Find the odd number less than 100, that is divisible by 7, and when divided by 10 has a remainder of 3.

Answer:

x=-1, x=3

Step-by-step explanation:

find the x intercepts

(x+1)(x-3)=0

x=-1

x=3

Answer:

3

Step-by-step explanation:

6x (horizontal totals) + 12 x(vertical totals) = 54

18x = 54

x = 3

HOPE THIS HELPS!!!

Answer:

6 divided by 3 would come first

Step-by-step explanation:

follow pemdas which stands for parenthesis, exponents, multiplication, division, adadditiaddition, then subtraction

Answer:

1km please brain list me pls

Answer:

Using Pythagorean theorem a2 + b2 = c2 15002 + 20002 = C2; c is 2,500 feet

Answer:

Step-by-step explanation:

1: multiply lxh which is 3x8 you should get 24 then you multiply that by 5.

2: Then you should get 120 then you multiply that by 6 because it has 6 sides and you have your answer.

THE ANSWER IS= 720yd 3

Answer:

3 weeks

Step-by-step explanation:

25+1.75=26.75

Saira can only withdraw up to $80.25

26.75 x 3 = 80.25

Answer:

All you do is 157/67

Step-by-step explanation:

Rounded down

157/67 is 2.34 sections

Answer:

so is volume length times width

Answer:

129

Step-by-step explanation:

you have to take 51 and subtract it from 180.

Answer:

-6

Step-by-step explanation:

if you put all on a number line negitive six is the furthest to the left. meaning its the lowest number

Answer:

Coordinates on a graph cannot be larger or smaller than each other. They are just locations. If you are asking which number has the lowest value, it would be the negative with the highest number. In this case, -6 is the smallest value.

Step-by-step explanation:

Answer:

something missing.............

Answer:

this the answer

Answer:

x = 7

Step-by-step explanation:

The 2 right triangles are similar by the AA postulate, then the ratios of corresponding sides are in proportion, that is

[tex]\frac{x}{4}[/tex] = [tex]\frac{3.5}{2}[/tex] ( cross- multiply )

2x = 14 ( divide both sides by 2 )

x = 7

Will recommend to see attached picture as name of angles are based on it.

[tex] \\ [/tex]

We can only find value of x if both triangles i.e triangle DOC and triangle AOB are similar.

[tex] \\ [/tex]

[tex]\sf \underline{In \: \triangle \: DOC \: and \: \triangle\:AOB: }[/tex]

[tex] \\ [/tex]

[tex] \sf1. \angle DOC = \angle AOB[/tex]

Reason :-

VOC (Vertically opposite angle)

How to recognize either it is VOC (Vertically opposite angle) or not?

So it's basically very easy to recognize, when ever u see lines intersect each other just like a multiply sign ( × ) either horizontal or parallel they are considered as VOC ans are always equal.

[tex] \\ [/tex]

[tex] \sf2. \angle CDO = \angle BAO[/tex]

Reason:-

Both are of 90°.

So how we recognized that these both angles were in 90°?

When ever you see that angle is marked in square ( □ ) like shape instead of curve shape then it means the angle is 90°.

[tex] \\ [/tex]

[tex]\sf\triangle \: DOC\simeq \triangle\:AOB: [/tex]

By :- AA (angle angle)

[tex] \\ \\ [/tex]

Now Finally Let's find value of x.

[tex] \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{DC}{AB} = \dfrac{OC}{OB} = \dfrac{OD}{OA} [/tex]

Reason :- Corresponding sides of similar triangle are in proportion.

[tex] \\ [/tex]

So:-

[tex] \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{DC}{AB} = \dfrac{OC}{OB}[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{2}{3.5} = \dfrac{4}{x}[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{3.5}{2} = \dfrac{x}{4}[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{35}{2 \times 10} = \dfrac{x}{4}[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{ \cancel{35}}{2 \times \cancel{10}} = \dfrac{x}{4}[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{7}{2 \times 2} = \dfrac{x}{4}[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{4 \times 7}{2 \times 2} = x[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{ \cancel4 \times 7}{\cancel2 \times 2} = x[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{ 2 \times 7}{1 \times 2} = x[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{\cancel 2 \times 7}{1 \times \cancel2} = x[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{1 \times 7}{1 \times 1} = x[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf\dfrac{7}{1 } = x[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf7= x[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \bf x = 7[/tex]

[tex] \\ \\ [/tex]

.°. length of x is equal to 7(unit)

Answer:

R72. 80

Step-by-step explanation:

1KG = R36, 40

2KG = R36.40 X 2

= R72. 80

Answer:

Step-by-step explanation:

Discount % = 10 %

Discount price = 10% of marked price = 10% of x

Marked price - discount =SP

[tex]x-\dfrac{10}{100}x=180\\\\\\\dfrac{100}{100}x-\dfrac{10}{100}x=180\\\\\\\dfrac{90}{100}x=180\\\\\\x=180*\dfrac{100}{90}=2*100\\\\\\[/tex]

x= 200

Marked price = 200

Answer:

x² - 12x + 27

Step-by-step explanation:

(f + g)(x)

= f(x) + g(x)

= x² - 13x + 36 + x - 9 ← collect like terms

= x² - 12x + 27 ← in standard form

[tex]17.00906 < 17.00936 < 17.00963 < 17.09360 < 17.09361[/tex]

Hope that helps!

Answer:

Today was rough? I'm bad at jokes

Answer:

The percentage of the adult racehorses weigh more than 570 kg is 1.7% ⇒ 1st answer Step-by-step explanation: Adult racehorse weights are normally distributed, with a mean of 500 kg and a standard deviation of 33 kg We need to find the percentage of the adult racehorses weigh more than 570 kg To solve the problem do these steps 1. Find z-score 2. Use z-score to find the corresponding area which represented P(x) 3. Change P(x) to percentage ∵ z = (x - μ)/σ ∵ The mean μ = 500 kg ∵ The standard deviation σ = 33 kg ∵ x = 570 kg Substitute these values in the rule above ∴ z = Let us use the normal distribution table to find the corresponding area ∵ The area corresponding to z-score of 2.12 is 0.98300 ∵ We need x > 570 , then we need the area to the right of the z-score ∴ P(x > 570) = 1 - 0.98300 = 0.017 Change it to percentage by multiplying the answer by 100% ∴ The percentage of x > 570 = 0.017 × 100% = 1.7% The percentage of the adult racehorses weigh more than 570 kg is 1.7%

Step-by-step explanation:

The percentage of the adult racehorses weigh more than 570 kg is 1.7% ⇒ 1st answer Step-by-step explanation: Adult racehorse weights are normally distributed, with a mean of 500 kg and a standard deviation of 33 kg We need to find the percentage of the adult racehorses weigh more than 570 kg To solve the problem do these steps 1. Find z-score 2. Use z-score to find the corresponding area which represented P(x) 3. Change P(x) to percentage ∵ z = (x - μ)/σ ∵ The mean μ = 500 kg ∵ The standard deviation σ = 33 kg ∵ x = 570 kg Substitute these values in the rule above ∴ z = Let us use the normal distribution table to find the corresponding area ∵ The area corresponding to z-score of 2.12 is 0.98300 ∵ We need x > 570 , then we need the area to the right of the z-score ∴ P(x > 570) = 1 - 0.98300 = 0.017 Change it to percentage by multiplying the answer by 100% ∴ The percentage of x > 570 = 0.017 × 100% = 1.7% The percentage of the adult racehorses weigh more than 570 kg is 1.7%

Answer:

yes it is correct good work

Answer:

Step-by-step explanation:

The polynomial is simplified by combining like terms. Like terms are identified more easily if the variables in each term are written in the same order. We usually like to use alphabetical order. Two of the like terms have opposite coefficients, so they cancel. The result is ...

  (3 1/2 -2 1/2)xy² +(-2 4/5 +2 4/5)x²y

  = xy² . . . . simplified expression

__

For x = 1, y = -2, the value of the expression is ...

  (1)(-2)² = 4

==================================================

Explanation:

We can rewrite the exponent 9.969 as 9 + 0.9 + 0.06 + 0.009

Then convert each decimal to a fraction

Your teacher is choosing not to reduce any of these fractions.

Then you'll use this rule [tex]a^{b+c} = a^b*a^c[/tex] to break up the exponent into the pieces mentioned.

So,

[tex]5^{9.969} = 5^{9 + 0.9+0.06+0.009}\\\\5^{9.969} = 5^{9 + 9/10+6/100+9/1000}\\\\5^{9.969} = 5^{9}\cdot 5^{9/10}\cdot 5^{6/100}\cdot 5^{9/1000}\\\\[/tex]

Step-by-step explanation:

A quadratic equation can be constructed from their roots,

[tex](x - p)(x - q)[/tex]

where p and q are the roots.

Here the roots are

[tex]2 - \sqrt{3} [/tex]

and

[tex]2 + \sqrt{3} [/tex]

So we have

[tex](x - (2 - \sqrt{3} ))(x - (2 + \sqrt{3} ))[/tex]

[tex] {x}^{2} - 2x - x \sqrt{3} - 2x + x \sqrt{3} + 4 - 3[/tex]

[tex] {x}^{2} - 4x + 1 = 0[/tex]

So our answer is x^2

[tex] {x}^{2} - 4x + 1 = 0[/tex]

Answer:

Step-by-step explanation:

The two rules are :-

15 - 10(n - 1)

25 - 10n

Answer:

Explanation:

sequence: 15, 5, -5, -15, -25

solve:

1st rule 25 - 10n:

25 - 10(0) = 15

25 - 10(2) = 5

25 - 10(3) = -5

25 - 10(4) = -15

25 - 10(5) = -25

second rule using 15 - 10(n - 1):

15 - 10(1 - 1) = 15

15 - 10(2 - 1) = 5

15 - 10(3 - 1) = -5

15 - 10(4 - 1) = -15

15 - 10(5 - 1) = -25

Answer:

18

Step-by-step explanation:

you take away -9 from both sides

27-9=18

Answer:

9

Step-by-step explanation:

so first you send +9 to the right , it will become -9

2p + 9 = 27

2p = 27 - 9

you substract -9 from 27

2p = 18

next step you send 2 to the other side... since it multiply on the left side...it will become divide on the right side, so that p can be alone

2×p = 18

p = 18 ÷2

p = 9

i rewrote it without explication

full step is : 2p = 27 - 9

2p = 18

p = 18 ÷ 2

p = 9

Step-by-step explanation:

we start with the point-slope form

y - y1 = a(x - x1)

where "a" is the slope, (x1, y1) is a point on the line, and then we simplify that equation giving us the slope-intercept form

y = ax + b

so,

y - -9 = -9(x - 1)

y + 9 = -9(x - 1)

and now simplifying this

y + 9 = -9x + 9

y = -9x