Here, we want to get the length of the third side
Mathematically, we can get this by the use of Pythagoras' theorem
It states that the square of the length of the hypotenuse equals the sum of the squares of the two other sides
Let the missing side be s
From the diagram, we have the hypotenuse as 25 (the hypotenuse is the longest side and it is the side that faces the right angle
We have this as;
[tex]\begin{gathered} 25^2=s^2+24^2 \\ s^2=25^2-24^2 \\ s^2\text{ = 625-576} \\ s\text{ = }\sqrt[]{49} \\ s\text{ = 7} \end{gathered}[/tex]What are the coefficient(s) in the following expression:
x² + 2x-5xy-y+3y¹
2,4
A
B
C
D
1, 2, 5, 1,3
2,-5, 3
1, 2, 5, 1, 3
Step-by-step explanation:
based on the expression you wrote here, the correct answer is
1, 2, -5, -1, 3
since none of your answer options show this, you must have made a mistake either with the expression itself or with the answer options.
please choose in your original the one matching my answer above.
Solve for k 4k – 6/3k – 9 = 1/3
hello
to solve this simple equation, we need to follow some simple steps.
[tex]4k-\frac{6}{3}k-9=\frac{1}{3}[/tex]step 1
multiply through by 3
we are doing this to eliminate the fraction and it'll help us solve this easily
[tex]\begin{gathered} 4k(3)-\frac{6}{3}k(3)-9(3)=\frac{1}{3}(3) \\ 12k-6k-27=1 \end{gathered}[/tex]notice how the equation haas changed suddenly? well this was done to make the question simpler and faster to solve.
step 2
collect like terms and simplify
[tex]\begin{gathered} 12k-6k-27=1 \\ 12k-6k=1+27 \\ 6k=28 \\ \end{gathered}[/tex]step three
divide both sides by the coefficient of k which is 6
[tex]\begin{gathered} \frac{6k}{6}=\frac{28}{6} \\ k=\frac{14}{3} \end{gathered}[/tex]from the calculations above, the value of k is equal to 14/3
Write a sine function that has a midline of 4 , an amplitude of 3 and a period of 2/3
Given a midline of 4, an amplitude of 3 and a period of 2/3 we are asked to write a sine function.
Explanation
The equation of a sine function is given as
[tex]y=Asin(\frac{2\pi x}{T})+B[/tex]Where A is the amplitude, T is the period and B is the midline of the sine function.
Therefore, we will have;
[tex]\begin{gathered} y=3sin(2\pi x\div\frac{2}{3})+4 \\ y=3sin(2\pi x\times\frac{3}{2}_)+4 \\ y=3s\imaginaryI n(3\pi x)+4 \end{gathered}[/tex]Answer:
[tex]y=3s\imaginaryI n(3\pi x)+4[/tex]Simplify (v2 + 10v + 11)(v2 + 3v – 4) using the distributive property of multiplication ove addition(DPMA)
Given:
[tex](v^2+10v+11)(v^2+3v-4)[/tex]To find- the simplification.
Explanation-
We know that the distribution property of multiplication over addition says
[tex]a(b+c)=ab+ac[/tex]Use this property to simplify, and we get
[tex]\begin{gathered} =(v^2+10v+11)(v^2+3v-4) \\ =v^2(v^2+3v-4)+10v(v^2+3v-4)+11(v^2+3v-4) \end{gathered}[/tex]Multiply by opening the bracket, and we get
[tex]=(v^4+3v^3-4v^2)+(10v^3+30v^2-40v)+(11v^2+33v-44)[/tex]Now, open the bracket and combine the like terms.
[tex]\begin{gathered} =v^4+3v^3-4v^2+10v^3+30v^2-40v+11v^2+33v-44 \\ =v^4+(3v^3+10v^3)+(11v^2-4v^2+30v^2)-40v+33v-44 \end{gathered}[/tex]On further solving, we get
[tex]=v^4+13v^3+37v^2-7v-44[/tex]Thus, from the distributive property of multiplication over addition, we get v⁴+13v³+37v²-7v-44.
The answer is v⁴ + 13v³ + 37v² - 7v - 44.
evaluate the following function for f(-2) .f(x)=3x+12
Given :
[tex]f(x)=3x+12[/tex]WE need to find the value of f(-2)
So, substitute with x = -2
[tex]f(-2)=3\cdot-2+12=-6+12=6[/tex]So, the value of f(-2) = 6
y - y1 = m (x - x1 ) write an equation in point slope form given point ( 4, -3 ) and m = 1
The point-slope form of a line is:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line and m is the slope.
Replacing with m = 1 and the point (4, -3):
y - (-3) = 1(x - 4)
y + 3 = x - 4
HELP PLEASEEEEE!!!!!!
Answer: D=2/7 R=4/7
Step-by-step explanation: there are 7 parts and D is the 2nd part R is the 4th part.
Put the following equation of a line into slope-intercept form, simplifying all fractions.4x + 20y = -180
The equation of a straight line is
y = mx + c
4x + 20y = -180
make 20y the subject of the formula
20y = -180 - 4x
20y = -4x - 180
divide all through by 20
20y/20 = -4x/20 - 180/20
y = -1/5x - 9
The answer is y = -1/5x - 9 where your slope is -1/5 and intercept is -9
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Find the midpoint m of z₁ = (9+7i) and Z₂ = (-7+7₂).
Express your answer in rectangular form.
m=
Re
The midpoint m of z₁ = (9+7i) and Z₂ = (-7+7i) is 1 + 7i .
Given complex numbers:
[tex]z_{1}[/tex] = (9 + 7i) and [tex]z_{2}[/tex] = (-7 + 7i)
compare these numbers with a1+ib1 and a2+ib2, we get
a1 = 9, a2 = -7 , b1 = 7 and b2 = 7.
Mid point of complex numbers = a1 + a2 /2 + (b1 + b2 /2)i
= (9 + (-7)/2 + (7 + 7 /2)i
= 2/2 + 14/2 i
Mid point m = 1 + 7i
Therefore the midpoint m of z₁ = (9+7i) and Z₂ = (-7+7i) is 1 + 7i
Learn more about the midpoint and complex numbers here:
https://brainly.com/question/11839107
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Math for Liberal Arts Lecture Class, Fall 2021 = Homework: Ch... Question 2, 1.1.3 Part 2 of 3 HW Score: Points: An election is held to choose the chair of a department at a university. The candidates are Professors Arg for short). The following table gives the preference schedule for the election. Use the table to complete pa Number of Voters 7 9 2 5 3 6 1st choice А A B D A 2nd choice B D D А E E 3rd choice D B E C B B 4th choice E C A B C D 5th choice C E C D A C (a) How many people voted in this election? ... 32 voters (Type a whole number.) (b) How many first-place votes are needed for a majority?
a) In this election voted: 7+9+2+5+3+6=32
b) For a majority you can follow the next rule:
The 50% of 32 is: 32*0.5=16, then, are needed at least 17 votes
c) Candidate A had 3 last-place votes, candidate B had 0 last-place votes, candidate C had 15 last-place votes, candidate D had 5 last-place votes and candidate E had 9 last-place votes.
Thus, the candidate with the fewest last-place votes is candidate B
The lengths of adult males' hands are normally distributed with mean 189 mm and standard deviation is 7.4 mm. Suppose that 15 individuals are randomly chosen. Round all answers to 4 where possible.
a. What is the distribution of ¯x? x¯ ~ N( , )
b. For the group of 15, find the probability that the average hand length is less than 191.
c. Find the first quartile for the average adult male hand length for this sample size.
d. For part b), is the assumption that the distribution is normal necessary? No Yes
Considering the normal distribution and the central limit theorem, it is found that:
a) The distribution is: x¯ ~ N(189, 1.91).
b) The probability that the average hand length is less than 191 is of 0.8531 = 85.31%.
c) The first quartile is of 187.7 mm.
d) The assumption is necessary, as the sample size is less than 30.
Normal Probability DistributionThe z-score of a measure X of a variable that has mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure X is above or below the mean of the distribution, depending if the z-score is positive or negative.From the z-score table, the p-value associated with the z-score is found, and it represents the percentile of the measure X in the distribution.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]. The mean is the same as the population mean.For sample size less than 30, such as in this problem, the assumption of normality is needed to apply the Central Limit Theorem.The parameters in this problem are given as follows:
[tex]\mu = 189, \sigma = 7.4, n = 15, s = \frac{7.4}{\sqrt{15}} = 1.91[/tex]
Hence the sampling distribution of sample means is classified as follows:
x¯ ~ N(189, 1.91).
The probability that the average hand length is less than 191 is the p-value of Z when X = 191, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem:
[tex]Z = \frac{X - \mu}{s}[/tex]
Z = (191 - 189)/1.91
Z = 1.05
Z = 1.05 has a p-value of 0.8531, which is the probability.
The first quartile of the distribution is X when Z has a p-value of 0.25, so X when Z = -0.675, hence:
[tex]Z = \frac{X - \mu}{s}[/tex]
-0.675 = (X - 189)/1.91
X - 189 = -0.675 x 1.91
X = 187.7 mm.
A similar problem, also involving the normal distribution, is given at https://brainly.com/question/4079902
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decide wether the following sides are acute obtuse or a right triangle.
The acute triangle is defined by the condition,
[tex]a^2+b^2The obtuse triangle is defined by the condition, [tex]a^2+b^2>c^2[/tex]Here, we have,
[tex]\begin{gathered} 19^2=361 \\ 12^2=144 \\ 15^2=225 \\ 12^2+15^2>19^2 \end{gathered}[/tex]Thus, the triangle is an obtuse triangle.
(a + 3)-(a + 2) Please help bc im stuck :>
Answer: 1
Step-by-step explanation:
We are given (a + 3) - (a + 2)
To think of this another way, we can distribute the negative sign out into the (a + 2)
(a + 3) -(a) - (2)
Now our expresssion looks like this:
(a + 3) - a - 2
Simplifying, we get
a - a + 3 - 2
The a terms cancel leaving us with
3-2
and that equals
1
Answer:
1
Step-by-step explanation:
1. Rewrite
: (a+3)-(a+2) = a + 3 - a - 2
2. Subtract
: 3-2 = 1 ... so now the equation is a + 1 - a
3. Combine like terms
: a -a = 0 (the a's cancel out) ... now you're left with 1
Since there is nothing left, your answer is 1.
Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skateboards and a standard deviation of 55 skateboards.
a) 84.13%
b) 2.28%
c) 15.86%
Explanation:Given:
the numbers of skateboards produced per day at a certain factory were normally distributed
mean = 20, 500
standard deviation = 55
To find:
a) On what percent of the day did the factories produced 20,555 or fewer?
b) On what percent of the day did the factories produced 20,610 or fewer?
c) On what percent of the day did the factories produced 20445 or fewer?
To determine the answers, we will use the z-score formula and then use the standard normal table to get the equivalence of the z-score
The formula of score is given as:
[tex]\begin{gathered} z=\frac{X-μ}{σ} \\ \mu\text{ = mean} \\ σ\text{ = standard deviation} \\ =\text{ value we want to find} \end{gathered}[/tex][tex]\begin{gathered} a)\text{ X}=\text{ 20555} \\ z\text{ = }\frac{20555\text{ - 20500}}{55}\text{ } \\ z\text{ = }\frac{55}{55}\text{ = 1} \\ on\text{ the standard normal table, z = 1 gives 0.84134} \\ Percent\text{ that they produced 20555 or fewer = 84.13\%} \end{gathered}[/tex][tex]\begin{gathered} b)\text{ X}=\text{ 20610} \\ z\text{ = }\frac{20610\text{ - 20500}}{55} \\ z\text{ = 2} \\ On\text{ the standard normal table, z = 2 corresponds to 0.97725} \\ \\ In\text{ this case, we were asked for the percent that produce 20610 or more} \\ To\text{ get ths percent, we will subtract 0.97725 from 1} \\ =\text{ 1 - 0.97725 = 0.02275 } \\ percent\text{ that produced 20610 or more = 2.28\%} \end{gathered}[/tex][tex]\begin{gathered} c)\text{ X = 20445} \\ z\text{ = }\frac{20445\text{ - 20500}}{55} \\ z\text{ = -1} \\ This\text{ translate to 0.1586} \\ percent\text{ that produced 20445 or fewer = 15.86\%} \end{gathered}[/tex]Imagine you are four years old. A rich aunt wants to provide for your future. She hasoffered to do one of two things.Option 1: She would give you $1000.50 a year until you are twenty-one.Option 2: She would give you $1 this year, $2 next year, and so on, doubling the amounteach year until you were 21.If you only received money for ten years, which option would give you the most money?
Given the situation to model the arithmetic and the geometric sequences.
Imagine you are four years old. A rich aunt wants to provide for your future. She has offered to do one of two things.
Option 1: She would give you $1000.50 a year until you are twenty-one.
This option represents the arithmetic sequence
The first term = a = 1000.50
The common difference = d = 1000.50
The general formula will be as follows:
[tex]\begin{gathered} a_n=a+d(n-1) \\ a_n=1000.50+1000.50(n-1) \\ \end{gathered}[/tex]Simplify the expression:
[tex]a_n=1000.50n[/tex]Option 2: She would give you $1 this year, $2 next year, and so on, doubling the amount each year until you were 21.
This option represents the geometric sequence
The first term = a = 1
The common ratio = r = 2/1 = 2
The general formula will be as follows:
[tex]\begin{gathered} a_n=a\cdot r^{n-1} \\ a_n=1\cdot2^{n-1} \end{gathered}[/tex]Now, we will compare the options:
The first term of both options is when you are four years old that n = 1
you only received money for ten years so, n = 10
So, substitute with n = 10 into both formulas:
[tex]\begin{gathered} Option1\rightarrow a_{10}=1000.50(10)=10005 \\ Option2\rightarrow a_{10}=1\cdot2^{10-1}=2^9=512 \end{gathered}[/tex]So, the answer will be:
For ten years, the option that gives the most money = Option 1
How many different choices of shirts does the store sell
Answer:
11
Explanation:
From the probability tree:
• There are 3 choices of small shirts.
,• There are 3 choices of medium shirts.
,• There are 3 choices of large shirts.
,• There are 2 choices of X-Large shirts.
Therefore, the number of different choices of shirts the store sells:
[tex]\begin{gathered} =3+3+3+2 \\ =11 \end{gathered}[/tex]There are 11 choices of shirts.
The area of a triangle is 5. two of the sides lengths are 4.1 and 2.5 and the included angle is obtuse. find the measure of the included angle, to the nearest tenth of a degree.
Given data:
The given area of the triangle is A=5.
The first side given is a=4.1.
The second side given is b=2.5.
The expression for the area of triangle is,
[tex]A=\frac{1}{2}ab\sin C[/tex]Substitute the given values in the above expression.
[tex]\begin{gathered} 5=\frac{1}{2}(4.1)(2.5)\text{ sin C} \\ \sin C=0.97561 \\ C=102.7^{\circ} \end{gathered}[/tex]Thus, the value of the angle is 102.7 degrees.
fred had a tray of brownies for his birthday. he ate 1/6 of the brownies by himself and his family ate 1/3 of the brownies how many brownies did fred and his family eat altogether
We want to know how many brownmies did Fred and his family eat together.
We will call to the total of the brownies by 1. On this case, after Fred ate 1/3 of the brownies, he will have:
[tex]1-\frac{1}{3}=\frac{3-1}{3}=\frac{2}{3}[/tex]This means that he has left 2/3 of the brownies. After his family ate 1/6 of the brownies:
[tex]\frac{2}{3}-\frac{1}{6}=\frac{4}{6}-\frac{1}{6}=\frac{3}{6}=\frac{1}{2}[/tex]This means they will have left 1/2 of the tray of brownies, and that they ate half of it.
What are all the rational roots of the polynomial f(x) = 20x4 + x3 + 8x² + x - 12?
Answer:
All the rational roots of the polynomial f(x) = 20x4 + x3 + 8x2 + x - 12 are 3/4 and -4/5.
I just need help finding the area of shape c.
We need to find the area of Shape C.
Please have a look at the diagram below:
To find x, we can use the Pythagorean Theorem on the right triangle.
[tex]\begin{gathered} 100^2+x^2=107^2 \\ \end{gathered}[/tex]Now, let's solve for x. The steps are shown below:
[tex]\begin{gathered} 100^2+x^2=107^2 \\ x^2=107^2-100^2 \\ x^2=11449-10000 \\ x^2=1449 \\ x=\sqrt[]{1449} \\ x=38.07 \end{gathered}[/tex]So, the top part (dotted line) is
[tex]\begin{gathered} x+100+x \\ =38.07+100+38.07 \\ =176.14 \end{gathered}[/tex]Now, we have a trapezoid. Let's find the area of the trapezoid:
[tex]\begin{gathered} A=\frac{1}{2}(b_1+b_2)h \\ A=\frac{1}{2}(100+176.14)(100) \\ A=13,807 \end{gathered}[/tex]Now, we need to subtract the area labeled (K) from the area of the trapezoid found.
--------------------------------------------------------------------------------
Area k is a triangle with side lengths 117, 117, and 176.14. Let's find the area of the triangle. The diagram is shown below:
Now, we will find h, the height of the triangle using Pythagorean Theorem.
[tex]\begin{gathered} 88.07^2+h^2=117^2 \\ h^2=117^2-88.07^2 \\ h^2=5932.6751 \\ h=\sqrt[]{5932.6751} \\ h=77.02 \end{gathered}[/tex]The area of the triangle (region K) is,
[tex]\begin{gathered} A=\frac{1}{2}bh \\ A=\frac{1}{2}(176.14)(77.02) \\ A=6783.15 \end{gathered}[/tex]The area of region C is the area of trapezoid - area of region k (triangle). So, the area is >>>>
[tex]\begin{gathered} A=13,807-6783.15 \\ A=7023.85 \end{gathered}[/tex]Answer7023.85(CO 6) Find the regression equation for the following data setx 245 187 198 189 176 266 210 255y 50 54 55 78 44 41 51 60cannot be determinedŷ = 74.17x – 0.09ŷ = -0.09x + 74.17ŷ = 0.09x – 74.17
Answer
ŷ = -0.09x + 74.17
Explanation
For the given data set:
x 245 187 198 189 176 266 210 255
y 50 54 55 78 44 41 51 60
The sum of x = 245 + 187 + 198 + 189 + 176 + 266 + 210 + 255 = 1726
The sum of y = 50 + 54 + 55 + 78 + 44 + 41 + 51 + 60 = 433
Mean x = 1726/8 = 215.75
Mean y = 433/8 = 54.125
Sum of squares (SSx) = 8391.5
Sum of products (SP) = -779.75
(Check the table below of the data for a better understanding).
The regression Equation is given by ŷ = bX + a
b = SP/SSx = -779.75/8391.5 = -0.09292
a = My - bMx = 54.13 - (-0.09 x 215.75) = 74.17279
Therefore, the regression equation for the data set is: ŷ = -0.09292x + 74.17279
The correct answer is ŷ = -0.09x + 74.17
Daniel ate 3 pieces of pizza. Jeremy ate 2 times that much. How many pieces of (p) did Jeremy eat?
Let:
x = pieces of pizza eaten by Daniel
y = Pieces of pizza eaten by Jeremy
Daniel ate 3 pieces of pizza. so:
[tex]x=3[/tex]Jeremy ate 2 times that much, so:
[tex]\begin{gathered} y=2x \\ so\colon \\ y=2(3) \\ y=6 \end{gathered}[/tex]Jeremy ate 6 pieces of pizza
What is the area of a rectangle with length of 6.5 feet (ft) and width of 2.5 ft?
The area of a rectangle is given by the formula
[tex]\begin{gathered} A=l\cdot w \\ \text{ Where l is the length and} \\ w\text{ is the width of the rectangle} \end{gathered}[/tex]So, you have
[tex]\begin{gathered} l=6.5\text{ ft} \\ w=2.5\text{ ft} \\ A=l\cdot w \\ A=6.5\text{ ft }\cdot2.5\text{ ft} \\ A=16.25\text{ ft}^2 \end{gathered}[/tex]Therefore, the area of this rectangle is 16.25 square feet.
what number need to be changed to make a linear function? And what does it have to turn into?
In order to have a linear function, the rate of change needs to be the same in each point
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]For
(-18,2)=(x1,y1)
(-14,4)=(x2,y2)
[tex]m=\frac{4-2}{-14+18}=\frac{1}{2}[/tex]for
(-14,4)=(x1,y1)
(-12,5)=(x2,y2)
[tex]m=\frac{5-4}{-12+14}=\frac{1}{2}[/tex]for
(-12,5)=(x1,y1)
(0,12)=(x2,y2)
[tex]m=\frac{12-5}{0+12}=\frac{7}{12}[/tex]as we can see here are the two numbers so we will obtain the equation in order to know the number that needs to be change
[tex]y=\frac{1}{2}x+11[/tex]therefore if x=0
[tex]y=\frac{1}{2}(0)+11=11[/tex]the number we need to change is 12 and need to be changed for 11
(0,11)
a. The number that needs to be changed in order to create a linear function is 12
b. That number needs to be changed to 11 in order for the function to be linear
The domain and ranger of a linear function is always all real numbers true or false ?
Answer:
Step-by-step explanation:
The domain and range of a linear function is always real numbers (T or F)
It is True. This is because of a couple of reasons.
1.) You cannot divide by 0.
2. A negative number cannot have its square root taken.
The range is determined by the domain in a linear function, and thus it must always consist of real numbers.
Use the distributive property to simplify 10 - 5( -3-7m) completely .
Simplify the expression by using the distributive property.
[tex]\begin{gathered} 10-5(-3-7m)=10+(-5)\cdot(-3)+(-5)\cdot(-7m) \\ =10+15+35m \\ =25+35m \end{gathered}[/tex]So answer is 25 + 35m.
Cut a 10-foot (ft.) long piece of wood into two pieces so that one piece is 2 ft longer than the other. Which of the following equations depicts the given situation?A. x/2 = 10B. x + 2 = 10C. 2x + 2 = 10D. None of the choices
Given:
Cut a 10-foot (ft.) long piece of wood into two pieces so that one piece is 2 ft longer than the other.
Required:
Which of the following equations depicts the given situation?
Explanation:
Let 10 feet long piece of wood cut into two pieces of length x(smaller piece) and
x+2 larger piece.
So, the equation will be
x + x + 2 =10
2x + 2=10
Answer:
Option C is correct.
Select the similarity transformation(s) that make ABCD similar to EFGH.
Answer:
D
F
Explanation:
We would compare the coordinates of the corresponding vertices of rectangles ABCD and EFGH. We would compare vertices A and E. From the information given,
A = (1, - 2)
E = (- 2, 4)
If we apply (x, y)---(- x, - y) to A, it becomes (- 1, - - 2) = (- 1, 2)
If we apply (x, y)---(2x, 2y) to (- 1, 2), it becomes (2 * - 1, 2 * 2) = (- 2, 4)
Thus, the correct similarity transformation(s) that make ABCD similar to EFGH are
D
F
3. In one linear function, when you subtracteach y-coordinate from the x-coordinate,the difference is 3. If the x-coordinate isnot greater than 10 and the y-coordinateis a positive whole number, how manyordered pairs are there?
Problem
3. In one linear function, when you subtract each y-coordinate from the x-coordinate, the difference is 3. If the x-coordinate is not greater than 10 and the y-coordinate is a positive whole number, how many ordered pairs are there?
Solution
Here are the conditions
x- y= 3
x <10
y >0
And then we have these as possible answers:
4-1 =3
5-2= 3
6-3=3
7-4=3
8-5=3
9-6=3
Then the total possible pairs are: 6
what angle is Supplementary to angle 2 and what are the Verticle angles in this picture?
Suplementary angle = 180° - angle 2
is Angle 1,
because Angle 2 + Angle 1 = 180°
Part 2. Vertical angles are
Angles 2 and 5