Answer:
1728 cm ^ 3.
Step-by-step explanation:
we are given 12 cm
As we know formula of volume of cube = s ^3 ( side * side * side ) So = 12 * 12* 12 = 1728 cm ^ 3.
Find the Volume cylinder (8cm) (12cm) h = 8cm r = 12cm h = 8 cm r = 12 cm. The volume of a cylinder is equal to the area of the base πr2 π r 2 times the height. π⋅(radius)2 ⋅(height) π ⋅ ( r a d i u s) 2 ⋅ ( h e i g h t) Substitute the values of the radius r = 12 r = 12 and height h = 8 h = 8 into the formula to find the volume of the cylinder
P.s hopes this helps
Rewrite the fraction with a rational denominator:
[tex]\frac{1}{\sqrt{5} +\sqrt{3} -1}[/tex]
Give me a clear and concise explanation (Step by step)
I will report you if you don't explain
The expression with rational denominator is [tex]\frac{(\sqrt 5 - \sqrt{3} + 1)(- 5+2\sqrt 3)}{13}[/tex]
How to rewrite the fraction?From the question, the fraction is given as
[tex]\frac{1}{\sqrt 5 + \sqrt{3} - 1}[/tex]
To rewrite the fraction with a rational denominator, we simply rationalize the fraction
When the fraction is rationalized, we have the following equation
[tex]\frac{1}{\sqrt 5 + \sqrt{3} - 1} = \frac{1}{\sqrt 5 + \sqrt{3} - 1} \times \frac{\sqrt 5 - \sqrt{3} + 1}{\sqrt 5 - \sqrt{3} + 1}[/tex]
Evaluate the products in the above equation
So, we have
[tex]\frac{1}{\sqrt 5 + \sqrt{3} - 1} = \frac{\sqrt 5 - \sqrt{3} + 1}{(\sqrt 5)^2 - (\sqrt{3} + 1)^2}[/tex]
This gives
[tex]\frac{1}{\sqrt 5 + \sqrt{3} - 1} = \frac{\sqrt 5 - \sqrt{3} + 1}{5 - 10 - 2\sqrt 3}[/tex]
So, we have
[tex]\frac{1}{\sqrt 5 + \sqrt{3} - 1} = \frac{\sqrt 5 - \sqrt{3} + 1}{- 5 - 2\sqrt 3}[/tex]
Rationalize again
[tex]\frac{1}{\sqrt 5 + \sqrt{3} - 1} = \frac{\sqrt 5 - \sqrt{3} + 1}{- 5 - 2\sqrt 3} \times \frac{- 5+2\sqrt 3}{- 5 +2\sqrt 3}[/tex]
This gives
[tex]\frac{1}{\sqrt 5 + \sqrt{3} - 1} = \frac{(\sqrt 5 - \sqrt{3} + 1)(- 5+2\sqrt 3)}{(-5)^2 - (2\sqrt 3)^2}[/tex]
So, we have
[tex]\frac{1}{\sqrt 5 + \sqrt{3} - 1} = \frac{(\sqrt 5 - \sqrt{3} + 1)(- 5+2\sqrt 3)}{25 -12}[/tex]
Evaluate
[tex]\frac{1}{\sqrt 5 + \sqrt{3} - 1} = \frac{(\sqrt 5 - \sqrt{3} + 1)(- 5+2\sqrt 3)}{13}[/tex]
Hence, the expression is [tex]\frac{(\sqrt 5 - \sqrt{3} + 1)(- 5+2\sqrt 3)}{13}[/tex]
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What is the product?(4y − 3)(2y2 + 3y − 5)8y3 + 3y + 158y3 − 23y + 158y3 − 6y2 − 17y + 158y3 + 6y2 − 29y + 15
We need to find the product of :
[tex]\mleft(4y-3\mright)\mleft(2y2+3y-5\mright)[/tex]So, the result as following:
[tex]\begin{gathered} \mleft(4y-3\mright)\mleft(2y^2+3y-5\mright) \\ =4y\cdot(2y^2+3y-5)-3\cdot(2y^2+3y-5) \\ =8y^3+12y^2-20y-(6y^2+9y-15) \\ =8y^3+12y^2-20y-6y^2-9y+15 \\ \\ =8y^3+6y^2-29y+15 \end{gathered}[/tex]So, the answer is the option 4. 8y3 + 6y2 − 29y + 15
Find the equation line parallel y=(-4/5)x+12 passing through (-6,2)
So we want to find the equation of a line parallel to
[tex]y=-\frac{4}{5}x+12[/tex]Passing through the point (-6,2).
First, remember that a line is parallel to other if their slopes are the same.
Then, the slope of our parallel line will be also -4/5.
Remember that a line has the following equation:
[tex]y=mx+b[/tex]Where m is the slope and b is the y-intercept.
Now, we know that the parallel line has slope = -4/5 and passes through the point (x,y) = (-6,2), so we could replace in our previous equation as follows:
[tex]\begin{gathered} 2=-\frac{4}{5}(-6)+b \\ 2=\frac{24}{5}+b \\ b=2-\frac{24}{5} \\ b=-\frac{14}{5} \end{gathered}[/tex]Therefore, the equation of the parallel line to y=(-4/5)x+12 passing through (-6,2) is:
[tex]y=-\frac{4}{5}x-\frac{14}{5}[/tex]
What kind of polyhedron can be assembled from this net?
It could be assembled a rectangular prism
and
Element X decays radioactively with a half life of 14 minutes. If there are 460 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 35 grams?
Step 1
Given;
[tex]\begin{gathered} Intially\text{ y}_0=460g \\ Half\text{ life, h=14 minutes} \\ y=\frac{460}{2}=230g,\text{ when t=h=14 min} \\ \end{gathered}[/tex]Putting these values in, we have;
[tex]\begin{gathered} 230=a(0.5)^1 \\ a=\frac{230}{0.5}=460g \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} y=460(0.5)^{\frac{t}{14}}---(1) \\ when\text{ y=35} \\ 35=460(0.5)^{\frac{t}{14}} \end{gathered}[/tex][tex]\begin{gathered} 35=460(0.5)^{\frac{t}{14}} \\ \frac{460\cdot \:0.5^{\frac{t}{14}}}{460}=\frac{35}{460} \\ 0.5^{\frac{t}{14}}=\frac{7}{92} \\ \frac{t}{14}\ln \left(0.5\right)=\ln \left(\frac{7}{92}\right) \\ t=\frac{14\ln\left(\frac{7}{92}\right)}{\ln\left(0.5\right)} \\ t=52.02689 \\ t\approx52.0\text{ minutes to the nearest tenth of a minute} \end{gathered}[/tex]Answer;
[tex]52.0\text{ minutes to the nearest tenth of a minute}[/tex]Solve each system of the equation by elimination. y=-4x+14y=10x-28
Explanation:
The elimination method consists in substracting one equation from the other, so you eliminate one of the variables and you have only one equation to solve for one variable.
In this case, y has the same coefficient in both equations, so this is the variable we will eliminate.
Substract the first equation from the second:
[tex]\begin{gathered} y=10x-28 \\ - \\ y=-4x+14 \\ \text{ ---------------------} \\ y-y=10x+4x-28-14 \\ 0=14x-42 \end{gathered}[/tex]And solve for x:
[tex]\begin{gathered} 14x=42 \\ x=\frac{42}{14} \\ x=3 \end{gathered}[/tex]Now, we replace x = 3 into one of the equations and solve for y:
[tex]y=-4\cdot3+14=-12+14=2[/tex]Answer:
• x = 3
,• y = 2
A glassblower makes vases. To prevent them from breaking,each vase's thickness should be 6 millimeters and candeviate by no more than 1 millimeter.Write an inequality to represent this situation, where t is thethickness in millimeters, and solve for the maximumthickness.
Since each vase should be 6 millimeters and can only deviate by no more than 1 millimeter, the inequality for the thickness would be:
[tex]6\ge t\leq7[/tex]And the maximum thickness would be 7 millimeters.
which of these is a formula that can be used to determine the nth term of the arithmetic sequence 15,27,39,51,....?
For an arithmetric progression, we need to find the common difference in the sequence
common difference = d = 2nd term - 1st term = 3rd term - 2nd term = 4th term - 3rd term
2nd term - 1st term = 27 -15 = 12
3rd term - 2nd term = 39-27 = 12
The result are the same.
Hence, d = 12
The first trm = 15
The formula for arithmetric sequence:
The nth term = 1st term + d(n - 1)
Replacing with the values we got above:
The nth term = 15 + 12(n - 1)
Since none of the options have the above, we would expand the parenthesis.
The nth term = 15 + 12×n - 12×1
The nth term = 15 + 12n - 12
= 15 -12 + 12n
The nth term = 3 + 12n = 12n + 3
From the options:
The nth term = 12n + 3 (option B)
[tex]a_n=\text{ }12n+3\text{ (}optionB)[/tex]
Find an equation of the tangent line to the graph of y = B(x) at x = 25 if B(25) = −1 and B ′(25) = − 1 5 .
The most appropriate choice for tangent to a curve will be given by-
[tex]3x + 2y = 73[/tex] is the required equation of tangent.
What is tangent to a curve?
Tangent to a curve at a point is the straight line that just touches the curve at that point.
Equation of tangent to a curve at a point [tex](x_1, y_1)[/tex] is given by
[tex]y - y_1 = \frac{dy}{dx}|_{(x_1,y_1)} (x - x_1)[/tex]
Here,
y = B(x), B(25) = -1, B'(25) = -1.5
Equation of tangent =
[tex](y - (-1)) = -1.5(x - 25)[/tex]
[tex]y + 1=-1.5x +37.5\\y + 1 = -\frac{3}{2}x + 37.5\\2y + 2 = -3x + 75\\3x+2y = 75-2\\3x+2y=73[/tex]
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the top ten medal- winning nations in a tournament in a particular year are shown in the table. use the given information and calculate the mean number of gold medals for all nations
Write the equation for a circle with the following informationcenter: (5,-3) radius: 7
Step 1: Problem
To determine the equation of a circle with centre (5, -3) and radius 7
Step 2: Substitute the centre value and radius to the equation
[tex]\begin{gathered} \text{Equation of a circle} \\ (x-a)^2+(y-b)^2=r^2 \\ \text{centre (5,-3) , radius =7} \\ a=5,\text{ b=-3, r=7} \\ (x-5)^2+(y-(-3))^2=7^2 \end{gathered}[/tex]Step 3: Simplify the above equation
[tex]\begin{gathered} (x-5)(x-5)\text{ + (y+3)(y+3) = 49} \\ x^2-5x-5x+25+y^2+3y+3y+9=49 \\ x^2-10x+25+y^2+6y+9=49 \\ x^2+y^2-10x+6y=49-25-9 \\ x^2+y^2-10x+6y=15 \\ x^2+y^2-10x+6y-15=0 \end{gathered}[/tex]Hence the equation of the circle is
[tex]x^2+y^2-10x+6y-15=0[/tex]Select from these metric conversions1 kg = 1000 g1 g = 1000mgand use dimensional analysis to convert 4.59 kg to g.4.59 kg X 1
Since
[tex]1kg=1000g,[/tex]then:
[tex]1=\frac{1000g}{1kg}.[/tex]Then:
[tex]4.59kg=\frac{4.59kg}{1}\times\frac{1000g}{1kg}=4590g.[/tex]Answer:
[tex]\frac{4.59kg}{1}\times\frac{1000g}{1kg}=4590g.[/tex]find the greatest common factor for 8n^3 6n^3
We determine the greatest common factor as follows:
[tex]8n^3+6n^3[/tex]So, we factor:
[tex]2n^3(4+3)[/tex]So, the greatest common factor is 2n^3.
Hi I need help with this thank you! Previous question that may help answer this one : Line of best fit: ^y1=−0.02 x+4.68 ● Curve of best fit: ^y2=−0.09 x2+1.09 x+2.83 Section 2 Question 1 Using a curve to make a prediction of the y value for an x value between two existing x values in your data set is called interpolation. Suppose the year is 2005, where x = 5 years: (a) Use the equation for the line of best fit to predict the number of cell phones sold during that year. Round answers to one decimal place and be sure to include the appropriate units. Your Answer: we have the linear equation: y1=-0.02x+4.68Where x is the number of years since the year 2000, y1 ----> is the number of cell phones sold. So for the year 2005, x=2005-2000=5 years.substitute:y1=-0.02(5)+4.68y1=4.58Therefore, the answer is 4.6 cell phones sold.(b) Use the equation for the non-linear curve of best fit to predict the number of cell phones sold during that year. Round answers to one decimal place and be sure to include the appropriate units. Your Answer: We have the equation y2=-0.09x^2+1.09x+2.83For x=5 yearssubstitute:y2=-0.09(5)^2+1.09(5)+2.83y2=6.03Therefore, the answer is 6.0 cell phones sold.
From the information provided we will have that the predictions will be:
*Line of best fit:
[tex]y_1=0.02(13)+4.68\Rightarrow y_1=4.94\Rightarrow y_1\approx4.9[/tex]So, the extrapolation from the line of best fit is 4.9 sold.
*Curve of best fit:
[tex]y_2=0.09(13)^2+1.09(13)+2.83\Rightarrow y_2=32.21\Rightarrow y_2\approx32.2[/tex]So, the extrapolation for the curve of best fit is 32.2 sold.
A rainstorm in Portland, Oregon, wiped out the electricity in 10% of the households in the city. Suppose that a random sample of 50 Portland households is taken after the rainstorm.Answer the following.(a)Estimate the number of households in the sample that lost electricity by giving the mean of the relevant distribution (that is, the expectation of the relevant random variable). Do not round your response.(b)Quantify the uncertainty of your estimate by giving the standard deviation of the distribution. Round your response to at least three decimal places.
Solution
Question A:
[tex]\begin{gathered} Mean=np \\ where, \\ n=\text{ Number of sample values} \\ p=\text{ Probability of mean} \\ \\ n=50 \\ p=10\%=\frac{10}{100} \\ \\ \therefore Mean=50\times\frac{10}{100}=5 \end{gathered}[/tex]- The number of households in the sample that lost electricity is 5
Question B:
[tex]\begin{gathered} \sigma=\sqrt{npq} \\ where, \\ \sigma=\text{ Standard deviation} \\ n=\text{ Number of data points in the sample} \\ p=\text{ Probability of obtaining the mean} \\ q=\text{ Probability of NOT}obtaining\text{ the mean}=1-p \\ \\ n=50 \\ p=10\%=0.1 \\ q=1-0.1=0.9 \\ \\ \sigma=\sqrt{50\times0.1\times0.9} \\ \sigma=2.121320343...\approx2.121 \end{gathered}[/tex]- The standard deviation is 2.121
Final answers
- The number of households in the sample that lost electricity is 5
- The standard deviation is 2.121
Which of the following data collection methods best describes the situation below?A polling company wants to predict which candidate will win an election. Company employees randomly call 1482 likely voters and ask them how they plan to vote.a. sample surveyb. experimentc. observational studyd. correlation
Answer
Option A is correct.
Explanation
Sample survey refers to the statistic
A parabola opening up or
equation in vertex form.
down has vertex (-1, 4) and passes through (-2, 17). Write its equation in vertex form.
Equation of parabola in vertex form is 13x² + 26x + 17
Define Parabola
A symmetrical open plane curve created when a cone and a plane that runs perpendicular to its side collide. Ideally, a projectile traveling under the pull of gravity will travel along a curve similar to this one.
Given,
vertex (h,k) = (-1, 4)
points (x,y) = (-2, 17)
We know, The equation in vertex form is
y = a(x - h)² + k
put the (h,k) values,
y = a(x - (-1))² + 4
y = a(x + 1)² + 4 --------- eq(i)
Next, find the value of 'a' by plug in the points of (x, y) in eq(i)
y = a(x + 1)² + 4
⇒17 = a(-2 + 1)² + 4
⇒17 = a(-1)² + 4
⇒17 = a + 4
⇒a = 13
Now, substitute 'a' value in eq(i) to find the equation of parabola
y = a(x + 1)² + 4
⇒ y = 13(x + 1)² + 4
⇒ y = 13(x² + 1 + 2x) + 4
⇒ y = 13x² + 13 + 26x + 4
⇒ y = 13x² + 26x + 17
Therefore, equation of parabola in vertex form is 13x² + 26x + 17
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Two ships left a port at the same time. Onetravelled due north and the other due eastat average speeds of 25.5 km/h and 20.8 km/h,respectively. Find their distance apart
Given:
Two ships left a port at the same time.
One travelled due north at an average speed of 25.5 km/h
And the other ship was due east at average speeds of 20.8 km/h
We will find their distance apart using the Pythagorean theorem.
The distance = Speed * Time
Let the time = t
So, the distance of the first ship = 25.5t
And the distance of the second ship = 20.8t
So, the distance between the ships (d) will be as follows:
[tex]\begin{gathered} d^2=(25.5t)^2+(20.8t)^2 \\ d^2=1082.89t^2 \\ \\ d=\sqrt{1082.89t^2} \\ d=32.907t \end{gathered}[/tex]So, the answer will be:
The distance in terms of time = 32.907t
We will find the distance when t = hours
So, distance = 164.54 km
Use the drawing tool(s) to form the correct answer on the provided graph, The function fx) is shown on the provided graph. Graph the result of the following transformation on f(X). f(x) + 6
We have that the line passes by the points (0, -2) & (1, 2). Using this we determine the slope (m) and then the function. After that we transformate the function. We proceed as follows:
[tex]m=\frac{2-(-2)}{1-0}\Rightarrow m=4[/tex]Now, using one of the points [In our case we will use (0, -2), but we can use any point of the line] and the slope, we replace in:
[tex]y-y_1=m(x-x_1)[/tex]Then:
[tex]y-(-2)=4(x-0)[/tex]Now, we solve for y:
[tex]\Rightarrow y+2=4x\Rightarrow y=4x-2[/tex]And we apply the transformation to our line, that is f(x) -> f(x) + 6:
[tex]y=4x-2+6\Rightarrow y=4x+4[/tex]Therefore our final line (After the transformation) is y = 4x + 4, and graphed that is:
A car rental company’s standard charge includes an initial fee plus an additional fee for each mile driven. The standard charge S (in dollars) is given by the function S = 15.75+0.50 M, where M is the number of miles driven. The company also offers an option to ensure the car against damage. The insurance charge I in dollars is given by the function I = 5.70+0.15 M. Let C be the total cost in dollars for a rental that includes insurance. Write an equation relating C to M.
Answer:
[tex]C\text{ = 0.65 M + 21.45}[/tex]Explanation:
Here, we want to write an equation that relates C to M
From the given question, we have to add the insurance to the standard charge to get the total cost
Mathematically:
[tex]C\text{ = S + I}[/tex]Now, we substitute the values for both S and I
That would be:
[tex]\begin{gathered} C\text{ = 15.75 + 0.50M + 5.70 + 0.15 M} \\ C\text{ = 0.65M + 21.45} \end{gathered}[/tex]
Function A and Function B are linear functions.
Which statement is true?
The y-value of Function A when x = -2 is greater than the y-value of Function B when x = -2.
The y-value of Function A when x = -2 is less than the y-value of Function B when x = -2.
Answer:
Step-by-step explanation:
The y-value of Function A when x = - 2 is less than the y-value of Function B when x = - 2.
why are integers rational numbers? give an example
Integers are rational numbers because it consists of zero, positive and negative numbers till infinity only.
What is Rational number?This is referred to as a number which can be expressed as the quotient p/q of two integers such that q ≠ 0 and they are present till infinity due to the large numbers and examples include 2000, 25 etc.
Integers are rational numbers because they contain zero, positive and negative numbers. Decimals and fractions are not included in this context and an example is 12, 100 etc which is why the aforementioned above was chosen as the correct choice.
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Jerome rolls two six-sided number cubes. What is the probability that he rolls doubles, given the sum of the numbers is 8?
Answer:
[tex]\frac{1}{6}[/tex]
Step-by-step explanation:
hope you get it thats the last pen that works in my house
Answer: There are five possible outcomes with a sum of 8:
2 and 6,
3 and 5,
4 and 4,
5 and 3,
6 and 2.
There is only one outcome, 4 and 4, that is doubles. Therefore, the probability is 1/5.
Step-by-step explanation: Got it right on Edmentum
HELP ASAP
What is the size of the smallest angle in Triangle A? Give your answer correct to one
decimal place. Show your calculations.
Answer:
A is an included angle between 3 and 5
3(4x+1)^2-5=25 using square root property
Answer:
[tex]x=\frac{-1+\sqrt{10}}{4}\text{ or }x=\frac{-1-\sqrt{10}}{4}[/tex]Explanation:
Given the equation:
[tex]3\left(4x+1\right)^2-5=25[/tex]To solve an equation using the square root property, begin by isolating the term that contains the square.
[tex]\begin{gathered} 3(4x+1)^{2}-5=25 \\ \text{ Add 5 to both sides of the equation} \\ 3(4x+1)^2-5+5=25+5 \\ 3(4x+1)^2=30 \\ \text{ Divide both sides by 3} \\ \frac{3(4x+1)^2}{3}=\frac{30}{3} \\ (4x+1)^2=10 \end{gathered}[/tex]After isolating the variable that contains the square, take the square root of both sides and solve for the variable.
[tex]\begin{gathered} \sqrt{(4x+1)^2}=\pm\sqrt{10} \\ 4x+1=\pm\sqrt{10} \\ \text{ Subtract 1 from both sides} \\ 4x=-1\pm\sqrt{10} \\ \text{ Divide both sides by 4} \\ \frac{4x}{4}=\frac{-1\pm\sqrt{10}}{4} \\ x=\frac{-1\pm\sqrt{10}}{4} \end{gathered}[/tex]Therefore, the solutions to the equation are:
[tex]x=\frac{-1+\sqrt{10}}{4}\text{ or }x=\frac{-1-\sqrt{10}}{4}[/tex]
Two numbers sum to 61. Twice the first subtracted from the second is 1. Find the numbers.
Evaluate the expression (4x^3y^-2)(3x^-2y^4) for x = –2 and y = –1.
Answer:
3x−2y)(4x+3y)
It can be written as =3x(4x+3y)−2y(4x+3y)
By further calculation =12x
2
+9xy−8xy−6y
2
So we get =12x
2
+xy−6y
2
A veterinarian is visited by many pets and their owners each day. Before the doctor attends to each pet, an assistant records information including the type, age, weight, and height of each pet. What are the individuals in the data set?
Since all the information in the study, such as the type, the age and the weight are related to the pet, individuals in each data-set are the pets.
Who are the individuals on a data-set or on a study?The individual of a data-set is the object which is being analyzed in the study, the object that has it's characteristics analyzed.
In the context of this problem, these following information are analyzed, at the register when the doctor attends each pet and registers the information.
Type of the pet.Age of the pet.Weight of the pet.Height of the pet.All these information belong to the pet that visits the veterinary, hence the individuals in each data-set are the pets.
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a large community college has professors and lectures. total number of facility members is 228. the school reported that they had five professors for every 14 lectures. how many of each type of faculty member does the community college employee?
a large community college has professors and lectures. total number of facility members is 228. the school reported that they had five professors for every 14 lectures. how many of each type of faculty member does the community college employee?
Let
x -----> number of professors
y ----> number of lectures
we have that
x+y=228
x=228-y -------> equation A
x/y=5/14
x=(5/14)y ------> equation B
equate equation A and equation B
228-y=(5/14)y
solve for y
(5/14)y+y=228
(19/14)y=228
y=228*14/19
y=168
Find the value of x
x=228-168=60
therefore
number of professors is 60number of lectures is 168An athlete runs at a speed of 9 miles per hour. If one lap is 349 yards, how many laps does he run in 22 minutes
An athlete run in 22 minutes is 19.232 laps
Given,
An athlete runs at a speed of 9 miles per hour.
and, If one lap is 349 yards.
To find the how many laps does he run in 22 minutes?
Now, According to the question:
Firstly, Convert the mph into yard per minute,
Remember that:
I mile = 1,760 yard
1hour = 60 minute
Convert the speed in miles/hour to yards/minute
9 [tex]\frac{miles}{hour}[/tex] = 9[tex]\frac{1760}{60}[/tex] = 264 yard/ min
We know that
The speed is equal to divide the distance by the time
Let
s → the speed
d → the distance in yards
t → the time in minutes
Using the formula :
Speed = distance/ time
Solve the distance:
d = speed x time
Speed = 264 yard/ minute
Time = 22 minute
Therefore,
Distance = 264 x 22
Distance = 5,808 yards
Divide the distance by 302 yards to find out the number of laps
= 5,808/ 302 = 19.232 laps
Hence, An athlete run in 22 minutes is 19.232 laps
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