Given the equation below, how many moles of nitrogen gas (N2) areneeded to react with 7.5 moles of hydrogen gas (H2)?N2+ 3H2 —>2 NH3

Answers

Answer 1

Answer

2.5 moles of N₂ are needed to react with 7.5 moles of hydrogen gas

Explanation

Given:

Equation: N₂ + 3H₂ → 2NH₃

Moles of H₂ = 7.5 moles

What to find:

The moles of nitrogen gas (N₂) needed to react with 7.5 moles of hydrogen gas

Step-by-step solution:

Let the mole of N₂ needed be x.

From the given balanced chemical equation:

3 moles of H₂ react with 1 mole of N₂

Therefore, 7. 5 moles of H₂ will react with x moles of N₂

Cross multiply

[tex]\begin{gathered} x\text{ moles }N_2\times3\text{ moles H}_2=7.5\text{ moles H}_2\times1\text{ mole N}_2 \\ \text{Divide both sides by 3 moles H}_2 \\ \frac{x\text{ moles }N_2\times3\text{ moles H}_2}{3\text{ moles H}_2}=\frac{7.5\text{ moles H}_2\times1\text{ mole N}_{2}}{3\text{ moles H}_2} \\ x\text{ moles }N_2=2.5\text{ moles} \end{gathered}[/tex]


Related Questions

What is the limiting reactant if 43.4 g of NH3 react with 30 g of NO? The balanced equation is 4NH3 + 6NO --> 5N2 + 6H2O

Answers

Answer

NO is the limiting reactant

Explanation

Given that:

The mass of NH3 that reacted = 43.4 g

The mass of NO that reacted = 30 g

The equation for the reaction is: 4NH3 + 6NO --> 5N2 + 6H2O

What to find:

The limiting reactant.

Step-by-step solution:

The first step is to convert the given mass of the reactants to moles.

Using the mole formula and the molar masses of (NH3 = 17.0 g/mol and NO = 30.0 g/mol)

[tex]\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Moles\text{ }of\text{ }NH_3=\frac{43.4g}{17.031g\text{/}mol}=2.55\text{ }mol \\ \\ Moles\text{ }of\text{ }NO=\frac{30g}{30.0g\text{/}mol}=1.0\text{ }mol \end{gathered}[/tex]

The final step is to determine the limiting reactant by comparing the mole ratio from the given equation with the mole ratio in the step above.

From the equation, 4 moles of NH3 reacted with 6 moles of NO

So 2.55 moles of NH3 is expected to react with (2.55 x 6)/4 = 3.825 moles of NO

1.0 mol NO is less than 3.825 mol NO, hence, NO is the limiting reactant because it will be the reactant to be completely used up first.

What is the density of hydrogen sulfide (H2S) at 0.2 atm and 311 K?Answer in units of g/L

Answers

Answer

Density = 0.267 g/L

Explanation

Given:

Pressure of H2S = 0.2 atm

Temperature = 311 K

We know:

The molar mass of H2S = 34,1 g/mol

R constant = 0.08206 L.atm/K.mol

Solution:

From the ideal gas law:

PV = nRT

We know that:

density = m/V

n = m/M

Therefore we can use the following equation to solve for density of H2S

[tex]\begin{gathered} density\text{ = }\frac{PM}{RT} \\ density\text{ = }\frac{(0.2\text{ atm x 34,1 g/mol\rparen}}{(0.08206\text{ }L.atm/K.mol\text{ x 311 K\rparen}} \\ \\ density\text{ = 0.267 g/L} \end{gathered}[/tex]

Please help me with this question. ​

Answers

Answer:1=B

2=A

Explanation:

If a gas has a pressure of 6 atm , a temp of 53k and a volume of 78 liters but the temp changes to 17k and the pressure changes to 85 atm what is the new volume

Answers

answer and explanation

we are given initial values of temperature, pressure and volume as well as the final value of temperature and pressure and we are asked to find the final volume.

we can do this using the combined gas equation

P1V1/T1 = P2V2/T2

when we plug in the values we get:

(6atm x78L)/53K = (85atm x V2/17K

8.83 = 85atm x V2 / 17K

V2 = 1.77 Liters

What is one way an atom can become more stable?

Answers

Unstable atoms usually are very large atoms with a big nucleus, this configuration sometimes gives the atoms this unstable characteristic, which is why they decay so fast (some will decay in a matter of milliseconds), and radioactive decay is a way that atoms can find to become more stable, in this type of process, particles (alpha and beta decay) and energy (gamma decay), can be emitted from an atom in order to reach stability, therefore the best option is the 3rd option

4 Al(s) + 302(g)->2Al2O3(s)When 42.39 g of Al and 85.16 g of O2 were reacted, 6.67 grams of aluminum oxidewere obtained. What is the percent yield? (Hint: You need to determine which one isthe limiting reactant and then the theoretical yield).

Answers

The reaction presented to us is balanced since we have 4 aluminum atoms and 6 oxygen atoms on both sides of the reaction.

Now, we have a given mass of aluminum and oxygen, we must first determine the moles of each using their molar mass.

Moles of Al

[tex]\begin{gathered} \text{Mol of Al}=GivengAl\times\frac{1molAl}{MolarMass,gAl} \\ \text{Mol of Al}=42.39gAl\times\frac{1molAl}{26.98gAl}=1.57molAl \end{gathered}[/tex]

Moles of O2

[tex]\begin{gathered} MolO_2=GivengO_2\times\frac{1molO_2}{MolarMass,gO_2} \\ MolO_2=85.16gO_2\times\frac{1molO_2}{31.998gO_2}=2.66molO_2 \end{gathered}[/tex]

Now that we have the number of moles, we will calculate what the limiting reagent is, that is, the reagent that limits the reaction by its number of moles.

To find the limiting reactant we must compare the amount of product obtained with the given amount of reactant separately. The reactant that produces the least amount of product is the limiting reactant.

Using Al as limiting reactant

[tex]\begin{gathered} \text{MolAl}_2O_3=MolAl\times\frac{2molAl_2O_3}{4molAl} \\ \text{MolAl}_2O_3=1.57molAl\times\frac{2molAl_2O_3}{4molAl}=0.785molAl_2O_3 \end{gathered}[/tex]

Using O2 as a limiting reactant

[tex]\begin{gathered} \text{MolAl}_2O_3=MolO_2\times\frac{2molAl_2O_3}{3molO_2} \\ \text{MolAl}_2O_3=2.66molO_2\times\frac{2molAl_2O_3}{3molO_2}=1.77molAl_2O_3 \end{gathered}[/tex]

Aluminum is the reagent that produces the least amount of aluminum oxide, so the limiting reagent will be Al. And it will produce 0.785 moles of Al2O3. In grams this will be:

[tex]\text{gAl}_2O_3=0.75molAl_2O_3\times\frac{101.95gAl_2O_3}{1molAl_2O_3}=80.03gAl_2O_3[/tex]

The percent yield will be:

[tex]\begin{gathered} \text{Percent yield=}\frac{\text{Actual yield}}{Theoretical\text{ yield}}\times100\% \\ \text{Percent yield=}\frac{\text{6}.67gA_{}l_2O_3}{80.03ggA_{}l_2O_3}\times100\%=8.33\% \end{gathered}[/tex]

The percent yield will be 8.33%

Match each colored row or group on the table to the family of elements it represents.Green (2nd column)Red (1st column)Purple (two rows below the rest of table)Blue (3rd to 12th columns)?Alkali metals?Alkaline earth metals?Transition metals?Lanthanides and actinides

Answers

Answer:

Green column - Alkaline earth metals

Red column - Alkali metals

Purple column - Lanthanides and actinides

Blue column - Transition metals

Explanations:

The red block are made up of group 1 elements and these elements are known as Alkali metals.

The green column are the group 2 elements in the periodic table and are known as the Alkali earth metals.

For the blue columns, they are element from group 3 to 10 and they are known as the transition metals.

For the purple column, they are Lanthanides and actinides

PLEASE HELP, IT’S DUE TODAY!
Isotopes of certain ___ elements that spontaneously emit ____ and ____ from the _____.

Answers

Isotopes of certain __radioactive__ elements that spontaneously emit __radiation__ and _rays___ from the __nuclei____

What causes isotopes to emit radiation ?

Any of multiple species of the same chemical element with differing masses whose nuclei are unstable and spontaneously produce radiation in the form of alpha, beta, and gamma rays are known as radioactive isotopes, also known as radioisotopes, radionuclides, or radioactive nuclides.

Isotopes are identical elemental atoms with differing quantities of neutrons. Numerous elements have one or more radioactive isotopes. Due to the instability of their nuclei, they decay and release radiation.

Many of the radioisotopes in the uranium, thorium, and actinium natural radiation decay series, as well as the naturally occurring radioisotopes potassium-40 and carbon-14, generate gamma radiation.

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3.0 x 10 ^23 atoms of calcium to moles

Answers

Answer:

[tex]0.5\text{ mole}[/tex]

Explanation:

Here, we want to get the number of moles

Mathematically:

[tex]1\text{ mole has 6.02 }\times\text{ 10}^{23}\text{ atoms}[/tex]

The number of moles in the question would be:

[tex]\frac{3.0\times10^{23}\text{ atoms}}{1}\times\frac{1\text{ mole}}{6.02\times10^{23}\text{ atoms}}\text{ = 0.5 mole}[/tex]

Can you help show me the conversion works for this problem in my online homework please?

Answers

There are 2.04*10^-4 moles of hydrogen.

To start the calculation it is necessary to use the molar mass of glycine:

- Glycine molar mass: 75.08 g/mol.

From the formula of glycine, we know that in 75.08g of glycine, there are 5 moles of hydrogen. So, in 3.06*10^-3g of glycine will be another amount of hydrogen, and we can calculate it with a mthematical Rule of Three:

[tex]\begin{gathered} 75.08\text{gGlycine}-5\text{molHydrogen} \\ 3.06\cdot10^{-3}\text{gGlycine}-x=\frac{3.06\cdot10^{-3}\text{gGlycine}\cdot5\text{molHydrogen}}{75.08\text{gGlycine}} \\ x=2.04\cdot10^{-4}\text{molHydrogen} \end{gathered}[/tex]

So, there are 2.04*10^-4 moles of hydrogen in 3.06*10^-3g of glycine.

Sulfur burns in oxygen to form sulfur dioxide. Write a skeleton equation for this chemical reaction.

Answers

A skeletal chemical equation is a representation of a chemical reaction using chemical formulae of reactants and products.

Sulfur = S

Oxygen = O

Sulfur dioxide = SO2

The skeleton equation is:

[tex]S+O_2\text{ }\Rightarrow SO_2[/tex]

Here the skeleton equation = balanced equation.

The solubility in hexane of organic compound O is measured and found to be 0.520-that would contain 120. mg of O at this temperature.Be sure your answer has the correct unit symbol and 3 significant digits.00.0olo88at 25. °C. Calculate the volume of a saturated solution of O in hexanemLE

Answers

According to the explanation given in the previous session, now we have hexane in an organic compound with the solubility of 0.520 g/mL at 25°C. We need to find the value of volume at 120.0 mg

1 gram = 1000 mg

120.0 mg = 0.12 grams

Now we can calculate the volume:

0.520g = 1 mL

0.12g = x mL

0.520x = 0.12

x = 0.12/0.520

x = 0.231 mL is the volume for this compound

In the following equation, how many grams of CO2 are produced if 2 moles of O2 react completely with methane (CH4)? CH4 + 2O2 -> CO2 + 2H2OHELPFUL INFO: molar mass of CO2=44g/mol, molar mass of O2=32g/mol, molar mass of CH4=16g/mol, and molar mass of water = 18g/mol

Answers

Step 1 - "Reading" the equation

The given chemical equation is:

[tex]CH_{4(g)}+2O_{2(g)}\to CO_{2(g)}+2H_2O_{(l)}[/tex]

The bigger numbers, those that come before the formulas of the substances, indicate the quantity in moles of each substance required in this rection.

We can "read" this reaction thus as :

one mole of CH4 reacts with 2 moles of O2 thus producing one mole of CO2 and two moles of H2O

As the exercise is specifically asking about the proportion between O2 and CO2, we can further simplify this statement to:

two moles of O2 produce one mole of CO2

Step 2 - Obtaining the "recipe" for the reaction

In order to obtain a relation in grams, we need to multiply the number of moles of each substance by its respective molar mass. Let's remember that:

two moles of O2 produce one mole of CO2

Therefore, converting to grams (molar masses: 32 g/mol for O2; 44 g/mol for CO2)

[tex]\begin{gathered} O_2\to2\text{ moles }\times32\text{ g/mole = 64g} \\ CO2\to1\text{ mole }\times44\text{ g/mole = 44g} \end{gathered}[/tex]

We have now obtained the "recipe" for this reaction:

64g of O2 produce 44g of CO2

Pretty much as we would with a cake recipe, we can use this to predict how much CO2 is formed.

Since the reaction of two moles of O2 is exactly what we have already calculated, 44g of CO2 would be formed in this reaction.

If 1495 J of heat is needed to raise the temperature of a 315 g sample of a metal from 55.0°C to 66.0°C, what is the specific heat capacity of the metal?

Answers

The specific heat capacity of the metal that needs 1495 J of heat to raise the temperature is 0.43J/g°C.

How to calculate specific heat capacity?

Specific heat capacity is the heat capacity per unit mass of a substance. It can be calculated by using the following formula:

Q = mc∆T

Where;

Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperature

According to this question, 1495 J of heat is needed to raise the temperature of a 315 g sample of a metal from 55.0°C to 66.0°C. The specific heat capacity can be calculated as follows;

1495 = 315 × c × {66 - 55}

1495 = 3465c

c = 1495/3465

c = 0.43J/g°C

Therefore, 0.43J/g°C is the specific heat capacity of the metal that requires a heat of 1495J.

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how do i calculate the molar mass of 5 and 65. K2Cr2O76. C12H22O11

Answers

To calculate the molar mass of a compound, we need to find at the periodic table the atomic mass of each element that belongs to the compound and then we multiply for the quantity of atoms of it.

So, for:

5. K2Cr2O7:

K = 39 g/mol

Cr = 52 g/mol

O = 16 g/mol

(2x39) + (2x52) + (7x16) = 78 + 104 + 112 = 294 g/mol

Molar mass of K2Cr2O7 = 294 g/mol

6. C12H22O11

C = 12 g/mol

H = 1 g/mol

O = 16 g/mol

(12x12) + (22x1) + (11x16) = 144 + 22 + 176 = 342 g/mol

Molar mass of C12H22O11 = 342 g/mol

What is neutralization reaction? Use an example to describe the components of neutralization reaction

Answers

1) Neutralization reaction.

In this type of reaction an acid and a base react to form a salt and water. In the course of the reaction H+ and OH- are produced. Afterward, they combine to produce water.

2) Example.

Acid: HCl

Base: NaOH

Salt: NaCl

[tex]\text{HCl}+\text{NaOH}\rightarrow NaCl+H_2O[/tex]

Perform the followingmathematical operation, andreport the answer to thecorrect number of significantfigures.

Answers

To find out how many significant numbers there are in a number we can rely on a few rules:

1. Non-zero digits are always significant

2. Any zeros between non-zero digits are significant

3. Final zeros or trailing zeros are significant if they come after the non-zero numbers in a decimal number situation

Example: .500 and .632000

In this question, we have:

0.0016/0.849 = 0.0019, this is the correct value with the correct number of significant figures

I need help with something please

Answers

Since both metals are in the same group in the periodic table and both non-metals are also in the same group in the periodic table, they have the same charge (metals = 1+; non-metals = 1-). So this makes the reaction easier for us:

NaCl + LiBr = LiCl + NaBr

What is the concentration of A pill weighing 325mg containing 22mg Mg

Answers

Step 1 - Understanding percentual concentration

To express the concentration of a substance as a percentual concentration, we just need to divide its mass by the total mass:

[tex]concentration\text{ in \% = }\frac{m_{substance}}{m_{total}}\times100[/tex]

Step 2 - Calculating the concentration in the pill

We want to calculate the concentration of Mg in the pill. Therefore, we'll divide its mass by the total mass of the pill:

[tex]concentration\text{ of Mg =}\frac{22mg}{325mg}\times100=6.8\text{ \%}[/tex]

Answer: the concentration of Mg in the pill is 6.8%

A bike rides at an average speed of 25 km/h. How many minutes will it take for this rider to ride a distance of 20 km?

Answers

Answer:

48 minutes

Explanation:

60 divided by 25 equals 2.4 then you times 2.4 by 20

What is the difference between concentrated and dilute with strong and weak?

Answers

The strength is a measure of the degree of ionization of a substance in an aqueous solution.

Some substances are strong and they dissociate completely (this is the case of hydrochloric acid, HCl, in water), some are weak and they do not dissociate completely (like acetic acid, CH3COOH).

The concentration is a measure of the amount of the substance in a solution and it is usually explessed in moles or percentage. It is a ratio of the substance to the solvent. A concentrated solution is a solution with a high percentage of the substance (solute) in the solution, and a dilute one is a solution with a low percentage of solute.

Which equation is balanced?
O 2Fe +02 → 2Fe2O3
O 3Fe +302 → 3Fe2O3
O 4Fe +302 → 2Fe2O3
O Fe +0₂ Fe₂O3

Answers

Answer:

C) 4Fe + 3O2 → 2Fe2O3

Explanation:

For this question, first you would go through all the options and make sure that there is an equal amount of elements on each side.

For the first option: 2Fe +02 → 2Fe2O3

You have only 2Fe atoms and 2O atoms on your reactant side and 4Fe and 6O atoms on your product side. This is not balanced.

For option b: 3Fe +302 → 3Fe2O3

You have 3Fe and 6O atoms on your reactant side while on your product side you have 6Fe and 6O atoms. This is not balanced.

For option c: 4Fe +302 → 2Fe2O3

You have 4Fe and 6O atoms on your reactant side and 4Fe and 6O atoms on your product side. This is balanced!

For option d: Fe +0₂ → Fe₂O3

You have 1Fe and 2O atoms on your reactant side and 2Fe and 3O atoms on your product side. This is not balanced.

***Remember to multiply the subscript of an element by their coefficient (number in front of molecule) if there is any.

Consider the balanced chemicalreaction below and determine thepercent yield for carbon dioxide if 4.50moles of propane yielded 7.64 moles ofcarbon dioxide.C3H8 +502 + 3CO2 + 4H2O-→

Answers

To solve this, we must know some terms:

% Yield = (Actual yield / Theoretical yield) x 100

Actual yield is already given = 7.64 moles

To obtain the theoretical yield, we use stoichiometry and proceed like this:

C3H8 + 5O2 => 3CO2 + 4H2O

1 mole C3H8 ------- 3 x 1 mole CO2

4.5 moles C3H8 ------ x

x = 13.5 moles

Therefore, our % yield:

% Yield = (7.64 moles/13.5 moles) x 100 = 57 % approximately

Answer: % yield = 57 %

PLEASE HELP ME!!!
A)Nuclear fusion releases protons and neutrons, so the total number of protons
and neutrons in a star changes throughout its life.
B)Nuclear fusion conserves protons and neutrons, so the total number of protons
and neutrons in a star changes throughout its life.
C)Nuclear fusion releases protons and neutrons, so the total number of protons
and neutrons in a star remains the same throughout its life.
D)Nuclear fusion conserves protons and neutrons, so the total number of protons
and neutrons in a star remains the same throughout its life.

Answers

A)Nuclear fusion releases protons and neutrons, so the total number of protons and neutrons in a star changes throughout its life is the true statement.

What are some uses for nuclear fusion?

A suggested method of producing energy would use heat from nuclear fusion processes to produce electricity. A heavier atomic nucleus is created by the fusion of two lighter ones, which also produces energy. Fusion reactors are devices created to use this energy.

Nuclear fusion is less risky than nuclear fission because the fuel rods produced by nuclear fission include dangerous radioactive waste that may be used in weapons and must be maintained carefully for thousands of years.

Powering the Sun and other stars are nuclear fusion processes. Two light nuclei combine to produce one heavy nucleus during a fusion process. The resultant single nucleus's total mass is less than the mass, which causes the process to release energy.

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How many grams of CO are produced when 33.0 g of C reacts? Fe2O3(s)+3C(s)→2Fe(s)+3CO(g)

Answers

Answer

77.0 grams of CO are produced when 33.0 g of C reacts.

Explanation

Given:

Mass of C = 33.0 g

Equation: Fe₂O₃(s) + 3C(s) → 2Fe(s) + 3CO(g)

What to find;

The grams of CO that are produced when 33.0 g of C reacts.

Step-by-step solution:

Step 1: Convert 33.0 g of C to moles.

Using the formula for moles and the molar mass of C = 12.0 g/mol, the moles of C is

[tex]\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Moles\text{ }of\text{ }C=\frac{33.0\text{ }g}{12.0\text{ }g\text{/}mol}=2.75\text{ }mol \end{gathered}[/tex]

Step 2: Determine the moles of CO produced.

Using the mole ratio of C and CO from the balance equation and the moles of C in step 1; the moles of CO produced is calculated as follows:

[tex]\begin{gathered} 3\text{ }mol\text{ }C=3\text{ }mol\text{ }CO \\ \\ 2.75\text{ }mol\text{ }C=x \\ \\ x=\frac{2.75\text{ }mol\text{ }C}{3\text{ }mol\text{ }C}\times3\text{ }mol\text{ }CO \\ \\ x=2.75\text{ }mol\text{ }CO \end{gathered}[/tex]

Step 3: Convert the moles of CO produced to mass in grams.

The moles of CO produced in step above can be converted to mass in grams as shown below

[tex]\begin{gathered} Mass=Moles\times Molar\text{ }mass \\ \\ Molar\text{ }mass\text{ }of\text{ }CO=12.0+16.0=28.0\text{ }g\text{ /}mol \\ \\ Mass\text{ }of\text{ }CO\text{ }produced=2.75\text{ }mol\times28.0\text{ }g\text{/}mol \\ \\ Mass\text{ }of\text{ }CO\text{ }produced=77.0\text{ }g \end{gathered}[/tex]

Hence, 77.0 grams of CO are produced when 33.0 g of C reacts.

A 51.72 g sample of a substance is initially at 23.5 °C. After absorbing 2547 J of heat, the temperature of the substance is 123.4 °C. What is the specific heat ( ) of the substance?

Answers

The heat absorbed or released by a substance is given by the following formula:

[tex]Q=m\cdot Cp\cdot(T2-T1)[/tex]

Where Q is the heat absorbed or released, m is the mass of the substance, Cp is the specific heat, T2 is the final temperature and T1 is the initial one.

We know the values of Q, m, T2 and T1 because they are given by the question statement, and we have to find the value of Cp.

Solve the equation for Cp and use the given values to find its value:

[tex]\begin{gathered} Cp=\frac{Q}{m\cdot(T2-T1)} \\ Cp=\frac{2547J}{51.72g(123.4\degree C-23.5\degree C)} \\ Cp=\frac{0.49J}{g\degree C} \end{gathered}[/tex]

The specific heat of the substance is 0.49J/g°C.

Answer the following questions assuming you have a 1.3M (molarity) solution ofHNO3 (5 points each, 15 points total)A. How many moles of HNO3 would you have in 0.6 liters of the above solution?B. How many grams of HNO3 would be present in 0.6 liters of the above solution?C. If you began with 0.6 liters of solution, and diluted the solution to a concentration of 0.45M, whatwould the final volume of the solution be?

Answers

Answer:

A) 0.78 moles

B) 49.15grams

C) 1.73L

Explanations:

The formula for calculating the molarity of a solution is expressed as;

[tex]\begin{gathered} molarity=\frac{moles}{volume} \\ moles=molarity\times volume \end{gathered}[/tex]

Given the following parameters

molarity of HNO3 = 1.3M

volume of HNO3 = 0.6L

A) moles of HNO3 = 1.3 * 0.6

moles of HNO3 = 0.78moles

B) Mass of HNO3 = moles * molar mass

Mass of HNO3 = 0.78 * 63.01

Mass of HNO3 = 49.15grams

There are 49.15grams of HNO3 present in 0.6L of the solution

C) According to dilution formula

[tex]\begin{gathered} C_1V_1=C_2V_2 \\ V_2=\frac{C_1V_1}{C_2} \\ V_2=\frac{1.3\times0.6}{0.45} \\ V_2=\frac{0.78}{0.45} \\ V_2=1.73L \end{gathered}[/tex]

Therefore the final volume of the solution will be 1.73L

What wavelength (in nm) of light is emitted when an electron transitions from the n
= 8 to the n = 2 state?

Answers

The wavelength in nm of light emitted when an electron transitions from n = 8 to n = 2 state is 38900nm.

It is given that the electron transition took place from n = 8 to n = 2. To find the wavelength, the following formula is to be used:

1/λ = R(1/n²₁ - 1/n²₂)

Here, n₁ = 2 n₂ = 8 and R = 109677. Therefore,

1/λ = 109677(1/2² - 1/8²)

1/λ = 109677(1/4 - 1/64)

1/λ = 109677((16-1)/64)

1/λ = 109677((15)/64)

1/λ = 0.234375 x 109677

1/λ = 25,705.5469

λ = 1/25,705.5469

λ = 3.89 x 10⁻⁵cm

λ = 38900 x 10⁻⁹m

λ = 38900nm

Therefore, the wavelength in nm from n=8 to n=2 transition is 38900nm

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Which type of radiation would you consider ionizing radiation?MicrowavesVisible lightSound wavesGamma rays

Answers

Ionization radiation is a type of energy with such a high value that it is capable of removing electrons from atoms and converting them into ions. This type of energy is extremely dangerous. The types of energy that fall into this category are X-rays and gamma rays.

So, the answer will be Gamma rays

What are the products of the neutralization reaction between HNO3 andCa(OH)2?OA. CaO, NO₂, and H₂OB. Ca3N₂ and H₂OOC. Ca(NO3)2 and H₂OOD. CaNO3 and H30+

Answers

Answer:

Ca(NO3)2 and H₂O. Option C is correct

Explanations:What is a neutralization reaction?

The combination of acid and base to form salt and water at the product is known as a neutralization reaction.

Hence the products of the neutralization reaction between HNO3 and Ca(OH)2 must be salt and water

From the given option, the equivalent product that are salt and water is Ca(NO3)2 and H₂O which gives the required product.

Other Questions
Line / contains the points (-4, -1) and (1, 1) asshown below.432-10x-212-1P-2--3-Line m will be drawn perpendicular to line I andcontaining point P. Identify the coordinates ofanother point on line m.(-1, 4)O (1,3)(-2,-4)(5,3) Jackson started a savings account using the bonus he received from work of $3,500. Theaccount is compounded weekly with an interest rate of 1.75% How much interest did theaccount earned in 18 years?O $1,295.65O $1,102.500 $4,795.65o $1,290 If and are the roots of the equation ax2+bx+c=0,=4ax2+bx+c=0,=4 and a,b,,c are in A. P then += SeleedhewingRead the sentence from Passage 1.The two visitors heard this strange talk, and they began to wonder if their host meant totoss them into the river bed; rich men had been known to do such things.How does the sentence help develop the conflict?O A.It clarifies that even though the father-in-law's speech is confusing, helets the man and his son know they will be thrown in the river bed.OB. It explains why the father-in-law is angry with the man and his son andwhy they feel they must leave his house immediately.OC. It gives the man and his son a reason to leave the father-in-law's housebecause they know his language does not make sense.OD. It shows that although the man and his son do not understand thefather-in-law, they become afraid of him based on his words. Julio emailed a contract to his vendors supply chain manager. Even though Julio sent the contract, the contract is not valid until the supply chain manager receives and executes the contract. What key principle about contracts does this scenario describe? A. Legal capacity B. Exchange of value C. Legal purpose D. Offer and acceptance Solve. (7x14)(x5) Match each scenario with the kind of culture it illustrates.Frank pays full attention to each taskand works hard to finish it on time.Rehman doesnt openly disagree withanyone. He prefers to talk around thesubject and drop hints in a gentle way.Lucy likes to do tasks on her ownrather than working with a team.Lee interrupts a speaker forclarification if he cant follow what thespeaker is saying.Marcel stands up when his supervisorapproaches him. He addresses her asmaam.boxes lable (low-context) and (high-context) Using the area formula A=LW (where A is the area L is the length and W is the width ) which of the following formulas would you use to solve for width ? Becky borrowed $580.00 from the bank. The loan had a 13.5% simpleannual interest rate, and she paid off the bill over 18 months. What wasthe total amount, including interest, Becky paid for the loan? A group of 23 students want to see the show at the planetarium. Tickets cost $11 for each student who is a member of the planetariums frequent visitor program and $13 for each student who is not a member. The total cost of the students tickets is $261. The oil tank in your car is leaking at a rate of 1.2 oz per mile driven you drove 15 miles how many cups of oil did your car leak a bank loaned out $23,000, part of it at the rate of 11% annual interest, and the rest at 12% annual interest. the total interest earned for both loans was $2,595.00. how much was loaned at each rate solve the system by graphing; y= -5/3x + 3 y= 1/3x - 3 Which of the following does not have high potential energy? atpnitrogenglucoseconcentration gradientelectrical/ion gradient Suppose that a plant had chloroplasts that could carry out the Calvin cycle, but these chloroplasts could not carry out the light-dependent reactions. Explain why these chloroplasts could not carry out photosynthesis to produce sugars. A student council president wants to learn about the preferred theme for the upcoming spring dance. Select all the samples that are representative of the population. If a student did an experiment were they mixed 25 mL of HCl (0.5M) and 7.4g of sodium bicarbonate together How many moles of carbon dioxide would be generated at STP? Show your balanced equation aswell. rochelle has a resting bp of 118/68. during exercise, her bp is 152/68 with a hr of 142 bpm. calculate rochelle's pulse pressure during exercise, and include units. your answer should include numbers and unit abbreviation only (eg. 32mpg). the average number of miles driven on a full tank of gas for a hyundai veracruz before its low fuel light comes on is 320. assume this mileage follows the normal distribution with a standard deviation of 30 miles. what is the probability that, before the low fuel light comes on, the car will travel . Calculate: (81)3/2