The slope of the line passing through the coordinates (9, 9) and (6, 7) is 2/3.
What is the slope of the line with the given coordinates?Slope is simply expressed as change in y over the change in x.
Slope m = ( y₂ - y₁ )/( x₂ - x₁ )
Given the data in the question;
Point 1( 9, 9 )
x₁ = 9y₁ = 9Point 2( 6, 7 )
x₂ = 6y₂ = 7To determine the slope, plug the given x and y values into the slope formula and simplify.
Slope m = ( y₂ - y₁ )/( x₂ - x₁ )
Slope m = ( 7 - 9 )/( 6 - 9 )
Slope m = ( -2 )/( -3 )
Slope m = ( 2 )/( 3 )
Slope m = 2/3
Therefore, the slope of the line is 2/3.
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The slope of the required line is 2/3 which passes through points (9, 9) and (6, 7).
What is the slope of the line?The slope is simply expressed as an inclination of the line in the coordinate system.
Slope m = (y₂ - y₁) / (x₂ - x₁)
Given that the line that passes through two points (9, 9) and (6, 7)
Let x₁ = 9, y₁ = 9 and x₂ = 6, y₂ = 7
The slope of the required line is
m = (y₂ - y₁ )/( x₂ - x₁ )
Substitute the values in the formula to get the slope of the line,
m = ( 7 - 9 )/( 6 - 9 )
m = ( -2 )/( -3 )
m = ( 2 )/( 3 )
m = 2/3
Therefore, the slope of the line would be 2/3.
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Write the equation below in standard form and then answer the following questions. If a value is a non-integer type your answer as a decimal rounded to the hundredths place. 4x^2+24x+25y^2+200y+336=0The center of the ellipse is (h,k). h= Answer and k= AnswerThe value for a is Answer . The value for b is Answer .The foci with the positive x value is the point ( Answer, Answer)The foci with the negative x value is the point ( Answer, Answer)
Given:
[tex]4x^2+24x+25y^2+200y+336=0[/tex]Aim:
We need to convert the given equation into the standard form of the ellipse equation.
Explanation:
Consider the standard form of the ellipse equation.
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]Consider the given equation.
[tex]4x^2+24x+25y^2+200y+336=0[/tex][tex]Use\text{ }336=36+400-100.[/tex][tex]4x^2+24x+25y^2+200y+36+400-100=0[/tex][tex]4x^2+24x+36+25y^2+200y+400-100=0[/tex]Take out the common terms.
[tex]4(x^2+6x+9)+25(y^2+8y+16)-100=0[/tex]Add 100 on both sides of the equation.
[tex]4(x^2+6x+9)+25(y^2+8y+16)-100+100=0+100[/tex][tex]4(x^2+6x+9)+25(y^2+8y+16)=100[/tex][tex]4(x^2+2\times3x+3^2)+25(y^2+2\times4y+4^2)=100[/tex][tex]\text{Use (a+b)}^2=a^2+2ab+b^2.[/tex][tex]4(x+3)^2+25(y+4)^2=100[/tex]Divide both sides by 100.
[tex]\frac{4\mleft(x+3\mright)^2}{100}+\frac{25\mleft(y+4\mright)^2}{100}=\frac{100}{100}[/tex][tex]\frac{\mleft(x+3\mright)^2}{25}+\frac{\mleft(y+4\mright)^2}{4}=1[/tex][tex]\frac{\mleft(x+3\mright)^2}{5^2}+\frac{\mleft(y+4\mright)^2}{2^2}=1[/tex][tex]\frac{\mleft(x-(-3)\mright)^2}{5^2}+\frac{\mleft(y-(-4)\mright)^2}{2^2}=1[/tex]The standard form of the given equation is
[tex]\frac{\mleft(x-(-3)\mright)^2}{5^2}+\frac{\mleft(y-(-4)\mright)^2}{2^2}=1[/tex]Compare with the general form of the ellipse equation.
We get h=-3, k=-4, a=5 and b=2.
The centre of the ellipse is h= -3 and k = -4.
The value of a is 5.
The value of b is 2.
We need to find the eccentricity of the ellipse.
[tex]e=\sqrt[]{1-\frac{b^2}{a^2}}[/tex]Substitute b=2 and a =5 in the formula.
[tex]e=\sqrt[]{1-\frac{2^2}{5^2}}=\sqrt[]{1-\frac{4}{25}}=\sqrt[]{\frac{25-4}{25}}=\sqrt[]{\frac{21}{25}}=0.9165[/tex][tex]e=0.9165[/tex]The foci of the ellipse are
[tex]((h\pm a)e,0)[/tex]Substitute h =-3, a=5 and e =0.9165 in the formula.
[tex]((-3\pm5)0.9165,0)[/tex]The foci with a positive x value are the point
[tex]((-3+5)0.9165,0)\text{ =}(1.83,0)[/tex]
[tex](1.83,0)[/tex]
The foci with a negative x value are the point
[tex]((-3-5)0.9165,0)\text{ =}(-7.33,0)[/tex][tex](-7.33,0)[/tex]An inspector found 18 defective radios during an inspection. If this is 0.024% of the total number of radios inspected, how many radios were inspected?
Total number of defected radios is 18
Let the total number of defective radios be taken as y
If 0.024% of the total number of radios inspected are defective, i.e 0.024% of y
[tex]\frac{0.024}{100}y=18[/tex]Solve for y, by cross multiplying
[tex]\begin{gathered} \frac{0.024}{100}y=18 \\ 0.024y=18\times100 \\ \text{Divide both sides by 0.024} \\ \frac{0.024y}{0.024}=\frac{1800}{0.024} \\ y=75000 \end{gathered}[/tex]Hence, the number of radios inspected, y, is 75000
Sara’s dogsMorning: 39, 21, 12, 27, 23, 19, 31, 36, 25Afternoon: 15, 51, 8, 16, 43, 34, 27, 11, 8, 39Comparing the morning and afternoon groups Create frequency tables to represent the morning and afternoon dogs as two sets of data. Group the weights into classes that range 10 pounds.
Answer;
Medain for morning is 25
Median for evening is 21.5
Explanation;
Here, we want to create frequency tables for each of the given groups
We start with the morning group
The frequency table for it is as follows;
Now, we proceed to the afternoon group
We have this as follows;
Lastly, we will want to get the median value of both groups
To do this, we need to re-arrange the values in the data set in ascending or descending order
For the purpose of this solution, we shall be using the ascending order mode. Then from here, we pick out the middle value
For the morning group, we have;
12, 19,21, 23,25,27,31,36,39
Since the numbers are 9, the middle number will be the 5th number since it leaves equal spread of values on the left and right
Thus, we have the median value as 25
The afternoon set, we have it as;
8,8,11,15,16,27,34,39,43,51
We proceed to choose the mid 5th values comig from both ends
We have this as;
We have these values as; 16 and 27
We add these and divide by 2
We have this as;
[tex]\frac{16+27}{2}\text{ = 21.5}[/tex]
A ladder that is 55 meters in length is resting on a branch of a tree, and the base of the ladder is 33 meters from the tree on the level ground. How high up is the branch on which the ladder is resting?
the diagram of situation is given as follows
so by using the right-angle property.
[tex]x^2+33^2=55^2[/tex][tex]\begin{gathered} x^2=3025-1089=1936 \\ x=\sqrt[]{1936} \end{gathered}[/tex][tex]x=44[/tex]so the height of the tree is 44
Please help me solve this using six grade math (easy formulas)
We will break the surface area of the tent up into its sides, the front and the back and the bottom.
Area of the sides: 2(5*7) = 70
Area of the front and the back: 2( 1/2 (6*4)) = 24
Area of the bottom: 7*6 = 42
Least amount of fabric required = 136ft
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Find (w ∘ w)(−1) for w(x)=3x^2+3x−3.
Answer: (w ∘ w)(−1)=
Answer:
15
Step-by-step explanation:
wow(-1) means w(w(-1))
so we can find out what w(-1) is
3(-1)^2+3(-1)-3=3-3-3
which is -3
then we can find w(-3)
3(-3)^2+3(-3)-3
which is 15
The triangles are similar, solve for the question mark. A Z с ? 15 10 12 B X D E 8 8 18 12.5 0 24
Answer:
18
Explanation:
The triangles are similar if their sides are proportional. It meant that the ratio of AB to CD is equal to the ratio of AE to CE, so we can write the following equation:
[tex]\begin{gathered} \frac{AB}{CD}=\frac{AE}{CE} \\ \frac{15}{10}=\frac{AE}{12} \end{gathered}[/tex]So, we can solve for AE as:
[tex]\begin{gathered} \frac{15}{10}\cdot12=\frac{AE}{12}\cdot12 \\ 18=AE \end{gathered}[/tex]Therefore, the measure of AE is 18
If r is the nominal rate and n is the number of times interest is compounded annually, then R=(1+r/n)^(n)-1 is the effective rate. Here, R represents the annual rate that the investment would earn if simple interest were paid. Use this formula to determine the effective rate for $1 invested for 1 year at 4.8% compounded semiannually.
Effective Rate in Compound Interest
Given r as the nominal rate of investment and n the number of times the interest is compounded annually, the formula for the effective rate is:
[tex]R=\mleft(1+\frac{r}{n}\mright)^n-1[/tex]We are required to find the effective rate for a rate of r=4.8% compounded semiannually. This means the value of n is 2 since there are two periods where interest is added to the principal per year.
Substituting the given values in the formula (recall r must be used as a decimal value, i.e. r=4.8/100=0.048):
[tex]R=(1+\frac{0.048}{2})^2-1[/tex]Calculating:
[tex]R=(1.024)^2-1=0.048576[/tex]The effective rate is 4.86%
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i am asked to find the range of this, (of the possible third angle)
Answer:
rage=<C-<B
=101°-70°
=30°
Juan earned 60% of the possible points on his first math test. His teacher offered to let him take another test to earn extra credit. Juan earned 80% of the possible points on the second test. Each test had the same number of possible points. If Juan earned 30 points on the first test, how many points did he earn on the second test?
Let:
x = Number of points Juan earned on the second text
n = Total number of points of each test
First, let's find the total number of points of each test using the information provided:
[tex]\begin{gathered} 0.6\cdot n=30 \\ so\colon \\ n=\frac{30}{0.6} \\ n=50 \end{gathered}[/tex]Now, we can find how many points Juan earned on the second test:
[tex]\begin{gathered} x=0.8\cdot n \\ x=0.8\cdot50 \\ x=40 \end{gathered}[/tex]Answer:
40 points
how do you work the problem 3k+16=5k?
We have the following:
[tex]3k+16=5k[/tex]solving for k
[tex]\begin{gathered} 5k-3k=16 \\ k=\frac{16}{2} \\ k=8 \end{gathered}[/tex]The value of k is 8
f(x) = 3x² - 5x+20
Find f(-8)
Answer:
Substitute x = -8 into f(x).
f(-8) = 3(-8)² - 5(-8) + 20
= 3(64) + 40 + 20
= 192 + 60
= 252
Evaluate 4w - 3y if w = 7 and y = 6
Answer:
10
Explanation:
Given the expression:
[tex]4w-3y[/tex]If w=7 and y=6
[tex]\begin{gathered} 4w-3y=4(7)-3(6) \\ =28-18 \\ =10 \end{gathered}[/tex]The value of the expression is 10.
18 area = in. 114, 134, Jordan's game started at 6:05 pm. The game finished at 7:10 pm, and it took 20 minutor to got home what time did
Notice that the first term is 114 and the third term is 134, then, between the first and the third, there are 20 units of difference.
Then, the common difference between each term must be 10, thus, the complete sequence is:
[tex]114,124,134,144,154[/tex]an airliner travels 30 miles in 4 minutes. what is its speed in miles per hour?
We need to convert minutes to hours. We know that 1 hour is 60 minutes so we can use the conversion factor of 1 hour = 60 minutes. We make sure the minutes cancel in the top and bottom leaving
30 miles 60 minutes
------------- * --------------
4 minutes 1 hour
30 miles * 60
--------------------
1 hour
180 miles
--------------
hour
From the origin of the coordinate plane, how many units does one travel along the y-axis to find the point with the coordinates (1,8)?
Solution:
Let's recall that in a coordinate plane, we consider (0, 0) as the origin because this is the point where the x and y-axes intersect.
Therefore, the unit you travel along the y-axis from the origin is:
8 - 0 = 8 (Value of y given - Value of y at the origin)
The answer is 8 units
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Find the equation of the linear function represented by the table below inslope-intercept form.xy1-3 -723-114-15
To find the linear equation, we use two points from the table (1, -3) and (3, -11). First, we have to find the slope with the following formula.
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where,
[tex]\begin{gathered} x_1=1 \\ x_2=3 \\ y_1=-3 \\ y_2=-11 \end{gathered}[/tex]Let's those coordinates to find the slope.
[tex]\begin{gathered} m=\frac{-11-(-3)_{}}{3-1}=\frac{-11+3}{2}=\frac{-8}{2}=-4\to m=-4 \\ \end{gathered}[/tex]The slope is -4.
Now, we use the point-slope formula to find the equation.
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-3)=-4(x-1) \\ y+3=-4x+4 \end{gathered}[/tex]Now, we solve for y to express it in slope-intercept form.
[tex]\begin{gathered} y+3=-4x+4 \\ y=-4x+4-3 \\ y=-4x+1 \end{gathered}[/tex]Therefore, the equation in slope-intercept form is y = -4x+1.What's the volume of a cube with a side length of 3 inches?
ANSWER
27 in³
EXPLANATION
The volume of a cube is the cube of its side length, L,
[tex]V=L^3[/tex]So, if a cube has a side length of 3 inches, then its volume is,
[tex]V=3^3in^3=27\text{ }in^3[/tex]Hence, the volume of a cube with a side length of 3 inches is 27 cubic inches.
Pat bought a washer/dryer for $900 and made 24 payments of $46.23. Howmuch did she pay in interest?a. $1,109.52b. $900c. $92.40d. $209.52
Given that:
Cost of the washer/dryer = $900
Number of payments made = 24
Amount paid in each payment = $46.23
Total amount she paid
[tex]\begin{gathered} =\text{Amount paid in each payment}\cdot Number\text{ of payments} \\ =46.23\cdot24 \\ =1109.52 \end{gathered}[/tex]Interest paid = Total amount paid - Cost of the washer/dryer
[tex]\begin{gathered} =1109.52-900 \\ =209.52 \end{gathered}[/tex]Option d is correct.
Riley read 1 book in 2 months. If she reads at a constant rate, how many books did she read in one month? Give your answer as a whole number or a FRACTION in simplest form.On the double number line below, fill in the given values, then use multiplication or division to find the missing value.
To find out the unit rate
Divide the total books by the total months
so
1/2=0.5 books per month
the answer is 0.5 books per monthIn the double number line
we have
books 0 0.5 1
months 0 1 2
What’s negative 5 + 1 fourth equal
Answer:
-4 3/4
Step-by-step explanation:
-5 x 4/4 + 1/4
-19/4 = -4 3/4
How much did he invest in Fund B, if both guns together returned a 8% profit.
Translate each English phrase in the following problem into an algebraic expression and set up the related equation. Let z be the unknown number. The sum of a number and -41 is equal to the quotient of the number and 11. Step 2 of 3: Translate "the quotient of the number and 11". Answer
An algebraic expression which represents the translation of "The sum of a number and -41 is equal to the quotient of the number and 11" is z - 1 = z/11.
How to translate an English phrase into an algebraic expression?In order to translate a word problem into an algebraic expression, we would have to assign a variable to the unknown number:
Let z represent the unknown number.
The sum of a number and -41 is given by:
z + (-1) = z - 1 ....equation 1.
The quotient of the number and 11 is given by:
z/11 .....equation 2.
Next, we would equate equation 1 and equation 2 as follows:
Translation; z - 1 = z/11
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Taylor has $430 in her savings account. The annual simple interest at the bank is 2%. How much intreast will she earn on her savings in 9 months?
we have the following equation
[tex]m(t)=430+430\cdot0.02\cdot t[/tex]where t is the time in years, as we have 9 months, we have to change to years
[tex]t=\frac{9}{12}=\frac{3}{4}=0.75[/tex]so after 9 months we get
[tex]430+430\cdot0.02\cdot0.75=430+6.45[/tex]So she will earn $6.45 in 9 month
what is the slope for the following points?(-1,1) and(3,3)
To find the slope for a line that connects the given points, use the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]where (x1,y1) and (x2,y2) are the given points.
Use:
(x1,y1) = (-1,1)
(x2,y2) = (3,3)
replace the values of the previous parameters in the formula for m:
[tex]m\text{ = }\frac{3-1}{3-(-1)}=\frac{2}{3+1}=\frac{2}{4}=\frac{1}{2}[/tex]Hence, the slope is 1/2
23)Suppose on a certain MTH 101 quiz, you scored a 94%. The mean score in the class was 82.6% with a standard deviation of 12.4%.a)How many standard deviations away from the mean are you?b)Using the following z-table snippet, determine what percent of your classmates you outperformed:
SOLUTION
Recall the z score formula:
[tex]z=\frac{x-\mu}{\sigma}[/tex]The given values are
[tex]x=94,\mu=82.6,\sigma=12.4[/tex]Therefore the score is:
[tex]\begin{gathered} z=\frac{94-86.4}{12.4} \\ z=0.6129 \end{gathered}[/tex]Therefore the score is 0.6129 standard deviations away from the mean.
b. From the table, the required value is 0.729069
Hence the percentage is 72.9069%
Shandar rents a pickup truck for her house move. She has to pay $96 for the first day, $88 for each additional day she keeps the truck, and 45 cents for each mile she drives. She will also be able to use a $25 coupon. Write an expression that represents the total cost when Shandar keeps the truck for h days and travels a total of p miles.Simplify the expression completely.List the terms in your expression.For each term, identify the coefficient and variable.
96 first day
88 for each additional day (h)
0.45 for each mile driven (p)
$25 coupon
Expression
Total cost = 96 + 88h + 0.45p - 25
Simplify:
Combine like terms:
TC = 96 - 25 + 88h + 0.45p
TC = 71 + 88h + 0.45p
Terms:
71 = constant
88h = coefficient 88 , variable h
0.45p= coeficcient 0.45 , variable p
The diagonal of a rectangle is 25 inches. The width is 15 inches. What is the area of the rectangle?
Answer:
300 in²
Step-by-step explanation:
Hello!
Because the diagonal forms right triangles, we can use the Pythagorean Theorem to find the missing length of the rectangle.
a² + b² = c²
a = legb = legc = hypotenuseIn this case, 25 is c, and 15 is a. We can solve for b using the formula.
Solve for ba² + b² = c²15² + b² = 25²225 + b² = 625b² = 400b = 20So the missing length of the rectangle is 20. We can find the area by multiplying 15 and 20
15 * 20 = A300 = AThe area is 300 in².
The position of an open-water swimmer is shown in the graph. The shortest route to the shoreline is one that is perpendicular to the sh Ay 10 00 6 water 4 shore |(2, 1) swimmer 19 -2 2 1 3 4 5X N -2 An equation that represents the shortest path is y=
Answer:
Explanation:
From the graph, we ca
Which 3 pairs of side lengths are possible measurements for the triangle?
SOLUTION
From the right triangle with two interior angles of 45 degrees, the two legs are equal in length, that is AB = BC
And from Pythagoras, the square of the hypotenuse (AC) is equal to the square of the other two legs or sides (AB and AC)
So this means
[tex]\begin{gathered} |AC|^2=|AB|^2+|BC|^2 \\ since\text{ AB = BC} \\ |AC|^2=2|AB|^2,\text{ also } \\ |AC|^2=2|BC|^2 \end{gathered}[/tex]So from the first option
[tex]\begin{gathered} BC=10,AC=10\sqrt{2} \\ |AC|^2=(10\sqrt{2})^2=100\times2=200 \\ 2|BC|^2=2\times10^2=2\times100=200 \end{gathered}[/tex]Hence the 1st option is correct, so its possible
The second option
[tex]\begin{gathered} AB=9,AC=18 \\ |AC|^2=18^2=324 \\ 2|AB|^2=2\times9^2=2\times81=162 \\ 324\ne162 \end{gathered}[/tex]Hence the 2nd option is wrong, hence not possible
The 3rd option
[tex]\begin{gathered} BC=10\sqrt{3},AC=20 \\ |AC|^2=20^2=400 \\ 2|BC|^2=2\times(10\sqrt{3})^2=2\times100\times3=600 \\ 400\ne600 \end{gathered}[/tex]Hence the 3rd option is wrong, not possible
The 4th option
[tex]\begin{gathered} AB=9\sqrt{2},AC=18 \\ |AC|^2=18^2=324 \\ 2|AB|^2=2\times(9\sqrt{2})^2=2\times81\times2=324 \\ 324=324 \end{gathered}[/tex]Hence the 4th option is correct, it is possible
The 5th option
AB = BC
This is correct, and its possible
The last option
[tex]\begin{gathered} AB=7,BC=7\sqrt{3} \\ 7\ne7\sqrt{3} \end{gathered}[/tex]This is wrong and not possible because AB should be equal to BC
Hence the correct options are the options bolded, which are
1st, 4th and 5th
