The equation of the line follows the following general structure:
[tex]y=mx+b[/tex]Where m is the slope of the line and b is the y intercept.
Find the corresponding values in the given formula, this way:
In the given equation, m has a value of -1/2, it means the slope is -1/2.
An 18-foot ribbon is attached to the top of a pole and is located on the ground 10 feet awayfrom the base of the pole. Suppose Mateo has a second ribbon that will be located anadditional 23 feet away past that point.Find the measure of the angle formed by Mateo's ribbon and the ground. Round the angle tothe nearest tenth of a degree.a10 ft18 ft23 ft8
To begin we need to find the value of a
We apply the Pythagorean theorem
[tex]\begin{gathered} 18^2=a^2+10^2 \\ a^2=18^2-10^2 \\ a=\sqrt{18^2-10^2} \\ a=4\sqrt{14} \end{gathered}[/tex]Now we find theta
Here we use the tangent that is the oppositive side over the adjacent side
[tex]\begin{gathered} \tan\theta=\frac{4\sqrt{14}}{33} \\ \\ \theta=\tan^{-1}(\frac{414}{33})=24.39\degree \end{gathered}[/tex]Explain when you can cancel a number that is in both the numerator and denominator and when you cannot cancel out numbers that appear in both the numerator and the denominator.
Let me write here an example of a common number/term in both numerator and denominator that we can cancel.
[tex]\frac{4xy}{4}=xy[/tex]In the above example, we are able to cancel out the common number 4 because they are stand alone numbers. We can divide 4 by 4 and that is 1. Hence, the answer is just xy.
Another example:
[tex]\frac{(x+2)(x-1)}{(x+2)(2x-1)}=\frac{(x-1)}{(2x-1)}[/tex]In the above example, we are able to cancel out (x + 2) because this term is a common factor to both numerator and denominator.
In the example, we can also see that -1 is a common number however, we cannot cancel it out because the number -1 is not a standalone factor. It is paired with other number/variable. (x - 1) and (2x - 1) are both factors but are not the same, that is why, we are not able to cancel that.
Another example:
[tex]\frac{(x+2)+(x-1)}{(x+2)+(2x-1)}=\frac{(x+2)+(x-1)}{(x+2)+(2x-1)}[/tex]As we can see above, (x + 2) is a common term however, we cannot cancel it. We can only cancel common terms if they are common factors of both numerator and denominator. (Notice the plus sign in the middle. )
The term (x + 2) above is not a factor of the numerator and denominator, hence, we cannot cancel it.
Which of the following are solutions to the following solutions to the following solutions?
We have to find the solutions to the equation:
[tex]|x+4|=8[/tex]The absolute value function is in fact a piecewise function, so it may have two solutions.
We consider for the first solution that the argument inside the absolute function is positive, that is x + 4 > 0. Then, we will have:
[tex]\begin{gathered} x+4=8 \\ x=8-4 \\ x=4 \end{gathered}[/tex]Now, we consider that the the argument is negative and is made positive by the absolute value function (it will shift the sign, which can be represented by a multiplication by -1). This means that x + 4 < 0, and the solution will be:
[tex]\begin{gathered} -(x+4)=8 \\ -x-4=8 \\ -x=8+4 \\ -x=12 \\ x=-12 \end{gathered}[/tex]We can see it in a graph as:
Answer: the solutions are x = 4 and x = -12.
2. Axely says that 8is equivalent to –.125repeating. Without solving, evaluate her claim in thespace below.
we are asked about the claim that the fraction -12 / 8 is equivalent to the decimal expression -0.125... (repeating)
Without evaluating the expression, we can say that the clain is INCORRECT, since just the quotient 12/8 should give a number LARGER than "1" (one) in magnitude (the number 12 is larger than the number 8 in the denominator. We can also say that such division cannot ever give a repeating decimal at infinity, since divisions of integer numbers by 8 or 4 never render a repeating decimal, but a finite number of decimals.
428 x 35 using long multiplication .
Answer:
14980
Step-by-step explanation:
4 2 8
x
3 5
-----------
2 1 4 0 ---> 428 x 5
1 2 8 4 ---> 428 x 3 but since 3 is in the 10s place we shift by 1
--------------- to the left. You can think of that 1248 as 12480
1 4 9 8 0 --> add the two rows
Hope that helps. I tried my best to explain :)
Answer:
4 2 8
× 3 5
+ 2 1 4 0
+ 1 2 8 4
= 1 4 9 8 0
Step-by-step explanation:
Suppose that an individual has a body fat percentage of 19.2% and weighs 153 pounds. How many pounds of his weight is made up of fat? Round your answer to the nearest tenth.
Step 1
The given body fat percentage = 19.2%
The given body weight = 153 pounds
Required: To find how many pounds of his weight is made up of fat.
Step 2
Find out what 19.2% of his weight is
[tex]\begin{gathered} \frac{100}{19.2}=\frac{153}{x} \\ \text{where x represents the value of 19.2\% of his weight in pounds} \end{gathered}[/tex][tex]\begin{gathered} 100x=\text{ 153}\times19.2 \\ \frac{100x}{100}=\frac{2937.6}{100} \\ x=29.376\text{ pounds} \\ x\approx\text{ 29.4 pounds to the nearest tenth} \end{gathered}[/tex]Hence, the pounds of his weight made up of fat to the nearest tenth = 29.4 pounds
There is a bag filled with 5 blue and 4 red marbles.
A marble is taken at random from the bag, the colour is noted and then it is replaced.
Another marble is taken at random.
What is the probability of getting at least 1 blue?
The probability of getting exactly 1 blue marble from a bag which is filled with 5 blue and 4 red marbles is 40/81.
What is probability?Probability of an event is the ratio of number of favorable outcome to the total number of outcome of that event.
A bag is filled with 5 blue and 4 red marbles.
The total number of marble in the bag are,
5+4=9
One marble is taken at random from the bag, the color is noted and then it is replaced. The probability of getting blue marble is,
P(B)=5/9
probability of getting red marble is,
P(R)=4/9
The Probability of getting red marble in first pick and probability of getting blue marble in second pick
P1=5/9×4/9=20/81
The Probability of getting blue marble in first pick and probability of getting red marble in second pick is,
p2=4/9×5/9=20/81
The exactly 1 blue is taken out, when first marble is red and second is blue or the first one is blue and second one is red. Thus, the probability of getting exactly 1 blue is,
P=p1+p2
=20/81+20/81
40/81
Hence the probability of getting exactly 1 blue marble from a bag which is filled with 5 blue and 4 red marbles is 40/81.
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Consider the following algebraic expression:7s - 7Step 1 of 2: Identify the first term of the algebraic expression. Indicate whether the term is a variable term or a constant term. For avariable term, identify the variable and the coefficient of the term.
Given the algebraic expression below
[tex]7s-7[/tex]The first term of the algebraic expression is
[tex]7s[/tex]The first term "7s" is a variable term.
The variable of the first term is "s"
The coefficient of the variable term is 7
You are choosing between two health clubs. Club A offers membership for a fee
of $20 plus a monthly fee of $25. Club B offers membership for a fee of $25
plus a monthly fee of $24. After how many months will the total cost of each
health club be the same? What will be the total cost for each club?
Let:
x = Number of months
y1 = Total cost for Club A
y2 = Total cost for Club B
a = Fee of Club A per month
b = Fee of Club B per month
c = Initial fee of Club A
d = Initial fee of Club B
so:
[tex]\begin{gathered} y1=ax+c \\ y1=25x+20 \\ -------- \\ y2=bx+d \\ y2=24x+25 \end{gathered}[/tex]So, the total cost will be the same for:
[tex]\begin{gathered} y1=y2 \\ 25x+20=24x+25 \\ solve_{\text{ }}for_{\text{ }}x\colon \\ 25x-24x=25-20 \\ x=5 \end{gathered}[/tex]The cost will be the same for the month number 5. And the total cost will be:
[tex]\begin{gathered} y1(5)=25(5)+20=145 \\ y2(5)=24(5)+25=145 \end{gathered}[/tex]$145
Using Calculus with Data in a tablePlease let me know if you have any questions regarding the material, thanks!
ANSWER
g'(0.1) = 4
EXPLANATION
As stated, g(x) is a composition of two functions: f(x) and 2x. To find its derivative, we have to use the chain rule,
[tex]g^{\prime}(x)=f^{\prime}(x)\cdot(2x)^{\prime}=f^{\prime}(2x)\cdot2[/tex]So, the derivative of g(x) = f(2x) is twice the derivative of f(x) and, therefore,
[tex]g^{\prime}(0.1)=f^{\prime}(2\cdot0.1)\cdot2=f^{\prime}(0.2)\cdot2=2\cdot2=4[/tex]Hence, g'(0.1) = 4.
Use the Binomial Theorem to expand the expression.(x +6)^3
ok
[tex]\begin{gathered} (x+6)^3=^{}x^3+3(x)^2(6)+3(x)(6)^2+6^3 \\ \text{ = x}^3+18x^2\text{ + 3(36)x + 216} \\ \text{ = x}^3+18x^2\text{ + 108x + 216} \end{gathered}[/tex][tex]\begin{gathered} (a+b)^3\text{ } \\ first\text{ term = a} \\ \text{second term = b} \\ \text{theorem } \\ (a+b)^3=a^3+3a^2b+3ab^2+b^3 \end{gathered}[/tex]that is the rule
just identify a and b in your problem
a = x
b = 6
Substitute in the theorem, and simplify
Determine if the side lengths could form a triangle. Use an inequality to prove the answer. Inequality must be used.
The side lengths given form a triangle
Explanation:Let the lengths of the sides of the triangle be "a", "b" and "c"
For the length to form sides of a triangle, the sum of any two sides of the triangle must be greater than the third as shown:
[tex]\begin{gathered} a+b>c \\ a+c>b \\ b+c>a \end{gathered}[/tex]Given the sides of the triangle as 34km, 27km, and 58km
Let a = 34km, b = 27km and c = 58km
Substituting these values in the expression above to check if it is true:
[tex]\begin{gathered} 34+27=61>58 \\ 34+58=92>27 \\ 27+58=85>34 \end{gathered}[/tex]Since the inequality expression supports the theorem above, hence the side lengths given form a triangle
hannah paid 15.79 for a dress that was originally marked 24.99 what js the percent of discount
The percentage of discount is 37%
Here, we want to calculate the percentage of discount
The first thing we need to do here is to calculate the discount amount
Mathematically, we have this as;
[tex]24.99-15.79\text{ = 9.2}[/tex]Now, we find the percentage of 24.99 is this discount
We have this as;
[tex]\frac{9.2}{24.99}\text{ }\times100\text{ \% = 36.8\%}[/tex]The percentage of discount is approximately 37%
Solve for xX/250 = 3/500
Answer:
x = 3/2 = 1.5
Explanation:
The initial equation is:
[tex]\frac{x}{250}=\frac{3}{500}[/tex]To solve the equation, we need to multiply both sides by 250 as:
[tex]\begin{gathered} \frac{x}{250}\cdot250=\frac{3}{500}\cdot250 \\ x=\frac{3\cdot250}{500} \\ x=\frac{750}{500} \end{gathered}[/tex]This fraction can be simplified as:
[tex]x=\frac{750}{500}=\frac{750\div250}{750\div250}=\frac{3}{2}=1.5[/tex]Therefore, the value of x is 3/2 as a fraction or it is 1.5 as a decimal.
Garret’s coin bank contains500 nickels dimes and quarters. He has the same number of nickels as dimes and the total value of the coins is &72.50. How many quarters does he have?
Since he has the same number of nickels as dimes.
x = nickels
x = dimes
500 - 2x = quarters
the total value of the coins is $72.50
5x + 10x + 25(500-2x) = 7250
Solve for x
15x + 25(500) + 25(-2x) = 7250
15x + 12,500 - 50x = 7250
Combine like terms
15x - 50x = 7250 - 12500
-35x = -5250
Divide both sides of the equation by -35
-35x/-35 = -5250/-35
x = 150
150 quarters
consider the parent function f(x)=x^2. a. graph y=f(x). b. write an equation for f(1/2x). Then sketch a graph of y=f(1/2x) and describe the transformation. c.write an equation for f(3x). Then sketch a graph of y=f(3x) and describe the transformation.
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
f(x)=x²
f(1/2x) = ?
graph of y=f(1/2x) = ?
Step 02:
b. f(1/2x)
x ===> 1/2x
[tex]f\text{ (1/2 x) = (}\frac{1}{2}x)^2=\frac{1}{4}x^2[/tex]Step 03:
c. Graph:
We give values to x, and we obtain the values of y.
f(x) = 1/4 x²
e.g.
if x = 4
y = 1/4 (4)² = 1/4 * 16 = 4
That is the solution for b. and c.
find the sum.(7-b) + (3) +2 =
please help me it’s do tomorrow 1) Discrete or Cont?
Domain
Range
Function?
The correct options regarding each function are as follows:
1.
Continuous.Domain: {-3, 2}.Range: (-∞,∞).Function: No.2.
Continuous.Domain: (-5,5]Range: [-2,2]Function: Yes.3.
Continuous.Domain: (-∞,∞).Range: (-∞,∞).Function: Yes.4.
Continuous.Domain: (-∞,∞).Range: {3}Function: Yes.5.
Discrete.Domain: {-5, -4, 1, 2, 5}.Range: {-5,0,1,4}.Function: Yes.6.
Continuous.Domain: (-∞,4].Range: [0,∞).Function: Yes.Continuous and discreteThe graph is classified as continuous or discrete as follows:
Continuous: solid line.Discrete: set of points.Hence only function 5 is discrete, the other are all continuous.
Domain and range:In the graph of a function, the domain and the range are given as follows:
Domain: values of x -> set of input values.Range: values of y -> set of output values.Hence the domain and the range for the functions in this problem are given as follows:
1.
Domain: {-3, 2}. -> two vertical lines, one at x = -3 and the other at x = 2.Range: (-∞,∞).2.
Domain: (-5,5] -> open interval due to the open circle at x = -5.Range: [-2,2]3.
Domain: (-∞,∞).Range: (-∞,∞).4.
Domain: (-∞,∞).Range: {3} -> constant function at y = 3.5.
Domain: {-5, -4, 1, 2, 5}. -> discrete function, hence both the domain and the range contain only those exact values, not an interval.Range: {-5,0,1,4}.6.
Domain: (-∞,4].Range: [0,∞).When does a graph represent a function?A graph represents a function if it has no vertically aligned points, that is, each input is mapped to only one output.
Hence only item 1 is not a function, as the two inputs x = -3 and x = 2 are mapped to multiple outputs.
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Mark the corresponding with a check to in the boxplease!
The whole numbers are defined as the positive integers including zero. The whole number does not contain any decimal or fractional part.
An integer is a number with no decimal or fractional part, from the set of negative and positive numbers, including zero.
A rational number is a number that is of the form p/q where p and q are integers and q is not equal to 0.
An irrational number is a type of real number which cannot be represented as a simple fraction.
Real numbers include rational numbers like positive and negative integers, fractions, and irrational numbers. In other words, any number that we can think of, except complex numbers, is a real number.
Therefore,
I didn't really get it when my teacher tried to explain this
The formula for determining the volume of a cylinder is expressed as
V = pi * r^2h
Where
V represents volume of cylinder
pi is a constant whose value is 3.142
r represents radius of cylinder
h represents height of cylinder
From the information given,
h = 10
r = 3
V = 3.142 * 3^2 * 10
V = 282.78 in^3
The closest measurement is option A
What property of equity is this identify the property : if B is between O and K, BK=OK
Segment addition
The sum of the lenghts of the segments OB and Bk will give the total lenght OK
An isosceles right triangle has 6 cm legs . Find the length of the hypotenuse
Step-by-step explanation:
we have a right-angled triangle.
so, we can use Pythagoras
c² = a² + b²
c is the Hypotenuse, a and b are the legs.
in our case
c² = 6² + 6² = 36 + 36 = 72
c = Hypotenuse = sqrt(72) = 8.485281374... cm
Answer:
hypotenuse = √72 (or 8.49)
Step-by-step explanation:
An isosceles right triangle has 6 cm legs . Find the length of the hypotenuse
isosceles right triangle = 2 equal side and 2 equal angleswe use the Pythagorean theorem (In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides)hypotenuse² = 6² + 6²
hypotenuse² = 36 + 36
hypotenuse² = 72
hypotenuse = √72 (or 8.49)
The data in the table show how long (in minutes, t) it takes several commuters to drive to work. Find the correlation coefficient and the equation of the best fit for the data. Treat the commute distance d as the independent variable.
Given the set of data
sort
Commute data (x)
24,25,27,30, 35,35,46,50,52
Commute distance (y)
20,20,29,20,34,39,29,34,50
The line of best fit is given by
with
[tex]R^2=0.5592[/tex][tex]R=\sqrt{0.5592}[/tex][tex]R=0.747[/tex]R= 0.75
with function
[tex]t=0.7+5.5[/tex]Correct answer
option D
Answer: r ≈ 0.75
t ≈ 0.8d + 11.5
Step-by-step explanation:
You have to use a graphing calculator to solve this problem.
This is the correct answer (I just took the test).
452 pointsTo factor x2 + bx + c, the numbers you choose to fill in the empty spots of (x + )(x + ).1mustchoose your answer...to equal c.2Previous34Сл
The Quadratic format is
[tex]\begin{gathered} x^2\text{ + bx + c } \\ \text{The b is gotten by adding the factors } \\ \text{But the c is gotten by multiplying the factors } \end{gathered}[/tex]The answer to the question is that the factors must multiply to form c
A special deck of cards has 4 blue cards, and 4 red cards. The blue cards are numbered 1, 2, 3, and 4. The red cards are numbered 1, 2, 3, and 4. The cards are well shuffled and you randomly draw one card.A = card drawn is blueB = card drawn is odd-numbereda) How many elements are there in the sample space? b) P(A) = c) P(B) =
Answer
• a) 8
,• b) 4/8
,• c) 4/8
Explanation
Given
• Blue cards: 4, {B1, B2, B3, B4}
,• Red cards: 4 {R1, R2, R3, R4}
,• A = card drawn is blue
• B = card drawn is odd-numbered {B1, R1, B3, R3}
Procedure
• a) elements in the sample space
There are: S = {B1, B2, B3, B4, R1, R2, R3, R4}
Thus, the number of elements in the sample space is n(S) = 8.
• b) P(A)
Can be calculated as follows:
[tex]P(A)=\frac{n(A)}{n(S)}=\frac{4}{8}[/tex]• c) P(B)
Can be calculated as follows:
[tex]P(B)=\frac{n(B)}{n(S)}=\frac{4}{8}[/tex]Need answer if you could show work would be nice
In the Polynomial function f(x)= [tex]2x^{3} -11x^{2} -12x+36 =0 then[/tex]
So all the zeros of f(x) algebraically
[tex]\mathrm{f}(\mathrm{x}) \ are\ \mathrm{x}=-2, \mathrm{x}=\frac{3}{2}, \mathrm{x}=6$[/tex].
Step: 1
Given[tex]$f(x)=2 x^3-11 x^2-12 x+36$and $f(6)=0 \Rightarrow(x-6)$ is factor of $f(x)$now $f(x)=2 x^3-11 x^2-12 x+36$$$[/tex]
[tex]\begin{aligned}&\Rightarrow \mathrm{f}(\mathrm{x})=\left(2 \mathrm{x}^2-12 \mathrm{x}^2\right)+\left(\mathrm{x}^2-\right. \\&\Rightarrow \mathrm{f}(\mathrm{x})=2 \mathrm{x}^2(\mathrm{x}-6)+(\mathrm{x}-6)^2 \\&\Rightarrow \mathrm{f}(\mathrm{x})=(\mathrm{x}-6)\left(2 \mathrm{x}^2+\mathrm{x}-6\right)\end{aligned}$$[/tex]
Step: 2
Now consider [tex]$2 x^2+x-6=2 x^2+4 x-3 x-6$$$\begin{aligned}&\Rightarrow 2 x(x+2)-3(x+2) \\&\Rightarrow 2 x^2+x-6=(2 x-3)(x+2)\end{aligned}$$[/tex]
[tex]$5 \circ f(x)=(x-6)\left(2 x^2+x-6\right)$$$\Rightarrow \mathrm{f}(\mathrm{x})=(x-6)(2 \mathrm{x}-3)(\mathrm{x}+2)$$[/tex]
Step: 3
so for finding zeros of
[tex]$f(x) \rightarrow f(x)=0$$$\Rightarrow(x-6)(2 x-3)(x+2)=0$$$$\Rightarrow(x-6)=0 ;(2 x-3)=0 ;(x+2)=0$$[/tex]
[tex]$$\Rightarrow x=6, x=\frac{3}{2} ; x=-2$$[/tex]
Explanation: Please refer to solution in this step.
Answer:
So required zeros of
[tex]\mathrm{f}(\mathrm{x}) \ are\ \mathrm{x}=-2, \mathrm{x}=\frac{3}{2}, \mathrm{x}=6$[/tex]
What is polynomial function?A polynomial consists of two words, poly and nominal. "Poly" means many and "nomial" means term, and so when combined, polynomials can be said to be "algebraic expressions with many terms." Let's go ahead and start by defining polynomial functions and their types.
The polynomial function in standard form is:
f(x) = [tex]a_{n}x^{n} +a_{n-1} x^{n-1} +.....a_{2} x^{2} +a_{1} x+a0[/tex]
This algebraic expression is called a polynomial function of the variable x. The name of a polynomial is determined by the number of terms it contains.
The three most common polynomials we usually encounter are
monomial binomial trinomialTo learn more about polynomial function, refer;
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Solve for 5x - 3y = -45the equations beside it are the answer choices.
You have the following equation:
5x - 3y = -45
In order to solve the previous equation for y, you proceed as follow:
5x - 3y = -45 subtract 5x both sides
- 3y = -45 - 5x multiply by -1 both sides
(-1)(-3y) = (-1)(-45 - 5x)
3y = 45 + 5x divide by 3 both sides
y = 45/3 + 5/3 x order the right side
y = 5/3 x + 15
Hence, the solution for y is y = 5/3 x + 15
Determine the function that represents the following tables. Time (seconds) 1, 4, 7, 10, 13, the Distance (miles) 5 20 35 50 65.
the function is d= f(t)
when t1= 1 , d1= 5
when t2= 4, d2= 20
[tex]\text{rate od change = }\frac{d_2-d_1}{t_2-t_1}[/tex][tex]\text{rate of change = }\frac{20-5}{4-1}=\text{ }\frac{15}{3}=\text{ 5}[/tex][tex]\begin{gathered} ifd_{2\text{ }}=20,d_{3\text{ }}=35,t_{2\text{ }}=4,t_{3\text{ }}=7 \\ \text{rate of change = }\frac{d_3-d_2}{t_3-t_2}\text{ = }\frac{35-20}{7-4}=\text{ }\frac{15}{3}=\text{ 5} \end{gathered}[/tex]Thus if d is a function of t
and the rate of change is constant
then d = 5t is the function
passes through (1,3) and parallel to y=-x
The equation of a line parallel to y=-x and passes through (1,3) is x+y=4
What is the relationship between coordinates and the equation of a line?The coordinates of a line pass through the equation of a line.
What is the relationship between two parallel lines?Two parallel lines make the same angle with respect to the x-axis ie. make the same slope.
We have been given that the line is parallel to y=-x or x+y=0
Thus, they will be having the same slope which is -1.
Since, in the equation Ax+By+C=0, the slope is equal to -A/B
So putting the values in the equation y=mx+c where m is the slope and c is the constant
y=-x+c
Now we know that the equation passes through (1,3)
So, putting values 1=-3+c which gives c=4
Therefore, the equation of the line is y=-x+4 or x+y=4.
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Eddie brought his DVD set to the secondhand store to sell he was paid for all three DVDs in the set before he left Eddie used $15.70 of his earnings to purchase a pair of headphones had $2.30 remaining which equation can you use to find the amount of money Eddie received for each DVD
15.70(d-3)=2.30
3d-15.70=2.30
15.70d-3=2.30
3(d-15.70)=2.30
Answer:
3d - 15.70 = 2.30
Step-by-step explanation:
We don't know the cost of one DVD, so let's use d to represent this unknown variable. Eddie sold 3 DVDs, so 3 multiplied by d equals his total earnings.
Eddie then used $15.70 of his earnings to buy a pair of headphones. We can represent this by subtracting 15.70 from the total earnings (3d).
After buying/subtracting the price of the headphones from his total earnings, Eddie had $2.30 left over, which can be represented by making 3d - 15.70 equal 2.30.
So, the final equation turns out to be: 3d - 25.70 = 2.30
:)