Find the inverse for: f(x) = x + 1/2

If it's not 6 cubic feet (because by the wording the answer is given).

If one dimension of the amount of soil they remove is 6, then you have to do 6*6*6= 216

If the total amount of soil removed is 6 cubic feet, then the dimensions of the cube would be [tex]\sqrt[3]{6}[/tex]

Answer:

x=4

Step-by-step explanation:

In a parallelogram opposite sides are congruent. That means BC and AD are congruent if ABCD must be a parallelogram.

[tex]6+3x=x+14\\6+2x=14\\2x=8\\x=4[/tex]

To double check you can substitute x into the equations again and check if they are equal.

[tex]6+3(4)=(4)+14\\6+12=18\\18=18[/tex]

Answer:

  b.  ellipse

Step-by-step explanation:

The squared terms have the same sign and different coefficients. That means the equation describes an ellipse.

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Additional comment

both variables are highest degree 2:

  coefficients have the same sign and magnitude: circle

  coefficients have the same sign and different magnitude: ellipse

  coefficients have different signs: hyperbola*

only one variable has highest degree 2:

  parabola

____

* If the equation can be factored to a product of linear terms that is zero, then the equation is of two intersecting lines. This is a degenerate case of the hyperbola in which the major axis is zero: the two vertices are the same point.

Answer:

Step-by-step explanation:

WX = 18sin(57) = 15.1

XZ = 18cos(57) = 9.8

m∠W = 90 - 57 = 33°

Answer:

B. 3x = 15

Step-by-step explanation:

To find out which equation is the correct one, we just have to replace x with 5 for each one.

2 + x = 3

2 + 5 = 7

Since 2 + 5 is 7, this one is incorrect.

3 x 5 = 15

3 times 5 is 15, so B is correct. Let's try out the other ones anyway.

5 / 2 = 2.5

Incorrect.

5 - 7 = -2

Incorrect.

The only correct equation was B. 3x = 15

Answer:

?????

Step-by-step explanation:

is there any questions you need help with ?

Answer:

a = 3

b = -7

c = 13

Step-by-step explanation:

[tex]\sf{given \ equation: 3x^2+bx+c[/tex]

[tex]\sf{sum \ of \ roots :\sf\frac{7}{3}[/tex]

[tex]\sf{product \ of \ the \ roots:\frac{13}{3}[/tex]

[tex]\sf{sum \ of \ roots \ = -\dfrac{coefficient \of \ x}{coefficient \ of \ x^2} }[/tex]

[tex]\sf \frac{-b}{3} = \frac{7}{3}[/tex]

[tex]\sf b = \frac{-7*3}{3}[/tex]

[tex]\sf b =- 7[/tex]

[tex]\sf{product \ of \ roots \ = \dfrac{constant \ term}{coefficient \ of \ x^2} }[/tex]

[tex]\sf{\frac{c}{3} =\frac{13}{3}[/tex]

[tex]\sf c = \frac{13*3}{3}[/tex]

[tex]\sf c = 13[/tex]

Therefore found that a = 3, b = -7, c = 13

Answer:

b = -7

c = 13

Step-by-step explanation:

[tex]3x^2+bx+c[/tex]

[tex]\textsf{sum of roots}=\dfrac{-b}{a}\\\\\textsf{product of roots}=\dfrac{c}{a}[/tex]

[tex]\textsf{Given sum of roots}=\dfrac73:[/tex]

[tex]\implies \dfrac{-b}{a}=\dfrac73[/tex]

[tex]\implies a=3, b=-7[/tex]

[tex]\textsf{Given product of roots}=\dfrac{13}{3}:[/tex]

[tex]\implies \dfrac{c}{a}=\dfrac{13}{3}[/tex]

[tex]\implies a=3, c=13[/tex]

Therefore,

[tex]3x^2-7x+13[/tex]

NB: The actual calculated roots are imaginary numbers as the function [tex]f(x)=3x^2-7x+13[/tex] does not intercept the x-axis

Answer: 19

Step-by-step explanation:

We know that [tex].\overline{6}=2/3[/tex], so [tex].0\overline{6}=2/30 = 1/15[/tex]

Meaning we have [tex]3.1+1/15 = \frac{31}{10}+\frac{1}{15}=\frac{31(3)+1(2)}{30}=\frac{95}{30}=\frac{19}{6}[/tex]

Answer:

so, 10 laps in 25 mins we want to make mins=1 so

10/25=2/5 times 5/5=2/5

if you multiply 2/5 by 2/2 then you get 4/10 and 4/10=0.4

the runner can run 0.4 or 2/5 lap in 1 minute

Step-by-step explanation:

it is the answer box I'm a genius

There are 12 dimes and 19 nickels

Since Jace has $2.15 in nickels and dimes.

We know that 1 nickel = $ 0.05 and 1 dime = $0.10

Let

We have that

0.05n + 0.10n' = 2.15   (1)

Since he has 7 more nickels than dimes, we have that

n = n' + 7       (2)

Substituting equation (2) into (1), we have

0.05n + 0.10n' = 2.15   (1)

0.05(n' + 7) + 0.10n' = 2.15  

0.05n' + 0.35 + 0.10n' = 2.15  

0.15n' + 0.35 = 2.15  

0.15n' = 2.15 - 0.35

0.15n' = 1.8

n' = 1.8/0.15

n' = 12

Since the number of nickels, n = n' + 7

Substituting n = 12 into the equation, we have

n = n' + 7

n = 12 + 7

n = 19

So, there are 12 dimes and 19 nickels

Learn more about simultaneous equations here:

https://brainly.com/question/21654746

Answer:

A

Step-by-step explanation:

The initial amount is 64, so that would be the y-intercept.

Each piece of wood, x, is [tex]6\frac{1}{4}[/tex] inches long, so x pieces would be [tex]6\frac{1}{4}x[/tex] pieces long.

Because you're subtracting the length of the pieces from the total length, you would subtract [tex]6\frac{1}{4}x[/tex] from 64.

Hope this helps!

Answer:

D. 30%

Step-by-step explanation:

Answer:

D) 30%

Step-by-step explanation:

→ a = 0.3

General formula,

→ a × 100 = %

Let's solve the problem,

→ 0.3 × 100

→ 30%

Thus, option (D) is answer.

Answer:

[tex]\huge\boxed{\bf\:A = 3W}[/tex]

Step-by-step explanation:

If [tex]\sf\:W = \frac { A } { 3 }[/tex], then A = ?

At first let's shift the the term 'W' to the LHS & A/3 to the RHS to bring the equation in the standard form.

[tex]\sf\:\frac{A}{3}=W[/tex]

Now, we know that, A/3 is the same as ⅓ A. Then,

[tex]\sf\:\frac{1}{3}A=W[/tex]

By multiplting both sides by 3..

[tex]\sf\:\frac{\frac{1}{3}A}{\frac{1}{3}}=\frac{W}{\frac{1}{3}} \\\sf\: A=\frac{W}{\frac{1}{3}}[/tex]

Divide [tex]\sf\:\frac{W}{\frac{1}{3}}[/tex] by its reciprocal.

[tex]\sf\:A=\frac{W}{\frac{1}{3}} \\ \sf\:A = \frac{3W}{1}\\[/tex]

So, the value of A is [tex]\downarrow[/tex]

[tex]\boxed{\bf\:A = 3W}[/tex]

__________

Have a great day ahead!

I do not really know what the exact answer you are looking for is but please give me brainiest  in return

Feet: 75

Years: 35

Step-by-step explanation:

Half of 40 is 20 and luckily they already gave us how much she would earn if she worked 20 hours.

So all we have to do is multiply the amount of money she earned when she worked 20 hours by 2 to see how much she earned when she worked 40 hours.

20 hours:165 dollars or 20:165

20 x 2= 40 and 165x2=330

So if Monique worked 40 hours she would earn $330.

Using the volume of the rectangular prism, it is found that it takes 7 hours to fill the pool.

The volume of a rectangular prism of dimensions l, w and h is given by the multiplication of it's dimensions, that is:

V = lwh.

In this problem, the dimensions in meters are: l = 7, w = 3, h = 0.75. Hence, the volume in cubic meters is:

V = lwh = 7(3)(0.75) = 15.75.

It fill 2.25 cubic meters per hour, hence, for 15.75 cubic meters, the time taken is:

15.75/2.25 = 7 hours.

More can be learned about volume of a rectangular prism at https://brainly.com/question/17223528

Answer:

The number is 1203

Answer below is correct :)

Step-by-step explanation:

Please mark brainliest if it helps! =D

That "shell" figure is supposed to represent 0.

So the number

•••

(shell)

•••

is the base-20 number 303₂₀, which in base-10 is

303₂₀ = 3 × 20² + 0 × 20¹ + 3 × 20⁰ = 1203

Answer:

A: Vertical angles are congruent, C is the midpoint of BE, and ∠B ≅ ∠E.

B: C is the midpoint of AD, BC ≅ EC, and Vertical angles are congruent.

C: I assume you cannot use CPCTC so AAS and ASA.

Step-by-step explanation:

A: Since vertical angles are congruent, the interior angles using point C of the triangles are congruent. If C is the midpoint of BE, BC ≅ EC. Draw the congruent parts based on the 3 statements with tick marks and you will see that you have two pairs of congruent angles with an included pair of congruent sides, so ASA applies.

B: If C is the midpoint of AD, AC ≅ DC. Since vertical angles are congruent, the interior angles using point C of the triangles are congruent. Draw the congruent parts based on the 3 statements with tick marks and you will see that you have two pairs of congruent sides with an included pair of congruent angles, so SAS applies.

C: ∠B ≅∠E and ∠A ≅∠D since these are pairs of alternate interior angles. Since vertical angles are congruent, the interior angles using point C of the triangles are congruent and it is given that AB ≅ DE. When making the appropriate marks, you will see that only AAS and ASA can be used without CPCTC.

Answer:

67% as a fraction is 67/100

using the keyword 'of' they mean to multiply

67/100 x 242.07 = 162.1869, rounding to the nearest cent would be $162.19

Answer:

B (6,0) because when graphed it would make a 90° angle

Answer: (B)

Step-by-step explanation:

For the triangle formed to be a right triangle in this case, the next point has to have the same x value as one of the two points in order for it to form a right triangle.

Hope that helps!

Alternate exterior angles are formed by a transversal intersecting two parallel lines, therefore, your alternate exterior angles are <1 and <5.

Your alternate interior angles are  <2 and <6/ <3 and <7.

Corresponding angles are formed when two parallel lines are intersected by a transversal. (<1 and <3)

Vertical angles are formed when two lines intersect each other. Therefore, <1 and <7 fall into this category.

Answer:

y = -5/2x + 27/2

Step-by-step explanation:

line formula is y = mx + b

perpendicular means number next to the x (slope or m) becomes a negative reciprocal

2/5x -> -5/2x

then use point slope formula

y - y1 = m (x - x1)

y - 6 = -5/2 (x - 3)

y - 6 = -5/2x + 15/2

y = -5/2x + 15/2 + 6

y = -5/2x + 15/2 + 12/2

y = -5/2x + 27/2

Answer:

The answer is b, which is 3+x+3

Answer:

cos²Θ

Step-by-step explanation:

simplify the expression using the identities

tanΘ = [tex]\frac{sin0}{cos0}[/tex]

cos2Θ = 1 - 2sin²Θ

cos²Θ = 1 - sin²Θ

then

tanΘ × sinΘ × cosΘ + cos2Θ

= [tex]\frac{sin0}{cos0}[/tex] × sinΘ × cosΘ + 1 - 2sin²Θ ( cancel cosΘ on numerator/ denominator )

= sinΘ × sinΘ + 1 - 2sin²Θ

= sin²Θ + 1 - 2sin²Θ

= 1 - sin²Θ

= cos²Θ

Answer:

[tex]\cos^2(\theta)[/tex]

Step-by-step explanation:

Trig identities used:

[tex]\cos(2\theta)=\cos^2(\theta)-\sin^2(\theta)[/tex]

[tex]\tan(\theta)=\dfrac{\sin(\theta)}{\cos(\theta)}[/tex]

Therefore,

[tex]\tan(\theta)\times\sin(\theta)\times\cos(\theta)+\cos(2\theta)[/tex]

[tex]=\dfrac{\sin(\theta)}{\cos(\theta)}\times\sin(\theta)\times\cos(\theta)+\cos(2\theta)[/tex]

[tex]=\sin^2(\theta) +\cos(2\theta)[/tex]

[tex]=\sin^2(\theta) +\cos^2(\theta)-\sin^2(\theta)[/tex]

[tex]=\cos^2(\theta)[/tex]