1)Given,
Quadrilateral DEFG with vertices;
D = (-1, 2)E = (-2, 0)F = (-1,-1) G = (1, 3)We have to find the coordinates of E', F', G'.
A figure is translated when it is moved to the left, right, up, or down.
The original figure's points are all translated (moved) by the same amount and in the same direction.
Here,
Compare the coordinates of D with the coordinates of D' to determine the mapping rule that converts DEFG to D'E'F'G'.
D = (-1, 2)
D' = (-2, -2)
The x-coordinate has be translated 1 unit to the left.
The y-coordinate has been translated 4 units down.
Then,
The mapping rule is:
(x, y) → (x-1, y-4)
To find the coordinates of E', F' and G', apply the mapping rule to the given vertices of the pre-image:
⇒ E' = (-2-1, 0-4) = (-3, -4)
⇒ F' = (-1-1, -1-4) = (-2, -5)
⇒ G' = (1-1, 3-4) = (0, -1)
That is,
The coordinates are;
E' = (-3, -4)F' = (-2, -5)G' = (0, -1)Learn more about translation maps here;
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Bob buys a vase for $15 and spends $2 per flower.
4) Write an equation to represent the cost of buying flowers.
If Bob buys a vase for $15 and spends $2 per flower, then the equation to represent the cost of buying flowers is 15+2x
The cost of flower vase = $15
The cost of each flower = $2
Consider the number of flowers as x
Then the linear equation that represents the cost of buying flowers = The cost of flower vase + The cost of each flower × x
Substitute the values in the equation
The equation that represents the cost of buying flowers = 15+2x
Hence, If Bob buys a vase for $15 and spends $2 per flower, then the equation to represent the cost of buying flowers is 15+2x
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Find the area of a triangle with vertices at N(-4,2), A(3,2)and P(-1,-4).
The distance between points N and A is 7, and we can take that as the base of the tringle (up side down)
The distance between the base (NA) and the point P is 6, and we can take that as the height of the triangle
Area of a triangle = (Base x Height)/2
Area = (7 x 6)/2 = 42/2 = 21
Answer:
Area = 21
One angle measures 140°, and another angle measures (5k + 85)°. If the angles are vertical angles, determine the value of k.
The value of k when one angle measures 140°, and another angle measures (5k + 85)° and if the angles are vertical angles is 11.
What is vertical angles?
Vertical angles are angles opposite each other where two lines cross.
Note: Vertical angles are equal.
To calculate the value of k, we use the principle of vertical angle
From the question,
140 = (5k+85)°Solve for k
5k = (140-85)5k = 55Divide both side by the coefficient of k (5)
5k/5 = 55/5k = 11Hence, the value of k is 11.
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A. Marvin worked 4 hours a day plus an additional 5-hour day for a total of 29 hours.B. Marvin worked 9 hours a day for a total of 29 hoursC. Marvin worked 4 hours one day plus an additional 5 hours for a total of 29 hours.D. Marvin worked 4 days plus 5 hours for a total of 29 hours.
Use a truth table to determine whether the two statements are equivalent.
The answer is option(b) i.e,the given statements are not equivalent.
What is Truth table?
A truth table is a breakdown of a logic function by listing all possible values the function can attain. Such a table typically contains several rows and columns, with the top row representing the logical variables and combinations, in increasing complexity leading up to the final function.
Let's proof it by using truth table :
p q (~q → ~p) (~p → ~q)
F F T T
F T T F
T F F T
T T T T
As you've seen in truth table (~q → ~p) ≠ (~p → ~q)
Therefore, the answer is option(b) i.e,the given statements are not equivalent.
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Line AB is tangent to circle C at B and line AD is tangent to circle C at D. What is the lenghth AB.
Answer:
Explanation:
The Two Tangent Theorem states that if we draw two lines from the same point which lies outside a circle, such that both lines are tangent to the circle, then their lengths are the same.
To be able to find AB we have to 1st of all find the value of x by equating both lengths together since both AB and AD are equal as shown below;
[tex]\begin{gathered} 2x^2+3x-1=2x^2-4x+13 \\ 2x^2-2x^2+3x+4x=13+1 \\ 7x=14 \\ x=\frac{14}{7}=2 \end{gathered}[/tex]S
What is the value of p in the proportion below? 20/6 = p/12O 2 O 10O 40O 72
20/6 = p/12
cross-multiply
p x 6 = 20 x 12
6p = 240
divide both-side of the equation by 6
p = 240/6
p = 40
Let S be the universal set, where: S = { 1 , 2 , 3 , ... , 18 , 19 , 20 } Let sets A and B be subsets of S , where: Set A = { 2 , 5 , 9 , 11 , 12 , 14 , 15 , 17 , 18 } Set B = { 4 , 7 , 8 , 9 , 10 , 12 , 15 , 17 , 18 , 19 , 20 } Find the following: LIST the elements in the set ( A ∪ B ): ( A ∪ B ) = { } Enter the elements as a list, separated by commas. If the result is the empty set, enter DNE LIST the elements in the set ( A ∩ B ): ( A ∩ B ) = { } Enter the elements as a list, separated by commas. If the result is the empty set, enter DNE
The elements that are in ( A ∪ B ) = { 2, 4, 5, 7, 8, 9, 10 , 11, 12, 14, 15, 17, 18, 19, 20}
The elements of the set that are in ( A ∩ B ) = {9, 12, 15, 17, 18 }
What is a the union of a set?This is the term that is used to refer to all of the elements that are contained in a two or more sets which are a subset of the Universal set.
In this case, the union of the set is given as the elements in both A and B written together as { 2, 4, 5, 7, 8, 9, 10 , 11, 12, 14, 15, 17, 18, 19, 20}. All of these values are in A and B.
What is the intersection of a set?This is the term that is used to refer to all of the values that would appear in the two sets that are in the subset of the universal set.
Here we have the value of A ∩ B = {9, 12, 15, 17, 18 }
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Please help me and I will give the pictures for the choices..
The first compound indequality is:
[tex]x>7\, and\, x<7[/tex]We can view this in the real line:
There is no number that can be both greater AND less than 7, which makes the correct answer "No solution".
The second is:
[tex]x<7\, or\, x>7[/tex]Now, we are not looking for intercetion, we are looking for the union of both. The firts inequality takes all number less than 7 and the second all that are greater than 7, so the only one that is not a solution is 7, which means the correct answer is "all real numbers except 7"
The third is:
[tex]x\ge7\, and\, x\le7[/tex]This is the same as the first one, but now the 7 is included in both:
So, there is only 7 that can be in both indequalitys, thus the correct answer is "one solution, 7".
The fourth is
[tex]x\le7\, or\, x\ge7[/tex]This is similar to the second, but now 7 is included, which means it is also a solution, thus the answer is "all real numbers".
Can you please solve the last question… number 3! Thanks!
Let us break the shape into two triangles and solve for the unknowns.
The first triangle is shown below:
We will use the Pythagorean Theorem defined to be:
[tex]\begin{gathered} c^2=a^2+b^2 \\ where\text{ c is the hypotenuse and a and b are the other two sides} \end{gathered}[/tex]Therefore, we can relate the sides of the triangles as shown below:
[tex]25^2=y^2+16^2[/tex]Solving, we have:
[tex]\begin{gathered} y^2=25^2-16^2 \\ y^2=625-256 \\ y^2=369 \\ y=\sqrt{369} \\ y=19.2 \end{gathered}[/tex]Hence, we can have the second triangle to be:
Applying the Pythagorean Theorem, we have:
[tex]22^2=x^2+19.2^2[/tex]Solving, we have:
[tex]\begin{gathered} 484=x^2+369 \\ x^2=484-369 \\ x^2=115 \\ x=\sqrt{115} \\ x=10.7 \end{gathered}[/tex]The values of the unknowns are:
[tex]\begin{gathered} x=10.7 \\ y=19.2 \end{gathered}[/tex]Suppose that the edge lengths x, y, z of a closed rectangular box are changing at the following rates: dx/dt= 1m/s, dy/dt= -2 m/s, and dz/dt= 0.5 m/s.
At the instant x= 2m, y= 3m, z= 5m, find the rates of change:
a) volume of the box
b) surface area of the box
c) diagonal of the box
a) The rate of change of the volume of the box is 8m³/s.
b) The rate of change of the surface area of the box is -19m²/s.
c) The rate of change of the diagonal of the box is 1m/s.
Let the rate of change of the edge length x, y, and z of a closed rectangular box are:
dx/dt= 1m/s
dy/dt= -2 m/s
dz/dt= 0.5 m/s
a) The volume of the box
From the formula of the volume,
V=xyz
Then,
differentiate w.r.t t
[tex]\frac{dV}{dt} = xy\frac{dz}{dt} + yz\frac{dx}{dt} +xz\frac{dy}{dt}[/tex]
[tex]\frac{dV}{dt} = xy(0.5)+ yz(1)+xz(-2)[/tex]
put the value of x, y, z , then we get
[tex]\frac{dV}{dt} = 2.3.(0.5)+ 3.5.(1)+2.5.(-2)[/tex]
[tex]\frac{dV}{dt} = 3+ 15 - 10[/tex]
[tex]\frac{dV}{dt} = 8m^3/s[/tex]
The rate of change of the volume of the box is 8m³/s.
b) surface area of the box
surface area of the rectangular box is
s = 2xy + 2yz + 2zx
differentiate w.r.t t
[tex]\frac{ds}{dt} = 2(y + z)\frac{dx}{dt} + 2(z + x)\frac{dy}{dt} +2(x + y)\frac{dz}{dt}[/tex]
[tex]\frac{ds}{dt} = 2(y + z)(1) + 2(z + x)(-2)+2(x + y)(0.5)[/tex]
[tex]\frac{ds}{dt} = 2(3 + 5)(1) + 2(5 + 2)(-2)+2(2 + 3)(0.5)[/tex]
[tex]\frac{ds}{dt} = 16 -40 + 5[/tex]
[tex]\frac{ds}{dt} = -19m^2/s[/tex]
The rate of change of the surface area of the box is -19m²/s.
c) diagonal of the box
lengths of the boxes for the diagonal is
s = 2x² + y² + z²
differentiate equation w.r.t t
[tex]\frac{ds}{dt} = 4x\frac{dx}{dt} + 2y\frac{dy}{dt} +2z\frac{dz}{dt}[/tex]
[tex]\frac{ds}{dt} = 4.2.1+ 2.3.(-2) +2.5.(0.5)[/tex]
[tex]\frac{ds}{dt} = 8 -12 + 5[/tex]
[tex]\frac{ds}{dt} =1m/s[/tex]
The rate of change of the diagonal of the box is 1m/s.
a) The rate of change of the volume of the box is 8m³/s.
b) The rate of change of the surface area of the box is -19m²/s.
c) The rate of change of the diagonal of the box is 1m/s.
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Daniel's family raises honey bees and sells the honey at the farmers' market. To get ready for market day, Daniel fills 24 equal sized jars with honey. He brings a total of 16 cups of honey to sell at the farmers' market.
Use an equation to find the amount of honey each jar holds.
To write a fraction, use a slash ( / ) to separate the numerator and denominator.
The fraction for the amount of honey each jar holds is 2/3.
What is an equation?A mathematical equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario.
From the information, Daniel fills 24 equal sized jars with honey and he brings a total of 16 cups of honey to sell at the farmers' market.
The amount of honey will be:
= Number of cups / Number of jars
= 16 / 24
= 2/3
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i need immediate help.The exercise consists of finding the axis of symmetry for the equation below.
Our equation
[tex]y=\frac{1}{3}(x+2)^2-1,[/tex]is a quadratic equation. In simple words, it's a parabola, whose graph (red curve) is the following:
The axis of symmetry of a parabola is just the line dividing the parabola into its two arms. In the graph, the axis of symmetry is the blue vertical line. It's usually represented algebraically by
[tex]x=\text{ The first component of the vertex}[/tex]AnswerThe axis of symmetry of our quadratic equation is
[tex]x=-2[/tex]Find the quotient of these complex numbers.(4 + 4i) (5 + 4i) =A.B.C.D.
Find the quotient given below:
[tex]\frac{4+4i}{5+4i}[/tex]When managing complex numbers, we must recall:
[tex]\begin{gathered} i^2=-1 \\ \text{ Or, equivalently:} \\ i=\sqrt{-1} \end{gathered}[/tex]Multiply and divide the expression by the conjugate of the denominator:
[tex]\frac{4+4i}{5+4i}\cdot\frac{5-4i}{5-4i}[/tex]Multiply the expressions in the numerator and in the denominator. We can apply the special product formula in the denominator:
[tex](a+b)(a-b)=a^2-b^2[/tex]Operating:
[tex]\frac{(4+4i)(5-4i)}{5^2-(4i)^2}[/tex]Operate and simplify:
[tex]\frac{20-16i+20i-16i^2}{25-16i^2}[/tex]Applying the property mentioned above:
[tex]\frac{20-16i+20i+16}{25+16}[/tex]Simplifying:
[tex]\frac{36+4i}{41}[/tex]find a slope of the line that passes through (8,8) and (1,9)
The slope formula is
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]we can use this formula by introducing the values of the given points. In our case
[tex]\begin{gathered} (x_1,y_1)=(8,8) \\ (x_2,y_2)=(1,9) \end{gathered}[/tex]Hence, we have
[tex]m=\frac{9-8}{1-8}[/tex]It yields,
[tex]m=\frac{1}{-7}[/tex]hence, the answer is
[tex]m=-\frac{1}{7}[/tex]3: Select the correct equation for the given situation. Then, select the solution for that equation. Two research submarines start to rise vertically toward the ocean surface. The Tri-I sub is at 4,863 feet below sea level (or -4,863 feet) and is ascending 81.1 feet per minute. The Quad-II sub is at 3,645 feet below sea level (or -3,645 feet) and is ascending 76.9 feet per minute. If the ocean surface is at 0 feet, how many minutes (m) must elapse for the two submarines to reach the same depth? m = 290 minutes m = 145 minutes m = 53.8 minutes 4,863 - 76.9m = 3,645 - 81.1m O -4,863 + 81.1m = - 3,645 + 76.9m 0 - 4, 863 + 76.9m = -3, 645 + 81.1m – 4, 863 – 81.2m 2 – 3, 645 + 76.9m Om < 53.8 minutes
Unknown, the correct equation is:
- 4,863 + 81.1m = - 3,645 + 76.9m
And to solve for m, you use the standard form:
Like terms:
81.1m - 76.9m = -3,645 + 4,863
4.2m = 1,218
Answer:Nuts
Step-by-step explanation:
green on green
