we have the functions
[tex]\begin{gathered} f\mleft(x\mright)=x^3+3x^2+4x+5 \\ g(x)=5 \end{gathered}[/tex]so
g(f(x))=5the product of (2-x)and (1-x)is equal to x^2-3x+2
So the product of (2-x) and (1-x) is equal to x^2 - 3x + 2
Hello! Need a little help on parts a,b, and c. The rubric is attached, Thank you!
In this situation, The number of lionfish every year grows by 69%. This means that to the number of lionfish in a year, we need to add the 69% to get the number of fish in the next year.
This is a geometric sequence because the next term of the sequence is obtained by multiplying the previous term by a number.
The explicit formula for a geometric sequence is:
[tex]a_n=a_1\cdot r^{n-1}[/tex]We know that a₁ = 9000 (the number of fish after 1 year)
And the growth rate is 69%, to get the number of lionfish in the next year, we need to multiply by the rate og growth (in decimal) and add to the number of fish. First, let's find the growth rate in decimal, we need to divide by 100:
[tex]\frac{69}{100}=0.69[/tex]Then, if a₁ is the number of lionfish in the year 1, to find the number in the next year:
[tex]a_2=a_1+a_1\cdot0.69[/tex]We can rewrite:
[tex]a_2=a_1(1+0.69)=a_1(1.69)[/tex]With this, we have found the number r = 1.69. And now we can write the equation asked in A:
The answer to A is:
[tex]f(n)=9000\cdot1.69^{n-1}[/tex]Now, to solve B, we need to find the number of lionfish in the bay after 6 years. Then, we can use the equation of item A and evaluate for n = 6:
[tex]f(6)=9000\cdot1.69^{6-1}=9000\cdot1.69^5\approx124072.6427[/tex]To the nearest whole, the number of lionfish after 6 years is 124,072.
For part C, we need to use the recursive form of a geometric sequence:
[tex]a_n=r(a_{n-1})[/tex]We know that the first term of the sequence is 9000. After the first year, the scientists remove 1400 lionfish. We can write this as:
[tex]\begin{gathered} a_1=9000 \\ a_n=r\cdot(a_{n-1}-1400) \end{gathered}[/tex]Because to the number of lionfish in the previous year, we need to subtract the 1400 fish removed by the scientists.
The answer to B is:
[tex][/tex]A baker paid $15.05 for flour at a store that sells flour for $0.86 per pound.
Solution:
Given that a store sells flour for $0.86 per pound, this implies that
[tex]1\text{ lb}\Rightarrow\$0.86[/tex]Given that a baker paid $15.05, let y represent the amount of flour the baker bought.
Thus,
[tex]y\text{ lb}\Rightarrow\$15.05[/tex]To solve for y,
[tex]\begin{gathered} 1\text{lb}\operatorname{\Rightarrow}\operatorname{\$}0.86 \\ y\text{ lb}\Rightarrow\$15.05 \\ cross-multiply, \\ y\text{ lb = }\frac{\$\text{15.05}}{\$0.86}\times1\text{ lb} \\ =17.5\text{ lb} \end{gathered}[/tex]Hence, the baker bought 17.5 lb of flour.
Construct a polar equation for the conic section with the focus at the origin and the following eccentricity and directrix.Conic Eccentricity Directrix1ellipsex= -75e =
In order to find the polar equation of the ellipse, first let's find the rectangular equation.
Since the directrix is a vertical line, the ellipse is horizontal, and the model equation is:
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]Where the center is located at (h, k), the directrix is x = -a/e and the eccentricity is e = c/a.
So, if the eccentricity is e = 1/5 and the directrix is x = -7, we have:
[tex]\begin{gathered} \frac{c}{a}=\frac{1}{5}\rightarrow a=5c\\ \\ -\frac{a}{e}=-7\\ \\ \frac{a}{\frac{c}{a}}=7\\ \\ \frac{a^2}{c}=7\\ \\ \frac{25c^2}{c}=7\\ \\ 25c=7\\ \\ c=\frac{7}{25}\\ \\ a=5\cdot\frac{7}{25}=\frac{7}{5} \end{gathered}[/tex]Now, let's calculate the value of b with the formula below:
[tex]\begin{gathered} c^2=a^2-b^2\\ \\ \frac{49}{625}=\frac{49}{25}-b^2\\ \\ b^2=\frac{25\cdot49}{625}-\frac{49}{625}\\ \\ b^2=\frac{24\cdot49}{625}\\ \\ b^2=\frac{1176}{625} \end{gathered}[/tex]Assuming h = 0 and k = 0, the rectangular equation is:
[tex]\frac{x^2}{\frac{49}{25}}+\frac{y^2}{\frac{1176}{625}}=1[/tex]Now, to convert to polar form, we can do the following steps:
[tex]\begin{gathered} \frac{25x^2}{49}+\frac{625y^2}{1176}=1\\ \\ 600x^2+625y^2=1176\\ \\ 600(r\cos\theta)^2+625(r\sin\theta)^2=1176\\ \\ 600r^2\cos^2\theta+625r^2\sin^2\theta=1176\\ \\ r^2(600\cos^2\theta+625\sin^2\theta)=1176\\ \\ r^2=\frac{1176}{600\cos^2\theta+625\sin^2\theta}\\ \\ r=\sqrt{\frac{1176}{600\cos^2\theta+625\sin^2\theta}}\\ \\ r=\sqrt{\frac{1176}{600+25\sin^2\theta}} \end{gathered}[/tex]Another way of writing this equation in polar form is:
[tex]r=\frac{ep}{1+\sin^2\theta}[/tex]Where p is the distance between the focus and the directrix.
Since the foci are located at (±c, 0) = (±7/25, 0) and the directrix is x = -7, the distance is:
[tex]p=7-\frac{7}{25}=\frac{175}{25}-\frac{7}{25}=\frac{168}{25}[/tex]So the equation is:
[tex]\begin{gathered} r=\frac{\frac{1}{5}\cdot\frac{168}{25}}{1+\sin^2\theta}\\ \\ r=\frac{\frac{168}{125}}{1+\sin^2\theta}\\ \\ r=\frac{1.344}{1+\sin^2\theta} \end{gathered}[/tex]The vertex of the parabola below is at the point
SOLUTION
The equation of a parabola in a vertex form is given
since the parabola is on the x-axis.
[tex]\begin{gathered} x=a(y-h)^2+k \\ \text{Where } \\ \text{Vertex}=(h,k) \end{gathered}[/tex]From the diagram given, we have
[tex]\text{vertex}=(-4,-2)[/tex]Substituting into the formula above, we have
[tex]\begin{gathered} x=a(y-h)^2+k \\ h=-4,k=-2 \end{gathered}[/tex]We have
[tex]\begin{gathered} x=(y-(-2)^2-4 \\ x=(y+2)^2-4 \end{gathered}[/tex]Since the parabola is a reflection from the parent function, then
[tex]a=-2[/tex]The equation of the parabola becomes
[tex]x=-2(y+2)^2-4[/tex]Answer; x = -2(y + 2)^2-4
When we use function notation, f(x)=# is asking you to find the input when the output is the given number. We can also consider that an ordered pair can be written as (x,#). With this is mind, explain why f(x)=0 is special.
Notice that f(x)=0 is special because is the intercept of the graph with the x-axis and if f(x) corresponds to a function, the x-intercepts are the roots of the function.
The ordered pair can be written as (x,0), where x is such that f(x)=0.
1. In the figure, angle CAB is 47. What would prove that angle ACD is also 47?
A A reflection of ABC over AC, such that ABC maps to CDA.
B A rotation of ABC 180 clockwise around C, such that ABC maps to ADC.
C A rotation of ABC 180 counterclockwise around A, such that ABC maps to ADC.
D A translation of ABC to the top right, such that ABC maps to ADC.
The correct option C: A rotation of ABC 180 counterclockwise around A, such that ABC maps to ADC.
What is termed as the rotation?Geometry can be used to determine the meaning of rotation in mathematics. As a result, it is described as the movement of something around a center or an axis. Any rotation is regarded as a specific space motion that freezes at at least one point. In reality, a earth rotates on its axis, which is also an instance of rotation. Because a clockwise rotation has a negative magnitude, a counterclockwise rotation does have a positive magnitude.For the given question;
In triangles ABC angle CAB is 47.
If the triangles ABC and ACD becomes congruent such that angle ACD corresponds to angles ABC.
Then, both angles will be equal.
For, this, a rotation of ABC 180 counterclockwise around A, such that ABC maps to ADC is to be done.
To know more about the rotation, here
https://brainly.com/question/1164739
#SPJ13
I need help finding the passing adjusted grade of 70A=10R^1/2
Given:
Passing grade = 70
Formula for adjusted grade, A:
[tex]A=10R^{\frac{1}{2}}[/tex]Given a passing adjusted grade of 70, let's find the raw score, R.
To solve for R, substitute 70 for A and solve for R.
We have:
[tex]\begin{gathered} 70=10R^{\frac{1}{2}} \\ \end{gathered}[/tex]Divide both sides by 10:
[tex]\begin{gathered} \frac{70}{10}=\frac{10R^{\frac{1}{2}}}{10} \\ \\ 7=R^{\frac{1}{2}} \end{gathered}[/tex]Take the square of both sides:
[tex]\begin{gathered} 7^2=(R^{\frac{1}{2}})^2 \\ \\ 7^2=R^{\frac{1}{2}\times2} \\ \\ 49=R^1 \\ \\ 49=R \\ \\ R=49 \end{gathered}[/tex]Therefore, the raw score a student would need to have a passing adjusted grade of 70 is 49
ANSWER:
49
sorry you have to zoom in to see better. its a ritten response.
A: height is increasing from 0-2 interval.
B: Height remains the same on 2-4
C: 4-6 the height is decreasing the fastest, because the slope is the steepest on that interval.
D: Baloon would be on the ground at 16 seconds, and will not fall down further. that is the way it is in real-world (constraint).
The first year shown the number of students per teacher fell below 16 was
Using the y axis, we want to find when it goes below 16
The x value when y is less than 16 for the first time is 2002
10 ptQuestion 10A can of soup has a volume of 80 in and mass of 10 ounces. A can of tuna has a volume of 56 in and mass of 8ounces. About how much less is the density of the soup than the tuna (give your answer in ounces/square inch).Round your answer to the nearest 1000th.SOUPSTUNA CHUNKSBrineLENTIL0.0179 ounces per per square inches less0.1429 ounces per per square inches less0.1250 ounces per per square inches less0.0099 ounces per per square inches less
We have that the general formula for the density given the volume and the mass is:
[tex]d=\frac{m}{v}[/tex]in this case, the densities for the can of soup and the can of tuna are:
[tex]\begin{gathered} d_{soup}=\frac{10}{80}=\frac{1}{8} \\ d_{tuna}=\frac{8}{56}=\frac{1}{7} \end{gathered}[/tex]the difference between these two densities is:
[tex]\frac{1}{7}-\frac{1}{8}=\frac{1}{56}=0.0179[/tex]therefore, there is 0.0179 less density of the soup than the tuna
the price of a gallon of unleaded gas has risen to $2.92 today. yesterday's price was $2.85. find the percentage increase. round to the nearest 10th of a percent
Given:
[tex]\begin{gathered} P_{\text{today}}=2.92,P_{today}=Price\text{ of a gallon of unleaded gas today} \\ P_{\text{yesterday}}=2.85, \\ P_{yesterday}=Price\text{ of a gallon of unleaded gas today} \end{gathered}[/tex]To Determine: The percentage increase round to the nearest 1oth of a percent
The formula for percentage increase is given below:
[tex]\begin{gathered} P_{in\text{crease}}=\frac{increase}{P_{\text{initial}}}\times100\% \\ In\text{crease}=P_{final}-P_{in\text{itial}} \end{gathered}[/tex]Substitute the given into the formula
[tex]\begin{gathered} P_{\text{yesterday}}=P_{i\text{nitial}}=2.85 \\ P_{\text{today}}=P_{\text{final}}=2.92 \\ \text{Increase}=2.92-2.85=0.07 \end{gathered}[/tex][tex]\begin{gathered} P_{in\text{crease}}=\frac{increase}{P_{\text{initial}}}\times100\% \\ P_{in\text{crease}}=\frac{0.07}{2.85}\times100\% \\ P_{in\text{crease}}=0.02456\times100\% \\ P_{in\text{crease}}=2.456\% \\ P_{in\text{crease}}\approx2.5\%(nearest\text{ 10th)} \end{gathered}[/tex]Hence, the percentage increase to the nearest 10th of a percent is 2.5%
4. You are making guacamole for a familygathering. Your first trip to the store, youpurchased 5 avocados and 3 pounds of tomatoesfor $13.30. The head count changed, and youwent back for an additional 3 avocados and 8pounds of tomatoes, spending another $22.55.What is the price per avocado and pound oftomatoes?
hello
to solve this question, we need to write an equation expressing the word problem and solve for the price of each item.
let x represent the cost of avocados
let y represent the cost of tomatoes
[tex]\begin{gathered} 5x+3y=13.30\ldots\text{.equation 1} \\ 3x+8y=22.55\ldots\text{.equation 2} \end{gathered}[/tex]from equation 1, let's make xthe subject of formula
[tex]\begin{gathered} 5x+3y=13.30 \\ 5x=13.30-3y \\ \text{divide both sides by 5 to solve for x} \\ x=\frac{13.30-3y}{5} \\ \text{this is equation 3} \end{gathered}[/tex]put equation 3 into equation 2
[tex]\begin{gathered} 3x+8y=22.55 \\ 3(\frac{13.30-3y}{5})+8y=22.55 \\ \frac{39.9-9y}{5}+8y=22.55 \\ \text{solve for y} \\ \frac{39.9-9y+40y}{5}=22.55 \\ \frac{39.9+31y}{5}=22.55 \\ 39.9+31y=22.55\times5 \\ 39.9+31y=112.75 \\ 31y=112.75-39.9 \\ 31y=72.85 \\ y=\frac{72.85}{31} \\ y=2.35 \end{gathered}[/tex]since y = 2.35, let's put that in either equation 1 or 2
from equation 2
3x + 8y = 22.55
put y = 2.35 and solve for x
[tex]\begin{gathered} 3x+8y=22.55 \\ y=2.35 \\ 3x+8(2.35)=22.55 \\ 3x+18.8=22.55 \\ 3x=22.55-18.8 \\ 3x=3.75 \\ x=\frac{3.75}{3} \\ x=1.25 \end{gathered}[/tex]from the calculations above, the price per avocado and pound of tomatoes are $1.25 and $2.35 respectively
What is the distance from the ball to the base of the building? Round to the nearest foot.*
Given:
[tex]\theta=37^{\circ}\text{ ; height of the building is }60\text{ ft}[/tex][tex]\begin{gathered} \tan 37^{\circ}=\frac{Height\text{ of the building}}{\text{Distance between the ball and foot of the building}} \\ 0.7536=\frac{60}{\text{Distance between the ball and foot of the building}} \\ \text{Distance between the ball and foot of the building}=\frac{60}{0.7536} \\ =80\text{ feet} \end{gathered}[/tex]80 feet is the final answer.
Sand will be placed under the base of a circular pool with a diameter of 14 feet. 1 bag of sand covers about 5 square feet. How many bags of sand are needed? Use 3.14 for pi. Round bags up.
I am getting hung up on the last part of doing this problem.
Any help is greatly appreciated.
Sand will be placed under the base of a circular pool with a diameter of 14 feet. 1 bag of sand covers about 5 square feet. the number of bags of sand required is 30bags.
The area of the pool is
A = πr²
A = 3.14×(7 ft)² = 153.8 ft²
The number of bags of sand required is ...
(153.8 ft²)/(5 ft²/bag) ≈ 30.76bags
bags of sand are needed.
What is diameter?The diameter is defined as twice the length of the radius of the circle. The radius is measured from the centre of the circle to one endpoint on the boundary of the circle, while the diameter is the distance measured from one end of the circle to a point on the other end of the circle that passes through the centre. This is indicated by the letter D. The circumference of a circle has an infinite number of points, which means that the circle has an infinite number of diameters and each diameter of the circle is the same length.
Ø is the symbol used in the design to indicate the diameter. This symbol is often used in technical data and drawings.
To learn more about diameter, refer;
https://brainly.com/question/13624974
#SPJ13
Mara bought a bag that contained 16 cups of sugar. She uses two-thirds cup of sugar each time she make a batch of cookies. If the bag now has 10 cups of sugar left, how many batches of cookies has she made?
From a bag of 16 cups of sugar , Mara used 2/3 cups of sugar to make 1 batch of cookies , then number of baches made by 6 cups of sugar is equal to 9 batches.
As given in the question,
Total number of cups of sugar in a bag = 16
Cups of sugar used to make 1 batch of cookies = 2/3
Number of cups of sugar left in a bag = 10
Number of cups of sugar used = 6
2/3 cups of sugar = 1 batch of cookies
1 cup of sugar = 3/2 batch of cookies
6 cups of sugar = [(3/2) × 6 ]
= 9 batches of cookies
Therefore, from a bag of 16 cups of sugar , Mara used 2/3 cups of sugar to make 1 batch of cookies , then number of baches made by 6 cups of sugar is equal to 9 batches.
Learn more about number here
brainly.com/question/17429689
#SPJ1
Divide the following polynomial using synthetic division, then place the answer in the proper location on the grid. Write answer in descending powers of x.
(x ^4 - 3x^3 + 3x^2 - 3x + 6) / (x - 2)
SOLUTION
We want to perform the following division using synthetic division
[tex]\frac{x^4-3x^3+3x^2-3x+6}{x-2}[/tex]This becomes
First we write the problem in a division format as shown below
Next take the following step to perform the division
Now, we have completed the table and we obtained the following coefficients, 1, -1, 1, -1, 4
Note that the first four ( 1, -1, 1, -1) are coefficients of the quotient, while the last one (4) is the coefficient of the remainder.
Hence the quotient is
[tex]x^3-x^2+x-1[/tex]And the remainder is 4.
Hence
[tex]\frac{x^4-3x^3+3x^2-3x+6}{x-2}=x^3-x^2+x-1+\frac{4}{x-2}[/tex]Transforming the graph of a function by shrinking or stretching
So,
From the graph of the function f(x), we can notice it contains the points:
[tex]\begin{gathered} f(2)=-4\to(2,-4) \\ f(-2)=-2\to(-2,-2) \end{gathered}[/tex]If we use the transformation, we obtain the new points:
[tex]\begin{gathered} f(\frac{1}{2}x)\to f(\frac{1}{2}(2))=f(1)=-\frac{7}{2}\to(2,-\frac{7}{2}) \\ f(\frac{1}{2}x)\to f(\frac{1}{2}(-2))=f(-1)=-\frac{5}{2}\to(-2,-\frac{5}{2}) \end{gathered}[/tex]All we need to do to graph the new line is to plot the points:
[tex](2,-\frac{7}{2})\text{ and }(-2,-\frac{5}{2})[/tex]And form a line that passes through them.
Can you help to solve for number 5. Solving for X.
We will work at first with the small triangle ADC
[tex]m\angle DAC+m\angle C=m\angle ADB[/tex]mm[tex]m\angle DAC=55-20=35^{\circ}[/tex]We will use the sine rule
[tex]\frac{65}{\sin35}=\frac{AD}{\sin 20}[/tex]By using the cross multiplication
[tex]\begin{gathered} AD\times\sin 35=65\times\sin 20 \\ AD=\frac{65\sin 20}{\sin 35} \end{gathered}[/tex]In triangle ABD
We will use
[tex]\sin 55=\frac{x}{AD}[/tex]Then
[tex]x=AD\sin 55[/tex]Substitute AD by its value above
[tex]undefined[/tex]Kara's original financial plan required that she save $220 amonth for two years in order to have $5,280 for the downpayment on a car. However, after one year she has onlymanaged to save $2,300. How much will Kara have to save each month in the second year in order to reach her original goal of $5,280?
given data:
the amount needed to pay the downpayment of the car = $5280.
original financial plan = $220 per month.
The amount kara saved after 1 year = $2300.
the balance amount she needed to save
[tex]\begin{gathered} =5280-2300 \\ =2980 \end{gathered}[/tex]now, divide the balance amount by 12, because 1 year =12 months.
[tex]\begin{gathered} =\frac{2980}{12} \\ =248.3 \end{gathered}[/tex]Thus, kara needs to save 248 dollors each month in order to have 5280 dollors after a year.
If tan A = ã and tan B=16calculate and simplify the following:?tan(A - B) = +
SOLUTION
[tex]\begin{gathered} In\text{ Trigonometry} \\ \tan (A-B)=\frac{\tan A-\tan B}{1+\tan A\text{ tan B}}_{} \end{gathered}[/tex]Given:
[tex]\begin{gathered} \tan \text{ A= }\frac{5}{6} \\ \tan \text{ B= }\frac{1}{6} \end{gathered}[/tex]Now substitute these given into the expression above:
[tex]\tan (A-B)=\frac{\frac{5}{6}-\frac{1}{6}}{1+(\frac{5}{6}\times\frac{1}{6})}[/tex]Simplifying further:
[tex]=\frac{\frac{2}{3}}{1+\frac{5}{36}}[/tex][tex]\begin{gathered} =\frac{\frac{2}{3}}{\frac{41}{36}} \\ =\frac{2}{3}\times\frac{36}{41} \\ =\frac{72}{123} \\ =\frac{24}{41} \end{gathered}[/tex]The answer therefore is:
[tex]\frac{24}{41}[/tex]what is the nessecary information you need to know about a cube?
Answer: the width, length and height
Step-by-step explanation: multiply the width length and height of a cube and you get the area
Can you please help me
From the question,
[tex]\begin{gathered} m\angle AFE=m\angle BFC\text{ (Vertically opposite angles)} \\ \therefore \\ m\angle AFE=70^{\circ} \end{gathered}[/tex]We also have
[tex]m\angle AFB=m\angle EFC\text{ (Vertically opposite angl}es)[/tex]Remember that the sum of angles at a point equals 360°. Therefore
[tex]\begin{gathered} m\angle AFB+m\angle BFC+m\angle CFE+m\angle AFE=360 \\ \therefore we\text{ have} \\ 2(m\angle AFB)+2(70)=360 \\ 2(m\angle AFB)=360-140=220 \\ m\angle AFB=\frac{220}{2}=110 \end{gathered}[/tex]Therefore, m(AB) is 110°.
Hence, OPTION B is correct.
Kayla has $37.99 in her checking account. she uses her debit card to make purchases of $26.29 and $22.98 which overdraws her account. her bank charges her account an overdraft fee of $25.00. She then deposits her paycheck for $55.07 from her part time job. what is the balance in her account?
Aye itz just me, this is the solution:
Initial balance = $ 37.99
Purchase 1 = ($ 26.29)
Purchase 2 = ($ 22.98)
Overdraft fee = ($ 25.00)
Deposit = $ 55.07
______________________
New balance = 37.99 - 26.29 - 22.98 - 25 + 55.07
New balance = $ 18.82
Solve the inequality a < 5 and write the solution using: Inequality Notation:
Answer:
Step-by-step explanation:
The country of Scotstats requires the people in their country to have license tags on their car such that the first 3 characters are English letters but no letter may repeat. The last 3 characters must each be a number 0-9 and again no numbers can be repeated. How many license tags are possible?
Answer
11,232,000 possible license tags.
Explanation
The licenses have space for 6 characters.
We need to note that there are 26 alphabets and 10 numbers to pick from.
So, for the first character, any of the 26 alphabets can take this spot.
For the second character, 25 alphabets are now available for that space. (Since repetition is not allowed)
For the third character, 24 alphabets are available for that.
For the fourth character, any of the 10 numbers can take up that spot.
For the fifth character, only 9 numbers can take this spot now. (No repetition rule too)
For the sixth character, 8 numbers can take that spot.
So, mathematically, the number of license tags possible will be
26 × 25 × 24 × 10 × 9 × 8 = 11,232,000 possible license tags
Hope this Helps!!!
cost to rent a paddle boat at the city park includes a intentral fee of $7.00, plus $3.50 per hour. Which equation models the relationship between the total cost, y, and the number of hours, X, that the paddle boat is rentedA. y = 3.5x + 7. B. y = 7x + 3.5C. y = x/7 + 3.5. D. y = x/3.5 + 7
The total cost is represented as y, and the number of hours as x.
The intentral fee is $7.00.
Since the cost is $3.50 per hour, the total cost is
y=3.5x+7.
Hence, option A is correct.
Which of the following correctly represents the movement on the number line for the calculation 21 - (- 15) + (- 30) ?
a- left right left
b-right left left
c- right left right
d-right right left
It is the movement on the number line is right right left
The option (d) is correct .
Given,
The movement on the number line for the calculation
21 - (- 15) + (- 30)
To find the which of the following correctly represents the movement of calculation?
Now, According to the question:
21 - (- 15) + (- 30)
21 + 15 - 30 = 6
right right left
Hence, It is the movement on the number line is right right left
The option (d) is correct.
Learn more about Number line at:
https://brainly.com/question/13425491
#SPJ1
3) There are 24 applicants for three jobs: computer programmer, software tester, and manager. How many ways can this be done?
this is a combination, so
[tex]24C3=\frac{24\cdot23\cdot22}{3\cdot2\cdot1}=2024[/tex]answer: 2024 ways
could someone please help :(
Given from the number line:
D = -2 and F = 13
So, the distance DF = 13 - (-2) = 13 + 2 = 15
1) find E such that, DE : EF = 2 : 1
so,
so, x : (15 - x) = 2 : 1
x = 30 - 2x
3x = 30
x = 10
So, E = -2 + 10 = 8
=========================================================================
2) E is 4/5 of the distance from F to D
So, the distance from F = 4/5 * 15 = 12
So, E = 13 - 12 = 1
=====================================================================
3) the ratio of DE : EF = 2 : 3
So,
3x = 2 ( 15 - x)
3x = 30 - 2x
5x = 30
x = 30/5 = 6
E = -2 + 6 = 4
=================================================
4) E is 1/3 of the distance from D to F
So, the distance DE = 1/3 * 15 = 5
So, E = -2 + 5 = 3
=====================================================
As a summery:
1) E = 8
2) E = 1
3) E = 4
4) E = 3
