Find the molecular formula from the following empirical formulas
KSO2 (206.34 g/mol)
BH3 (27.668 g/mol)
C3FeO6 (375.76 g/mol)
SF5 (254.14 g/mol)

Answers

Answer 1

The molecular formula of KSO₂ is K₂S₂O₄. Similarly the molecular formula of BH₃ is B₂H₆ and that of C₃FeO₆ is C₆Fe₂O₁₂.

What is empirical formula ?

The empirical formula of a compound is derived from the number of moles of each element present and converting their ratio of number of moles into whole numbers.

The molecular formula is derived by dividing the molecular mass by the formula mass and multiply the empirical formula with the obtained integer.

The formula mass of KSO₂ = 103 g/mol

molecular mass  = 206.34 g.

206.34/103 = 2.

then molecular  formula = K₂S₂O₄

The formula mass of BH₃ = 14 g/mol

molecular mass  = 27.668 g.

27.668/14 = 2.

then molecular  formula = B₂H₆

The formula mass of  C₃FeO₆  = 187.8 g/mol

molecular mass  = 375.6g.

375.6 /187.8 = 2.

then molecular  formula = C₆Fe₂O₁₂

The formula mass of  SF₅ = 127 g/mol

molecular mass  = 254.14 g.

254.14 /127  = 2.

then molecular  formula = S₂F₁₀

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Related Questions

how many significant figures does the number 1.006x10 7 have?

Answers

Answer:

4 significant figures.

Explanation:

As the number is expressed in standard form, you only need to look at the coefficient.

This is because [tex]1.006 * 10^7 = 10060000[/tex], so multiplying by 10 to the power of anything just results in zeros at the end of the number. A zero at the end is not a significant figure, so is ignored.

This means that you look at 1.006 for the significant figures.

The first non-zero digit is 1, so this is the first significant figure. There is then a zero, another zero, and finally a six. This is a total of 4 significant figures.

Final answer:

The number 1.006 x 10^7 has 4 significant figures. These include the '1', and the three digits following the decimal point - '0', '0', '6', which all contribute to its precision.

Explanation:

The number 1.006 x 10^7 includes significant figures which are digits carrying meaningful contributions to its measurement precision. This number has 4 significant figures: the '1', and the three numbers after the decimal point, '0', '0', and '6'. Every non-zero number is always significant; zeroes between two significant digits are significant. Here, the zeroes aren't placeholders but significant digits, thus contributing to the precision of the measurement.

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The half-life of barium-131 given to patients undergoing x-ray imaging is 11.6 days. Suppose that 0.5g of barium-131 is given to a patient. How many grams would remain 2 months (60 days) later?

Answers

The amount of the barium-131 that would remain after 2 months (i.e 60 days), given that the barium-131 has an half-life of 11.6 days is 0.014 g

How do I determine the amoun remaining after 2 months?

We know that the half-life of a material is the time taken for half the material to decay.

Thus, given the half-life of the barium-131, we shall begin our calculation by obtaining the number of half lives that has passed. This is shown below:

Half-life (t½) = 11.6 daysTime (t) = 2 months = 60 daysNumber of half-lives (n) =?

n = t / t½

n = 60 / 11.6

Finally, we shall determine the amount that will remain after 2 months. This is illustrated below:

Number of half-lives (n) = 60 / 11.6Original amount (N₀) = 0.5 gAmount remaining (N) = ?

N = N₀ / 2ⁿ

N = 0.5 / 2^(60 / 11.6)

N = 0.014 g

In conclusion, we can say that the amount that would remain after 2 months is 0.014 g

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Which equation shows how velocity is related to frequency and wavelength?
A. v= f x £
B. v=f-£
C. V = f/£
D. V = £/f

Answers

The equation that shows how velocity is related to frequency and wavelength is v=f/£.

What is wavelength?

Wavelength is a measure of the distance between two successive peaks of a wave, usually expressed in meters.

Velocity (v) is the speed at which a wave travels and is measured in meters per second (m/s).
Frequency (f) is the number of waves that pass by a given point in a given period of time and is measured in hertz (Hz).
Wavelength (£) is the distance between two successive wave crests and is measured in meters (m).
Therefore, the equation that shows how velocity is related to frequency and wavelength is v=f/£.

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Answer:A. v=f x E

Explanation: i just did the quiz

N-methyl acetamide molecules can form dimers with each other. This dimerization is favored with CCl4 as a solvent but disfavored in aqueous solution. Why?

Answers

The N-methyl acetamide molecules can form dimers with each other through hydrogen bonding interactions between the amide hydrogen and the nitrogen atom of another molecule. The strength of these interactions depends on the solvent in which the molecules are dissolved.

In CCl4, the solvent is a non-polar solvent, which means that the solvent molecules do not have any polar groups that can form interactions with the N-methyl acetamide molecules. As a result, the N-methyl acetamide molecules are free to interact with each other and form dimers. The absence of polar groups in the solvent means that the molecules are not surrounded by any solvent molecules, hence the dimerization is favored.

On the other hand, water is a polar solvent, which means that the water molecules have polar groups that can form interactions with the N-methyl acetamide molecules. The polar nature of water means that the N-methyl acetamide molecules are surrounded by water molecules, which can interact with the polar groups on the N-methyl acetamide molecules and disrupt the hydrogen bonding interactions between the molecules. As a result, the dimerization of N-methyl acetamide molecules is disfavored in aqueous solution, and the molecules are less likely to form dimers.

Part A
Write net ionic equation for the following reaction:
H₂SO⁴ (aq) +MgCO₃(s) →H₂O(l) +CO₂(g) + MgSO⁴ (aq)
Express your answer as a chemical equation including phases.
Based on the positions of strontium (Sr) and antimony (Sb) in the periodic table, which would you expect to be the better reducing agont? Will the following reaction occur? Explain.
2Sb ³⁺(aq) + 3Sr (s)→ 2Sb (s) +3 Sr (s)²⁺ (aq)
Match the items in the left column to the appropriate blanks in the sentences on the right.
right
not occur
Sr
left
occur
Sb
_____ is more metallic than _____ because it is in the same period and to the _____
of _____ on the periodic table_____ . is the better reducing agent.
This reaction 2Sb ³⁺(aq) + 3Sr (s)→ 2Sb (s) +3 Sr (s)²⁺ (aq) _____

Answers

Answer:

H2SO4(aq)+yuomeg

Explanation:

w2Sb

Describe the type of bonds that different materials have and explain how these bonds account for the differences in melting point?

Answers

Lead contain covalent bond.Mercury has containing covalent bonding. Sodium chloride contained ionic bond. In water hydrogen bonding is present.

What is bond ?

An enduring attraction between atoms or ions known as a chemical bond is what allows molecules and crystals to form. The bond may be created by the sharing of electrons in covalent bonds or by the electrostatic attraction of two oppositely charged ions, as in ionic bonds.

A water molecule contains two hydrogen atoms. With the oxygen atoms of various water molecules, both of these atoms are capable of forming hydrogen bonds. Up to three other water molecules can form hydrogen bonds with each individual water molecule.

Thus, Lead contain covalent bond.Mercury has containing covalent bonding. Sodium chloride contained ionic bond.

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Compound A, C undergoes reaction with ozone, followed by Zn treatment, to give 10H16, reacts with 2 molar equivalent(s) of hydrogen on catalytic hydrogenation. A Compound A > HCH CH3CCH3 Propose a structure for A. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms In cases where there is more than one answer, just draw one.

Answers

The catalytic hydrogenation reaction is drawn like attached file

How to determine determine the reaction?

As per given formula is C₁₀H₁₆C₁₀H₁₆. The double bond equivalent (DBE) of the formula given will be:

DBE = (2C + 2 + N − H − X) : 2

notation:

C = The number of the carbon atom.

N = The number of the nitrogen atom.

H = The number of the hydrogen atom.

X = The number of the halogen atom.

DBE = (2 × 10 + 2 + 0 − 18 − 0) : 2

DBE = (20 + 2 − 18) :2

DBE = 2

It result in bicyclic compound. The catalytic hydrogenation reaction is drawn similarly to attached file

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please help

What is the most significant cause of species extinction on Earth?

A) rare disease
B) habitat destruction by humans
C) natural climate events
D) earthquakes

Answers

Answer:

b

Explanation:

i think

If 6g of Mg completely react with excess oxygen, what volume of oxygen will be consumed?​

Answers

The number of volume of the oxygen that would be consumed is 2.8 L.

What is the volume of the oxygen that would be consumed?

Let us recall that what we have here is the process of the use of the stoichiometry of the reaction so as to be able to obtain the mass and the volume of the reactants that are taking place in the reaction as we are going to have in the case that is at hand.

What we now need to do so that we can be able to use the stoichiometry of the reaction would just be to write down the equation of the reaction and this is going to give us the reaction; [tex]2Mg(s) + O_{2} (g) ---- > 2MgO[/tex].

In this case we know that;

Number of moles of the magnesium = 6g/24 g/mol

= 0.25 moles

Now we know that;

If 2 moles of the magnesium reacts with 1 mole of the oxygen then

0.25 moles of the magnesium would react with 0.25 * 1 /2

= 0.125 moles

Volume of oxygen that is consumed is; 0.125 moles * 22.4 L
=2.8 L

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How is density calculated given mass and volume?
A.Mass divided by volume
B.Mass multiplied by volume
C.Sum of volume and mass
D.Difference of volume
and mass

Answers

The answer correct is sum of volume and mass

Calculate the bond energy of the Br-Cl bond, in kJ/mol, using AHº for the reaction (1.6 kJ/mol) and the information in the following table Bond Bond Energy (kJ/mol)
Br - Br 193
CI - CI 243
Br - CI ?

Answers

The bond energy of the Br-Cl bond would be 217.2 KJ/mol.

[tex]Cl_{2}[/tex] + [tex]Br_{2}[/tex]   ----> 2 Br - Cl

Δ H° reaction = (bond of energy of [tex]Cl_{2}[/tex] + bond energy of [tex]Br_{2}[/tex] ) - 2 (bond energy of Br - Cl)

1.6 = 243 + 193 - 2 (B.E of Br - Cl)

Bond energy of Br - Cl = 243 + 193 - 1.6 / 2 = 217.2 KJ/mol

Electrostatic forces between negatively charged electrons and positively charged atomic nuclei produce bonds. The amount of energy required to separate the atoms forming a molecular bond into free atoms is known as bond energy, and it serves as a gauge of the strength of a chemical connection.

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Draw the products of the following reactions, indicating both regiochemistry and stereochemistry when appropriate.
CH3 1. Hg(OAc)
2, H20 2. NaBHA
• Use wedge and hash bonds ONLY when needed to show reaction stereochemistry. • In cases where there is more than one answer, just draw one.

Answers

The product of the reaction is attached.

The reaction provided in the equation is an electrophilic addition reaction. Electrophilic addition refers to a reaction between an electrophile and nucleophile, adding to double or triple bonds. In the given reaction, alkene is converted into neutral alcohol. As an alkene is treated with the reagent (Hg(OAc)₂, NaBH), the product obtained will be alcohol. This type of reaction is called oxymercuration- demercuration reaction.

In the reaction, the addition of water can occur without acidic conditions. In the presence of reagent mercury (II) acetate cyclic mercurinium ion will form, called . Following this, the reagent will reduce, a reaction called demercuration reaction. Together, this is called oxymercuration- demercuration reaction. As Mercury(II) acetate contains empty d- orbitals it will act as an electrophile and as alkene contains a double bond that will act as a nucleophile. They will form cyclic mercurinium ion and Hg-OAC will be released. In the presence of water hydroxide, the ion will attach on most substituted carbon. In the presence of reagent NaBHsubscript4 reduction will occur and carbon– mercury bond will reduce. This reaction will follow Markovnikov’s rule. Hence, the product of the reaction is attached.

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How does the theory explain the mass laws.

Answers

Answer:

Atoms always have the same characteristic mass and cannot be created or destroyed.

Explanation:

Dalton's atomic theory was the very first complete attempt to describe all matter in terms of atoms and their properties. He based his theory on the law of conservation of mass and the law of constant composition.

The first part of the theory states that all matter is made of atoms, which are indivisible. His law which is related to multiple proportions , is part of the basis for modern atomic theory. He has given the following ideas for conservation of mass:

a. All atoms of a given element are identical.

b. The atoms of different elements vary in mass and size.

c. Atoms are indestructible.

I hope this helped

Where are electrons released in an electromechanical cell?
a. the anode
b. the cathode
c. the entire cell
d. the salt bridge

Answers

The Anode is the negative or reducing electrode that releases electrons to the external circuit and oxidizes during and electrochemical reaction.

Answer: Anode

Explanation:

Electrons flow from the anode to the cathode.

Are all anions non metals

Answers

Explanation ; first, each element that forms Cations is a metal, except for one ( hydrogen), while each element that forms anions is a nonmetal. This is actually one of the chemical properties of metals and nonmetals: metals tend to form cations , while non tend to form anions.

Rank the labeled protons (Ha-Hd) in order of increasing acidity starting with the least acidic.
Select one:
a. Hbb. Hdc. Hbd. Ha

Answers

The order of acidity of the protons that is correct is option B.

What makes the hydrogen acidic?

We must look into the reason  for the acidity of the hydrogen atoms if we want to get the real answer to the question that we have here. We have to note that the hydrogen atom that is closest to the place where there is an electron withdrawing group would be most acidic.

This implies that the hydrogen atom that is close to the highly electron withdrawing carboxyl group would be quite more acidic that an alkane hydrogen.

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