We first need to calculate the slope of the line.
m=(0-0)/(5-0)=0 since the slope is equal to zero we have that the line is horizontal.Then the equation is
[tex](y-0)=0(x-0)\Rightarrow y=0[/tex]the equation is y=0
144 grapefruits in 4 boxes, How many grapefruits in 100 boxes?
Problem
144 grapefruits in 4 boxes, How many grapefruits in 100 boxes?
Solution
for this case we can do the following proportional rule:
4/144 = x/100
And solving for x we got:
x= 100 (4/144)= 2.77
So between 2 and 3 grape fruits are expected
2. The Venn diagram shows the sets U, X and Y.UXY.34 246..9.512:31List the elements of the following sets:(a) X(b) Y(c) U(d) XUY(e) XnY(g) X\Y(h) Y\X(f) X'(1) (XY)2:31
Given the Venn diagram in the question, we can proceed to answer the questions as follow
[tex]\begin{gathered} X=\text{members of the subset X} \\ This\text{ gives: 1,2,3,4, and 5} \end{gathered}[/tex][tex]\begin{gathered} QuestionA\text{ } \\ X=1,2,3,4,and\text{ 5} \\ \end{gathered}[/tex]Question B
Y= members of subset Y
Y =2,4,6, and 8
Question C
U means that we should list all elements in the universal set
U = ALL members of the set
U = 1,2,3,4,5,6,7,8, and 9
Question D
This is the union of both sets X and Y. This means we will list all the members that are found in the 2 subsets
[tex]\text{XUY}=1,2,3,4,5,6,\text{ and 8}[/tex]Question E
[tex]\begin{gathered} \text{XnY means we are to find the elements that are common to both X and Y} \\ \text{XnY}=2\text{ and 4} \end{gathered}[/tex]Question F
X' means that we should find all members of the set except that of X
[tex]X^{\prime}=6,7,8,\text{ and 9}[/tex]Question G
X\Y means that we should list the elements of X that are not found in Y
X\Y= 1,3, and 5
Question H
Y\X means that we should list the elements of Y that are not found in X
Y\X= 6, and 7
Question I
To solve (XnY)' we will follow the steps below
Step 1: Find (XnY)
[tex]\text{XnY}=2\text{ and 4}[/tex]Step 2: Find (XnY)'
[tex]We\text{ will list all elements aside (XnY)}[/tex][tex](XnY)^{^{\prime}}\Rightarrow1,3,5,6,7,8,\text{and 9}[/tex]
In 1906 Kennelly developed a simple formula for predicting an upper limit on the fastest time that humans could ever run distances from 100 yards to 10 miles. His formula is given by t= 0.0588s^(1.125) where s is the distance in meters and t is the time to run thatdistance in seconds.a. Find Kennelly's estimate for the fastest a human could possibly run 1609 meters.t= seconds (Round to the nearest thousandth as needed.)
For this problem, we are given a formula that predicts the fastest a human can run a certain distance. We need to determine the time a human can run 1609 meters.
The formula is:
[tex]t=0.0588s^{1.125}[/tex]We need to replace s with 1609 and solve for t.
[tex]\begin{gathered} t=0.0588(1609)^{1.125}\\ \\ t=0.0588\cdot4049.26\\ \\ t=238.096 \end{gathered}[/tex]The fastest a human can run 1609 meters is 238.096 seconds.
What is the area of this trapezoid? Enter your answer in the box. ft2
Given the figure, we can deduce the following information:
Upper base = 15 ft
Lower base = 37 ft
Height = 18 ft
To determine the area of a trapezoid, we use the formula:
[tex]A=\frac{a+b}{2}h[/tex]where:
A=Area
a=upper base
b=lower base
h=height
We plug in what we know:
[tex]\begin{gathered} A=\frac{a+b}{2}h \\ =\frac{15+37}{2}(18) \\ \text{Simplify} \\ A=\frac{52}{2}(18) \\ =\frac{936}{2} \\ A=468ft^2 \end{gathered}[/tex]Therefore, the area of the trapezoid is 468 ft^2.
45. (09.01) Let A = {1, 2, 3, 4, 5} and B = {2,4}. What is A n B? O {2,4) O {1, 2, 3) O {1, 2, 3, 4 } O {1, 2, 3, 4,5)
Answer:
{2,4}
Explanation:
Given sets A and B defined below:
[tex]\begin{gathered} A=\mleft\{1,2,3,4,5\mright\} \\ B=\mleft\{2,4\mright\} \end{gathered}[/tex]The set A Π B is the set of elements common to sets A and B.
[tex]A\cap B=\{2,4\}[/tex]8x - 3x + 4x = -36x = ?
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
8x - 3x + 4x = -36
x = ?
Step 02:
We must apply the algebraic rules to find the solution.
8x - 3x + 4x = -36
12x - 3x = - 36
9x = - 36
x = - 36 / 9
x = - 4
The answer is:
x = - 4
HighByte Entertainment sells four types of products: video games, DVDs, CDs, and radios. The numbers sold for 2020 and 2021 are shown in the double bargraph below. Use this graph to answer the questions.
Solution
Use this graph to answer the questions below:
The numbers sold for 2020 and 2021 are shown in the double bar above
1. The number of radio sold in 2021 = 440
2. Which products sold more in 2021 than in 2020 :
The only products that sold more in 2021 than in 2020 is video games
3. Which products sold the least over the two years
The products that sold the least = DVDS
Find g(x), where g(x) is the translation 4 units left of f(x)=|x|.
The equation for the translated function is:
g(x) = |x + 4|
How to find g(x)?
For a function f(x), a horizontal translation of N units is written as:
g(x) = f(x + N)
if N > 0, the translation is to the left.if N < 0, the translation is to the right.Here we have:
f(x) = |x|
And the translation is of 4 units to the left, so the translated function is:
g(x) = f(x + 4) = |x + 4|
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The graph below shows the length of Jutta's hair over 6 months period. Each month point represents a measurement at the beginning of a month. How many inches did her hair grow between the beginning of February and the beginning of July?
Given:
Length of hair at the beginning of february is 4.1''
Length of hair at the beginning of July is 7.7''
[tex]\begin{gathered} \text{Hair grown between beginning of February an beginning of July=7.7''-4.1''} \\ =3.6^{\doubleprime} \end{gathered}[/tex]The points −−5, 11 and r, 9 lie on a line with slope 2. Find the missing coordinate r.
Solution
[tex]\begin{gathered} Let\text{ }(x_1,y_1),\text{ }(x_2,y_2) \\ Let\text{ }m=slope \\ m=\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex][tex]\begin{gathered} If(-5,-11)=\text{ }(x_1,y_1),then\text{ }x_1=-5,\text{ }y_1=-11 \\ (r,9)=\text{ }(x_2,y_2),then\text{ }x_2=r,\text{ }y_1=9 \end{gathered}[/tex]Using the Slope formula written above;
[tex]\begin{gathered} 2=\frac{9-(-11)}{r-(-5)} \\ 2=\frac{20}{r+5} \\ Cross\text{ }multiply \\ 2(r+5)=20 \\ Expansion\text{ }of\text{ }bracket \\ 2r+10=20 \\ 2r=20-10 \\ 2r=10 \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }2 \\ \frac{2r}{2}=\frac{10}{5} \\ r=5 \end{gathered}[/tex]Therefore, the missing co-ordinate r is 5.
The vertex of a quadratic function is (2, -1) and its y-intercept is 7. Find the function,
Given:-
[tex]\text{vertex}=(2,-1),y-intercept=7[/tex]To find:-
The function.
So the formula is,
[tex]y=a\mleft(x-h\mright)^{2}+k[/tex]So substituting we get,
[tex]y=7(x-2)^2-1[/tex]So the value. we get,
[tex]\begin{gathered} y=7(x-2)^2-1 \\ y=7(x^2-4x+4)-1 \end{gathered}[/tex]Since the value of x is,
[tex]\begin{gathered} y=7x^2-28x+28-1 \\ y=7x^2-28x+27 \end{gathered}[/tex]So the value,
[tex]y=7x^2-28x+27[/tex]Which of the following are roots of the polynomial function?Check all that apply.F(x) = x3 + 3x2 - 9x+5A. 1 - 13B. 3 - 2C. 1D. 1. 13E. 3 + 2F. -5
we have
F(x) = x3 + 3x2 - 9x+5
solve by graphing
using a graphing tool
the figure in the attached image
REmember that the zeros
please wait a minute
the roots are -5 and 1
therefore
answer option C and F
please help me ASAP!!!
substitute x = 5 in the above function
[tex]f(5)=\sqrt[]{2(5)^2-3(5)+1}[/tex][tex]=\sqrt[]{2(25)-15+1}[/tex][tex]=\sqrt[]{50-15+1}[/tex][tex]=\sqrt[]{36}=\text{ 6}[/tex]f(5) = 6
What 3D shape will be formed when the following are rotated around the axis
a)
A washer will be formed
b)
A cone will be formed
C)
A sphere will be formed
discriminant for 2n^2+8n+1=-7
The given equation is
[tex]\begin{gathered} 2n^2+8n+1=-7 \\ 2n^2+8n+1+7=0 \\ 2n^2+8n+8=0 \end{gathered}[/tex]Where a = 2, b = 8, and c = 8.
The discriminant formula is
[tex]D=b^2-4ac[/tex]Let's replace the values
[tex]D=(8)^2-4(2)(8)=64-64=0[/tex]The equation has one real solution.What is the value of 7C4?A). 35B). 840C). 2,520D). 5,040
Answer:
A) 35
Explanation:
The combination nCx can be calculated as:
[tex]\text{nCx}=\frac{n!}{x!(n-x)!}[/tex]Where n! = n(n-1)(n-2)...(2)(1)
So, to find 7C4, we need to replace n by 7 and x by 4 to get:
[tex]7C4=\frac{7!}{4!(7-4)!}=\frac{7!}{4!(3)!}[/tex]Therefore, 7C4 is equal to:
[tex]7C4=\frac{7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1}{(4\cdot3\cdot2\cdot1)(3\cdot2\cdot1)}=\frac{5040}{24(6)}=\frac{5040}{144}=35[/tex]So, the answer is:
A) 35
The maintenance department at the main campus of a large state university receives daily requests to replace fluorescent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 42 and a standard deviation of 10. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 42 and 62.
we are given
mean=42
Std=10
if the mean=42 + std =10 42+10=52
if the mean=42 - std=10 42-10=32
Rule -- 68-95-99.7
68% of the measures are within 1 standard deviation of the mean.
42+10=52
95% are within 2.
42+20=62
99.7% are within 3.
42+30=72
The normal distribution is symmetric, which means that 50% of the measures are above the mean and 50% are below.
we are ask for the porcentage of request between 42-62 (between the mean and 2+std)
62 is two standard deviations above the mean.
Of the 50% of the measures below the mean, 95% are between 42 and 62, so
0.95(50)=47.5
The approximate percentage of light bulb replacement requests numbering between 42 and 62 is of 47.5%
There is one male snake, and the rest are female. She needs one vitamin pill for every female snake. How many vitamin pills does she need if the number of snakes is: a. 10b. 6C. X
We are told that there is one male snake, and the rest are female.
She needs one vitamin pill for every female snake.
1. If there are 10 snakes, this means that if one is male, the number of female snakes are:
[tex]10-1=9\text{ females}[/tex]Sine one vitamin pill is needed for each female snake, she would need 9 vitamin pills.
2. If there are 6 snakes, this means that if one is male, the number of female snakes are:
[tex]6-1=5\text{ females}[/tex]Sine one vitamin pill is needed for each female snake, she would need 5 vitamin pills.
3. If there are X snakes, this means that if one is male, the number of female snakes are:
[tex]X-1=(X-1)\text{ females}[/tex]Sine one vitamin pill is needed for each female snake, she would need (X-1) vitamin pills.
Identify the side lengths that form a right triangle.a. 12, 13, 16b. 15, 20, 21c. 9, 40, 42d. 10, 24, 26Identify the side lengths that form a right triangle.a. 3, 4, 8b. 30, 40, 45c. 5, 12, 13d. 6, 12, 133. do the side lengths of 8, 10, and 13 form a right triangle? 4. Determine if ▼ABC is a right triangle if AB=36, AC=48 and BC=60
Answer:
d. 10, 24, 26
Explanation:
To identify the side lengths that form a right triangle, we check if it satisfies the Pythagorean theorem.
By the theorem:
[tex]\begin{gathered} a^2=b^2+c^2 \\ a\text{ is the hypotenuse, the longest side.} \end{gathered}[/tex]a. 12, 13, 16
[tex]\begin{gathered} 16^2=12^2+13^2 \\ 256=144+169 \\ 256\neq313 \end{gathered}[/tex]These side lengths do not form a right triangle.
b. 15, 20, 21
[tex]\begin{gathered} 21^2=15^2+20^2 \\ 441=225+400 \\ 441\neq625 \end{gathered}[/tex]These side lengths do not form a right triangle.
c. 9,40,42
[tex]\begin{gathered} 42^2=9^2+40^2 \\ 1764=81+1600 \\ 1764\neq1681 \end{gathered}[/tex]These side lengths do not form a right triangle.
d. 10, 24, 26
[tex]\begin{gathered} 26^2=10^2+24^2 \\ 676=100+576 \\ 676=676 \end{gathered}[/tex]These side lengths form a right triangle since both sides of the equation are the same.
Do you know anything about dilation!?
5. Graph the system of inequalities. Then, identify a coordinate point in the solution set.2x -y > -3 4x + y < 5
We have the next inequalities
[tex]\begin{gathered} 2x-y>-3 \\ 4x+y<5 \end{gathered}[/tex]as we can see if we graph these inequalities we will obtain the next graph
where the red area is the first inequality and the blue area is the second inequality
and the area in purple is the solution set of the two inequalities
one coordinate point in the solution set could be (0,0)
Use the graph of 'f' in the figure below to answer the following questions. 1. State the domain and range of 'f'.2. Find the average rate of change of 'f' over the interval [0,6].
The domain of the given function corresponds to:
[tex]\lbrack-4,-2)\cup(-2,6)[/tex]And the range of the function is:
[tex](-2,6)[/tex]The average rate of change of f over the interval [0,6] is:
[tex]\frac{5.5-(-2)}{0-6}=\frac{7.5}{-6}=-\frac{5}{4}=-1.25[/tex]
Suppose the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 17 million dollars. If incomes for the industry are distributed normally, what is the probability that a randomly selected firm will earn less than 112 million dollars? Round your answer to four decimal places.
0.8413 is the probability that a random selected firm will earn less than 112 million dollar
What is probability?Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1.
Let X be a random variable represents the income of the firm in the industry
Hence
X~ N (mean =u= 95 , standard deviation= d = 17 )
We must determine the likelihood that a randomly chosen company will make fewer than 112 million dollars in earnings ie.
P(X<112) = P(X-u/d < 112-95/17)
Z=X-u/d = 112 - 95/17 = 1
P(X<112) = P(Z-1)=0.8413
Using the standard normal probability table.
P(X<112) = 0.8413
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Using the order of operations, which operation should you perform last to evaluate the expression below?(7*4)+(10 ÷ 2)*(14.7 - 9)A.multiplicationB.divisionC.additionD.subtractionHELP! A.P.S
Explanation
Given (7*4)+(10 ÷ 2)*(14.7 - 9), we can see that only two operations occur outside of the parenthesis which is multiplication and addition.
In the order of evaluation of expressions, the parenthesis comes first before multiplication and then addition. Therefore,
Answer: Option C (Addition)
can you help me with key attributes of quadratic function
The shape of a quadratic function is a parabola.
The domain of a quadratic function is the set of all real numbers.
The range of the quadratic function is the set of all y values at or above the vertex for a parabola open upwards.
In the given parabola, y=0 is the y coordinate of the vertex of the parabola.
Therefore, the range is R=[0, ∞).
The domain is (-∞, ∞).
Sara is 33 years younger than Rolando. The sum of their ages is 105. Select the system of equations if Sara’s age is represented by S and Rolando’s age is represented by R.
Given:
Sara's age is represented by S and Ronaldo's age is represented by R.
Since,
Sara is 33 years younger than Ronaldo, then;
S= R - 33
Now, the sum of ages of Sara and Ronaldo is 105 then
[tex]R+S=105[/tex]Hence, from above,
[tex]\begin{gathered} S+R=105 \\ S=R-33 \end{gathered}[/tex]Therefore, second option is correct.
Scientists are conducting an experiment with a gas in a sealed container. The mass of the gas is measured, and the scientists realize that the gas is leaking over time in a linear way. Nine minutes since the experiment started, the gas had a mass of 68.4 grams. Thirteen minutes since the experiment started, the gas had a mass of 61.2 grams. At what rate is the gas leaking? Use g for grams and min for minutes.
the rate is:
[tex]m=\frac{61.2-68.4}{13-9}=-\frac{7.2}{4}=-1.8\frac{g}{\min }[/tex]43/1/2 divided by 1/1/4
When 43/1/2 is divided by 1/1/4 , the value will be 34 4/5.
What is a fraction?A fraction simply means a numbers that's represented as a/b where a = numerator and b = denominator
In this case, the division of the fraction will be:
43 1/2 ÷ 1 1/4
= 87/2 ÷ 5/4
= 87/2 × 4/5
= 174 / 5
= 34 4/5
This shows the. concept of fractions.
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Which of the following is an equation of a line that is parallel to y = 4x - 5 and has a y-intercept of (0, 7)?
Answer:
Step-by-step explanation:
To start your equation is in the format y=mx+b.
For a line to be parallel it must have the same slope (m) so we know 4 must remain the same. x & y will not change since they represent the variables. y=4x (so far) then the point (0,7) as stated is the y intercept. 0 is the x value and 7 is the y we need to add 7 to our equation.
final equation y=4x+7
Which sequence of transformations will map AABC onto AA' B'C'?A- reflection and translationB- rotation and reflectionC- translation and dilation D- dilation and rotation
For the given problem, we can observe that the image is bigger than the original diagram.
We can also observe that the image is rotated counterclockwise.
Hence, the sequence of transformation that maps triangle ABC onto triangle A'B'C' is a dilation and a rotation.
Answer: Option D
