Answer:
69
Explanation:
Perform addition first as;
(0.210 + 0.41) = 0.62 -------{2 significant figures}
Perform product
(1.10 x 102) = 112 -------------- {3 significant figures}
The combined product
0.62 x 112 =69.44
= 69 ----------2 significant figures
Rule
The least number of significant figures in the numbers performing the operation determines the number of significant figures in the answer.
Amy finds the voice of her text-to-speech tool annoying. What should she do?
try to change the voice
stop using the tool
turn down the volume
reprogram the tool
Answer:
A
Explanation:
So basically there is this chart and all you just to name what energy will transform into what energy so like here is just an example like solar to mechanical or something like sorry the arrows are a bit scuffed
Answer:
free points let's gooo
The amplitude of oscillations reduces to one-sixth of its original value in 10 oscillations. Find the logarithmic decrement.
Answer:
Explanation:To describe a damped harmonic oscillator, add a velocity dependent term, bx, where b is the vicious damping coefficient.
Atoms are split at power plant to create electricity*
O A. Radiant to Mechanical
O B. Nuclear to Electrical
O C. Chemical to Radiant
D. Mechanical to Electrica;
help please I’m in a test that closes at 6
Answer:
B. Nuclear to Electrical
Explanation:
Atoms are split at power plants to create electricity. The energy conversion in this process is from nuclear to electrical energy.
When atoms are split, nuclear energy is released. Some part of the mass of the atom is converted to energy. The nuclear energy released is expressed as heat energy. This energy is used to heat water in boilers when produces steam that are used to drive the movement of turbines. This in turn generates electricity.A heater is rated to dissipate 1440 W when connected to a 120 V source. The current drawn by the device is
Answer:
The current drawn by the heater is 12 A.
Explanation:
Given;
power dissipated by heater, P = 1440 W
Source voltage, V = 120 V
The electric power of the heater is given by;
P = IV
Where;
I is the current drawn by the heater
Make I the subject of the formular;
I = P / V
Substitute the given values and solve for the current "I";
I = 1440 / 120
I = 12 A
Therefore, the current drawn by the heater is 12 A.
Problem 10: A simple pendulum with mass, m=1 kg and length, L=2.0 m is released by
a push when the support string is at an angle of 45° from the vertical direction. The initial
speed of the suspended mass at the release point is 3.0 m/s.
(a) The maximum angle that pendulum moves in the second half of its swing is
(b) The mechanical energy of pendulum (measured relative to its lowest point) is
Answer:
A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?
Explanation:
Janet jumps horizontally off a high diving platform with a velocity of 2.63 m/s and lands in the water 1.9 s later. How high is the platform
Answer:
The height of the platform is 22.686 m.
Explanation:
Given;
initial velocity of Janet, u = 2.63 m/s
time of her motion, t = 1.9 s
The height of the platform is given by;
h = ut + ¹/₂gt²
substitute the given values and solve for height "h"
h = (2.63 x 1.9) + ¹/₂(9.8)(1.9)²
h = 4.997 + 17.689
h = 22.686 m
Therefore, the height of the platform is 22.686 m.
A 135 kg horizontal platform is a uniform disk of radius 1.95 m and can rotate about the vertical axis through its center. A 63.7 kg person stands on the platform at a distance of 1.05 m from the center, and a 30.1 kg dog sits on the platform near the person 1.33 m from the center. Find the moment of inertia of this system, consisting of the platform and its population, with respect to the axis.
Answer:
the moment of inertia is 380.14 kg-m^2
Explanation:
The computation of the moment of inertia is as follows:
The net moment of inertia is
= MR^2 ÷ 2 + m_p d_p^2 + m_d d_d^2
= 135 × 1.95^2 ÷2 + 63.7 × 1.05^2 + 30.1 × 1.33^2
= 380.14 kg-m^2
hence, the moment of inertia is 380.14 kg-m^2
We simply applied the above formula so that the correct value could come
And, the same is to be considered
Calculate the time needed to accelerate a 50 kg object from 2 m/s to 12 m/s if a force of 10 N is
applied.
Hi there!
[tex]\large\boxed{\text{50 seconds.}}[/tex]
Begin by calculating the acceleration on the object by using the formula
F = m · a (Newton's Second Law) where:
F = Force (N)
m = Mass (kg)
a = acceleration (m/s²)
Plug in the given values:
10 = 50 · a
10 = 50a
10 / 50 = a
a = 1/5 = 0.20 m/s²
Solve for the time using the kinematic equation:
Δv / a = t, or (vf - vi) / a = t
Plug in the acceleration along with the initial and final velocites into the equation:
(12 - 2) / 0.20 = 10 / 0.20 = 50 seconds.
Can someone help me with this question please picture is above
Answer:
It should be B.
Explanation:
Because expansionary monetary policy works by expanding the money supply faster than usual or lowering short-term interest rates. It is enacted by central banks and comes about through open market operations, reserve requirements, and setting interest rates.
I hope this helped!!!
If a net force is acting on an object, then the object is definitely
at rest
Оа
Ob
с
moving at a constant velocity
being accelerated.
losing mass
Od
Answer:
it is being accelerated
Explanation:
A student claimed that thermometers are useless because a thermometer always registers its own
temperature. How would you respond?
Answer:
I wud respond no, actually it registers ur temperature
If mechanical energy is converted to thermal energy, then the spring would not compress as far as it would otherwise. This will cause the spring constant to be lower than it really is.
a. True
b. False
Answer:
False.
Explanation:
Given that if mechanical energy is converted to thermal energy, then the spring would not compress as far as it would otherwise. This will cause the spring constant to be lower than it really is.
This statement is false. Because if mechanical energy is converted to thermal energy, there will be distortions in the solid pattern of the spring. And this will make the spring to compress.
Also, no matter what may happen to the spring, the spring constant remains constant. That is, unchanged.
Is this a scientific model? Use complete sentences to explain why or why not.
Answer:
Yes
Explanation:
This is a scientific model as it represents complex objects, events, and a physical process. It has detail and an image that is relevant and helps to understand the process if that's water cycle.
A mouse is running across a room with a speed of 2.2 m/s. The mass of the mouse is 1.4 kg. What is the Kinetic Energy of the mouse?
Answer:
3.39 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
From the question we have
[tex]k = \frac{1}{2} \times 1.4 \times {2.2}^{2} \\ = 0.7 \times 4.84 \\ = 3.388 \: \: \: \: \: \: \: \: \: [/tex]
We have the final answer as
3.39 JHope this helps you
Answer:
im not sure
Explanation:
Today, the universe is considered to be in which shape?
Answer:
is it a spear
Explanation:
Which requires more work: lifting a 100 kg sack a vertical distance of 2 m or lifting a 50 kg sack a vertical distance of 4 m?Explain.
Answer:
They both require the same amount of work.
Explanation:
Work is said to be done if the force applied to a body cause the boody to move through a distance. Mathematically;
Workdone = Force * Distance
Workdone = mass * acceleration due to gravity * Distance
For the 100kg sack lifted through a distance of 2m:
Workdone = 100 * 9.8 * 2
Workdone = 980 * 2
Workdone = 1960Joules
For 50kg sack lifted through a distance of 4m;
Workdone = 50 * 9.8 * 4
Workdone = 200 * 9.8
Workdone = 1960Joules.
Since the workdone in carry both sack is the same, hence they both require the same amount of work.
A typical road bike wheel has a diameter of 70 cm including the tire. In a time trial, when a cyclist is racing along at 12 m/s how fast is a point at the top of the tire moving?
Answer:
24 m/s
Explanation:
Given that,
A typical road bike wheel has a diameter of 70 cm including the tire.
Speed of the cyclist = 12 m/s
We need to find the speed at the top of the tire moving. The velocity of the topmost point is twice that of the velocity of the object.
v = 2 × 12
= 24 m/s
Hence, the required velocity is 24 m/s.
The speed at which the point at the top of the tire moves is 24 m/s.
Given that,
A typical road bike wheel has a diameter of 70 cm including the tire.In a time trial, when a cyclist is racing along at 12 m/s.Based on the above information, the calculation is as follows:
We know that the velocity of the point should be the twice of the object velocity.
So,
= 2 (12)
= 24 m/s
Therefore we can conclude that the speed at which the point at the top of the tire moves is 24 m/s.
Learn more: brainly.com/question/23334479
Sandy soil has a relatively low thermal conductivity. Therefore, the surface layer over sandy soil will normally reach a lower temperature during the day than it would over soil that is moist or covered with vegetation.
a. True
b. False
Answer:
False
Explanation:
Granted, sandy soil has low conductivity, but the surface layer of sandy soil isn't low particularly during the day. Sandy soil reacts more to temperature when compared with other types of soil, and as such, during the day under a hot temperature, the texture of sandy soil is usually hot, and not low like the question suggested. Invariably, the inference the question is making is wrong and not correct, so false
If the original experiment is repeated with a 1.0 kg aluminum block, what is the final temperature of the water and block
Answer:
T₂ = 36.36°C
Explanation:
The complete question is:
A 0.5 kg block of aluminum (Caluminum = 900J/kg*C)is heated to 200 C. The block is then quickly placed in an insulated tub of cold water at 0C (Cwater=4186J/kg*C) and sealed. At equilibrium, the temperature of the water and block are measured to be 20C.
A) If the original experiment is repeated with a 1.0 kg {kg} aluminum block, what is the final temperature of the water and block?
Answer: We will apply the law of conservation of energy here:
Heat Loss by Aluminum Block = Heat Gained by Water
m₁C₁ΔT₁ = m₂C₂ΔT₂
where,
m₁ = mass of aluminum block
C₁ = Specific Heat Capacity of Aluminum Block = 900 J/kg °C
ΔT₁ = Change in Temperature of Aluminum Block
m₂ = mass of water
C₂ = Specific Heat Capacity of Water = 4186 J/kg °C
ΔT₂ = Change in Temperature of water
Therefore, for initial given condition:
m₁ = 0.5 kg
ΔT₁ = 200°C - 20°C = 180°C
m₂ = ?
ΔT₂ = 20°C - 0°C = 20°C
Therefore,
(0.5 kg)(900 J/kg °C)(180°C) = m₂(4186 J/kg °C)(20°C)
m₂ = 81000 J/(83720 J/kg)
m₂ = 0.97 kg
Now, we have the mass of water. So, we can solve for the final equilibrium temperature if the mass of block is changed to 1 kg. So, for the new state:
m₁ = 1 kg
m₂ = 0.97 kg
ΔT₁ = 200°C - T₂
ΔT₂ = T₂ - 0°C
T₂ = Final Equilibrium Temperature = ?
Therefore,
(1 kg)(900 J/kg °C)(200°C - T₂) = (0.97 kg)(4186 J/kg °C)(T₂ - 0°C)
180000 J - (900 J/°C)(T₂) = (4050 J/°C)(T₂)
180000 J = (900 J/°C)(T₂) + (4050 J/°C)(T₂)
T₂ = (180000 J)/(4950 J/°C)
T₂ = 36.36°C
A 1990 kg car moving at 20.0 m/s collides and locks together with a 1540 kg car at rest at a stop sign. Show that momentum is conserved in a reference frame moving at 10.0 m/s in the direction of the moving car.
Answer:
The momentum before collision and momentum after collision is equal in a frame of reference moving at 10.0 m/s in the direction of the moving car.
Explanation:
[tex]m_1[/tex] = Mass of moving car = 1990 kg
[tex]u_1[/tex] = Velocity of moving car in stationary frame = 20 m/s
[tex]m_2[/tex] = Mass of stationary car = 1540 kg
[tex]u_2[/tex] = Velocity of stationary car in stationary frame = 0 m/s
v = Combined velocity in stationary frame
Momentum conservation for stationary frame
[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{1990\times 20+0}{1990+1540}\\\Rightarrow v=\dfrac{3980}{353}\ \text{m/s}[/tex]
In frame moving at 10 m/s the velocities change in the following ways
[tex]u_1=20-10\\\Rightarrow u_1=10\ \text{m/s}[/tex]
[tex]u_2=0-10\\\Rightarrow u_1=-10\ \text{m/s}[/tex]
[tex]v=\dfrac{3980}{353}-10\\\Rightarrow v=\dfrac{450}{353}\ \text{m/s}[/tex]
Momentum before collision
[tex]m_1u_1+m_2u_2=1990\times 10+1540\times -10\\\Rightarrow m_1u_1+m_2u_2=4500\ \text{kg m/s}[/tex]
Momentum after collision
[tex](m_1+m_2)v=(1990+1540)\times \dfrac{450}{353}\\\Rightarrow (m_1+m_2)v=4500\ \text{kg m/s}[/tex]
The momentum before collision and momentum after collision is equal. So, the momentum is conserved in a reference frame moving at 10.0 m/s in the direction of the moving car.
What is the water pressure at the deepest part of the ocean in the Challenger Deep in the Mariana Trench at 10,994 m below the surface.
Answer:
The pressure is 107417976.4 N[tex]m^{-2}[/tex]
Explanation:
The pressure of water at a given height/ depth can be determined by:
Pressure = σhg
Where: σ is the density of water, h is the height/ depth, and g is the gravitational force.
Given that; h = 10994 m, but σ = 997 kg/[tex]m^{3}[/tex] and g = 9.8 m/[tex]s^{2}[/tex]
Thus, the pressure of water at the deepest part of the ocean will be:
Pressure = 997 x 10994 x 9.8
= 997 x 107741.2
= 107417976.4
Pressure = 107 420 KN[tex]m^{-2}[/tex]
The pressure of water at 10994 m below the surface is 107417976.4 N[tex]m^{-2}[/tex]
What is the only bone of the skull that moves?
Answer:
Mandible.
Explanation:
The mandible in the bone that allows you to open and close your mouth, otherwise known ad the jawbone.
Answer:
mandible
Explanation:
which is also the lower jaw and it allows the mouth to open and close
hope i helped
Light is shone on a diffraction grating
with d = 1.00 x 10-6 m. The second
order (m = 2) maximum occurs at an
angle of 74.6º. What is the
wavelength of the light IN
NANOMETERS?
[?] nm
Hint: The answer will be between 400 and 700.
Answer:
λ = 482.05 nm
Explanation:
The diffraction phenomenon and the diffraction grating is described by the expression
d sin θ = m λ
where d is the distance between two consecutive slits, λ the wavelength and m an integer representing the order of diffraction
in this case they indicate the distance between slits, the angle and the order of diffraction
λ = [tex]\frac{d sin \theta }{m}[/tex]d sin θ / m
let's calculate
λ = 1.00 10⁻⁶ sin 74.6 / 2
λ = 4.82048 10⁻⁷ m
Let's reduce to nm
λ = 4.82048 10⁻⁷ m (10⁹ nm / 1 m)
λ = 482.05 nm
A piano wire has a tension of 650 N and a mass per unit length of 0.060 g/cm. What is the speed of waves on this wire
Answer:
The speed of waves on this wire is 329.14 m/s
Explanation:
Given;
tension of the wire, T = 650 N
mass per unit length, μ = 0.06 g /cm = 0.006 kg/m
(convert the unit of mass per length in g/cm to kg/m by dividing by 10 = 0.06 / 10 = 0.006 kg/m)
The speed of waves on this wire is given as;
[tex]v = \sqrt{\frac{T}{\mu} } \\\\v = \sqrt{\frac{650}{0.006} }\\\\v = 329.14 \ m/s[/tex]
Therefore, the speed of waves on this wire is 329.14 m/s
Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 30.5 m/s (about 68 mph ) around the turn, what is the race car's centripetal (radial) acceleration
Answer:
[tex]a=16.32\ m/s^2[/tex]
Explanation:
Given that,
The radius of the track, r = 57 m
The speed of a race car, v = 30.5 m/s
We need to find the centripetal acceleration of the car. Its formula that is use to find it is given by :
[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(30.5)^2}{57}\\\\=16.32\ m/s^2[/tex]
So, the car's centripetal acceleration is [tex]16.32\ m/s^2[/tex].
The crowd at a concert lifts a singer to a height of 2.2 m. The crowd uses a total of force of 600 N. How much work has the crowd done?
Answer:
1320 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 600 × 2.2
We have the final answer as
1320 JHope this helps you
A material that reflects or absorbs all the light that strikes it is
A. opaque.
B. transparent.
C. translucent.
D. primary.
Answer:
b. transparent
Explanation:
Photons interact with an object by some combination of reflection, absorption and transmission. Some materials, such as plate glass and clean water, transmit much of the light that falls on them and reflect little of it; such materials are called optically transparent.
A 0.2-kg stone attached to a string is swung in a circle with a radius 0.6 m on a horizontal frictionless surface. What is the tension in the string if the stone makes 150 revolutions per minute?
Answer:
The value is [tex]T = 29.58 \ N[/tex]
Explanation:
From the question we are told that
The mass of the stone is [tex]m = 0.2 \ kg[/tex]
The radius of the circle is [tex]r = 0.6 \ m[/tex]
The angular speed is [tex]w = 150 \ rpm = \frac{ 2 * \pi * 150 }{ 60 } = 15.7 \ rad/s[/tex]
Generally the tension in the string is mathematically represented as
[tex]T = m * r * w ^2[/tex]
=> [tex]T = 0.2 * 0.6 * 15.7 ^2[/tex]
=> [tex]T = 29.58 \ N[/tex]
A lever, inclined plane, pulley, wedge,
screw, and
and axle are all
types of simple machines.
O driving
O wheel
A lever, wheel, inclined plane, pulley, wedge, screw, and axle are all types of simple machines.
What is a simple machine?A simple machine can be described as a mechanical device that changes the direction or magnitude of a force. The simplest mechanisms use mechanical advantage to multiply force. A simple machine such as Lever, Wheel and axle, Pulley, Inclined plane, Wedge, and Screw.
A simple machine utilizes a single exerted force to do work against a single load force. Ignoring friction, the work done is equal to the work done by the force.
Simple machines are termed the elementary "building blocks" of which all more complicated machines are composed. The mechanical advantage of a machine is the product of the mechanical advantages of the simple machines of which it is composed.
Learn more about the simple machines, here:
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