The two unit vectors orthogonal to both j-k and i+j are [tex]\frac{i}{\sqrt{3} }- \frac{j}{\sqrt{3} } -\frac{k}{\sqrt{3} }[/tex]
Let a bar = j- k = < 0,1,-1>
b bar = i+j = <1,1,0>
the cross product a x b bar is orthogonal to both a and b bar
= i ( 0-(-1) ) -j ( 0-(-1) ) + r (0-1)
= i-j-k
A unit vector is a vector whose length is 1 unit
There the unit vector is :
[tex]\frac{i-j-k}{\sqrt{1^2+(-1)^2+(-1)^2} } = \frac{i-j-k}{\sqrt{3} }[/tex]
= [tex]\frac{i}{\sqrt{3} }-\frac{j}{\sqrt{3} }-\frac{k}{\sqrt{3} }[/tex]
The second unit vector orthogonal to both a and b bar would be negative of the previous vector.
= [tex]-\frac{i}{\sqrt{3} }-\frac{j}{\sqrt{3} }-\frac{k}{\sqrt{3} }[/tex]
Hence the two unit vectors orthogonal to both j-k and i+j are [tex]\frac{i}{\sqrt{3} }- \frac{j}{\sqrt{3} } -\frac{k}{\sqrt{3} }[/tex]
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Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The second part of the trip there was no traffic so she could drive 44 mph. If the trip took her 5 hours, how long did she travel at each speed? In traffic she drove for _____ hours After the traffic cleared she drove for ____ hours.
Answer:
In traffic, she drove for 3 hours
and After the traffic cleared she drove for 2 hours.
Explanation:
Given that the road trip was 136 miles;
[tex]d=136[/tex]The first part of the trip there was lots of traffic, she only averaged 16 mph;
[tex]v_1=16[/tex]The second part of the trip there was no traffic so she could drive 44 mph;
[tex]v_2=44[/tex]She traveled for a total of 5 hours;
[tex]t=5[/tex]let x represent the time in traffic when she traveled at 16 mph
[tex]t_1=x[/tex]the time the traffic is clear would be;
[tex]t_2=t-t_1=5-x[/tex]Recall that distance equals speed multiply by time;
[tex]d=v_1t_1_{}_{}^{}+v_2t_2[/tex]substituting the values;
[tex]136=16x+44(5-x)[/tex]solving for x;
[tex]\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}[/tex]So;
[tex]\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}[/tex]Therefore, In traffic, she drove for 3 hours
and After the traffic cleared she drove for 2 hours.
what is 5x6 I need help
Thus, the required solution is 30.
Answer: 30
Step-by-step explanation: 30
Elena has two aquariums each shaped like a rectangular prism. For each question explain or show your reasoning. A) One aquarium has a length of 7/2 feet a width of 4/3 feet and a height of 3/2 feet. What is the volume of the aquarium.
In may 2020, there were 2,119,800 people in the available labor force in oregon. the unemployment rate in oregon for may 2020 was 14.2%. determine the number of people who were unemployed in oregon during may 2020. round your answer to the nearest whole number.
301,012
1) Considering the data, we can write out the following equivalence:
[tex]\begin{gathered} 2,119,800---100\% \\ x--------14.2\% \end{gathered}[/tex]2) Notice that we need to rewrite those figures as 100% =1, and 14.2% as 0.142.
Now we can calculate how many people are equivalent to that rate of unemployment:
[tex]\begin{gathered} \frac{2119800}{x}=\frac{1}{0.142} \\ x=2119800\cdot0.142 \\ x=301,011.6\approx301,012 \end{gathered}[/tex]Notice that we rounded off to the nearest whole number.
3) So, there were approximately 301,012 Oregonians unemployed at that time
Solve the following system of equation using substitution4x + 2y = 10x - y= 13What is the solution for y?
ANSWER
y = -7
EXPLANATION
To solve using the substitution method we have to clear x from one of the equations as a function of y. For example, for equation 2:
[tex]x=13+y[/tex]Then replace x in the first equation by this expression:
[tex]4(13+y)+2y=10[/tex]And solve for y:
[tex]\begin{gathered} 4\cdot13+4y+2y=10 \\ 52+6y=10 \\ 6y=10-52 \\ 6y=-42 \\ y=\frac{-42}{6} \\ y=-7 \end{gathered}[/tex]Find the 52nd term.16, 36, 56, 76,…
Answer:
[tex]\text{ a}_{52}\text{ = 1,036}[/tex]Explanation:
Here, we want to find the 52nd term of the sequence
What we have to do here is to check if the sequence is geometric or arithmetic
We can see that:
[tex]\text{ 36-16 = 56-36=76-56 = 20}[/tex]Since the difference between the terms is constant, we can say that the terms have a common difference and that makes the sequence arithmetic
The nth term of an arithmetic sequence can be written as:
[tex]\text{ a}_n\text{ = a +(n-1)d}[/tex]where a is the first term which is given as 16 and d is the common difference which is 20 from the calculation above. n is the term number
We proceed to substitute these values into the formula above
Mathematically, we have this as:
[tex]\begin{gathered} a_{52}\text{ = 16 +(52-1)20} \\ a_{52}\text{ = 16 + (51}\times20) \\ a_{52}\text{ = 16 + 1020 = 1,036} \end{gathered}[/tex]Hi, I always have a hard time with these, the whole question is in the picture.
we have that
x1 ----> number of cars with a 7,000 gal capacity
x2 ---> number of cats with a 14,000 gal capacity
x3 ---> number of cars with a 28,000 gal capacity
so
7000x1+14000x2+28000x3=462000
using a 3x3 system of equations solver
the solution is
x1=-2s-4t+66
x2=s
x3=t
The answer is option B
1 x(x-2) how I do this
x(x-2)
Apply the distributive property:
x(x)+x(-2)
x^2-2x
Dave has a collection of 60 DVDs. One quarter of them are action mc
What is the ratio of the number of action DVDs to all ofner genres?
Answer:
15:45 i think
Step-by-step explanation:
25% of 60 is 15
60-15=45
15:45
You have a huge review project for English where you have to answer 300 questions. You start on it after school at 5:00. At 6:30, you have answered 55 questions.What time will you finish your assignment if you don't take any breaks?
Given :
The total questions = 300
Time of starting = 5:00
At 6:30 the number of answered questions = 55
The time spent to answer 55 questions = 6:30 - 5:00 = 1:30 hours
Which is equal to : 1 hour and 30 minutes = 90 minutes
So, the rate of answering the questions =90/55 = 18/11 minute per question
So, for solving the 300 questions, the time will be :
[tex]300\cdot\frac{18}{11}=490\frac{10}{11}\min [/tex]So, 490 10/11 minutes = 8 hours and
Given parallelogram JKLM, what could the expression 180 - (3x + 8) represents? Explain.
Based on the given figure, you can conclude:
The expression 180 - (3x + 8) represents a supplementary angle to the angle (3x + 8). This angle would be an angles subtended from side KL to a line that is a prolongation of line JK.
Find the common difference of the arithmetic sequence 5,14,23
The Solution.
The given sequence is
[tex]5,14,23[/tex]The common difference of the arithmetic sequence is given by the formula below:
[tex]\text{common difference(d)=T}_2-T_1=T_3-T_2[/tex]In this case,
[tex]T_1=5,T_2=14,T_3=23[/tex]Substituting these values in the formula above, we get
[tex]\begin{gathered} \text{common difference = 14-5=23-14}=9 \\ \text{common difference}=9 \end{gathered}[/tex]So,the correct answer is 9.
what is the image of 2,10 after a dilation by a scale factor of 1/2 centered at the origin
A dilation is given by:
[tex](x,y)\rightarrow(kx.ky)[/tex]where k is the scale factor.
In this case we have:
[tex](2,10)\rightarrow(\frac{1}{2}\cdot2,\frac{1}{2}\cdot10)=(1,5)[/tex]Therefore the image is the point:
[tex](1,5)[/tex]Using the equation and the ordered-pairs found previously, plot the points on the graph that would best satisfy theequation.y= 2^x
Given the following equation:
[tex]y=x^2[/tex]We will graph the given function using the points that will be written in ordered-pairs.
The given function is a quadratic function with a vertex = (0, 0)
We will graph the points using five points
The vertex and 4 points, 2 points before the vertex and 2 points after the vertex.
So, we will substitute x = -4, -2, 2, 4
[tex]\begin{gathered} x=-4\rightarrow y=16 \\ x=-2\operatorname{\rightarrow}y=4 \\ x=2\operatorname{\rightarrow}y=4 \\ x=4\operatorname{\rightarrow}y=16 \end{gathered}[/tex]So, the points are: (-4, 16), (-2, 4), (0, 0), (2, 4), (4, 16)
The graph using the points will be as follows:
follow the order of operations and evaluate the exponential expression (5+1)^2-(9-5)^2x3
Justin earns a base salary of $1500 per month at
the jewelry shop. He also earns a 3% commission
on all sales. If Just sold $82,975 worth of jewelry
last month, how much would he make for the
month including his base salary and commission?
The total salary earned by the Justin including the commission is $3959.25.
What exactly is the commission?A commission is extra money earned based on job performance.Members believe to be paid a specified amount of money depending on achievement marketed, sessions closed, recruits placed, and so on—when they agree to a commission-based position as well as commission framework (more by signing the agreement).For the given question;
The base salary of Justin is $1500.
The commission earned by Justin is 3%.
The jewelry of worth $82,975 last month.
Let x be the total commission earned.
Then,
3% of 82,975 = x
x = 3× 82,975 / 100
x = $2489.25
Total salary = base salary + commission
Total salary = $1500 + $2489.25
Total salary = $3959.25
Thus, the total salary earned by the Justin including the commission is $3959.25.
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Jordan’s of Boston sold Lee Company of New York computer equipment with a $7,000 list price. Sale terms were 4/10, n/30 FOB Boston. Jordan’s agreed to pay the $400 freight. Lee pays the invoice within the discount period. What does Lee pay Jordan’s?
Finding the area of unusual shapes
The shape in question is a composite shape.
It comprises two(2) shapes which are a triangle and a semi-circle.
The area of the shape is the sum of the area of the triangle and that of the semi-circle
The area of the triangle is:
[tex]A_{triangle}=\frac{1}{2}\times base\times height[/tex][tex]\begin{gathered} \text{Base of the triangle =}6\text{ yard} \\ Height\text{ of the triangle= 4 yard} \end{gathered}[/tex]Thus,
[tex]\begin{gathered} A_{triangle}=\frac{1}{2}\times6\times4 \\ A_{triangle}=12\text{ yards} \end{gathered}[/tex]Area of the Semi-circle is:
[tex]A_{semi-circle}=\frac{\pi\times r^2}{2}[/tex][tex]\begin{gathered} \text{Diameter of the circle=6 yard} \\ \text{Radius}=\frac{Diameter}{2} \\ \text{Radius}=\frac{6}{2}=3\text{ yard} \end{gathered}[/tex][tex]\begin{gathered} A_{semi-circle}=\frac{3.14\times3^2}{2} \\ A_{semi-circle}=\frac{28.26}{2} \\ A_{semi-circle}=14.13\text{ yard} \end{gathered}[/tex]Hence, the area of the composite shape is:
[tex]\begin{gathered} \text{Area of the triangle + Area of the semi-circle} \\ 12+14.13=26.13\text{ yard} \end{gathered}[/tex]Identify the domain and range of the relation. Is the relation a function? Why or why not?
{(-3, 1), (0, 2), (1, 5), (2, 4), (2, 1)}
Domain: {-3, 0, 1, 2}
Range: {1, 2, 4, 5}
The relation is not a function because one of its x-values has two corresponding y-values.
What is the Domain and Range of a Relation?All the set of values of x in a relation are referred to as the range of a relation, while all the set of values of y in a relation are called the domain of the relation.
How to Determine if a Relation is a Function?If each of the x-values in a relation all have only one possible corresponding y-value, then the relation is a function.
Given the relation, {(-3, 1), (0, 2), (1, 5), (2, 4), (2, 1)}:
The domain is: {-3, 0, 1, 2}
The range is: {1, 2, 4, 5}
The relation has two y-values, 4 and 1, that corresponds to the x-value, 2. Therefore, it is not a function.
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The given relation is not a function because its x-values have two corresponding y-values. Domain: {-3, 0, 1, 2} and Range: {1, 2, 4, 5}
What is the Domain and Range of a Relation?The domain of a function is the set of all the possible input values that are valid for the given function.
The range of a function is the set of all the possible output values that are valid for the given function.
Given the relation as {(-3, 1), (0, 2), (1, 5), (2, 4), (2, 1)}
Therefore,
The domain will be: {-3, 0, 1, 2}
The range will be: {1, 2, 4, 5}
The relation has two y-values, 4 and 1, which corresponds to the x-value, 2.
The given relation is not a function because its x-values have two corresponding y-values. Domain: {-3, 0, 1, 2} and Range: {1, 2, 4, 5}
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simplify the following expression using the distributive property and combining like terms:3(y-4) -5(y+8)
3(y-4) - 5(y+8)
3y - 12 - 5y - 40
-2y - 52
What is 16m + 24n? (P.S, this is about factoring expressions.)
aWe can factorize by a common factor
[tex]16m+24n[/tex][tex](8\times2)m+(8\times3)n[/tex][tex]8(2m+3n)[/tex]ANSWER
8(2m+3n)
how can i get an elimination out of this equatio
The simultaneous equations are:
[tex]\begin{gathered} -2x+7y=-23 \\ 6x-7y=-1 \end{gathered}[/tex]Since, the unknown y has the same co-efficient across the two(2) equations, we can eliminate it directly.
Thus, we have:
[tex]\begin{gathered} -2x+7y=-23 \\ 6x-7y=-1 \\ ----------- \\ -2x+6x=-23-1 \\ 4x=-24 \\ x=\frac{-24}{4} \\ x=-6 \end{gathered}[/tex]To find y, substitute for x = -6 into any of the equations.
Thus, we have:
[tex]\begin{gathered} \text{from equation i)} \\ -2x+7y=-23 \\ -2(-6)+7y=-23 \\ 12+7y=-23 \\ 7y=-23-12 \\ 7y=-35 \\ y=-\frac{35}{7} \\ y=-5 \end{gathered}[/tex]Hence, the correct option is option A
Consider the function y = f(x) shown at right, trace each interval where the function behavior is A. Increasing, using a GREEN pencil Identify the interval(s) ___B. Decreasing, using a RED pencil Identify the interval(s) ___ C. Constant, using a YELLOW pencil Identify the interval(s) ___ D. State the Domain of the function ___ E. State the Range of the function ___ F. What thoughts do you have about the intervals stated above? Did you use brackets (closed/included points) or parentheses (open/non-included points)? Why or why not?
You have a function f(x). To identify the increasing interval and decreasing interval of f(x), you consider that an increasing interval is determined by the values of x in which the value of f(x) increases. For the decreasing interval you focus on the values of x in which the values of f(x) decreases.
You can notice in the given graph:
The increasing interval is (-8 , -4) U (3 , 6)
The decreasing interval is (-4 , -2)
The constant interval is (-2 , 3)
The domain of the function is (-8 , 6)
The previous interval is given by the available values of x
The range of the function is (-4 , 8)
The previos interval is given by the values of f(x) for the values of x in the domain.
The following image is a sketch of the graph with the respective intervals.
Plot the x-intercept and y-intercepts to graph the equationy = 1/3x - 1
The equation is written in the slope-intercept form:
[tex]y=mx+b[/tex]Where:
m = Slope
b = y-intercept
From the equation we can conclude that the y-intercept is:
[tex](0,-1)[/tex]We can find the x-intercept as follows:
[tex]\begin{gathered} y=0 \\ \frac{1}{3}x-1=0 \\ \frac{1}{3}x=1 \\ x=3 \end{gathered}[/tex]The x-intercept is:
(3,0)
The graph is:
[tex]undefined[/tex]3. A square has sides of length 612 inches. Area of length times width.
What is the area of the square in square inches?
The area of the square in square inches is 374544 inches².
How to find the area of a square?A square is a quadrilateral with 4 sides equal to each other. Opposite sides of a square is parallel to each other.
Each angle of a square is 90 degrees.
Therefore,
area of square = l²
where
l = side lengthTherefore,
The square has a side length of 612 inches. The area of the square can be found as follows:
area of square = l²
l = 612 inches
Hence,
area of square = 612²
Therefore,
area of the square = 612 × 612
area of the square = 374544 inches²
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Write the following linear equation in function notation. Y = 2x + 5a.) f(y) = 2x+ 5b.) f = 2x + 5c.)f(x) = 2x + 5d.)It is already written in function notation
Answer
Option C is correct.
The function notation
Explanation
A Ferris wheel at a carnival has a diameter of 72 feet. Suppose a passenger is traveling at 5 miles per hour. (A useful fact: =1mi5280ft.)
(a) Find the angular speed of the wheel in radians per minute.
(b) Find the number of revolutions the wheel makes per hour. (Assume the wheel does not stop.)
a) The Ferris wheel has an angular speed is 12.222 radians per minute.
b) The Ferris wheel makes 116.712 revolutions in an hour.
How to understand and analyze the kinematics of a Ferris wheel
Kinematics is a branch of mechanical physics that studies the motion of objects without considering its causes. In other words, kinematics studies displacements, velocities and accelerations in translation, rotation and combined motion. In this case we find a Ferris wheel rotating around its axis at constant rate.
a) Then, the angular speed (ω), in radians per minute, is determined by the following product:
ω = v / R
Where:
v - Linear velocity at the rim of the Ferris wheel, in feet per second.R - Radius of the Ferris wheel, in feet.Please notice that the length of the radius is the half of the length of the diameter.
If we know that v = 5 mi / h and R = 36 feet, then the angular speed of the wheel is:
ω = [(5 mi / h) · (1 h / 60 min) · (5280 ft / 1 mi)] / [(0.5) · (72 ft)]
ω = 12.222 rad / min
The angular speed is 12.222 radians per minute.
b) A revolution is equal to an angular displacement of 2π radians and an hour is equal to 60 minutes. Then, we can derive the number of revolutions in an hour by dimensional analysis:
n = (12.222 rad / min) · (1 rev / 2π rad) · (60 min / h)
n = 116.712 rev / h
There are 116.712 revolutions in an hour.
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A chocolate chip cookie recipe ask for 1 1/2 times as much flour as chocolate chips if 3 1/2 cups of flour is used what quantity of chocolate chips would then be needed according to the recipe
Given:
Amount of chocolate chips needed = 1 1/2 times as much floor.
Amount of floor used = 3 1/2 cups.
Let's find the quantity of chocolate chips that would be needed according to the recipe.
To find the amount of chocolate chips used, we have:
Amount of chocolate chips
[tex]undefined[/tex]Write each of the following products (the result to a multiplication problem) using exponents to express the results in a simpler form.(3a)(5a) __________(5p)(2p) ___________(3 inches)(5 inches)___________(5 feet)(2 feet)_________
Let's do the mutiplications:
(3a)(5a) = 15a²
(5p)(2p) = 10p²
(3 inches)(5 inches) = 15 inches²
(5 feet)(2 feet) = 10 feet²mutiplic
Determine whether each linear function is a direct a variation. If so, state the constant of variation. If not, explain why notI need help for number 6
In direct variation function, variables x and y are related by the next formula:
y = kx
where k is the constant of variation.
Isolating k for the above formula, we get:
k = y/x
Computing y divided by x with the values of the table:
[tex]\frac{5}{10}\ne\frac{6}{11}\ne\frac{7}{12}\ne\frac{8}{13}[/tex]Given that all the quotients are different, then the linear function is not a direct variation
