You can notice that the given function is symmetric respect to the y-axis.
It means that the value of the function for both x and -x is the same:
[tex]f(-x)=f(x)[/tex]This is the characteristic of a even function.
Hence, the answer is B
Hello, I need some assistance with the following question. Q1.
Given the expression f/g
Which is a rational expression.
The domain is all real numbers of (x) except the zeros of the denominators
The zeros of the denominators can be calculated using the equation g(x)=0
So, the answer will be as follows:
The domain of f/g consists of numbers (x) for which g(x) ≠ 0 that are in the domains of both f and g
Find the average rate of change of f(x)=3x^2-8x from x=1 to x=6
Answer:
The answer is 13
If f(x) = 2x+3, what is f(-2)
Answer: f(-2) = -1
Step-by-step explanation:
2x + 3
2(-2) +3
-4 + 3
-1
Answer:
Step-by-step explanation:
you plug in the -2 to the equation for x
f(-2)= 2(-2)+3
f(-2)=-1
there are 5 adult cats, 6 middle aged cats, and ___ kittens, if there are 19 animals in total, how many kittens are there, solve for the blank.
ANSWER
There are 8 kittens
EXPLANATION
If the sum of the number of adult cats, middle aged cats and kittens is 19:
[tex]\begin{gathered} \text{adult}+\text{middle aged+kittens=19} \\ 5+6+\text{kittens}=19 \\ \text{kittens}=19-5-6 \\ \text{kittens}=8 \end{gathered}[/tex]factor the trinomial6x² + 17x + 12
Answer: The factor of the above function is (2x + 3) (3x + 4)
We are given the below function
[tex]6x^2\text{ + 17x + 12}[/tex]This function can be factor using factorization method
The co-efficient of x^2 = 6
Multiply 6 by 12 to get the constant of the function
12 x 6 = 72
Next, find the factors of 72
Factors of 72 : 1 and 72, 2 and 36, 6 and 12, 9 and 8, 3 and 24
The only factor that will give us 17 when add and give us 72 when multiply is 8 and 9
The new equation becomes
[tex]\begin{gathered} 6x^2\text{ + 17x + 12} \\ 6x^2\text{ + 8x + 9x + 12} \\ \text{Factor out 2}x \\ 2x(3x\text{ + 4) + 3(3x + 4)} \\ (2x\text{ + 3) (3x + 4)} \end{gathered}[/tex]The factor of the above function is (2x + 3) (3x + 4)
Use the substitution u = (2x - 2) to evaluate the integral x³e(^2x^4-2) dx
The substitution u = (2x - 2) to the integral x³e(^2x^4-2) dx is (2x – 2)/4 +c
What is meant by integral?In mathematics, an integral assigns numerical values to functions in order to describe concepts like displacement, area, volume, and other outcomes of the combination of infinitesimally small data. Integral discovery is a process that is referred to as integration. One of the fundamental, crucial operations of calculus, along with differentiation, is integration[a]. It can be used to solve issues in mathematics and physics involving, among other things, the volume of a solid, the length of a curve, and the area of an arbitrary shape. The integrals listed here are those that fall under the category of definite integrals, which can be thought of as the signed area of the region in the plane that is enclosed by the graph of a particular function between two points on the real line.Therefore,
Use the substitution
U = (2x -2)
to evaluate integral x³e(^2x^4-2) dx
let u = 2x -2
du = x dx or dx =du/2
u = 2x-2
du = d(2x – 2)
du = 2dx
dx = du/2
∫ (2x -2)dx = ∫u du/2
=1/2 ∫u du
= ½ u square /2 +c
= u square /4 +c
= (2x – 2)/4 +c
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The Cunninghams are moving across the country. Mr.Cunningham leaves 3 hours before Mrs. Cunningham. If he averages 55 mph and sheaverages 75 mph, how many hours will it take Mrs. Cunningham to catch up to Mr. Cunninham to catch up to mr.cunningham
Solution:
Remember, distance traveled is the rate times the time. (d = rt) Mrs. Cunningham will overtake Mr. Cunningham when they have traveled the same distance.
Mrs. Cunningham's equation will be:
[tex]d=\text{ }75t[/tex]Since he was traveling 3 hours longer, Mr. Cunningham's equation will be:
[tex]d=55(t+3)[/tex]If they travel the same distance, the equations can be set equal to each other:
[tex]\text{ }75t=55(t+3)[/tex]applying the distributive property, this is equivalent to:
[tex]\text{ }75t=55t\text{ +165}[/tex]this is equivalent to:
[tex]75t-55t\text{ = 165}[/tex]this is equivalent to:
[tex]20t\text{ = 165}[/tex]solving for t, we obtain:
[tex]t\text{ =}\frac{165}{20}=8.25[/tex]So that, we can conclude that the correct answer is:
It will take Mrs. Cunningham 8.25 hours to overtake her husband.
Can someone please help me with this drag and drop? I would appreciate It a lot! Please explain :) I’ll give brainliest
Answer:
move B to true then everything is right ✅
Suppose that $16,065 is invested at an interest rate of 6.6% per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time t, in years. b) What is the balance after 1 year? 2 years?5 years? 10 years? c) What is the doubling time?
Okay, here we have this:
Considering the provided information we obtain the following:
a)
Replacing in the Compound Interest formula we obtain the following:
[tex]\begin{gathered} A(t)=Pe^{rt} \\ A(t)=16065e^{0.066t} \end{gathered}[/tex]b)
After 1 year (t=1):
[tex]\begin{gathered} A(1)=16065e^{0.066(1)} \\ A(1)\approx17,161.06 \end{gathered}[/tex]We obtain that after one year the balance is aproximately $17,161.06.
After 2 years (t=2):
[tex]\begin{gathered} A(2)=16065e^{0.066(2)} \\ A(2)=18331.90 \end{gathered}[/tex]We obtain that after two years the balance is aproximately $18,331.90
After 5 years (t=5):
[tex]\begin{gathered} A(5)=16065e^{0.066(5)} \\ A(5)=$22,345.90$ \end{gathered}[/tex]We obtain that after five years the balance is aproximately $22,345.90.
After 10 years (t=10):
[tex]\begin{gathered} A(10)=16065e^{0.066(10)} \\ A(10)=$31,082.44$ \end{gathered}[/tex]We obtain that after ten years the balance is aproximately $31,082.44.
c)
In this case the doubling time will be when she has double what she initially had, that is: $16,065*2=$32130, replacing in the formula:
[tex]32130=16065e^{0.066t}[/tex]Let's solve for t:
[tex]\begin{gathered} 32130=16065e^{0.066t} \\ 16065e^{\mleft\{0.066t\mright\}}=32130 \\ \frac{16065e^{0.066t}}{16065}=\frac{32130}{16065} \\ e^{\mleft\{0.066t\mright\}}=2 \\ 0.066t=\ln \mleft(2\mright) \\ t=\frac{\ln\left(2\right)}{0.066} \\ t\approx10.502years \end{gathered}[/tex]Finally we obtain that the doubling time is approximately 10.502 years or about 10 years 6 months.
Which of the following could be the areas of the three squares below? A. 12ft^2, 16ft^2, 20ft^2B. 10ft^2, 18ft^2, 30ft^2C. 4ft^2, 5ft^2, 12ft^2D. 8ft^2, 16ft^2, 24ft^2i have to show work too :(
The correct option is D
8ft^2, 16ft^2, 24ft^2 could be the three areas of the given squares
Explanation:To know the area of the three squares, we need to know the side length of each square. This can be done by applying Pythagorean rule on the right-angle triangle formed in the middle.
The square of the longest side (hypotenuse) is equal to the sum of the squares of the other two sides (legs).
The area of a square is the square of its side length.
Taking the square roots of each of the given options, which ever option has Pythagorean triple is the correct option.
A.
[tex]2\sqrt[]{3},4,2\sqrt[]{5}[/tex]This is NOT a Pythagorean triple.
B.
[tex]\sqrt[]{10},3\sqrt[]{2},\sqrt[]{30}[/tex]This is NOT a Pythagorean triple.
C.
[tex]2,\sqrt[]{5},2\sqrt[]{3}[/tex]This is NOT a Pythagorean triple
D.
[tex]2\sqrt[]{2},4,2\sqrt[]{6}[/tex]This is a Pythagorean triple.
CHECK[tex]\begin{gathered} (2\sqrt[]{2})^2+4^2=(2\sqrt[]{6})^2 \\ 8+16=24 \\ 24=24 \end{gathered}[/tex]Yea I can see if it works if it’s okay
SOLUTION
We want to find the derivative of
[tex]y=sin(1.2t-3.7)[/tex](a) So, using chain rule, the inside function is u,
we have the inside:
[tex]u=1.2t-3.7[/tex]outside becomes
[tex]y=sin(u)[/tex](b) The derivative of
inside, we have
[tex]\frac{du}{dt}=1.2[/tex]derivative of the outside, we have
[tex]\frac{dy}{du}=cos(u)[/tex]chain rule we have
[tex]\begin{gathered} \frac{dy}{dt}=\frac{dy}{du}\times\frac{du}{dt} \\ =cos(u)\times1.2 \\ =cos(1.2t-3.7)\times1.2 \end{gathered}[/tex]Hence the answer is
[tex]\frac{dy}{dt}=1.2cos(1.2t-3.7)[/tex]A manager measured the number of goods, y, that his company produced in a hours. The
company produces goods at a rate of 5 per hour. At hour 9, the company had produced 45
goods.
Which equation, in point-slope form, correctly represents the goods produced by the company
after x hours?
Oy-45 = 5(x-9)
Oy+9= 5(x +45)
Oy 45= 5(x + 9)
Oy-9=5(x - 45)
Answer:
[tex]y-45=5(x-9)[/tex]
Step-by-step explanation:
Definition of the variables:
y = total number of goods produced.x = time in hours.Given information:
The company produces goods at a rate of 5 per hour. At hour 9, the company had produced 45 goods.As the rate of change is constant and linear, the rate of change is the slope of the line. Therefore, the slope is 5.
At hour 9 (x-value) the company had produced 45 (y-value) goods. Therefore, this can be represented by the point (9, 45).
[tex]\boxed{\begin{minipage}{5.8 cm}\underline{Point-slope form of a linear equation}\\\\$y-y_1=m(x-x_1)$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $(x_1,y_1)$ is a point on the line.\\\end{minipage}}[/tex]
Substitute the found slope and point into the point-slope formula:
[tex]\implies y-y_1=m(x-x_1)[/tex]
[tex]\implies y-45=5(x-9)[/tex]
Therefore, the equation that correctly represents the goods produced by the company after x hours is:
[tex]\boxed{y-45=5(x-9)}[/tex]
the top of the hill rises 67 feet above checkpoint 4, which is -211. What is the altitude of the top of the hill?
Answer:
-144 feet
Step-by-step explanation:
-211 plus the added 67 feet it is above equals an altitude of -144ft
find the value of x
For supplementary angles, we can do the following equality
[tex]3x+4=x+70[/tex]What we have to do, is to clear "x" to find its value.
[tex]\begin{gathered} 3x-x=70-4 \\ 2x=66 \\ x=\frac{66}{2} \\ x=33 \end{gathered}[/tex]In conclusion, the value of x is 33
Suppose you deposit $600 into an account that pays 5% annual interest, compounded continuously. How much will you have in the account in 4 years? ƒ(t) = ae^rt
To determine the amount that will be on the account after 4 years you have to apply the given exponential function that models the amount of money on the account with respect to the time.
[tex]f(t)=ae^{rt}[/tex]Where
a represents the initial amount
r represents the interest rate expressed as a decimal value
t is the time period in years
The initial amount on the account is a= $600
The time period is t= 4 years
The interest rate is r=5%, divide it by 100 to express it as a decimal value:
[tex]r=\frac{5}{100}=0.05[/tex]Using this information, you can calculate the final amount:
[tex]\begin{gathered} f(t)=ae^{rt} \\ f(4)=600e^{0.05\cdot4} \\ f(4)=600e^{0.2} \\ f(4)=732.84 \end{gathered}[/tex]After 4 years there will be $732.84 on the account. The correct option is B.
7. 4×= 3yy=-4x + 39. y+2=0x+ 2 = 011.x-5y=45x + y = 4Determine if the graphs will show parallel or perpendicular lines, or neither.
Given:
[tex]\begin{gathered} 4x=3y \\ y=-4x+3 \end{gathered}[/tex]Sol:.
If the both line are perpendicular then multipilcation of slope is -1 then:
[tex]\begin{gathered} y=mx+c \\ m=\text{slope} \\ \end{gathered}[/tex][tex]\begin{gathered} 3y=4x \\ y=\frac{4}{3}x \\ m_1=\frac{4}{3} \end{gathered}[/tex][tex]\begin{gathered} y=-4x+3 \\ m_2=-4 \end{gathered}[/tex][tex]\begin{gathered} =m_1m_2 \\ =\frac{4}{3}\times-4 \\ m_1m_2\ne-1 \\ \text{That mean its not perpendicular } \end{gathered}[/tex]For parallel line slope are same then its not a parallel line
So line neither perpendicular or parallel.
I need help with this question Write and expression that models the situation:Sarah has spent x dollars out of the 30 dollars she started with.
Okay, here we have this:
Considering that it says "spent", it represents an outflow of money, therefore we take it as negative, so we obtain:
Actual Situation: Initial money - money spent
Actual Situation: 30 - x
A number cube is rolled once, {1,2,3,4,5,6)Determine the likelihood of each situation,Column AColumn B1.rolling an even numbera. unlikely2.rolling a 7b. impossible3.rolling a number greater than 0Ccertain4.rolling a number that is greater than 2d. likely5.rolling a 2 or 3e equally likely
The likelihood of the following situations:
1. rolling an even number is likely.
2. rolling a 7 is impossible.
3. rolling a number greater than 0 is certain.
4. rolling a number that is greater than 2 is likely.
5. rolling a 2 or 3 is equally likely
Factor the following polynomials. Remember, factoring strategies for quadratic polynomials may be needed here.
For this problem, we are given a polynomial, and we need to factor it.
The polynomial is given below:
[tex]64-324x^4[/tex]We can use the difference between two squares to factor this polynomial. The base form of this notable product is shown below:
[tex]\begin{gathered} (a-b)(a+b)=a^2-b^2\\ \\ \end{gathered}[/tex]We can do the same with the original polynomial:
[tex]64-324x^4=8^2-(18x^2)^2=(8-18x^2)(8+18x^2)[/tex]The answer is (8-18x²)(8+18x²).
he multiplication table below can be used to find equivalent ratios.
A multiplication table.
Which ratio is equivalent to the ratio 18:24?
15:20
20:15
30:36
36:30
Answer:
15:20
Step-by-step explanation:
18:24 can be written [tex]\frac{18}{24}[/tex] if I simplify this by dividing the top and bottom by 6, I get [tex]\frac{3}{4}[/tex]
I am looking for what other ration will reduce to [tex]\frac{3}{4}[/tex]
[tex]\frac{15}{20}[/tex] Divide the top and bottom by 5 and you will get [tex]\frac{3}{4}[/tex]
number one name three collinear points number to name four coplanar Point number three name two sets of lines intersect number for name two points not contained in the plane
The points lying on a single line are called colinear points. So here,
KJD are colinear points as they are lying on a same line.
Points lying on the same plane are called coplanar points. So here, IJFE are coplanar points.
The two sets of line intesects are KD and CF, IG and FH.
The two points that are not in the plane are A and B.
50 Points
A rectangle has sides measuring (2x + 5) units and (3x + 7) units.
Part A: What is the expression that represents the area of the rectangle? Show your work.
Part B: What are the degree and classification of the expression obtained in Part A?
Part C: How does Part A demonstrate the closure property for the multiplication of polynomials?
The expression that represents the area of the rectangle is 6x²+29x+35.
Given that, a rectangle has sides measuring (2x + 5) units and (3x + 7) units.
What is the area of a rectangle?The area occupied by a rectangle within its boundary is called the area of the rectangle. The formula to find the area of a rectangle is Area = Length × Breadth.
Part A:
Now, area = (2x+5)(3x+7)
= 2x(3x+7)+5(3x+7)
= 6x²+14x+15x+35
= 6x²+29x+35
So, the area of a rectangle is 6x²+29x+35
Part B:
A polynomial's degree is the highest or the greatest power of a variable in a polynomial equation.
Here, the degree of the expression 6x²+29x+35 is 2.
Part C:
Closure property of multiplication states that if any two real numbers a and b are multiplied, the product will be a real number as well.
Here, we obtained product of two binomials is trinomial
Therefore, the expression that represents the area of the rectangle is 6x²+29x+35.
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The average score for games played in the NFL is 22 and the standard deviation is 9.3 points. 41 games are randomly selected. Round all answers to 4 decimal places where possible and assume a normal distribution.
a. What is the distribution of ¯x x¯
? ¯xx¯ ~ N( , )
b. What is the distribution of ∑x ? ∑x ~ N ( , )
c. P( ¯x > 19.8214) =
d. Find the 60th percentile for the mean score for this sample size.
e. P(20.6214 < x¯< 23.2262) =
f. Q1 for the x¯distribution =
g. P( ∑x > 829.0774) =
For part c) and e), Is the assumption of normal necessary? NoYes
Using the normal distribution and the central limit theorem, it is found that:
a) The distribution is: x¯ ~ N(22, 1.45).
b) The distribution is: ∑x ~ N(902, 59.55).
c) P( ¯x > 19.8214) = 0.9332 = 93.32%.
d) The 60th percentile for the mean score for this sample size is of 22.37 points a game.
e) P(20.6214 < x¯< 23.2262) = 0.6312 = 63.12%.
f) Q1 for the x¯distribution = 21 points a game.
g) P( ∑x > 829.0774) = 0.8888 = 88.88%.
Assumption of normality is not necessary, as the sample sizes are greater than 30.
Normal Probability DistributionThe z-score of a measure X of a variable that has mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure X is above or below the mean of the distribution, depending if the z-score is positive or negative.From the z-score table, the p-value associated with the z-score is found, and it represents the percentile of the measure X in the distribution.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].Also by the Central Limit Theorem, for the sum of n instances of a variable, the mean is of [tex]\n\mu[/tex] and the standard deviation is of [tex]\sigma\sqrt{n}[/tex].Finally, by the Central Limit Theorem, assumption of normality is only necessary when the sample size is less than 30.For a single game, the mean and the standard deviation of the number of points scored are given as follows:
[tex]\mu = 22, \sigma = 9.3[/tex]
For the average of 41 games, the standard error is:
[tex]s = \frac{9.3}{\sqrt{41}} = 1.45[/tex]
Hence the distribution is: x¯ ~ N(22, 1.45).
For the sum of the 41 games, the mean and the standard error are given as follows:
41 x 22 = 902.[tex]s = 9.3\sqrt{41} = 59.55[/tex].Hence the distribution is: ∑x ~ N(902, 59.55).
In item c, the probability is one subtracted by the p-value of Z when X = 19.8214, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem:
[tex]Z = \frac{X - \mu}{s}[/tex]
Z = (19.8214 - 22)/1.45
Z = -1.5
Z = -1.5 has a p-value of 0.0668.
1 - 0.0668 = 0.9332 = 93.32%.
The 60th percentile for the distribution is X when Z = 0.253, hence:
[tex]Z = \frac{X - \mu}{s}[/tex]
0.253 = (X - 22)/1.45
X - 22 = 0.253 x 1.45
X = 22.37.
For item e, the probability is the p-value of Z when X = 23.2262 subtracted by the p-value of Z when X = 20.6214, hence:
X = 23.2262:
[tex]Z = \frac{X - \mu}{s}[/tex]
Z = (23.2262 - 22)/1.45
Z = 0.85
Z = 0.85 has a p-value of 0.8023.
X = 20.6214:
[tex]Z = \frac{X - \mu}{s}[/tex]
Z = (20.6214 - 22)/1.45
Z = -0.95
Z = -0.95 has a p-value of 0.1711.
0.8023 - 0.1711 = 0.6312 = 63.12%.
The first quartile for the distribution is X when Z = -0.675, hence:
[tex]Z = \frac{X - \mu}{s}[/tex]
-0.675 = (X - 22)/1.45
X - 22 = -0.675 x 1.45
X = 21.
For item g, the probability is one subtracted by the p-value of Z when X = 829.0774, hence:
[tex]Z = \frac{X - \mu}{s}[/tex]
Z = (829.0774 - 902)/59.55
Z = -1.22
Z = -1.22 has a p-value of 0.1112.
1 - 0.1112 = 0.8888 = 88.88%.
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Sue wants to plant 545 acres of wheat. She has planted a 128 acre field near the river. Whatpercent of her wheat crop has she planted?
Percentage of the wheat crop planted = 128/ 545 x 100
= 12800/545
= 23.4 percent
please help me please
F (x) = (-1/20)x + 13.6
Then
Radmanovics car y -intercept is= 13.6 gallons
Mr Chin's car y-intercept is= 13.2
Then , in consecuence
Radmanovics car has a larger tank, than Mr Chin's car.
Answer is OPTION D)
can someone please help!!!
The simplified expression is as follows:
[tex]\frac{\frac{3x^{6} }{14y^{9} } }{\frac{33x^{4} }{10y^{2} } } = \frac{5x^{2} }{77y^{7} }[/tex]
How to simplify expression?The expression can be simplified as follows:
To simplify an expression means to write an equivalent expression which contains no similar terms.
This means that we will rewrite the expression with the fewest terms possible.
Therefore,
[tex]\frac{\frac{3x^{6} }{14y^{9} } }{\frac{33x^{4} }{10y^{2} } }[/tex]
The expression can be represented as follows:
3x⁶ / 14y⁹ ÷ 33x⁴ / 10y²
3x⁶ / 14y⁹ × 10y² / 33x⁴
Hence,
3x⁶ / 14y⁹ × 10y² / 33x⁴ = 30x⁶y² / 462x⁴y⁹
Therefore,
30x⁶y² / 462x⁴y⁹ = 10x² / 154y⁷ = 5x² / 77y⁷
Hence,
[tex]\frac{\frac{3x^{6} }{14y^{9} } }{\frac{33x^{4} }{10y^{2} } } = \frac{5x^{2} }{77y^{7} }[/tex]
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True or False? A circle could be circumscribed about the quadrilateral below.B82"O A. TrueA 105°98° cO B. False75%
Solution
For this case since we want to verify if a circle can be circumscribed in the quadrilateral we can use the following Theorem:
Theorem: If a quadrilateral is incribed in a circle then the opposite sides are supplementary
And we cna verify:
105+ 98= 203
82 +75= 157
Then we can conclude that the answer is:
False
the Center is (2,0) the circle passes through the point (4.5,0) What is the Radius?
The radius of the circumference would be
x2 = 4.5
x1 = 2
r = x2 - x1
r = 4.5 - 2.0
r = 2.5
The radius would be 2.5
1 punto Two distinct coplanar lines that do not intersect are known as lines * A. parallel B. perpendicular C. skew D. Tangent
Coplanar lines are lines that lies in the same plane.
By definition, two distince lines that lies in the same plane and that do not intersect are said to be parallel
Hence the correct choice is A
6. Suppose that wedding costs in the Caribbean are normally distributed with a mean of $6000 and a standard deviation of $735. Estimate the percentage of Caribbean weddings that cost (a) between $5265 and $6735. % (b) above $6735. % (c) below $4530. % (d) between $5265 and $7470. %
To solve this problem, the first thing we must do is find the Z-Score of the given costs: $5265 , $6735 , $4530 ,and $7470
Then we proceed to find the percentages for each interval based on the graph
z-score for $5265 )
[tex]Z_{5265}=\frac{5265-6000}{735}=-1[/tex]z-score for $6735 )
[tex]Z_{6735}=\frac{6735-6000}{735}=1[/tex]z-score for $4530 )
[tex]Z_{4530}=\frac{4530-6000}{735}=-2[/tex]z-score $7470 )
[tex]Z_{7470}=\frac{7470-6000}{735}=2_{}[/tex]now, let's analyze the intervals
a ) between $5265 and $6735
This interval goes from (μ-σ) to (μ+σ)
if we look at the graph we find that this corresponds to a percentage of 68%
b) above $6735
This corresponds to what is to the right of (μ+σ)
This is a percentage of 16%
[tex]\frac{100-68}{2}=\frac{32}{2}=16[/tex]c ) below $4530
This corresponds to what is to the left of (μ-2σ)
This is a percentage of 2.5%
[tex]\frac{100-95}{2}=\frac{5}{2}=2.5[/tex]d ) between $5265 and $7470
This interval goes from (μ-σ) to (μ+2σ)
This is a percentage of 81.5%
[tex]\begin{gathered} 100-\frac{100-68}{2}-\frac{100-95}{2} \\ =100-16-2.5 \\ =81.5 \end{gathered}[/tex]