for each triangle list the sides in order from shortest to longest explain your reasoning with words or numbers for the order

For Each Triangle List The Sides In Order From Shortest To Longest Explain Your Reasoning With Words

Answers

Answer 1

a. For the first triangle ,

Two angles are given. To determine the third angle apply the property of triangle which is sum of the angles of the triangle is 180 degree.

[tex]27^{\circ}+82^{\circ}+\angle T=180^{\circ}[/tex][tex]\angle T=180^{\circ}-27^{\circ}-82^{\circ}=71^{\circ}[/tex]

The triangle angles and sides relationship-

The longest side of a triangle is opposite the biggest angle measure.

The shortest side of a triangle is opposite the smallest angle measure in a triangle.

Therefore,

The shortest side is side opposite to the smallest angle that is MT.

The largest side is side opposite to the largest angle that is AT.

Hence the order for the sides from shortest to largest is

[tex]MT

b. The triangle is given . First determine the value of x and find the angle using the property of triangle which is sum of the angles of the triangle is 180 degree.

[tex]8x-1+3x+4+3x+9=180^{\circ}[/tex][tex]14x+12=180[/tex][tex]14x=168[/tex][tex]x=12[/tex]

The angles obtained are

[tex](8x-1)=95,(3x+4)=40,(3x+9)=45[/tex]

We know that the longest side of a triangle is opposite the biggest angle measure.

The shortest side of a triangle is opposite the smallest angle measure in a triangle.

Hence the shortest side is JK and largest side is JL.

Hence the order for the sides from shortest to largest is

[tex]JK

Related Questions

A window washer drops a tool from their platform 155ft high. The polynomial -16t^2+155 tells us the height, in feet, of the tool t seconds after it was dropped. Find the height, in feet, after t= 1.5 seconds.

Answers

The answer is is pie

17. 19yd. 28in.- 16yd. 31in.18. 61wk. 4da.- 18wk. 6da.21. 8tbsp. 2tsp. * 15

Answers

We need to solve the next expressions:

17. 19yd. 28in.- 16yd. 31in

We need to solve subtract each expression.

Then:

19yd. 28in.- 16yd. 31in =

19yd - 16yd and 28in-31in

3yd -3in

Then, we have the next equivalent.

1 yard = 36 in

So:

36 in - 3 in = 33 in

Therefore

19yd. 28in.- 16yd. 31in = 2 yard 33

18 61wk. 4da.- 18wk. 6da.

We need to subtract both expression:

Then

61wk - 18wk = 43kw

4da-6da = -2da

Where 1 week = 7 days

Then

7 da - 2da = 5 da

Hence, 43kw -1 wk = 42 wk.

The result is:

42 wk 5 da

21. 8tbsp. 2tsp. * 15

We need to convert 2ts into tbsp and then multiply the result by 15.

If

1 tsp ------- 0.333tbsp

Then

2tp ------ 2(0.333tbsp)= 0.66666 tbsp

Now

(8tbsp + 0.6666 ) * 15 = 130 tbsp

y = 3× - 1y = -3× + 1

Answers

Given two equations,

[tex]\begin{gathered} y=3x-1 \\ y=-3x+1 \end{gathered}[/tex]

Comapring both equations,

[tex]\begin{gathered} 3x-1=-3x+1 \\ 3x+3x=1+1 \\ 6x=2 \\ x=\frac{2}{6}=\frac{1}{3} \end{gathered}[/tex]

Therefore, x = 1/3.

a wall in marcus bedroom is 8 2/5 feet high and 16 2/3 feet long. of he paints 1/2 of the wall blue, how many square feet will be blue?140128 2/157064 2/15

Answers

Answer:

[tex]70[/tex]

Explanation:

What we want to answer in this question is simply, the area of the room that will be painted blue if he decides he would paint exactly have the room blue

So, we need to simply get the area of the room and divide this by half

Mathematically, the area of a rectangle is the product of its two sides

Thus, we have it that the area of the room is:

[tex]\begin{gathered} 8\frac{2}{5}\times16\frac{2}{3} \\ \frac{42}{5}\times\frac{50}{3}\text{ = 14}\times10=140ft^2 \end{gathered}[/tex]

Now, to get the area painted blue, we divide this by 2 as follows or multiply by 1/2

We have this as:

[tex]140\times\frac{1}{2}=70ft^2[/tex]

How do you decide which rational number operations to use to solve problems

Answers

One can decide which rational number operations to use to solve problems based on the context of the information.

What is a rational number?

Studying rational numbers is significant because they illustrate how the world is so complex that we will never be able to comprehend it.

A rational number is defined as the ratio or fraction p/q of two numbers, where p and q are the numerator and denominator, respectively. Every integer and 3/7, for example, are rational numbers.

A rational number is defined as the quotient of the fraction p/q of two integers, a numerator p and a non-zero denominator q. Every integer is a rational number since q might be equal to 1.

In this case, the operation include addition, subtraction, division, etc. This will be based on the context.

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A statement of Chandler's biweekly earnings is given below. What is Chandler's gross pay?

Answers

SOLUTION:

Step 1:

In this question, we are asked to calculate Chandler's gross pay from the statement of bi-weekly earnings.

Step 2:

To get the Gross pay, we need to do the following:

[tex]\text{Gross pay - Total Deductions = Net Pay}[/tex]

Now, we need to calculate Total Deductions:

[tex]\text{ \$ 105.00 + \$ 52.14 + \$ 10.62 + \$ 26. 15 = \$ 193.91}[/tex]

Now, we have that the Net Pay = $ 780. 63

Then,

[tex]\begin{gathered} \text{Gross Pay - \$ 193. 91 = \$ 7}80.\text{ 63} \\ \text{Gross pay = \$ 780.63 + \$ 193.91} \\ \text{Gross Pay = \$ 974. 54} \end{gathered}[/tex]

CONCLUSION:

Chandler's Gross Pay = $ 974. 54

The function used to compute the probability of x successes in n trials, when the trials are dependent, is the _____. a.binomial probability functionb.Poisson probability functionc.hypergeometric probability functiond.exponential probability function

Answers

Given:

The function used to compute the probability of x successes in n trials, when the trials are dependent.

Required:

To choose the correct option for the given statement.

Explanation:

The hypergeometric distribution is a discrete probability distribution. It is used when you want to determine the probability of obtaining a certain number of successes without replacement from a specific sample size.

Therefore the option c is correct.

Final Answer:

c ) hypergeometric probability function.

draw a right triangle with a leg that as a length of 10 and the angle opposite to that side is 55 degrees. find the length of the hypotenuse. round your answer to nearest tenth.

Answers

Question:

Draw a right triangle with a leg that has a length of 10 and the angle opposite to that side is 55 degrees. find the length of the hypotenuse. round your answer to the nearest tenth.​

Solution:

A right triangle with a leg that has a length of 10 and the angle opposite to that side is 55 degrees is given by the following picture:

In this case, the appropriate trigonometric identity is:

[tex]\sin (55^{\circ})\text{ = }\frac{y}{h}[/tex]

where y is the opposite side, and h is the hypotenuse. Now, replacing the given data in the previous equation we obtain:

[tex]\sin (55^{\circ})\text{ = }\frac{10}{h}[/tex]

and solving for h, we get:

[tex]h\text{ = }\frac{10}{\sin (55^{\circ})}\text{ = 12.207}\approx12.21[/tex]

then, the correct answer is:

[tex]h\text{ =}12.21[/tex]

Point M is the midpoint of AB. If AM = b² + 5b and
MB = 3b + 35, what is the length of AM?

Answers

Step-by-step explanation:

since M is the midpoint, it means that AM = MB.

so,

b² + 5b = 3b + 35

b² + 2b - 35 = 0

the general solution to such a quadratic equation

ax² + bx + c = 0

is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case (x is called b, don't get confused, as this is not the factor of x) this gives us

b = (-2 ± sqrt(2² - 4×1×-35))/(2×1) =

= (-2 ± sqrt(4 + 140))/2 = (-2 ± sqrt(144))/2 =

= (-2 ± 12)/2 = -1 ± 6

b1 = -1 + 6 = 5

b2 = -1 - 6 = -7

therefore, we have 2 solutions

b = 5

AM = 5² + 5×5 = 25 + 25 = 50

b = -7

AM = (-7)² + 5×-7 = 49 - 35 = 14

control, as AM = MB

MB = 3×5 + 35 = 15 + 35 = 50

or

MB = 3×-7 + 35 = -21 + 35 = 14

AM = MB in both cases, so, all is correct.

Consider the circle x ^ 2 + y ^ 2 = 100 and the line x + 3y = 10 and their points of intersection (10, 0) and B = (- 8, 6) . Find coordinates for a point C on the circle that makes chords AB and AC have equal length . Be sure to justify your answer.

Answers

The equation of circle is given by,

[tex]x^2+y^2=100\text{ ---(1)}[/tex]

The equation of line is given by,

[tex]x+3y=10\text{ ---(2)}[/tex]

The points of intersection of the circle and line is,

A=(Xa, Ya)=(10, 0)

B=(Xb, Yb)=(-8, 6)

The length of chord AB can be calculated using distance formula as,

[tex]\begin{gathered} AB=\sqrt[]{(X_b-X_a)^2+(Y_b-Y_a)^2} \\ =\sqrt[]{(-8-10)^2+(6-0)^2} \\ =\sqrt[]{(-18)^2+6^2} \\ =\sqrt[]{324+36} \\ =\sqrt[]{360} \\ =6\sqrt[]{10} \end{gathered}[/tex]

Let (Xc, Yc) be the coordinates of point C on the circle. Hence, using equation (1), we can write

[tex]X^2_c+Y^2_c=100\text{ ---(3)}[/tex]

Using distance formula, the expression for the length of chord AC is given by,

[tex]AC=\sqrt[]{(X_c^{}-X_a)^2+(Y_c-Y_a)^2_{}}[/tex]

Since (Xa, Ya)=(10, 0),

[tex]\begin{gathered} AC=\sqrt[]{(X^{}_c-10_{})^2+(Y_c-0_{})^2_{}} \\ AC=\sqrt[]{(X^{}_c-10_{})^2+Y^2_c} \end{gathered}[/tex]

It is given that chords AB and AC have equal length. Hence, we can write

[tex]\begin{gathered} AB=AC \\ 6\sqrt[]{10}=\sqrt[]{(X^{}_c-10_{})^2+Y^2_c} \end{gathered}[/tex]

Squaring both sides of above equation,

[tex]\begin{gathered} 360=(X^{}_c-10_{})^2+Y^2_c\text{ } \\ (X^{}_c-10_{})^2+Y^2_c=360\text{ ----(4)} \end{gathered}[/tex]

Subtract equation (4) from (3) and solve for Xc.

[tex]\begin{gathered} (X^{}_c-10_{})^2-X^2_c=360-100 \\ X^2_c-2\times X_c\times10+100-X^2_c=260 \\ -20X_c=260-100 \\ -20X_c=160 \\ X_c=\frac{160}{-20} \\ X_c=-8 \end{gathered}[/tex]

Put Xc=-8 in equation (3) to find Yc.

[tex]\begin{gathered} (-8)^2+Y^2_c=100 \\ 64+Y^2_c=100 \\ Y^2_c=100-64 \\ Y^2_c=36 \\ Y^{}_c=\pm6 \\ Y^{}_c=6\text{ or }Y_c=-6 \end{gathered}[/tex]

So, the coordinates of point C can be (Xc, Yc)=(-8, 6) or (Xc, Yc)=(-8, -6).

Since (-8, 6) are the coordinates of point B, the coordinates of point C can be chosen as (-8, -6).

Therefore, the coordinates of point C is (-8, -6) if chords AB and AC have equal length.

what is the solution to the system 3x-y+5=02x+3y-4=0A. X= -1, Y= -2B. X= -1, Y= 2C. X= 2, Y= -1D. X= 2, Y= 1

Answers

To find the solution to the system of equation

we will use the elimination method

3x - y = - 5 ----------------------------(1)

2x + 3y = 4 -------------------------------(2)

We will eliminate y and solve for x

multiply equation (1) through by 3

9x - 3y = - 15 ------------------------------------(3)

add equation (2) and equation (3)

11x = -11

divide both-side of the equation by 11

x = -1

substitute x = -1 in equation (1) and solve for y

3x - y = - 5

3(-1) - y = -5

-3 - y = -5

add 3 to both-side of the equation

- y = -5 +3

-y = -2

multiply through byb -1

y = 2

Hence, the correct option is B

2625÷32 long division way​

Answers

Answer: 82 R1 or decimal form 82.031

Step-by-step explanation:

0082

. --------

-0

26

. - 0

. 262

. -256

65

-64

. 1

Jim baked 48 cookies with 4 scoops of flour. How many scoops of flour does Jim need in orderto bake 96 cookies? Assume the relationship is directly proportional.

Answers

Given:

Jim baked 48 cookies with 4 scoops of flour.

So, the unit rate will be = 48/4 = 12 cookies/scoop of flour

So, for 96 cookies, the number of scoops of flour will be =

96/12 = 8

So, the answer will be 8 scoops of flour

Im confused on what you have to do in order to find the answer

Answers

Given:

The ship is moved from (-10,9) to (-1,-5) in the coordinate plane.

To find:

The transformation rule

Explanation:

The initial point can be written to obtain the terminal point as follow,

[tex](-10+9,9-14)\rightarrow(-1,-5)[/tex]

In general,

We write,

[tex](x,y)\rightarrow(x+9,y-14)[/tex]

Final answer: Option C.

[tex](x,y)\operatorname{\rightarrow}(x+9,y-14)[/tex]

Find the interest and future value of a deposit of $12,000 at 5.5% simple interest for 10 years.

Answers

Given:

Principal - $12,000

Annual Interest Rate = 5.5% or 0.055 in decimal form

Time in years = 10 years

Find: simple interest and future value

Solution:

The formula for getting the simple interest is:

[tex]Interest=Principal\times Rate\times Time[/tex]

Let's replace the variables in the formula with their corresponding numerical value.

[tex]Interest=12,000\times0.055\times10[/tex][tex]Interest=6,600[/tex]

The interest after 10 years is $6, 600.

So, if the interest is 6,600, the future value of the money is:

[tex]FV=Principal+Interest[/tex][tex]FV=12,000+6,600[/tex][tex]FV=18,600[/tex]

The future value of the deposited money after 10 years is $18, 600.

In 1990, the cost of tuition at a large Midwestern university was $104 per credit hour. In 1998, tuition had risen to $184 per credit hour.

Answers

We have to find the linear relationship for the cost of tuition in function of the year after 1990.

The cost in 1990 was $104, so we can represent this as the point (0, 104).

The cost in 1998 was $184, so the point is (8, 184).

We then can calculate the slope as:

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{184-104}{8-0} \\ m=\frac{80}{8} \\ m=10 \end{gathered}[/tex]

We can write the equation in slope-point form using the slope m = 10 and the point (0,104):

[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-104=10(x-0) \\ y=10x+104 \end{gathered}[/tex]

We can then write the cost c as:

[tex]c=10x+104[/tex]

We then can estimate the cost for year 2002 by calculating c(x) for x = 12, because 2002 is 12 years after 1990.

We can calculate it as:

[tex]\begin{gathered} c=10(12)+104 \\ c=120+104 \\ c=224 \end{gathered}[/tex]

Now we have to calculate in which year the tuition cost will be c = 254. We can find x as:

[tex]\begin{gathered} c=254 \\ 10x+104=254 \\ 10x=254-104 \\ 10x=150 \\ x=\frac{150}{10} \\ x=15 \end{gathered}[/tex]

As x = 15, it correspond to year 1990+15 = 2005.

Answer:

a) c = 10x + 104

b) $224

c) year 2005.

Find the principal which amounts to #5,000 at simple interestin 5 years at 2% per annum

Answers

To answer this we have to apply the simple interest formula:

I =P x r x t

Where:

I= interest

P= Principal

R= Interest rate ( in decimal form)

t = time (years)

Replacing with the values given:

Interest= I

Principal = ?

Interest rate = 2/100 =0.02

time= 5 years

I = P x 0.02 x 5

I= 0.1P

Amount= P+I

A = P+0.1P

5,000= P+0.1P

5,000= 1.1P

5,000/1.1 =P

4,545.45 =P

Eliana drove her car 81 km and used 9 liters of fuel. She wants to know how many kilometres she can drive on 22 liters of fuel. She assumes her car will continue consuming fuel at the same rate. How far can Eliana drive on 22 liters of fuel? What if Eliana plans to drive from Dubai to Abu Dhabi via Sheikh Zayed Bin Sultan which is 139.4 km? How many liters of fuel does she need?

Answers

Eliana can drive 198 km with 22 liters of fuel.

If Eliana plans to drive from Dubai to Abu Dhabi via Sheikh Zayed Bin Sultan which is 139.4 km then she would need 15.5 liters of fuel

In this question, we have been given Eliana drove her car 81 km and used 9 liters of fuel.

81 km=9 liters

9 km= 1 liter

She wants to know the distance she can drive on 22 liters of fuel. She assumes her car will continue consuming fuel at the same rate.

By unitary method,

22 liters = 22 × 9 km

              = 198 km

Also, given that  if Eliana plans to drive from Dubai to Abu Dhabi via Sheikh Zayed Bin Sultan which is 139.4 km.

We need to find the amount of fuel she would need.

Let 139.4 km = x liters

By unitary method,

x = 139.4 / 9

x = 15.5 liters

Therefore, Eliana can drive 198 km with 22 liters of fuel.

If Eliana plans to drive from Dubai to Abu Dhabi via Sheikh Zayed Bin Sultan which is 139.4 km then she would need 15.5 liters of fuel

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Approximate the intervals where each function is increasing and decreasing.

Answers

1)

[tex]\begin{gathered} \text{Increasing:} \\ I\colon(-1.2,2)\cup(1.2,\infty) \\ \text{Decreasing:} \\ D\colon(-\infty,-1.2)\cup(2,1.2) \end{gathered}[/tex]

2)

[tex]\begin{gathered} \text{Increasing:} \\ I\colon(-3,0.5) \\ \text{Decreasing:} \\ D\colon(-\infty,-3)\cup(-0.5,\infty) \end{gathered}[/tex]

3)

[tex]\begin{gathered} \text{Increasing:} \\ I\colon(3,\infty) \\ \text{Decreasing:} \\ D\colon(-\infty,3) \end{gathered}[/tex]

4)

[tex]\begin{gathered} \text{Increasing:} \\ I\colon(-\infty,4) \\ \text{Decreasing:} \\ D\colon(4,\infty) \end{gathered}[/tex]

11) What is the area of the composite figure? *7 points6 ftT T2 ft5 ft3ft220O 212223

Answers

Answer: 22

Step-by-step explanation:

One pump can empty a pool in 7 days, whereas a second pump can empty the pool in 14 days. How long will it take the two pumps, working together, to empty the pool? (Fractional answers are OK.)The first pump's rate is_____per day.The second pump's rate is____per day.The combined pumps rate is____per day.It will take the two pumps_____per day.

Answers

The first step is to define the daily rates of each pump

From the information given,

First pump can empty the pool in 7 days. This means that

Daily rate of first pump = 1/7

The first pump's rate is 1/7 per day

Second pump can empty the pool in 14 days. This means that

Daily rate of second pump = 1/14

The second pump's rate is 1/14 per day

Let t be the number of days it will take both pumps, working together to empty the pool. Thus,

combined daily rate of both pumps = 1/t

The rates are additive. It means that

1/7 + 1/14 = 1/t

Simplifying the left side, we have

3/14 = 1/t

The combined pumps rate is 3/14 per day

By taking reciprocal of both sides,

t = 14/3 = 4.67

It will take the two pumps 4.67 days to empty the pool together

Use Descartes Rules of signs to complete the chart with possibilities for the nature of the roots of the following equations:A) x^3 - x^2 + 4x - 6 = 0B) x^5 - x^3 + x + 1 = 0

Answers

Given:

[tex]\begin{gathered} x^3-x^2+4x-6=0 \\ x^5-x^3+x+1 \end{gathered}[/tex]

Required:

To determine the possibilities for the nature of the roots of the given equation.

Explanation:

(A)

I have tried but but there is some part that i keep getting wrong

Answers

we have that

K is the center of circle

J -----> point of tangency

segment IK is a radius

segment JL is a chord

segment GI is a secant

segment JI is a diameter

segment GJ is a tangent

arc JIL is a major arc

arc JL is a minor arc

arc JLI is a half circle (180 degrees)

Part 2

we have that

arc TU=87 degrees -------> by central angle

arc ST

Remember that

arc ST+87+72=180 degrees ------> by half circle

so

arc ST=180-159

arc ST=21 degrees

arc WV

we have

arc WV+arc UV=180 degrees -----> by half circle

arc UV=72 degrees

so

arc WV=180-72

arc WV=108 degrees

arc VUT

arc VUT=arc VU+arc UT

substitute given values

arc VUT=72+87

arc VUT=159 degrees

arc WU=180 degrees -----> by half circle de

I need help for problem number 9. On the right side of the paper.

Answers

Constant of variation ( k ):

• y = 2/3

,

• x = 1/4

[tex]k=\frac{y}{x}=\frac{\frac{2}{3}}{\frac{1}{4}}=\frac{8}{3}[/tex]

k = 8/3

Based on k we can find the value of y when x =3/4 as follows:

[tex]\begin{gathered} k=\frac{y}{x} \\ y=k\cdot x \\ y=\frac{8}{3}\cdot\frac{3}{4}=2 \end{gathered}[/tex]

Answer:

• k = 8/3

,

• When ,x, = ,3/4,,, y = 2

Draw the angle 0=-pi/2 in standard position find the sin and cos

Answers

An angle in standard position has the vertex at the origin and the initial side is on the positive x-axis.

Thus, the initial side of the angle is:

Now, half the circumference measures pi, thus, pi/2 is a quarte of the circumference. As we want to find the angle -pi/2, then we need to rotate the terminal side clockwise:

Find the sine and the cosine.

The sine and the cosine in the unit circle are given by the coordinates as follows:

[tex](\cos\theta,\sin\theta)[/tex]

As can be seen in the given unit circle, the terminal side is located at:

[tex](0,-1)[/tex]

Thus, the values of cosine and sine are:

[tex]\begin{gathered} \cos\theta=0 \\ \sin\theta=-1 \end{gathered}[/tex]

200 lottery tickets are sold for $6 each. The person with the single winning ticket will get $71. What is the expected value for a ticket in this lottery?

Answers

Given:

200 lottery tickets are sold for $6 each.

The person with the single winning ticket will get $71.

So, The probability of winning = 1/200

The probability of losing =

[tex]undefined[/tex]

Answer: the expected value is. aroud 1-2

Step-by-step explanation:

16. Eric is deciding how many trees to plant.
Here are his estimates of the time it will take.
Number of trees
1 tree
2 trees
3 trees
4 trees
5 trees
Time
30 minutes
40 minutes
50 minutes
60 minutes
70 minutes

Answers

With each additional tree , the estimated time increases by 10 minutes .

in the question ,

a table with number of trees and time required to plant them is given .

For planting 1 tree 30 minutes is required to plant them .

for planting 2 trees 40 minutes is required to plant them .

increase in number of tree = 2 tree - 1 tree = 1 tree

change in time required = 40 min - 30 min = 10 min

for planting 3 trees , 50 minutes is required to plant them .

increase in number of tree = 3 trees - 2 trees = 1 tree

change in time required = 50 min - 40 min = 10 min

So, we can see that for every additional tree planted the time increases by 10 minutes .

Therefore , with each additional tree , the estimated time increases by 10 minutes .

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A gumball machine contains 5 blue gumballs and 4 red gumballs. Two gumballs are purchased, one after the other, without replacement.

Find the probability that the second gumball is red.

Answers

Answer:   4/9

===================================================

Work Shown:

5 blue + 4 red = 9 total

A = P(1st is red, 2nd is red)

A = P(1st is red)*P(2nd is red, given 1st is red)

A = (4/9)*(3/8)

A = 12/72

B = P(1st is blue, 2nd is red)

B = P(1st is blue)*P(2nd is red, given 1st is blue)

B = (5/9)*(4/8)

B = 20/72

C = P(2nd is red)

C = A+B

C = 12/72 + 20/72

C = 32/72

C = 4/9

Use the change of base formula and a calculator to evaluate the logarithm

Answers

The change of base formula states that:

[tex]\log _bx=\frac{\ln x}{\ln b}[/tex]

this means that we can caculate any logarithm using the natural logarithm if we make the quotient of the natural logarithm of the original value and the natural logarithm of the original base.

In this case we have:

[tex]\begin{gathered} x=14 \\ b=\sqrt[]{3} \end{gathered}[/tex]

Then, using the change of base formula, we have:

[tex]\log _{\sqrt[]{3}}14=\frac{\ln 14}{\ln \sqrt[]{3}}[/tex]

Once we have the expression we just evaluate the expression on the right to get the appoximation we need:

[tex]\log _{\sqrt[]{3}}14=\frac{\ln14}{\ln\sqrt[]{3}}\approx4.804[/tex]

Dianne is 23 years older than her daughter Amy. In 5 years, the sum of their ages will be 91. How old are they now?Amy is ? years old, and Dianne is ? years old.

Answers

Currently

Let Amy's current age be x. Since Dianne is 23 years older than her daughter, then she is (x + 23) years old.

In 5 years

Amy's age will be (x + 5) years.

Dianne's age will be:

[tex]x+23+5=(x+28)\text{ years}[/tex]

The sum of their ages in 5 years is 91. Therefore, we have:

[tex](x+5)+(x+28)=91[/tex]

Solving, we have:

[tex]\begin{gathered} x+5+x+28=91 \\ 2x=91-5-28 \\ 2x=58 \\ x=\frac{58}{2} \\ x=29 \end{gathered}[/tex]

Amy is 29 years old. Therefore, Dianne will be:

[tex]29+23=52\text{ years old}[/tex]

ANSWER:

Amy is 29 years old, and Dianne is 52 years old.

Other Questions
Assuming a fixed hourly pay rate, how much would an employee earn for working 4 hours based on this wage table? Hourly Pay Table Hours Worked 2 Money Earned $12.00 $24.00 $36.00 ? A. $36.00 B. $45.00 C. $64.00 D. $48.00 Determine the x-intercept for 3x + 2y = 14.A) (7,0) B) (0,7) C) (14/3,0) D) (0,14/3) How long can you lease the car before the amount of the lease is more than the cost of the car based on declining sales of its over-sized kites, kim's kites korp. is considering improving the over-sized kites, developing an entirely new product, or introducing a new marketing strategy for the existing kites to a different target market. what stage of the product life cycle is kim's kites experiencing? Use the Distributive Property to solve the equation 2/3 (9a + 6) = 23.8 Simplify: 15.4 + 3.02 Today, October 20, 2022, seven friends ate lunch together at Chipotle.Friend #1 eats there every day - including weekends.Friend #2 eats there every other day - including weekendsFriend #3 eats there every third day - including weekendsFriend #4 eats there every fourth day - including weekendsFriend #5 eats there every fifth day - including weekendsFriend #6 eats there every sixth day - including weekendsFriend #7 eats there every seventh day - including weekendsAssuming that none of them catch Covid or miss any days, what will be the date when the friends again all eat lunch together at Chipotle? make k the subject 2A= K^2 +3t IF YOU HAD A BUSINESS AND WANTED TO MAKE THE MOST PROFIT USING THE AGE-SEX DISTRIBUTION INFORMATION OF THE UNITED STATES POPULATION PYRAMID, WHAT TYPE OF PRODUCTS WOULD YOU SELL AND WHY? According to Newtons second law of motion,how much force will be required to accelerate an object at the same rate if it mass is reduced by half ? suppose that 70% of the total runtime of an application is consumed in carrying out floating-point operations. what will be the overall improvement in performance if: a. all of the floating-point operations can be sped up by a factor of 1.6? b. only 50% of the floating-point operations that are consumed in evaluating an expensive function can be sped up by a factor of 5? 1. Based on Homer's description of the Cyclopes (plural) in lines 109-120, predict what conflicts might arise for Odysseus and his men? 1. In the graph below, point D is reflected across the y-axis. What are the coordinates of itsimage?2(3,-1)(3, 1)(-3,-1)(-3, 1) Complete the sentences by choosing the correct wordor phrase from the box. There are two which you do notneed to use. (You may need to make small changes to theverbs.)acquaintance arrogant bossy competitivedown-to-earth easygoing sensitive fallout withget on with go out with make it up split up consider newton's 3rd law, the force that the earth exerts on a person will be equal and opposite that what the person applies to the earth. however, why don't we see the earth accelerate? true or false: under the terms of a standard universal policy, if beth stops paying her premiums, then the administrative fee and cost of death benefit will be deducted from the savings portion of her policy (assuming sufficient cash value accumulation,) and the policy will remain active. true knoll, incorporated, currently sells 15,000 units a month for $50 each, has variable costs of $20 per unit, and has fixed costs of $300,000. knoll is considering increasing the price of its units to $60 per unit. this will not affect costs, but demand is expected to drop 20%. should knoll increase the price of its product? brazilian coffee farmers have benefited from multiple choice the drop in the value of the brazilian real. the depreciation of the u.s. dollar. the drop in the price of robusta beans. the depreciation of the vietnamese dong. the sharp appreciation of the local currency. Suppose that you earn $15 (Score for Question 1: ___ of 5 points)1. Wendy wants to find the width, AB, of a river. She walks along the edge of the river 300 ft and markspoint C. Then she walks 80 ft further and marks point D. She turns 90 and walks until her location,point A, and point C are collinear. She marks point E at this location, as shown.AriverAD 80 ft300 ftBE(a) Can Wendy conclude that AABC and AEDC are similar? Why or why not?(b) Suppose DE = 50 ft Calculate the width of the river, AB. Show all your work.Answer