Answer:
f(-8)= -112
Step-by-step explanation:
-2(-8)^2 + 2(-8)
-2(-64) + 16
-128 + 16
= -112
hope this helped
have a good day :)
Select the correct answer.
What is the approximate value of this logarithmic expression?
log5 18
The logarithms as a sum or difference of logarithms, using the power rule if necessary, to expand them.
The approximate value exists [tex]$\log _5 18 \approx 1.80$[/tex].
What is meant by logarithmic expression?An equation using the logarithm of an expression containing a variable is referred to as a logarithmic equation. Check to verify if you can write both sides of the equation as powers of the same number before attempting to solve an exponential equation.
Write logarithms as a sum or difference of logarithms, using the power rule if necessary, to expand them. Utilizing the quotient rule, product rule, and power rule in that order is frequently beneficial.
The change of base formula can be used.
[tex]$\log _5(18)=\frac{\log 18}{\log 5} \approx \frac{1.25527}{0.69897} \approx 1.7959$$[/tex]
simplifying the above equation, we get
[tex]$\log _5 18 \approx 1.80$[/tex]
Therefore, the correct answer is option B. 1.80.
The complete question is:
Select the correct answer.
What is the approximate value of this logarithmic expression? [tex]$\log _5 18$[/tex]
A. 1.28
B. 1.80
C. 0.56
D. 2.89
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A student worked 51 hr during a week one summer. The student earned $5. 10 per hour for the first 40 hr and $7.65 per hour for overtime. How much did the student earn during the week?
We will determine the earnings for the week as follows:
[tex]W=40(5.10)+11(7.65)\Rightarrow W=288.15[/tex]So, the student earned $288.15 that week.
1. Juan bought fruit from the grocery store. The variables below define his purchase. Juan's bananas cost half as much as apples. Which equations can be used to model his purchase? Select each correct equation.* a = the number of apples he bought b = the number of bananas he bought x= the cost of an apple in dollars y= the cost of a banana in dollars A- a= 1/2 bb- y=1/2 xc- a=2bd- x=2ye- y=2af- b=1/2 x
Juan's bananas cost half ( 1/2) as much as apples.
x= the cost of an apple in dollars
y= the cost of a banana in dollars
Multiply the cost of an apple by 1/2 (half). that expression must be equal to the cost of a banana.
y = 1/2 x (option b)
Four more than three times a number, is less than 30. Which of the following is not a solution?61278
Solution
- To solve the question, we simply need to interpret the question line by line.
- Let the number be x.
- "Four more than three times a number" can be written as:
[tex]\begin{gathered} \text{ Three times a number is: }3x \\ \text{ For more than three times a number becomes: }4+3x \end{gathered}[/tex]- "Four more than three times a number is less than 30" can be written as:
[tex]4+3x<30[/tex]- Now, we can proceed to solve the inequality and find the appropriate range of x. This is done below:
[tex]\begin{gathered} 4+3x<30 \\ \text{ Subtract 4 from both sides} \\ 3x<30-4 \\ 3x<26 \\ \text{ Divide both sides by 3} \\ \frac{3x}{3}<\frac{26}{3} \\ \\ \therefore x<8\frac{2}{3} \end{gathered}[/tex]- This means that all correct solutions to the inequality lie below 8.666...
- This further implies that any number greater than this is not part of the solutions of the inequality.
- 12 is greater than 8.666
Final Answer
The answer is 12
Toni decides to plant a 2-foot wide rectangular flower garden along one side of the pool and patio but outside the fence. She measures the length of the fence to be 44 feet long. What is the area of the flower garden?
If she decides to plant a 2-foot wide rectangular flower garden along one side of the pool and patio but outside the fence. She measures the length of the fence to be 44 feet long. The area of the flower garden is 88 square feet.
Area of the flower gardenUsing this formula to determine the area of the flower garden
Area = Width × Length
Where:
Width = 2 feet
Length = 44 feet
Let plug in the formula
Area = 2 × 44
Area = 88 square feet
Therefore the area is 88 square feet.
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Look at the figure below. 8 8 4 4 Which expression can be evaluated to find the area of this figure?
Answer
[tex]8^2-4^2[/tex]Step-by-step explanation
The figure consists of a square with sides of 8 units from which a square of sides of 4 units has been subtracted.
The area of a square is calculated as follows:
[tex]A=a^2[/tex]where a is the length of each side.
Substituting a = 8, the area of the bigger square is:
[tex]A_1=8^2[/tex]Substituting a = 4, the area of the smaller square is:
[tex]A_2=4^2[/tex]Finally, the area of the figure is:
[tex]A_1-A_2=8^2-4^2[/tex]I need help finding 5 points. the vertex, 2 to the left of the vertex, and 2 points to the right of the vertex.
Let's convert the given equation first into a vertex form.
[tex]y=a(x-h)^2+k[/tex]where (h, k) is the vertex.
The vertex form of the equatio that we have is:
[tex]y=-2(x-0)^2+0[/tex]Hence, the vertex of the equation is at the origin (0, 0).
Since "a" is negative, our parabola is opening downward.
Let's identify two points to the left of the vertex. Let's say at x = -1. Replace "x" with -1 in the equation.
[tex]\begin{gathered} y=-2(-1)^2 \\ y=-2(1) \\ y=-2 \end{gathered}[/tex]Hence, we have a point to the left of the parabola at (-1, -2).
Let's say x = -2. Replace "x" with -2 in the equation.
[tex]\begin{gathered} y=-2(-2)^2 \\ y=-2(4) \\ y=-8 \end{gathered}[/tex]Hence, we also have another point to the left of the parabola at (-2, -8).
If our x is to the right of the vertex, say, x = 1. Replace "x" with 1 in the equation.
[tex]\begin{gathered} y=-2(1)^2 \\ y=-2(1) \\ y=-2 \end{gathered}[/tex]We have a point to the right of the parabola at (1, -2).
If x = 2, let's replace "x" with 2 in the equation.
[tex]\begin{gathered} y=-2(2)^2 \\ y=-2(4) \\ y=-8 \end{gathered}[/tex]Hence, we also have another point to the right of the parabola at (2, -8).
The graph of this equation is:
an athlete eats 45 g of protein per day while training. how much protein will she eat during 23 days of training?
SOLUTION
From the question, the athlete eats 45 g of protein in a day. This means that in 23 days the athlete will eat
[tex]\begin{gathered} 23\times45\text{ g of protein } \\ =23\times45 \\ =1,035g \end{gathered}[/tex]Hence the answer is 1 035 g of protein, or 1.035 kg of protein.
Note that: To change grams to kilograms, we divide by 100.
See photo for problem
Answer:
possible outcome= {H,T}
number of possible outcome=2
obtaining a tail(T)=1
n(T)=1
P(T)=n(T)/number of possible outcome
=1/2
In the accompanying diagram, three vertices of parallelogram ORST are O(0,0), R(b,d), and T(a,0). What are the coordinates of S?A. (a, b)B. (a+b, d)C. (a+b, b)D. (a, d)
In a parallelogram, the opposite sides are parallel.
This means that RS is parallel to OT. So, the y value of S is the same as the y value of R, which is d, so y = d. Thus:
[tex]S=(x,y)=(x,d)[/tex]Now, we need to find x.
Since the sides RO and ST are also parallel, the x distance from O to R is the same as the x distance from T to S.
The x distance from O to R is
[tex]b-0=b[/tex]The x distance from T to S is
[tex]x-a[/tex]Since these x distances are equal, then:
[tex]\begin{gathered} b=x-a \\ x=a+b \end{gathered}[/tex]Then, the coordinates of S are:
[tex](a+b,d)[/tex]Which corresponds to option B.
Miguel is judging an essay contest. He has to select the best, second best, and third best. If there are 6 essays entered, how many ways could he choose the top essays?
There are 120 ways to choose the top essays.
What is Multiplication?To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.
Given that;
There are 6 essays entered.
And, He has to select the best, second best, and third best.
Now,
Since, There are 6 essays entered.
Hence, The number of ways to choose the top essays = [tex]^{6} P_{3}[/tex]
= 6! / 3!
= 6×5×4
= 120
Thus, The number of ways = 120
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2x2 + 5 = 6x Solve using the quadratic formula with the answer as a+bi form
Let's begin by listing out the information given to us:
[tex]\begin{gathered} 2x^2+5=6x \\ 2x^2-6x+5=0 \\ a=2,b=-6,c=5 \end{gathered}[/tex]We proceed to use the quadratic formula, we have:
[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ a=2,b=-6,c=5 \\ x=\frac{-(-6)\pm\sqrt[]{-6^2-4(2\cdot5)}}{2(2)} \\ x=\frac{6\pm\sqrt[]{36-40}}{4}=x=\frac{6\pm\sqrt[]{-4}}{4} \\ \sqrt[]{-4}=2i \\ x=\frac{6\pm\sqrt[]{-4}}{4}\Rightarrow\frac{6\pm2i}{4} \\ x=\frac{6}{4}+\frac{2i}{4},\frac{6}{4}-\frac{2i}{4} \\ x_1=1.5+0.5i \\ x_2=1.5-0.5i \end{gathered}[/tex]A card is drawn from a deck of 52 cards. What is the probability that it is a numbered card (2-10) or a heart?
we know that
Total cards=52
Total numbered card (2-10)=36
Total heart=13
numbered card and heart=9
therefore
The probability is equal to
P=(36+13-9)/52
P=40/52
P=20/26=10/13
The answer is 10/13Given the formula for the nth term, state the first 5 terms of each sequence.t1= 800, tn= -0.25tn-1
In this case, we'll have to carry out several steps to find the solution.
Step 01:
data:
t1 = 800
tn = - 0.25 tn-1
Step 02:
sequence:
t1 = 800
t2 = -0.25 (800) = - 200
t3 = -0.25 (-200) = 50
t4 = -0.25 (50) = -12.5
t5 = - 0.25 (-12.5) = 3.125
The answer is:
t1 = 800
t2 = - 200
t3 = 50
t4 = -12.5
t5 = 3.125
The graph of polynomial f is shown. Select all the true statements about the polynomial.aThe degree of the polynomial is even.bThe degree of the polynomial is odd.cThe leading coefficient is positive.dThe leading coefficient is negative.eThe constant term of the polynomial is positive.fThe constant term of the polynomial is negative.
Explanation:
From the graph,
we can see that the graph is symmetric about the y axis
Hence,
We can say that the Polynomial is even
Also, Because th opwning of the function is downwards,
Hence the leading coefficient is negative
Also we can see that the y-intercept is positive
That is when x=0, y=3
Hence,
The constant term of the polynomial is positive.
Therefore,
The final answers are OPTION A,OPTION D,OPTION E
In the figure below, m2 = 49. Find mx 1.
By definition, a Right angle is an angle that measures 90 degrees.
Complementary angles are those angles that add up to 90 degrees.
For this case, you can identify that the angle 1 and the angle 2 are Complementary angles, because when you add them, you get 90 degrees (a Right angle).
Knowing the above, you can set up the following equation:
[tex]m\angle1+m\angle2=90\degree[/tex]Since you know that:
[tex]m\angle2=49\degree[/tex]You can substitute this value into the equation and the solve for the angle 1 in order to find its measure. You get that this is:
[tex]\begin{gathered} m\angle1+49\degree=90\degree \\ m\angle1=90\degree-49\degree \\ m\angle1=41\degree \end{gathered}[/tex]The answer is:
[tex]m\angle1=41\degree[/tex]In Mrs. Franco‘s class for every 64 is there a April right the ratio of boys to girls in simplest form
The ratio of boys to girls in Mrs. Franco's class is 3:2 .
The Ratio is defined as the comparison of two quantities that have the same units .
In the question ,
it is given that
In Mrs. Franco's class
For every 6 boys there are 4 girls in the class
we have to find the ratio of , boys to girls
the number of boys = 6
the number of girls = 4
So , the ratio can be written as
boys / girls = 6/4
writing the ratio in the simplest form , we get
boys/girls = 3/2
the ratio is 3:2 .
Therefore , The ratio of boys to girls in Mrs. Franco's class is 3:2 .
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The cost to mail a package is 5.00. Noah has postcard stamps that are worth 0.34 and first-class stamps that are worth 0.49 each. An equation that represents this is 0.49f + 0.34p = 5.00Solve for f and p.If Noah puts 7 first-class stamps, how many postcard stamps will he need?
ANSWER
[tex]\begin{gathered} f=\frac{5.00-0.34p}{0.49} \\ p=\frac{5.00-0.49f}{0.34} \\ p=4.618\approx5\text{ postcard stamps} \end{gathered}[/tex]EXPLANATION
The equation that represents the situation is:
[tex]0.49f+0.34p=5.00[/tex]To solve for f, make f the subject of the formula from the equation:
[tex]\begin{gathered} 0.49f=5.00-0.34p \\ \Rightarrow f=\frac{5.00-0.34p}{0.49} \end{gathered}[/tex]To solve for p, make p the subject of the formula from the equation:
[tex]\begin{gathered} 0.34p=5.00-0.49f \\ \Rightarrow p=\frac{5.00-0.49f}{0.34} \end{gathered}[/tex]To find how many postcard stamps Noah will need if he puts 7 first-class stamps, solve for p when f is equal to 7.
That is:
[tex]\begin{gathered} p=\frac{5.00-(0.49\cdot7)}{0.34} \\ p=\frac{5.00-3.43}{0.34}=\frac{1.57}{0.34} \\ p=4.618\approx5\text{ postcard stamps} \end{gathered}[/tex]Evaluate: 2x – 16y for x = −2 and y = 3
To evaluate the expression with the given values, we need to substitute them and perform any required calculation.
To do so, we need to remember the following rule:
If we have a multiplication of two numbers with different signals, one of them positive and the other negative, the result will be negative. If the multiplication is made with two numbers with the same signal, both positive or both negative, the result will be positive.
From this, we perform the following calculation:
[tex]\begin{gathered} 2x-16y \\ 2\cdot(-2)-16\cdot(3) \\ -4-48 \\ -52 \end{gathered}[/tex]From the solution developed above, we are able to conclude that the solution is:
- 52Use the remainder theorem to find P (1) for P(x) = 2x - 3x' + 3x -3.Specifically, give the quotient and the remainder for the associated division and the value of P (1).미미2Quotient = 0Х$2Remainder =0P(1) =
Using the remainder theorem, we must find P(1) for:
[tex]P(x)=2x^4-3x^3+3x-3[/tex]1) Because we want to evaluate P(x) for x = 1, we must compute
[tex]\frac{2x^4-3x^3+3x-3}{x-1}[/tex]2) Now we make the synthetic division by putting a 1 in the division box:
The remainder from the division is:
[tex]R=-1[/tex]The quotient of the division is:
[tex]2x^3-x^2+2x+2[/tex]3) From the synthetic division we get a remainder R = -1, applying the Remainder Theorem we get that:
[tex]P(1)=R=-1[/tex]Summary
The answers are:
1)
[tex]Quotient=2x^3-x^2+2x+2[/tex]2)
[tex]Remainder=-1[/tex]3)
[tex]P(1)=-1[/tex]Write the equation of the function in the graph.. Please show all of your work so i can understand
The vertex form of a parabola is:
[tex]y=a(x-h)^2+k[/tex]where (h, k) is the vertex of the parabola and a is some constant.
From the graph, the vertex is located at (1, 4), that is, h = 1 and k = 4.
Substituting with these values and the point (0, 3), we get:
[tex]\begin{gathered} 3=a(0-1)^2+4 \\ 3-4=a(-1)^2 \\ -1=a\cdot1 \\ -\frac{1}{1}=a \\ -1=a \end{gathered}[/tex]Then, the equation of the function is:
[tex]\begin{gathered} y=-1(x-1)^2+4 \\ y=-(x-1)^2+4 \end{gathered}[/tex]Find the expression for the possible width of the rectangle.
Given the area of the rectangle is given by the following expression:
[tex]A=x^2+5x+6[/tex]The area of the rectangle is the product of the length by the width
So, we will factor the given expression
To factor the expression, we need two numbers the product of them = 6
and the sum of them = 5
So, we will factor the number 6 to find the suitable numbers
6 = 1 x 6 ⇒ 1 + 6 = 7
6 = 2 x 3 ⇒ 2 + 3 = 5
So, the numbers are 2 and 3
The factorization will be as follows:
[tex]A=(x+3)(x+2)[/tex]So, the answer will be the possible dimensions are:
[tex]\begin{gathered} \text{Length}=x+3 \\ \text{Width}=x+2 \end{gathered}[/tex]Use this information to answer the following two questions. Mathew finds the deepest part of the pond to be 185 meters. Mathew wants to find the length of a pond. He picks three points and records the measurements, as shown in the diagram. Which measurement describes the depth of the pond? Hide All Z between 13 and 14 meters 36 m 14 m between 14 and 15 meters between 92 and 93 meters Х ag between 93 and 94 meters
it's letter A. Between 13 and 14 meters
Because one side measure 14, and the height (depth) could not be
higher than 14 meters .
The length of the pond can be calculated using the Pythagorean theorem
length^2 = 36^2 + 14^2
length^2 = 1296 + 196
length^2 = 1492
length = 38.6 m
How can a greatest common factor be separated from an expression
Answer: divide each term from the original expression (3x3+27x2+9x ) by the GCF (3x), then write it in the parenthesis
Step-by-step explanation:
Answer:
You take it out and place it as a multiple.
Step-by-step explanation:
5x+15
GCF = 5
5(x+3)
Hope that helps
im doing math and im wondering when do i switch the inequality?
Question:
Solve the following inequality:
[tex]12x+6<17[/tex]Solution:
Consider the following inequality
[tex]12x+6<17[/tex]solving for 12x, we get:
[tex]12x<17-6[/tex]this is equivalent to:
[tex]12x<11[/tex]solving for x, we get:
[tex]x<\frac{11}{12}[/tex]so that, the correct answer is:
[tex]x<\frac{11}{12}[/tex]Which of the following is the result of using the remainder theorem to find F(-2) for the polynomial function F(x) = -2x³ + x² + 4x-3?
Solution
We have the polynomial
[tex]f(x)=-2x^3+x^2+4x-3[/tex]Usin the remainder theorem, we find f(-2) by substituting x = -2
So we have
[tex]\begin{gathered} f(x)=-2x^{3}+x^{2}+4x-3 \\ \\ f(-2)=-2(-2)^3+(-2)^2+4(-2)-3 \\ \\ f(-2)=-2(-8)+4-8-3 \\ \\ f(-2)=16+4-8-3 \\ \\ f(-2)=20-11 \\ \\ f(-2)=9 \end{gathered}[/tex]Therefore, the remainder is
[tex]9[/tex]h(x) =-4x+ 3; Find h(x-1)
Answer:
h(x-1) = - 4x + 7
Explanation:
To find h(x - 1), we need to replace x by (x-1) on h(x). Then:
[tex]\begin{gathered} h(x)=-4x+3 \\ h(x-1)=-4(x-1)+3 \\ h(x-1)=-4x-4(1)+3 \\ h(x-1)=-4x+4+3 \\ h(x-1)=-4x+7 \end{gathered}[/tex]Therefore, h(x-1) = - 4x + 7
I need help with this please it’s revisiting proportional relationships
In order to calculate the cost of 7.5 lbs of walnuts, we can use the following rule of three, knowing that 3/4 lbs have a cost of $3.45:
[tex]\begin{gathered} \text{weight}\to\text{ cost} \\ \frac{3}{4}\text{ lbs}\to3.45 \\ 7.5\text{ lbs}\to x \end{gathered}[/tex]Now, we can write the following proportion and solve for x:
[tex]\begin{gathered} \frac{\frac{3}{4}}{7.5}=\frac{3.45}{x} \\ x\cdot\frac{3}{4}=7.5\cdot3.45 \\ x=\frac{7.5\cdot3.45\cdot4}{3} \\ x=34.5 \end{gathered}[/tex]Therefore the cost is $34.50.
The probability of failing a test is 0.115 if you consider a group of 12 people taking a test on a given day, what is the probability that two or more of them will fail the test
If the probability of failing a test is 0.115 if you consider a group of 12 people taking a test on a given day, then the probability that two or more of them will fail the test is 0.41
The probability of failing a test = 0.115
Total number of people = 12
We have to find the probability that two or more of them will fail the test
We know the binomial distribution
P(X≥2) = 1 - P(X<2)
= 1 - P(X=0) - P(X=1)
P(X≥2)= 1 - [tex](12C_{0}) (0.115^0)(1-0.115)^{12}[/tex] - [tex](12C_{1}) (0.115^1)(1-0.115)^{11}[/tex]
= 0.41
Hence, if the probability of failing a test is 0.115 if you consider a group of 12 people taking a test on a given day, then the probability that two or more of them will fail the test is 0.41
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The probability that a tourist- will spot a Cheetah in Kruger National park is 0.4, the probability that he will spot a Tiger, is 0.7, and the probability that he will spot a Cheetah, or a Tiger or both is 0.5. What is the probability that the tourist will spot: (a) both animals? (b) neither of the animals? (c) Determine with appropriate reason whether the event of spotting a Cheetah and a Tiger are independent or not?
Since the probability of Cheetah is 0.4
Since the probability of Tiger is 0.7
Since the probability of Cheetah or Tiger or both is 0.5
Let us draw a figure to show this information
Then we need to find both animals (x)
Since
[tex]0.5+x=0.7+0.4-x[/tex]Add x to both sides and subtract 0.5 from both sides
[tex]\begin{gathered} 0.5+x+x=0.7+0.4-x+x \\ 0.5+2x=1.1 \\ 0.5-0.5+2x=1.1-0.5 \\ 2x=0.6 \end{gathered}[/tex]Divide both sides by 2 to find x
[tex]\begin{gathered} \frac{2x}{2}=\frac{0.6}{2} \\ x=0.3 \end{gathered}[/tex]a) The probability of both animals is 0.3
Since the total of probability is 1, then to find the neither subtract (0.4 + 0.7 - 0.3) from 1
[tex]\begin{gathered} N=1-(0.4+0.7-0.3) \\ N=1-0.8 \\ N=0.2 \end{gathered}[/tex]b) the probability of neither is 0.2
Events A and B are independent if the equation P(A∩B) = P(A) · P(B)
Since
[tex]P(Ch\cap T)=0.3[/tex]Since P(Ch) . P(T) = 0.4 x 0.7 = 0.28
Then
[tex]P(Ch\cap T)\ne P(Ch).P(T)[/tex]c) The events are not independent