hello I don't know if you can help me with this but I no am doing something wrong. because at the bottom its not spelling right
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8. The difference of three and a number means x+3 or x-3 because in both equations you have three units plus or minus the number X.
10. '"4 times the sum of a number and three" means
[tex]4\cdot(x+3)=4x+12[/tex]Letter D
Related Questions
Let w be defined as 2 more than the number of digits in the integer w. For example, 15* = 4 (2 digits in 15 + 2). If whas 7000 digits, then what is the value of (w)*?
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The number of digits in 7000 is 4
The number of digits in w=7000
[tex](w)^{\cdot}=\text{ the number of digits in w+2}[/tex][tex](w)^{\cdot}=\text{7000+2}[/tex][tex](w)^{\cdot}=7002[/tex]Hence the required value is 7002.
do you know the north Zone at the football stadium has 95 Rose there are 48 seats in a row how many people will the North end zone seat
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The North zone at the football stadium has 95 rows.
There are 48 seats in a row.
How many people will the North end zone seat?
Since there are 95 rows and each row has 48 seats, multiply them to get the total number of seats.
[tex]\begin{gathered} total\: seats=rows\times seats \\ total\: seats=95\times48 \\ total\: seats=4560 \end{gathered}[/tex]Therefore, there are 4560 people sitting in the North zone.
To find the area of a shape region:Find the area of the entire region:Fimd the area of the unshaded region(s)Subtract the area of the unshape region from the area of the entire region
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IN order to find the area of the shaded region, proceed as follow:
calculate the area of the right triangle:
A = b·h/2
A = (21 yd)(34 yd)/2 = 357 yd²
next, calculate the area of the circle:
A' = π r²
A' = (3.1415)(7 yd)² = 153.93 yd²
next, subtract the area of the circle to the area of the rectangle:
AT = A - A' = 357 yd² - 153.93 yd²
AT = 203.07 yd²
Hence, the area of the shaded region is 203.07 yd²
Find the circumference of a circle with a diameter of centimeters. Round your answer to the nearest centimeter.
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Circumference = 2* pi * r
r = radius
r = diameter/2
r = 50/2
r = 25 cm
Circumference = 2*3.14 * 25
Circumference = 157 cm
Result = 157 cm
The second choice
Peri earned $55 for 5 dog walks. If Peri earned $22, how many times did she walk her neighbor's dog?
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Answer:
2
Step-by-step explanation:
55÷5=11
22÷11=2
The students of a school were asked to participate in a competition for making and decorating penholders in the shape of a cylinder with a base, using cardboard.Each penholder was to be radius of 3cm and height 10.5 cm. The school was to supply the competitors with cardboard. If there were 35 competitors, how much cardboard was required to be brought for the competition. Assume: pi = 22/7
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Recall the surface area for the following figures.
[tex]\begin{gathered} \text{Cylinder}=2\pi rh+2\pi r^2 \\ \\ \text{The term }2\pi r^2\text{ includes a cover both the top and bottom of the cylinder} \\ \text{Since we will be using only the bottom modify the formula such that it only} \\ \text{includes the bottom part} \\ \\ \text{Pen Holder Surface Area}=2\pi rh+\pi r^2 \end{gathered}[/tex]Given that
height = h = 10.5 cm
radius = r = 3 cm
π = 22/7
Substitute the following given and we have the surface area for the pen holder
[tex]\begin{gathered} \text{Pen Holder Surface Area}=2\pi rh+\pi r^2 \\ \text{Pen Holder Surface Area}=2(\frac{22}{7})(3\operatorname{cm})(10.5\operatorname{cm})+(\frac{22}{7})(3\operatorname{cm})^2 \\ \text{Pen Holder Surface Area}=198\operatorname{cm}+(\frac{22}{7})(9\operatorname{cm}) \\ \text{Pen Holder Surface Area}=198\operatorname{cm}+\frac{198}{7}\operatorname{cm} \\ \text{Pen Holder Surface Area}=\frac{1584}{7}\operatorname{cm}^2 \end{gathered}[/tex]Now that we have the surface area, multiply it by 35 since there are 35 competitors in the competition
[tex]undefined[/tex]Triangle CHE Is drawn below. What is the measure of y in the diagram?* I 2 meters 3 meters O 12 meters 6 meters None of the above
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The given triangles are similar to each other, this means that we can get the length of the sides of the larger triangle by multiplying the corresponding lengths of the smaller one by a scale factor.
We can get the scale factor by dividing the length of one of the sides of the larger triangle by the length of the corresponding side in the smaller triangle, like this:
By taking the left sides
[tex]s=\frac{8}{4}[/tex]Then, in order to get the length of the base of the larger triangle (6), we just have to multiply the length of the base of the smaller triangle (y) by the scale factor (2), like this:
6 = 2×y
From this equation, we can solve for y to get:
2y = 6
2y/2 = 6/2
y = 3
Then, y equals 3 meters
Sophia spent $40 on supplies to make 20 bracelets. She plans to sell them at a craft show for $5 each. Let y represent the amount of her profit. Is it discrete or continuous? And what are the domain and range?
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we have that
y ------> the amount of her profit
x -----ghe number of bracelets
REmember that
Profit is equal to sell minus cost
so
y=5x-40
the domain is the interval (0,1,2,3,4,5) ------> is a discrete
the range is equal to
For x=
The endpoints are a side of a rectangle ABCD in the coordinate plane at A(3,4), B(6,1) Find the equation of the line the given segment The line segment is line Segment AB
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The endpoints are a side of a rectangle ABCD in the coordinate plane at A(3,4), B(6,1) Find the equation of the line the given segment
The line segment is line Segment AB
step 1
Find the slope of segment AB
m=(1-4)/(6-3)
m=-3/3
m=-1
step 2
Find the equation of the line in slope intercept form
y=mx+b
we have
m=-1
point (3,4)
substitute
4=(-1)*(3)+b
4=-3+b
b=4+3
b=7
therefore
the equation of segment AB is
y=-x+7A ladder resting on a vertical wall makes an angle whose tangent is 2.5 with the ground of the distance between the foot of the ladder and the wall is 60cm what is the length on the ladder
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If AC denote the ladder and B be foot of the wall the length of the ladder AC be x metres then the length of the ladder exists 5 m.
What is meant by trigonometric identities?Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions. There are numerous distinctive trigonometric identities that relate a triangle's side length and angle.
Let AC denote the ladder and B be foot of the wall. Let the length of the ladder AC be x metres.
Given that ∠ CAB = 60° and AB = 2.5 m In the right Δ CAB,
cos 60° = AB / AC
simplifying the above equation, we get
⇒ AC = AB / (cos 60°)
x =2 × 2.5 = 5 m
Therefore, the length of the ladder exists 5 m.
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What is the probability that a data value in a normal distribution is between a Z score of -1.52 and Z score of -.34
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We are asked to find the probability that a data value in a normal distribution is between a Z score of -1.52 and -0.34
[tex]P(-1.52First, we need to find out the probability corresponding to the given two Z-scoresFrom the Z-table, the probability corresponding to the Z-score -1.52 is 0.0643
From the Z-table, the probability corresponding to the Z-score -0.34 is 0.3669
So, the probability is
[tex]\begin{gathered} P(-1.52Therefore, the probability that a data value in a normal distribution is between a Z score of -1.52 and a Z score of -0.34 is 30.3%Option A is the correct answer.
Question 5 of 10 Solve the proportion below. 23 A 6 B. 8 C. 9 D.
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solve for x
[tex]\begin{gathered} 12.6\times\frac{x}{12.6}=\frac{5}{7}\times12.6 \\ x=\frac{63}{7}=9 \end{gathered}[/tex]answer: C. 9
i need help with this. for 2nd option, select only one sub-option
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A matrix being in row echelon form means that Gaussian elimination has operated on the rows.
A matrix is in reduced row echelon form (also called row canonical form) if it satisfies the following conditions:
- It is in row echelon form.
-The leading entry in each nonzero row is a 1 (called a leading 1).
-Each column containing a leading 1 has zeros in all its other entries.
The matrix presented on the problem satisfies all conditions, therefore, the matrix is indeed in reduced row-echelon form.
Is 1/4 n - 16 equivalent to 4(n - 4)?
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Answer:
[tex]\frac{1}{4}n-16[/tex]is not equivalent to:
[tex]4(n-4)[/tex]Explanation:
The expression
[tex]\frac{1}{4}n-16[/tex]can be written as:
[tex]\frac{1}{4}(n-64)[/tex]It is not equivalent to:
[tex]4(n-4\text{)}=4n-16[/tex]Quadrilateral PQRS is plotted in the coordinate plane. The quadrilateral is dilated by a scale factor of 3/4. What are the new ordered pairs for P'Q'R'S'?
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Explanation:
The first thing is to state the coordinates of Quadrilateral PQRS
P (5, 5), Q (3, 5), R (3, 1), S (5, 1)
Then we find the distance between two points using the distance formula
[tex]dis\tan ce\text{ = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex][tex]\begin{gathered} P(5,5),Q(3,5)\text{ = (x1, y1) and (x2, y2)} \\ \text{distance PQ = }\sqrt[]{(5-5)^2+(3-5)^2}\text{ = }\sqrt[]{0+(-2)^2}\text{ =}\sqrt[]{4} \\ \text{distance PQ = }2 \end{gathered}[/tex][tex]\begin{gathered} Q(3,5),R(3,1)\text{= (x1, y1) and (x2, y2)} \\ \text{distance QR = }\sqrt[]{(1-5)^2+(3-3)^2}\text{ = }\sqrt[]{(-4)^2+0}\text{ = }\sqrt[]{16} \\ \text{distance QR = 4} \end{gathered}[/tex]It is a quadrilateral, meaning the two lengths are equal. Like wise the two widths are equal.
length PQ = length SR = 2
Length QR = length PS = 4
Scale factor = 3/4
Scale factor = corresponding side of new image/ corresponding side of original image
PQRS = original image, P'Q'R'S' = new image
3/4 = P'Q'/PQ
3/4 = P'Q'/2
P'Q' = 2(3/4) = 6/4 = 3/2
Since P'Q' = S'R'
S'R' = 3/2
3/4 = Q'R'/QR
3/4 = Q'R'/4
Q'R' = 3/4 (4) = 12/4 = 3
Since Q'R' = P'S
P (5, 5), Q (3, 5), R (3, 1), S (5, 1)
PQRS to P'Q'R'S' = 3/4(
P' = 3/4 (5, 5) = (15/4, 15/4)
Q' = 3/4 (3, 5) = (9/4, 15/4)
R' = 3/4 (3, 1) = (9/4, 3/4)
S' = 3/4 (5, 1)
Jo borrowed $3800 for 8 months from a bank at 5.5% a. how much interest did jo pay the bank for the us of it's money?b. how much did he pay total?
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Let's begin by listing out the given information:
Loan (p) = $3,800
Time (t) = 8 months = 8/12 year
Interest rate (r) = 5.5%
a)
We calculate it thus:
[tex]\begin{gathered} I=\frac{p\times r\times t}{100} \\ I=\frac{3800\times5.5\times\frac{8}{12}}{100}=139.33 \\ I=\text{\$}139.33 \end{gathered}[/tex]b)
The amount paid in total is:
[tex]\begin{gathered} A=p+I \\ A=3800+139.33=3939.33 \\ A=\text{\$}3939.33 \end{gathered}[/tex]Solve this system of equations by elimination. Enter your answer as an ordered pair (x,y). Do not use spaces in your answer. If your answer is no solution, type "no solution". If your answer is infinitely many solutions, type "infinitely many solutions".
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5x + 2y = -12 (a)
3y + 5x =-8 (b)
First, write (b) in the ax+by=c form:
5x + 3y = -8 (b)
Now, subtract (b) to (a) to eliminate x
5x + 2y = -12
-
5x + 3y = -8
__________
-y = -4
solve for y:
Multiply both sides by -1
y=4
Replace y=4 on (a) and solve for x:
5x + 2 (4) = -12
5x + 8 = -12
5x = -12-8
5x = -20
x = -20/5
x = -4
Solution: (-4,4)
Alec wants to purchase a new phone that costs $219.00. His current average net pay is $212.34 each week. What percent of his weekdy net pay does Alec need to save each week, for the next seven weeks, to reach
his goal? Round to the nearest hundredth (1 point)
9.69%
14.73%
O 21.76%
31.28%
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Answer:
14.73%
Step-by-step explanation:
firstly let's divide the phone price into 7 equal parts. by this equation 219.00/7=31.28
So Alec needs to save $31.28 but we want the percentage.
by equation x%*212.34=31.28
x=(31.28*100)/212.34=3128/212.34=14.73
so Alec needs to save 14.73% of 212.34 each week.
12. Jimmy is paid $14.50 per hour for a regular forty-hour work week and 5 point time and a half for any hour worked over 40. This pas week, Jimmy earned $754.00 in total pay. How many hours of overtime did Jimmy work?
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Jimmy is paid $14.50 per hour for a regular forty-hour work week and 5 point time and a half for any hour worked over 40. This pas week, Jimmy earned $754.00 in total pay. How many hours of overtime did Jimmy work?
Let
x -----> the total hours worked
we have that
$14.50 --------> 40 hours
5.5($14.50) -------> > 40 hours
so
754=14.50*40+5.5(14.50)x
solve for x
754=580+79.75x
79.75x=754-580
79.75x=174
x=2.2 hours
the figure shows a net for a three-dimensional figure. the net includes three squares.a) what is the three dimension figure. b) what is the surface area of the digure.
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(b).
The area of the figure is equal to the sum of the area of the three squares and 2 triangles.
The area of the square is
[tex]2\operatorname{cm}\times2\operatorname{cm}=4\operatorname{cm}^2[/tex]The area of the triangle is
[tex]\frac{1}{2}\times1.7\operatorname{cm}\times2\operatorname{cm}=1.7\operatorname{cm}^2[/tex]Hence, two triangles and three squares have a total area of
[tex](4\operatorname{cm}\times3)+(2\times1.7cm)=15.4\operatorname{cm}^2[/tex]I need help with this statistics question please!
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The margin of error of a z-confidence interval is given by: [tex]$M=z \frac{\sigma}{\sqrt{n}}$$[/tex]
The margin of error of a z-confidence interval is 142.945936.
How to estimate the margin of error?The margin of error of a z-confidence interval exists given by:
[tex]$M=z \frac{\sigma}{\sqrt{n}}$$[/tex]
Where, z is the critical value.
[tex]$\sigma$[/tex] be the population standard deviation.
n is the sample size.
The first step is finding the critical value, which exists z with a p-value of [tex]$\frac{1+\alpha}{2}$[/tex] in which [tex]$\alpha$[/tex] is the confidence level.
In this problem, [tex]$\alpha[/tex] = 0.95, therefore, z with a p-value of 1 + 0.95 / 2 = 0.975, which means that it is z = 1.96.
The population standard deviation exists of 12.2 meters, thus [tex]$\sigma[/tex] = 12.2.
We want a width of 5 , thus a margin of error of M = 2. Therefore, we have to simplify the equation for the margin of error for n.
Let the equation be [tex]$M=z \frac{\sigma}{\sqrt{n}}$$[/tex]
substitute the values in the above equation, we get
[tex]$2=1.96 \frac{12.2}{\sqrt{n}}$[/tex]
[tex]$2 \sqrt{n}=1.96(12.2)$[/tex]
simplifying the above equation, we get
[tex]$\sqrt{n}=\frac{1.96(12.2)}{2}$[/tex]
[tex]$(\sqrt{n})^2=\left(\frac{1.96(12.2)}{2}\right)^2$[/tex]
n = 142.945936
Therefore, the value of n = 142.945936.
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which is an incorrect rounding for 53.864a) 50b) 54c) 53.9d) 53.87
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The incorrect rounding is 53.87
Explanations:The given number is 53.864
If the number is approximated to 2 decimal places
53.864 = 53.86
If the number is approximated to 1 decimal place
53.864 = 53.9
If the number is approximated to the nearest unit
53.864 = 54
If the number is approximated to the nearest tens:
53.864 = 50
Note: 53.864 cannot be approximated to 53.87 because the third decimal place (4) is not up to 5
what's the difference between two whole number 1/2 percent of 36 and 30% of 10
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Here, we proceed step by step, to obtain our answer,
[tex]\frac{1}{2}[/tex] % of 36 can be written as ,
0.5 % of 36 , which means,
100 % refers to 36, then
0.5 % refers to what, thus, by cross multiplication we get,
0.5 % of 36 = [tex]\frac{0.5 X 36}{100}[/tex] = 0.18 ___(1), which can be expressed in whole numbers as 0.
Now, 30 % of 10 means,
100 % refers to 10, then
30 % refers to what, thus, by cross multiplication we get,
30 % of 10 = [tex]\frac{30 X 10}{100}[/tex] = 3 __(2)
From equations (1) and (2),
the whole numbers that we obtain are 0 and 3, respectively,
Thus the difference between these two whole numbers is,
= 3 - 0 = 3.
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Solve the inequality and write the solution using:
the inequality
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2) Add or subtract the following polynomials: (5pts each) 1) (98-7x' +5x-3)+(2x* +4x'-6x-8) = ii) (8x* +6x - 4x2 -2)-(3x* – 5x – 7x+9)=
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When we are adding/subtracting polynomials, we add or subtract like terms.
For example,
x^2 added with x^2 terms
x^4 added with x^4 terms
numbers (constants) added with numbers etc.
2 i)[tex](9x^5-7x^2+5x-3)+(2x^4+4x^3-6x-8)[/tex]Since we are "adding" the 2nd parenthesis polynomial, we can take out the parenthesis and put them in order and them simply add/subtract(!) The steps are shown below:
[tex]\begin{gathered} (9x^5-7x^2+5x-3)+(2x^4+4x^3-6x-8) \\ =9x^5-7x^2+5x-3+2x^4+4x^3-6x-8 \\ =9x^5+2x^4+4x^3-7x^2+5x-6x-3-8 \\ =9x^5+2x^4+4x^3-7x^2-x-11 \end{gathered}[/tex]Note: there were like terms with "x's" and "constants". We added/subtracted them only.
What is the y-intercept of f(x) =(3/5)^x?
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Answer:
the y intercept is -1.
Step-by-step explanation:
the y intercept is -1 because it goes through the point (0,-1)
See attachment for problem
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The liters in the tank when it is filled to a height of 3.70 is 5,580 liters
The liters that needs to be added to 100% capacity is 480 liters
What is the volume?A right circular cone is a three dimensional object has a flat circular base that tapers to a vertex. The volume of a right circular cone is the amount of space in the right circular cone.
Volume of a cone = 1/3(πr²h)
Where:
π = pi = 3.14r = radius h = heightVolume of the right circular cone when its filled to a height of 3.70 = 1/3 x 3.14 x 3.70 x 1.20² = 5.58 m³
5.58 x 1000 = 5,580 liters
Volume of the right circular cone when it is full = 1/3 x 3.14 x 4 x 1.20² = 6.03 m³
6.03 x 1000 = 6030 liters
Liters that needs to be added to 100% capacity = 6030 liters - 5,580 liters = 480 liters
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find the value of the expression 4d ÷ c when c=3and d=6 simplify your answer
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Could you please help with
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The angle measures
m WXZ = 180 - 90 - 24
mWXZ = 66°
The functions f(x) and g(x) are shown on the graph.f(x)=x^2What is g(x)?A. g(x)=(x+3)^2B. g(x)=(x-3)^2C. g(x)=(1/3x)^2D. g(x)=3x^2
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Given:
[tex]f(x)=x^2[/tex]Let's find g(x).
From the given graph, we can see the graph of g(x) is compressed horizontally from f(x).
Thus, to find g(x) aply the transformation rules for function.
We have:
Horizontal compression of b units ==> f(bx)
Given the point on g(x):
(x, y) ==> (2, 12)
Let's solve for the value of the compressed factor.
We have:
[tex]\begin{gathered} 12=b(2)^2 \\ \\ 12=b4 \\ \\ \text{Divide both sides by 4:} \\ \frac{12}{4}=\frac{b4}{4} \\ \\ 3=b \\ \\ b=3 \end{gathered}[/tex]This means the graph of f(x) was compressed horizontally by a factor of 3 to get g(x).
Thus, to write the function for g(x), we have:
[tex]g(x)=3x^2[/tex]ANSWER:
[tex]D\text{.}g(x)=3x^2[/tex]