Find the missing side of the right triangle. Leave your answer in simplest radical form. show work

Find The Missing Side Of The Right Triangle. Leave Your Answer In Simplest Radical Form. Show Work

Answers

Answer 1

Applying the Pithagorean Theorem

we have

[tex]12^2=x^2+(8\sqrt[]{2})^2[/tex]

solve for x

[tex]\begin{gathered} 144=x^2+128 \\ x^2=144-128 \\ x^2=16 \\ x=\sqrt[]{16} \end{gathered}[/tex]x=4 mi

Related Questions

Factor Problem Completely 16n^3 - 56n^2 + 8n - 28

Answers

Given

The equation is given as

[tex]16n^3-56n^2+8n-28[/tex]

Explanation

Factorisation the equation,

[tex]4(4n^3-14n^2+2n-7)[/tex]

Factorise the polynomial.

[tex]4(2n-7)(2n^2+1)[/tex]Answer

Hence the answer is

[tex]4(2n-7)(2n^2+1)[/tex]

Can you please help me find the area of the shaded triangle? Thank you :)

Answers

Area of shaded triangle = Area of triangle - area of circle

Area of triangle = 1/2 x base x height

Base= 16 yds

Height= 19 yds

Area of triangle = 1/2 x 16 x 19 = 8 x 19 =152 square yard

[tex]\begin{gathered} \text{Area of circle = }\pi\times r^2 \\ \pi=3.14 \\ r=5\text{yds} \\ \text{Area of circle = 3.14 }\times5^2=78.5yard^2 \end{gathered}[/tex]

Area of shaded triangle = 152 - 78.5 =73.5 square yard

Given that angle A lies in Quadrant III and sin(A)= −17/19, evaluate cos(A).

Answers

As we know;

[tex]sin^2(x)+cos^2(x)=1[/tex]

We will use this equality. We take the square of the sine of the given angle and subtract it from [tex]1[/tex].

[tex]sin^2(A)=(-\frac{17}{19} )^2=\frac{289}{361}[/tex][tex]sin^2(A)+cos^2(A)=1[/tex][tex]sin^2(A)=1-cos^2(A)[/tex][tex]\frac{289}{361}=1-cos^2(A)[/tex][tex]cos^2(A)=1-\frac{289}{361} =\frac{72}{361}[/tex][tex]\sqrt{cos^2(A)} =cos(A)[/tex][tex]\sqrt{\frac{72}{361} }=\frac{6\sqrt{2} }{19}[/tex]

In the third region the sign of cosines is negative. Therefore, our correct answer should be as follows;

[tex]cos(A)=-\frac{6\sqrt{2} }{19}[/tex]

Question 39.Find the inverse of the given function. Graph both functions on the some set of axes and show the line y=x as a dotted line in the graph.

Answers

First, to find the inverse of a function, call the original function "x" and call call "x" in the original function as the inverse function:

[tex]\begin{gathered} f(x)=5x+1 \\ x=5f^{-1}(x)+1 \end{gathered}[/tex]

Now, we solve for the inverse function:

[tex]\begin{gathered} x=5f^{-1}(x)+1 \\ 5f^{-1}(x)+1=x \\ 5f^{-1}(x)=x-1 \\ f^{-1}(x)=\frac{x}{5}-\frac{1}{5} \end{gathered}[/tex]

To graph lines, we can find two points in it and draw a line that passes through both.

Let's pick x = 0 and x = 1 for the first equation:

[tex]\begin{gathered} f(0)=5\cdot0+1=1 \\ f(1)=5\cdot1+1=6 \end{gathered}[/tex]

So, we plot the points (0, 1) and (1, 6).

For the inverse, we can simply invet the coordinates, which is the same as picking x = 1 and x = 6:

[tex]\begin{gathered} f^{-1}(1)=\frac{1}{5}-\frac{1}{5}=0 \\ f^{-1}(6)=\frac{6}{5}-\frac{1}{5}=\frac{5}{5}=1 \end{gathered}[/tex]

Thus, we have the points (1, 0) and (6, 1).

The line y = x is jus the diagonal that passes though point (0, 0) and (1, 1), for example.

Putting these points and drawing the lines, we get:

The ratio of students polled in 6th grade who prefer lemonade to iced tea is 8:4, or 2:1. If there were 39 students in 6th grade polled, explain how to find the number of students that prefer lemonade and the number of students that prefer iced tea. Be sure to tell how many students prefer each.

Answers

Since we know the ratio is 2:1, then to find the number of students who like iced tea we convert the ratio to a fraction:

[tex]\frac{1}{2}[/tex]

this means that one of two students preferred iced tea.

To find the number of students who prefer iced tea we multiply the total number of students by the fraction, then:

[tex]39\cdot\frac{1}{2}=\frac{39}{2}=19.5[/tex]

Since we can't have a fraction of a student, we conclude that 19 students prefer iced tea and 20 prefer lemonade.

write each of the following numbers as a power of the number 2

Answers

Answer

The power on 2 is either -3.5 in decimal form or (-7/2) in fraction form.

Explanation

To do this, we have to first note that

[tex]\begin{gathered} \sqrt[]{2}=2^{\frac{1}{2}} \\ \text{And} \\ 16=2^4 \end{gathered}[/tex]

So, we can then simplify the given expression

[tex]\begin{gathered} \frac{\sqrt[]{2}}{16}=\frac{2^{\frac{1}{2}}}{2^4}=2^{\frac{1}{2}-4} \\ =2^{0.5-4} \\ =2^{-3.5} \\ OR \\ =2^{\frac{-7}{2}} \end{gathered}[/tex]

Hope this Helps!!!

Please assist me. I have no idea how to start this equation

Answers

Part a

Remember that the linear equation in slope-intercept form is

y=mx+b

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem

the equation is of the form

C=m(n)+b

where

m=8.50

b=350

therefore

C=8.50n+350

Part b

A reasonable domain for n (number of cups)

Remember that the number of cups cannot be a negative number

so

the domain is the interval [0, infinite)

but a reasonable domain could be [0, 500]

Find out the range

For n=0 -----> C=350

For n=500 ----> C=8.50(500)+350=2,100 ZAR

the range is the interval [350,2,100]

Part c

calculate the cost

For n=100 cups ----> C=8.50(100)+350=1,200 ZAR

For n=200 cups ----> C=8.50(200)+350=2,050 ZAR

For n=400 cups ---> C=8.50(400)+350=3,750 ZAR

Part d

Average cost

Divide the total cost by the number of cups

For 100 cups ------> 1,200/100=12 ZAR per cup

For 200 cups ----> 2,050/200=10.25 ZAR per cup

For 400 cups ----> 3,750/400=9.38 ZAR per cup

Part e

it is better to order more cups, to reduce the initial ZAR 350 cost.

Part f

In this problem we have the ordered pairs

(200, 2150) and (400, 3750)

Find out the slope m

m=(3750-2150)/(400-200)

m=8 ZAR per cup

Find out the linear equation

C=mn+b

we have

m=8

point (200,2150)

substitute and solve for b

2150=8(200)+b

b=2150-1600

b=550

therefore

The linear equation is

C=8n+550

Part g

A reasonable domain could be [0, 600]

Find out the range

For n=0 ------> C=550

For n=600 ----> C=8(600)+550=5,350

The range is the interval [550,5350]

Part h

The gradient is the same as the slope

so

slope=8

that means ----> the cost of each cup is 8 ZAR

Part i

For n=600

C=8(600)+550=5,350 ZAR

Part j

we have the inequality

8n+550 < 8.50n+350

Solve for x

550-350 < 8.50n-8n

200 < 0.50n

400 < n

Rewrite

n > 400

For orders more than 400 cups is more effective to order from Cupomatic

Verify

For n=401

C=8n+550=8(401)+550=3,758 ZAR

C=8.50n+350=8.5(401)+350=3,758.5 ZAR

the cost is less in CUPOMATIC, is ok

the answer is

For orders more than 400 cups is more effective to order from Cupomatic

StatusRecovery8Help ResourcessAABC ~ AXYZFind the missing side length, s.B.3 65А&Х-ZCross multiplySE ][?] = [ ]153s

Answers

Since triangles ABC and XYZ are similar, the ratio between their corresponding sides is constant; thus,

[tex]\begin{gathered} \frac{AB}{XY}=\frac{BC}{YZ} \\ \Rightarrow\frac{3}{5}=\frac{6}{s} \end{gathered}[/tex]

Solving for s,

[tex]\begin{gathered} \frac{3}{5}=\frac{6}{s} \\ \Rightarrow\frac{3}{5}\cdot s=\frac{6}{s}\cdot s \\ \Rightarrow\frac{3s}{5}=6 \\ \Rightarrow\frac{3s}{5}\cdot5=6\cdot5 \\ \Rightarrow3s=30 \\ \Rightarrow s=\frac{30}{3} \\ \Rightarrow s=10 \end{gathered}[/tex]

Thus, the result of the cross multiplication is 3s=30 and the answer is s=10

What is the standard form of the equation of a line passing through points (2,3) and (2,-5)?

Answers

Answer:

[tex]x\text{ = 2}[/tex]

Explanation:

Here, we want to find the standard form of the equation

We have the standard form as:

[tex]Ax\text{ + By = C}[/tex]

We can arrive at this using the two-points form:

This is:

[tex]\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{y-y_1}{x-x_1}[/tex]

(x1,y1) = (2,3)

(x2,y2) = (2,-5)

Now, as we can see, the line is a vertical line since the x-value is the same

Thus, we have it that:

[tex]x\text{ = c}[/tex]

where c will represent the x-intercept

Thus, we have the equation of the line as:

[tex]x\text{ = 2}[/tex]

Consider the expression 6+(x+3)^2. Tabulate at least SIX different values of the expression.​

Answers

Considering the expression 6+(x+3)^2. the table of at least SIX different values of the expression is

x               y

0            15

1             22

2            31

3            42

4            55

5            70

How to determine the he table of at least SIX different values of the expression

The table is completed by substituting the values of x in the given expression as follows

6 + (  x + 3 )^2

for x = 0, y = 6 + ( 0 + 3) ^2 = 15

for x = 1, y = 6 + ( 1 + 3) ^2 = 22

for x = 2, y = 6 + ( 2 + 3) ^2 = 31

for x = 3, y = 6 + ( 3 + 3) ^2 = 42

for x = 4, y = 6 + ( 4 + 3) ^2 = 55

for x = 5, y = 6 + ( 5 + 3) ^2 = 70

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$1750 is invested in an account earning 3.5% interest compounded annualy. How long will it need to be in an account to double?

Answers

Given :

[tex]\begin{gathered} P\text{ = \$ 1750} \\ R\text{ = 3.5 \%} \\ A\text{ = 2P} \\ A\text{ = 2}\times\text{ 1750 = \$ 3500} \end{gathered}[/tex]

Amount is given as,

[tex]\begin{gathered} A\text{ = P( 1 + }\frac{R}{100})^T \\ 3500\text{ = 1750( 1 + }\frac{3.5}{100})^T \\ \text{( 1 + }\frac{3.5}{100})^T\text{ = }\frac{3500}{1720} \end{gathered}[/tex]

Further,

[tex]\begin{gathered} \text{( 1 + }\frac{3.5}{100})^T\text{ = 2} \\ (\frac{103.5}{100})^T\text{ = }2 \\ (1.035)^T\text{ = 2} \end{gathered}[/tex]

Taking log on both the sides,

[tex]\begin{gathered} \log (1.035)^T\text{ = log 2} \\ T\log (1.035)\text{ = log 2} \\ T\text{ = }\frac{\log \text{ 2}}{\log \text{ 1.035}} \end{gathered}[/tex]

Therefore,

[tex]\begin{gathered} T\text{ = }\frac{0.3010}{0.0149} \\ T\text{ = 20.20 years }\approx\text{ 20 years} \end{gathered}[/tex]

Thus the required time is 20 years.

Write a multiplication expression to represent each situation. Then find each product and explain its meaning. Ethan burns 650 calories when he runs for 1 hour. Suppose he runs 5 hours in one week.

Answers

We know that

• Ethan burns 650 calories per hour.

If he runs 5 hours we just have to multiply this time with the given rate.

[tex]650\cdot5=3,250[/tex]Therefore, Ethan burns 3,250 calories in 5 hours.

solve 6 + 5 on the sqr root of 249 - 2x = 7

Answers

ANSWER

x = 124

EXPLANATION

First we have to clear the term that contains x in the equation. In this case, this term is the second term. So we have tu subtract 6 from both sides of the equation:

[tex]\begin{gathered} 6-6+\sqrt[5]{249-2x}=7-6 \\ \sqrt[5]{249-2x}=1 \end{gathered}[/tex]

Then, we have to eliminate the root. Note that in the expression inside the root there are two terms. To do this, we have to apply the "opposite" operation on both sides of the equation, which in this case is exponent 5:

[tex]\begin{gathered} (\sqrt[5]{249-2x})^5=1^5 \\ 249-2x=1 \end{gathered}[/tex]

Now we do something similar to the first step. We want to leave on one side of the equation only the term that contains x and the rest on the other side. To do this we can either add 2x on both sides, or subtract 249 from both sides. We'll apply the first option because then we'll have a positive coefficient for x:

[tex]\begin{gathered} 249-2x+2x=1+2x \\ 249=1+2x \end{gathered}[/tex]

However, we now have to subtract 1 from both sides of the equation:

[tex]\begin{gathered} 249-1=1-1+2x \\ 248=2x \end{gathered}[/tex]

Finally, to find x, we have to divide both sides by 2:

[tex]\begin{gathered} \frac{248}{2}=\frac{2x}{2} \\ 124=x \end{gathered}[/tex]

Hence, the solution to the equation is x = 124.

I resolved this problem for a test already but it looks like the graph it’s not ok can you help me?

Answers

SOLUTION

The function given is

[tex]f(x)=2x+1[/tex]

To obtain the slope, we compare the equation above with the standard form of a slope intercept form.

Hence,, slope intercept is given as

[tex]\begin{gathered} y=mx+c \\ \text{Where m=slope.c=intercept on y (0,c)} \end{gathered}[/tex]

Comparing with the function given, we have

[tex]\begin{gathered} M=2,c=1 \\ \text{Hence } \\ \text{slope}=2,\text{ y-intercept=(0,1)} \end{gathered}[/tex]

Therefore

The slope = 2 and the y-intercept= (0,1 )

The graph of the functionis given in the image below

Shanice has 4 times as much many pairs of shoes as does her brother Ron. If Shanice gives Ron 12 pairs of shoes, she will have twice as many pairs of shoes as Ron does. How many pairs of shoes will Shanice have left after she gives Ron the shoes?

Answers

Let's define:

x: pairs of shoes of Shanice

y: pairs of shoes of Ron

Shanice has 4 times as much many pairs of shoes as does her brother Ron, means:

x = 4y (eq. 1)

If Shanice gives Ron 12 pairs of shoes, she will have twice as many pairs of shoes as Ron does, means:

x - 12 = 2y (eq. 2)

Replacing equation 1 into equation 2:

4y - 12 = 2y

4y - 2y = 12

2y = 12

y = 12/2

y = 6

and

x = 4*6 = 24

After she gives Ron the shoes, she will have left 24-12 = 12 pairs of shoes

factor the following by taking on the greatest common factor 14a^3 + 35a^2 +42a

Answers

Let's break apart each term into its factors:

[tex]\begin{gathered} 14a^3=2\cdot7\cdot a\cdot a\cdot a \\ 35a^2=5\cdot7\cdot a\cdot a \\ 42a=2\cdot3\cdot7\cdot a \end{gathered}[/tex]

The common factors are

7 * a

That is,

[tex]7\cdot a=7a[/tex]

Now, factorizing the expression, we have:

[tex]\begin{gathered} 14a^3+35a^2+42a \\ =7a(2a^2+5a+6) \end{gathered}[/tex]Answer[tex]7a(2a^2+5a+6)[/tex]

3. The data in the table gives the number of barbeque sauce bottles (y) that are sold with orders of chicken wings (x) for each hour on a given day at Vonn's Grill. Use technology to write an equation for the line of best fit from the data in the table below. Round all values to two decimal places.

Answers

1) Let's visualize the points

2) To find the equation for the line of best fit we'll need to follow some steps.

2.1 Let's find the mean of the x values and the mean of the Y values

2.2 Now It's time to find the slope, with the summation of the difference between each value and the mean of x times each value minus the mean over the square of the difference of the mean of x and x.

To make it simpler, let's use this table:

The slope then is the summation of the 5th column over the 6th column, we're using the least square method

[tex]m=\frac{939.625}{1270.875}=0.7393\cong0.74[/tex]

The Linear coefficient

[tex]\begin{gathered} b=Y\text{ -m}X \\ b=14.625-0.73(19.875) \\ b=0.11625\cong0.12 \end{gathered}[/tex]

3) Finally the equation of the line that best fit is

[tex]y=0.73x+0.12[/tex]

Hi, can you help me to solve thisexercise, please!!For cach polynomial, LIST all POSSIBLE RATIONAL ROOTS•Find all factors of the leading coefficient andconstant value of polynonnal.•ANY RATIONAL ROOTS =‡ (Constant Factor over Leading Coefficient Factor)6x^3+7x^2-3x-1

Answers

[tex]\begin{gathered} Possible\: Roots\colon\pm1,\pm\frac{1}{2},\pm\frac{1}{3},\pm\frac{1}{6} \\ Actual\: Rational\: Roots\colon\: None \end{gathered}[/tex]

1) We can do this by listing all the factors of -1, and the leading coefficient 6. So, we can write them as a ratio this way:

[tex]\frac{p}{q}=\pm\frac{1}{1,\:2,\:3,\:6}[/tex]

Note that p stands for the constant and q the factors of that leading coefficient

2) Now, let's test them by plugging them into the polynomial. If it is a rational root it must yield zero:

[tex]\begin{gathered} 6x^3+7x^2-3x+1=0 \\ 6(\pm1)^3+7(\pm1)^2-3(\pm1)+1=0 \\ 71\ne0,5\ne0 \\ \frac{1}{2},-\frac{1}{2} \\ 6(\pm\frac{1}{2})^3+7(\pm\frac{1}{2})^2-3(\pm\frac{1}{2})+1=0 \\ 2\ne0,\frac{7}{2}\ne0 \\ \\ 6(\pm\frac{1}{3})^3+7(\pm\frac{1}{3})^2-3(\pm\frac{1}{3})+1=0 \\ 1\ne0,\frac{23}{9}\ne0 \\ \frac{1}{6},-\frac{1}{6} \\ 6(\frac{1}{6})^3+7(\frac{1}{6})^2-3(\frac{1}{6})+1=0 \\ \frac{13}{18}\ne0,-\frac{5}{3}\ne0 \end{gathered}[/tex]

3) So the possible roots are:

[tex]\pm1,\pm\frac{1}{2},\pm\frac{1}{3},\pm\frac{1}{6}[/tex]

But there are no actual rational roots.

writing equations in slope-intercept form common core algebra 1question 1

Answers

The equation of the line in the slope-intercept form is y = mx + b, where "m" is the slope and "b" is the y-intercept.

"b" is the point (0, yi).

"m" can be found using 2 points P₁ (x₁, y₁) and P₂ (x₂, y₂), according to the formula below:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

So, to solve this question, follow the steps below.

(a) First graph

Step 01: Find the y-intercept and another point in the graph.

To find the points in the graph, choose a x-value and find its corresponding y-value.

Choosing x = 0, y = 2.

P₁ = (0, 2).

Choosing x = -3, y = -2.

P₂ = (-3, -2).

Step 02:

The table shows a linear relationship between x and y. Drag and drop the options provided into the correct boxes to complete the equation. х 1 0 6 -4 41 у 9 -39 The equation that represents the relationship Is y = -8 -41 ON 9 4 O?

Answers

To calculate the equation first we need to choose two points of the table

P1 (1,1)=(x1,y1)

P2(0,9)=(x2,y2)

then we calculated the slope m

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

substituting the points we have

[tex]m=\frac{9-1}{0-1}=\frac{8}{-1}=-8[/tex]

then we can calculate the equation

[tex](y-y1)=m(x-x1)[/tex][tex](y-1)=-8(x-1)[/tex]

[tex]y-1=-8x+8[/tex]

[tex]y=-8x+8+1[/tex]

the equation is

[tex]y=-8x+9[/tex]


3. Convert the angle 3π/4 to degrees.

Answers

Answer:

135°

Step-by-step explanation:

To convert an angle from radians to degrees, multiply by [tex]180/\pi[/tex].

[tex]\frac{3\pi}{4} \cdot \frac{180}{\pi}=135^{\circ}[/tex]

The pentagonal prism below has a height of 13 units and a volume of 247 units ^3. Find the area of one of its bases.

Answers

• Volume of pentagonal prism = area of base x height

Volume = 247 unis^3

height = 13 units

Replacing:

V = A x h

A = V / h

A = 247/13 = 19 units^2

URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS

Answers

According to visual inspection, shape A has been rotated 180° counterclockwise about the origin and then translated 1 unit to the left.

What is meant by transformation?

A point, line, or geometric figure can be transformed in one of four ways, each of which affects the shape and/or location of the object. Pre-Image refers to the object's initial shape, and Image, after transformation, refers to the object's ultimate shape and location.

The four basic transformations exist:

TranslationReflectionRotationDilation

According to visual inspection, shape A has been rotated 180° counterclockwise about the origin and then translated 1 unit to the left.

Therefore, the correct answer is option C) translated 1 unit to the left and then rotated 180° counterclockwise about the origin

The complete question is:

Describe the transformation that maps the pre-image A to the image A.

A) translated 8 units up and then reflected across the y-axis

B) translated 8 units down and then reflected across the y-axis

C) translated 1 unit to left and then rotated 180° counterclockwise about the origin

D) translated 1 unit to right and then rotated 180° counterclockwise about the origin.

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Determine if the 2 lines are parallel, perpendicular, or neither based on their slope-intercept equations.
Equations of lines G & H;
Line G: y=-6x + 14
Line H: y=6x-14
O Perpendicular
O Not Enough Information
O Parallel
O Neither
POSS
10 11
12 13 14 15

Answers

Answer:

perpendicular because the slopes are opposite

Step-by-step explanation:

GRAPH each triangle and CLASSIFY the triangle according to its sides and angles.

Answers

Answer:

[tex]\Delta CAT\text{ is an ISOSCELES triangle}[/tex]

Explanation:

To properly classify the traingle, we need to get the length of the sides

To get the length of the sides, we need to get the distance between each two points using the distance between two points formula

Mathematically,we have the formula as:

[tex]D\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Where (x1,y1) refers to the coordiantes of the first point while (x2,y2) refers to the coordinates of the second point

let us get the coordinates of the individual points as seen from the plot shown

C (1,8)

A (5,10)

T (7,6)

So, let us find the distance between each two points

For AC, we have:

[tex]D\text{ = }\sqrt[]{(5-1)^2+(10-8)^2}\text{ = }\sqrt[]{20}[/tex]

For AT, we have:

[tex]D=\sqrt[]{(7-5)^2+(6-10)^2\text{ }}\text{ = }\sqrt[]{20}[/tex]

Lastly, for CT, we have:

[tex]D\text{ = }\sqrt[]{(7-1)^2+(6-8)^2\text{ }}\text{ = }\sqrt[]{40}[/tex]

From our calculations, we can see that AC = AT

If we have a triangle which has two of its sides equal in length (the angle facing these sides would be same too), we call this an isosceles triangle

So, the class of triangle CAT is isosceles triangle

Which statement best describes the area of the triangle shown below?

Answers

ANSWER

Option D - The area of this triangle is one-half of that of a square that has area of 12 square units

EXPLANATION

We want to the best description of the area of the triangle given.

To do this, we have to first find the area of the triangle.

The area of a triangle is given as:

[tex]A\text{ = }\frac{1}{2}(b\cdot\text{ h)}[/tex]

Where b = base and h = height

From the diagram, we have that:

b = 4 units

h = 3 units.

Therefore, the area of this triangle is:

[tex]\begin{gathered} A\text{ = }\frac{1}{2}(4\cdot\text{ 3)} \\ A\text{ = }\frac{1}{2}(12) \\ A\text{ = 6 square units} \end{gathered}[/tex]

Checking through the options, we see that the only correct option is Option D.

This is because the area of this triangle (6 square units) is one-half of that of a square that has area of 12 square units

What is the y-intercept of the line x+2y=-14? (0,7) (-7,0) (0,-7) (2,14)

Answers

[tex]\begin{gathered} \text{First, we need to isolate y} \\ 2y=-x-14 \\ y=\frac{-x-14}{2} \\ y=\frac{-x}{2}-\frac{14}{2} \\ y=-\frac{x}{2}-7 \\ -7\text{ represents the y-intercept} \\ \text{When you write as a point it would be (0, -7)} \end{gathered}[/tex]

i inserted a picture of the questioncan you state whether the answer is A, B, C OR D

Answers

Looking at the triangles, they are both right triangles. They have congruent legs = 12. They have congruent acute angles of 45 degerees. Thus, they are congruent triangles. The answer is True

Is x5 + x2 + x a polynomial? Explain why or why not.

Answers

A polynomial is a mathematical expression formed by variables and coefficients, that involves only the operations of addition, subtraction, multiplication and non-negative integer exponentiation of variables.

The expression:

[tex]x^5+x^2+x[/tex]

Is formed by the addition of three terms, each consisting of the variable x raised to a positive integer quantity. Therefore, the given expression is a polynomial.

Describe it and decide if normal curve could be used as model

Answers

Answer:

The symmetric is symmetric

The distribution is unimodal

The mean, median, and mode are equal

A normal distribution is appropriate

Explanation:

The normal distribution is symmetric and unimodal, where the mode, the median, and the mean are equal. This distribution has the following shape

Therefore, the normal curve can be used as a model for the distribution.

So, the answers are:

The symmetric is symmetric

The distribution is unimodal

The mean, median, and mode are equal

A normal distribution is appropriate

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