we have the vector
u=-8i+5j
see the attached figure to better understand the problem
tan(x)=5/8
x=tan^-1(5/8)
x=32 degrees
Find out the angle theta
148 degrees
the answer is 148 degrees
6. If f(x) = x2 - 1, which of the following is equal to g(x) = f(x - 3)?
A.g(x) = x/ +8
B.g(x) = x2 + 6x+8
C.g(x)= x2 - 6x + 8
D.g(x) = x2 + 6x- 10
( x - 2) ( x - 4 ) is function which is equal to g(x) .
In the simplest terms, what is a function?
As a set of inputs with one output for each, a function is defined as a relationship between them. In plain English, a function is an association between inputs in which each input is connected to precisely one output. A domain, codomain, or range exists for every function.f(x) = x² - 1
f( x - 3 ) = ( x - 3 )² - 1
= x² + 9 - 6x -1
= x² -6x + 8
= x² -4x -2x + 8
= x( x - 4 ) -2( x - 4)
= ( x - 2) ( x - 4 )
g(x) = f(x - 3)
= ( x - 2) ( x - 4 )
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( f - 12) + Pf decreased by the sum of 12 and p is it correct?
The sum of 12 and P can be written as 12 + P
Then, f decreased by the sum of 12 and P can be written as:
f - (12 + P)
Answer: it isn't correct, the correct answer is f - (12 + P)
Please help!
2|x-1| >2
5
Answer: 6, -4
Step-by-step explanation:
[tex]\frac{2}{5}|x-1| \geq 2\\\\|x-1| \geq 5\\\\x-1 \leq -5, x-1 \geq 5\\\\x \leq -4, x \geq 6[/tex]
What is the smallest integer greater than 800 that is relatively prime to 10!
The smallest integer greater than 800 that is relatively prime to 10! is 801
How to determine the number greater than 800 that is relatively prime to 10!The term relatively prime refers to numbers who has a greatest common factor of 1. If two numbers have a greatest common factor of 1 the two numbers are said to be relatively prime
solving for 10!
10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1
= 362880
prime factorization of 10!
= 2^7 * 3^4 * 5 * 7
prime factorization of 801
= 3^2 * 89
The greatest common factor of both numbers is 1, this is not included to the factors in the prime factorization but 1 is a known common factor already.
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Julia just let a new candle and then let it burn all the way down to nothing. The candle
burned at a rate of 0.75 inches per hour and its initial length was 9 inches. Write an
equation for L, in terms of t, representing the length of the candle remaining
unburned, in inches, t hours after the candle was lit.
L=
Answer: L= 9-.75x
Step-by-step explanation: since it starts at 9 inches tall and is melting at .75 inches per hour, it's going to be the initial length, 9, minus the rate, .75, times the time/hours past, so x
9. What is the value of x?
Answer:
A, 61.
Step-by-step explanation:
(2x+24). If we sub in 61 for x, we get (2(61)+24). Follow order of operations.
2 times 61= 122. Add 24 and you get 146. We can know this is correct because we are given the other angle and it's degrees, whch is also 146 degrees. Therefore, the answer is A, 61.
if i get a 60% on a math test then what would my final grade be overall
its an 80% rn
Answer:
A D
Step-by-step explanation:
An A is 90% to 100% A B is 80% to 89% A C is 70% to 79% A D is 60% to 69%
A barge is being towed by two tugboats, using ropes with force vectors as shown.
SOLUTION
From the question, we are given
[tex]\begin{gathered} F_1=(11,000,5000) \\ F_2=(14,500,-8,000) \end{gathered}[/tex]Now, to find the angle between the ropes, we will take the dot product of two vectors. This is given as
[tex]\begin{gathered} a.b=|a||b|cos\theta \\ so,\text{ we have } \\ cos\theta=\frac{a.b}{|a||b|} \end{gathered}[/tex]But writing the forces in vector form, we have
[tex]\begin{gathered} F_1=11,000i+5000j \\ F_2=14,500i-8,000j \end{gathered}[/tex]Applying the formula above, we have
[tex]\begin{gathered} cos\theta=\frac{a.b}{|a||b|} \\ cos\theta=\frac{(11,000)(14,500)+(5000)(-8000)}{\sqrt{11,000^2+5000^2)\sqrt{14500^2+(-8000)^2}}} \\ cos\theta=\frac{159,500,000-40,000,000}{\sqrt{121,000,000+25,000,000}\sqrt{210,250,000+64,000,000}} \\ cos\theta=\frac{119,500,000}{\sqrt{146,000,000}\sqrt{274,250,000}} \\ cos\theta=\frac{119,500,000}{12,083.04579\times16560.4952} \\ cos\theta=\frac{119,500,000}{200,101,221.806675} \\ cos\theta=0.5971977 \end{gathered}[/tex]Now, theta becomes
[tex]\begin{gathered} \theta=cos^{-1}0.5971977 \\ \theta=53.3305 \end{gathered}[/tex]hence the answer is option B, 53 degrees
SOLUTION
From the question, we are given
[tex]\begin{gathered} F_1=(11,000,5000) \\ F_2=(14,500,-8,000) \end{gathered}[/tex]Now, to find the angle between the ropes, we will take the dot product of two vectors. This is given as
[tex]\begin{gathered} a.b=|a||b|cos\theta \\ so,\text{ we have } \\ cos\theta=\frac{a.b}{|a||b|} \end{gathered}[/tex]But writing the forces in vector form, we have
[tex]\begin{gathered} F_1=11,000i+5000j \\ F_2=14,500i-8,000j \end{gathered}[/tex]Applying the formula above, we have
[tex]\begin{gathered} cos\theta=\frac{a.b}{|a||b|} \\ cos\theta=\frac{(11,000)(14,500)+(5000)(-8000)}{\sqrt{11,000^2+5000^2)\sqrt{14500^2+(-8000)^2}}} \\ cos\theta=\frac{159,500,000-40,000,000}{\sqrt{121,000,000+25,000,000}\sqrt{210,250,000+64,000,000}} \\ cos\theta=\frac{119,500,000}{\sqrt{146,000,000}\sqrt{274,250,000}} \\ cos\theta=\frac{119,500,000}{12,083.04579\times16560.4952} \\ cos\theta=\frac{119,500,000}{200,101,221.806675} \\ cos\theta=0.5971977 \end{gathered}[/tex]Now, theta becomes
[tex]\begin{gathered} \theta=cos^{-1}0.5971977 \\ \theta=53.3305 \end{gathered}[/tex]hence the answer is option B, 53 degrees
I need help with this
Angle XBC is a corresponding angle to angle AXY.
The value of angle BXC is 30 degrees.
How to find measure of angles?When parallel lines are cut by a transversal line, angle relationships are formed such as alternate angles, corresponding angles, linear angles, vertically opposite angles etc.
Therefore, XY and BD are parallel lines and are cut by the transversal line AB and XC.
XBC forms an isosceles triangle.
∠AXY = 75 degrees.
∠XBC is a corresponding angle to ∠AXY.
Corresponding angles are congruent.
Therefore,
∠AXY = ∠XBC
Let's find the angle BXC.
The sum of angle in a triangle is 180 degrees.
The triangle BXC is an isosceles triangle. An isosceles triangle has base angles equal to each other.
Hence,
75 + 75 + ∠BXC = 180°
∠BXC = 180 - 150
∠BXC = 30°
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3 3 Luke started a weight-loss program. The first week, he lost x pounds. The second week, he lost 2 pounds less than 2 times the pounds 3 he lost the first week. The third week, he lost 1 pound more than ã of the pounds he lost the first week. 3 Liam started a weight-loss program when Luke did. The first week, he lost 1 pound less than 2 times the pounds Luke lost the first 5 week. The second week, he lost 4 pounds less than 2 times the pounds Luke lost the first week. The third week, he lost 2 pound more 5 than 3 times the pounds Luke lost the first week. Assuming they both lost the same number of pounds over the three weeks, complete the following sentences. 4 pounds 6 pounds 21 4 2 pounds 13 - 40Luke started a weight loss program the first week he lost X pounds the second week he lost 3/2 pounds less than 3/2 times the pounds he lost the first week the third week he lost 1 pound more than three-fourths of the Pouncey lost the first week
We know that Luke lost x pounds the first week.
We also know that the second week 3/2 less than 3/2 times the pounds he lost the first week, this means that the secons week he lost:
[tex]\frac{3}{2}x-\frac{3}{2}[/tex]Finally the third week he lost 1 pound more than 3/4 of the pounds he lost the first week. This can be written as:
[tex]\frac{3}{4}x+1[/tex]Hence luke lost a total of:
[tex]x+\frac{3}{2}x-\frac{3}{2}+\frac{3}{4}x+1=\frac{13}{4}x-\frac{1}{2}[/tex]Therefore the expression for Luke's weight loss is:
[tex]\frac{13}{4}x-\frac{1}{2}[/tex]Liam lost the first week 1 pound less than 3/2 times the loss Luke had the first week this can be express as:
[tex]\frac{3}{2}x-1[/tex]The second week he lost 4 pounds less than 5/2 times the loss of Luke the firs week then we have:
[tex]\frac{5}{2}x-4[/tex]Finally Liam lost 1/2 pound more than 5/4 times the loss of Luke the first week, then:
[tex]\frac{5}{4}x+\frac{1}{2}[/tex]Adding this we have:
[tex]\frac{3}{2}x-1+\frac{5}{2}x-4+\frac{5}{4}x+\frac{1}{2}=\frac{21}{4}x-\frac{9}{2}[/tex]Therefore Liam's expression is:
[tex]\frac{21}{4}x-\frac{9}{2}[/tex]Now, we know that both of them lost the same weight, then we have the equation:
[tex]\frac{13}{4}x-\frac{1}{2}=\frac{21}{4}x-\frac{9}{2}[/tex]Solving for x we have:
[tex]\begin{gathered} \frac{13}{4}x-\frac{1}{2}=\frac{21}{4}x-\frac{9}{2} \\ \frac{21}{4}x-\frac{13}{4}x=\frac{9}{2}-\frac{1}{2} \\ \frac{8}{4}x=4 \\ x=\frac{4}{\frac{8}{4}} \\ x=2 \end{gathered}[/tex]Therefore Luke lost 2 pound the first week.
Finally we plug the value of x in the expression for Luke's weight loss to get the total amount over the three weeks:
[tex]\begin{gathered} \frac{13}{4}(2)-\frac{1}{2}=\frac{13}{2}-\frac{1}{2} \\ =\frac{12}{2} \\ =6 \end{gathered}[/tex]Therefore they lost 6 pounds in three weeks.
1. Given the function g(x)=(x-4)² + 3
I’ve been asked to graph the function but they gave me no reference points to be able to find my corresponding points how do I find them with just the function?
There is no need of reference points to plot the graph of this function and we can select our reference range by ourselves as discussed above. The graph is attached in the end.
What is a function?A function is a relation between a independent variable and a dependent variable such that the value of dependent variable depends upon the independent one. For example -
f(x) = 2x + 5
g(x) = 4x + 9
Given is function g(x) = (x - 4)² + 3
There is no need of any reference points to graph this function. You can take the reference points in a specific range. For example, you can plot the graph for the values of [x] from x = -5 to x = 5. It can be noticed that we have taken 5 - 5 points on both sides of the [x] axis. Make sure that you ensure this symmetry. Range could be any, for example from x = - 7 to 7, x = - 10 to 10 etc. The given function is -
g(x) = (x - 4)² + 3
We will plot the graph for x = -3 to x = 3
g(-3) = 52
g(-2) = 39
g(-1) = 28
g(0) = 19
g(1) = 12
g(2) = 7
g(3) = 4
Now, we will plot these coordinates on the graph. The plotted graph is attached with the answer.
Therefore, we can conclude that, there is no need of reference points to plot the graph of this function and we can select our reference range by ourselves as discussed above.
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how do you factor the polynomial expression 16y4-625x4
We have the following:
[tex]16y^4-625x^4[/tex]factoring:
[tex]\begin{gathered} (4y^2)^2-(25x^2)^2=\mleft(4y^2+25x^2\mright)\mleft(4y^2-25x^2\mright)=(4y^2+25x^2)\mleft(2y+5x\mright)\mleft(2y-5x\mright) \\ \end{gathered}[/tex]Therefore, the answer is:
[tex]\mleft(4y^2+25x^2\mright)\mleft(2y+5x\mright)\mleft(2y-5x\mright)[/tex]Is the image an example of an angle?
B
65°
A
C
O No; AB and BC intersect in more than one point.
O Yes; AB and BC do not form a line and share an endpoint.
O No; AB and BC form a line.
O Yes; AB and BC are perpendicular to each other.
Yes, the image an example of an angle AB and BC do not form a line and share an endpoint.
What is an angle ?An angle is formed when two lines are extending from a point .
Using this Knowledge it can be deduced from the figure that line BA and BC are extending from point B. Hence forming an angle of 65 degrees
Analyzing the options
option A is wrong as line AB and BC intersected only on one point. formation of a line do not typically say if an angle is formed or not hence making option c incorrect. There is no perpendicular line formed in th figure .
This leaves option B as the correct option
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3x+7y=63 solve for x
Answer:
[tex]x = 21 - 2\frac{1}{3}y[/tex]
Step-by-step explanation:
3x + 7y = 63
Minus 7y from both sides, then you get...
3x = 63 - 7y
Now we divide both sides by three to find the value of x:
[tex]x = 21 - 2\frac{1}{3}y[/tex]
(-4k - 1) - (-6k - 6)
Answer:
2k + 5
Step-by-step explanation:
Since this is a subtraction problem, you need to change it to an addition problem. When you do this, you also need to change the sign of each term in the second set of parentheses.
(-4k - 1) - (-6k - 6)
(-4k - 1) + (6k + 6)
Remove the parentheses and add like terms.
-4k - 1 + 6k + 6
2k +5
Robert finds some nickels and pennies in his change purse. How many
coins does he have if he has 110 nickels and 130 pennies? How many
coins does he have if he has n nickels and p pennies?
Total coins, 110 nickels and 130
pennies:
Total coins, n nickels and p pennies:
Pls answer fast
Answer:
Step-by-step explanation:
If coins 110 plus 130 will give you 240 coins
If actual money 110 times 5 will give you 550 plus 130 will give you 680 or 6 dollars and 80 cents.
N times 5 plus p will be your equation
Triangle VWX is formed by connecting the midpoints of the side of triangle STU.
The lengths of the sides of triangle VWX are shown. What is the length of SU?
Figures not necessarily drawn to scale.
The length of the side SU will be equal to 4√2.
What is a Pythagorean theorem?Pythagorean theorem states that in the right angle triangle the hypotenuse square is equal to the sum of the square of the other two sides.
The formula for the Pythagorean theorem will be given as:-
H² = P² + B²
Here,
H = Hypotenuse
P = perpendicular
B= Base
The length of the sides of the triangle is formed by joining the midpoints of the bigger triangle are xw=2, xv=2, and vw = 3.
Here sv = vt = xw = 2 units. Apply the Pythagorean theorem in a triangle xsv.
H² = P² + B²
sx² = xv² + sv²
sx = √ ( 2² + 2² )
sx = √8
sx = √ ( 2 x 2 x 2 )
sx = 2√2
SU = 2 sx
SU = 2 x 2√2
SU = 4√2
Therefore, the length of the side SU will be equal to 4√2.
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Hi may you please help me
The value of x is 85° when a pair of parallel lines intersects another pair of parallel lines.
According to the question,
We have the following information:
A pair of parallel lines intersects another pair of parallel lines.
We have a figure where an angle is given as 85°.
Now, the following theorems would be helpful in finding the value of x:
When a pair of parallel lines is intersected by another line then the sum of two consecutive interior angles is 180°. (1)
When a pair of parallel lines is intersected by another line then the alternate interior angles are equal. (2)
Vertically opposite angles are equal. (3)
(Now, we will refer to these theorems by the number given in the brackets.)
Now, by theorem 3, we have vertically opposite angle as 85°.
Now, its alternate interior angle will also be 85°.
Now, 85° and x° are vertically opposite angles.
So, by theorem 3, we have the value of x as 85°.
Hence, the value of x is 85°.
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D
E
F
The measure of angle D is 50°, the measure of angle E is 80°, and the
measure of angle F is 10 x. What is the value of x?
Answer:
5
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
Since angle D is 50, E is 80, we can add those two for now, 50+80=130, to make it 180, we can do 180-130 which gives us 50. So the value of x is 5. Sorry that its pretty confusing
Line g is dilated by a scale factor of 1/2 from the origin to create line g'. Where are points E' and F' located after dilation, and how are lines g and g' related? 4 3 g 1 E -5 -2 -1 0 -1 -2
C) The lines g and g' are parallel and E'(-2,0) and F'(0, 1)
1) Let's locate points E and F.
E (0,2) and F( -4,0)
Given that line was dilated by a scale factor k = 1/2 about the origin we can state the following
• The line segment g' is shorter, half of g.
,• Points E'(0,1) and F'(0,1)
3) Examining the answers we can state:
The lines g and g' are parallel and E'(-2,0) and F'(0, 1)
Two angles are complementary. One angle is 4° less than four times the other angle. Find the measures of the angles.
Answer:
one of the angles is 48 degrees the other is 42 degrees
Step-by-step explanation:
Complementary is 90
45 + 45 = 90
48 +42=90
=What is 623 divided by 7
623 / 7 = 89
Result = 89
The vertices of △ABC are A(2, −3), B(−3, −5), and C(4, 1). If (x,y)--> (x-4, y-1), give the vertices of △A′B′C′.
Answer:
A' = (-2, -4)
B' = (-7, -6)
C' = (0, 0)
Step-by-step explanation:
Vertices of triangle ABC:
A = (2, -3)B = (-3, -5)C = (4, 1)Given mapping rule:
(x, y) → (x - 4, y - 1)
This notation tells you that the x-coordinate is translated 4 units to the left, and the y-coordinate is translated 1 unit down.
Substitute the coordinates of each point into the mapping rule to find the vertices of triangle A'B'C':
⇒ A' = (2 - 4, -3 - 1) = (-2, -4)
⇒ B' = (-3 - 4, -5 - 1) = (-7, -6)
⇒ C' = (4 - 4, 1 - 1) = (0, 0)
Change 6.3 kg to grams pls it's urgent
Answer:
6,300 grams
Step-by-step explanation:
kg to g is multiply by 1,000
Answer:
Step-by-step explanation:
630%
a package boodins weighs 6.2 ounces. A package of rews weighs 9.97 ounces. how much more does a package of rews weigh than a package of boondins
Based on the package of boondins and the package of rews, the package of rews will have a weight in relation to the package of boondins that is 3.77 ounces
How to find the different in weights?To find how much more that the package of rews weighs over the boondins, deduct the weight of the package of boondins from the weight of a package of rews.
Weight of package of rews = 9.97 ounces
Weight of package of boondins = 6.2 ounces
The difference in the weight of the packages is:
= 9.97 - 6.2
= 3.77 ounces
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The required difference in the package of the bodies and rews is 3.77 ounces.
As per the given in the question,
boudin is 6.2 ounces in weight and rews are 9.97 ounces in weight.
here,
As per observation, rews weighs more than bodies, and the difference between their weights is simply evaluated from the subtraction between the weight. So,
Weigh difference = weigh of rews - weigh of boodins
Substitute the value in the above equation,
Weigh difference = 9.97 - 6.2 = 3.77.
Thus, the required difference in the package of the bodies and rews is 3.77 ounces.
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what the meaning of geometric sequence?
Answer:
What is the meaning of geometric sequence?
Step-by-step explanation:
A geometric sequence is a sequence in which each term is found by multiplying the preceding term by the same value. Its general term is. a n= a 1 r n – 1. The value r is called the common ratio. It is found by taking any term in the sequence and dividing it by its preceding term.
Answer:
Below.
Step-by-step explanation:
It is a sequence of numbers with a common ratio. That is, each term after the first is obtained by multiplying the previous one by the common ratio.
Examples:
2, 6, 18, 54 ... is a geometrics sequence with common ratio 3.
1, 1/2, 1/4, 1/8 ... has a common ratio of 1/2.
-1, 1, -1, 1, -1 ... has a common ratio of -1.
The nth term of a geometric sequence is given by
a r^(n-1) where a = first term and r = common ratio.
For any integer of n which of the following, n and n+2, n-1 and n+1, 2n and 2n+2, 2n-1 and 2n+1, 2n+ 1 and 2n+2, 2n and 2n+1 are always 2 consecutive even numbers
The number 2n and 2n + 2 will always are 2 consecutive even numbers.
What is termed as the consecutive even numbers?Consecutive numbers are numbers that obey one another in a regular adding up order or pattern. They are written in a series with a fixed difference here between numbers and no numbers skipped in between. We know that even numbers end in 0, 2, 4, 6, and 8. Consider a set of even numbers ranging from 2 to 12 but rather write those in ascending order. When written from smallest to largest, the numbers are organized as 2, 4, 6, 8, 10, 12. The difference between any former leader pair is 2, as we can see. As a result, these numbers comprise the collection of consecutive even numbers.From the given option in the question;
2n and 2n + 2 will always be two consecutive even number.
For, n = 1, the numbers be 2 and 4.
For, n = 2, the numbers be 4 and 6.
For n = 3, the numbers be 6 and 8....and so on.
Thus, the number 2n and 2n + 2 will always are 2 consecutive even numbers.
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For which equations is 8 a solution? Select the four correct answers. x + 6 = 2 x + 2 = 10 x minus 4 = 4 x minus 2 = 10 2 x = 4 3 x = 24 StartFraction x Over 2 EndFraction = 16 StartFraction x Over 8 EndFraction = 1
The equations with a solution of 8 are:
x+2=10, x -4 = 4, 3x = 24, and x/8 =1
This is further explained below.
What are equations?An equation is a formula that, in mathematics, expresses the equivalence of two expressions by linking them with the equals symbol =. In other words, an equation is a mathematical expression.
An equation is a mathematical statement that demonstrates that two mathematical expressions have the same value. This is the most basic version of the definition of an equation in algebra.
For example, the phrase "3x + 5" = 14 is an equation, in which the two expressions "3x + 5" and "14" are separated by the symbol for "equal."
Now we consider all equations given
1)
x+6 = 2
x = 2-6
x = -4
2)
Considering question 2 equation to see if it equals 8
x+2=10
x = 10-2
x = 8
3)
Considering question 3 equation to see if it equals 8
x -4 = 4
x = 4+4
x = 8
4)
Considering question 4 equation to see if it equals 8
x-2=10
x = 10+2
x = 12
5)
Considering question 5 equation to see if it equals 8
2x = 4
x = 2
6)
Considering question 6 equation to see if it equals 8
3x = 24
x = 8
7)
Considering question 7 equation to see if it equals 8
x/2 = 16
x = 32
8)
Considering question 8 equation to see if it equals 8
x/8 =1
x = 8
In conclusion, only equations:
x+2=10, x -4 = 4, 3x = 24, and x/8 =1 have the solution of 8
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3.2+2(-1.5)-3.4
(pls solve by doing the order of operations)
(step by step pls)
AS per the order of operations, the value of the expression 3.2+2(-1.5)-3.4 is -3.2
Order of operations:
Order of operations states the rule that tells the correct sequence of steps for evaluating a math expression.
The order using PEMDAS:
Parentheses,
Exponents,
Multiplication and Division (from left to right),
Addition and Subtraction (from left to right).
Given,
Here we have the expression. 3.2+2(-1.5)-3.4
Now, we have to use the order of operations concept in order to solve it.
The highest priority for the order of operation is brackets and the next priority is for division and multiplication,
So, here we have to solve those things first, then we get,
=> 3.2 + (-3) - 3.4
We know that (+) x (-) = -, so, the expression is rewritten as,
=> 3.2 - 3 - 3.4
The next priority is for addition and subtraction,
So, the result is,
=> 3.2 - 6.4
=> -3.2
Therefore, the resulting number is -3.2
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I need help with this practice I attempted this and got 13.96? Make sure your answer is rounded to the nearest hundredth
Law of Cosines
Given two side lengths a and b of a triangle and the angle included by them θ, the length of the third side can be calculated as:
[tex]c^2=a^2+b^2-2ab\cos \theta[/tex]We have a = 14, b = 9, θ = 71°. Substituting:
[tex]\begin{gathered} c^2=14^2+9^2-2\cdot14\cdot9\cos 71^o \\ c^2=196+81-252\cdot0.325568 \\ c^2=194.956825 \\ c=\sqrt[]{194.956825} \\ c=13.96 \end{gathered}[/tex]The length of CD is 13.96